Magnification is the relationship between the size of an image and the size of the item that created it in optics. The ratio of the image length to the object length, as measured in planes perpendicular to the optical axis, is referred to as linear magnification, also known as lateral or transverse magnification.
Since the section of the sphere is mirrored on both sides, the focal length of the concave mirror and the convex mirror will be the same. Therefore, we can use the mirror formula:
1/f = 1/u + 1/v
Where f is the focal length, u is the distance of the object from the mirror, and v is the distance of the image from the mirror.
When the section is used as a concave mirror, the magnification is given by:
m = -v/u = +4.10
Since the magnification is positive, the image is upright.
Now, when the same object is placed in front of the convex side at the same distance u, the image will be virtual and erect. The magnification is given by:
m = v/u
To find v, we need to first find f. We know that:
m = -v/u = +4.10
Therefore, v = -4.10u
Now, using the mirror formula, we can find f:
1/f = 1/u + 1/v
1/f = 1/u - 1/4.10u
1/f = (4.10 - 1)/4.10u
f = 4.10u/3.10
f = 1.32u
Now that we know the focal length, we can find the image distance v:
1/f = 1/u + 1/v
1/1.32u = 1/u + 1/v
v = -0.32u
Therefore, the magnification is: m = v/u = -0.32
So, the at the same distance in front of the convex side is -0.32.
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what is the terminal voltage (in v) of a large 1.05 v carbon-zinc dry cell used in a physics lab to supply 1.50 a to a circuit, if the cell's internal resistance is 0.150 ω?
The terminal voltage of the large 1.05 V carbon-zinc dry cell is 0.825 V when supplying 1.50 A to a circuit with an internal resistance of 0.150 Ω.
To calculate the terminal voltage of the carbon-zinc dry cell, we can use Ohm's Law which states that V = I*R, where V is the voltage, I is the current, and R is the resistance.
In this case, the current is given as 1.50 A and the internal resistance is 0.150 Ω. So,
V = I*R
V = 1.50 A * 0.150 Ω
V = 0.225 V
However, this is the voltage drop across the internal resistance of the cell. To find the terminal voltage, we need to subtract this voltage drop from the initial voltage of the cell, which is 1.05 V.
Terminal voltage = Initial voltage - Voltage drop
Terminal voltage = 1.05 V - 0.225 V
Terminal voltage = 0.825 V
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If 5.0 x 10^21 electrons pass through a 20-Ω resistor in 10 min, what is the potential difference across the resistor?
a. 21 V
b. 32 V
c. 27 V
d. 37 V
e. 54 V
The correct option is C, The potential difference across the resistor is 26.6 V, which is closest to 27 V.
We know that [tex]5.0 \times 10^{21[/tex]electrons pass through the resistor in 10 minutes, so we need to find the current in units of amperes (A):
1 electron has a charge of [tex]1.6 \times 10^{-19} C[/tex]
The resistor's rate of electrons travelling through it per second is [tex](5.0 \times 10^{21}) / (10 \times 60) = 8.33 \times 10^{16[/tex] electrons/s
The current is therefore
[tex]I = (8.33 \times 10^{16} electrons/s) \times (1.6 \times 10^{-19} C/electron)[/tex] = 1.33 A
Now we can use Ohm's law to find the potential difference across the resistor:
V = IR = (1.33 A) x (20 Ω) = 26.6 V
A resistor is designed to have a specific resistance value, which is measured in ohms. Resistors are used in a wide range of electrical and electronic applications to control the amount of current flowing through a circuit, to limit voltage, and to divide voltage.
A resistor is made of a material that has a high resistance to the flow of electric current, such as carbon or metal. The resistance of a resistor is determined by its physical dimensions, material, and temperature. Resistors come in various shapes and sizes, including cylindrical, rectangular, and surface-mount types. Resistors are often color-coded to indicate their resistance value, tolerance, and other specifications. They can be connected in series or parallel in a circuit to achieve specific voltage and current requirements.
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A boat crosses a river. The boat points at right angles to the river bank and it travels at a
speed of 3.5m/ s relative to the water.
A river current acts at right angles to the direction the boat points. The river current has a
speed of 2.5m/ s.
By drawing a scale diagram or by calculation, determine the speed and direction of the boat
relative to the river bank.
With respect to the earth, the boat is moving at a speed of 4.07 m/s while angled 60.3 degrees to the west of north.
What is the river velocity formula?To determine the area in ft2, multiply the stream's average depth by its width. To calculate the stream's velocity in feet per second, divide the distance travelled by the average transit time.
