A rightward force is applied to a 6-kg object to move it across a rough surface at constant
velocity. The object encounters 15 N of frictional force. Use the diagram to determine the
gravitational force, normal force, net force, and applied force.

The final image is found to be 2.37cm in front of the eyepiece.

The focal length of the eyepiece is 2.00 cm and it is placed at a distance of 19.00 cm in front of the objective lens.

Now, we can use the lens formula to find the position of the image,

1/v - 1/u = 1/f

Where,

v is the position of the image,

u is the position of the objective in front of the eyepiece,

f is the focal length of the eyepiece.

Now, putting values,

1/v - 1/(-19) = 1/(-3)

The focal length and u are taken negative because of the sign standard sign convention of the lens.

1/v+1/19 = -1/3

Solving further,

v = -2.38 cm

So, the final image is 2.38 cm in front of the eyepiece.

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The moment of the force about A will be 14150.97 N-m Force = 200 N

A force's moment is determined by its magnitude and distance from the rotating axis. The moment of a force around a point measures the force's strength (the perpendicular distance of the line of action of the force from the point). The turning effect of a force is known as its moment. The moment of force, sometimes referred to as the torque. A moment must develop because of a force F, which prevents the line of action from passing through the location where the moment is to be taken. If the line of action does not travel through that location, the moment is zero since the magnitude of the moment arm is 0.

[tex]amp; \vec{F}=200\left(-\cos 30^{\circ} \hat{j}+\sin 30 \hat{k}\right) M \\& \vec{F}=200 \cdot\left(\frac{-\sqrt{3} \hat{\imath}+\hat{k}}{2}\right)=100(-\sqrt{3} \hat{\jmath}+\hat{k}) M \\& \overrightarrow{r_A}=-50 \hat{\jmath}, \quad \vec{r}_C=60 \hat{i}+25 \hat{1} \\& \Rightarrow \quad \vec{r}_{C A}=\vec{r}_e-\vec{r}_A=60 \hat{\imath}+755[/tex]

Moment of F about A -

[tex]amp; \vec{M}_A=\vec{\pi} A \times \vec{F}=(60 \hat{+}+75 \hat{1}) \times(100(-\sqrt{3} \gamma+\hat{k}) \\& \vec{M}_A=100\{-\sqrt{3} .60 \hat{k}-60 \hat{\imath}+0+75 \hat{\jmath}\}[/tex]

[tex]\vec{MA}=7500 i-6000 i-6000 \sqrt{3} \hat{N} N-m\\\\\mid \vec{MA}|_A=14150.97 N-m[/tex]

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Iodine molecules are small enough to pass freely through the membrane however, starch molecules are complex and too large to pass through the membrane. Initially, there was a higher concentration of iodine outside than inside the tube.

Thus iodine diffused into the tube with the starch. Iodine is able to pass through the membrane while starch is not. The Glucose-testing strips indicate that glucose has been able to pass out of the tubing and into the external fluid. Thus proving the tubing allows movement in both directions.

Iodine was able to diffuse across the membrane because it is small and hydrophobic and starch was not because it is too large The Dialysis tubing provides a semi-permeable membrane. Only allowing smaller molecules to pass through it. Iodine molecules are small enough to pass freely through the membrane, however, starch molecules are complex and too large to pass through the membrane.  

The iodine is a small molecule and can move from outside the tubing to inside it. To test whether iodine or starch has crossed the synthetic membrane, you will look for color change. A solution of iodine is tan and a solution of starch is milky white; when iodine and starch are together in the same solution, they react and the solution turns purple, dark blue, or black.

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Answer:

below

Explanation:

Vertical position = vo t + 1/2 at ^2

    where vo = 20 sin25 =8.45       and    a = -9.81 m/s^2

         Vertical position =  - 4.905 t^2 + 8.45 t

                  max will occur at  t = -b/2a =  -8.45 / (2* -4.905) = .861 s

      Plug in this value to find vertical height

   vertical position =  8.45(.861) - 1/2 (9.81)(.861)^2  = 6.92 m

b)   magnitude when it comes down = magnitude when it went up = 20 m/s

The total distance it travels in one period is 0.44m

Distance is a numerical or every so often qualitative size of how some distance aside items or factors are. In physics, the distance may check with the physical duration or an estimation primarily based on other criteria.

The space between the two factors in the physical space is the period of an immediate line among them, that's the shortest feasible course.

It reduces the entire or a part of the arena to a small sheet of paper. At the same time of making a map, cartographers have to pay attention to properly constitute the distance between two locations.

