A piecewise function g(x) is represented by the graph.
Which functions represent a piece of the function? Select three options.
Answers
The piecewise functions that are represented by the graph are; g(x) = −2, x < −2; g(x) = −2x + 6, x ≥ 1; g(x) = x/2 + 1, –2 ≤ x < 1
How to Interpret a Piecewise Function graph?From the attached graph of the piecewise function, we can access each option as follows;
A) g(x) = −2x, −2 < x < 0
This is not represented by the graph because g(x) = −2x has negative slope which means it goes downward. There's also no y-intercept in g(x) = −2x.
B) g(x) = −2, x < −2;
This is represented by the graph because g(x) = −2 is a horizontal line which is only on the left side of x = -2.
C) g(x) = x − 2, −2 < x < 1;
This is not represented by the graph because g(x) = x − 2 has y-intercept at y = -2 and slope of 1 which means that graph of g(x)= x - 2 must be going upward and crossing at y = -2.
D) g(x) = −2x + 6, x ≥ 1
This is represented by the graph because g(x) = −2x+6 satisfies the graph which is going downward.
E) g(x) = x/2 + 1, –2 ≤ x < 1
This is represented by the graph because g(x) = (x/2) + 1 satisfies the graph which is going downward.
The options are;
g(x) = −2x, −2 < x < 0
g(x) = −2, x < −2
g(x) = x − 2, −2 < x < 1
g(x) = −2x + 6, x ≥ 1
g(x) = x/2+ 1, –2 ≤ x < 1
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Related Questions
True or False. Both distributions are bell-shaped and symmetric but where the peak falls on the number line is determined by the mean.
Answers
Both distributions are bell-shaped and symmetric but where the peak falls on the number line is determined by the mean.
The given statement is false.
A bell curve is a graph depicting the ordinary distribution, which has a shape harking back to a bell. The top of the curve suggests the mean, mode, and median of the records accrued.
The everyday distribution is a bell-fashioned and symmetrical distribution this is used to calculate the opportunity. in the everyday distribution, the mathematics means, mode, and median are usually the same, and the normal distribution is likewise called the Gaussian distribution.
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A budweiser delivery truck in west texas has driven 1,386 miles in 4 days. he leaves the distributor and stops at 24 stores during this period. between stops the driver averages ___ miles. do not count the driving back to the distributor.
Answers
Using proportions, it is found that between stops the driver averages 57.75 miles.
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three.
In 1,386 miles, the driver had 24 stops, hence the number of miles per stop is found as follows:
1386/24 = 57.75 miles.
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To babysit one child, Fernando charges $10 to drive to the appointment plus $4 per hour. He saves 30% of the total amount he earns. Brenna charges $6 per hour and saves 25% of the total amount she earns. Which equation can be used to determine the number of hours, h, after which Fernando and Brenna will have saved the same amount of money?
a 10 + 0.3(4h) = 0.25(6h)
b 0.3(10) + 4h = 0.25(6h)
c 0.3(10 + 4h) = 0.25(6h)
d 0.3(14h) = 0.25(6h)
Answers
Th equation that can be used to determine when they would have saved the same amount is 0.3(10 + 4h) = 0.25(6h).
When would they have saved the same amount?
The equation that can be used to determine the amount saved by Fernando is:
total amount saved = percentage saved x (amount charged to drive to the appointment + total amount earned)
0.3( $10 + $4h)
The equation that can be used to determine the amount saved by Brenna is:
percentage saved x total amount earned
0.25h
When they save the amount amount, the two above equations would be equal: 0.3(10 + 4h) = 0.25(6h).
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Find f(g(2)) if f(x) = 2x-1 g(x) = -3x Find f(g(2)) if f(x) = 2x-1 g(x) = -3x -6 -9 3 -13Let Q (in grams) represent the mass of a quantity of carbon-14, which has a half-life of 5730 years. The quantity present after t years is Q(t)=10\cdot\left(\frac12\right)^{\left(\frac t{5730}\right)}Q(t)=10⋅(
2
1
)
(
5730
t
)
.
Determine the quantity present after 2000 years.
