Answer:
He was 0.4781 s in air.
Explanation:
This question is on an object launched horizontally with zero angle and at a height H.
The formula to apply is ;
[tex]T=\sqrt{\frac{2H}{g} }[/tex]
where ;
T=time of flight = ?
H= height of the object was launched = 1.12 m
T= √2*1.12/9.8
T=√0.22857
T= 0.4781 seconds
Is Nuclear Energy renewable? Why or why not? Use in your own words.
Explanation:
Nuclear energy is argued to be renewable because it is found in the atoms that make up the earth, does not emit carbon and its use can be made unlimited by the use of technologies.
Answer:
Nuclear energy is a non-renewable energy source that comes from the nucleus of atoms.
A large, open at the top, upright cylindrical tank contains fuel oil with a density of 0.890 ✕ 103 kg/m3.
(a) If the air pressure is 101.3 kPa, determine the absolute pressure (in Pa) in the fluid at a depth of 28.0 m.
(b) Determine the force (in N) exerted by only the fluid on the window of an instrument probe at this depth if the window is circular and has a diameter of 3.20 cm.
Answer:
a) Pabs = 345.7 [kPa]
b) F = 278.08 [N]
Explanation:
Manometric pressure in liquids is defined as the product of density by gravitational acceleration by the height of the liquid.
[tex]P_{g} =Ro*g*h[/tex]
where:
Pg = manometric pressure [Pa]
Ro = density = 0.890*10³[kg/m³]
g = gravity acceleration = 9.81 [m/s²]
h = liquid height = 28 [m]
Now the absolute pressure is defined as the sum of the atmospheric pressure plus the manometric pressure
a)
[tex]P_{abs}=P_{man}+P_{gau}\\P_{abs}= 101300 + (890*9.81*28)\\P_{abs} = 345765.2 [Pa] = 345.7 [kPa][/tex]
b) To determine the force at that point
The pressure is now defined as the relationship of a force over the area.
[tex]P=F/A\\F = P*A\\[/tex]
But the area of a circle can be calculated as follows:
[tex]A=\frac{\pi }{4} *(0.032)^{2}\\A = 0.0008042[m^{2}] \\F = 345765.2*0.0008042\\F = 278.08 [N][/tex]
Bandura found that children who witnessed aggressive behavior being punished were far more likely to be aggressive than children who did not.
Please select the best answer from the choices provided
T
F
(Psychology)
Bandura's social learning theory, imitation, and observation are the two main ways that people pick up new skills. Bandura's theory encompasses more than just the notion that interaction with the environment leads directly to learning.
What Bandura children witnessed aggressive behavior?According to Bandura, hostility can also be learned indirectly through observational learning. According to the social learning theory, children learn through imitation.
An individual will internalize and replicate the aggressive behaviors of a role model in the future.
According to Bandura social learning theories, children pick up aggressive behaviors via watching others act aggressively and seeing how these actions are reinforced over time.
Therefore, it is false being punished were far more likely to be aggressive than children who did not.
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What does a barometer measure?
Answer:
Have a great day!
Explanation:
Barometers. A barometer is a scientific instrument used to measure atmospheric pressure, also called barometric pressure.
Answer:
atmospheric pressure
Explanation:
HELP ME ASAP!!!!
Select the correct answer.
According to Erik Erikson's psychosocial theory of personality, which stage occurs during adolescence?
A. identity versus identity confusion
B.
initiative versus guilt
C. generativity versus stagnation
D.
intimacy versus isolation
Reset
Next
Answer:
Identity versus confusion is the fifth stage of ego according to psychologist Erik Erikson's theory of psychosocial development.
Explanation:This stage occurs during adolescence between the ages of approximately 12 and 18. During this stage, adolescents explore their independence and develop a sense of self.
Answer:
D) autonomy versus shame and doubt
Explanation:
When forces in a system are in balance there is
Answer:
Equilibrium
Explanation:
When forces in a system are in balance, there is equilibrium.
A balance of forces around a system causes equilibrium of a system.
