A sample of nitrogen gas occupies 1.83 L at 27 °C and 1.000 atm of pressure. What will

the volume be at -100 °C and the same pressure?​

1) State the equation that represents the chemical reaction

P2O5 + 3H2O → 2H3PO4

2) State the molar ratios: 1 mol P2O5 : 3 mol H2O : 2 mol H3PO4

3) Use the proportions 3molH2O / 2 mol H3PO4

0.729 mol H3PO4 * [ 3 mol H2O / 2 mol H3PO4] = 1.094 mol H2O

Answer: 1.094 mol of water

Answer: The answer that i got for this is 1.09 give the other kid the brainliest.

Explanation:

Based on the observations described, it is likely that the white solid is a true hydrate.

Water droplets on the side of the test tube: When heating a hydrate, the water molecules trapped within the crystal lattice are released as vapor. The presence of water droplets on the side of the test tube indicates that water was indeed released during the heating process.

Brownish residue: The brownish residue obtained after heating the solid suggests that the white solid might contain a transition metal ion. Transition metal ions can form complex compounds that exhibit different colors, including brown.

Dissolving in water: The brownish residue dissolves in water, indicating that it is soluble in the solvent.

Dark reddish-brown solution: The solution obtained after dissolving the brownish residue is described as dark reddish-brown. This color could be attributed to the formation of a complex compound between the transition metal ion in the residue and the water or other substances present in the solution.

Based on the observations of water droplets upon heating, the brownish residue that dissolves in water, and the resulting dark reddish-brown solution, it is likely that the white solid is a true hydrate.

The presence of water droplets and the dissolution of the residue suggest that water was released from the solid during heating, indicating the presence of water molecules within the crystal lattice.

The color change to brownish and the subsequent dark reddish-brown solution point towards the involvement of a transition metal ion, possibly forming a complex compound.

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Answer:

7. Ionization energy

8. Lattice energy

9. Free energy

10. Activation energy

Explanation:

I. Ionization energy: The energy required to convert a ground-state atom in the gas phase to a gaseous positive ion. Thus, it is the minimum energy required to remove or detach an electron from a neutral atom in a gaseous state. Generally, atoms with relatively large atomic radii tend to have a low ionization energy.

II. Lattice energy: The energy change that occurs in the conversion of an ionic solid to widely separated gaseous ions. This ultimately implies that, it is the energy generated during the conversion of an ionic solid into gaseous ions and as such is a measure of the cohesive force binding the ions of an ionic compound using the Born-Haber cycle.

III. Free energy: the energy in a chemical or physical change that is available to do useful work. Thus, it is a thermodynamic quantity that measures the maximum capacity of a system to do work at constant temperature and pressure.

IV. Activation energy: The energy required to form the transition state in a chemical reaction. When the activation energy of a reaction is low, the rate of the reaction would be faster. Therefore, an enzyme speeds or catalyzes the rate of a reaction by lowering its activation energy.

Option a, 1000 L of liquid water, is likely to have the highest heat capacity among the given options.

The heat capacity of a substance refers to the amount of heat energy required to raise the temperature of that substance by a certain amount. In general, substances with higher molar masses and larger numbers of atoms or molecules tend to have higher heat capacities.

Given the options provided:

a. 1000 L of liquid water has a higher heat capacity compared to the other options because water has a relatively high molar mass and specific heat capacity.

b. 10 g of sand generally has a lower heat capacity compared to water since sand has a lower molar mass and specific heat capacity.

c. 1 g of iron has a moderate heat capacity. While iron has a higher molar mass compared to sand, it typically has a lower specific heat capacity than water.

d. 5 g of glass generally has a lower heat capacity compared to water, as glass has a lower molar mass and specific heat capacity.

Therefore, option a, 1000 L of liquid water, is likely to have the highest heat capacity among the given options.