Let Q (in grams) represent the mass of a quantity of carbon-14, which has a half-life of 5730 years. The quantity present after t years is Q(t)=10\cdot\left(\frac12\right)^{\left(\frac t{5730}\right)}Q(t)=10⋅(
2
1
)
(
5730
t
)
.
Determine the quantity present after 2000 years.
7.851 grams
1.117 grams
0.785 grams
1.745 grams
Answers
The quantity that is present after 2000 years will be A. 7.851 grams.
How to calculate the quantity?From the information given, initially at t = 0, the quantity is 10 grams.
After 2000 years, the appropriate quantity will be:
Q(2000) = 10 (1/2) × (2000/5730)
Q(2000) = 7.851 grams.
In conclusion, the correct option is A.
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what does the Symbol z- stands
Answers
Which graph represents viable values for y = 2x, where x is the number of pounds of rice scooped and purchased from a bulk bin at the grocery store and y is the total cost of the rice?
On a coordinate plane, a straight line with a positive slope begins at point (0, 0), and ends at point (2.5, 5).
On a coordinate plane, blue diamonds appear at points (0, 0), (1, 2), (2, 4).
On a coordinate plane, a straight line with a positive slope begins at point (negative 2.5, negative 5), crosses the x- and y-axis at point (0, 0), and ends at point (2.5, 5).
On a coordinate plane, blue diamonds appear at points (negative 2, negative 4), (negative 1, negative 2), (0, 0), (1, 2), (2, 4).
Mark this and return Save and Exit Next
Answers
The correct match for the graph of the total cost function is the option B graph.
What is a function?The function is a type of relation, or rule, that maps one input to specific single output.
Given;
y = 2x is function
so, our graph should be of function y = 2x
Here, x is the number of pounds of rice scooped and purchased from a bulk bin at the grocery store and y is the total cost of the rice.
it means x is a number like 0, 1, 2, 3
so, the graph of the total cost function is a discrete function in nature.
Hence, graph-B is correct answer.
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Given: ΔABC with
Prove: AD/DB=CE/EB
Statement Reason
1. given
2. If two parallel lines are cut by a transversal, the corresponding angles are congruent.
3. ΔABC ~ ΔDBE AA criterion for similarity
4. Corresponding sides of similar triangles are proportional.
5. AB = AD + DB
CB = CE + EB segment addition
6. Substitution Property of Equality
7. division
8. Subtraction Property of Equality
6
What is the missing step in this proof?
A.
∠CAB ≅ ∠ACB, ∠EDB ≅ ∠DEB
B.
∠ADE ≅ ∠DBE, ∠CED ≅ ∠EBD
C.
∠CAD ≅ ∠ACE, ∠ADE ≅ ∠CED
D.
∠CAB ≅ ∠EDB, ∠ACB ≅ ∠DEB
Answers
Given that DE||AC, by similar triangles, we have;
D. <CAB congruent to <EDB, <ACB congruent to <DEBHow can the missing step be found?A part of the question that appears missing is; side DE||AC
The completed two column proof is presented as follows;
Statement. Reason
1. DE||AC 1. Given
2. <EDB congruent to <CAB
<DEB congruent to <ACB
Which can be written as; <CAB congruent to <EDB, <ACB congruent to <DEB
2. If two parallel lines are cut by a common transversal, the corresponding angles are congruent
3. ∆ABC ~ ∆DBE 3. by AA criterion for similarity
4.
[tex] \mathbf{\frac{ AB }{ CB} } = \frac{ DB }{ EB} [/tex]
4. Corresponding sides of similar triangles are proportional
5. AB = AD + DB
CB = CE + EB 5. Segment addition postulate
6. [tex] \mathbf{\frac{ AD + DB }{ CE + EB} } = \frac{ DB }{ EB} [/tex]
6. Substitution property of equality
7. [tex] \frac{ AD + DB }{ DB} = \frac{ CE + EB }{ EB} [/tex]
7. Division property
8. [tex] \frac{ AD }{ DB} + 1 = \frac{ CE }{ EB} + 1 [/tex]
[tex] \frac{ AD }{ DB} = \frac{ CE }{ EB} [/tex]
8. Subtraction property
Therefore, the missing step in the proof is the option;
D. <CAB congruent to <EDB, <ACB congruent to <DEBLearn more about similar triangles here;
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PLEASE 100 POINTS AND BRAINLIEST
Answers
Answer:
29u
Step-by-step explanation:
a = (V-U)/t = (1.2u-u)/10 = 0.02u
D1: V₀t+0.5at² = (u)(10)+(0.5)(0.02u)+(10)(10) = 11u
D2: (V)(t) = (1.2u)(15) = 18u
D = D1 + D2 = 29u
For first half
Initial velocity=uFinal velocity=v=1.2uTime=10sWe need acceleration first
a=(1.2u-u)/10a=0.2u/10a=0.02uSo distance traveled (Apply second equation of kinematics
s=10u+1/2(0.02u)(10)²s=10u+2/2×100/100×us=11u mFor second half
No acceleration
Distance=Speed×Time
1.2u(15)18u mTotal distance
D=11u+18uD=29u mcan someone help me ?
