A resistor dissipates 2.00 W when the rms voltage of the emf is 10.0 V. At what voltage will the resistor dissipate 10.0 W

Nicolaus Copernicus wrote the pioneering book that suggested the Earth probably orbits the Sun (instead of the other way around).

The father of modern astronomy is Polish astronomer by the name of Nicolaus Copernicus. He was the first contemporary scientist from Europe to put forth the Heliocentric Theory of the universe, which holds that Earth and other planets rotate around the sun.

By reading other astronomers' writings and making his own observations, Copernicus established his heliocentrism theory. He noted that heliocentrism provided a much more comprehensive explanation for the motions of the planets. Nicolaus Copernicus created his own heliocentric planetary system astronomical model. He published his results in the Commentariolus somewhere about 1514.

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The deceleration is -8 m/s² and the time taken by the car is 2.5 s.

It is given that,

Speed, v = 8 m/s

Distance, d = 20m

We need to find the time taken by the car and deceleration.

As we know speed is defined as

v = d/t

Plugging in the values,

t =  20/8

t = 2.5s

Now from the deceleration formula,

a =  - v/ t

a is the deceleration, v is the speed and t is the time taken.

a = - 20/ 2.5

a = - 8 m/s²

Thus, the time taken by the car and deceleration is 2.5 s and -8 m/s² respectively.

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Hot spot volcanism is responsible for the formation of volcanic island chains in the oceans and is denoted as option D.

This is a rupture in the earth crust thereby giving rise to the release of hot lava, gases etc from below the surface.

The pushing of the lava through the cracks partially melts the plate at a subduction zone thereby forming the volcanic island chains.

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Considering the definition of potential energy, the potential energy of the box is 42.9678 J.

Potential energy is the energy that measures the ability of a system to do work based on its position. In other words, this is the energy that a body located at a certain height above the ground has.

Gravitational potential energy is the energy associated with the gravitational force. This will depend on the relative height of an object to some reference point, the mass, and the strength of gravity.

So for an object with mass m, at height h, the expression applied to the gravitational energy of the object is:

Ep= m×g×h

Where:

In this case, you know:

Replacing in the definition of potential energy:

Ep= 7.3 kg × 9.81 m/s² × 0.60 m

Solving:

Ep= 42.9678 J

Finally, the potential energy of the box is 42.9678 J.

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-ItzKenzo

-CuteSiKenzo(Oo cute)

Alam kung wala kang pake tángina mo!!

The frequency is 94.2 Hz

We  are given the energy of a photon = 6.24x10-29 kJ

We  are asked to find the frequency (ν),

We use the equation E = hν where E is energy, h is Planck's constant and ν is the frequency

The quantity of events per unit of time that occur when an event repeats itself at regularly spaced intervals is known as its frequency.

6.24x10-29 kJ = 6.626x10-34 J-sec * ν

ν = 6.24x10-29 kJ x 1000 J/kJ  / 6.626x10-34 Jsec

ν = 6.24x10-26 J / 6.626x10-34 Jsec

ν = 0.942x108 s-1 = 9.42x107 s-1 = 9.42x107 Hz

9.42x107 Hz x 1 MHz/106 Hz = 94.2 MHz

Hence the frequency is 94.2MHz

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(a) By using the law of conservation of energy, the distance moved by the solid disk along the ramp is 0.96 m.

(b) The answer does not depend on the mass and radius of the disc as these values are canceled when the law of conservation of energy is applied.

What is the law of conservation of energy?

The law of conservation of energy states that the total energy of an isolated system is conserved.

The total initial energy Ei of the disc rolling down an inclined plane is given by the formula,

Ei=1/2*mv^2 + 1/2*Iω^2

where m is the mass of the disc, v is the velocity of the disc, I is the moment of inertia and ω is the angular velocity of the disc.