The water's velocity in the x-direction is 2.0 m/s slower than that of the ground. (since the water is flowing to the east). So, the following formula can be used to determine the boat's velocity in relation to the ground:
v_ground = v_water + v_boat
where v_water = (-2.0 m/s, 0) and v_boat = (0, 3.5 m/s)
v_ground = (-2.0 m/s, 0) + (0, 3.5 m/s) = (-2.0 m/s, 3.5 m/s)
the Pythagorean theorem and the inverse tangent function are used to determine the velocity's magnitude and direction:
|v_ground| = sqrt((-2.0 m/s)² + (3.5 m/s)²) = 4.07 m/s
θ = atan(3.5 m/s / (-2.0 m/s)) = -60.3° (measured counterclockwise from the positive x-axis)
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The specific heat capacity of water is 4.18 J/g° C. Which description is TRUE?
The specific heat capacity of water is the amount of energy required to raise the temperature of 1 gram of water by 1 degree Celsius, and it is equal to 4.18 Joules per gram per degree Celsius. This property of water is important in many fields, including chemistry, physics, and engineering.
Specific heat capacity refers to the amount of heat energy required to raise the temperature of 1 gram of a substance by 1 degree Celsius. In the case of water, it takes 4.18 Joules of heat energy to increase the temperature of 1 gram of water by 1 degree Celsius. This property helps water maintain stable temperatures and makes it a good substance for transferring heat.
The specific heat capacity of water is 4.18 J/g °C. This statement is TRUE.
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Consider an inverter with its input voltage V,- 0. Why would the inverter dissipate power even in this case?
The inverter dissipates power even with its input voltage V,- 0 because of the following reasons:
1)Switching losses
2)Standby losses
3)Leakage currents.
An inverter is an electronic device that converts DC (direct current) power to AC (alternating current) power. In an inverter, a voltage source, typically a battery or a DC power supply, is connected to the input of the inverter. The input voltage is then converted into an AC output voltage by means of electronic switches such as transistors or thyristors.
Even when the input voltage of an inverter is zero, the inverter may still dissipate power due to various reasons such as:
1) Switching losses: The electronic switches used in the inverter have finite switching times and during this time, they may not be fully conducting or fully non-conducting. This results in a short-circuit condition across the input voltage source, which causes current to flow and power to be dissipated.
2) Standby losses: Inverters may have standby circuits that draw a small amount of power even when there is no load connected to the output. This power is dissipated in the inverter circuitry and may be used to power the control circuitry or for other purposes.
3) Leakage currents: The electronic components used in the inverter circuitry have finite resistance and capacitance values, which can result in leakage currents that flow even when there is no input voltage present. These leakage currents can cause power to be dissipated in the inverter circuitry.
Therefore, even when the input voltage of an inverter is zero, the inverter may still dissipate power due to the reasons mentioned above. The amount of power dissipated will depend on the specific design of the inverter and the conditions under which it is operating.
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specific gravity number is same as density number of matters. the unit of specific gravity is …?………
The unit of Specific Gravity is dimensionless.
The statement explains that specific gravity is a dimensionless unit, which means that it has no unit associated with it. Specific gravity is used to compare the density of a substance to the density of a reference substance, usually water. It is a ratio of the two densities and is expressed as a number without any unit. Although density and specific gravity are related, they are not the same thing. Density is typically measured in units such as kg/m³ or g/cm³, while specific gravity is a unitless number that compares the densities of two substances.
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Tripling the tension in a guitar string will change its natural frequency by what factor?
A. 3^ 1/2
B. 1.5
C. 3^ -1/2
D. 3
Tripling the tension in a guitar string will change its natural frequency by a factor of A. [tex]3^1^/^2[/tex]
The natural frequency of a vibrating string, like a guitar string, is determined by its tension, length, and mass per unit length. This relationship is given by the formula:
f = (1/2L) × √(T/μ)
where f is the natural frequency, L is the length of the string, T is the tension, and μ is the mass per unit length.
Now, let's consider the case when the tension is tripled. Let f₁ be the original frequency and f₂ be the new frequency after tripling the tension. We have:
f₁ = (1/2L) × √(T/μ)
f₂ = (1/2L) × √(3T/μ)
To find the factor by which the natural frequency changes, divide f₂ by f₁:
(f₂ / f₁) = [√(3T/μ)] / [√(T/μ)] = √(3T/μ)×√(μ/T) = √3
So, tripling the tension in a guitar string will change its natural frequency by a factor of √3, which corresponds to option A. [tex]3^1^/^2[/tex] .
