A sample of hydrogen gas collected by displacement of water occupied 30mL at 24 C on a day when the barometric pressure was 736t orr. What volume would the hydrogen occupy if it were dry and at STP? The vapor pressure of water at 24 C is 22.4 torr

Answers

Answer 1

Answer:

[tex]v_2=6,48*10^{-4}L[/tex]

Explanation:

From the question we are told that:

Volume of hydrogen  [tex]V_1=30mL=>30*10^{-3}[/tex]

Temperature [tex]T_1=24C=>24+273=>297k[/tex]

Pressure of water [tex]P_1=22.4torr=>\frac{22.4}{760}=0.0295atm[/tex]

Let

STP(Standard Temperature and pressure)

 [tex]T_2=273K[/tex]

 [tex]P_2=1atm[/tex]

Generally the equation for ideal gas is mathematically given by

 [tex]\frac{p_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]

Therefore

 [tex]v_2=\frac{P_1v_1T_2}{T_1P_2}[/tex]

 [tex]v_2=\frac{0.0295*30*10^{-3}*273}{297*1}[/tex]

 [tex]v_2=6.48*10^{-4}L[/tex] (at STP(Standard Temperature and pressure))


Related Questions

I have to do this for homework please help :)

Answers

Answer:

1..... nucleus

2......electron cloud

3.......protons

4........Neutrons

5..........electron

6............electrons

7...............Isotopes

8.....,...........ions

9....................charge

which atom has the highest ionization energy? magnesium, barium, calcium, beryllium

Answers

Explanation:

Beryllium has the highest Ionization energy

Energy that is made from the power of moving water
a
b
ОООО
wind
hydroelectric
coal
с
d
biomass

Answers

Hydroelectric energy is produced.

Predict the total pressure in Container C if the initial pressure in
Container A was tripled and Container B was reduced by one-third then
mixed together in Container C.
SHOW ALL WORK

Answers

Answer:

[tex]98 \times x6x \geqslant {36461 { {3 \frac{ \sqrt[ |?| ]{?} }{?} }^{2} }^{?} }^{2} [/tex]

okay

How many grams of caffeine should we prepare in a 10 mL standard of 3 mm
a) 0.05 grams
b) 2.57 grams
c) 0.00583 grams
d) 5 grams

PLEASE HELP!

Answers

Answer:

if it is espresso(1 shot), the coffee content to be considered is: (77/44)*(10/3)= 5.833= 0.005833 grams

Explanation:

Find the molecular weight of CO

Answers

Answer:

The molecular weight of CO is 28.01g/mole.

The molecular mass of CO is 12.01 + 16.00 or 28.01 g/mol.

What is diffusion? How does the motion of gas molecules explain how a gas diffuses throughout a room?

Answers

Answer:

Diffusion in gases

Diffusion is driven by differences in concentration. When chemical substances such as perfume are let loose in a room, their particles mix with the particles of air. The particles of smelly gas are free to move quickly in all directions

Explanation:

hope this helps

An isotope undergoes radioactive decay. The new isotope that forms has an atomic number that is 2 less than the original isotope’s.
Which kind of decay has occurred, and how do you know?
1)alpha decay because alpha particles have a large mass
2)beta decay because beta particles can have negative charge
3)alpha decay because alpha particles have two protons and two neutrons
4)gamma decay because gamma rays are photons

Answers

Answer:

3)alpha decay because alpha particles have two protons and two neutrons

Explanation:

When a radioactive isotope undergoes a decay, a daughter nucleus or nuclei is/are formed. The mass number and atomic number of the daughter nucleus gives us an idea of the nature of radioactive decay that the parent nucleus underwent.

If the daughter mass number of the daughter nucleus is four units less than that of the parent nucleus and the atomic  number of the daughter nucleus is two units less than that of the parent, then such a decay is an alpha decay.

An alpha particle has two protons and two neutrons thus it has a mass number of 4 and an atomic number of two.

If hydrochloric acid is obtained commercially at a concentration of 12.1M, how many milliliters of 12.1M HCl(aq) must be used to prepare 2.00x103mL of 0.500M HCL(aq)?

Answers

Answer:

[tex]V_1=82.6mL[/tex]

Explanation:

Hello there!

In this case, according to this question, we will need to deal with this dilution problem, because it is asking for the volume of a 12.1-M stock solution of HCl. In such a way, we can use the following equation, under the assumption of no change in the number of moles in the solution:

[tex]M_2V_2=M_1V_1[/tex]

Thus, we solve for the initial volume, V1, as shown below:

[tex]V_1=\frac{M_2V_2}{M_1}[/tex]

And plug in the initial concentration and final concentration and volume to obtain:

[tex]V_1=\frac{2000mL*0.500M}{12.1M}\\\\V_1=82.6mL[/tex]

Regards!