Calculation:

amplitude = 0.11m

total distance (s) = 4 (amp)

4 × 0.11 = 0.44m

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Answer:

Below

Explanation:

The man will have Gravitational  POTENTIAL energy due to Earth's gravity of mgh

 mgh = 68 kg * 9.81 m/s^2 * 6m = 4002 J

The bungee has ELASTIC potential energy of 1/2 k x^2

  where x = stretch distance and k = spring constant

         = 1/2 (82.6 N/m) ( 50-20 m)^2 = 37170 J

Total = 4002 + 37170 = 41172 J

Answer:

2.5 m/s²

Explanation:

F = ma (Newton's 2nd Law)

a = F/m = 3,000 N /  1,200 kg = 2.5 m/s²

Explanation:

If you apply a force on a box and push it across a surface, you are doing work on the box. The amount of work done is equal to the force applied multiplied by the distance the box moves in the direction of the force. This means that if you apply a greater force or move the box a greater distance, you will do more work on the box.

Once you let go of the box, the work that you did on the box is no longer being applied, and the box will come to a stop unless there are other forces acting on it (such as gravity or friction). If the box is on a horizontal surface and there is no friction, it will not move at all after you let go, and the work you did on it will be completely converted into kinetic energy (the energy of motion). If the box is on a sloping surface or there is friction, the kinetic energy will be converted into other forms of energy, such as heat, and the box will slow down and eventually stop.

Answer:

The mass of the air in a room can be calculated by multiplying the volume of the room by the density of the air. The volume of the room can be calculated by multiplying its length, width, and height. So, if the room has dimensions of 1m x 2m x 3m, its volume would be 1m x 2m x 3m = 6 cubic meters. If the density of the air in the room is 1.3kg/m³, the mass of the air in the room would be 6m³ x 1.3kg/m³ = 7.8kg.

The correct answer is option a. A red indicator light on a dashboard typically indicates a serious vehicle malfunction that needs to be addressed immediately.

This type of light is usually used to indicate a problem that could cause damage to the vehicle or affect its safety if not addressed promptly. It is important to pay attention to a red indicator light and to have the vehicle checked by a mechanic as soon as possible to diagnose and fix the problem.

A red indicator light on a dashboard typically indicates a serious or critical issue with the vehicle that requires immediate attention. Ignoring this light could lead to further damage or safety concerns. It is important to have the vehicle checked by a mechanic as soon as possible.

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Answer:

The players feel equal force against one another.

Explanation:

This is known from Newton's Third Law of Motion which states that for every action/force there is an equal and opposite reaction/force. Therefore, even if one player is larger, the force exerted on each player from the other is the same.

(a). A circuit is just a path that ends and begins the same vertex, hence the yes answer. (b). In a graph, a route is a series of nearby sides who cross at the same vertices.

In electronics, a circuit is a completely circular conduit through which electricity travels. A simple circuit comprises a current provider, conductors, and a demand. The term "circuit" refers generally to any ongoing path for the transmission of energy, information, or a signal.

(a). Any method of moving over the graph's edges is a route. There is no restriction on the beginning or ending vertices, edges, etc. A path is any feasible path that connects two vertices.

(b). In a cycle, the start and end vertices are the same. As a result, a route can be a cycle if its start and end vertices are similar and a cycle is established during traversal.

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When the voltage and resistance is doubled the current will remain constant.

The voltage and resistance are inversely correlated, and the current is directly proportional to both. Any change in voltage will have an equal and opposite effect on current. Therefore, doubling or tripling the voltage will result in doubling or tripling the current.We know that I = V/R where I = current V = voltage and R = resistance such that

Given voltage is doubled so v2 = 2V

and resistance is also doubled so R2= 2R

I2 = V2/R2 = 2V/2R = V/R = I

Hence I2 = I

Therefore the current will remain same when both voltage and resistance are doubled.

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The frequency at which it is broadcasting is 875 KHz for a local am radio station broadcasts at an energy of kj/photon

Given,

Energy of a photon = 5.80 x 10-31 kJ x ( 1000 J / 1kJ) = 5.8 x 10-28 J

We know,

E = hv

Here,

"h" is the plank's constant = 6.626 x 10-34 J.s

v = frequency in Hz

Now, rearranging the formula,

v = E / h

Substituting the values,

v = 5.8 x 10-28 J / 6.626 x 10-34 J.s

v = 875340 s-1 or Hz

Now, converting Hz to kHz,

Given, 1kHz = 103 Hz

= 875340 Hz x ( 1 kHz / 103 Hz)

= 875.3 kHz

Frequency = 875 kHz [3S.F]

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Answer:

ALL OF THE ABOVE

Explanation:

A vehicle undergoes acceleration when what three things happen?

