A section of a high speed test track is circular with a radius of curvature R = 1860 m.

At what angle of θ should the track be inclined so that a car traveling at 61.0 m/s (136 mph) would keep moving in a circle if there is oil on that section of the track, i.e., it would not slip sideways even with zero friction on that section. (Hint: The car's vertical acceleration is zero)

Answer:

animals and wildlife (c)

Explanation:

Ecotourism is essentially tourism of nature--which highly incorporates animals/wildlife

> it usually has a goal of conservation of nature

poaching is illegally hunting wild animals, which is focused on an aspect of nature protection (which is why it is ecotourism)

the only option listed here that is about ecotourism is animals and wildlife (c), meaning that this is the correct fill-in

hope this helps! have a lovely day :)

Answer:

.714 m

Explanation:

The VERTICAL component is all we are interested in for this Q

Vertical velocity = 6.32  m/s   sin 36.3° = 3.742 m/s

Vertical displacement  =   vo t  - 1/2 at^2

                                     = -1/2 at^2 + vo t  

        max occurs at - b/2a = -3.742/ (2(-1/2(9.81)) = .3814 sec

                then vot-1/2 at^2 =

                          3.742 (.3814) - 1/2 ( 9.81)(.3814^2) = .714 m

Answer:

.714

Explanation:

The work done by the man is the product of his applied force and the displacement of the bag and the man gets tired because his internal energy has be converted to work.

The work done by the man is the product of his applied force and the displacement of the bag.

The man gets tired because his internal energy has be used to do work on the bag.

Thus, the work done by the man is the product of his applied force and the displacement of the bag and the man gets tired because his internal energy has be converted to work.

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Answer:

E=kQ/r*2

=(9. 10*9)(11.10*-9)/(0,07)*2

=20204 N. C*-1

The field lines will point towards the source charge because it is negatively charged.

Hi there!

To start, we can use the equation for the charge of a capacitor versus time.
[tex]q(t) = C\epsilon (1 - e^{-\frac{t}{\tau}})[/tex]

[tex]q(t)[/tex] = Charge on capacitor vs. time

[tex]\epsilon[/tex] = EMF of battery (40 V)

**Note: 'Cε' is equal to the MAXIMUM CHARGE on a capacitor.

Where the time constant is given as:
[tex]\tau = RC[/tex]
[tex]\tau[/tex] = Time Constant (s)
[tex]R[/tex] = Resistance (0.5 MΩ)
[tex]C[/tex] = Capacitance (90 μF)

Let's first convert the given units to the necessary 'J',  'Ω' and 'F' to make things easier:

[tex]J = 50.2 mJ[/tex]

[tex]50.2 mJ * \frac{0.001J}{1mJ} = 0.0502 J[/tex]

[tex]R = 0.5 M\Omega\\\\0.5M\Ohm * \frac{1000000\Omega}{1M\Ohm} = 500000\Omega[/tex]

[tex]F = 90 \mu F[/tex]

[tex]90 \mu F * \frac{0.000001 F}{1\mu F} = 0.00009 F[/tex]

Now, let's calculate the time constant.

[tex]\tau = RC = (500000)(0.00009) = 45 s[/tex]

Time to use the equation for energy stored in a capacitor:
[tex]E_C = \frac{1}{2}\frac{Q^2}{C}[/tex]

Our 'Q' varies with time, so:
[tex]E(t)= \frac{1}{2}\frac{( C\epsilon (1 - e^{-\frac{t}{\tau}}))^2}{C}\\\\E(t) = \frac{1}{2}\frac{( C^2\epsilon^2 (1 - e^{-\frac{t}{\tau}})^2)}{C}\\\\E(t) = \frac{1}{2}( C\epsilon^2 (1 - e^{-\frac{t}{\tau}})^2)[/tex]

Let's now plug values into our equation.

