Answer:
3.87 s
Explanation:
When the y component = 0, the ball is at its apex and 1/2 of the way through its flight.
vy = 19 + at where a = - 9.81 m/s
0 = 19 - 9.81t shows the one-half-flight 't' = 1.94 s
double this result to get total 't' = 3.87 s
an object with a mass of 5kg is initially at rest on a frictionless horizontal surface. a horizontal force is applied to the objevt. the object changes its position as
The object changes its position as a result of the force applied to it. This change in position is known as acceleration.
What explanation is responsible for the acceleration?The magnitude of the acceleration of the object depends on the magnitude of the force applied and the mass of the object. Based on the Second Law of Motion, the acceleration of an object is directly proportional to the force applied and inversely proportional to the mass of the object. This relationship can be expressed mathematically as:
a = F/m
where a is the acceleration of the object, F is the force applied, and m is the mass of the object.
So in this case, if a force of F is applied to the 5kg object, it will experience an acceleration of a = F/5. For example, if a force of 10N is applied to the object, it will accelerate at a rate of 2 m/s^2 (a = 10N/5kg = 2 m/s^2).
Therefore, the correct answer is as given above
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If a piece of elastic wire 2 meters long and 3 centimeters in diameter increases its length by 2.5 cm when a force of 0.25 is applied to its area than Find the force applied on the string and the Young's scale of the string?
Answer:
The force applied on the string is 0.25 N and the Young's modulus of the string is 10 N/m
Explanation:
The force applied on the string can be calculated using the equation:
Force = (change in length * Young's modulus) / original length
The Young's modulus of the string can be calculated using the equation:
Young's modulus = (Force * original length) / change in length
Plugging in the given values:
Force = (2.5 cm * Young's modulus) / 2 m
= (0.025 m * Young's modulus) / 2 m
= 0.025 * Young's modulus
= 0.25 (given)
= 0.25 N
Young's modulus = (0.25 N * 2 m) / 0.025 m
= 10 N/m
A 9.0-kg box of oranges slides from rest down a frictionless incline from a height of 5.0 m. A constant frictional force, caused by friction with the surface from point A to point B, brings the block to rest at point B, 19 m from point A. What is the coefficient of kinetic friction between A and B?
The gravitational potential energy at the point the box begins must be equal to the kinetic energy at position A and this energy must have been "used up" by friction by the time the box gets to B. So letâs compare the energy at the starting position to that at B (which is zero). There is no reason to include point A.
When a 9.0-kg box of oranges slides from rest down a frictionless incline from a height of 5.0 m with a frictional force then the coefficient of kinetic friction between A and B is 9.9m/s.
What is kinetic friction?The frictional force acting between two moving objects is termed as Kinetic friction.
Solution:
Given:
Let v represent the speed of the box at point A, x represent the distance the box slides down the slope (without friction), and represent the angle of the incline.
Remember that v = ultimate speed, therefore v 2 - v02 = 2 an x
beginning speed being
A=acceleration and X=displacement
While moving up the slope, the box begins at rest (v0 = 0) and moves a distance x with an acceleration of a to reach a speed v.
F = m g sin() = m a, where m = 9.0 kg and g = 9.8 m/s2, and a = g sin().
Using a little trigonometry, write the distance x in terms of :
x = (5.0 m) / sin(x), where sin(x) = (5.0 m)
To find:v, enter the following into the formula above:
= 2 g sin(5.0 m) / sin(5.0 m)
10.0 m) g v
= 9.9 m/s
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BRAINLIEST -- 11 pts
A 2,713 kg van runs into the back of a 843 kg compact car at rest. They move off together at 6.9 m/s. Assuming the friction with the road is negligible, calculate the initial speed of the van.
WILL GIVE BRAINLIEST!!!!
explanation is preferred so i can learn but not necessary
Answer: approximately 9.02 m/s.
Explanation: In this scenario, we can use the conservation of momentum to determine the initial speed of the van. Momentum is defined as the product of an object's mass and velocity, and it is conserved in collisions where there is no net external force. This means that the total momentum of the van and car before the collision must be equal to the total momentum of the van and car after the collision.