A pan containing 20.0 grams of water was allowed to cool from a temperature of 95.0 °C. If the amount of heat released is 1,200 joules, what is the approximate final temperature of the water? (5 points)
75 °C
78 °C
81 °C
87 °C

Answers

Answer:

78° C.

Explanation:

The final temperature of water is 81℃ , if it is allowed to cool from a temperature of 95  and  it releases heat of 1200J.

What is the final temperature of water?

In the following question we will apply specific heat Capacity equation

q=mct Δt

q= 1200J   m= 20 g c= 4.186  T₁= 95 ℃

1200= 20 ✕4.186(95-T₂)

T₂=81℃

Hence, The water cools to 81℃ temperature

Learn about specific heat capacity

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Molar mass of propan-1-ol

Answers

Answer:

60g/mol.

Explanation:

TO FIND :-

Molar mass of Propan-1-ol

FACTS TO KNOW BEFORE FINDING ANSWER :-

Chemical formula of Propan-1-ol = CH₃CH₂CH₂OH [or] C₃H₈OMolar mass of C = 12g/mol.Molar mass of H = 1g/mol.Molar mass of O = 16g/mol.

SOLUTION :-

Molar mass of C₃H₈O = 3(Molar mass of C) + 8(Molar mass of H) + 1(Molar mass of O)

Molar mass of C₃H₈O = (3×12) + (8×1) + 16 = 36 + 8 + 16 = 60g/mol.

6 a 100 sample of Au - 198 Au 198 be? Decays to 3.125 g in 13.5 days, what would the half-life of au198 be?

Answers

Answer:

Half-life = 2.7 days

Explanation:

The radioactive decay of an isotope follows the equation:

Ln[A] = -kt + ln[A]₀

Where [A] could be taken as the amount of A after t time, k is decay constant, [A]₀ initial amount of A.

Replacing to solve k:

Ln[3.125g] = -k*13.5days + ln[100g]

-3.465736 = -k*13.5days

k = 0.2567days⁻¹

Half-life is:

half-life = ln2 / k

Half-life = 2.7 days

A gas has an initial pressure of 120 kPa, a volume of 23 liters, and a temperature of 20°C. If the pressure is raised to 150 kPa the new volume is 17 liters, what is the new temperature of the gas? *
A.100 K
B.0.003 K
C.270.7 K
D.18.4 K

Answers

Answer: C 270.7 k is the temperature of the gas

Which of the following MOST LIKELY causes the rate of a chemical reaction to increase?

Decreasing the reaction temperature

Grinding up a solid reactant

Adding an inhibitor

Using a larger container

Answers

Explanation:

Reactant concentration.

Increasing the concentration of one or more reactants will often increase the rate of reaction. This occurs because a higher concentration of a reactant will lead to more collisions of that reactant in a specific time period.

How many elements in a periodic table?

Answers

There are 118 elements in the periodic table.

I NEED HELP WITH CHEM PLEASE HAVE A DECENT ANSWER

Answers

Answer:

x is HCl because pH = 2 (acid and it reacted with Mg plus it turned litmus paper to red)

y is NaOH because pH = 10 (base and turned litmus paper to blue)

z is NaCl because pH = 7 (neutral and no reaction to litmus paper and Mg)

CaCl2
Ca +
CI2
Balance this equation

Answers

To balance Ca + Cl2 = CaCl2 you'll need to be sure to count all of atoms on each side of the chemical equation.

Once you know how many of each type of atom you can only change the coefficients (the numbers in front of atoms or compounds) to balance the equation for Calcium + Chlorine gas.

chemical formula for diethyl ester dimethyl ammonium chloride
-PLEASE HELP ASAP

Answers

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The ____ allows you to compare the elements and understand their properties​

Answers

Answer:

Periodic Table

hope this helps

have a good day :)

Explanation:

The periodic table allows you to compare the elements and understand their properties​.

What is periodic table?

Periodic table is a tabular arrangement of elements in the form of a table. In the periodic table, elements are arranged according to the modern periodic law which states that the properties of elements are a periodic function of their atomic numbers.

It is called as periodic because properties repeat after regular intervals of atomic numbers . It is a tabular arrangement consisting of seven horizontal rows called periods and eighteen vertical columns called groups.

Elements present in the same group have same number of valence electrons and hence have similar properties while elements present in the same period show gradual variation in properties due to addition of one electron for each successive element in a period.