If there is acceleration, the velocity will change, either increasing or decreasing. The correct answer is D.

The rate of growth of velocity is defined as acceleration. Acceleration usually indicates that the speed is changing, but this is not always the case. When an object is in motion in a circular track at a steady speed, it is still going to accelerate because its velocity direction changes.

Newton's Second Law states that an object's acceleration is the net result of all force applied to it. Acceleration is measured in meters per second squared.

The formula is given as,

a = Δv / Δt

If acceleration exists, the change of the velocity will be there and it may be increasing or decreasing. Then the correct option is D.

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The percentage of our total energy output is attributable to the thermic effect of food up to 10%.

Decreased thermic effects of food are observed differently in the elderly and may predispose them to fat gain. Increased energy expenditure is very important for weight loss efforts.

Types of vigorous activity that can boost your metabolism include brisk walking 2 miles or biking uphill. Total Energy Expenditure The amount of energy you expend per day includes not only the calories you expend during physical activity but also the calories expended at rest the calories expended when digesting food and heat generation.

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21 and 7 years make up the Earth-Mars synodic period. The ecliptic plane is where the orbits of Earth, Mars, and the cycler trajectory are located.

Synodic times are significant because they frequently correspond to direct observables, but physical rotation periods do not. This significance was crucial for determining the planets' orbital periods throughout the history of astronomy.

Synodic period: The amount of time it takes for a body in the solar system, such as a planet, the Moon, or a man-made satellite to return to the same or nearly the same location with respect to the Sun as seen from the Earth.

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Answer:

A The kinetic energy was converted to thermal energy

Explanation:

Friction braking is the most commonly used braking method in modern vehicles. It involves the conversion of kinetic energy to thermal energy by applying friction to the moving parts of a system. The friction force resists motion and in turn generates heat, eventually bringing the velocity to zero.

Answer:

The correct answer is A: The kinetic energy was converted to thermal energy.

When a bicyclist squeezes the brakes and slows down to a stop, the kinetic energy of the moving bicycle is converted to thermal energy. This is because the brakes on a bicycle work by converting the kinetic energy of the moving bike into heat energy through friction. When the brakes are applied, the brake pads clamp down on the brake rotor, which is attached to the wheel. The friction between the brake pads and the brake rotor slows the wheel down and converts the kinetic energy of the moving bicycle into heat energy. This heat energy can then be dissipated through the brake pads and the brake rotor, causing the bicycle to come to a stop.

Explanation:

Answer:

Is this a research paper?

Answer:

3×x for both .they did the same amount.

Answer:

v = 3231.09887 m/s

Explanation:

The attached image includes the steps to get to the answer provided.

Answer:

1/2 m v^2 = E        conservation of energy

Both will have the same speed.

v = (s2 - s1) / t     holds for both coins

The coin that slides down the frictionless track will take longer to reach the bottom - the speed for both at the bottom will be the same

The binding energy per nucleon of 235-U and 137-Cs is given below when a nucleus of 235u undergoes fission

235-U = 7.6 MeV

137-Cs = 8.39 MeV

What is the 235-U and 137-Cs nucleons' binding energy?

The following equation gives a nucleus' binding energy:

mc2 = BE, where BE is the binding energy.

m is a mass defect.

For 235U, c = 931.49 MeV/u is the speed of light.

A=235 m=1.9150664 BE=1.9150664 *931.49 MeV/u BE=1783.8648 MeV

The equation BE/A BE/A = 1738.648 MeV / 235 BE/A = 7.6 MeV determines the binding energy per nucleon.

Binding energy for 137-Cs is:

BE = 1.23383 u * 31.49 MeV/u, where m is the mass defect, giving 1149.3003 MeV.

The binding energy per nucleon, BE/A, is as follows:

A is 137 in the instance of 137-Cs, hence BE/A equals 1149.3003 MeV / 137 BE/A is 8.39 MeV.

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To find the apparent position of the fish to an observer outside the bowl, we can use the lens equation:

1/p + 1/q = 1/f

where p is the distance from the object (the fish) to the center of the lens (in this case, the center of the fishbowl), q is the distance from the image to the center of the lens, and f is the focal length of the lens.