We can write this as an equation:
2,713 kg * v1 + 0 kg * 0 m/s = 2,713 kg * 6.9 m/s + 843 kg * 6.9 m/s
where v1 is the initial speed of the van. Solving for v1, we get:
v1 = (2,713 kg * 6.9 m/s + 843 kg * 6.9 m/s) / 2,713 kg
= 6.9 m/s + (843 kg * 6.9 m/s) / 2,713 kg
= 6.9 m/s + 3.12 m/s
Therefore, the initial speed of the van was approximately 9.02 m/s.
Q)What is the force between two small charged spheres having charges of 2 × 10^–7C and 3 × 10^–7 C placed 30 cm apart in.
The force that is acting on the spheres is obtained as 0.006 N from the calculation that is done here.
What is the force between the charges?We know that the force can be obtained by the use of the Coulomb's law. From the Coulomb's law, we know that the force that acts for the charges on the charges must be an attractive force as we can see and then we can be able able to use the formula;
F = K[tex]q_{1}[/tex][tex]q_{2}[/tex]/r^2
F = force on the object
K = electric constant
[tex]q_{1}[/tex] and [tex]q_{2}[/tex] = magnitude of the charges on the object.
Then we have;
F = 9 * 10^9 * 2 × 10^–7 * 3 × 10^–7 /(30 * 10^-2)^2
F = 54 * 10^ -5/0.09
F = 0.006 N
Thus, it is clear that we have an attractive force that would act on the species and the magnitude of the charged spheres 0.006 N as we can see from the calculation here.
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A beam of electrons moves at velocity 4.6 ⋅105
m/s in the positive x direction through a uniform 2.8 T magnetic field pointing in the positive y direction.
What direction does the magnetic force point?
+x
-x
+y
-y
+z
-z
What is the magnitude of the force?
F
(a) The direction of the magnetic field is positive z direction.
(b) The magnitude of the magnetic force is 2.063 x 10⁻¹³ N.
What is the direction of the magnetic field?The direction of the magnetic field is determined by applying Fleming's right hand rule.
The right hand rule states that if you point your right thumb in the direction of the velocity, your index finger in the direction of the magnetic field and then your middle finger will point in the direction of the the resulting magnetic force.
The magnitude of the magnetic force is calculated as follows;
F = qvB
where;
q is the charge of the electronv is the velocity of the electronB is the direction of magnetic fieldF = ( 1.602 x 10⁻¹⁹ x 4.6 x 10⁵ x 2.8 )
F = 2.063 x 10⁻¹³ N
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Suppose that you would like to study star A all year round. Its declination is 25 degrees above the celestial equator. At which of the following locations on Earth could you be to observe this star all year round?
(a) at a latitude of 67 degrees N
(b) only at the South Pole
(c) at a latitude of 63 degrees N
(d) at a latitude of 25 degrees N
The declination is also known as latitude hence, star A is at a latitude of 25 degrees N from the earth so, option D is correct.
What is the equator?A hypothetical line that would make a large circle around the Earth's surface, equidistant from the poles and on a plane perpendicular to the axis of rotation of the planet, is known as an equator. It establishes the boundary between the Northern and Southern hemispheres of the Earth and serves as the standard for measuring latitude.
Considering that, star A's declination is 25 degrees above the celestial equator. The star is located at a latitude of 25 degrees to the North because the declination is also known as the latitude. Therefore, the observer must be (d) located at a latitude of 25 degrees N in order to examine the star all year long.
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PLEASE HELP ME ANSWER THE PHYSICS QUESTIONS ON MY PROFILE!!! i will give brainliest to the first to answer!!! this one and the other ones
this is the easiest one
Find the uniform acceleration that causes a car's velocity to change from 23.6 m/s to 85.9 m/s in 7.6 seconds.
The work done in pushing a 40 kg chair from the kitchen table to 10 meters down the
hall would be about “blank”
neglecting friction.
The work done in pushing a 40 kg chair from the kitchen table to 10 meters down the hall would be 3920 Nm.