For a solid disc, I=1/2mr^2, and since it is rolling without slipping, the rolling velocity of the disc will be equal to its translational velocity, that is,

v=ωr or ω=v/r

So using ω=v/r and I=1/2mr^2, it can be written,

Ei=1/2*m(v)^2 + 1/2*(1/2mr^2)(v/r)^2

Ei=1/2*m(v)^2*(1+1/2*)

Ei=3/4*mv^2

If the height covered by the disc is h before stopping, then its final total  energy Ef will be equal to the potential energy, that is,

Ef=m*g*h

From the law of conservation of energy, it can be written,

Ei=Ef

3/4*mv^2=m*g*h

h=3v^2/(4g)

The length of the ramp is then given by the formula,

l=hcosecθ

where θ is the inclination angle. So

l= 3v^2/(4g)*cosecθ

Here g=9.8 m/s^2, v=2.5 m/s  and θ=30.0 degree. Using these values,

l= 3*(2.5 )^2/(4*9.8)*cosec( 30)

l= 0.96 m

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Answer:

In my opinion the unstoppable object will hit the unmovable object and stop but the wheels will still be rolling and trying to move but can't.

The magnitude and direction of the electric field at the position of this charge.3.33 N/C upward

An electric field is the electric force per unit of charge. It is assumed that the field's direction corresponds to the direction in which a positive test charge would experience force. The electric field is directed radially inward toward a negative point charge and radially outward from a positive charge.

Value of force F given  = 10N

value of charge Q = 3 C

We know that E = F/Q

E = 10/3

= 3.33N

where charge is scalar quantity so the direction of force is the direction of electric field

Hence the magnitude and direction of the electric field at the position of this charge.3.33 N/C upward

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Answer:

The force of gravitation is 1.98×10^(20) m.

Explanation:

Note: The value of m1, m2, r, and G is taken to be 5.97×10^(24) kg, 7.348×10^(22) kg, 3.84×10^(8) m, and 6.67×10^(-11) N m^2/ kg^2 respectively.

The force of gravitation F acting between two masses is calculated using the formula,

F=Gm1m2/ r^2

where G is the gravitational constant.

Hence force F is

F=6.67×10^(-11)×5.97×10^(24)×7.348×10^(22)/ (3.84×10^(8))^2

F=1.98×10^(20) N

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The velocity of the golf ball is 65.2 m/s

The principle of conservation of momentum is that the momentum before collision is equal to the momentum after collision.

Given that;

(0.2kg *  55 m/s) + (0.046kg * 0 m/s) = (0.2kg * 40 m/s) + (0.046kg  * v)

11 = 8 + 0.046v

v = 11 - 8/0.046

v = 65.2 m/s

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Answer:

B = μ I / (2 * R)     magnetic field at center of current carrying loop

I1 / R1 = I2 / R2        and we want to know R2

R2 = I2 / I1 * R1 = 29 / 10 * 01 = .029 m

The thermal energy was produced is 116J

Now we know that the frictional force produces the energy that is lost as heat as the body slides down the incline. The magnitude of the frictional force is obtained from;

Ff= μmgcosθ

Ff =  0.65 *  5.0 kg * 9.8 m/s^2 * cos 25

Ff = 29 N

Hence, the thermal energy is;

29 N * 4.0 m = 116J

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Potential relays measure the back emf developed across the start winding to operate the relay.

What is Potential:

Potential relays are used with single-phase capacitor, which need relatively high starting torque.

Their main function is to assist in starting the motor.

When power is applied to the coil, the contact(s) change position.

A relay with power applied to the coil is said to be energized.

Back EMF is the system in the coil of an electric motor that opposes the current flowing through the coil, when the armature rotates.

so here,

Potential relays measure the back emf developed across the start winding to operate the relay.

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The average power needed to produce this final speed is 1069.1 hp.

Mass of the dragster,  m = 500.0 kg,

Displacement travelled by the dragster,  s = 402 m,

Time taken in this travel,  t = 5.0 s,

Final velocity of the dragster,  v = 130 m/s.

Let the initial velocity of the dragster be u and acceleration be a.

Using kinematical equation,  s = ut + (1/2)at^2.

402  =  u*5  + (1/2)*a*5^2

10*u + 25*a  = 804.      ...........(1)

Using kinematical equation, v = u +at.

130 = u + 5*a

5*u + 25*a = 650.       .............(2)

Solving (1)and (2), we get,

u =  30.8 m/s.