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An 18,000 Btu/h split air conditioner is running at full load to keep a room at 25°C in an environment at 45°C. The power input to the air conditioner compressor is 2.5 kw. Determine the COP of the air conditioning unit and the rate at which heat is rejected to the ambient from the air conditioner condenser. [1 Btu = 1,055 kJJ.
COP of the air conditioning unit is 7.596, and the rate at which heat is rejected to the ambient from the air conditioner condenser is 21.49 kW.
To determine the Coefficient of Performance (COP) of the 18,000 Btu/h split air conditioner and the rate at which heat is rejected to the ambient from the air conditioner condenser, follow these steps:
1. Convert the air conditioner capacity from Btu/h to kW:
18,000 Btu/h * (1,055 kJ / 1 Btu) * (1 kW / 1,000 kJ) = 18,990 W = 18.99 kW
2. Calculate the COP:
COP = Cooling Capacity (kW) / Power Input (kW)
COP = 18.99 kW / 2.5 kW = 7.596
3. Calculate the heat rejected to the ambient:
Heat Rejected = Cooling Capacity + Power Input
Heat Rejected = 18.99 kW + 2.5 kW = 21.49 kW
So, the COP of the air conditioning unit is 7.596, and the rate at which heat is rejected to the ambient from the air conditioner condenser is 21.49 kW.
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the ship leaves port and travels n47e for 55 miles. write the vector that models the ships movement in component form
The vector that models the ship's movement in component form is ⟨38.71, 39.21⟩.
To find the vector in component form, we will follow these steps:
1. Convert the bearing of N47E to a standard angle.
2. Calculate the horizontal (x) and vertical (y) components of the vector using trigonometry.
Step 1: Convert N47E to a standard angle:
N47E means 47 degrees to the east of the north direction. To find the standard angle, measured counterclockwise from the positive x-axis, we subtract 47 degrees from 90 degrees: 90 - 47 = 43 degrees.
Step 2: Calculate the horizontal and vertical components:
Now that we have the standard angle, we can use trigonometry to find the x and y components of the vector. The ship travels 55 miles at an angle of 43 degrees. Using cosine and sine, we get:
x = 55 * cos(43°) ≈ 38.71
y = 55 * sin(43°) ≈ 39.21
Thus, the vector in component form is ⟨38.71, 39.21⟩.
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An inductor with an inductance of L = 18.0 mH and a resistance of R = 4.33 12 is connected in series to the terminals of a battery with an EMF of E = 7.78 V (negligible internal resistance) and a switch that has been closed for a long time. At time t = 0, the battery is shorted to leave a discharging RL circuit. a. (Q6 ans 2 pts, Q7 work 4 pts) What is the time constant 7 for this RL circuit? b. (Q8, 6 pts) What is the current in the circuit at time ti = 3.66 ms? c. (Q9, 6 pts) What is the EMF across the inductor at time tı? d. (Q10,6 pts) What is the value of current in the circuit at t ? e. (Q11, 6 pts) At what time is the energy in the inductor 60.0% of its initial value? To continue, please give the time constant (part a) in units of ms.
a. The time constant (τ) for this RL circuit can be calculated using the formula τ = L/R, where L is the inductance and R is the resistance of the circuit. Plugging in the given values, we get τ = 18.0 mH / 4.33 Ω = 4.16 ms.
The time constant is a measure of how quickly the circuit reaches its steady state. It represents the time it takes for the current in the circuit to reach 63.2% of its final value after the switch is closed.
In other words, after a time equal to the time constant, the current in the circuit will have reached approximately 63.2% of its maximum value.
This means that if we wait for a time of about 5-time constants, the current in the circuit will have reached almost 100% of its final value, and the circuit will have effectively reached its steady state.
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An L-R-C series circuit has L = 0.400 H, C = 4.00 μF, and R = 370 Ω. At t = 0 the current is zero and the initial charge on the capacitor is 2.80 × 10−4 C.
Part A
What is the values of the constant A in the followin equetion?
q=Ae−(R/2L)tcos(1LC−R24L2−−−−−−−−√t+ϕ)
The value of the constant A in the given equation is 2.97 × 10⁻⁴ C.
To find the value of A, we need to use the initial conditions given in the problem. At t=0, the current is zero and the initial charge on the capacitor is 2.80 × 10⁻⁴ C.
Using the equation for charge in an L-R-C series circuit, we can write:
q = q(max) * sin(ωt + ϕ)
where q(max) is the maximum charge on the capacitor, ω is the angular frequency, and ϕ is the phase angle.