What is gravitational force?Gravity, also called gravitational force in mechanics, is the universal force of attraction that acts between all matter. It is the weakest of the known forces in nature, and therefore plays no role in determining the internal properties of everyday matter. It controls the orbits of objects, stars, galaxies, and the universe as a whole, as well as the structure and evolution of objects elsewhere in the universe.
On Earth, every object has a weight, or downward gravitational force, proportional to its mass. , the mass of the Earth acts on them. Gravity is measured by the acceleration it imparts to a free-falling object. At the Earth's surface, the acceleration of gravity is approximately 9.8 meters (32 feet) per second. For each second her body is in free fall, its velocity increases by about 9.8 meters per second. On the moon, the acceleration of a free-falling object is approximately 1.6 meters per second.
Gravitational force on chair:
F = mg
When, F = force
m = mass of chair (40 kg)
g = gravitational acceleration (9.8 m/s²)
F = 40 × 9.8
F = 392 N
For work done:
W = F × s
Where, w = work done
F = force (392 N)
s = distance (10 m)
W = 392 × 10
W = 3920 Nm
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the emf induced in a loop rotating in a uniform magnetic field is largest when the normal to the plane of the loop makes an angle of with the field.
The emf induced in a rotating loop in the greatest uniform magnetic field when the normal to the plane of the loop makes an angle with the field of 0 (zero).
Induction electromotive force (abbreviated as induction emf) is an electromotive force that arises in the coil caused by a changing magnetic field with a fast tempo. This force includes a certain amount of magnetic flux.
Factors that affect the magnitude of the induced emf are:
The speed of changing the magnetic field. The faster the magnetic field changes, the greater the induction emf that arises.The number of turns. The more turns, the greater the induced emf that arises.The figure shows that the angle of rotation in the normal plane is 0 degrees. The induced emf strength is maximum only when the plane normal to the coil makes 90 or 270 degrees with the magnetic field as shown in the figure below.
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The amount of work done on an object is the force applied to the object times the distance the object is moved while the force is applied or, more succinctly, work = (force)(distance). We will use the International System of Units: Force is measured in Newtons, N, and distance is measured in meters, m. Weight is the gravitational force applied to the object and cable, therefore, weight = force. Cable (3 N per m) 40 - X Object (1500 N) Ax How much work is done lifting a 1500 N object from the ground to the top of a 40 m building if the cable weighs 3 N per m? Here the 1500 N object is constant, but as you retract the cable, the overall weight (force) decreases. The diagram to the right can help you derive the integral to calculate the work done from the ground to the top of the buildingX1=40X2=0
The Total work done = work done on the object + work done on the cable
From the given information,
weight of the object is = 1500 N
weight of rope is = 3N per m
height interval is = 0 to 40 m
Work = force x distance
If distance = x, then, we have the integral below as shown in the image:
By substituting x = 40 and x = 0, it becomes
1620(40) - 3/2 * (40)^2 - 1620(0) - 3/2 * (0)^2
= 64800 - 2400
= 62400 Nm
the work done from the ground to the top of the building is 62400 Nm
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A baseball player uses a pitching machine to help him improve his batting average. He places the 73.9 kg machine on a frozen pond. The machine fires a 0.118 kg baseball horizon-
tally at a speed of 40.8 m/s. What is the magnitude of the recoil velocity
of the machine?
Answer in units of m/s.
According to the law of conservation of momentum, the magnitude of the recoil velocity of the machine is equal to the magnitude of the initial velocity of the baseball, since the total momentum of the system (the machine and the baseball) remains constant. In this case, the magnitude of the initial velocity of the baseball is 40.8 m/s, so the magnitude of the recoil velocity of the machine is also 40.8 m/s. Answer: \boxed{40.8}.
The mass of earth is 5.97 x 10²⁴kg, the mass of the moon is 7.35 x 10²² kg and the mean distance of the moon from the center of Earth is 3.84 X 10⁵ km. Calculate the magnitude of the gravitational force exerted by earth on the Moon
The magnitude of the gravitational force exerted by earth on the moon will be equal to 1.85 × 10⁵ N.