Answers
Answer:
∠ C = 26°
Step-by-step explanation:
the sum of the 3 angles in a triangle = 180° , that is
∠ A + ∠ B + ∠ C = 180°
120° + 34° + ∠ C = 180°
154° + ∠ C = 180° ( subtract 154° from both sides )
∠ C = 26°
In a function why berries directly with X in the constant of variation is two which table could represent the function
Answers
The correct option is (D)
What is a function?An expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).
the complete question is attached below
As, per the data given we can say that
the variation of quantity is 2.
So, the equation can be
y=2x
This equation defined by part (4) of the question.
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how many centigram are equal to 9.95 milligram
Answers
Answer:
0.995 centigram
Step-by-step explanation:
divide the mass value by 10
Find the sum of the geometric sequence. (7 points) 1 divided by 3, 2 divided by 3, 4 divided by 3, 8 divided by 3, 16 divided by 3
Answers
The sum of the geometric sequence is 31/3
How to determine the sum?The sequence is given as:
1/3, 2/3, 4/3, 8/3, 16/3
The sum of the sequence is;
Sum = 1/3+ 2/3+ 4/3+ 8/3+ 16/3
Evaluate
Sum = 31/3
Hence, the sum of the geometric sequence is 31/3
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3. Find the point of intersection of the graphs for each system. a) x - y = 1 and 3x - y = -1
Answers
Answer:
the point of intersection is (-1 , -2)
Step-by-step explanation:
[tex]\begin{cases}x-y=1&(1)\\ 3x-y=-1&(2)\end{cases}[/tex]
(2) - (1) ⇒ (3x - y) - (x - y) = (-1) - 1
⇒ 3x - y - x + y = -2
⇒ 3x - x = -2
⇒ 2x = -2
⇒ x = -1
……………………………
Now ,we can determine the value of y
by substituting x by its value -1 in the first equation (1) :
(1) x - y = 1 ⇒-1 - y = 1 ⇒ -y = 2 ⇒ y = -2
========================
Conclusion:
x = -1
y = -2
Then ,the point of intersection of the graphs is (-1 , -2)
Hello !
[tex]\begin{cases} x - y &=1 \\ 3x-y &= - 1 \end{cases} \\\Leftrightarrow \begin{cases} x =y + 1 \\ 3x-y = - 1 \: \: \: \: \: (a)\end{cases} [/tex]
We replace x by y+1 in (a) :
[tex]3(y + 1) - y = - 1 \\ 3y + 3 - y = - 1 \\ 2y = - 4 \\ y = \frac{ - 4}{2} = - 2[/tex]
Now we replace x by -1 in the first equation.
[tex]x + 2 = 1 \\ x = -1[/tex]
The point of intersection is (-1;-2).
Have a nice day
Help ON PLATO
Please I need help w more stuff too
Answers
Answer:
find the graph where y is 3 less than x in value
Step-by-step explanation:
the answer explains it if you showed us the graphs we would be able to answer it for you
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
A group of high school students were surveyed about which type of movie they enjoy watching most. The results are shown in the two-way
relative frequency table below.
Female
Male
Total
Comedy
64
54
118
Drama
16
6
22
Action
20
22
42
Sci-Fi
6
27.2% 57.4% 5.7%
12
18
Use the information provided in the table to match each description with the correct percentage of students.