[tex]0.0502 = \frac{1}{2}(0.00009)(40^2) (1 - e^{-\frac{t}{45}})^2[/tex]

Simplifying:
[tex]0.697 = (1 - e^{-\frac{t}{45}})^2[/tex]

Take the square root of both sides.

[tex]0.835 = 1 - e^{-\frac{t}{45}}\\\\ e^{-\frac{t}{45}} = 0.165[/tex]

Take the natural log of both sides.

[tex]-\frac{t}{45} = ln(0.165) \\\\\frac{t}{45} = 1.802\\\\t = \boxed{81.08 s}[/tex]

The skin is NOT a reproductive organ and the spines attract predators are the incorrect statements.

The list is incorrect because skin is not a reproductive organ and the spines do not attract predators towards each other. Skin protects the body from the outer environment whereas the spines repel the predators from the plant body.

So we can conclude that the skin is NOT a reproductive organ and the spines attract predators are the incorrect statements.

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The altimeter reading is 29.17 from the Kollsman window is 29.17 in Hg

The given parameters are:

The pressure altitude is calculated as:

Altitude = (29.92 – Altimeter reading) * 1,000 + Ground level

Substitute the known values

1450 = (29.92 - Altimeter reading) * 1000 + 700

Subtract 700 from both sides

750 = (29.92 - Altimeter reading) * 1000

Divide through by 1000

0.75 = 29.92 - Altimeter reading

Evaluate the like terms

Altimeter reading = 29.17

Hence, the altimeter reading is 29.17 from the Kollsman window is 29.17 in Hg

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Answer:

The atomic number is the number of protons in an element

Answer:

2

Explanation:

8-0/4

Final velocity-initial velocity/time taken

the mass of mars is

6.39 × 10^23 kg

The energy (in calories) required to power the heart for one day is 268.32 Cal

1 day = 24 h

24 h = 24 × 60 = 1440 mins

1440 mins = 1440 × 60 = 86400 s

Thus,

1 day = 86400 s

From the question given,

1 s = 13 J

Therefore,

86400 s = 86400 × 13

86400 s = 1123200 J

Divide by 4186 to express in calories

86400 s = 1123200 / 4186

86400 s = 268.32 Cal

Thus, the energy needed to power the heart for 1 day is 268.32 Cal

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Complete question

Under normal conditions the human heart converts about 13.0 J of chemical energy per second into 1.30 W of mechanical power as it pumps blood throughout the body. (a) Determine the number of Calories required to power the heart for one day given that 1 Calorie equals 4186

The center of the mass of a one-meter long rod, made of 50 cm of iron (density 8gcm3) and 50 cm of aluminum (density 2.7gcm3) is 37.62(cm)

λ Fe =8g/cm,λ Al =2.7g/cm

There is a metal rod 1 meter long, with the first 50cm being iron and the other 50cm aluminum. the problem is solved in a one-dimensional case meaning it's a thin rod.

Next, we would solve by definition of the center of mass

We would also note that the masses of iron and aluminum are just the product of their length and linear density.

[tex]X_C_M[/tex]= [tex]\frac{8(g/cm). \frac{2500(cm^2)}{2} + 2.7 (g/cm). \frac{7500(cm^2)}{2} }{8(g/cm).50(cm) + 2.7(g/cm). 50 (cm)}[/tex]

= 37.62(cm)

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After plugging all the data into the equation, the result of the relative centrifugal force (RCF)  is measured in terms of g.

The relative centrifugal force (RCF) or the g force is the radial force generated by the spinning rotor as expressed relative to the earth's gravitational force.

RCF = ac/g

where;

[tex]RCF = \frac{\omega ^2 r}{g} = 1.118\times 10^{-5} \ (RPM)^2 r = 11.18r\ (RPM/1000)^2[/tex]

where;

Find the maximum RCF of the JS-4.2 rotor can be obtained from its maximum speed (4200 rpm) and its rmax (250 mm);

[tex]RCF = 11.18 \times 25\ cm \times (\frac{4200 \ RPM}{1000} )^2 = 4,930.3 \times g[/tex]

Thus, after plugging all the data into the equation, the result is measured in terms of g.

