The area of the rectangle obtained is (3.75 ± 0.03) m². The perimeter of the rectangle obtained is (8 ± 0.64) m.
Given dimensions:
Length (L) = (2.5 ± 0.2) m
Width (W) = (1.5 ± 0.2) m
(a) Area of the rectangle (A) is given by:
A = L × W
A = (2.5 ) × (1.5 )
A = 3.75 m²
The relative uncertainty in area = ΔA / A
ΔA = (ΔL / L) × A + (ΔW / W) × A
ΔA = (0.2 / 2.5) × 3.75 + (0.2 / 1.5) × 3.75
ΔA = 0.03 m²
Therefore, the area of the rectangle is (3.75 ± 0.03) m².
(b) Perimeter of the rectangle (P) is given by:
P = 2 × (L + W)
P = 2 × (2.5 + 1.5)
P = 2 × 4
P = 8 m
Relative uncertainty in perimeter = ΔP / P
ΔP = (ΔL / L) × P + (ΔW / W) × P
ΔP = (0.2 / 2.5) × 8+ (0.2 / 1.5) × 8
ΔP = 0.64 m
Therefore, the perimeter of the rectangle is (8 ± 0.64) m.
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I need help asap!!!
Answer:
Probably competition with television news-
by 1953 television was becoming common in many houses and people could obtain news from television newscasts
1. A supersonic airplane is flying horizontally at a speed of 2610 km/h. What is the centripetal acceleration of the airplane, if it turns from North to East on a circular path with a radius of 80.5 km?
2. How much time does the turn take?
3. How much distance does the airplane cover during the turn?
1)The centripetal acceleration will be 84622.360 km/h².
2)The time the turn take is 0.19 hour.
3)The distance the airplane cover during the turn is 505.54 km.
What is centripetal acceleration?The acceleration needed to move a body in a curved way is understood as centripetal acceleration.
The direction of centripetal acceleration is always in the path of the center of the course. The total acceleration is the result of tangential and centripetal acceleration.
The given data in the problem;
R is the radius= 80.5 m
v is the linear speed = 2610 km/h
a is the total acceleration.
1)
The centripetal acceleration is found by
[tex]\rm a_c = \frac{v^2}{R} \\\\ a_c = \frac{(2610 \ km/h)^2}{80.5} \\\\ a_c = 84622.360 \ km/h^2[/tex]
2)
The time the turn take is;
[tex]\rm a= \frac{4 \pi^2R}{T^2} \\\\\ 84622.360 = \frac{4 \times (3.14)^2 \times 80.5}{T^2} \\\\\ T = 0.19 \ hr[/tex]
3)
The distance the airplane cover during the turn is;
C= 2πR
C=2 × 3.14 × 80.5 km
C= 505.54 km
Hence centripetal acceleration, time the turn take, and distance the airplane cover during the turn will be 84622.360 km/h²,0.19 sec, and 505.54 km respectively.
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A transformer consists of 340. primary windings and 980. secondary windings. If the emf of the primary coil is 30.0 V, what is the emf across the secondary coil? 34.7 Ω
Answer:
86.47 V
Explanation:
It will be multiplied by the ratio of the windings
980/340 * 30 = 86.47 v
1. Refer to the diagram. A magnet is moved away from a coil that is connected to a galvanometer. Explain how applying Lenz’s law helps determine the direction of the induced emf in the coil. What is the direction of the induced emf in the coil? Explain how the direction can be verified using the second right-hand rule.
The Lenz's law gives the direction of induced current. According to this law, the induced current opposes the cause that produces it.
What is Lenz law ?Lenz's law states that: The current induced in a circuit due to a change in a magnetic field is directed to oppose the change in flux and to exert a mechanical force which opposes the motion.
According to the question,
If we keep the magnet stationary and moved the coil back and forth within the magnetic field, an electric current would be induced in the coil.
Then by either moving the wire or changing the magnetic field we can induce a voltage and current within the coil and this process is known as Electromagnetic Induction.
When the coil AB is approaching towards north pole of the magnet, the magnetic flux linking to the coil increases.
Now according to Lenz's law,
This magnetic field created will oppose its own or we can say opposes the decrease in flux through the coil and this is possible only if approaching coil side attains south polarity, as we know dissimilar poles attract each other.
