A projectile is launched horizontally at a speed of 40 meters per second from a platform located a vertical distance h above the ground. The projectile strikes the ground after time at horizontal distance from the base of the platform. [Neglect friction.]
Calculate the vertical distance, h, if the projectile's total time of flight is 4.5 seconds. You must show work to earn full credit with the minimum 3 steps:
1. Equation used
2. Substitution with correct units
3. Final answer with correct units
Answers
Answer:1
Explanation:t=rad2h/g
The launch of projectiles allows to find the height of the body launched horizontally is:
The height is 99.2 m
Projectile launching is an application of kinematics where there is no acceleration on the x-axis and the y-axis is the gravity acceleration.
In the attachment we see a diagram of the movement, as the body is thrown horizontally, its initial vertical speed is zero.
y = y₀ + [tex]v_o_y[/tex] t - ½ g t²
Where y, y₀i are the current and initial heights, respectively, [tex]v_{oy}[/tex] the vertical initial velocity, g the acceleration of gravity and t the time.
0 =y₀ + 0 - ½ g t²
y₀ = ½ g t²
let's calculate
y₀ = ½ 9.8 4.5²
y₀ = 99.2 m
y₀ = h = 99.2 m
This is the initial height of the object when it is thrown.
In conclusion using the projectile launch we can find the height of the horizontally launched body is:
The height is 99.2 m
Learn more here: brainly.com/question/10903823
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Answers
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Answers
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Answers
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