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If you take an antacid tablet, the ph in your stomach will increase. this means your stomach juice becomes more acidic - False

The stomach's pH will rise if a person takes an antacid pill. Antacids neutralise excess stomach acid to treat conditions like gastroesophageal reflux disease, heartburn, and acid indigestion. They usually consist of elements such as calcium carbonate, magnesium or aluminium hydroxide; when coupled with stomach acid, these elements react to form salts and water.

Antacids reduce the acidity of the stomach contents by raising the pH level and neutralising the stomach's acid. This can aid in reducing the symptoms brought on by excessive acid production. Therefore, it is untrue that taking an antacid increases the acidity of the stomach liquid.

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A buffer is primarily used to limit the pH change in a solution. Option A is correct.

A buffer is the solution which contains the weak acid and its conjugate base or weak base and its conjugate acid. It is designed to resist changes in pH when small amounts of acid or base are added to it.

When an acid or base is added to a buffer solution, the buffer components react with the added ions to minimize the impact on the solution's pH. If an acid is added, the buffer will react with the acid by accepting the H⁺ ions. If a base is added, the buffer will react with the base by donating H⁺ ions. In both cases, the buffer helps maintain the pH at a relatively stable level.

To prevent an acid from dissociating, is not accurate. A buffer does not prevent an acid from dissociating. In fact, the acid in a buffer solution is necessary to provide the conjugate base and maintain the buffer's pH buffering capacity.

To neutralize the pH of a solution, is also not accurate. A buffer does not neutralize the pH of a solution to a particular value. Instead, it resists significant changes in pH when small amounts of acid or base are added.

To prevent a salt from dissolving, is unrelated to the purpose of a buffer. A buffer is not used to prevent the dissolution of salts.

Hence, A. is the correct option.

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Answer:

q = mC∆T

q = heat = ?

m = mass = 6.30 g

C = specific heat = 0.385 J/g/deg

∆T = change in temperature = 32-20 = 12º

q = ((6.30 g)(0.385 J/g/deg)(12 deg) = 29.1 J (to 3 significant figures)

Explanation:

The rate of formation of SO₃ is 4.84 × 10⁻³ m/s. The correct option is d. 4.84 × 10⁻³ M/s.

To determine the rate of formation of SO₃, we need to consider the stoichiometry of the balanced equation. The coefficient of SO₃ is 2, which means that for every 1 mole of O₂ reacted, 2 moles of SO₃ are formed.

Given that the rate of O₂ loss is 2.42 × 10⁻³ m/s, we can use the stoichiometry to find the rate of formation of SO₃.

Rate of formation of SO₃ = (2 moles SO₃ / 1 mole O₂) × (2.42 × 10⁻³ m/s)

Rate of formation of SO₃ = 4.84 × 10⁻³ m/s

Therefore, the rate of formation of SO₃ is 4.84 × 10⁻³ m/s. The correct option is d. 4.84 × 10⁻³ M/s.

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Answer:

I'll do the first one for you. The reason why I'm not going to do the rest is because this is pretty simple stuff. I'll explain how I got the answer, please read it ^^ the rest of the problems should be a breeze.

1. 5.454285714285714 liters, or approx. 5.45 liters

Explanation:

P1V2 = P2V2

P1 refers to the original pressure. V1 refers to the original volume, or the amount of space the gas takes up.

P2 and V2 refer to the final pressure or volume, accordingly.

You insert the values into the equation, like so:

(8.3)(46) = (70)(x)

Now, multiply.

381.8 = 70x

Use inverse operations to find the value of x. Divide 381.8 by 70 to isolate x.

381.8/70 = x

5.454285714285714 = x

The volume of the gas when the pressure is increased to 70.0 mm Hg is approximately 5.45 liters. Don't forget about the units at the end, when you write your final answer.

Important! When pressure increases, volume decreases, and vice versa. Volume and pressure for gases are inversely proportional. So even though the pressure increased, that doesn't mean the volume increases, too.

You can check your answers easily!