Once we know the magnetic polarity of the coil side, we can easily determine the direction of the induced current by applying right hand rule. In this case, the current flows in the A to B direction.
The right-hand rule. If you point your pointer finger in the direction the positive charge is moving, and then your middle finger in the direction of the magnetic field, your thumb points in the direction of the magnetic force pushing on the moving charge.
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A point charge Q1 = +6.0 nC is at the point (0.30 m, 0.00 m); a charge Q2 = -1.0 nC is at (0.00 m, 0.10 m), and a charge Q3 = +5.0 nC is at (0.00 m, 0.00 m). What are the magnitude and direction of the net force on the +5.0-nC charge due to the other two charges? (k = 1/4πε0 = 9.0 × 109 N ∙ m2/C2)
Answer:
My Answer is Answer
Explanation:
We can use Coulomb's equation, which states that the force between two point charges is imparted: due to the other two charges ([tex]\rm Q_1[/tex] and [tex]\rm Q_2[/tex]) to obtain a net force on the +5.0 nC charge ([tex]\rm Q_3[/tex]).
[tex]\rm F = k * |Q_1 * Q_2| / r^2[/tex]
where:
F = force between the charges
k = Coulomb's constant ≈ 9.0 x [tex]\rm 10^9 N.m^2/C^2[/tex]
[tex]\rm Q_1[/tex] and [tex]\rm Q_2[/tex] = magnitudes of the charges
r = distance between the charges
Calculating the forces separately for each pair of charges and then find the net force:
Force between [tex]\rm Q_3[/tex] and [tex]\rm Q_1[/tex]:
[tex]\rm Q_3[/tex] = +5.0 nC = +5.0 x [tex]10^-^9[/tex] C
[tex]\rm Q_1[/tex] = +6.0 nC = +6.0 x [tex]10^-^9[/tex] C
[tex]\rm r_1[/tex] = distance between [tex]\rm Q_3[/tex] and [tex]\rm Q_1[/tex] = √[(0.00 m - 0.30 m[tex])^2[/tex] + (0.00 m - 0.00 m[tex])^2[/tex]] ≈ 0.30 m
[tex]\rm F_1[/tex]= k * |[tex]\rm Q_3[/tex] * [tex]\rm Q_1[/tex]| / [tex]\rm r_1^2[/tex]
[tex]\rm F_1[/tex] = (9.0 x [tex]10^9[/tex] N·[tex]\rm m^2/C^2[/tex]) * |(5.0 x [tex]10^-^9[/tex] C) * (6.0 x [tex]10^-^9[/tex] C)| / (0.30 [tex]\rm m)^2[/tex]
[tex]\rm F_1[/tex]≈ 6.0 N (towards the left)
Force between [tex]\rm Q_3[/tex] and [tex]\rm Q_2[/tex]:
[tex]\rm Q_3[/tex] = +5.0 nC = +5.0 x [tex]10^-^9[/tex] C
[tex]\rm Q_2[/tex] = -1.0 nC = -1.0 x [tex]10^-^9[/tex] C
r2 = distance between Q3 and Q2 = √[(0.00 m - 0.00 m)^2 + (0.00 m - 0.10 m)^2] ≈ 0.10 m
[tex]\rm F_2[/tex] =[tex]\rm k * |Q_3 * Q_2| / r2^2[/tex]
[tex]\rm F_2[/tex] = (9.0 x [tex]\rm 10^9 N.m^2/C^2[/tex]) * |(5.0 x [tex]10^-^9[/tex] C) * (-1.0 x [tex]10^-^9[/tex] C)| / (0.10 [tex]\rm m)^2[/tex]
[tex]\rm F_2[/tex] ≈ 45.0 N (towards the top)
Now we can sum the forces in the x and y directions to determine the net force:
Net force in the x-direction = [tex]\rm F_1[/tex] = 6.0 N (to the left)
Net force in the y-direction = [tex]\rm F_2[/tex] = 45.0 N (upwards)
The Pythagorean theorem can be used to determine the magnitude and direction of the net force.
