Answer:
A.) 3.19s
B.) 0
C.) 55.1
Explanation:
Given that a rock fell of the edge of a cliff and encountered a displacement of 50m. The final vertical velocity of the rock was 10m/s.
To Find the
A.) time the rock was in the air,
Given that
h = 50m,
initial velocity U = 0,
acceleration due to gravity g =9.8m/s^2
Using second equation of motion:
h = Ut + 1/2gt^2
Substitute all the parameters into the equation
50 = 1/2 × 9.8 × t^2
100 = 9.8t^2
t^2 = 100/9.8
t^2 = 10.2
t = 3.19s
B.) the horizontal velocity when the rock left the cliff
The horizontal velocity is equal to zero since horizontal acceleration is zero.
C.) and the vertical displacement the rock had.
Using the third equation of motion.
V^2 = U^2 + 2gH
Where U = 0
V = 10m/s
Substitute all the parameters into the formula
10^2 = 0 + 2 × 9.8 × H
100 = 19.6H
H = 100/19.6
H = 5.1
The vertical displacement = 50 + 5.1
The vertical displacement = 55.1 m
Define malleability?
Answer:
Explanation:
the quality or state of being malleable: such as. a : capability of being shaped or extended by hammering, forging, etc. the malleability of tin.
The energy is different within each wave type across the spectrum true or false
Answer:
T kinda waky tho -_-----_-----_-////_----_---///
Explanation:
Answer:
true
Explanation:
[10 POINTS ❗️❗️ and brainlist :)]
Roy throws a ball up in the air. Each time he throws the ball up in any direction, it falls back to the ground as shown in the illustration. The ball comes back to the ground because of the
A) weak electric force of the earth.
B) strong magnetic force of the earth.
C) force of air resistance on the ball.
D) strong gravitational force of the earth.
Answer:
D) Strong gravitational force of the earth
Explanation:
Gravitational force is the force that attracts to objects with mass.This forces tries to pull masses together, that is why attractive in nature.
HELLO PLEASE HELPPP!! WILL GIVE BRAINIEST
Answer: Wavelength
Explanation:
Answer:
C) wavelength
Explanation:
I hope this is right, have a nice day!
1. A kettle contains 1.5kg of water at a
temperature of 18°C. How much energy is
needed to bring the water to the boil?
Answer:
water boiling point is usually 100°C so I think we subtract 18 degrees Celsius from 100 degrees Celsius to get 82 degrees Celsius to be the energy needed
an average net force of 31.6 N is used to accelerate a 15.0 kg object uniformly from rest to 10.0 m/s leftward. What is the change in momentum?
Answer:
-150 kg m/s
Explanation:
The change of momentum is calculated as ;
Δp= m*Δv where
where
Δp= change in momentum
Δv = vf-vi
m= mass of the object
Change in momentum is also calculated when using the formula;
Δp = F * Δt when F is the net force applied and Δt is the time of action.
In this case;
m= 15 kg
vf= -10 m/s
vi= 0 m/s
Taking rightward direction to be positive, then leftward will be negative.
Applying the formula as;
Δp = m*Δv
Δp = 15 * { -10 -0} = 15*-10 = -150 kg m/s
Which of the following is strenuous?
Atraining for an athletic competition
Bsharing a candy bar with a friend
Creading an exciting mystery
Dforgetting to complete your homework
Answer:
I think it c
Explanation:
Answer:
Atraining for an athletic competition
A golfer hits a ball at 10.5 m/s at an angle of 25 degrees.
a) How long will the ball be moving?
B) How far will the ball go? C) How high will the ball go?
Q: How can variations in the rate of interaction between the hydrosphere and the atmosphere result in global climate change?
A. by causing droughts and floods
B. by producing more greenhouse gases
C. by changing the amount of water on Earth
D. by decreasing the atmospheric temperature
How does a second class lever make our work easier?
What is the average translational KE of 5 moles of gas molecules at 300 K?
a.
2.1 x 103 J
b.
1.87 x 104 J
c.
1.78 x 105 J
d.