Just multiply your final answer by its corresponding pressure or volume and compare it to the other. I hope that made sense. Like so:

5.454285714285714 x 70 = 381.8

8.3 x 46 = 381.8

That makes P1V2 DOES equal P2V2, and your answer is correct.

I hope this helped in time for you to submit it before the deadline! Good luck.

Tips!

For #2: I'm pretty sure the mentioning of the temperature (25.0 °C) doesn't matter. You can ignore it, it won't affect your calculations.

For #4: the standard pressure in mm Hg (millimeters of mercury) is 760 mm Hg. That's your P2.

Water molecules that surround the metal ions act as weak Brønsted-Lowry acids and donate protons to the solution, increasing its acidity.

Hydrated transition metal ions typically produce solutions that are acidic. Transition metal ions are elements from the transition series that are capable of forming coordination complexes that have characteristic colors, and they exhibit a wide range of oxidation states and show various magnetic properties.In addition, when transition metals react with water, they create hydrated metal ions, which produce acidic solutions. This is because water molecules that surround the metal ions act as weak Brønsted-Lowry acids and donate protons to the solution, increasing its acidity.Therefore, the correct answer is (a) acidic.

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The V/Q (Ventilation/Perfusion) ratio of a normal upright lung is 0.8, which indicates that ventilation is less than perfusion.

The V/Q ratio is a measure of the ratio between the amount of ventilation (airflow) reaching the alveoli of the lungs and the amount of blood perfusion (blood flow) in the pulmonary capillaries. In a normal upright lung, the V/Q ratio is 0.8, which means that ventilation is less than perfusion.

Ventilation refers to the movement of air into and out of the alveoli, allowing for gas exchange. Perfusion, on the other hand, refers to the blood flow in the pulmonary capillaries, which carries deoxygenated blood to the lungs for oxygenation.

A V/Q ratio of 0.8 indicates that there is relatively less airflow (ventilation) compared to blood flow (perfusion) in the lung. This can occur in certain areas of the lung where blood flow is relatively high compared to the amount of air reaching those regions. Factors such as gravity and differences in regional blood flow can contribute to this imbalance in ventilation and perfusion.

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Answer:

Report of the climate change can help the people. As when people wants to go for  picnics or somewhere else. They did not have any idea that what will be the climate when they go. Report of climate change help him to choose the right time for going on picnics or  somewhere else.

Answer:

The report mentioned ways that people’s lives may change because of climate change, such as rising sea levels, reduced crop efficiency, and heat waves. This information may encourage the public to change the way they use energy, for example how they heat their homes or power their cars.

Explanation:

Answer:

For A: The molarity is the solution 9.706 M

For B: The molarity of the solution is 10.91 M.

For C: The molarity of the solution is 1.78 M.

Explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L.

The formula used to calculate molarity:

[tex]\text{Molarity of solution}=\frac{\text{Number of moles of solute}}{\text{Volume of solution (L)}}[/tex]                 ......(1)

For A:

Number of moles = 3.30 moles

Volume of solution = 0.340 L

Plugging values in equation 1:

[tex]\text{Molarity of solution}=\frac{3.30 mol}{0.340 L}=9.706 mol/L[/tex]

For B:

Number of moles = 6.00 moles

Volume of solution = 550 mL = 0.550 L        (Conversion factor: 1 L = 1000 mL)

Plugging values in equation 1:

[tex]\text{Molarity of solution}=\frac{6.00 mol}{0.550 L}=10.91 mol/L[/tex]

For C:

Number of moles = 0.0160 moles

Volume of solution = 9.00 mL = 0.009 L

Plugging values in equation 1:

[tex]\text{Molarity of solution}=\frac{0.0160 mol}{0.009 L}=1.78 mol/L[/tex]

Answer:

D

Explanation:

It states that D has oxygen, and is closer to the Sun.