Magnitude of net force = √(Net force in the x-direction[tex])^2[/tex]+ (Net force in the y-direction[tex])^2[/tex]
Magnitude of net force ≈ √(6.0 N[tex])^2[/tex] + (45.0 N[tex])^2[/tex]≈ √(36 [tex]\rm N^2[/tex] + 2025 [tex]\rm N^2[/tex]) ≈ √(2061 [tex]\rm N^2[/tex]) ≈ 45.4 N
The direction of the net force is the angle θ:
θ = arctan(Net force in the y-direction / Net force in the x-direction)
θ = arctan(45.0 N / 6.0 N) ≈ arctan(7.5) ≈ 82.9°
As a result, the net force exerted by the other two charges on the +5.0 nC charge has a strength of about 45.4 N and is directed about 82.9° above the negative x-axis (in the upper left direction).
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3.2 Define conservation of energy.
Answer:
A principle stating that energy cannot be created or destroyed, but can be altered from one form to another.
Explanation:
Answer : C) Electrons are many thousand times smaller than the nucleus and negatively charged.
Reasoning : Edguinity
The mass of a proton and neutron and the positive charge of the proton accounts for why the electrons are thousands of times smaller than the nucleus and negatively charged.
What are electrons?Electrons are one of the three fundamental particles that make up an atom.
Electrons are negatively-charged particles which are found in certain regions of space around the nucleus of an atom at a particular instant.
The nucleus is composed of protons and neutrons. The protons are positively-charged while the neutrons are neutral. Thu, the negative charge of the electron balances the positive charge of the nucleus.
The mass of a proton is about 1840 times heavier than the electron. Thus, the nucleus is many thousand times heavier than the electron.
In conclusion, the negative charge of the electron ensures an atom is neutral.
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how is this answer correct
Answer:
b
Explanation:
c is a velocity time graph, showing how a body moves with constant velocity with change in time
You cover the following displacements every day going to school: d1=50 m, E and d2=95 m, N. You do this for 12 minutes. a) What is your speed in m/s? b) What is your velocity in m/s?
The speeds and velcity will be 0.020 m/sec and 0.0149 m/sec.
What is speed?Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while V for the final speed. its si unit is m/sec.
Given data;
d1=50 m E
d2=95 m N
Time period,t = 12 min = 12 × 60 sec = 7200 sec
The displacement is the shortest distance found from the pythogorous theorem as;
Displacement = √[(50 )²+(95)²]
Displacement = 107.35 m
a)The speed is found as;
Speed = distance / time
Speed = 50 +95 / 7200
Speed = 0.020 m/sec
b)The velocity is found as;
Velocity = Displacement / time
Velocity = 107.35 / 7200
Velocity = 0.0149 m/sec
Hence the speed and the velcity will be 0.020 m/sec and 0.0149 m/sec.
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6. (a) Suppose the earth is revolving round the sun in a circular orbit of radius one b astronomical unit (1.5% 10 km). Find the mass of the sun. G = 6.67 x 10" N m² kg 2. (b) If the mass of sun is 2 x 10" kg, distance of earth from the sun is 1.5 x 10¹ m and period of revolution of the former around the latter is 365.3 days, find the value of G.
Answer:
tough
ques
Explanation:
An extended body (not shown in the figure) has its center of mass at the origin of the reference frame. In the case below give the direction for the torque τ with respect to the center of mass of the body due to force F acting on the body at a location indicated by the vector r.
Options are:
X
-Y
Z
-Z
The direction of torque τ this method is mathematically given as
D=X
Option A is correct.
What is the direction of torque?Generally, the equation for torque is mathematically given as
τ = r X F
Since F is the force exerted on the body at r, we need to know the direction of this torque with regard to the body's center of mass.
The dominant hand (the right) is used.Just run the fingers of our right hand along the line r.Our right palm should be placed on the letter F. Then, we'll gradually move r into F. The direction of the thumb's motion will indicate the torque's vector.In conclusion, the direction of this method is
D=X Option A.
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the main source of this energy is
.
Answer:motion
Explanation:
kinetic energy of an object that it possess due to its motion.
Magnets attract objects made up of _______;_______and _______
Which of the following statements regarding work and retirement is true?
The statement regarding work and retirement that is true is that most older Americans say they would prefer to enter retirement gradually.
What is retirement?Retirement is defined as the time in an individuals life that such leaves the Labour market or the workforce.
In some countries such as the United States of America, most elderly citizen prefer taking retirement process slowly.