We can find the values of ω and ϕ using the given values of L, C, and R:
ω = 1 / √(LC) = 5000 rad/s
ϕ = arctan((1/RC) - (ωL/R)) = 1.392 rad
Now we can rewrite the equation for charge in terms of the given equation:
q = Ae^(-R/2L)t * cos(√(1/LC - R²/4L²)t + ϕ)
At t=0, we know that q=2.80 × 10⁻⁴ C. Plugging this in and solving for A, we get:
2.80 × 10⁻⁴ = A * cos(ϕ)
A = 2.80 × 10⁻⁴ / cos(ϕ)
A = 2.80 × 10⁻⁴ / cos(1.392)
A = 2.97 × 10⁻⁴ C
Therefore, the value of the constant A in the given equation is 2.97 × 10⁻⁴ C.
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2. at what frequency is the reactance of a 350.0-µh inductor equal to 120 ω?
The reactance of a 350.0-µh inductor equal to 120 ω in frequency is 1.03MHz
The reactance of an inductor is given by the formula Xl = 2πfL, where Xl is the inductive reactance, f is the frequency in hertz, and L is the inductance in henries.
Frequency is a number that describes how often a particular item appears in the given data set. In physics, frequency is a number that describes how frequently a particular item appears in the given data set. There are two types of frequency distributions: grouped and ungrouped. The two different kinds of frequency tables are distribution.
To find the frequency at which the reactance of a 350.0-µh inductor is equal to 120 ω, we can rearrange the formula as follows:
f = Xl / (2πL)
Substituting the given values, we get:
f = 120 Ω / (2π x 350.0 x 10^-6 H)
f ≈ 1.03 MHz
Therefore, the frequency at which the reactance of a 350.0-µh inductor is equal to 120 ω is approximately 1.03 MHz.
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Part C Four racecars are driving at constant speeds around a circular racetrack. The daiabie gives the speed of each car and each car's d Speed (m/s) 40 40 50 50 Position (m) 20 25 20 Car Rank the cars' accelerations from largest to smallest. To rank items as equivalent, overlap them Largest Acceleration lu The corect rankig carat be determined. lity Ansuers Qive Up Submit
The cars' accelerations ranked from largest to smallest are, Car 3, Car 1, Car 4, Car 2.
To rank the cars' accelerations from largest to smallest, we first need to calculate their centripetal accelerations. Centripetal acceleration is the acceleration experienced by an object moving in a circular path and is given by the formula:
a = v² / r
where a is the centripetal acceleration, v is the speed of the car, and r is the radius of the circular track. Since the distances given in the table correspond to the positions of the cars on the track, we can assume that the track is a circle with a radius of 5 meters (half the difference between the distances of each car). Using this radius, we can calculate the centripetal acceleration for each car:
Car 1: a = (40 m/s)² / 5 m = 320 m/s²
Car 2: a = (40 m/s)² / 10 m = 160 m/s²
Car 3: a = (50 m/s)² / 5 m = 500 m/s²
Car 4: a = (50 m/s)² / 10 m = 250 m/s²
Therefore, the cars' accelerations ranked from largest to smallest are:
Car 3 (500 m/s²)
Car 1 (320 m/s²)
Car 4 (250 m/s²)
Car 2 (160 m/s²)
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--The complete question is, Part C Four racecars are driving at constant speeds around a circular racetrack. The data table gives the speed of each car and each car's distance at that instant.
Speed (m/s) 40 40 50 50
Position (m) 20 25 20 25
Rank the cars' accelerations from largest to smallest.--
(5) For water, n = 1.333. A fish is 80 cm below the surface of a pond. How far below the surface of the water does the fish appear to be (in cm), to an observer outside the water and almost directly above the fish?
To an observer outside the water having a refractive index of 1.33, and almost directly above the fish, the fish appears to be at a depth of 60 cm below the surface of the water.
The apparent depth of an object in water is given by the formula:
apparent depth = real depth / refractive index
where the refractive index of water is n = 1.333.
In this case, the real depth of the fish is 80 cm. So the apparent depth of the fish is:
apparent depth = 80 cm / 1.333
apparent depth = 60 cm
Therefore, the fish appears to be 60 cm below the surface of the water to an observer outside the water and almost directly above the fish.
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A 3.5cm radius hemisphere contains a total charge of6.6*10-7 C. the flux through the rounded portion of thesurface is 9.8*104 Nm2/C. The flux throughthe flat base is: a. 0 b. +2.3*104 Nm2/C c. -2.3*104 Nm2/C d. +9.8*104 Nm2/C e. -9.8*104 Nm2/C
The negative sign indicates that the electric field is directed inward toward the center of the hemisphere.