Hope this helped, and please mark as Brianliest <3

Answer:

I am pretty sure it is B

Explanation:

The others would either burn u like a crispy chicken nugget or freeze you like a popsicle

Answer

Plants can respond to the change of season by losing their leaves, flowering, or breaking dormancy. Plants go through seasonal changes after detecting differences in day length.

Explanation:

The half-life of the radioisotope is approximately 14.72 hours, which is closest to option d) 1.44 hr (1 hour and 26.4 minutes).

Radioisotopes are radioactive isotopes of elements that are used in a variety of applications, including medical imaging and cancer treatment. They are also used in geology and archaeology to determine the age of rocks and artifacts. The activity of a radioisotope is the rate at which it decays, measured in counts per minute (CPM). The half-life of a radioisotope is the amount of time it takes for half of the atoms to decay.

Given that the activity of a radioisotope is 3000 counts per minute at one time and 2736 counts per minute 48 hours later, we can use the formula A = A₀ (1/2)^(t/T) to find the half-life of the radioisotope.

Where A is the activity after time t, A₀ is the initial activity, T is the half-life, and t is the time elapsed.

Substituting the values given in the problem, we get:

2736 = 3000 (1/2)^(48/T)

Dividing both sides by 3000, we get:

0.912 = (1/2)^(48/T)

Taking the natural logarithm of both sides, we get:

ln 0.912 = ln (1/2)^(48/T)

Using the rule that ln (a^b) = b ln a, we get:

ln 0.912 = (48/T) ln (1/2)

Dividing both sides by ln (1/2), we get:

ln 0.912 / ln (1/2) = 48/T

Using a calculator to evaluate the left-hand side, we get:

3.26 = 48/T

Multiplying both sides by T, we get:

3.26T = 48

Dividing both sides by 3.26, we get:

T ≈ 14.72 hours

Therefore, the half-life of the radioisotope is approximately 14.72 hours, which is closest to option d) 1.44 hr (1 hour and 26.4 minutes).

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The noble gas expected to show the largest deviations from the ideal gas behavior is Xenon (Xe).The molar volume of a gas at STP is 22.4 L. This is because 1 mole of gas occupies 22.4 L of volume at 0°C and 1 atm pressure

The ideal gas behavior is only possible at low pressures and high temperatures. A gas can be assumed to be ideal if its atoms or molecules are far apart and there is no interaction between them. Since noble gases are monatomic gases and their atoms are quite far apart, they are expected to behave like ideal gases.However, xenon is the largest of all noble gases, and its atoms have large sizes and masses. As a result, they experience stronger attractive forces between atoms than the other noble gases, leading to deviations from ideal gas behavior.The molar volume of a gas at STP is 22.4 L. This is because 1 mole of gas occupies 22.4 L of volume at 0°C and 1 atm pressure. Hence, the correct answer is option D) 22.4.

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The Required Correct Answer for the rate of appearance of N2 is 1.4 g/s.

Explanation : Given reaction is2NH3(g) → N2(g) + 3H2(g)The stoichiometric coefficients of NH3 and N2 in the balanced chemical equation are 2 and 1 respectively, which indicates that one mole of N2 is produced for every 2 moles of NH3 consumed.The rate of disappearance of NH3 is 1.7 g/s.

Number of moles of NH3 disappearing per second can be determined by the following formula:n = m/MwWhere,n = number of moles of NH3 disappearing per secondm = mass of NH3 disappearing per secondMw = molecular weight of NH3.The molecular weight of NH3 is 17 g/mol.

So,m/Mw = 1.7/17= 0.1 mole/sNow we know that 2 moles of NH3 produce 1 mole of N2. Hence, 0.1 mole/s of NH3 will produce (1/2) × 0.1 = 0.05 mole/s of N2The mass of N2 produced can be calculated by using the formula:m = n × MwThe molecular weight of N2 is 28 g/mol.So, m = 0.05 × 28= 1.4 g/s

Therefore, the rate of appearance of N2 is 1.4 g/s.