Therefore, the statement regarding work and retirement is that retirement is a gradual process which one starts to process while actively in service
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The figure below shows a man in a boat on a lake. The man's mass is 74 kg, and the boat's is 135 kg. The man and boat are initially at rest when the man throws a package of mass m = 15 kg horizontally to the right with a speed of vi = 5.0 m/s.
What is the velocity of the boat after the package is thrown? Neglect any resistance force from the water. (Give the magnitude in m/s, and select the correct direction from the options given.)
The velocity of the boat after the package is thrown is 0.36 m/s.
Final velocity of the boat
Apply the principle of conservation of linear momentum;
Pi = Pf
where;
Pi is initial momentumPf is final momentumv(74 + 135) = 15 x 5
v(209) = 75
v = 75/209
v = 0.36 m/s
Thus, the velocity of the boat after the package is thrown is 0.36 m/s.
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A planet X moves in an elliptical path as shown below. At which point does the planet moves faster. B Assume, Ethiopian institute of space science and technology, allows to launch a space station with you. While you are in orbit, you gets thirsty. The only thing in the space station were a cup of water. you go to the cup of water and pick it up, But unfortunately your hand is twisted and the cup is turned down. Because the cup is turned down, water pour on to the floor. How would you get water?
We can get water from the sweat and exhaled breath of the people present in the space station.
How would you get water?We can get water from the sweat and exhaled breath. The water we drink is recycled from the sweat and exhaled breath of the people present in the space station which was collected through condensation on the Space Station's walls.
So we can conclude we can get water from the sweat and exhaled breath of the people present in the space station.
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A crate with a mass of M = 62.5 kg is suspended by a rope from the endpoint of a uniform boom. The boom has a mass of m = 116 kg and a length of l = 7.65 m. The midpoint of the boom is supported by another rope which is horizontal and is attached to the wall as shown in the figure.
1. The boom makes an angle of θ = 57.7° with the vertical wall. Calculate the tension in the vertical rope.
2. What is the tension in the horizontal rope?
The boom makes an angle of θ = 60.2° with the vertical wall and the tension in the horizontal rope is mathematically given as
[tex]T_1=730.85 \mathrm{~N}[/tex]
[tex]T_1'=\frac{1980.51 \mathrm{~N}}{}[/tex]
What is the tension in the vertical rope.?Generally, the equation for is mathematically given as
1) Tension in vertical rope,
[tex]T_{1}=74.5 \times 9.81\\T_1=730.85 \mathrm{~N}[/tex]
2) Tension in horizontal rope,
[tex]\sum{Mg} =0\\Mg\frac{l}{2} \sin \theta+T_{1} \frac{l}{2} \sin \theta &=T_{2} l \cos \theta \\[/tex]
[tex]T_{2} &=\frac{M g(l / 2) \sin \theta+T_{1}(l / 2) \sin \theta}{l \cos \theta} \\\\&=\frac{M g \tan \theta}{2}+\frac{T_{1} \tan \theta}{2} \\\\T_{2} &=\frac{142 \times 9.81 \tan 61.8}{2}+\frac{730.85 \times \tan 61.8}{2} \\\\=& 1299+681.51[/tex]
[tex]T_1=\frac{1980.51 \mathrm{~N}}{}[/tex]
In conclusion, the tension in the horizontal rope is
[tex]T_1=\frac{1980.51 \mathrm{~N}}{}[/tex]
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You are raising up a big bucket of water from a 25.9 m deep well. The combined mass of the water and the bucket is 13.9 kg. The bucket is attached to a heavy duty steel chain. The mass of the chain is 19.3 kg.
1. How much work do you perform during the lifting process?
2. If it takes 1.75 minutes for you to raise the bucket of water out of the well, then what was your average power?
1. The amount of work done during the lifting process is 8426.824 J
2. The average power used in the process is 80.26 Watts
1. How to determine the workdone Combine mass (m) = 13.9 + 19.3 = 33. 2 KgAcceleration due to gravity (g) = 9.8 m/s²Height (h) = 25.9 mWork done (Wd) =?Wd = mgh
Wd = 33. 2 × 9.8 × 25.9
Wd = 8426.824 J
2. How to determine the powerWork done (Wd) = 8426.824 JTime (t) = 1.75 mins = 1.75 × 60 = 105 sPower (P) =?P = Wd / t
P = 8426.824 / 105
P = 80.26 Watts
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Three resistors with resistances of R1=12 ohms (Ω), R2=8 ohms, and R3=24 ohms are in a series circuit with a 12-volt battery. (A) What is the total resistance of the resistors? (B) How much current can move through the circuit? (C) What is the current through each resistor?