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The speed of the roller coater at the bottom of the hill is 31 m/s.

Apply the principle of conservation of mechanical energy as follows;

K.E(bottom) = P.E(top)

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

v = √(2 x 9.8 x 49)

v = 31 m/s

Thus, the speed of the roller coater at the bottom of the hill is 31 m/s.

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Answer:

[tex]1,\!000\; {\rm kg}[/tex].

Explanation:

The "[tex]g[/tex]" given in the question likely refers to the strength of the gravitational field. The standard unit of [tex]g[/tex] is [tex]{\rm m \cdot s^{-2}}[/tex], same as the standard unit of acceleration. However, since [tex]1\; {\rm N} = 1\; {\rm kg \cdot m \cdot s^{-2}[/tex], the standard unit of [tex]g[/tex] is equivalent to [tex]{\rm N \cdot kg^{-1}}[/tex].

For instance, the gravitational strength on the surface of the earth is approximately [tex]g = 10\; {\rm N \cdot kg^{-1}}[/tex]. However, the question did not specify the unit of this value.

If the mass of an object is [tex]m[/tex], the weight of that object would be [tex](\text{weight}) = m\, g[/tex] when the gravitational field strength around that object is [tex]g[/tex]. It is given that for the object in this question, [tex]m\, g = (\text{weight}) = 10,\!000\; {\rm N}[/tex] when [tex]g = 10\; {\rm N \cdot kg^{-1}}[/tex]. Therefore, the mass [tex]m\![/tex] of this object would be:

[tex]\begin{aligned}m &= \frac{(\text{weight})}{g} \\ &= \frac{10,\!000\; {\rm N}}{10\; {\rm N \cdot kg^{-1}}} \\ &= 1,\! 000\; {\rm kg}\end{aligned}[/tex].

Answer:

the total number of atoms of each element present is the same on both sides of the equation. (if I remember correctly)

The current made by the circuit produce this effect by generating a magnetic field that attracts the car magnetically to the crane lift and is denoted as option C.

This is a machine which is used to lift and lower objects which are most times heavy.

It employs the use of magnetic force as it is generated when the button is switched on in this scenario.

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Due a decrease in the velocity of the cart, the change in kinetic energy is negative

Kinetic energy is the energy of a body due to its motion.

Since the cart is slowed down, its velocity decreases and the change in kinetic energy is negative.

In conclusion, the change in kinetic energy of a body is affected by the mass and velocity of the body.

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If the current in a wire increases from 5A to 10A, the magnetic field generated will also be doubled.

Hi ! I will help you to discuss about "magnetic field around a conducting wire". A conducting wire that carried electric current can generate amount of magnetic fields. In a standard winding condition, the increase number of electric current will be proportional to the increase number of the generated magnetic field. In other condition, the increase in distance (between center of field with a point) will be inversly proportional to the increase in the generated magnetic field. So, the magnetic field that generated around a current-carrying wire can be expressed in the following equation.

[tex] \boxed{\sf{\bold{B = \frac{\mu_0 \cdot I}{2\pi \cdot d}}}}[/tex]

With the following condition:

We can assume that:

We know that :

What was asked ?

Step by step :

[tex] \sf{B_1 : B_2} [/tex]

[tex] \sf{\frac{\cancel{\mu_0} \cdot I_1}{\cancel{2\pi} \cdot d_1} : \frac{\cancel{\mu_0} \cdot I_2}{\cancel{2\pi} \cdot d_2}} [/tex]

[tex] \sf{\frac{I_1}{d_1} : \frac{I_2}{d_2}} [/tex]

[tex] \sf{\frac{I_1}{\cancel d} : \frac{I_2}{\cancel d}} [/tex]

[tex] \sf{I_1 : I_2} [/tex]

[tex] \boxed{\sf{\bold{1 : 2}}} [/tex]

From the above comparison, we can see that the ratio of the magnetic field at a point will be the same as the ratio of the current flowing through the conducting wire is 1 : 2. So, The magnetic field generated will also be doubled.