What is gravity?The fundamental force of attraction operating on all matter is recognized as gravity, also spelled gravity, in mechanics. It has no impact on identifying the interior properties of common matter because it is the weakest force known to exist in nature.
The formation and growth of planets, galaxies, and the universe are all under the influence of this long-range, cosmic force, which further determines the trajectories of objects throughout the universe and the entire universe.
As per the given information in the question,
Mass of earth, M₁ = 5.97 × 10²⁴ kg
Mass of moon, M₂ = 7.35 x 10²² kg
Distance between moon from center of earth, r = 3.84 X 10⁵ km
G = 6.67×10¹¹ Nm² / kg²
Use the formula of force,
F = GM1M2 / r²
F = [(6.67×10¹¹) (5.97 × 10²⁴)(7.35 x 10²²)]/( 3.84 X 10⁵)²
F = 1.85 × 10⁵ N
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5. Which of the following is true about the Wechsler tests?
O
The Wechsler tests use a number of subtests to measure both verbal and nonverbal intelligence.
The Wechsler tests use a number of subtests to measure emotional intelligence.
The Wechsler tests use a number of subtests to measure eight different types of intelligence.
The Weschler tests can prove a test taker is a savant.
Answer:
One true statement about the Wechsler tests is that they use a number of subtests to measure both verbal and nonverbal intelligence. The Wechsler Adult Intelligence Scale (WAIS) and the Wechsler Intelligence Scale for Children (WISC) are among the most commonly used intelligence tests in the world. These tests are designed to assess an individual's cognitive abilities, including their ability to think abstractly, solve problems, and understand and use language. The tests use a variety of subtests to measure different aspects of intelligence, including verbal comprehension, perceptual reasoning, working memory, and processing speed. These subtests are combined to produce a full-scale IQ score, which provides an overall measure of an individual's cognitive ability.
A 10 kg rock falls from a height of 18 m and
lands on a guy about 3 s later. How much power
did it hit him with?
It struck him with 60 W of power. when a 10 kg rock hits a guy after falling from a height of 18 m and landing on him after around 3 s.
What does the word "power" mean?Power is the rate of production of work. P=Wt. The watt (W), which is equal to 1 joule per second (1J/s), is the SI unit for power. Power is a measure of how quickly energy is used up since power is the transfer of energy. An example would be a 60-W light bulb, which uses 60 J of energy every second.
Power= mass. velocity + power=10*18/3*10 = 60 W,
resulting in the power of a falling rock being 60W.
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A ball having a mass of 350 g is thrown against the wall at a rate of 2 m/s. The ball then bounces at the same rate in the exact opposite direction of the direction of coming. Suppose a process Bounce lasts for 0.01 seconds. Calculate the force Done wall to reverse the direction of the ball.
The force on the wall by a ball having a mass of 350 g is 140N.
What is force?Force is the product of mass and acceleration.
To calculate the force on the wall, we use the formula below.
Formula:
F = m(v-u)/t.................. Equation 1Where:
F = Forcem = Massv = Final velocityu = Initial velocityt = TimeFrom the question,
Given:
m = 350 g = 0.35 kgu = -2 m/s v = 2 m/st = 0.01 sSubstitute these values into equation 1
F = 0.35(2-[-2])/0.01F = 0.35×4/0.01F = 140 NHence, the force on the wall is 140N.
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two boxes of masses m and 2m are in contact with each other on a frictionless surface. (see fig. 4-3.) what is the acceleration of the more massive box?
the acceleration of the more massive box is = F/3M.
What is the formula for acceleration?This equation a = v/t denotes acceleration (a), which is the velocity that changes (v) over the time period (t).
What three forms of acceleration are there?The three main types of accelerated motions are uniform acceleration, quasi acceleration, and average acceleration.The motion in which an item moves inside a straight line while increasing in velocity at regular intervals is referred to as uniform acceleration.
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A bare helium nucleus has two positive charges and a mass of 6.64 ✕ 10−27 kg.