Total
106
94
200
18.9%
6.4%
percentage of female students who prefer sci-fi
45.8% 33.3%
percentage of students who prefer comedies that are male
percentage of male students who prefer dramas
percentage of students who prefer action movies that are female
47.6%
Answers
Answer:
a) 5.7%
b) 45.8%
c) 6.4%
d) 47.6%
Step-by-step explanation:
remember, we find percentage as:
specific / total
(ex. if we have 2 dogs and 2 cats, and we want to find what percentage of total animals are dogs, we divide 2/4 to get 0.5, or 50%)
percentage of female students who prefer sci-fi
here, we know we have 106 female students (total: 106)
and we have 6 of those students who prefer sci-fi (specific: 6)
6 / 106 = 0.05660..
which we can round to: 0.0566
So, the first percentage is 5.66%
(5.7%)
percentage of students who prefer comedies that are male
we have 118 students who prefer comedies (total: 118)
and 54 of those students that are male (specific: 54)
54 / 118 = 0.4576...
which we can round to 0.4576
So, the second percentage is 45.76%
(45.8%)
percentage of male students who prefer dramas
we have 94 male students (total: 94)
and 6 who prefer dramas (specific: 6)
6 / 94 = 0.0638298...
which we can round to 0.0638
So, the third percentage is 6.38%
(6.4%)
percentage of students who prefer action movies that are female
we have 42 students who prefer action movies (total: 42)
and 20 of those who are female (specific: 20)
20 / 42 = 0.47619..
which we can round to 0.4762
So, the fourth percentage is 47.62%
(47.6%)
hope this helps! have a lovely day :)
1. Which statement about this figure is true?
Answers
The planetary boundary layer (PBL) is the lowest layer of the troposphere; its characteristics are influenced by contact with the ground. Wind speed, temperature, and moisture in the PBL all affect weather patterns around the globe. A random sample of days was obtained and the height of the PBL (in meters) above the Great Basin Desert was measured using weather radar. Assume the underlying distribution of PBL heights is normal.
Height(m)
1 673 2 664 3 906 4 956 5 751 6 752 7 654
8 610 9 816 10 667 11 690 12 657 13 920 14 741 15 646 16 682 17 715
18 618 a. Find a 95% confidence interval for the true mean height of the PBL above the Great Basin Desert. b. Is there any evidence to suggest that the true mean height of the PBL above the Great Basin Desert is different from 700 m? There is_____to suggest that the mean height is different from 700 m. The confidence interval_____the value 700 so it is_____as the true mean height of the PBL.
Answers
The confidence interval for the true mean height of the PBL above the Great Basin Desert is (651.48,748.52) and there is any sufficient evidence that the true mean is different from 700 m .
Given Heights in meters: 673,664,906,956,751,752,654,610,816,667,690,657,920,741,646,682,715,618 and confidence level of 95%.
We have to show the evidence that the true mean height is different from 700 m.
We have to first make hypothesis.
[tex]H_{0}:[/tex]μ=700
[tex]H_{1}[/tex]:μ≠700
We have to first find the population standard deviation.
σ=[tex]\sqrt{(x-x bar)^{2}/n-1 }[/tex]
=[tex]\sqrt{187375.1/17}[/tex]
=104.98
Z=(X-μ)/σ
=(700-728.78)/104.98 (μ=728.78 is calculated in figure)
=-0.2741
p value of -0.2741 =0.39358
0.39358
0.39358<0.90
so we reject the null hypothesis.
Which means that the true mean is different from 700m.
Confidence level=X±z*s/[tex]\sqrt{n}[/tex]
Upper level=700 +1.96*104.98/[tex]\sqrt{18}[/tex]
=700+48.52
=748.52.
Lower level=700-1.96*104.98[tex]\sqrt{18}[/tex]
=700-48.52
=651.48
Hence the confidence interval is (651.48,748.52).
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Determine the vertex of the quadratic relation y=2(x+2)(x-6).
Answers
Answer:
V = (2,-32)
Step-by-step explanation:
Hello!
The vertex of a quadratic lies on the Axis of Symmetry (AOS). The axis of symmetry is exactly in the middle of the roots of the Quadratic. We can solve for the AOS by finding the average of the two roots.