Farsightedness is corrected with a convex lens. The correct answer is a convex lens.

The center and edges of a convex lens alternate in thickness. Convergence or focus of the light rays caused by the passage of light through a convex lens aids in projecting the picture onto the retina of the eye. As a result, the person can see items in their immediate surroundings more clearly and the greater focus length of the eye is balanced.

In order to have a positive focal length, a convex lens must be thicker in the middle and narrower in the corners. A convex lens causes light to bend inward and towards its center as it travels through it. By bending the light, the focal point is brought closer to the lens and helps to focus the incoming light rays.

Hence, farsightedness is corrected with a convex lens. The correct answer is a convex lens.

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The magnitude of the force on the left-hand pole is mathematically given as

f'=0.167N

Q=45 degrees

Generally, the equation for Force is  mathematically given as

[tex]\frac{mg}{sin \theta}[/tex]

Therefore

[tex]F=\frac{17.1*10^{-3}*9.8}{sin45}[/tex]

F=0.237N

Considering horizontal axis or plane

f'-fcos=0

Therefore

f'=0.237*cos45

f'=0.167N

In conclusion, the slope

[tex]tan\theta= 30/30\\\\tan\theta=1\\\\\theta=45[/tex]

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The net force is the 10N force and its direction is towards F2 force.

The resultant force or the net force is the actual force that acts on a body. We are told that the two forces act in opposite directions hence the net force is F2 - F1  = 30 N - 20 N = 10 N.

ii) The direction of this net force is going to be towards the 30N force.

iii) If the body does not move under the application of these forces then the F1 force must be reinforced by another force which balances it against the F2 force.

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B. When the ball is rolling across the floor at a constant velocity, the change in its kinetic energy is zero.

The change in kinetic energy of an object is the dereference between the final kinetic energy and the initial kinetic energy.

ΔK.E = K.Ef - K.Ei

ΔK.E = 0.5m(vf² - vi²)

where;

At constant velocity, the initial velocity and final velocity are equal.

ΔK.E = 0.5m(0) = 0

Thus, when the ball is rolling across the floor at a constant velocity, the change in its kinetic energy is zero.

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1. The magnitude of the gravitational force between the Earth and an m is  54.1 N.

2. The magnitude of the gravitational force between the Moon and an m is  1.91 x 10⁻⁴ N.

3. The ratio of the magnitude of the gravitational force between an m on the surface of the Earth due to the Sun to that due to the Moon is 169.6.

The gravitational force between Earth and mass, m is calculated as follows;

F(Earth) = Gm₁m₂/R²

F(Earth) = (6.67 x 10⁻¹¹ x 5.5 x 5.98 x 10²⁴)/(6,370,000)²

F(Earth) = 54.1 N

F(moon) = Gm₁m₂/R²

F(moon) = (6.67 x 10⁻¹¹ x 5.5 x 7.36x 10²²)/(3.76 x 10⁸)²

F(moon) = 1.91 x 10⁻⁴ N

F(sun) = Gm₁m₂/R²

F(sun) = (6.67 x 10⁻¹¹ x 5.5 x 1.99x 10³⁰)/(1.5 x 10¹¹)²

F(sun) = 0.0324 N

= 0.0324/1.91 x 10⁻⁴

= 169.6

Thus, the magnitude of the gravitational force between the Earth and an m is  54.1 N.

The magnitude of the gravitational force between the Moon and an m is  1.91 x 10⁻⁴ N.

The ratio of the magnitude of the gravitational force between an m on the surface of the Earth due to the Sun to that due to the Moon is 169.6.