A body will remain its state of rest or continue in uniform motion unless acted upon by an external force. This balance of forces on a body keeps a body at rest. Even in motion, the body is at rest unless an external force acts on it.A diffraction grating has rulings of 890 lines/mm. When white light is incident normally on the grating, what is the longest wavelength that forms an intensity maximum in the fifth order
Answer:
225nm
Explanation:
The Maxima of diffraction girating
dsin( θ)= m(λ)
Where θ)= angle between central axis and corresponding point
The wavelength is to corresponding sin( θ)
Then the maximum number of (λ) can be seen by setting sin( θ)= 1 then
d= m(λ)
At fifth order maximum m=1 then
d= 5(λ)
Where d= distance between the slit and with girating of 1/890rullig/mm
d= 1/890rullig/mm= 8.90×10^-6m
At maximum wavelength
d= 5(λ)
(λ)=5/d
= 8.90×10^-6m/5
=2.75*10^-7
= 275nm
Therefore, longest wavelength that forms an intensity maximum in the fifth order is 275nm
In a football game the running back is running up the field. He starts from rest and runs 4 seconds with an acceleration of 1.3m/s^2.
What is the magnitude of his displacement
Answer:
3.38m
Explanation:
Given parameters:
Time = 4s
Acceleration = 1.3m/s²
Unknown:
Magnitude of the displacement = ?
Solution:
The body starts at rest and the initial velocity is 0m/s. To solve this problem, we have to use the expression below;
S = Ut + [tex]\frac{1}{2}[/tex]at²
S = displacement
t is the time
a is the acceleration
U is the initial velocity
V is the final velocity
Insert the parameters and solve;
S = (0 x 4) + [tex]\frac{1}{2}[/tex] x 1.3² x 4 = 3.38m
Bobby runs with an average velocity of 7.5 m/s over a straight-line distance of 90 meters. Calculate the time Bobby ran?
Answer:
12s
Explanation:
Given parameters:
Velocity = 7.5m/s
Distance = 90m
Unknown:
Time taken = ?
Solution:
Speed is the rate of distance traveled with time. It is mathematically expressed as;
Speed = [tex]\frac{distance}{time}[/tex]
Since the unknown is time;
Time = [tex]\frac{distance}{speed}[/tex]
Insert the parameters and solve;
Time = [tex]\frac{90}{7.5}[/tex] = 12s
21) The distance between crest and the adjacent trough of water wave is 3m They pass a given point
at a rate of 5m/sec. find
(a) the frequency?
(b) the speed of the water waves?
Answer:
1.67m
5m/s
Explanation:
Given parameters:
Wavelength of the wave = 3m
Speed of the wave = 5m/s
Unknown:
Frequency of the wave = ?
Speed of the water waves = ?
Solution:
The distance between crest and the adjacent trough of water waves is known as the wavelength of a wave.
To find the frequency ;
V = f∧
V is the speed of the wave
f is the frequency
∧ is the wavelength
Insert the parameters and find the frequency;
f = V/ ∧ = 5 / 3 = 1.67Hz
The rate at which the wave passed a given point is the speed of the wave and it is 5m/s
A disrupted circuit in which the current bypasses its proper path is a(n) ________ circuit.
Answer:
short circuit
Explanation:
A disrupted circuit in which the current bypasses its proper path is a short circuit.
What is a Short circuit?A short circuit is an electrical circuit which allows the electric current to travel along an unintended and uninterrupted path with no or very low electrical impedance in the circuit. This results in an excessive current flow through the electric circuit.
A short circuit is a situation in which there is faulty connection or damaged wire that causes electric current to travel along the wrong route in the circuit with low or no resistance and damage an electrical device. This may cause serious damage, fire, or even small-scale explosions.
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At what incident angle, with respect to the normal to the interface, is light inside the crown glass completely polarized when reflected from water
Answer:
57°
Explanation:
Etienne Malus discovered the idea of polarization by reflection. If light is incident on a surface at an angle of 57°, the reflected ray is found to be plane polarized.
Hence, with respect to the normal to the interface, light incident at 57° is completely polarized.
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Planets A and B have the same mass, but planet A is half the size of planet B.
Which statement correctly explains the weight you would experience on each
planet?
O A. You would weigh the same on both planets because your mass
would be the same on both.
O B. You would weigh the same on both planets because the masses
of the planets are the same.
O c. You would weigh less on planet A because the distance between
you and the planet's center of gravity would be smaller.
O D. You would weigh more on planet A because the distance between
you and the planet's center of gravity would be smaller.
Answer:
c. You would weigh less on planet A because the distance between
you and the planet's center of gravity would be smaller.
Explanation:
The statement that best describes your weight on each planet is that you would weigh less on planet A because the distance between you and the planet's center of gravity would be smaller.