According to work-energy theorem,

Work done = change in kinetic energy

W  = (1/2)*m*(v^2 - u^2)

W = (1/2)*500*(130^2 - 30.8^2)

W  =  3987840. J

Therefore power rating of the dragster is given by,

P  ⇒  W/t. =  3987840/5 = 797568 watt.

P  ⇒ 797568/746 =  1069.1 hp.

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The answer is 1069.1 hp.  

Mass of the dragster,  m = 500.0 kg,

Displacement travelled by the dragster,  s = 402 m,

Time taken in this travel,  t = 5.0 s,

Final velocity of the dragster,  v = 130 m/s.

Let the initial velocity of the dragster be u and acceleration be a.

Using kinematical equation,  s = ut + (1/2)at^2.

 402  =  u*5  + (1/2)*a*5^2

 10*u + 25*a  = 804.      ...........(1)

Using kinematical equation, v = u +at^.

 130 = u + 5*a^

5*u + 25*a = 650.       .............(2)

Solving (1)and (2), we get,

u =  30.8 m/s.

According to work -energy theorem,

Work done = change in kinetic energy

 W  = (1/2)*m*(v^2 - u^2)

,  W = (1/2)*500*(130^2 - 30.8^2)

,  W  =  3987840. J

therefore Power rating of the dragster is given by,

P  =  W/t. =  3987840/5 = 797568 watt.

,  P  = 797568/746 =  1069.1 hp.        

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The Measure of angle E is 55° and Length of the side EF is 12.49 units

The diagram is missing in the question and hence the diagram is shown below!!!

Given the triangle EDF with angle measures ∠D = 43° and ∠F = 82°.

As, we know, The sum of the measures of angles in a triangle is 180°.

So, we have,

∠E + ∠D + ∠F = 180°

i.e. ∠E + 43° + 82° = 180°

i.e. ∠E = 180° - 125°

i.e. ∠E = 55°

Thus, the measure of angle E is 55°.

Further we have

15/sin55 = EF / sin43

∴ EF =  15*sin43/sin55

∴EF = 10.23/0.189

EF = 12.49 units

Hence the length of side of EF is 12.49 units

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Please give the person above me brainliest!!!

✔ 55

✔ 12.49

The distance traveled by the box along the ramp is 0.51 m.

Apply the principle of conservation of energy;

Potential energy of the box at top of incline = Elastic potential energy at bottom

mgh = ¹/₂kx²

where;

h = L sinθ

where;

mg(L sinθ) = ¹/₂kx²

(18)(9.8)(L sin25) = ¹/₂(740)(0.32)²

74.55 L = 37.89

L = 37.89 / 74.55

L = 0.51 m

Thus, the distance traveled by the box along the ramp is 0.51 m.

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The beat frequency he hears in his head will be 1.6 Hz

A sound pressure wave's frequency, also known as pitch, is the number of times it repeats itself every second.

The frequency of the sound is the inverse of the period. If the wavelength of a wave is short. The wave will indeed have a lower frequency. A longer wavelength denotes a lower frequency.

Given data;

The frequency at which the fluorescent light "hums",f=120 Hz

The frequency at which the bored grad student "hums",f'=118.4 Hz

The beat frequency he hears in his head is,fₐ=?

The beat frequency he hears in his head is found as;

fₐ = f-f'

fₐ = 120 - 118.4 Hz

fₐ = 1.6 Hz

Hence the beat frequency he hears in his head will be 1.6 Hz.

At 120 Hz, a fluorescent light "hums." At 118.4 Hz, a Ph.D. student who is bored hums. He hears 1.6 Hz as the rhythm frequency in his brain.

Hence the beat frequency he hears in his head will be 1.6 Hz

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The maximum grade (in percent) is 14%.

Suppose angle be theta.

Power = force * velocity

35*746 = [1300*9.8* sin theta + 410]* (43*1000/3600)

sin theta = (35*746/(43*1000/3600) - 410)/(1300*9.8) = 0.139

grade = tan ( arcsin 0.139 )

= 0.140

= 14%

Drag is a mechanical pressure. it is generated via the interplay and speaks to a stable body with a fluid (liquid or fuel). It is not generated via a force area, within the feel of a gravitational field, or an electromagnetic field, wherein one item can have an effect on some other item without being in physical touch.