What is a 3.5cm radius hemisphere contains?We can use Gauss's law to solve this problem, which states that the electric flux through a closed surface is equal to the total charge enclosed by the surface divided by the electric constant, ε0.
In this case, we are given the radius of the hemisphere, r= 3.5 cm, and the total charge enclosed by the surface, Q = 6.6 x 10^-7 C. We are also given the flux through the rounded portion of the surface, Φ = 9.8 x 10^4 Nm^2/C.
To find the flux through the flat base, we can use the fact that the flux through the entire closed surface must be equal to the sum of the fluxes through each part of the surface. Since we know the flux through the rounded portion of the surface, we can subtract that from the total flux to find the flux through the flat base:
Φ_total = Φ_rounded + Φ_flat
Φ_flat = Φ_total - Φ_rounded
The flux through the entire closed surface is given by the surface area of the hemisphere, which is:
A_total = 2πr²
A_total = 2π(0.035 m)²
A_total = 0.0077 m²
The flux through the entire surface is:
Φ_total = Q/ε0 = (6.6 x 10⁻⁷ C) / (8.85 x 10⁻¹² N^-1m⁻²C²)
Φ_total = 7.44 x 10⁴ Nm²/C
Now we can find the flux through the flat base:
Φ_flat = Φ_total - Φ_rounded
Φ_flat = (7.44 x 10⁴ [tex](Nm^2/C)[/tex]) - (9.8 x 10⁴ [tex]Nm^2/C[/tex])
Φ_flat = -2.36 x 10⁴ [tex]Nm^2/C[/tex]
Therefore, the answer is (c) -2.3 x 10⁴ [tex]Nm^2/C.[/tex]
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the intensity of a sound wave emitted by a hair dryer is 4.65 µw/m2. what is the sound level (in db)?
The sound level (in dB) of a hair dryer emitting a sound wave with an intensity of 4.65 µW/m² can be calculated using the following formula:
Sound level (dB) = 10 log (I/I0)
Where I is the sound wave intensity in question (4.65 µW/m²) and I0 is the reference intensity of 1 µW/m².
Substituting the values into the formula, we get:
Sound level (dB) = 10 log (4.65/1)
Sound level (dB) = 10 log (4.65)
Sound level (dB) = 57.6 dB (rounded to one decimal place)
Therefore, the sound level emitted by the hair dryer is 57.6 dB.
Hi! To calculate the sound level in decibels (dB) of a sound wave emitted by a hair dryer with an intensity of 4.65 µW/m², you can use the following formula:
Sound level (dB) = 10 × log10(I/I₀)
where I is the intensity of the sound wave (4.65 µW/m²) and I₀ is the reference intensity, which is 10^-12 W/m².
So, Sound level (dB) = 10 × log10(4.65 × 10^-6 W/m² / 10^-12 W/m²) = 73.68 dB
Therefore, the sound level of the hair dryer is approximately 73.68 dB.
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a 1000 kg car traveling at a speed of 40 m/s skids to a haha on rawl concrete where f-x = 0.60. how long are the skid marks?
The automobile stops and moves in the opposite direction of its starting velocity, as indicated by the negative sign. The length of the car's skid marks is around 136.05 metres.
Calculation-
the equation of motion
[tex]v^2 = u^2 + 2a s[/tex]
Given:
Mass of the car (m) = 1000 kg
Initial velocity (u) = 40 m/s
Final velocity (v) = 0 m/s
Coefficient of friction (f) = 0.60
The friction force (F) acting on the car
[tex]F = f * m * g[/tex]
the acceleration due to gravity (9.8 m/s^2).
Plugging in the values:
[tex]f = 0.60m = 1000 kgg = 9.8 m/s^2F = 0.60 * 1000 kg * 9.8 m/s^2F = 5880 N[/tex]
The acceleration (a) of the car
[tex]F = m * aPlugging in the values:F = 5880 Nm = 1000 kg5880 N = 1000 kg * aa = 5880 N / 1000 kga = 5.88 m/s^2[/tex]
the equation of motion to calculate the distance (s)
[tex]v^2 = u^2 + 2a s0 = (40 m/s)^2 + 2 * 5.88 m/s^2 * s0 = 1600 m^2/s^2 + 11.76 m/s^2 * s11.76 m/s^2 * s = -1600 m^2/s^2s = (-1600 m^2/s^2) / (11.76 m/s^2)s = -136.05 m[/tex]
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A 61.5 m length of insulated copper wire is wound to form a solenoid of radius 1.9 cm. The copper wire has a radius of 0.53 mm_. (Assume the resistivity of copper is rho = 1.7 x 10^-8 Ω-m.rho =.) If the solenoid is attached to a battery with an emf of 6.0 V and an internal resistance of 350 m-Ω350 m-Ω, compute the time constant of the circuit.