The focal length of a lens is given by the formula:

f = (n-1)R/2(n-1)

where R is the radius of the lens (in this case, the radius of the fishbowl) and n is the refractive index of the lens material (in this case, water).

Since the diameter of the fishbowl is 28.0 cm, the radius is 14.0 cm. The refractive index of water is approximately 1.33, so the focal length is approximately 8.5 cm.

To find the apparent position of the fish, we need to find p and q. If we let q be the distance from the image to the center of the lens, then the distance from the fish to the center of the lens is p = R - q.

Substituting these values into the lens equation, we get:

1/p + 1/q = 1/f

1/(R-q) + 1/q = 1/f

Solving this equation for q, we find that q = R/2 = 14.0 cm/2 = 7.0 cm.

This means that the apparent position of the fish is 7.0 cm from the center of the fishbowl.

To find the magnification of the fish to an observer outside the bowl, we can use the formula:

m = -q/p

Substituting the values we found above, we get:

m = -7.0 cm / (14.0 cm - 7.0 cm) = -1/2 = -0.5

This means that the fish is magnified by a factor of -0.5, or half its size.

A. The original momentum of the fullback is 450 Kg.m/s

B. The impulse imparted on the fullback is 450 Ns

C. The force exerted on the fullback is 900 N

D. The force exerted on the tackler is -900 N

A. How do I determine the original momentum?

The original momentum of the fullback can be obtained as follow:

Momentum = mass × velocity

Momentum of fullback= 90 Kg × 5 m/s

Momentum of fullback = 450 Kg.m/s

B. How do I determine the impulse imparted?

The impulse imparted, can be obtained as shown below:

Impulse = m(v + u) since the came to rest

Impulse = 90 × (0 + 5)

Impulse = 90 × 5

Impulse = 450 Ns

C. How to determine the force exerted on the fullback?

The force exerted on the fullback can be obtain as follow:

Impulse = force × time

450 = Force × 0.5

Divide both sides by 0.5

Force = 450 / 0.5

Force = 900 N

D. How to determine the force exerted on the tackler?

From Newton's 3rd law of motion which states that to every action, there is an equal an opposite reaction.

Since the force exerted on the fullback is 900 N. Thus, the force exerted on the tackler will be -900N

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The speed of the platform so that the person detects a beat frequency of 1.00 Hz is 5.286m/s.

The speaker moving towards the wall is emitting the sound of frequency of 115Hz and the platform right next to the speaker is detecting the sound reflected by the wall and emitted by the speaker.

Now, to find the speed of the platform so that the person here the beta frequency pf 1.00Hz, we will use the relation,

F = (c+v/c-v)f

c = Speed of waves in the medium

u = Speed of the receiver relative to the medium

v = Speed of the source relative to the medium

f = emitted frequency

Our values are given,

Beat frequency = 7Hz

Reflective Doppler frequency = 225+7=232Hz

Putting values,

232 =  (c+v/c-v)225

solving further,

v = 5.286 m/s.

So, the speed of the platform shoud be 5.286m/s.

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When we go 19113 Km above the surface of earth, the weight of the person will become half.

The weight of the person is given by

W = Mg

Where,

M is mass of the person and g is the gravitational acceleration.

The gravitational acceleration of the earth varies with the height from the surface of the earth as,

g' = g(R/(R+H))²

Where,

R is the radius of earth,

g' is the gravitational acceleration at height H,

For g' = g/2,

g/2 = g(R/(R+H))²

1/√2 = (R/(R+H))²

Solving further,

H = 3R

So, when we go to a distance 3R above the surface of earth the weight of the person will become half.

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The runner takes 11.61 s to complete the entire race when they continue with same speed.

If the runner accelerated for 6.4 s, the velocity at which they accelerated will be:

Acceleration = velocity/time

3 = V/6.4

Making V the subject and by cross multiplying,

V = 3 × 6.4

V = 19.2 m/s

The runner maintains the speed through out the journey.

Speed = distance/time

Making time as the subject of formula,

Time = distance/speed

Time = 100 / 19.2

Time = 5.21 s

Therefore, a runner will complete the entire race in 6.4 + 5.21 = 11.61 s

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Answer:

Newton's First Law of Motion (aka Law of Inertia)

Explanation:

Answer:

Explanation:

a = ΣF/m

a = (0.4kg * 9.8m/s^2)/(5.98 * 10^24kg)

a = 6.56 * 10^-25 m/s^2