Answer:
The answer is the question 6.64*10-24=39.4
A coffee mug is _____ while a wine glass is _____. Question 6 options: transparent; opaque opaque; transparent translucent; opaque translucent; transparent
Answer:
A coffee mug is opaque while a wine glass is transparent.
PLEASE HELP ME ANSWER THE PHYSICS QUESTIONS ON MY PROFILE!!! i will give brainliest to the first to answer!!! this one and the other ones
A 2,713 kg van runs into the back of a 843 kg compact car at rest. They move off together at 6.9 m/s. Assuming the friction with the road is negligible, calculate the initial speed of the van.
Answer:
The initial speed of the van is 9.044 m/s
Explanation:
After an inelastic collision, bodies stick together and move at a common speed. Momentum is conserved, but some kinetic energy is lost.
Here is the formula for an inelastic collision:
[tex]m_1*v_{1i} +m_2*v_{2i}=v_f(m_1+m_2)[/tex]
Let the van be object 1; let the compact car be object 2.
Lets solve for [tex]v_{1i}[/tex]
Isolate terms with [tex]v_{1i}[/tex] to the left hand side.
Subtract [tex]m_2*v_{2i}[/tex] from both sides:
[tex]m_1*v_{1i}=v_f(m_1+m_2)-m_2*v_{2i}[/tex]
Divide both sides by [tex]m_1[/tex].
[tex]v_{1i}=\frac{v_f(m_1+m_2)-m_2*v_{2i}}{m_1}[/tex]
Simplify
[tex]v_{1i}=\frac{m_2(v_f-v_{2i})}{m_1}+v_f[/tex]
Enter our numbers into the equation.
[tex]m_1=2713[/tex]
[tex]m_2=843[/tex]
[tex]v_{2i} =0[/tex]
[tex]v_f=6.9[/tex]
[tex]v_{1i} =\frac{843(6.9-0)}{2713} +6.9[/tex]
[tex]v_{1i} =\frac{843(6.9)}{2713} +6.9[/tex]
[tex]v_{1i} =\frac{5816.7}{2713} +6.9[/tex]
[tex]v_{1i} =2.144 +6.9[/tex]
[tex]v_{1i} =9.044[/tex]
A ball is attached to one end of a wire, the other end being fastened to the ceiling. The wire is held horizontal, and the ball is released from rest (see the drawing). It swings downward and strikes a block initially at rest on a horizontal frictionless surface. Air resistance is negligible, and the collision is elastic. The masses of the ball and block are, respectively, 1.70 kg and 2.50 kg, and the length of the wire is 1.21 m. Find the velocity (magnitude and direction) of the ball (a) just before the collision, and (b) just after the collision.
Just before the collision, the ball has a velocity of 9.3 m/s, downward. After the collision, the ball has a velocity of 6.2 m/s, upward.
To solve this problem, we can analyze the motion of the ball and block before and after the collision using the principles of conservation of energy and momentum. Since the collision is elastic, the total kinetic energy of the system is conserved. The ball has gravitational potential energy before the collision, which is converted to kinetic energy as it falls.
The block has no kinetic energy before the collision, but gains some after the collision due to the transfer of momentum from the ball. By equating the total kinetic energy before and after the collision and using the principle of conservation of momentum, we can solve for the velocities of the ball and block.
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for d, you will want to mention a specific term/concept that you're describing for why mrp is downward sloping.
Inside this services and products (G&S) financial instrument, the DD curve depicts the link between variations through one exogenous construct and one regressor.
What is a MRP?The marginal revenue generated by using one more unit of a product is known as the marginal product of labor (MRP). MRP is used to calculate the ideal resource level while also making crucial decisions about the company's output. The MRP makes the assumption that expenses for other components won't change.
With increased production, a commodity's marginal usefulness decreases. As a result, when there is a greater supply, prices would decrease and demand will rise. Therefore, when the price is lower, consumers would desire fewer things. The aggregate supply slopes downward for this reason.
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Two protons (charge q
= 1.602·10-19 C) move at the same speed v=
1.6 ·105 m/s in opposite directions parallel to the x-axis. At the instant when they are at the same x-position, the proton moving in the negative direction is at distance r=
0.7 m in the positive y-direction with respect to the one moving in the positive direction.