A battery has an internal resistance if 0.4 ohm and an e.m.f. of 6 volts. It really is connected to an SPST (single pole, single throw) switch, which is connected to the a 2.6 ohm resistor.
Which expressions result in the battery's emf and the resistor's current?Answer. The formula for a battery's emf is V + I r, where V denotes the battery's terminal voltage, r denotes the battery's internal resistance, and I is the current flowing through the circuit.
What is the formula for EMF current and voltage?The electromotive force (EMF) formula can be written as e = IR + Ir or e = V + Ir, where e is just the electromotive force (in volts), I is the current (in amps), R is the load resistance, and r is the reactance of the cell, measured in ohms.
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find the minimum magnetic field needed to exert a 5.3 ×10−15 n force on an electron moving at 24 ×106 m/s .
The minimum magnetic field needed to exert a 5.3 × 10^(-15) N force on an electron moving at 24 × 10^6 m/s is approximately 1.37 × 10^(-4) T (teslas).
To find the minimum magnetic field needed to exert a 5.3 × 10^(-15) N force on an electron moving at 24 × 10^6 m/s, you'll need to use the following formula for the magnetic force on a moving charge:
F = q * v * B * sin(θ)
where F is the magnetic force, q is the charge of the electron, v is its velocity, B is the magnetic field, and θ is the angle between the velocity and the magnetic field.
The charge of an electron (q) is -1.6 × 10^(-19) C. Since we want to find the minimum magnetic field (B), the angle θ should be 90°, making sin(θ) equal to 1.
Rearrange the formula to solve for B:
B = F / (q * v * sin(θ))
Now, plug in the values:
B = (5.3 × 10^(-15) N) / ((-1.6 × 10^(-19) C) * (24 × 10^6 m/s) * (1))
B ≈ 1.37 × 10^(-4) T
Approximately 1.37 × 10^(-4) T (teslas) of magnetic field is required to apply a 5.3 × 10^(-15) N force to an electron travelling at 24 × 10^6 m/s.
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GPS (Global Positioning System) satellites orbit at an altitude of 2.1x107 m . You may want to review (Pages 392-398) Find the orbital period. Express your answer using two significant figures VO AXD ? T= h Submit Request Answer Part B Find the orbital speed of such a satellite. Express your answer using two significant figures. ? 3300 m/s Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining
According to the question the orbital speed of the satellite is 3300 m/s.
What is orbital speed?Orbital speed is the speed at which an object orbits, or revolves around, another object. It is the speed of an object in a circular orbit around a central body, such as a star, a planet, or a moon. The speed of an object in an elliptical orbit is not constant, however, it changes as the object moves closer to, or further away from, the central body.
T = 2π√(a3/μ)
Plugging these values into the equation above, we get:
T = 2π√(2.1x107 m3/3.986x1014 m3/s2)
T = 2.5x104 s
The orbital period of the satellite is 2.5x104 s, or 6.9 hours.
v = 2πa/T
Plugging in the values for a and T, we get:
v = 2π(2.1x107 m)/(2.5x104 s)
v = 3300 m/s
The orbital speed of the satellite is 3300 m/s.
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What is the kinetic energy of a 0.135-kg baseball thrown at 40.0 m/s (90.0 mph)?
a. 54.0 J
b. 87.0 J
c. 108 J
d. 216 J
The kinetic energy of a 0.135-kg baseball thrown at 40.0 m/s (90.0 mph) is c. 108 J.
To find the kinetic energy of the baseball, you can use the following formula:
Kinetic energy (KE) = 0.5 × mass × velocity²
In this case, the mass of the baseball is 0.135 kg, and the velocity is 40.0 m/s. Plug these values into the formula:
KE = 0.5 × 0.135 kg × (40.0 m/s)²
Now, calculate the kinetic energy:
KE = 0.5 × 0.135 kg × 1600 m²/s²
KE = 0.0675 × 1600
KE = 108 J
So, the correct answer is c. 108 J.