Rootsy = 2(x + 2)(x - 6)0 = 2(x + 2)(x - 6)0 = (x + 2)(x - 6)0 = x + 2: x = -20 = x - 6: x = 6The two roots of the quadratic are 6 and -2.
Solve for the AOS[tex]AOS = \frac{r_1 + r_2}{2}[/tex][tex]AOS = \frac{6-2}{2}[/tex][tex]AOS = \frac42[/tex][tex]AOS = 2[/tex]The Axis of symmetry of the quadratic is 2.
VertexSince the vertex lies on the AOS, we know the x-value of the vertex. We can solve for the y-value by plugging in the value of the AOS in the equation.
Find the Vertex
y = 2(x + 2)(x - 6)y = 2(2 + 2)(2 - 6)y = 2(4)(-4)y = 2(-16)y = -32The Vertex of the quadratic is at (2,-32).
What is the smallest positive integer that has a square root that is greater than 10?
Answers
The smallest positive integer that has a square root that is greater than 10 is 101
How to determine the integer?Let the integer be represented by n
The square root is greater than 10.
So, we have:
[tex]\sqrt n > 10[/tex]
Square both sides
n > 100
The above means that the integer is greater than 100.
The smallest integer greater than 100 is 101
Hence, the smallest positive integer that has a square root that is greater than 10 is 101
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Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options.
x < 5
–6x – 5 < 10 – x
–6x + 15 < 10 – 5x
A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.
A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left.
Answers
The inequality are –6x + 15 < 10 – 5x and a number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.
Inequality expressionsInequality are expressions not separated by an equal sign. Given the inequality expression below;
–3(2x – 5) < 5(2 – x)
Expand
-6x + 15 < 10 - 5x
Collect the like terms
-6x + 5x < 10 - 15
-x < -5
x > 5
Hence the correct representations of the inequality are –6x + 15 < 10 – 5x and a number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.
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What is the center of MN given M(3, -1) and N(7,-5)
Answers
Answer:
(5, -3)
Step-by-step explanation:
So the center of the two points, or a line can be defined using the equation: [tex]midpoint=(\frac{x_2+x_1}{2}, \frac{y_2+y_1}{2})[/tex]. So using the two points you gave, you simply plug the values in to get
[tex]midpoint=(\frac{3+7}{2}, \frac{-1+(-5)}{2})\\[/tex]
Add numerators:
[tex]midpoint=(\frac{10}{2}, \frac{-6}{2})[/tex]
Simplify fraction:
[tex]midpoint=(5, -3)[/tex]
two fifth grade classes raised money for their local animal shelters. there are 20 students in class a each student raised 12 there are 26 students in class b each student in class b rasied 1.5 times as much as each student in class a
Answers
The amount the first charity got is $10.
The amount the second charity got is $20.
How much did each charity get?The first step is to determine the amount raised by the second fifth grade class: 1.5 x $12 = $18
The total amount raised by the two classes : $18 + $12 = 30
Let x represent the amount gotten by the first charity
Amount gotten by the second charity : 2x
2x + x = $30
3x = $30
x = $30 / 3
x = $10
Amount gotten by the second charity : 2(10) = $20
Two fifth grade classes raised money for their local animal shelters. there are 20 students in class a each student raised $12. there are 26 students in class b each student in class b raised 1.5 times as much as each student in class a. The money raised went to two charity. One charity received two times as much as the other. How much money did each charity receive? Show your work and explain your answer.
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Erin had 555555 stuffed bears. she took out her favorite 777 bears and then equally divided the other bears among her 333 sisters. erin's youngest sister, su, already had 151515 stuffed bears. how many stuffed bears does su have now?
Answers
The number of stuffed bears with Su=153181
What is the number of stuffed bears Su has?Total number of bears Erin has=555555
The number of bears Erin took out=777
Remaining number of bears with Erin=555555-777
=554778
Now, these remaining stuffed bears are to be divided equally among 333 sisters.
So, each sister gets [tex]\frac{554778}{333}[/tex]=[tex]1666[/tex] stuffed bears.
To find the number of stuffed bears Su has, find the sum of her share of stuffed bears and the number of stuffed bears she already had.
Number of stuffed bears Su already has=151515
Total number of bears she has at present=151515+1666
=153181
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Name two monomials with a quotient of 12
Answers
Find the surface area of the figure!! pls show work thank you!!! geometry!!
