A school cafeteria spent $2,700 for ingredients necessary to prepare 450 meals. What is the rate spent per meal?

Answer:

DF= 20

Step-by-step explanation:

6x-4+3x-5=46

then you solve for x (x=5).

then plug it it : 3(5)+5=20

Value of DF is 20 unit

ED = 6x - 4

DF = 3x + 5

EF = 46

Value of DF

We know that;

EF = ED + DF

46 = 6x - 4 + 3x + 5

46 = 9x + 1

9x = 45

x = 5

Value of DF = 3x + 5

Value of DF = 3(5) + 5

Value of DF = 15 + 5

Value of DF = 20 unit

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Answer:

What solution set? I think you forgot to add a picture..

What solution do you need help with? :)

Answer:

y = - 3x² - 24x - 60

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (- 4, - 12 ), thus

y = a(x + 4)² - 12

To calculate a substitute (- 7, - 39) into the equation

- 39 = a(- 7 + 4)² - 12 ( add 12 to both sides )

- 27 = 9a ( divide both sides by 9 )

- 3 = a

y = - 3(x + 4)² - 12 ← in vertex form

Expand (x + 4)²

y = - 3(x² + 8x + 16) - 12

   = - 3x² - 24x - 48 - 12

y = - 3x² - 24x - 60 ← in standard form

   = - 3(x²

Answer:

$1200

Step-by-step explanation:

180 divided by 9 is 20, so they earned $20 per car washed. They want to wash 60 cars, and if they wash 60 cars they would earn $1200. (60 x 20)

Answer:

$1200

Step-by-step explanation:

Our revenue is directly proportional to the number of cars. That means our revenue is increasing at a constant rate, and thus, we are getting the same amount of money per car. That means we can find out how much we get from washing 1 car.

[tex]\frac{180}{9} = 20[/tex]

$20 per car.

If we washed 60 cars, we'd earn 60 * $20:

[tex]60*20 = 1200[/tex]

Answer: $1200

Answer:

x = -11

Step-by-step explanation:

-12 = x - 1

-12 + 1 = x

x = -11

Answer:

[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{x = - 11}}}}}[/tex]

Step-by-step explanation:

[tex] \bigstar{ \sf{ \: - 12 = x - 1}}[/tex]

[tex] \tt{Step \: 1 \: }[/tex] : Swap the sides of the equation

[tex] \hookrightarrow{ \sf{x - 1 = - 12}}[/tex]

[tex] \tt{Step \: 2 \: }[/tex] : Move 1 to right hand side and change it's sign

[tex] \hookrightarrow{ \sf{x = - 12 + 1}}[/tex]

[tex] \tt{Step \: 3}[/tex] : Calculate

Remember : The negative and positive integers are always subtracted but posses the sign of the bigger integer.

[tex] \hookrightarrow{ \sf{x = - 11}}[/tex]

The value of x = 11

Hope I helped!

Best regards! :D

~TheAnimeGirl

Answer:

The smallest of the integers is 7

Step-by-step explanation:

Let the integers be x, y and z

From the question, the integers are consecutive odd integers.

Hence,

If the smallest of the integers is x and the largest is z, then we can write that,

x + 2 = y and

y + 2 = z

Then, x + 2 + 2 = z

∴ x + 4 = z ....... (1)

From the question, four times the smallest decreased by 5 is the same as the largest increased by 12, that is

4x -5 = z + 12 ....... (2)

Put the value of z = x + 4 in equation (1) into equation (2),

We then get

4x - 5 = x + 4 + 12

4x - x = 4 + 12 + 5

3x = 21

x = 7

Hence, the smallest of the integers is 7

The other integers are 9 and 11 ( y= 9 and z = 11)

Answer:

the answer is 2.620

Step-by-step explanation:

the way u will get this is at the top there pattern is adding the bottom they are subtracting 2

Answer:  see proof below

Step-by-step explanation:

Given: A + B = C                → A = C - B

                                          → B = C - A

Use the Double Angle Identity:     cos 2A = 2 cos² A - 1

                                             → (cos 2A + 1)/2 = cos² A

Use Sum to Product Identity: cos A + cos B = 2 cos [(A + B)/2] · 2 cos [(A - B)/2]

Use Even/Odd Identity: cos (-A) = cos (A)

Proof LHS → RHS:

LHS:                     cos² A + cos² B + cos² C

[tex]\text{Double Angle:}\qquad \dfrac{\cos 2A+1}{2}+\dfrac{\cos 2B+1}{2}+\cos^2 C\\\\\\.\qquad \qquad \qquad =\dfrac{1}{2}\bigg(2+\cos 2A+\cos 2B\bigg)+\cos^2 C\\\\\\.\qquad \qquad \qquad =1+\dfrac{1}{2}\bigg(\cos 2A+\cos 2B\bigg)+\cos^2 C[/tex]

[tex]\text{Sum to Product:}\quad 1+\dfrac{1}{2}\bigg[2\cos \bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A-2B}{2}\bigg)\bigg]+\cos^2 C\\\\\\.\qquad \qquad \qquad =1+\cos (A+B)\cdot \cos (A-B)+\cos^2 C[/tex]