The total resistance of the resistors is R=44Ω. And the current will be I= 0.27 A.
What is the function of a resistor?Resistors are electronic components whose main function is to limit the flow of electrical charges by converting electrical energy into thermal energy.
A)The resistances connected in series in an arm of a circuit, total resistance of that arm of is given by algebric sum individual resistances.
R = R1 + R2 + R3 = 12 + 8 + 24 = 44Ω
B) Ohm's law gives that:
V = IR
Where,
Voltage applied to circuit (V)current flowing through the circuit (I) total resistance of the circuit (R)(I) = V/R = 12 / 44 = 3/11 = 0.27 A
C) In series combination, all the resistances are connected one after other in a linear fashion. So, current flowing through first resistor passes to second, and then third and so on. Hence, the current flowing through all the resistance in series combination is same as the current flowing through that arm of circuit.
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A Mercedes-Benz 300SL (m = 1700 kg) is parked on a road that rises 15 degrees above the horizontal. What are the magnitudes of (a) the normal force and (b) the static frictional force that the ground exerts on the tires?
Answer: See below
Explanation:
Given:
Mass of the Mercedes-Benz (m) = 1700 kg
Inclination of the road (θ) = 15.0
The free body diagram is shown in figure attached below
a) The normal force is equal to the cos component of the weight of the car.
[tex]\begin{aligned}&f=m g \cos \theta \\&f=1700 \times 9.81 \times \cos 15 \\&f=16108.74 \mathrm{~N}\end{aligned}[/tex]
b) The static force will be equal to the weight's sin component.
[tex]\begin{aligned}&f=m g \sin \theta \\&f=1700 \times 9.81 \times \sin 15 \\&f=4316.32 \mathrm{~N}\end{aligned}[/tex]
Calculate the focal length of a spherical mirror whose radius of curvature is 25 cm
Answer:
The focal length is R/2 = 25 cm / 2 = 12.5 cm
A ray from the center of curvature is focused back on itself (R cm)
As the angle of the ray is changed to being parallel to the axis the ray from the mirror will be brought closer to the mirror
f(parallel) < focus (back upon itself)
compare angles of incidence and reflection
Assume the pipe in the bathroom has a radius 34 cm and the pipe in the chamber has a radius of 45cm.
The Velocit,y Height and flow rate is is mathematically given as
v2= 1.92m/sh=2.06m F= 700kg/sWhat is the flow rate?Generally, the equation for the Continuity equation is mathematically given as
A1v1=A2v2
Therefore
[tex]v2=\frac{r1^2}{r2^2}v1[/tex]
v2= 1.92m/s
Generally, the equation for Pressure is mathematically given as
the difference is related by
[tex]P=\rho g h[/tex]
Therefore
[tex]h=P / \rho g[/tex]
(1000)(9.81)(h)=2*10100
h=2.06m
Generally, the equation for Flow rate is mathematically given as
[tex]F=\rho Av[/tex]
Therefore
[tex]F=(1000)\pi (0.45)^2 1.1[/tex]
F= 700kg/s
In conclusion, The resulting solutions are
v2= 1.92m/s
h=2.06m
F= 700kg/s
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After brushing, Fluffy's fur has a charge of +8.0 × 10-9 coulombs and her plastic brush has a charge of –1.4 × 10-8 coulombs. If the distance between the fur and brush is roughly 5.0 × 10-1 meters, what is the approximate magnitude of the force between them?
(k = 9.0 × 109 newton·meters2/coulomb2)
The approximate magnitude of the force between them is [tex]-4.032*10^-^6 N[/tex]
What is columbo's law?According to Coulomb, the electric force for charges at rest has the following properties:
Like charges repel each other; unlike charges attract.
Thus, two negative charges repel one another, while a positive charge attracts a negative charge.
The equation in Coulomb's law is :
[tex]F =\frac{{kq_1q_2}}{r^2}[/tex]
Where F is the force between charges, k is a constant, q₁ is the charge of the first particle, q₂ is the charge of the second particle and r is the distance between the two particle charges.