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You need to raise the temperature of a gas by 10°C. To use the least amount of heat energy, should you heat the gas at constant pressure or at constant volume? Reset 0 constant pressure You should use heating at because the required amount of heat is constant volume proportional to volume proportional to pressure inverse proportional to molar specific heat proportional to molar specific heat
Heating the gas at constant volume allows for the most efficient transfer of heat energy to raise the temperature of the gas by a given amount, such as 10°C, and would require the least amount of heat energy.
You should heat the gas at a constant volume in order to use the least amount of heat energy to raise the temperature by 10°C.
When heat is added to a gas at constant volume, the entire amount of energy is used to increase the temperature of the gas. This is because at constant volume, no work is done by the gas to expand against external pressure, and all the heat energy goes towards increasing the internal energy of the gas, which results in a higher temperature.
On the other hand, when heat is added to a gas at constant pressure, some of the energy is used to do work against the external pressure as the gas expands. This means that less energy is available to increase the internal energy of the gas and raise its temperature by the same amount compared to heating at constant volume.
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The position of a particle moving along a coordinate plane is s = StartRoot 1 + 5 t EndRoot, with s in meters and t in seconds. What is the particle’s velocity when t = 3 sec?
a. 1/8 m/s
b. 2 m/s
c. 5/8 m/s
d. 4 m/s
c. The velocity of the particle when t = 3 sec is 5/8 m/s.
To find the velocity of the particle, we need to take the derivative of the position function with respect to time (t):
s(t) = sqrt(1 + 5t)
v(t) = ds/dt = (1/2)(1 + 5t)^(-1/2) * 5
At t = 3 sec, we have:
v(3) = (1/2)(1 + 5(3))^(-1/2) * 5
v(3) = (1/2)(16)^(-1/2) * 5
v(3) = 5/8 m/s
Therefore, the answer is c. 5/8 m/s.
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Does hydrogen bonding occur in a pure sample of dimethyl ether? Match the items in the left column to the appropriate blanks in the sentences on the right. Reset Help in the same molecule Hydrogen bonding in a pure sample of dimethyl ether. A hydrogen bond is interaction between a hydrogen atom bonded to and an electron-rich occurs does not occur region elsewhere an attractive In the same molecule or in a different molecule in a different molecule a low electronegative atom (like C, B, P) a repulsive a very electronegative atom (O, N. or F)
Hydrogen bonding does not occur in a pure sample of dimethyl ether.
A hydrogen bond is an interaction between a hydrogen atom bonded to an electron-rich region elsewhere in the same molecule or in a different molecule with a very electronegative atom (like O, N, or F), resulting in an attractive force. However, dimethyl ether contains only C and H atoms, which have low electronegativities and cannot participate in hydrogen bonding, resulting in a repulsive force. In dimethyl ether, hydrogen is bonded to a low electronegative atom (like C), which does not allow for hydrogen bonding to take place.
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A solid ball of metal has a spherical cavity inside it. When the ball is heated the volume of the cavity will
a. increase
b. decrease
c. remain unaffected
d. have its shae changed
The volume and shape of the spherical cavity inside the solid metal ball will remain the same when the ball is heated. The correct option is c. remain unaffected.
When a solid ball of metal is heated, it expands due to the increase in temperature. However, the spherical cavity inside the ball does not expand as it is already a fixed size. This means that the space occupied by the cavity remains the same, while the metal ball around it expands.
As a result, the volume of the cavity inside the metal ball remains unaffected when the ball is heated. The shape of the cavity will also remain the same as it is a fixed shape that cannot change due to temperature changes.
It is important to note that the type of metal the ball is made of will affect how much it expands when heated. Some metals have a higher coefficient of thermal expansion, meaning they will expand more than others when heated. However, this expansion will only affect the outer surface of the metal ball and not the cavity inside it.
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a parallel plate capacitor is connected to a 9 volt battery. if the plate area is decreased, then the electric field between the plates of the capacitora. decreasesb. increasesc. remains constantd. changes in an unknown waye. will change based on the dielectric constant of the dielectric
If the plate area of a parallel plate capacitor is decreased while it is connected to a 9 volt battery, the electric field between the plates of the capacitor will increase.
This is because the capacitance of a parallel plate capacitor is inversely proportional to the distance between the plates. As the plate area decreases, the distance between the plates decreases, which increases the capacitance. The relationship between the voltage (V), electric field (E), and the plate separation (d) can be expressed as: V = E * d. Since the voltage across the capacitor remains constant, the increase in capacitance leads to an increase in the electric field between the plates. The dielectric constant of the dielectric material between the plates will also affect the capacitance, but it is not directly related to the increase in electric field due to the decrease in plate area.