What is the magnetic field direction at the point of the proton moving in the negative direction?
+x
-x
+y
-y
+z
-z
What is the magnetic force direction experienced by the proton moving in the negative direction?
+x
-x
+y
-y
+z
-z
The magnetic field at the point of the proton moving in the negative direction is equal to 1.84 ×10⁻¹⁴ T.
The magnetic force experienced by the proton moving in the negative direction is equal to 4.71 x 10⁻²⁸ N.
What is the magnetic field due to proton?The magnitude of the magnetic field due to the proton at distance 'r' moving in the negative direction is determined as follows;
F = q.v.B = (kq²)/r²
q.v.B = kq²/r²
B = kq/vr²
Where, k is the coulomb's constant, r is the distance between two protons, q is the charge of the protons, and v is the proton's speed.
Given the charge on the proton, q = 1.602 × 10⁻¹⁹C
The speed of the proton, v = 1.6 × 10⁵ m/s
B = (9 × 10⁹ × 1.602 × 10⁻¹⁹) / (1.6 x 10⁵ m/s × 0.7 × 0.7)
B = 18.39 × 10⁻¹⁵ T
B = 1.84 ×10⁻¹⁴ T
The magnetic force in the negative direction experienced by the proton is calculated as follows;
F = qvB
F = 1.602 × 10⁻¹⁹× 1.6 x 10⁵ × 18.39 × 10⁻¹⁵ T
F = 47.1 × 10⁻²⁹ N
F = 4.71 × 10⁻²⁸ N
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What is the displacement illustrated?
What is the distance illustrated?
start/finish
2m
4m
4m
2m
(a) The displacement of the person as illustrated is 0 m.
(b) The distance travelled by the person is determined as 12 m.
What is the displacement of the person?
The displacement of the person as illustrated is the change in the position of the person.
Mathematically, the formula for displacement of an person is given as;
Δx = xf - xi
where;
xf is the final position of the personxi is the initial position of the personΔx = (2 m + 4m ) - ( 4m + 2m ) = 0
The total distance travelled by the person is calculated as;
d = 2 m + 4 m + 4 m + 2 m
d = 12 m
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if beam (1) is the incoming beam in the figure, which of the other four red lines are reflected beams and which are refracted beams? (select all that apply.) reflected beams 2 3 4 5 refracted beams 2 3 4 5
Beams that bounce off a surface and continue to travel through that same medium are said to be reflected. However, because of this The refracted beams are 3, 5, and the reflected beams are 2, 4, and 2.
What other term do you use to describe reflecting?Cogitate, deliberate, reason, conjecture, and think are some typical synonyms of reflect. While each of these phrases means "to utilize one's skills of imagination, judgment, or inference," "reflect" denotes thoughtful deliberation about a memory.
Use reflect in what ways?To contemplate something thoroughly and deeply I must think for a while before making a choice. Think about or consider something She was given some alone time to consider the effects of her choice. show that... The interview had gone well, he thought as he was driving home.
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Three electromagnetic waves travel through a certain point P along an x axis. They are polarized parallel to a y axis, with the following variations in their amplitudes. Find their resultant at P
E1 =(10.0μV/m)sin[(2.0×10^14rad/s)t]
E2 =(5.00μV/m)sin[(2.0×10^14rad/s)t+45.0∘]
E3 =(5.00μV/m)sin[(2.0×10^14rad/s)t−45.0∘]
Their resultant at point P is 17.07μV/m.
What is electromagnetic waves?Electromagnetic waves are a type of energy wave that has both electric and magnetic field components. They are created by the movement of electrically charged particles and travel through space at the speed of light. Electromagnetic waves can be used for communication, radiation, and other purposes. They are also responsible for the electromagnetic spectrum, which ranges from high-energy gamma rays to low-energy radio waves. Electromagnetic waves are used in a variety of applications, such as radio and television broadcasts, cellular phone communications, and radar. They can also be used to diagnose medical conditions and to detect objects in space. Electromagnetic waves are used in scientific research and are important in the understanding of the universe.