For instance drag on a ship moving in water or drag on an aircraft shifting in the air. therefore drag pressure is the resistance pressure resulting from the motion of a body thru a fluid like water or air. This drag force acts opposite to the path of the oncoming float velocity.

Drag is generated via the distinction in speed between the strong item and the fluid. There needs to be motion among the object and the fluid. If there's no movement, there's no drag. It makes no difference whether or not the item moves via a static fluid or whether or not the fluid movements beyond a static stable item.

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The maximum grade (in percent) is 14%.

Suppose angle be theta.

Power = force * velocity

35*746 = [1300*9.8* sin theta + 410]* (43*1000/3600)

sin theta = (35*746/(43*1000/3600) - 410)/(1300*9.8) = 0.139

grade = tan ( arcsin 0.139 )

= 0.140

= 14%

Drag is a mechanical pressure. it is generated via the interplay and speaks to a stable body with a fluid (liquid or fuel). It is not generated via a force area, within the feel of a gravitational field, or an electromagnetic field, wherein one item can have an effect on some other item without being in physical touch.

For instance drag on a ship moving in water or drag on an aircraft shifting in the air. Therefore drag pressure is the resistance pressure resulting from the motion of a body thru a fluid like water or air. This drag force acts opposite to the path of the oncoming float velocity.

Drag is generated via the distinction in speed between the strong item and the fluid. There needs to be a move between the object and the fluid. If there's no movement, there's no drag. It makes no difference whether or not the item moves via a static fluid or whether or not the fluid moves beyond a static stable item.

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The rms current in the primary coil of a transformer is 0.5 Ampere .

Energy/power is not gained or lost going through an ideal transformer.

Consequently, the transformer in this situation doesn't really matter. The entire device receives 60 watts of power from the wall outlet if the lamp consumes energy at a rate of 60 watts.

∴ Power = (voltage) x (current)

60 watts = (120 v) x (current)

Current = (60 watts) / (120 v)

Current = 0.5 Ampere

Therefore, the rms current in the primary coil of a transformer is 0.5 ampere.

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Runner A is faster than runner B and Runner B has a head start.

The velocity time graph shows us how fast that an object can be. The slope of the graph is the acceleration.

If we look at the graph as shown in the image attached to this answer, we can see that Runner A is faster than runner B and Runner B has a head start.

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Answer:

Runner A is

✔ faster

than runner B.

Runner

✔ B

has a head start.

Explanation:

2.25 m/s² of acceleration is required to increase the speed of a car from 26 mi/h to 51 mi/h in 5 seconds.

To find the answer, we need to know about the acceleration.

Thus, we can conclude that the constant acceleration is 2.25 m/s².

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The ratio of the height attended by the object thrown upward to that thrown at some angle θ with the vertical is 1.  

Note: It is assumed that the mass of the first object is m and the mass of the second object is 2m. Also, the first object is thrown upward and the second object is thrown at some angle θ with the vertical.

Projectile motion: Any object that is thrown in the air is called a projectile and the motion described by it under gravity is called the projectile motion.  

If the air resistance is neglected, then the acceleration due to gravity g is the same for all objects irrespective of their masses. It is given that both objects remain in the air for the same time period. So first calculate the time period for the objects when they are in the air.

Time period of the first object: The first object is thrown in the air upwards so from the second kinematics equation,

h1=u1*t1-(1/2)*gt1^2

where h1 is the height, t1 is the time, and u1 is the initial velocity for the first object.

When the object is not in air h1=0, so

0=u1*t1-(1/2)*gt1^2

After solving the above quadratic equation, the values of t1 obtained are t1=0 which represents the initial time, and t1=2u1/g which represents the time period. So the time period of the first object is,

t1=2u1/g

Time period of the second object: The second object is thrown at some angle θ with the vertical as shown in the diagram. From the diagram, the initial velocity along the vertical direction is,

u2=uocos(θ)

where uo is the initial velocity and u2 is the initial velocity along the vertical direction.