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Answer:

Molecular mass is a number equal to the sum of the atomic masses of the atoms in a molecule.

Explanation:

The molecular mass gives the mass of a molecule relative to that of the 12 C atom, which is taken to have a mass of 12. Hence why Molecular mass is a number equal to the sum of the atomic masses of the atoms in a molecule.

Answer:

They study different way people have died or could die to better aid investigators.

Explanation:

Answer:

second opinion is correct

Answer:

E

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E

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E

E

E

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BRAINLIEST PLEASE

Answer:

cornea, pupil, lens, vitreous humor

Answer:

cornea, pupil, lens, vitreous humor 

Explanation:

Answer:

while atoms form together, they percentage their outermost electrons to create more sustainable strength states. This sharing bonds the atoms into an ionic shape or a molecule

Explanation:

i hope this help a little

A laboratory fume hood, also known as a fume cupboard or fume cabinet, is a specially designed enclosure used in laboratories to protect workers from exposure to hazardous fumes, gases, vapors, or dust. The correct answer is:

1. Open the sash as much as possible

2. Work at least 25 cm inside the hood

4. Place objects to one side-work on the other side

5. Use a raised shelf along the back of the hood.

A fume hood typically consists of a transparent sash or door at the front that can be opened or closed, allowing access to the work area inside the hood. The hood is connected to an exhaust system that draws air through the hood, creating a negative pressure inside and preventing the escape of hazardous substances into the laboratory environment.

Opening the sash allows for better airflow and reduces the buildup of hazardous substances inside the hood. Working inside the hood ensures that you are within the protected area where airflow is present. Placing objects to one side of the hood and working on the other side helps maintain a clear and unobstructed airflow path. Using a raised shelf along the back of the hood allows for better organization of materials and equipment, keeping them within reach but away from the front of the hood.

Therefore, the correct options are:

1. Open the sash as much as possible

2. Work at least 25 cm inside the hood

4. Place objects to one side-work on the other side

5. Use a raised shelf along the back of the hood.

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Best practices for using a lab fume hood include not opening the sash more than necessary, working at least 25 cm inside the hood, using slow, steady movements, arranging objects to one side, and using a raised shelf along the back of the hood. Much like fume hoods, biological safety cabinets use containment and directional airflow for safety.

When using a laboratory fume hood, it's crucial to observe best practices to ensure safety. The best practices include:

Laboratory biological safety cabinets, or BSCs, also use a similar principle of containment and directional airflow to protect lab workers and the environment from exposure to hazards. For instance, Class I BSCs use air intake filters to prevent environmental contaminants from entering the workspace and air exhaust filters to contain pathogens within the hood.

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Answer:

31.3 mL

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2HCl + Ba(OH)₂ —> BaCl₂ + 2H₂O

From the balanced equation above,

The mole ratio of the acid, HCl (nₐ) = 2

The mole ratio of the base, Ba(OH)₂ (n₆) = 1

Finally, we shall determine the volume of the acid need for the reaction as follow:

Molarity of acid, HCl (Mₐ) = 0.062 M

Mole ratio of the acid, HCl (nₐ) = 2

Volume of base, Ba(OH)₂ (V₆) = 19.4 mL

Molarity of base, Ba(OH)₂ (M₆) = 0.050 M

Mole ratio of the base, Ba(OH)₂ (n₆) = 1

Volume of acid, HCl (Vₐ) =?

MₐVₐ / M₆V₆ = nₐ / n₆

0.062 × Vₐ / 0.050 × 19.4 = 2/1

0.062 × Vₐ / 0.97 = 2

Cross multiply

0.062 × Vₐ = 0.97 × 2

0.062 × Vₐ = 1.94

Divide both side by 0.062

Vₐ = 1.94 / 0.062

Vₐ = 31.3 mL

Thus, the volume of the acid needed is 31.3 mL