Option D is correct : This positive charge will veer east
It is given that the particle has a positive charge.
So, the direction of the force on the positive charge (and also the acceleration) is in the same direction as the electric field.
Now the electric field is uniform and points in east, the force on it [tex]F=qE[/tex]will also be pointed towards the east.
The positive charge was initially moving north, which means that the velocity vector was in the direction of north and when a positive charge first reaches an area with an electric field and force pointing east, its velocity vector will change to be along the electric field, or east.
That’s why a positive charge traveling north enters a region where the electric field is uniform and points east will veer east.
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What happens when the gravity of a massive star's collapsing core is able to overcome neutron degeneracy pressure
when the gravity of a massive star's collapsing core is able to overcome neutron degeneracy pressure, then The core contracts and becomes black hole.
What is degeneracy pressure:
The degeneracy pressure found in the interior of a white dwarf or neutron star. The degeneracy pressure is greatly needed in the interior of these stars to counteract the pressure due to gravity.Some neutron stars may have a surface layer of highly degenerate matter that is compressed to great density, but still has some protons
Unlike the main body of the neutron star which is Neutronium, matter compressed until it is all neutrons, packed together. Essentially a huge atomic nucleus.
The star cools and all remaining matter is bound by gravitation into a neutron star.
This object is composed primarily of degenerate neutron matter, this star will collapse into a black hole because gravity will overcome the neutron degeneracy pressure.
hence, when the gravity of a massive star's collapsing core is able to overcome neutron degeneracy pressure, The core contracts and becomes a black hole.
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A current of 0.050 amps flows in a circuit element with a resistance of 25 ohms what is the voltage drop across the circuit element. (use ohms law V=IR)
The voltage drop across the circuit, given that 0.05 A flows in the circuit is 1.25 V
Ohm's lawThis law states as follows:
V = IR
Where
V is the potential differenceI is the currentR is the resistorHow to determine the voltageFrom the question given above, the following data were obtained:
Current (I) = 0.05 AResistance (R) =25 ohmsVoltage (V) =?V = IR
V = 0.05 × 25
V = 1.25 V
Therefore, the voltage drop across the circuit is 1.25 V
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A 5.0-kg object is moving with speed 2.0 m/s. A 1.25-kg object is moving with speed 4.0 m/s Both objects encounter the same constant braking force, and are brought to rest. Which object travels the greater distance before stopping
Acceleration is constant, so we can use the following kinematic equation and Newton's second law.
[tex]{v_f}^2 - {v_i}^2 = 2a\Delta x \implies -{v_i}^2 = -2\dfrac{F}{m}\Delta x \implies {v_i}^2 = 2\dfrac{F}{m} \Delta x[/tex]
where [tex]v_i[/tex] and [tex]v_f[/tex] are initial/final velocities, [tex]a[/tex] is acceleration, [tex]\Delta x[/tex] is displacment, [tex]F[/tex] is force, and [tex]m[/tex] is mass. Since the objects are coming to rest, the acceleration opposes the direction of motion and is negative.
Solve for [tex]\Delta x[/tex].
[tex]\Delta x = -\dfrac{m {v_i}^2}{2F}[/tex]
Compute the displacements of both objects.
[tex]\Delta x_{5.0\text{-kg}} = -\dfrac{(5.0\,\mathrm{kg}) \left(2.0\frac{\rm m}{\rm s}\right)^2}{2F} = -\dfrac{10}F \dfrac{\rm m}{\rm N}[/tex]
[tex]\Delta x_{1.25\text{-kg}} = -\dfrac{(1.25\,\mathrm{kg}) \left(4.0\frac{\rm m}{\rm s}\right)^2}{2F} = -\dfrac{10}F \dfrac{\rm m}{\rm N}[/tex]
Then both objects are displaced by the same amount.
Answer:
They stop in the same distance
Explanation:
f friction is the same for both and must overcome the KE of each object to bring each to rest.
f friction * d = 1/2 mv^2 for each object :
f * d1 = 1/2 m1 v1^2 f * d2 = 1/2 m2 v2^2
= 1/2 5 (2 )^2 = 1/2 1.25 (4)^2
Object 1 KE = 10 j Object 2 KE = 10 j
f d1 / f d2 = 10 / 10 ( f is the same for both)
d1 / d2 = 1 so d1 = d2 they stop in the same distance !