This is based on Newton's law of universal gravitation which states that "the force of gravity between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distances between them".Since weight is dependent on the force of gravity and mass, the planet with more gravitational pull will have masses on them weighing more.
Since the distance between the person and the center of the planet is smaller, therefore, the weight will be lesser.Answer:it’s D for ape x
Explanation:
A plane flies for 2 hours at a speed of 430 km/h. How far did the plane travel?
Answer:
860 km
Explanation:
430*2=860
An airplane accelerates with a constant rate of 3.0 m/s2
starting at a velocity of 21 m/s. If the final velocity is 60 m/s,
what is the displacement during this period?
Answer:
526.5m
Explanation:
Given parameters:
Acceleration = 3m/s²
Initial velocity = 21m/s
Final velocity = 60m/s
Unknown:
Displacement = ?
Solution:
To solve this problem, we apply the right motion equation which is shown below;
V² = U² + 2aS
V is the final velocity
U is the initial velocity
a is the acceleration
S is the displacement
Insert the parameters and solve;
60² = 21² + 2(3)S
3600 = 441 + 6S
3600 - 441 = 6S
3159 = 6S
S = 526.5m
A source of sound produces a note of 512 Hz in air at 17 degree celsius with wavelength 66.5 cm. Find the ratio of molar heat capacities at constant pressure to constant volume at NTP. Densities of air and mercury at NTP are 1.293 kg/m^3 and 13600 kg/m^3 respectively.
Answer:
a. 0.32 b. 1448 m/s
Explanation:
We know v ∝ √T where v = velocity of sound and T = absolute temperature.
Let v₁ = velocity of sound at 17°, v₁ = fλ where f = frequency of sound = 512 Hz and λ = 66.5 cm = 0.665 m
So, v₁ = fλ = 512 Hz × 0.665 m = 340.48 m/s
T₁ = 17 + 273 = 290 K
Let v₂ = velocity of sound in air at NTP = unknown and T₂ = temperature at NTP = 0°C + 273 = 273 K
Now v₁/v₂ = √T₁/√T₂
So, v₂ = (√T₂/√T₁)v₁
= [√(T₂/T₁)]v₁
substituting the values of the variables, we have
v₂ = [√(273 K/290 K)]340.48 m/s
v₂ = [√0.9413]340.48 m/s
v₂ = (0.9702)340.48 m/s
v₂ = 330.35 m/s
Also v = √(γP/ρ) where v = velocity of sound in air at NTP = 330.35 m/s, γ = ratio of molar heat capacities, P = pressure at NTP = 1.013 × 10⁵ Pa and ρ = density of air = 1.293 kg/m³
Since, v = √(γP/ρ)
making γ subject of the formula, we have
γ = v²ρ/P
substituting the values of the variables, we have
γ = (330.35 m/s)² × 1.293 kg/m³/1.013 × 10⁵ Pa
= 31975.36 kg/m²s² ÷ 1.013 × 10⁵ Pa
= 0.32
b. Speed of sound in mercury v₃ = √(B/ρ) where B = Bulk modulus of mercury = 28.5 × 10⁹ Pa and ρ = density of mercury = 13600 kg/m³
v₃ = √(B/ρ)
= √(28.5 × 10⁹ Pa/13600 kg/m³)
= √(28.5 × 10⁹ Pa/13.6 × 10³ kg/m³)
= √(2.096 × 10⁶) m/s
= 1.448 × 10³ m/s
= 1448 m/s
What is the speed of the tip of the minute hand of a clock where the hand is of length 7cm?
Explanation:
Q1) What is the speed of the tip of the minute hand of a clock where the hand is of length 7cm?
Ans1) speed, v=st=2πrT=2×227×7×10-260×60=119×10-4=1.22×10-4m/s
Hope it helpsNewton’s Law of Cooling. Newton’s law of cooling states that the rate of change in the temperature T(t) of a body is proportional to the difference between the temperature of the medium M(t) and the temperature of the body. That is, dT/dt = K[M(t) - T(t)] , where K is a constant. Let K = 0.04 (min)-1 and the temperature of the medium be constant, M(t) = 293 kelvins. If the body is initially at 360 kelvins, use Euler’s method with h = 3.0 min to approximate the temperature of the body after
(a) 30 minutes.
(b) 60 minutes.