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a 10.5 v battery is connected to a 5.2 pf parallel-plate capacitor. what is the magnitude of the charge on each plate? answer in units of c
The magnitude of the charge on each plate is 54.6 × 10⁻¹² C when a 5.2 pf parallel plate capacitor is connected to a 10.5 v battery.
To find the magnitude of the charge on each plate of a parallel-plate capacitor, you can use the formula:
Q = C × V
where Q is the charge on each plate, C is the capacitance of the capacitor, and V is the voltage across the capacitor.
Given the values in the question:
V = 10.5 V (voltage)
C = 5.2 pF (capacitance, in picofarads)
First, we need to convert the capacitance from picofarads (pF) to farads (F):
1 pF = 1 × 10⁻¹² F
So, C = 5.2 × 10⁻¹² F
Now, we can use the formula to find the charge:
Q = C × V
Q = (5.2 × 10⁻¹² F) × (10.5 V)
Q = 54.6 × 10⁻¹² C
The magnitude of the charge on each plate is 54.6 pC (pico coulombs) or 54.6 × 10⁻¹² C.
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At t=0 the current to a dc electric motor is reversed, resulting in an angular displacement of the motor shaft given by theta(t)=( 259rad/s )t- 19.5rad/s^2 )t^2-( 1.49rad/s^3 )t^3. 1.At what time is the angular velocity of the motor shaft zero? 2.Calculate the angular acceleration at the instant that the motor shaft has zero angular velocity. 3.How many revolutions does the motor shaft turn through between the time when the current is reversed and the instant when the angular velocity is zero? 4.How fast was the motor shaft rotating at t=0, when the current was reversed? 5.Calculate the average angular velocity for the time period from t=0 to the time calculated in part A.
At times t = 5.84 and t = 12.64, the motor shaft's angular velocity is zero. It accelerates at an angle of -156.4 rad/s². Until the angular velocity is zero, the motor shaft makes around 96.6 revolutions.
Why does the orientation of the AC generator's coil change every half-rotation?Alternating current, often known as a current that continually changes direction (polarity), is produced by an AC generator by the polarity of the current in each arm changing after every half cycle.
theta'(t) = 259 - 39t - 4.47t² = 0
t = (-(-39) ± √((-39)² - 4(259)(-4.47))) / (2(-4.47))
t ≈ 5.84 seconds or t ≈ 12.64 seconds
theta''(t) = -39 - 8.94t
At t ≈ 5.84 seconds, the angular acceleration is:
theta''(5.84) = -39 - 8.94(5.84) ≈ -90.1 rad/s²
At t ≈ 12.64 seconds, the angular acceleration is:
theta''(12.64) = -39 - 8.94(12.64) ≈ -156.4 rad/s²
theta(t) = (259t - 19.5t² - 1.49t³) dt
Integrating between t=0 and t ≈ 5.84 seconds, we get:
theta ≈ 606.6 radians
We divide by 2 to translate to revolutions:
theta ≈ 96.6 revolutions
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will indium display the photoelectric effect with uv light? with infrared light?
Since UV light has greater energy photons than infrared light, indium is expected to exhibit the photoelectric effect with UV light but not with infrared light.
Will indium exhibit the photoelectric effect when exposed to infrared or ultraviolet light?If indium is exposed to UV light, the photoelectric effect will manifest. When exposed to infrared light, it won't exhibit the photoelectric effect.
Which metal only emits electrons from its surface when exposed to UV light?Certain metals, including zinc, cadmium, magnesium, etc., were found to only emit electrons from their surfaces when exposed to ultraviolet light with a short wavelength. Lithium, sodium, potassium, caesium, and rubidium are examples of alkali metals that can be sensitive to visible light.
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the angular velocity of a rotating turntable is given in rad/s by ω(t) = 4.5 0.64t - 2.7t2. what is its angular acceleration at t = 2.0 s?
The angular acceleration of the rotating turntable at t = 2.0 s is -10.16 rad/s².
To find the angular acceleration of the rotating turntable at t = 2.0 s, we need to first find the derivative of the given angular velocity function ω(t) = 4.5 + 0.64t - 2.7t².
Step 1: Differentiate the angular velocity function with respect to time t.
dω/dt = 0 + 0.64 - 5.4t
Step 2: Substitute t = 2.0 s into the derivative to find the angular acceleration.
α(t) = 0.64 - 5.4(2.0)
α(t) = 0.64 - 10.8
α(t) = -10.16 rad/s²
The angular acceleration of the rotating turntable at t = 2.0 s is -10.16 rad/s².
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