A spring whose spring constant is 260 lbf/in has an initial force of 100 lbf acting on it. Determine the work, in Btu, required to compress it another 1 in. The work required to compress it another 1 in is Btu.
The work required to compress it another 1 in Btu is 0.02463 Btu.
Work finished is elaborated in the sort of way that it consists of both forces exerted at the frame and the full displacement of the body. This block is preceded by a steady force F. The reason for this pressure is to transport the frame a sure distance d in an instant course in the direction of the force.
To explicit this idea mathematically, the work W is the same as the pressure f instances the distance d, or W = FD. If the pressure is being exerted at a perspective θ to the displacement, the work finished is W = FD cos θ.
The work is executed whenever a force actions something over a distance. you can calculate the electricity transferred, or work completed, by multiplying the force by way of the space moved inside the course of the force.
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For a simple compressible system, the change in the total energy of a system during a process is affected by ______. Multiple choice question. changes in potential and kinetic energies only change in potential energy only change in kinetic energy only changes in potential, kinetic, and internal energies change in internal energy only
For a simple compressible system, the change in the total energy of a system during a process is affected by changes in potential, kinetic, and internal energies.
First law of thermodynamics:The conservation of energy principle sometimes referred to as the first law of thermodynamics, offers a reliable framework for researching the connections between the many types of energy and their interactions. The first law of thermodynamics asserts that energy can only change forms during a process; it cannot be created or destroyed, according to experimental data. As a result, during a procedure, every piece of energy should be taken into account.
The evaluation of the system's energy at the start and end of the process, as well as the difference between them, is necessary to calculate the energy change of a system during a process. That is,
Energy change = Energy at final state - Energy at the initial state
Δ[tex]E_{system}[/tex] = [tex]E_{2} - E_{1}[/tex]
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You have just checked out a Lime bicycle, only to find that one of its tires is flat. Luckily, you have a bicycle pump with you. As you refill the flat tire, you find that it takes a considerable amount of effort to do it. Why
It will take a considerable amount of effort to pump the flat tire because of the bicycle pump has smaller area and it will require more force to push air into the flat tire.
Difference in air pressurePressure is defined as force applied per unit area of the given surface.
Pressure = Force/Area
The pressure of air inside the bicycle pump is smaller compared to the air pressure inside the tire.
Thus, it will take a considerable amount of effort to pump the flat tire because of the bicycle pump has smaller area and it will require more force to push air into the flat tire.
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A 1000-kg sports car of mass accelerates from rest to 20 m/s in 6.6 s. What is the frictional force exerted by the road on the car? Group of answer choices 1500 N 1750 N 2750 N 3000 N
The frictional force exerted by the road on the car is 3000N
Given the mass of the car is 1000 kg , the velocity of the car is 20m/s
and the time is 6.6s
We need to find the frictional force exerted by the road on the car
We know that Force = mass * acceleration
Now here Mass is given but acceleration is not given
So, we will find acceleration by using the formula v = u+at
Where u = 0
v = 20m/s
a = ?
t = 6.6
Substitute the values in the formula We get
v = u+at
20 = 0+(a)(6.6)
20/6.6 = a
∴ a = 3.03 m/s^2
Rounding to nearest tenth is 3m/s^2
Hence the acceleration is 3m/s^2
Now substituting the value of acceleration in F = ma
Where m = mass
a = acceleration
F = 1000*3
∴ F = 3000N
Hence the frictional force exerted by the road on the car is 3000 N
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A boy wants to throw a can straight up and then hit it with a second can. He wants the collision to occur 4.0 meters above the throwing point. In addition, he knows that the time he needs between throws is 3.0 seconds. Assuming he throws both cans with the same speed, what must the initial speed be
16.03 m/s is the initial speed of the cans.
Newton’s equations of motion has to be used to solve it;
He wants collision at height (h) = 4.0 m
The acceleration due to gravity as,
g =9.8ms−²
The initial speed of the thrown can is calculated by:
h = vt - ¹/₂gt²
4 = 3t - (0.5)(9.8)(3)²
4 = 3t - 44.1
3t = 48.1
t = 48.1/3
t = 16.03 m/s
Thus, the initial speed of the boy's thrown can is 16.03 m/s.
By measuring the rate at which the velocity varies with regard to the passage of time, one can calculate the acceleration of a body. By calculating the rate at which the displacement varies with regard to the passage of time, the velocity may be calculated. The perpendicular distance between the body's initial and final locations is its displacement. These are all vector quantities, meaning they all have both magnitude and direction.
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The pilot of the fighter jet turns by banking the wings such that the lift of the wings has a component in
the direction of the centre of the turn. The pilot wishes to turn the jet in a tight radius of 960.0 m while
maintaining a constant circular speed of 1440 km/h. Determine the angle of bank needed, measured from
the vertical.
The angle of bank needed, measured from the vertical is 86.6⁰.
Banking angle of the circular path
The angle of bank needed, measured from the vertical is calculated as follows;
v = √(rg tanθ)
where;
v is the speed = 1440 km/h = 400 m/sr is radius of the curve = 960 mg is acceleration due to gravityθ is the banking angle400² = (960 x 9.8 x tanθ)
tanθ = 400²(960 x 9.8)
tanθ = 17
θ = arc tan(17)
θ = 86.6⁰
Thus, the angle of bank needed, measured from the vertical is 86.6⁰.
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hello friends,i need ur help on this,topic of Motion in straight line.
hurryy up please.
and keep answering correctly.
Answer:
V = a * t for uniformly accelerated motion starting at zero speed
V = 4 s * 9.8 m/s^2 = 39.2 m/s
S = V0 t + 1/2 a t^2 = 1/2 a t^2
S = 1/2 * 9.8 m/s^2 * 16 s^2 = 78.4 m
Check:
Average speed = 39.2 / 2 = 19.6 m/s
S = 4 * 19.6 = 78.4 m
An object has a mass of 20.41 kg and an acceleration of 8.22 m/s2. What is the force acting on the object?
Answer: 167.7702 N (Newtons)
Explanation: I had this type of work, so I hope I am correct.
Answer:
~ 168 N
Explanation:
F = m a
= 20.41 * 8.22 = 167.7702 N
Which mechanical component is required in every gas-engine vehicle, but often not needed in an electric vehicle?.
a gearbox bru.
Binding of a signaling molecule to which type of receptor leads directly to a change in the distribution of substances on opposite sides of the membrane?.
When two sides of a membrane are in contact with each other, the distribution of ions will alter as a result of the binding of a signal molecule to a ligand-gated ion channel.
What is a ligand-gated ion channel?
Ligand-gated ion channels (LGICs) are membrane proteins that are structurally integral and feature a pore that permits the controlled passage of particular ions across the plasma membrane. The electrochemical gradient for the permeant ions drives the passive ion flux.
When a chemical ligand, such as a neurotransmitter, attaches to the protein, ligand-gated ion channels open. Changes in membrane potential cause voltage channels to open and close. When a receptor physically deforms, as in the case of pressure and touch receptors, mechanically-gated channels open.
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Projectile effects are a hazard in __________________. magnetic resonance imaging (MRI) fields pediatric units emesis stations operating theaters
Projectile effects are a hazard in MRI fields.
What is MRI field?MRI stands for - Magnetic resonance imaging and it is a medical imaging technique that uses a magnetic field and radio waves to create detailed images of the organs and tissues in your body.
Projectile effects are a hazard in MRI fields, due to attraction exerted by the static magnetic field of the MRI scanner on ferromagnetic objects accidentally introduced into the MRI-scanner room.
Thus, Projectile effects are a hazard in MRI fields.
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What is an application of a magnetic effect of an electric current?
And how does the application work due to the magnetic effect of an electric current?
Applications of Magnetic Effect of ELectric Current:
Electrical appliances such as the electric doorbell, electric fan, electric engines work on the principle of electromagnets. They are used in lifting weighty iron gears and iron scrap.
What is magnetic effect of electric current short answer?Magnetic field exercises a force on a current carrying conductor. The force exerted on the current carrying conductor depends upon the demand of current and movement of magnetic field acting on it.
What is an example of magnetic effect?Examples of magnetic force is a compass, a motor, the interests that hold stuff on the refrigerator, train tracks, and new roller coasters. All moving costs give rise to a magnetic field and the charges that move through its regions, share a force.
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What causes earthquakes?
Where do earthquakes begin?
Answer:
An earthquake is caused by a sudden slip on a fault. The tectonic plates are always slowly moving, but they get stuck at their edges due to friction.
Explanation:
Tensions around rocks are increasing, and an earthquake begins at tectonic plates.
The majority of earthquakes begin at or close to tectonic plate borders, where stress and strain gradually build up due to interactions between the plates over time. An earthquake occurs when the amount of accumulated tension surpasses the capacity of the rocks, which causes an abrupt release of energy. When there is an earthquake, seismic waves are released, and we feel and sense shaking as a result.
But even beyond plate borders, within tectonic plates, earthquakes can still happen. These earthquakes, also known as intraplate earthquakes, are frequently connected to old faults or weak spots in the crust of the Earth. Despite being less frequent than those near plate borders, intraplate earthquakes can nevertheless be severe and cause damage in populated regions.
Hence, tensions around rocks are increasing, and an earthquake begins at tectonic plates.
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What do simple machines increase?
O movement
O force
O gravity
O mechanical advantage
Answer:
Mechanical advantage
Explanation:
Machines help us in giving more output than the input incurred so it only increases mechanical advantage, all the other quantities are dependent on the mechanical advantage.
An automated machine passes milk through steam at a temperature of 138OC for two seconds and then cools it rapidly. This is an example of ____________________.
Option (c) is correct
This is an example of Ultra-high-temperature pasteurization(UHT).
For ultra-high-temperature (UHT) pasteurization, milk or cream must be heated for one or two seconds to 138–150 °C (280–302 °F).
The most popular application of UHT is in the production of milk, although it is also used in the production of fruit juices, cream, soy milk, yoghurt, wine, soups, honey, and stews.
The normal unrefrigerated shelf life of UHT milk in a sterile container is six to nine months.
UHT milk is aseptically packaged to provide a shelf-stable good. A sterile product is put within a sterile package using aseptic packaging and such processing needs to happen in a sterile setting.
Both pasteurization and sterilization help in the destruction of microbes and enzymes by heating but pasteurization only kills the vegetative stage of the bacteria, which is where the spores survive, whereas sterilization kills all microorganisms and their spores.
Therefore, an automated machine passes milk through steam at a temperature of 138°C for two seconds and then cools it rapidly is an example of Ultra-high-temperature pasteurization.
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An asteroid on the earth's orbit experiences a free-fall acceleration which is 8.0 times smaller than it would be on the earth. what is the distance between the asteroid and the earth's surface measured in the earth's radii? neglect the gravity of the moon.
The the distance between the asteroid and the earth's surface measured in the earth's radius is 1.82 R
What are the Asteroids:
Asteroids are small, rocky objects that orbit the Sun. They are much smaller than planets.They are found between the orbits of Mars and Jupiter, though some have more eccentric orbits.here,
An asteroid experiences acceleration on earth's orbit which is 8.0 times smaller than it on the earth surface.
Free fall acceleration of Asteroid:
on earth's surface = gon earth's orbit = g' = g / 8so,
g' = GM /(R + x)^2 ------1
g = GM / R^2
g' = 1/8 ( GM / R^2 ) -------1
where G is gravitational constant
M is mass of earth
R is earth's radius
comparing both equations 1 and 2
GM /(R + x)^2 = 1/8 ( GM / R^2 )
8 R^2 = (R + x)^2
2√2 * R = R + x
x = R (2√2 - 1)
x = 1.82*R
hence, The the distance between the asteroid and the earth's surface measured in the earth's radius is 1.82*R
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A 36,287 kg truck has a momentum of 907,175 kg • meters per second. what is the truck’s velocity? meters per second
The truck's velocity is 25 m/s.
It is given that,
mass, m= 36,287 kg
momentum, p = 907,175 kg-m/s
Using the formula of momentum, we know that
p = mv
Plugging in the values
907,175 kg-m/s = 36,287 kg x v
v = 25 m/s
So, the velocity of the truck is 25 m/s.
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Answer:25
Explanation:your welcome!:)
PLEASE HELP ME I BEGGG
Answer:
,ff
Explanation:
2331552378 added mee
which type of rock can only form below earths surface?
Answer: Igneous it forms because of magma but magma is under the earths surface so its Igneous
Explanation:
Answer:
its metamorphic.
Explanation:
Based on the chemical equation, use the drop-down menu to choose the coefficients that will balance the chemical
equation:
(Na₂HPO4-Na4P₂07
+ H₂0
The coefficients in order are 2, 1, 1
What is balanced chemical equation?A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge is the same for both the reactants and the products.
In other words, the mass and the charge are balanced on both sides of the reaction.
According to the given situation,
To balance the the chemical equation,
Step 1 - Add a 2 on the Na2HPO4:
2(Na₂HPO₄) ⇒ Na4P₂O₇ + H₂O
Step 2 -Next take count of each element on both sides to see if the 2 is balanced or not:
On the left there are 4 Na, 2 H, 2 P, and 8 O
On the right there are 4 Na, 2 H, 2 P, and 8 O
Step 3 - Now we will divide by 2
i.e. 2 NA.H. P
The coefficient of Na is 2 , Coefficient of H is 1 and Coefficient of P is 1
Therefore,
The coefficients in order are 2, 1, 1.
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Two infinite sheets of current flow parallel to the y-z plane. The left-hand sheet, which intersects the x-axis at x = 0, consists of an infinite array of wires parallel to the z-axis with a density n = 910 wires/m and a current per wire of IL = 0.17 A in the +z direction. The right-hand sheet, which intersects the x-axis at x = a = 12 cm, is identical to the left-hand sheet, except that it has a current per wire of IR = 0.17 A in the -z direction.
a) Calculate the y-components of the net magnetic field in the following places: x1 = -15 cm, x2 = 6 cm, and x3 = 24 cm. (The x- and z-components of the B-field are zero.)
B(x1)y = T
B(x2)y = T
B(x3)y = T
b) Suppose the above configuration of currents is unchanged except that the direction of the current IR is reversed so that now IR also flows in the +z direction. (The magnitude remains the same.) Calculate the y-components of the net magnetic field at the same positions as in part a).
B(x1)y = T
B(x2)y = T
B(x3)y = T
c) Return to the configuration of part a). Suppose you want to have the region 0 < x < a able to confine electrons (qe- = -1.60 x 10-19 C, me- = 9.11 x 10-31 kg) that have been accelerated from rest through a 66 V electrostatic potential. If the electrons are to be stacked in circular orbits parallel to the x-z plane with centers on the plane x = a/2, what is the minimum current per wire required if IL and IR are equal in magnitude but opposite in direction?
IL = A
Two infinite sheets of current flow parallel to the y-z plane. The left-hand sheet, which intersects the x-axis at x = 0, consists of an infinite array of wires parallel to the z-axis with a density of n = 910 wires/m and current per wire of IL = 0.14 A in the +zdirection.
The right-hand sheet, which intersects the x-axis at x = a = 12 cm, is identical to the left-hand sheet, except that it has a current per wire of IR = 0.14 A in the -z-direction.
(a) Calculate the y-components of the net magnetic field in the following places:
x1 = -15 cm, x2 =6 cm, and x3 = 24 cm. (The x- and z-components of the B-field are zero.)
B(x1)y = T
B(x2)y = T
B(x3)y = T
Please check the attached file for a detailed answer.
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Calculate the magnitude of the electric field inside the solid at a distance of 9.40 cmcm from the center of the cavity.
The magnitude of electric field inside the solid at a distance of 9.50cm from the center of the cavity is 6.5 x 10⁵ N/C.
Volume of shell of chargeV = ⁴/₃π(R³ - r³)
V = ⁴/₃π (0.092³ - 0.0655³)
V = 2.085 x 10⁻³ m³
Total charge of the surfaceQ = Vσ
where;
V is volumeσ is charge densityQ = 2.085 x 10⁻³ m³ x 7.35 x 10⁻⁴ C/m³
Q = 1.53 x 10⁻⁶ C
Electric field due to the shellE = kQ/R²
E₁ = (9 x 10⁹ x 1.53 x 10⁻⁶)/(0.092)²
E₁ = 1.627 x 10⁶ N/C
Electric field due to the charge qE₂ = (9 x 10⁹ x 2.14 x 10⁻⁶)/(0.092)²
E₂ = 2.276 x 10⁶ N/C
Electric field inside the solid at a distance of 9.50cm from the center of the cavity;
E = E₂ - E₁
E = 2.276 x 10⁶ N/C - 1.627 x 10⁶ N/C
E = 6.5 x 10⁵ N/C
Thus, the magnitude of electric field inside the solid at a distance of 9.50cm from the center of the cavity is 6.5 x 10⁵ N/C.
Complete question:
A point charge of -2.14uC is located in the center of a spherical cavity of radius 6.55cm inside an insulating spherical charged solid. The charge density in the solid is 7.35×10−4 C/m^3.
a) Calculate the magnitude of the electric field inside the solid at a distance of 9.20cm from the center of the cavity.
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The odometer of a car changes from 1048 km to 1096 km in 40
minutes. Calculate the average velocity.
O 22 m/s
O 14 m/s
20 m/s
O 18 m/s
Answer:
20m/s
Explanation:
it covers 20 metres in a second
What are the 2 forces acting on a projectile?
A. Gravity and Tension
B. Air Resistance and Tension
C. Gravity and Air Resistance
D. Gravity and Normal Force
Answer:
Gravity and Air resistance.
Explanation:
A projectile is an object that is launched into the air by the application of an external force and they are able to move freely under the influence of gravity and air resistance.
Therefore,
The 2 forces acting on a projectile are:
Gravity and Air resistance.
While in Earth's orbit, an 80-kg astronaut carrying a 20-kg tool kit is initially drifting toward a stationary space shuttle at a speed of 2 m/s. If she throws the tool kit toward the shuttle with a speed of 6 m/s, her final speed is what value
The answer is 1 m/s toward the shuttle.
In physics, conservation means that the initial and final values are equivalent. This implies that a system's total starting and total final momentums will be identical in terms of momentum. The force acting on an item will always be equal to the change in the object's momentum over time, according to Newton's second law.
Therefore, initial momentum = final momentum
Pi = Pf
100*2 = 20*6+80*v
200 = 120+80*v
200-120 = 80*v
80 = 80*v
1 = v
v = 1 m/s
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An object travels around a circle of radius 4.00 m with a velocity of 2.00m/s. What is its angular velocity? (Please keep your answer with two decimal place and no units)
Angular velocity of the object is 0.5 radian/second.
To find the answer, we need to know about the angular velocity.
What's the mathematical expression of angular velocity?The angular velocity= velocity/ radius
What will be the angular velocity, if an object moves in a circular path of radius 4m and velocity 2 m/s?The angular velocity of the object is 2/4 = 0.5 radian/second.
Thus, we can conclude that the angular velocity is 0.5 radian/second.
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A heat pump used to heat a house runs about one-third of the time. The house is losing heat at an average rate of 22,000 kJ/h. If the COP of the heat pump is 2.8, determine the power the heat pump draws when running.
The power that heat pump draws when running will be 6.55 kj/kg
A heat pump is a device that uses the refrigeration cycle to transfer thermal energy from the outside to heat a building (or a portion of a structure).
Given a heat pump used to heat a house runs about one-third of the time. The house is losing heat at an average rate of 22,000 kJ/h and if the COP of the heat pump is 2.8
We have to determine the power the heat pump draws when running.
To solve this question we have to assume that the heat pump is at steady state
Let,
Q₁ = 22000 kj/kg
COP = 2.8
Since heat pump used to heat a house runs about one-third of the time.
So,
Q₁ = 3(22000) = 66000 kj/kg
We known the formula for cop of heat pump which is as follow:
COP = Q₁/ω
2.8 = 66000 / ω
ω = 66000 / 2.8
ω = 6.66 kj/kg
Hence the power that heat pump draws when running will be 6.55 kj/kg
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