Answer:
After 30 minutes, the temperature of the body is: T₁₀ = 311.60 K
After 60 minutes, the temperature of the body is: T₂₀ = 298.18 K
Explanation:
Given that:
[tex]\dfrac{dT}{dt}= K \bigg [ M(t) -T(t)\bigg][/tex]
where;
K = 0.04
M(t) = 293
Then;
[tex]\dfrac{dT}{dt}= 0.04 \bigg [ 293 -T\bigg][/tex]
[tex]\dfrac{dT}{dt}= 11.72 -0.04 \ T[/tex]
Using Euler's Formula;
[tex]T_{n+1} = T_n + hf( t_n, T_n)[/tex]
where;
[tex]f(t_n,T_n) = 11.72 - 0.04 T_n[/tex]
Then;
[tex]T_{n+1} = T_n + 3.0 (11.72-0.04 \ T_n)[/tex]
[tex]T_{n+1} = 0.88T_n + 35.16 \ ---(1)[/tex]
At initial state [tex]t_0[/tex] (0); [tex]T_0[/tex] = 360
At t₁ = 3.0 when T₀ = 360
[tex]T_1= 0.88 T_o + 35.16[/tex]
[tex]T_1= 0.88 (360) + 35.16[/tex]
[tex]T_1 = 351.96 \ K[/tex]
At t₂ = 6.0 when T₂ = 0.88T₁ + 35.16
T₂ = 0.88(351.96) + 35.16
T₂ = 344.89 K
At t₃ = 9.0 when T₃ = 0.88T₂ + 35.16
T₃ = 0.88(344.89) + 35.16
T₃ =338.66 K
At t₄ = 12.0 when T₄ = 0.88T₃ + 35.16
T₄ = 0.88(338.66) + 35.16
T₄ = 333.18 K
At t₅ = 15.0 when T₅ = 0.88T₄ + 35.16
T₅ = 0.88(333.18) + 35.16
T₅ = 328.36 K
At t₆ = 18.0 when T₆ = 0.88T₅ + 35.16
T₆ = 0.88(328.36) + 35.16
T₆ = 324.12 K
At t₇ = 21.0 when T₇ = 0.88T₆ + 35.16
T₇ = 0.88(324.12) + 35.16
T₇ = 320.39 K
At t₈ = 24.0 when T₈ = 0.88T₇ + 35.16
T₈ = 0.88(320.29) + 35.16
T₈ = 317.02 K
At t₉ = 27.0 when T₉ = 0.88T₈ + 35.16
T₉ = 0.88(317.02) + 35.16
T₉ = 314.14 K
At t₁₀ = 30 when T₁₀ = 0.88T₉ + 35.16
T₁₀ = 0.88(314.14) + 35.16
T₁₀ = 311.60 K
At t₁₁ = 33.0 when T₁₁ = 0.88T₁₀ + 35.16
T₁₁ = 0.88(311.60) + 35.16
T₁₁ = 309.37 K
At t₁₂ = 36.0 when T₁₂ = 0.88T₁₁ + 35.16
T₁₂ = 0.88(309.37)+ 35.16
T₁₂ = 307.41 K
At t₁₃ = 39.0 when T₁₃ = 0.88T₁₂ + 35.16
T₁₃ = 0.88( 307.41) + 35.16
T₁₃ = 305.68 K
At t₁₄ = 42.0 when T₁₄ = 0.88T₁₃ + 35.16
T₁₄ = 0.88(305.68) + 35.16
T₁₄ = 304.16 K
At t₁₅ = 45.0 when T₁₅ = 0.88T₁₄ + 35.16
T₁₅ = 0.88(304.16) + 35.16
T₁₅ = 302.82 K
At t₁₆ = 48.0 when T₁₆ = 0.88T₁₅ + 35.16
T₁₆ = 0.88(302.82) + 35.16
T₁₆ = 301.64 K
At t₁₇ = 51.0 when T₁₇ = 0.88T₁₆ + 35.16
T₁₇ = 0.88(301.64) + 35.16
T₁₇ = 300.60 K
At t₁₈ = 54.0 when T₁₈ = 0.88T₁₇ + 35.16
T₁₈ = 0.88(300.60) + 35.16
T₁₈ = 299.69 K
At t₁₉ = 57.0 when T₁₉ = 0.88T₁₈ + 35.16
T₁₉ = 0.88(299.69) + 35.16
T₁₉ = 298.89 K
At t₂₀ = 60 when T₂₀ = 0.88T₁₉ + 35.16
T₂₀ = 0.88(298.89) + 35.16
T₂₀ = 298.18 K
Which event demonstrates electromagnetic waves transferring energy?