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A gas' pressure is 850 torr at 47 degrees. At what temperature will the pressure be 655 torr?

Answers

Answer:

From Pressure Law

P1/T1 = P2/T2

Changing our temp to kelvin

T1 = 47 +273 = 320K

We're looking for T2

Making T2 the subject

T2 =P2 x T1 / P1

= 655 x 320/850

T2 = 246K

If your end product is 1.5 moles of KMnO4, how many moles of manganese oxide were used in the reaction?

The equation for the production of potassium permanganate is as follows:

2 MnO2 + 4 KOH + O2 → 2 KMnO4 + 2 KOH + H2
You must show all work

Answers

Answer:

1.5 moles of KMnO4 will be produced from 1.5 moles of MnO2

Explanation:

The balanced equation of this chemical reaction is

2 MnO2 + 4 KOH + O2 → 2 KMnO4 + 2 KOH + H2

2 moles of MnO2 produces 2 moles of   KMnO4

That means 1 moles of KMnO4 will be produced from 1 moles of MnO2

Hence, 1.5 moles of KMnO4 will be produced from 1.5 moles of MnO2

The moles of manganese oxide were used in the reaction is 1.5 moles.

What is stoichiometry?

Stoichiometry of any reaction tells about the relative amount of species present before and after the chemical reaction.

Given chemical reaction is:

2MnO₂ + 4KOH + O₂ → 2KMnO₄ + 2KOH + H₂

From the stoichiometry of the reaction, it is clear that same moles of manganese oxide and potassium permanganate is involved in the reaction.

2 moles of KMnO₄ = produce by 2 moles of MnO₂

1.5 moles of KMnO₄ = produce by 2/2×1.5=1.5 moles of MnO₂

Hence, required moles are 1.5 moles.

To know more about moles, visit the below link:

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How many moles of sulfur S, will react with six moles of aluminum?

Answers

Answer:

9 moles of Sulphur will react with 6moles of Aluminum

Which of the following best describes density?

- the relationship between length and mass

- the relationship between volume and area

- the relationship between mass and area

- the relationship between mass and volume

Answers

Answer:

the relationship between mass and volume

How do I calculate the pOH of a Solution at 25℃ with a [OH-1] = 6.5 x 10-9 M and state whether the Solution is Acidic, Basic, or Neutral?

Answers

Answer:

pOH = 8.19

Acidic solution (pH < 7.0)

Explanation:

The pOH of the solution is defined as:

pOH = - log [OH⁻]

Since we have [OH⁻] = 6.5 x 10⁻⁹ M, we calculate the pOH as follows:

pOH = - log (6.5 x 10⁻⁹) = 8.19

To know if the solution is acidic, neutral or basic, we have to calculate the pH from the value of pOH:

pH + pOH = 14

⇒ pH = 14 - pOH = 14 - 8.19 = 5.81

The solution is acidic because pH < 7.0.

Someone please help me

Answers

Answer:reflection

Explanation:

The combustion of acetylene gas is represented by this equation: 2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)
How many moles of H2O are produced when 64.0 g C2H2 burn in oxygen?

M.M

H2O = 18.02 g/mol

C2H2 = 26.04 g/mol


2.46 moles H2O
5.13 moles H2O
4.92 moles H2O
2.00 moles H2O

Answers

Answer:

Approximately [tex]2.46\; \rm mol[/tex].

Explanation:

Make use of the molar mass data ([tex]M({\rm C_2H_2}) = 26.04\; \rm g \cdot mol^{-1}[/tex]) to calculate the number of moles of molecules in that [tex]64.0\; \rm g[/tex] of [tex]\rm C_2H_2[/tex]:

[tex]\begin{aligned}n({\rm C_2H_2}) &= \frac{m({\rm C_2H_2})}{M} \\ &= \frac{64.0\; \rm g}{26.04\; \rm g\cdot mol^{-1}}\approx 2.46\; \rm mol\end{aligned}[/tex].

Make sure that the equation for this reaction is balanced.

Coefficient of [tex]\rm C_2H_2[/tex] in this equation: [tex]2[/tex].

Coefficient of [tex]\rm H_2O[/tex] in this equation: [tex]2[/tex].

In other words, for every two moles of [tex]\rm C_2H_2[/tex] that this reaction consumes, two moles of [tex]\rm H_2O[/tex] would be produced.

Equivalently, for every mole of [tex]\rm C_2H_2[/tex] that this reaction consumes, one mole of [tex]\rm H_2O[/tex] would be produced.

Hence the ratio: [tex]\displaystyle \frac{n({\rm H_2O})}{n({\rm C_2H_2})} = \frac{2}{2} = 1[/tex].

Apply this ratio to find the number of moles of [tex]\rm H_2O[/tex] that this reaction would have produced:

[tex]\begin{aligned}n({\rm H_2O}) &= n({\rm C_2H_2}) \cdot \frac{n({\rm H_2O})}{n({\rm C_2H_2})} \\ &\approx 2.46\; \rm mol \times 1 = 2.46\; \rm mol\end{aligned}[/tex].

What type of reaction is Al + KOH +H2O = K[Al(OH)4] + H2

Answers

Answer:

Al + 2 KOH + 6 H 2O → 3 H 2 + 2 K[Al(OH) 4] This is a complexation reaction: K[Al(OH) 4] is the formed complex. ; Silvery-white, malleable, ductile, odorless metal.

Explanation:

I hope this help

Use an example of how we use an informal kind of scientific method in our everyday lives

Answers

Answer:

baking cookies

Explanation:

One example of using a scientific method is baking cookies. You make a hypothesis that you cookies will be done in 15 minutes. Then, after 15 minutes, you see that either your hypothesis was correct and you cookies are perfect or you need to bake them longer making you hypothesis incorrect. (please change the wording up a bit if you want. i tried to make it make the most sense)

Answer:

Explanation:

When you loose your phone. You try to remember where you last used your phone, and question yourself where you might have left it. If you say that you probably left it in the kitchen, that would be like your hypothesis. Then you go look for it where you thought you left it which would be your experiment. If maybe it is not there that would be like your conclusion so you would reject your hypothesis because it was wrong. Then you try the scientific method again but with a different hypothesis, like that maybe you left it in the living room. You do your experiment which is when you go look for it. In the conclusion if your hypothesis was right you accept your hypothesis. That can be an example of how we use the scientific method in our everyday lives.

A Cartesian Diver demonstrates which of the following?
A. the inverse relationship of Boyle's law
B. the direct relationship of Boyle's law
C. squeezing the bottle, pushes the test tube down.
D. the density of a gas is less than the density of water.

Answers

Answer:

(a) The inverse relationship of Boyle's law.

Explanation:

A Cartesian diver is used in scientific experiments to demonstrate the certain principles in science such as;

i. The principle of floatation or the Archimedes' principle.

ii. The implication of the ideal gas law as seen in, for example, Boyle's law and pressure law,

iii. Pascal's principle.

The diver demonstrates that given a large soft drink bottle containing water and a medicine dropper at its top, squeezing the bottle pushes the dropper down to the bottom. When the squeezing stops, the dropper comes back to the top again.

Now using this to demonstrate Boyle's law (which shows the relationship between pressure and volume where increase in one results in the decrease in the other), when the bottle is squeezed (which means pressure is increased on the bottle), the water is forced into the medicine dropper thereby decreasing the volume of air in the dropper. Removing pressure on the bottle produces an opposite effect.

An engine operates on a Carnot cycle that uses 1mole of an ideal gas as the
working substance and operates from a most compressed stage of 100 Nm and
327 K. It expands isothermally to a pressure of 90 Nm and then adiabatically to a
most expanded stage of 27 K. Calculate the AU, 9, and w for each step. Calculate
the net work done and the efficiency of the cycle [Cv,m for the gas) is 25 J/k/mol.​

Answers

Answer:

Step 1;

q = w = -0.52571 kJ, ΔS = 0.876 J/K

Step 2

q = 0, w = ΔU = -7.5 kJ, ΔH = -5.00574 kJ

Explanation:

The given parameters are;

[tex]P_i[/tex] = 100 N·m

[tex]T_i[/tex] = 327 K

[tex]P_f[/tex] = 90 N·m

Step 1

For isothermal expansion, we have;

ΔU = ΔH = 0

w = n·R·T·ln([tex]P_f[/tex]/[tex]P_i[/tex]) = 1 × 8.314 × 600.15 × ln(90/100) = -525.71

w ≈ -0.52571 kJ

At state 1, q = w = -0.52571 kJ

ΔS = -n·R·ln([tex]P_f[/tex]/[tex]P_i[/tex]) = -1 × 8.314 × ln(90/100) ≈ 0.876

ΔS ≈ 0.876 J/K

Step 2

q = 0 for adiabatic process

ΔU = 25×(27 - 327) = -7,500

w = ΔU = -7.5 kJ

ΔH = ΔU + n·R·ΔT

ΔH = -7,500 + 8.3142 × 300 = -5,005.74

ΔH = ΔU = -5.00574 kJ

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