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The value of change in kinetic energy, ΔEk when a cart is being pulled forward by a hanging mass is Positive

In order words, ΔEk in the above question is positive

Kinetic energy can be defined as the energy a body possess when the body is in motion or due its motion

In conclusion, the value of change in kinetic energy, ΔEk when a cart is being pulled forward by a hanging mass is Positive

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The average speed of the round trip is 1.25 m/s.

The average speed of the round trip journey is obtained by taking the average of the forward and return speed of the journey.

Average speed = 1.0 + 1.5/2 = 1.25 m/s

In conclusion, the average speed of the round trip is the average of the initial and final speeds.

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The final position of Gilligan in kilometers and degrees south of east relative to the island is  9.07 km, 61.4° south of east.

A vector is a quantity or phenomenon that has two independent properties: magnitude and direction.

The term also denotes the mathematical or geometrical representation of such a quantity.

According to the question,

Suppose, the direction east as i, direction west as -i, direction north as j and direction south as j.

Therefore,

1. : 2.5 km 45° north of west

[tex]= 2.5 cos45 (-i) + 2.5 cos45 (j)\\ = -1.77(i) + 1.77(j)[/tex]

2. : 4.7 km 60° south of east

[tex]= 4.7 cos60 (i) + 4.7 sin60 (-j) \\= 2.35(i) - 4.07(j)[/tex]

3. : 5.1 km straight east

[tex]=5.1(i)[/tex]

4 : 7.2 km 55° south of west

[tex]= 7.2 cos55 (-i) + 7.2 sin55 (-j)\\ = -4.13(i) - 5.9(j)[/tex]

5: 2.8 km 5° north of east

[tex]= 2.8 cos5 (i) + 2.8 sin5 (j)\\= 2.79(i) + 0.24(j)[/tex]

The sum of all the above yields,

[tex]R = 4.34(i) + 7.96(-j)[/tex]

The magnitude of the resultant is:

[tex]|R| =\sqrt{4.34^{2} + (-7.96)^{2} }= 9.07[/tex]

The angle that the resultant makes is  as follows.

θ= [tex]tan^-^1(\frac{7.96}{4.34} )\\[/tex]

θ = 61.4°

Hence,

Final position relative to the island is 9.07 km, 61.4° south of east.

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A 150-g metallic rod with a specific heat of 0.11 cal/g.°C absorbs 82.5 calories of heat and its temperature increases from 20 °C to 25 °C.

It is the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).

A metallic rod of mass 150 g (m) absorbs 82.5 cal of heat (Q) and its temperature raises from 20 °C to 25 °C. We can calculate the specific heat (c) of the metal using the following expression.

Q = c × m × ΔT

c = Q / m × ΔT

c = 82.5 cal / 150 g × (25 °C - 20 °C) = 0.11 cal/g.°C

A 150-g metallic rod with a specific heat of 0.11 cal/g.°C absorbs 82.5 calories of heat and its temperature increases from 20 °C to 25 °C.

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Inertia is directly proportional to mass.

What is Walter Lewin famous for?

Walter Hendrik Gustav Lewin (born January 29, 1936) is a Dutch astrophysicist and former professor of physics at the Massachusetts Institute of Technology.

Lewin earned his doctorate in nuclear physics in 1965 at the Delft University of Technology and was a member of MIT's physics faculty for 43 years beginning in 1966 until his retirement in 2009.

According to Walter Levin,

The concept of moment of inertia is demonstrated by rolling a series of cylinders down an inclined plane.

Inertia is the resistance of any physical object to a change in its velocity. This includes changes to the object's speed, or direction of motion. An aspect of this property is the tendency of objects to keep moving in a straight line at a constant speed when no forces act upon them.

By rolling a series of cylinders down on an inclined plane , he demonstrated that a cylinder have a smooth friction.

He compares the rolling cylinder by using hollow cylinder and a heavy cylinder , and finalize the result that a hollow cylinder moves slowly but the heavy cylinder move faster.

Hence , By doing this experiment he explained about the inertia that Inertia depend on the mass of the object. As the heavy the object it will take more time to travel or move.

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