Answers
Answer:165
Step-by-step explanation:
Victor borrowed money at 5.25 percent simple annual interest. At the end of the year, the interest on the loan is $255.94. What was the amount of the loan?
Answers
$4,875.24Given:interest
255.94rate = 5.25%term
yearsimple.
1. take away five from twelve times f. 2. one-half of the sum of k and six 3.x squared minus the sum of 5 4.the sum of the product of a and b, and three times c 5.twenty-four times the product of x and y, plus g.
Answers
The expressions formed are,
12f -5(k+6)/2x²-x+5ab+3c24xy+gFormation of expressions in 1, 2 and 3:
In 1, twelve times f is, 12f
Taking away 5, it becomes (12f-5)
In 2, sum of k and 6 is, (k+6)
One-half of the above quantity is, (k+6)/2
In 3, sum of 5 with x is, (x+5)
Now, x squared minus the above expression indicates (x²-x+5)
Formation of expressions in 4 and 5:
In 4, product of a and b, is ab and 3 times c is 3c
Sum of the expressions evaluated in the previous statement = ab+3c
In 5, 24 times the product of x and y is, 24xy
Adding, g in the above computed expression, we get, 24xy+g
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Need help (problem and directions in the image):
Answers
Triangle ABC is congruent to triangle CDE using the side - angle - side congruence theorem. The sink hole is 52.2 ft and the Perimeter of ABC is 172.2 ft
What are congruent triangles?Two triangles are said to be congruent if they have the same shape and their corresponding sides are congruent.
In the image shown:
AC = CE, BC = ED and they have the same angle (opposite angles are congruent).
Hence:
Triangle ABC is congruent to triangle CDE using the side - angle - side congruence theorem.
AB = DE = 52.2 ft
Perimeter of ABC = AB + BC + AC = 50 + 70 + 52.2 = 172.2 ft
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12. Todd graphs a quadratic function. The graph of his quadratic
function passes through the points
(-2,0), (4,0), and (0,-32). Which quadratic function could be Todd's
function?
a. y = 4x² - 8x - 32
b. y = 4x² + 8x - 32
C. y = 2x² - 16x - 32
d. y = -4x² + 8x - 32
a
b
OC
d
Answers
You already know that the y-intercept in -32 for every equation by plugging in 0 for x, so disregard the coordinate (0,-32). Plug in -2 and 4 as your x values and check if they are equal to your y-value 0.
y = 2x² - 16x - 32 is the quadratic function of function passes through the points (-2,0), (4,0), and (0,-32).
What is Quadratic function?y=ax²+bx+c is called as Quadratic function
y=ax²+bx+c
The three points are (-2,0), (4,0), and (0,-32)
Let,
(-2,0) in equation
0=a(-2)²+b(-2)+c
0=-2b+c...(1)
(4,0)
0=a(4)²+b(4)+c
0=16a+4b+c..(2)
(0,-32)
-32=a(0)²+b(0)+c
c=-32...(3)
Hence put c value in (1)
0=-2b-32
2b=-32
b=-16
Now put b and c value in 2
0=16(a)+4(-16)+32
0=16a-64+32
0=16a-32
a=2
Hence y = 2x² - 16x - 32 is the quadratic function of function passes through the points (-2,0), (4,0), and (0,-32).
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Solve the system of equations using elimination: -8x-4y=4 and -5x-y=-11.
Answers
The solutions to the given system of equations are x = 4 and y = -9
Simultaneous linear equationsFrom the question, we are to determine the solutions to the given system of equations
The given system of equations are
-8x-4y=4 --------- (1)
-5x-y=-11 --------- (2)
Multiply equation (2) by 4
4 ×[-5x-y=-11 ]
-20x -4y = -44 -------- (3)
Now, subtract equation (3) from equation (1)
-8x -4y = 4 --------- (1)
-(-20x -4y = -44) -------- (3)
12x = 48
x = 48/12
x = 4
Substitute the value of x into equation (2)
-5x -y = -11
-5(4) -y = -11
-20 -y = -11
-y = -11 + 20
-y = 9
∴ y = -9
Hence, the solutions to the given system of equations are x = 4 and y = -9
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