The amplitude of first wave,a1 = 10.0μV/m
The amplitude of second wave, a2 = 5.00μV/m
The amplitude of third wave, a3 = 5.00μV/m
Phase angle of first wave, θ1 = 0°
Phase angle of second wave, θ2 = 45°
Phase angle of third wave , θ3 = -45°
Their resultant at point P is given by ,
R = a1 Cosθ1 + a2 Cos θ2 + a3 Cosθ3
= 10 * Cos0 + 5 * Cos(45) + 5 * Cos(-45)
=17.07μV/m
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For total internal reflection to occur, all of the following must happen but __________. Question 4 options: light must travel slower in the first medium light must refract light must strike the boundary at an angle greater than the critical angle the boundary must be reflective
For total internal reflection to occur, all of the following must happen but light must travel slower in the first medium.
What is the total internal reflection?Total internal reflection, can be described as the complete reflection of a ray of light within a medium however this medium could be water or glass from the surrounding surfaces back into the medium.
It should be noted that the total internal reflection will not take place unless the incident light is traveling within the more optically dense medium , hence phenomenon occurs if the angle of incidence is greater compare to certain limiting angle.
Therefore, option A is correct.
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Consider the AC circuit in the figure. The frequency of the AC source is adjusted while its voltage amplitude is held constant. The lightbulb will glow the brightest at which of the following?
A.high frequencies
B.the brightness will be the same at all frequencies
C.low frequencies
When the leg it is in has the least resistance, the lightbulb may glow brightest. Because inductive capacitance is inversely proportional to angular frequency, this occurs at low frequencies.
What generates opposition?Electrons moving through a conductors, for example a metal wire, create an electric current. The ions inside the metal may be struck by the speeding electrons. Resistance results this from, making it harder for the current to flow.
A resistance example is what?To better understand resistance, imagine how difficult it would be for a person to move from one shop to the next in a crowded market. This circumstance is undoubtedly comparable to an atom trying to get through a wire.
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_NO+_O2 > _NO2 balance this
Answer:
4NO+2O2------>4NO2
that's the answer
A neutron in a reactor makes an elastic head-on collision with the nucleus of an atom initially at rest.
Assume: The mass of the atomic nucleus is
about 12.4 the mass of the neutron.
What fraction of the neutron’s kinetic energy is transferred to the atomic nucleus?
If the initial kinetic energy of the neutron is
5.53 × 10−13 J, find its final kinetic energy.
Answer in units of J.
(a) The fraction of neutron's kinetic energy transferred to the atomic nucleus is 0.08.
(b) The final kinetic energy of the neutron is 5.08 x 10⁻¹³ J.
What is the final velocity of the atom?The final velocity of the atom is calculated by applying the principle of conservation of linear momentum as follows;
initial momentum of the neutron = final momentum of the atomic nucleus
m₁u₁ = m₂u₂
where;
m₁ is the mass of the neutronu₁ is the initial velocity of the neutronm₂ is the mass of the atomic nucleus u₂ is the final velocity of the atomic nucleusThe mass of the atomic nucleus = 12.4 m₁
u₂ = m₁u₁ / m₂
u₂ = m₁u₁ / (12.4 m₁)
u₂ = 0.08u₁
The initial kinetic energy of the neutron is calculated as;
K.Ei = ¹/₂m₁u₁²
The final kinetic energy of the atomic nucleus is calculated as;
K.Ef = ¹/₂m₂u₂²
K.Ef = ¹/₂(12.4 m₁)(0.08u₁)²
K.Ef = 0.08 (¹/₂m₁u₁²)
K.Ef = 0.08 (K.Ei)
The fraction of neutron's kinetic energy transferred to the atomic nucleus is calculated as;
= 0.08 (K.Ei) / K.Ei
= 0.08
= 8 %
The final kinetic energy of the neutron is calculated as follows;
K.E.f (neutron) = (1 - 0.08) x (5.53 x 10⁻¹³ J)
K.E.f (neutron) = 5.08 x 10⁻¹³ J
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