[tex]\text{Given:}\qquad \qquad 1+\cos C\cdot \cos (A-B)+\cos^2C[/tex]

[tex]\text{Factor:}\qquad \qquad 1+\cos C[\cos (A-B)+\cos C][/tex]

[tex]\text{Sum to Product:}\quad 1+\cos C\bigg[2\cos \bigg(\dfrac{A-B+C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B-C}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =1+2\cos C\cdot \cos \bigg(\dfrac{A+(C-B)}{2}\bigg)\cdot \cos \bigg(\dfrac{-B-(C-A)}{2}\bigg)[/tex]

[tex]\text{Given:}\qquad \qquad =1+2\cos C\cdot \cos \bigg(\dfrac{A+A}{2}\bigg)\cdot \cos \bigg(\dfrac{-B-B}{2}\bigg)\\\\\\.\qquad \qquad \qquad =1+2\cos C \cdot \cos A\cdot \cos (-B)[/tex]

[tex]\text{Even/Odd:}\qquad \qquad 1+2\cos C \cdot \cos A\cdot \cos B\\\\\\.\qquad \qquad \qquad \quad =1+2\cos A \cdot \cos B\cdot \cos C[/tex]

LHS = RHS: 1 + 2 cos A · cos B · cos C = 1 + 2 cos A · cos B · cos C   [tex]\checkmark[/tex]

Answer:

Hi there

Step-by-step explanation:

A linear function is a type of function and so must follow certain rules to be classified as a “function”. For example, functions can only have one output for each input. On the other hand, equations are just statements that make two things equal, like x = y or 52x = 100.

~Your Welcome! :)

Answer:4.0 and 6.0

Step-by-step explanation:

Answer:

A+3B=4+5r

Step-by-step explanation:

Given that,

A = 1+r+7r

B = 1-r

We need to find an expression that is equal to A+3B.

Putting the values of A and B in A+3B, we get :

A+3B = 1+r+7r + 3(1-r)

=1+8r+3-3r

=(1+3) +(8r-3r)

=4+5r

Hence, the values of A+3B equals 4+5r.

Answer:

x = -1

Step-by-step explanation:

x-7/4=-2

x-7=-8

x=-1

Answer:

6,000 feet

Step-by-step explanation:

Answer:

Step-by-step explanation:

Let the x be the number of months.

In x months, xian will have:

                       (52+16x) stamps

and kai will have:

                     (76+12x)stamps

To find out how many months they will have the same number of stamps, we evaluate the two expressions:

52+16x=76+12x

52+4x=76

4x=24

x=6

So xian and kai will have the same number of stamps after 6 months.

Using either of two expressions, each will have:

52+16(6)=76+12(6)= 148 stamps.

Would appreciate if you could give brainiest have a great day

Answer:

6 months

Step-by-step explanation:

56+ 12x = 80 + 8x

Answer:

[tex]x^{\frac{2}{3} }[/tex]

Step-by-step explanation:

Exponent Rules: [tex](b^m)^n = b^{mn}[/tex]

Exponent Rules: [tex]\frac{x^m}{x^n} = x^{m-n}[/tex]

Step 1: Write expression

[tex]\frac{\sqrt[4]{x^3} }{x^{\frac{1}{12} }}[/tex]

Step 2: Rewrite radical

[tex]\frac{{(x^3)^{\frac{1}{4} }} }{x^{\frac{1}{12} }}[/tex]

Step 3: Multiply powers (numerator)

[tex]\frac{{x^{\frac{3}{4} }} }{x^{\frac{1}{12} }}[/tex]

Step 4: Subtract powers

[tex]x^{\frac{2}{3} }[/tex]

Answer:

(-5,-3.5) is the midpoint

Step-by-step explanation:

See photo for the step-by-step explanation

Answer:

(4, -3.5)

Step-by-step explanation:

Answer:

5 paper clips each

Step-by-step explanation:

20/4 = 5

Answer:

They each get 5

Step-by-step explanation:

Answer:

-4x3=12

12÷-6=-2

hope this helps

Answer:

3/20

Step-by-step explanation:

Answer:

3.2

Step-by-step explanation:

3.2/1

Answer:

60yd

Step-by-step explanation:

First you multiply 3yd, and 6yd to get the area of 18 yards.

Second, you multiply the length of the triangle, so 6*7 is 42.

Finally you add both of the areas together to get the area of the full shape.

Answer:

Point A

Step-by-step explanation:

Answer:

4w + 3 = 2w + 7

-[2w]      -2w

-----------------------

2w + 3 = 7

       -3   -[3]

----------------------

2w  =  [4]

2w =  4

----    ----

2      [2]

w = [2]

Answer: x = 2

OA. The solution is

(Simplify your answer.)

Step-by-step explanation:

Answer:

22

Step-by-step explanation:

5/3=x-4/2

10=x-12

x=22

Answer:

[tex]3 \frac{2}{3}[/tex]

Step-by-step explanation:

5/3 = x - 4/2

5/3 + 4/2 = x

11/3 = x

x = 3 2/3

Answer:

Step-by-step explanation:

J

Answer:

you subtract the exponents