A scale factor that is less than 1, but greater than 0 is​

Answer:

$37.50

Step-by-step explanation:

{25(3)}0.50

-25 people times 3 cups for each person= 75

-0.50 times the amount of cups= 37.50

You would make 37 dollars and 50 cents.

Answer:

hope it works for u

Step-by-step explanation:

Given the length of the rectangle = l

the breadth  of the rectangle = b

perimeter of the rectangle = sum of length of all sides of the rectangle  

                                             = l+ b+ l+ b

                                             =2 l+2 b

                                             =2( l+ b)

∴ perimeter of the rectangle =2( l+ b)

as given perimeter = 1004 m

hence ,

2(l+ b)= 1004

(l+ b)=1004/2  = 502 m

Answer:

A, commutative

Step-by-step explanation:

Commutative property means that you can switch around the numbers, and get the same answer. However, the commutative property is only compatible for addition and multiplication. I.e. 2+6 equals 6+2, but 2-6 does not equal 6-2.

Answer:

C

Step-by-step explanation:

difference means minus

Answer:

B  

Step-by-step explanation:

7(300-28)=7(272)=1904

Answer:

a = 80

b = 40

c = 58

d = 19

e = 34

f = 36

Pls mark brainliest. Thanks!

Answer:

a = 80

b=40

c=58

d=19

e=34

f=36

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

(x-3)+7

Answer:

A

Step-by-step explanation:

b would +3 which is not right

c is also right...

d would be -x which is not right

Answer:

a

Step-by-step explanation:

Answer:

5 i believe correct me if im wrong

Step-by-step explanation:

To work this problem out you would do it as if it were just a simple equation

7x-19<16 (you would first have to add 19 to both sides)

7x<35 (then you would divide by 7 to get the variable by itself)

x<5 ( you answer would then be 5)

Answer:

Step-by-step explanation:

Tangent of 0 is always 0.

Answer:

A. President Millard Fillmore

Answer:

1.44

Step-by-step explanation:

1 box 18 candy bars each box 12.49

18 divide by 12.49 equals 1.44 each candy bars

Answer:

Step-by-step explanation:

[tex]b) (-8)*\frac{-2}{3}=\frac{(-8)*(-2)}{3}=\frac{16}{3}=5\frac{1}{3}\\\\c) \frac{-18}{3}= -6\\\\d) \frac{18}{-3}=\frac{6}{-1}= -6\\\\e) \frac{-18}{-3}=\frac{18}{3}= 6[/tex]

Answer:

33.8 ÷ 4 = 8.45

4 ÷ 33.8 = 0.118343195266

Step-by-step explanation:

Answer: -6

Step-by-step explanation: 7 + -6 = 1

:\

Answer:

x= -6

Step-by-step explanation:

x+7=1

1-7= - 6

SO , -6+7= 1

Total cost:-

[tex]\\ \sf\longmapsto 225/8(44.5)[/tex]

[tex]\\ \sf\longmapsto 28.1(44.5)[/tex]

[tex]\\ \sf\longmapsto 1251.5\$[/tex]

Recheck the question options

Answer:

b,y and m and x

Step-by-step explanation:

In order to solve for y, we need to do the inverse operation (basically the opposite) of multiplication, which is division. So therefore, we divide both sides by 18 in order to get [tex]y = 7[/tex].

We plug in and check.

[tex]18 * 7 = 126[/tex]

which is correct.

Answer:

-14c+10

Step-by-step explanation:

add the -8c and -6c together and add 7 and 3 together. number comes after the variable

Answer:

26

Step-by-step explanation:

f(-2)=4(-2)^2+10

=16+10

=26

Answer: (x+14)^2

Step-by-step explanation:

Answer:

-14, -12, 0, 6, 8

Step-by-step explanation:

Answer: -14, -12, 0, 6, 8

Step-by-step explanation:

This is correct because -14 is the number with the smallest value so it belongs last. Then comes -12, 0, 6, 8.

Hope this helps ;)

Answer:

Volume of the Tetrahedron T =[tex]\frac{1}{3}[/tex]

Step-by-step explanation:

As given, The tetrahedron T is bounded by the planes x + 2y + z = 2, x = 2y, x = 0, and z = 0

We have,

z = 0 and x + 2y + z = 2

⇒ z = 2 - x - 2y

∴ The limits of z are :

0 ≤ z ≤ 2 - x - 2y

Now, in the xy- plane , the equations becomes

x + 2y = 2 , x = 2y , x = 0 ( As in xy- plane , z = 0)