1.68 x 106 J
Answer:
What is the average translational kinetic energy of molecules in an ideal gas at 37°C? The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.
Explanation:
The average translational energy of a molecule is given by the equipartition theorem as, E = 3kT 2 where k is the Boltzmann constant and T is the absolute temperature.
An example of a chemical change is water boiling
Answer:
False, Boiling water is an example of a physical change and not a chemical change
Answer:
yes
Explanation:
cos from the boiling water, you can still get another change
which type of energy is released when a nucleus is split apart?
a. kinetic energy
b. elastic energy
c. chemical energy
d. nuclear energy
Answer:
D. Nuclear energy
Explanation:
A nucleus is the result of nuclear energy if it is split into an other the same result shall happen it being nuclear energy.
plz answer this...its urgent!!
its about gravitation..only 3 questions
Answer: For #1, 7.3 m/s2.
Explanation: See this wikipedia screenshot for explanation, it's complicated.
Define kinetic energy in your own words, and write a statement about how kinetic energy is affected as velocity increases.
Why is it difficult to charge a metallic rod with the method of friction?
pls answer quick
I got exam tomorrow
Insulators can be easily charged by friction as the extra electrons gained CANNOT easily escape. Conductors: materials that allow electrons to flow through them easily. Conductors CANNOT be easily charged by friction as the extra electrons gained can easily escape. When negatively charged rod is put near a metal can
what is the temperature of air if the speed of sound is 295m/s?
Answer:
Explanation:The speed of sound depends on several variables, but the only independent variable we need to calculate the speed of sound ... Enter your air temp and choose your units: The speed of sound: mph. Fahrenheit, knots. Celsius, m/s. Kelvin, ft/s.
If a small asteroid named ‘B612’ has a radius of only 20 m and mass of
1 × 104 kg, what is the acceleration due to gravity on its surface?
Acceleration produced in the motion of a body under the effect of gravity is called acceleration due to gravity.
It is a vector quantity and it's SI unit is m/s².
It is usually denoted by the symbol g.
Formula of Acceleration due to Gravity:
[tex] \boxed{ \bf{g = \dfrac{GM}{r^2}}}[/tex]
G → Universal Gravitational Constant [tex] \sf (6.67 \times 10^{-11} \ Nm^2/kg^2) [/tex]
M → Mass of the Asteroid (1 × 10⁴ kg)
R → Radius of the Asteroid (20 m)
By substituting values in the equation, we get:
[tex] \rm \longrightarrow g = \dfrac{6.67 \times {10}^{ - 11} \times 1 \times {10}^{4} }{20^2} \\ \\ \rm \longrightarrow g = \dfrac{6.67 \times {10}^{ - 11 + 4} }{400} \\ \\ \rm \longrightarrow g = 0.016675 \times {10}^{ - 7} \\ \\ \rm \longrightarrow g = 1.6675 \times {10}^{ -9} \: m {s}^{ - 1} [/tex]
[tex] \therefore [/tex] Acceleration due to gravity on the surface of small asteroid named ‘B612’ = [tex] \sf 1.6675 \times 10^{-9} \ m/s [/tex]
Acceleration produced in the motion of a body under the effect of gravity is called acceleration due to gravity. Acceleration due to gravity on the surface of small asteroid named ‘B612’ = 1.776 * 10 9 m/s2.
What is acceleration due to gravity?A free-falling item is one that is falling solely as a result of gravity, as was discovered in the previous section of this course. A free-falling object experiences a downward acceleration of 9.8 m/s. (on Earth).
The acceleration of any object moving only as a result of gravity is referred to as the acceleration of gravity.
In fact, this quantity, known as the acceleration of gravity, is so significant to physics that it has its own distinctive symbol, the letter g. The most precise measurement of the gravitational acceleration is 9.8 m/s.
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At its closest approach, a moon comes within 200,000 km of the planet it orbits. At that point, the moon is 300,000 km from the other focus of its orbit, f2. The planet is focus f1 of the moon's elliptical orbit. How far is the moon from the planet when it is 260,000 km from f2?