Question 7 options:
An astronaut tapping two rocks together
A person diving in a swimming pool
An explosion causing a window to break
Sun heating a car sitting in a parking lot
Answer:
Sun heating a car sitting in a parking lot
Explanation:
The sun heating a car sitting in a parking lot is an example of electromagnetic waves transferring energy.
Electromagnetic waves are produced from the vibration between electric and magnetic fields. These waves can be propagated through vacuum with no particles inside of them. The sun produces electromagnetic radiation through the process of nuclear fusion. These radiations are used to warm the earth surface. The sun heating a car sitting a parking lot is one vivid example.Answer:
d
Explanation:
Under what conditions does moving electric charge produce a magnetic force
in a copper wire?
A. Under any conditions
B. Only when the wire is connected to the magnet
C. Only when the wire is wrapped around an iron bar
D. Only when the wire is coiled
Answer:
I'm pretty sure that the answer is C. Hope this helps.
Explanation:
Answer:
Answer is A. Under any conditions
Explanation:
Just got it correct on A p e x
An elevator, in which a man is standing moving upward with a constant
speed of 10m/sec2. If a man drops a coin from a height of 2.5m. Find the time
taken by it to reach the oor of the elevation? g=9.8m/sec2
ANSWER
Lift frame :
Initial speed of the coin u=0 m/s
Acceleration a=9.8 m/s
2
Initial height of coin from the floor of elevator h=2.45 m
Time taken by coin to hit the floor T=
g
2H
⟹ T=
9.8
2×2.45
=
2
1
s
velocity of the lift (u₁) = 10 m/s
initial velocity of the coin (u₂) = 10 m/s
(the coin is also moving with the Elevator)
acceleration of the coin (a₂) = -9.8 m/s²
acceleration of the Elevator (a₁) = 0 m/s
Distance covered by the coin (s) = -2.5 m
__________________________________________________________
Relative Velocity and Acceleration:Relative velocity:
We will find the velocity and acceleration of the coin with respect to the lift since we are monitoring the motion of the coin
velocity of the coin with respect to the elevator (u₂₁) = u₂ - u₁
u₂₁ = 10 - 10
u₂₁ = 0m/s
Relative Acceleration:
acceleration of the coin with respect to the elevator (a₂₁) = a₂ - a₁
a₂₁ = -9.8 - 0
a₂₁ = -9.8
__________________________________________________________
Solving for the Time taken:From the second equation of motion, we know that:
s= ut + 1/2at₂
we can rewrite this equation in terms of relative motion:
s = u₂₁(t) + 1/2(a₁₂)t²
Notice that the time and the displacement are not relative, that's because displacement and time will remain the same no matter the frame of reference
replacing the known values in the equation:
-2.5 = (0)(t) + 1/2 (-9.8)(t²)
-2.5 = -4.9(t²)
dividing both sides by -4.9
t² = -2.5 / -4.9
t² = 25/49
t² = (5)² / (7)²
taking the square root of both the sides
t = 5/7 OR 0.71 seconds (approx)
Therefore, the coin will reach the floor of the Elevator in 0.71 seconds
3. A coin is tossed vertically upward.
a. What happens to its velocity while it is in the air?
b. Does its acceleration increase, decrease, or remain constant while it is in the air?
Answer:
a. The initial velocity will decrease until it reaches its final velocity/maximum (which is 0).
b. The acceleration always remain constant.
2.) Sally turns on the lamp in her bedroom. The lamp requires use of electrical
energy. Select two forms of energy that are present when the light-bulb is on.*
A.) Heat and force
B.) Motion and electrical
C.) Heat and light
D.) Force and sound
Answer:
c
Explanation:
The lamp lights up using electrical power, and so the light bulb heats up.
Answer:a
Explanation:
i took the test
Bugs Bunny, having a mass of 75 kg, is pulled by Babs Bunny and Buster Bunny. Babs
Bunny tugs Bugs with a 50 N force to the north, towards a carrot cake stand. Buster pulls
Bugs with a 120 N force to the south, towards a basket ball court. There is a force of
friction of 15 N. What will be Bug's acceleration?