According to the question,
The given values are:-
q₁ = +8.0 × 10⁻⁹
q₂ = –1.4 × 10⁻⁸
Substituting to the equation:
[tex]F =\frac{{kq_1q_2}}{r^2}[/tex]
=[tex]\frac{ { 9*10^{9} * 8* 10^{-9} *-1.4*10^{-8} }}{(5x10^-1)^2}[/tex]
= -4.032 x 10⁻⁶ N
Therefore,
-4.032 x 10⁻⁶ N is the approximate magnitude of the force between them.
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A prism of angle 60° is of a material of refractive index √√2. Calculate angles of minimum deviation and maximum deviation.
Answer:
i don't know if this helps but The refractive index of the material of the prism of an angle 60 degree is 1.62 for sodium light. there you go hope it helps
Explanation:
(b)) Suggest a reason why pail manufacturers prefer the shape shown to other shapes. 30 cm .... ( b ) ) Suggest a reason why pail manufacturers prefer the shape shown to other shapes . 30 cm ....
Manufacturers of pails prefer a cone shape because it has a suitable base as well as more space for its contents.
What is the most common shape of pails?The most common shape of pails is the shape of the frustum of a cone.
Pails are useful to contain liquids as well as some grainy solids like sand.
Because of their unique shapes, pails are able to rest on their bases and also has enough space to contain enough liquid as their top part spreads outwards.
In conclusion, the choice of shape of pails is to ensure they rest on the base and also have enough space for their contents.
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Obtain the formula for the focal length of a lens in terms of object distance (u)
and magnification (m)
Answer:
m=image distance÷object distance
Which notation is commonly used on force diagrams to show forces acting on an object.
Answer: is F^D
The notation that is commonly used on force diagrams to show forces acting on an object is FD.
What is free body diagram ?A free body diagram is a diagram that contains all the forces acting on an object.
These forces acting on an object include the following :
Upward force (normal reaction due to weight of the object)Downward force (downward force due to weight of the object)Frictional force (force resisting the motion)Thus, the notation that is commonly used on force diagrams to show forces acting on an object is FD.
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Suppose the mass of a fully loaded module in which astronauts take off from the Moon is 10,600 kg. The thrust of its engines is 25,500 N. (Assume that the gravitational acceleration on the Moon is 1.67 m/s2.)
(a) Calculate its magnitude of acceleration in a vertical takeoff from the Moon.
m/s2
(b) Could it lift off from Earth? If not, why not?
Yes, the thrust of the module's engines is equal to its weight on Earth.
No, the thrust of the module's engines is equal to its weight on Earth.
No, the thrust of the module's engines is less than its weight on Earth.
Yes, the thrust of the module's engines is greater than its weight on Earth.
If it could, calculate the magnitude of its acceleration. (If not, enter NONE.)
m/s2
(a) The magnitude of acceleration in a vertical takeoff from the Moon will be 0.73 m/s².
(b)Option d is correct.
What is force?Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
Force is defined as the product of mass and acceleration. Its unit is Newton.
Given data;
Force, F =?
Mass of a fully loaded module,m = 10,600 kg
Acceleration due to gravity on moon,g = 1.67 m/s²
Thrust of its engines is,F= 25,500 N.
The net force is found as follows;
[tex]\rm F_{net} = F -W[/tex]
ma = F-W
(10,600) kg × a = 25,500 N - (10,600 kg )(1.67)
a = 0.73 m/s²
b)
Yes, it lifts off from Earth. Because the thrust of the module's engines is greater than its weight on Earth.
F>W
Hence option d is correct.
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Help!!! Asap!!!
The arrows in the diagram show the direction of the magnetic fields of the
atoms that make up an object. Which material could the diagram represent?
A. Paper
B Steel
C Nickel
D Iron
Answer:
Probs paper cuz the rest are metals
A fish rests on the bottom of the bucket of water while the bucket is being weighed on a scale. When the fish begins to swim around, does the scale reading changed? Explain.
When the fish begins to swim around, the reading of the scale won't change because mass of the fish and the bucket is constant.
Weight of the fish and bucket
The weight of the fish inside the bucket depends on the mass of the bucket and fish.
W = mg
where;
m is mass of the bucket and fishg is acceleration due to gravityThus, when the fish begins to swim around, the reading of the scale won't change because mass of the fish and the bucket is constant.
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