Answer:
s₁ = 240,000 km
Explanation:
The distance between both the focuses f₁ and f₂ will be the sum of distances of the moon from each focus at a given point. Therefore,
s = s₁ + s₂
where,
s = total distance between the focuses = ?
s₁ = distance between f1 and moon = 200,000 km
s₂ = distance between f₂ and moon = 300,000 km
Therefore,
s = 200,000 km + 300,000 km
s = 500,000 km
Now, when the distance from f₂ becomes 260,000 km, then the distance from f₁(planet) will become:
s = s₁ + s₂
500,000 km = s₁ + 260,000 km
s₁ = 500,000 km - 260,000 km
s₁ = 240,000 km
PLSS THIS LOOKS SIMPLE Tina throws a softball up with an initial speed of 25 meters per second. Calculate the maximum height that the ball will reach.
Answer:
31.86m
Explanation:
recall that one of the equations of motion can be written
v² = u² + 2as
where
u = initial velocity = 25m/s
v = final velocity = 0m/s because at maximum height, the ball will momentary stop moving (i.e have zero velocity)
a = acceleration = -9.81m/s² (i.e a deceleration as it moves upwards equal to the magnitude of the gravitational acceleration)
s = distance (we are asked to find this)
substituting these into the equation:
v² = u² + 2as
0² = 25² + 2(-9.81)s
0 = 625 - 19.62s
19.62s = 625
s = 625 / 19.62
s = 31.86m
What is the formula for freefall?
Answer: vf = g * t
Explanation:
G represents the acceleration of gravity.
T represents time so multiply the acceleration of gravity times time.
can anyone help me with this
Answer:
earth is 4.54 billion years old
for an organism to survive they would have to change ( mutate )
A mutation is any permenant change in dna of a gene or chromosome
some mutations are bad and some can be good
Explanation:
What does is the glenohumeral joint and what does it do? (ANATOMY)
You pull horizontally on a 50 kg crate with a force of 400N and the friction force on the crate in 150N. What is the acceleration of the crate?
If you pull horizontally on a 50 kg crate with a force of 400 N and the friction force on the crate of 150 N, then the acceleration of the crate would be 5 m / s² .
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
As given in the problem if you pull horizontally on a 50 kg crate with a force of 400 N and the friction force on the crate in 150 N.
The net force acting on the crate = 400 N - 150 N
= 250 N
The acceleration of the crate = 250 / 50
= 5 m / s²
Thus, the acceleration of the crate would be 5 m / s² .
Learn more about Newton's second law here, refer to the link given below ;
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How many
different
elements are
present in
C6H12O6 ? How do you know
La superficie de unas botas suman 400 cm2 y la persona que las usa tiene 45 kg de masa, calcula la presión que ejerce sobre el piso. NOTA: Se debe encontrar la fuerza, para lo cual, se debe obtener el peso utilizando la fórmula de masa por gravedad que es 9.8 m / s2
Answer:
11025 N / m²
Explanation:
Los siguientes datos se obtuvieron de la pregunta:
Área (A) = 400 cm²
Masa (m) = 45 Kg
Aceleración por gravedad (g) = 9,8 m / s²
Presión (P) =?
A continuación, determinaremos la fuerza aplicada. Esto se puede obtener de la siguiente manera:
Masa (m) = 45 Kg
Aceleración por gravedad (g) = 9,8 m / s²
Fuerza (F) =.?
F = m × g
F = 45 × 9,8
F = 441 N
A continuación, convertiremos 400 cm² a m². Esto se puede obtener de la siguiente manera:
1 cm² = 0,0001 m²
Por lo tanto,
400 cm² = 400 cm² × 0,0001 m² / 1 cm²
400 cm² = 0,04 m²
Por tanto, 400 cm² equivalen a 0,04 m².
Finalmente, determinaremos la presión ejercida de la siguiente manera:
Área (A) = 0.04 m².
Fuerza (F) = 441 N
Presión (P) =?
P = F / A
P = 441 / 0,04
P = 11025 N / m²
Por tanto, la presión ejercida es 11025 M / m²
There is a spot of paint on the front wheel of the bicycle. Take the position of the spot at time t=0 to be at angle θ=0 radians with respect to an axis parallel to the ground (and perpendicular to the axis of rotation of the tire) and measure positive angles in the direction of the wheel's rotation. What angular displacement θ has the spot of paint undergone between time 0 and 2 seconds?
Here is the missing information.
An exhausted bicyclist pedal somewhat erraticaly when exercising on a static bicycle. The angular velocity of the wheels takes the equation ω(t)=at − bsin(ct) for t≥ 0, where t represents time (measured in seconds), a = 0.500 rad/s2 , b = 0.250 rad/s and c = 2.00 rad/s .
Answer:
0.793 rad
Explanation:
From the given question:
The angular velocity of the wheel is expressed by the equation:
[tex]\omega (t) =\dfrac{d\theta}{dt}[/tex]
The angular velocity of the wheels takes the description of the equation ω(t)=at−bsin(ct)
SO;
[tex]\dfrac{d \theta}{dt} = at - b \ sin \ ct[/tex]
dθ = at dt - (b sin ct) dt
Taking the integral of the above equation; we have:
[tex]\int \limits^{\theta}_{0} \ d \theta = \int \limits ^{t=2}_{0} at \ dt - (b \ sin \ ct) \dt[/tex]
[tex][\theta] ^{\theta}_{0} = a \bigg [\dfrac{t^2}{2} \bigg]^2_0 - \bigg[ -\dfrac{b}{c} \ cos \ ct \bigg] ^2_0[/tex]
where;
a = 0.500 rad/s2 ,
b = 0.250 rad/s and
c = 2.00 rad/s
[tex]\theta = (0.500 \ rad/s^2 ) \bigg [\dfrac{(2s)^2}{2} \bigg] - \bigg[ -\dfrac{0.250 \ rad/s}{2.00 \ rad/s} \ cos \ (2.00 \ rad/s )( 2.00 \ s) \bigg] - \bigg [ \dfrac{0.250 \ rad/s}{2.00 \ rad/s}\bigg ] cos 0^0[/tex]
[tex]\mathbf{\theta = 0.793 \ rad}[/tex]
Hence, the angular displacement after two seconds = 0.793 rad
A block weighing 35 N is resting on a steel table (us = 0.40).
The minimum force to start this block moving is ___ N.
Answer: 14
Explanation:
Force(normal)*coefficient
The static friction force is a force that prevents motion of an object kept on a surface, due to the interaction of the surface of the object and the surface on which it is kept
The minimum force required to start the block moving is 14 NReason:
The known parameter are;
The weight of the block, W = 35 N
The static friction of the surface of the table surface, [tex]\mu_s[/tex] = 0.40
Required:
To find the minimum force to start the block moving
Solution:
The force required to start the block moving is given by the frictional force that needs to be surpassed
Force required, F = Force of friction
Force of friction = Normal reaction × Coefficient of static friction
On a flat surface, the normal reaction = The weight of the object
∴ Force of friction, [tex]F_f[/tex] = Weight of the object × Coefficient of static friction
Which gives;
[tex]F_f = W \times \mu_s[/tex]
[tex]F_f = 35 \, N \times 0.40 = 14 \, N[/tex]
Force required, F = Force of friction, [tex]F_f[/tex] = 14 N
The minimum force required to start the block moving, F = 14 N
Learn more about the static friction force here:
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Your task now is to look up the effects of the temperature on an equilibrium and how the reaction will shift when adding or removing heat. Explain in no less than 4 complete sentences the effect of the temperature and list at least on example.
Answer:
If you increase the temperature, the position of equilibrium will move in such a way as to reduce the temperature again. It will do that by favouring the reaction which absorbs heat. In the equilibrium we've just looked at, that will be the back reaction because the forward reaction is exothermic.
Explanation:
As Derrick is driving around town, he stops at a red-light. When the light turns green, he takes off and travels
212m in 6.7 seconds. What is his average acceleration?
Answer:
31.6
Explanation:
velocity÷ time
212 ÷ 6.7 = 31.6m/s