Answer:
a = 0.73 m/s²
Explanation:
Considering South direction to be positive and North to be negative. The unbalanced force on bugs bunny will be given as:
Unbalanced Force = Force of Buster - Force of Babs - Friction
Unbalanced Force = 120 N - 50 N - 15 N
Unbalanced Force = 55 N
But, from Newton's Second Law:
Unbalanced Force = ma
55 N = ma
where,
m = mass of Bugs Bunny = 75 kg
a = acceleration of Bugs Bunny = ?
Therefore,
55 N = (75 kg)a
a = 55 N/75 kg
a = 0.73 m/s²
Answer:
a = 0.73 m/s²
Explanation:
-_- im tired -_-
Estimate the radiation pressure due to a bulb that emits 25 W {\rm W} of EM radiation at a distance of 9.5cm \;cm from the center of the bulb. Assume that light is completely absorbed
P=? unit?
Answer:
[tex]7.3*10^{-7} \frac{N}{m^2}[/tex]
Explanation:
[tex]\frac{25}{(4*\pi*(0.095)^{2}*3*10^8 }[/tex]
Hope this is right and helps!
HELP!!!!!! Need Help !!!
Answer:
its y
Explanation:
match the following
What is the half-life of a radioisotope?
half of the time needed for a sample of radioisotope to become stable
the time needed for half of a sample of radioisotope to decay
the time needed before the first half of a radioisotope begins to decay
half of the time needed for a radioisotope to leave the body
Answer: The amount of time it takes for half of the material to decay
B. The time needed for half of a sample of radioisotope to decay is the half-life of a radioisotope.
What is radioactive decay?Radioactive decay is the process by which an unstable atomic nucleus loses energy by radiation. A material containing unstable nuclei is considered radioactive.
The most common types of decay are alpha decay, beta decay, and gamma decay, all of which involve emitting one or more particles.
The radioactive half-life means, the time required for half the atoms of a particular radioisotope to decay into another isotope.
The half-life of a radioactive isotope is the amount of time it takes for one-half of the radioactive isotope to decay.
The half-life of a specific radioactive isotope is constant; it is unaffected by conditions and is independent of the initial amount of that isotope.
Therefore,
The half-life of a radioisotope is the time needed for half of a sample of radioisotope to decay.
The correct option is B
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A 75 kg student walks up three flights of stairs, a vertical height of about 50 ft. If the magnitude of the average rate at which the gravity force does work on the student equals 500 W, how long would it take the student to travel up the three flights of stairs?
Answer:
22.4 s
Explanation:
The following data were obtained from the question:
Mass (m) = 75 Kg
Height (h) = 50 ft
Power (P) = 500 W
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
Next, we shall convert 50 ft to metres (m). This can be obtained as follow:
1 ft = 0.3048 m
Therefore,
50 ft = 50 ft × 0.3048 m / 1 ft
50 ft = 15.24 m
Thus, 50 ft is equivalent 15.24 m.
Next, we shall determine the energy used by the student to walk up three flights of stairs. This can be obtained as follow:
Mass (m) = 75 Kg
Height (h) = 15.24 m
Acceleration due to gravity (g) = 9.8 m/s²
Energy (E) =?
E = mgh
E = 75 × 9.8 × 15.24
E = 11201.4 J
Finally, we shall determine the time taken for the student to travel up the three flights of stairs. This can be obtained as follow:
Power (P) = 500 W
Energy (E) = 11201.4 J
Time (t)
Power (P) = Energy (E) / Time (t)
500 = 11201.4 /t
Cross multiply
500 × t = 11201.4
Divide both side by 500
t = 11201.4 /500
t = 22.4 s
Therefore, it will take the student 22.4 s to travel up the three flights of stairs.
The time taken for the student to travel up the three stairs is 22.4 s.
The given parameters;
mass of the student, m = 75 kgheight of the stairs, h = 50 ft = 15.24 mwork done on the student by gravity, P = 500 WThe gravitational potential energy of the student due to vertical position of the three stairs is calculated as;
[tex]P.E = mgh\\\\P.E = 75 \times 9.8 \times 15.24 \\\\P.E =11,201.4 \ J[/tex]
The time taken for the student to travel up the three stairs is calculated as follows;
[tex]E = Pt\\\\t = \frac{E}{P} \\\\t = \frac{11,201.4}{500} \\\\t = 22.4 \ s[/tex]
Thus, the time taken for the student to travel up the three stairs is 22.4 s.
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