Firstly , we find the intersection between the lines x = 2y and x + 2y = 2

∴ we get

2y + 2y = 2

⇒4y = 2

⇒y = [tex]\frac{2}{4} = \frac{1}{2}[/tex] = 0.5

⇒x = 2([tex]\frac{1}{2}[/tex]) = 1

So, the intersection point is ( 1, 0.5)

As we have x = 0 and x = 1

∴ The limits of x are :

0 ≤ x ≤ 1

Also,

x = 2y

⇒y = [tex]\frac{x}{2}[/tex]

and x + 2y = 2

⇒2y = 2 - x

⇒y = 1 - [tex]\frac{x}{2}[/tex]

∴ The limits of y are :

[tex]\frac{x}{2}[/tex] ≤ y ≤ 1 - [tex]\frac{x}{2}[/tex]

So, we get

Volume = [tex]\int\limits^1_0 {\int\limits^{1-\frac{x}{2}}_{y = \frac{x}{2}}\int\limits^{2-x-2y}_{z=0} {dz} \, dy \, dx[/tex]

             = [tex]\int\limits^1_0 {\int\limits^{1-\frac{x}{2}}_{y = \frac{x}{2}}{[z]}\limits^{2-x-2y}_0 {} \, \, dy \, dx[/tex]

             = [tex]\int\limits^1_0 {\int\limits^{1-\frac{x}{2}}_{y = \frac{x}{2}}{(2-x-2y)} \, \, dy \, dx[/tex]

             = [tex]\int\limits^1_0 {[2y-xy-y^{2} ]}\limits^{1-\frac{x}{2}} _{\frac{x}{2} } {} \, \, dx[/tex]

             = [tex]\int\limits^1_0 {[2(1-\frac{x}{2} - \frac{x}{2}) -x(1-\frac{x}{2} - \frac{x}{2}) -(1-\frac{x}{2}) ^{2} + (\frac{x}{2} )^{2} ] {} \, \, dx[/tex]

             = [tex]\int\limits^1_0 {(1 - 2x + x^{2} )} \, \, dx[/tex]

             = [tex]{(x - x^{2} + \frac{x^{3}}{3} )}\limits^1_0[/tex]

             = 1 - 1² + [tex]\frac{1^{3} }{3}[/tex] - 0 + 0 - 0

             = 1 - 1 + [tex]\frac{1 }{3}[/tex] =  [tex]\frac{1}{3}[/tex]

So, we get

Volume =[tex]\frac{1}{3}[/tex]

The volume of Tetrahedron will be [tex]\frac{1}{3}[/tex] units.

Given,

The tetrahedron T is bounded by the planes,

[tex]x+2y+z=2......(1)\\ x=2y....(2)\\ x=0......(3) \\ z=0.....(4)[/tex]

From equation (1),

[tex]z=2-x-2y[/tex]

So the limits of z will be from 0 to [tex]2-x-2y[/tex].

Now, from equation (2),

[tex]y=\frac{x}{2}[/tex]

and from equation (1), putting z=0 we get,

[tex]x+2y=2\\y=1-\frac{x}{2}[/tex]

So the limits of y will be from [tex]\frac{x}{2}[/tex] to [tex]1-\frac{x}{2}[/tex].

On solving equation (1), for x we get

[tex]x+x+0=2[/tex] [tex](x=2y \ and \ z=0 )[/tex]

[tex]x=1[/tex].

So the limits of x will be from 0 to 1.

The volume of tetrahedron will be,

[tex]V=\int\limits^1_0 \, dx \int\limits^{1-\frac{x}{2} }_{\frac{x}{2} } \, dy \int\limits^{2-x-2y}_0 \, dz[/tex]

[tex]V=\int\limits^1_0 \, dx \int\limits^{1-\frac{x}{2} }_{\frac{x}{2} } \, dy [2-x-2y-0][/tex]

[tex]V=\int\limits^1_0 \, dx (1-2x+x^2)\\[/tex]

[tex]V=1-1+\frac{1}{3}[/tex]

[tex]V=\dfrac{1}{3}[/tex]

Hence the volume of tetrahedron is [tex]\frac{1}{3}[/tex] units.

For more details on Triple integration follow the link:

https://brainly.com/question/12632797

Answer:

[tex]73 {m}^{2} [/tex]

hope it's helpful ❤❤❤

THANK YOU.

Answer:

5d5d5e5dvg8v7c7c6c6x6x6x6c6c

Answer:

B

Step-by-step explanation:

Answer:

I believe the first answer is correct

Answer:

Subtract y from both sides of the equation.

x=8−y

2x+2y=16

Replace all occurrences of x with 8−y in each equation.

16=16

x=8−y

Remove any equations from the system that are always true.

x=8−y

Step-by-step explanation: