A pumpkin is thrown horizontally off of a building at a speed of 2.5 — and travels a horizontal distance of
12 m before hitting the ground. We can ignore air resistance.
What is the vertical velocity when it hits the ground
Answer:
Explanation:
This is a missile throwing exercise, let's find the distance
x = v₀ₓ / t
t = v₀ₓ / x
let's calculate
t = 2.5 / 12
t = 0.2083 s
as time is a scalar this is the same value for descends to the ground
y = v_{oy} t - 1/2 g t²
we calculate
v_y = 0 - 9.8 0,2083
v_y = - 2.04 m / s
the negative sign indicates that the speed is down
A pumpkin is thrown horizontally off of a building at a speed of 2.5 m/s and travels a horizontal distance of 12 m before hitting the ground. We can ignore air resistance.
What is the pumpkin's vertical velocity when it hits the ground?
Answer: -47.04
the radii of the pedal sprocket the wheel sprocket and the wheel of the bicycle
The radii of the pedal sprocket, the wheel sprocket, and the wheel of a bicycle can vary depending on the specific bicycle model and design.
There is no standard or fixed value for these radii as they can differ from one bicycle to another. The radii are typically determined by the manufacturer and are based on factors such as the intended use of the bicycle, gear ratios, and desired performance characteristics. The pedal sprocket is the smaller sprocket attached to the pedals of the bicycle. It is responsible for transferring the rider's pedaling force to the drivetrain of the bicycle. The radius of the pedal sprocket is generally smaller compared to the wheel sprocket and wheel. The wheel sprocket, also known as the rear sprocket or cassette, is located on the rear wheel of the bicycle. It engages with the chain and is responsible for transferring power from the pedals to the wheel. The radius of the wheel sprocket is usually larger compared to the pedal sprocket.
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A skier is pulled up a slope at a constant velocity by a tow bar. The slope is inclined at 22.9° with respect to the horizontal. The force applied to the skier by the tow bar is parallel to the slope. The skier's mass is 50.7 kg, and the coefficient of kinetic friction between the skis and the snow is 0.144. Calculate the magnitude of the force that the tow bar exerts on the skier.
The magnitude of the force exerted by the tow bar on the skier can be calculated using the principles of Newton's second law and considering the forces acting on the skier. The force applied by the tow bar is equal to the sum of the gravitational force and the force of kinetic friction.
The gravitational force acting on the skier can be calculated as the product of the skier's mass (m) and the acceleration due to gravity (g), which is approximately 9.8 m/s². Thus, the gravitational force is given by [tex]F_{gravity} = m g[/tex].
The force of kinetic friction can be determined using the equation [tex]F_{friction} = \mu \times N[/tex], where μ is the coefficient of kinetic friction and N is the normal force. The normal force is equal to the component of the gravitational force perpendicular to the slope, which is given by [tex]N = mg cos(\theta)[/tex], where [tex]\theta[/tex] is the angle of inclination.
Since the skier is pulled up the slope at a constant velocity, the net force acting on the skier is zero. Therefore, the force exerted by the tow bar is equal in magnitude but opposite in direction to the sum of the gravitational force and the force of kinetic friction. Thus, the magnitude of the force exerted by the tow bar on the skier can be calculated as follows:
[tex]F_{\text{tow bar}} = F_{\text{gravity}} + F_{\text{friction}} \\\\F_{\text{tow bar}} = m \cdot g + \mu \cdot N \\\\\[ F_{\text{tow bar}} = m \cdot g + \mu \cdot m \cdot g \cdot \cos(\theta)[/tex]
Plugging in the given values: mass (m) = 50.7 kg, coefficient of kinetic friction (μ) = 0.144, angle of inclination [tex](\theta)[/tex] = 22.9°, and acceleration due to gravity (g) ≈ 9.8 m/s², we can calculate the magnitude of the force exerted by the tow bar on the skier.
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One of the ways in which a coin operated vending machine checks to make sure that the coins fed to it are genuine is to roll them past a strong magnet. Group of answer choices Coins made of a good conductor will slow down as they roll past the magnet. Coins made of a good conductor will speed up as they roll past the magnet. Only coins made of magnetic materials such as iron will be affected by the magnet. The coins will become magnetized and thus can easily be sorted.
Answer:
Coins made of a good conductor will slow down as they roll past the magnet.
Explanation:
Conduction involves the transfer of electric charge or thermal energy due to the movement of particles. When the conduction relates to electric charge, it is known as electrical conduction while when it relates to thermal energy, it is known as heat conduction.
One of the ways in which a coin operated vending machine checks to make sure that the coins fed to it are genuine is to roll them past a strong magnet. As such, coins made of a good conductor will slow down as they roll past the magnet due to the force of attraction that exists between the magnet and the coin (metal).
This ultimately implies that, the magnet tends to attract the coin to itself and as such slowing down the motion of the coin. Similarly, if it's a fake coin, it simply means it would be a bad conductor and as such it will roll fast past the strong magnet.
bit.♠ly/3♠vhMu♠vJ remove symbols before searching or it wont work, there was a bug stoping me from attaching the image so there it is
Answer:
k and...
Explanation:
Answer:
no thank you.
explanation: Do not want to
a paraboloid is a 3d shape whose cross sections are parabolas. a solar cooker is in the shape of a paraboloid. it generates heat for cooking by reflecting sunlight toward a single point, the common focus of those parabolas. a cross section of the solar cooker can be modeled by the parabola shown below, opening up whose vertex is at the origin. if the cooker is 148 cm wide and 27.38 cm deep, how far above the base is the focal point?
The focal point of the solar cooker is 6.845 cm above the base.
How to calculate distance?For a parabolic reflector, the focal point (F) lies along the axis of symmetry, and the distance from the vertex to the focal point (the focus) is given by the equation:
4f = p
Where:
f = distance of the focal point from the vertex, and
p = depth of the paraboloid.
Given that the depth of the cooker is 27.38 cm, substitute this into the equation to find the focal point:
4f = 27.38 cm
f = 27.38 cm / 4
f = 6.845 cm
Therefore, the focal point of the solar cooker is 6.845 cm above the base.
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Fig. 2.1 shows a hammer being used to drive a nail into a piece of wood.
hammer head
-nail
wood
Fig. 2.1
The mass of the hammer head is 0.15 kg.
The speed of the hammer head when it hits the nail is 8.0m/s.
The time for which the hammer head is in contact with the nail is 0.0015s.
The hammer head stops after hitting the nail.
(a) Calculate the change in momentum of the hammer head.
Answer:
ΔP = - 1.2 Ns
Explanation:
The change in momentum of the hammer head can be given as follows:
[tex]\Delta P = P_f - P_i\\[/tex]
where,
ΔP = Change in Momentum = ?
Pf = Final Momentum
Pi - Initial Momentum
Therefore,
[tex]\Delta P = mv_f - mv_i\\\Delta P = m(v_f - v_i)[/tex]
where,
m = mass of hammer head = 0.15 kg
vf = final speed of hammer = 0 m/s
vi = initial speed of hammer = 8 m/s
Therefore,
[tex]\Delta P = (0.15\ kg)(0\ m/s-8\ m/s)[/tex]
ΔP = - 1.2 Ns
Twisting a bone along its longitudinal axis toward the midline of the body is ____________ .Twisting a bone along its longitudinal axis away from the midline of the body is ____________ .Rotation of the forearm, as if you're asking someone to hand you money or slap down on your hand, is called ____________ .Rotation of the forearm, as if you're turning over a can to empty it, is called ____________ .Movement of the thumb to approach and touch the fingertips is called ____________ .
Answer: Medial rotation
Lateral rotation
Supination
Pronation
Opposition
Explanation:
Medial rotation can be defined as the rotation of any of the body part towards the middle axis of the body. For example, movement of leg bones so that the toes are pointed towards inward.
Lateral rotation is the movement of the body parts or bones away from the middle axis of the body. For example. outward circle created by the upper limbs directed outwards.
Supination is the rotation of the forearm in such a way so that the palm is directed upwards so that hand can receive money or hand can slap a person.
Pronation is the downward motion of hand to put things down.
Opposition is the movement of the bones of the fingers the metacarpals which allow the thumb to touch the fingertips.
An AC source operating at 60Hz with a maximum voltage of 170V is connected in series with a resistor (R=1.2kΩ) and a capacitor (C=2.5μF). (a) What is the maximum value of the current in the circuit (b) What are the maximum values of the potential difference across the resistor and the capacitor? (c) When the current is zero, what are the magnitudes of the potential differences across the resistor, the capacitor and the AC source How much charge is on the capacitor at this instant (d) When the current is maximum, what are the magnitudes of the potential differences across the resistor, the capacitor, and the AC source? How much charge is on the capacitor at this instant?
The maximum value of the current in the circuit is approximately 0.1298 A. The maximum values of the potential difference across the resistor and the capacitor are equal to the maximum voltage (170 V) because they are in series with the AC source.
To solve this problem, we can use the concepts of AC circuit analysis and impedance.
Given:
Frequency (f) = 60 Hz
Maximum voltage [tex]\[V_\text{max}[/tex]) = 170 V
Resistance (R) = 1.2 kΩ = 1200 Ω
Capacitance (C) = 2.5 μF = 2.5 x 10⁻⁶ F
(a) The maximum value of the current in the circuit can be calculated using Ohm's law:
[tex]Imax = \frac{Vmax}{Z}[/tex]
where Z is the impedance of the circuit.
For a series RL circuit like this, the impedance Z is given by:
[tex]\[Z = \sqrt{R^2 + (X_c - X_l)^2}\][/tex]
where [tex]\[X_c[/tex] is the capacitive reactance and [tex]\[X_I[/tex] is the inductive reactance.
The capacitive reactance [tex]\[X_c[/tex] is given by:
[tex]\[X_c = \frac{1}{2\pi fC}\][/tex]
The inductive reactance Xl is given by:
Xl = 2πfL
However, since there is no inductor in the circuit (only a resistor and a capacitor), the inductive reactance is zero ([tex]\[X_I[/tex] = 0).
Substituting the values, we can calculate the maximum current:
[tex]\[X_c = \frac{1}{2\pi \cdot 60 \cdot 2.5 \cdot 10^{-6}}\][/tex]
≈ 530.66 Ω
[tex]\[Z = \sqrt{1200^2 + (530.66 - 0)^2}\][/tex]
≈ 1311.79 Ω
[tex]\[I_\text{max} = \frac{170 \text{ V}}{1311.79 \Omega}\][/tex]
≈ 0.1298 A
Therefore, the maximum value of the current in the circuit is approximately 0.1298 A.
(b) The maximum values of the potential difference across the resistor and the capacitor are equal to the maximum voltage ([tex]\[V_\text{max}[/tex]) because they are in series with the AC source. So:
Potential difference across the resistor = [tex]\[V_\text{max}[/tex]
Potential difference across the capacitor = [tex]\[V_\text{max}[/tex]
(c) When the current is zero, the potential difference across the resistor and the capacitor is zero because there is no current flowing through them. However, the potential difference across the AC source remains the same, which is the maximum voltage ([tex]\[V_\text{max}[/tex]). So:
Potential difference across the resistor = 0 V
Potential difference across the capacitor = 0 V
Potential difference across the AC source = [tex]\[V_\text{max}[/tex]
The magnitude of the potential difference across the AC source remains the same as the maximum voltage ([tex]\[V_\text{max}[/tex]).
To find the charge on the capacitor when the current is zero, we can use the equation:
Q = C * V
where Q is the charge, C is the capacitance, and V is the potential difference across the capacitor.
Q = (2.5 x 10⁻⁶ F) * 0 V
= 0 C
Therefore, the charge on the capacitor when the current is zero is 0 C.
(d) When the current is at its maximum value ([tex]\[I_\text{max}[/tex]), the potential difference across the resistor is given by Ohm's law:
Potential difference across the resistor = [tex]\[I_\text{max}[/tex] * R
= 0.1298 A * 1200 Ω
= 155.76 V
The potential difference across the capacitor can be found using the equation:
Potential difference across the capacitor =[tex]\[I_\text{max}[/tex] * [tex]\[X_c[/tex]
Potential difference across the capacitor = 0.1298 A * 530.66 Ω
= 69.75 V
The potential difference across the AC source remains the same as the maximum voltage ([tex]\[V_\text{max}[/tex]), which is 170 V.
To find the charge on the capacitor when the current is at its maximum, we can use the equation:
Q = C * V
Q = (2.5 x 10⁻⁶ F) * 69.75 V
≈ 0.0001744 C
Therefore, the charge on the capacitor when the current is at its maximum is approximately 0.0001744 C.
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A radiograph is taken with 120 mAs and a 200 cm SID producing 300 mR exposure, What intensity (mGya) would result at 400cm SID? (mAs constant)
The intensity (mGya) resulting at 400 cm SID, with a constant mAs of 120 is 75 mGya.
According to the inverse square law, the intensity of radiation is inversely proportional to the square of the distance. The formula to calculate the intensity is:
Intensity2 = Intensity1 * (Distance1 / Distance2)^2
Given that the initial intensity (Intensity1) is 300 mR, the initial distance (Distance1) is 200 cm, and the final distance (Distance2) is 400 cm, we can substitute these values into the formula:
Intensity2 = 300 mR * (200 cm / 400 cm)^2 = 300 mR * (1/2)^2 = 300 mR * 1/4 = 75 mR
Since 1 Gy (Gray) is equal to 1000 mGy, the intensity at 400 cm SID is 75 mR, which is equivalent to 0.075 mGya.
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~ is the following statement true or false? Explain your answer.
“Energy from the sun tends to affect only a small part of Earth's system."
Answer: False
Explanation: The sun is one of earths primary energy sources. Without the sun, all animals, plants, humans would die. The sun's energy provides warmth for humans and plants and animals cannot grow without the sun.
The statement "Energy from the sun tends to affect only a small part of Earth's system" is false.
What energy comes from the sun to Earth?The sun emits several forms of energy, including visible light, ultraviolet radiation, infrared radiation, and X-rays. Of these, visible light is the most abundant form of energy that reaches the Earth's surface.
The visible light from the sun provides the energy that drives the Earth's climate and weather patterns, powers photosynthesis in plants and algae, and is responsible for the colors we see in the world around us.
In addition to visible light, the sun also emits ultraviolet (UV) radiation. Some of this UV radiation is absorbed by the Earth's atmosphere, which helps to protect us from its harmful effects, but some of it reaches the Earth's surface and can cause skin damage and other health problems.
The sun also emits infrared radiation, which is responsible for heating the Earth's surface and atmosphere. This heat is important for the Earth's climate and weather patterns and is also used to generate electricity in solar power plants. The energy from the sun is essential for life on Earth and has a major impact on virtually every aspect of the Earth's system.
Here in the Question,
Energy from the sun has a major impact on the entire Earth system, from the atmosphere to the oceans to the land surface. The energy from the sun drives the Earth's climate and weather patterns, it powers the hydrologic cycle and drives ocean currents, and it provides the energy for photosynthesis, which is the basis of the Earth's food chain.
The energy from the sun that reaches the Earth's surface is also responsible for many physical and chemical processes that occur in the Earth's crust and upper mantle. For example, the energy from the sun powers the movement of tectonic plates, which leads to earthquakes, volcanic eruptions, and the formation of mountains.
The energy from the sun affects virtually every aspect of the Earth's system, from the smallest microorganisms to the largest geological features.
Therefore, the statement "Energy from the sun tends to affect only a small part of Earth's system" is false.
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A uniform magnetic field passes through a horizontal circular wire loop at an angle 15.1� from the vertical. The magnitude of the magnetic field changes in time according to, B(t) = (3.75T) + (2.75 T/s)t + (-6.05 T/s2)t2. The radius of the wire loop is 0.270 m, find the magnitude of the induced emf in the loop when t = 5.47 s
At t = 5.47 s, the magnitude of the induced emf in the loop is approximately 63.437 volts.
To find the magnitude of the induced electromotive force (emf) in the loop at a specific time, we can use Faraday's law of electromagnetic induction.
According to Faraday's law, the emf induced in a closed loop is equal to the rate of change of magnetic flux through the loop.
The magnetic flux through the loop is given by the formula:
Φ = B⋅A⋅cosθ
Where:
Φ is the magnetic flux,
B is the magnetic field,
A is the area of the loop, and
θ is the angle between the magnetic field and the normal to the loop.
Given:
B(t) = (3.75 T) + (2.75 T/s)t + (-6.05 T/[tex]s^2[/tex])[tex]t^2[/tex] (time-varying magnetic field)
θ = 15.1° (angle between the magnetic field and the vertical)
r = 0.270 m (radius of the loop)
t = 5.47 s (specific time)
First, let's find the magnetic field at the given time t = 5.47 s:
B(5.47) = (3.75 T) + (2.75 T/s)(5.47 s) + (-6.05 T/[tex]s^2[/tex])[tex](5.47 s)^2[/tex]
B(5.47) = 3.75 T + 15.0425 T + (-175.1383 T)
B(5.47) ≈ -156.348 T
Now, let's calculate the magnetic flux at the given time:
Φ = B(t)⋅A⋅cosθ
The area of the loop A is given by the formula: [tex]A = \pi r^2[/tex]
A = π[tex](0.270 m)^2[/tex]
Φ = (-156.348 T)⋅(π[tex](0.270 m)^2[/tex])⋅cos(15.1°)
Φ ≈ -156.348 T⋅0.22946[tex]m^2[/tex]⋅0.96593
Φ ≈ -34.407 Wb (we obtain a negative value for the flux due to the cosine of the angle)
Finally, the magnitude of the induced emf in the loop is given by the rate of change of magnetic flux with respect to time:
emf = -dΦ/dt
To find the derivative, we differentiate the given magnetic field equation with respect to time:
dB(t)/dt = (2.75 T/s) + (-12.1 T/[tex]s^2[/tex])t
emf = -(dΦ/dt) = -(-(dB(t)/dt))
emf = (2.75 T/s) + (-12.1 T/[tex]s^2[/tex])(5.47 s)
emf ≈ 2.75 T/s + (-66.187 T/s)
emf ≈ -63.437 T/s
Therefore, at t = 5.47 s, the magnitude of the induced emf in the loop is approximately 63.437 volts.
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The effective capacity utilization can be smaller than the design capacity utilization. O True False
The statement " The effective capacity utilization can be smaller than the design capacity utilization." is True because design capacity utilization refers to the maximum utilization of the system's capacity under ideal conditions.
Effective capacity utilization refers to the actual utilization of a system's capacity, taking into account factors such as downtime, maintenance, and other operational constraints. On the other hand, design capacity utilization refers to the maximum utilization of the system's capacity under ideal conditions.
In practice, it is common for the effective capacity utilization to be smaller than the design capacity utilization. This occurs due to various factors that affect the actual production or service delivery. These factors can include equipment breakdowns, scheduled maintenance, employee absenteeism, supply chain disruptions, and variations in customer demand.
The effective capacity utilization considers the real-world operational conditions and takes into account the constraints and limitations that can impact the system's performance. Therefore, it is not uncommon for the effective capacity utilization to be lower than the design capacity utilization, which represents the theoretical maximum utilization achievable under ideal circumstances.
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calculate the coulomb energy and the repulsion energy for NaCl ionic crystal at ists equrilibrium separation
To calculate the Coulomb energy and the repulsion energy for a NaCl ionic crystal at its equilibrium separation, we need to consider the ionic charges and the crystal lattice structure.
In NaCl, sodium (Na) has a +1 charge, and chloride (Cl) has a -1 charge. The crystal structure of NaCl is a face-centered cubic (FCC) lattice.
The Coulomb energy is the electrostatic interaction energy between the charged ions. It can be calculated using Coulomb's law:
Coulomb energy ([tex]E_{coul[/tex]) = (1 / 4πε₀) * Σ([tex]q_i * q_j[/tex]) / [tex]r_{ij[/tex]
Where:
ε₀ is the vacuum permittivity (8.854 × [tex]10^{-12}[/tex] C²/N·m²)
[tex]q_i[/tex] and [tex]q_j[/tex] are the charges of the ions
[tex]r_{ij[/tex] is the distance between ions i and j
The repulsion energy arises from the repulsion between the ions due to overlapping electron clouds. It can be approximated using an empirical expression known as the Born-Mayer equation:
Repulsion energy ([tex]E_{rep[/tex]) = A * exp(-B * r)
Where:
A and B are empirical constants specific to the crystal
r is the distance between ions
Now, let's assume the equilibrium separation ([tex]r_{eq}[/tex]) for NaCl at room temperature, which is approximately 2.82 Å (angstroms).
Using these values, we can calculate the Coulomb energy and the repulsion energy for NaCl at its equilibrium separation. However, the specific values of A and B for NaCl are required to obtain an accurate result.
These values are not readily available, and their determination involves experimental measurements and/or computational calculations beyond the scope of this text-based conversation.
Therefore, without the precise values of A and B, we cannot provide an exact numerical calculation of the Coulomb energy and the repulsion energy for NaCl at its equilibrium separation.
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if the car were released from a height of 100.0 cm, then one might predict the speed of the car at the bottom of the hill to be approximately _____. a. 3.65 m/s b. 3.83 m/s c. 5.42 m/s d. 12.1 m/s
If a car is released from a height of 100.0 cm, the predicted speed of the car at the bottom of the hill would be approximately 3.83 m/s.
When an object falls freely under the influence of gravity, it undergoes accelerated motion. The speed of the object increases as it falls. The relationship between the speed of a falling object and the distance it falls can be determined using the laws of motion. In this case, the car is released from a height of 100.0 cm, which is equivalent to 1.00 m.
To calculate the speed of the car at the bottom of the hill, we can use the equation for the final velocity of a freely falling object:
[tex]v = \sqrt(2 * g * h)[/tex]
Where v represents the final velocity, g is the acceleration due to gravity (approximately [tex]9.8 m/s^2[/tex]), and h is the height from which the car is released.
Plugging in the values, we have:
[tex]v =\sqrt(2 * 9.8 * 1.00)\\v =\sqrt(19.6)[/tex]
v ≈ 4.43 m/s
Therefore, the predicted speed of the car at the bottom of the hill is approximately 3.83 m/s. Hence, option b, 3.83 m/s, is the closest estimate.
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when the energy stored in the inductor is a maximum. how much energy is stored in the capacitor
When the energy stored in an inductor is at a maximum, the energy stored in the capacitor is zero. In an oscillating circuit consisting of an inductor and a capacitor, energy continuously transfers back and forth between the inductor and the capacitor.
At any given moment, the total energy in the circuit remains constant. When the energy stored in the inductor is maximum, all the energy is stored in the inductor's magnetic field. At the same time, the energy stored in the capacitor is minimum, as the capacitor's electric field is at its minimum.
As the energy oscillates between the inductor and the capacitor, there is a point in the cycle where the energy stored in the inductor is zero and the energy stored in the capacitor is maximum. This occurs when the charge on the capacitor plates is maximum and the voltage across the capacitor is maximum.
In summary, when the energy stored in the inductor is at a maximum, the energy stored in the capacitor is zero.
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The ___ of a position time graph represents an objects velocity
Answer:
this one is for your egg drop question
first question -
Use this worksheet to design your device and record your data. You can then use this form to help you write your lab report.
Height of egg drop: _5ft._
__________________________________________________________
Q2:
Ideas for Prototype Design
Teepee, large cube , small cube
__________________________________________________________
Q3:
Preliminary Sketches (attach separate paper if needed)
Option A: teepee
__________________________________________________________
Q4:
Advantages: Disadvantages:
● fully covered ● egg might crack
● could stand higher distances ●egg will most likely bounce around around but not crack but most likely to crack
__________________________________________________________
Q5:
Option B: large cube
Option C: smaller cube
__________________________________________________________
Q6:
more advantages and disadvantages
Advantages: Disadvantages:
● egg will be tightly secured so nothing bounces around
● egg might crack depending on the impact to the floor
__________________________________________________________
Q7:
Which of the three designs will you move forward with? Explain your reasoning for selecting this design.
I think i'm going to be moving forward with the teepee design
__________________________________________________________
Q8:
Building the Prototype
What modifications, if any, did you make to the basic design during the construction process?
I made it a little smaller than the original design
__________________________________________________________
Q9:
Predictions
Will your device cushion the egg? How will your device do this?
I think it will cushion the design if i put the plastic bag in with the egg it should prevent it from moving around to much
__________________________________________________________
Q10:
Will your device increase the time it takes for the egg to impact the ground? How will your device do this?
I think the extra weight added to the design might affect it by speeding up the process down to the floor
__________________________________________________________
Q11:
Observations
Record your observations and the results of the experimental tests of your device below.
First i tried the egg without the plastic bag and it cracked so i made the design smaller and added the plastic bag this time
__________________________________________________________
Q12:
Evaluating Your Prototype
What worked well? I would say definitely the plastic bag keeping the egg in place
__________________________________________________________
Q13:
Which features can be improved upon? The structure itself as in where the string and tape were
__________________________________________________________
Q14:
Suggestions
How could the design of this device be improved? More balance i guess because the egg would move alot without the bag
__________________________________________________________
Q15:
Why would this change be an improvement? What force or momentum principle is this improvement based on? If the egg had more balance then it would have a less chance of cracking i think this is a type of impulse toward the ground bc of the egg’s weight
__________________________________________________________
Q16:
Sketch of Final Design
Draw a well-labeled sketch of the final design.
( i provided it :) )
okie peace!
Answer
slope
Explanation:
define 1 unit electricity
Answer:
A unit is represented in kWH or Kilowatt Hour. This is the actual electricity or energy used. If you use 1000 Watts or 1 Kilowatt of power for 1 hour then you consume 1 unit or 1 Kilowatt-Hour (kWh) of electricity.
will the bulb light for the whole time that the capacitor discharges? explain. (hint: you might want to recall circuit 4 of electricity ii.) [2]
In-Circuit 4 of Electricity II, a circuit with a capacitor, resistor, and bulb was analyzed. The capacitor discharges slowly through the resistor in this circuit, causing the bulb to light up.
The capacitor discharges gradually and, as a result, the bulb will light up for a while, but it will not remain lit for the entire time that the capacitor discharges.The capacitor discharges as the bulb illuminates and the brightness of the bulb decreases. After a while, the bulb will go out entirely. The time it takes for the capacitor to discharge and the bulb to go out depends on the capacitance and resistance of the capacitor and the resistor. A higher capacitance or resistance will result in a longer discharge time and a longer time for the bulb to go out. The opposite is also true: a lower capacitance or resistance will result in a shorter discharge time and a shorter time for the bulb to go out.
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2. One of the cultural benefits of the ecosystems is:
A.flood prevention
B. recreation
C. climate moderation
D. erosion reduction.
Explanation:
Cultural Ecosystem Services (CES) are the non-material benefits people obtain from nature. They include recreation, aesthetic enjoyment, physical and mental health benefits and spiritual experiences. They contribute to a sense of place, foster social cohesion and are essential for human health and well-being.
How long will it take by 50W heater to melt 100g of ice at 0degreeC? Specific heat capacity of water = 4.2J/ (g0C), latent heat of fusion = 340 J/ g
Answer:
420 s
Explanation:
Write the SI unit of time and temperature
Answer:
The SI unit of time is second (s) and temperature is Kelvin (K)
Explanation:
hope it is helpful to you
A 0.49-kg mass suspended from a spring undergoes simple harmonic oscillations with a period of 1.45 s How much mass, in kilograms, must be added to the object to change the period to 1.75 s? Grade Summary Deductions Potential 0 100 sin() cotana tan acos( cosO asinO atanacotan) sinh cosh)ta cotanhO Submissions Attempts remaining (09.0 per attempt) detailed view 4 5 6 END Degrees Radians NO
The mass m₂ that must be added to the object to change the period to 1.75 s is 0.227 kg
Given below are the values of variables ,
Mass of the object (m) = 0.49 kg
Initial period (T₁) = 1.45 s
Final period (T₂) = 1.75 s
Let the added mass be m₂.
We need to find the mass m₂ that must be added to the object to change the period to 1.75 s.
The period of an object undergoing simple harmonic motion,
T = 2π √(m/k)
The force constant k is,
k = mg/l
For a spring mass system, the total mass is given by the sum of individual masses.
Therefore,
m₁ + m₂ = total mass of the system
The steps to solve the problem,
Step 1: Calculate the force constant of the spring k = mg/l.
we assume that the length of the spring is constant, and we can neglect it for our calculation.
k = (0.49 kg) x (9.81 m/s²) / l
= 4.802 m/s²
Step 2: Calculate the mass m₁ + m₂ for the initial period
T₁ = 2π √(m₁/k)
m₁ = (T₁/2π)² x k
= (1.45 s / 2π)² x 4.802 m/s²
= 0.227 kg
The mass of the object m₁ is given as 0.49 kg.
Therefore,
m₁ + m₂ = 0.49 kg + m₂
= 0.227 kg + m₂
= 0.717 kg
Step 3: Calculate the mass m₁ + m₂ for the final period
T₂ = 2π √((m₁ + m₂)/k)
m₁ + m₂ = (T₂/2π)² x k
= (1.75 s / 2π)² x 4.802 m/s²
= 0.318 kg + m₂
= 0.717 kg
Step 4: Find the mass m₂ that must be added
m₂ = 0.717 kg - 0.49 kg = 0.227 kg
Therefore, the mass m₂ that must be added to the object to change the period to 1.75 s is 0.227 kg.
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In recent years it has been possible to buy a 1. 0 F capacitor. This is an enormously large amount of capacitance. Suppose you want to build a 1. 1 Hz oscillator with a 1. 0 F capacitor. You have a spool of 0. 25-mm-diameter wire and a 4. 0-cm-diameter plastic cylinder.
How long must your inductor be if you wrap it with 2 layers of closely spaced turns?
An oscillator is an electronic device that produces an electrical signal at a specific frequency. A capacitor is an electrical component that stores electrical energy. In recent years, it has become possible to purchase a 1.0 F capacitor. This is an incredibly large amount of capacitance.
Suppose you want to build a 1.1 Hz oscillator using a 1.0 F capacitor and a spool of 0.25-mm-diameter wire and a 4.0-cm-diameter plastic cylinder. We can calculate the required inductance value using the formula:f = 1/2π√(L*C)Where f is the desired frequency, L is the inductance value, and C is the capacitance value. Substituting the given values:
[tex]f = 1.1 HzC = 1.0 F[/tex]
Plugging these values into the formula and solving for L:
1.1 Hz = 1/2π√(L*1.0 F)2π*1.1 Hz = √(L*1.0 F)6.88 Hz2 = L*1.0 F6.88 H/ F = LL = 6.88 H
[tex]1.1 Hz = 1/2π√(L*1.0 F)2π*1.1 Hz = √(L*1.0 F)6.88 Hz2 = L*1.0 F6.88 H/ F = LL = 6.88 H[/tex]We need to wrap this inductance value with two layers of closely spaced turns around the plastic cylinder.
The inner diameter of the cylinder is equal to the diameter of the wire, which is 0.25 mm or 0.00025 m. Therefore:d = 0.00025 mThe outer diameter of the cylinder is 4.0 cm or 0.04 m. Therefore:D = 0.04 mPlugging these values into the formula for A:
[tex]A = (π/4)(0.04² - 0.00025²)A = 0.001257 m²[/tex]
Plugging these values into the formula for L:
[tex]L = µn²A/lSolving for l:l = µn²A/L[/tex]
Plugging in the given values:
[tex]µ = 4π x 10^-7 H/mn = 2[/tex]
(since we want two layers)
[tex]A = 0.001257 m²L = 6.88 Hl = (4π x 10^-7 H/m)(2²)(0.001257 m²)/(6.88 H)l ≈ 0.0015 m[/tex] or 1.5 mm
Therefore, the length of the inductor should be approximately 1.5 mm.
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Which type of energy is the original source for the energy that food molecules can provide?
Answer:
Chemical potential energy
Explanation:
which is used to for any form of energy.
If you want to design a high efficiency wind turbine, what efficiency values is reasonable as your design goal?
The efficiency values that is reasonable If you want to design a high efficiency wind turbine is 45%
What should you now about the efficiency value of wind turbine?The efficiency of a wind turbine is the ratio of the power it generates to the power in the wind.
The theoretical maximum efficiency of a wind turbine is the Betz limit, which is 59.3%.
However, in practice, wind turbines are typically only about 35%- 45% efficient.
There are a number of factors that can affect the efficiency of a wind turbine, including the size of the turbine, the wind speed, and the design of the turbine.
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Ampere's Law is about the relation of the magnetic field and the currents producing it. True or False?
Ampere's Law is about the relation of the magnetic field and the currents producing it. It is true.
André-Marie Ampère developed Ampere's Law, which connects the magnetic field around a closed loop to the electric currents running through the loop. It asserts that the magnetic field line integral through a closed loop is equal to μ₀ times the total current going through the loop, where μ₀ is the permeability of empty space.
This rule establishes a mathematical link between the magnetic field and the currents that produce it. As a result, the assertion that Ampere's Law is about the relationship between the magnetic field and the currents that produce it is correct.
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a woman with mass 50 kg is standing on the rim of a large horizontal disk that is rotating at 0.80 rev/s about an axis through its center. the disk has mass 110 kg and radius 3.4 m. calculate the total angular momentum of the woman-disk system
14,879.9 kgm²/s is the total angular momentum of the woman-disk system
Define angular momentum
The rotating equivalent of linear momentum is angular momentum. It is a conserved quantity, meaning that the total angular momentum of a closed system stays constant, making it a significant physical quantity. Both the direction and the amplitude of angular momentum are conserved.
In an isolated system—one in which there are no external forces acting and, as a result, no torques or moments applied from outside the system—angular momentum is maintained.
I = M₂R² + M₁R²
I = R2 (M2 +0.5M1)
I = 42(500.5(270))
I = 2,960 kgm²
The angular speed ω = 0.8/ 2 *pi/1 i.e. 5.027 rad/s
L = Iω
L = 2,960 x 5.027 = 14,879.9 kgm²/s
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explain (a) how it is possible for a large force to produceonly a small, or even zero, torwue, and (b) how is it possible fora small force to produce a large torque
(a) Yes, it is possible for a large force to produce only a small or zero torque when the line of action of the force does not create a moment arm or when the force is applied directly through the axis of rotation.
(b) Yes, it is possible for a small force to produce a large torque when the force is applied at a greater distance from the axis of rotation, creating a larger moment arm.
Torque is the rotational equivalent of force and is calculated by multiplying the force by the distance from the axis of rotation. If the line of action of the force passes through the axis of rotation, the moment arm becomes zero, resulting in no torque being generated. This occurs when the force is applied directly on the axis or when the force is balanced by an equal and opposite force that cancels out the rotational effect.
Similarly, even if the force is not directly on the axis of rotation, if the moment arm is very small, the torque produced will also be small. The moment arm is the perpendicular distance between the axis of rotation and the line of action of the force. If the force is applied very close to the axis, the moment arm will be small, resulting in a smaller torque.
If a small force is applied at a considerable distance from the axis of rotation, the moment arm becomes larger, resulting in a larger torque. This is similar to using a wrench or a long lever to apply a small force to loosen a tight bolt. The length of the wrench or lever increases the moment arm, allowing a small force to produce a large torque.
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smoke detectors are based on the radioactive decay of americium-241. since multiple detectors are placed in a typical home, which type of radiation would you expect the source to emit?
a) alpha
b) beta
c) gamma
I KNOW THE ANSWER IS ALPHA BUT I DON'T KNOW WHY! PLEASE HELP!
In the case of smoke detectors based on the radioactive decay of americium-241, the type of radiation emitted by the source is alpha radiation.
Alpha particles are composed of two protons and two neutrons, essentially the same as a helium nucleus. They have a positive charge and are relatively large and heavy compared to other types of radiation. Americium-241 undergoes alpha decay, where it spontaneously emits an alpha particle from its nucleus. This decay process results in the production of a daughter nucleus and the release of an alpha particle, which consists of two protons and two neutrons. Alpha particles have a low penetrating power and can be easily stopped by a sheet of paper or a few centimeters of air. This characteristic makes them ideal for use in smoke detectors because they can ionize the air inside the detector chamber, allowing for the detection of smoke particles.
In contrast, beta and gamma radiation are not typically used in smoke detectors. Beta particles are high-energy electrons or positrons, while gamma rays are high-frequency electromagnetic waves. These types of radiation have higher penetrating power and would not be as effective in ionizing the air for smoke detection purposes. Therefore, the most likely type of radiation emitted by the americium-241 source in a smoke detector is alpha radiation.
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