From the second kinematic equation,

h2=u2*t2-(1/2)*gt2^2

where h2 is the height, t2 is the time, and u2 is the initial velocity for the second object along the vertical direction.

When the object is not in air h2=0, so using u2=uocos(θ),

0=uocos(θ)*t2-(1/2)*gt2^2

After solving the above quadratic equation, the values of t2 obtained are t2=0 which represents initial time, and t2=2uocos(θ)/g which represents  the time period. So the time period of the second object is,

t2=2uocos(θ)/g

Given that the time period is the same for both cases,

t1=t2

2u1/g=2uocos(θ)/g

u1=uo cos(θ)

Calculation of the ratio of the height of the object:

The maximum height is attained when the time of the object in the air is half of the total time period. At maximum height, velocity is zero.

From the third equation of motion.

v^2=u^2-2gh

h=u^2/2g

where h is the height and u is the initial velocity of an object.

Using it and u1=uo cos(θ) and u2=uo cos(θ), the ratio of h1 and h2 is,

h1/h2=  u1^2/2g÷u2^2/2g

h1/h2=(uo cos(θ))^2/(uo cos(θ))^2

h1/h2=1

The ratio of their height will be 1.

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Answer:

Amount of energy required to change the 1kg of a substance without changing its temperature.

When displacement is 0, an object is at its equilibrium position, at that moment, its speed is maximum and its acceleration is zero.

Speed is a scalar quantity used in physics to indicate the distance of change of an object that travels in any direction.

Conversely, displacement and acceleration are vector quantities because they express magnitudes but not a direction.

In conclusion, when an object is at its equilibrium position its speed is maximum and its acceleration is zero.

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Answer:

We feel cold when tap or well water in winter because heat flows from hot body to cold body.

Explanation:

Our body is in optimal status is a hot body and tap or well water is a cold body. Therefore we feel cold.

When we drink tap or well water in the winter, we feel chilled because heat transfers from a hot body to a cold body.

Convection, often known as a heat transfer mechanism, is a method of moving heat. When a fluid, such as air or water, is moving, this heat transfer takes place. Temperature differences within the fluid cause convection.

Due to the increased kinetic energy of the particles, a fluid loses density at the area nearest to the heat source as it is heated. The less dense portion of the fluid then rises, while the denser portion sinks.

The process keeps happening because the less dense fluids sink as they move away from their heat source while the denser fluids rise as they move toward the heat source. Convection currents are produced by this.

Therefore, When we drink tap or well water in the winter, we feel chilled because heat transfers from a hot body to a cold body.

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The spring constant is 147 N/m

Given the mass of the block is 2.00 kg , the mass of the body is 300 g and the length of the spring is 2.00 cm

We need to find the spring constant

A spring is an object that can be deformed by a force and then return to its original shape after the force is removed.

The force required to stretch an elastic object such as a metal spring is directly proportional to the extension of the spring

We know that F = kx

300(9.8)= k (0.02)

k = 147.15 N/m

Rounding off to the nearest is 147N/m

The spring constant is 147N/m

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The work done by force on a spring hung from the ceiling will be 1.67 J

Any two things with mass are drawn together by the gravitational pull. We refer to the gravitational force as attractive because it consistently seeks to draw masses together rather than pushing them apart.

Given that a spring is hung from the ceiling with a 2.0-kg mass suspended hung from the spring extends it by 6.0 cm and a downward external force applied to the mass extends the spring an additional 10 cm.

We need to find the work done by the force

Given mass is of 2 kg

So let,

F = 2 kg

x = 0.1 m

Stiffness of spring = k = F/x

k = 20/0.006 = 333 n/m

Now the formula to find the work done by force will be as follow:

Workdone = W = 0.5kx²

W = 0.5 x 333 x 0.1²

W = 1.67 J

Hence the work done by force on a spring hung from the ceiling will be 1.67 J

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The height reached by the projectile from the point of projection is determined as 12.84 m.

H = vt + ¹/₂gt²

where;

H = (13.2 x sin37)(1) + (0.5)(9.8)(1)²

H = 12.84 m

Thus, the height reached by the projectile from the point of projection is determined as 12.84 m.

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