A piece of metal has a mass of 32.4g and has a volume of 24.9cm³. What is its
density?

Answers

Answer 1

A piece of metal has a mass of 32.4g and has a volume of 24.9cm³, then its density is 1.301 g/cm³

What is density?

Density is defined as mass of a material substance per unit of the volume. The equation for density is d = M/V, where d stands for density, M for mass, and V for volume.

Grams per cubic centimeter are a common unit of density measurement. For instance, the density of Earth is 5.51 grams per cubic centimeter, whereas the density of water is 1 gram per cubic centimeter.

Density measures how tightly a mass of matter is packed. The density of a mass depends on how tightly it is packed in relation to the volume that it takes up. A low density substance, on the other hand, has a lower mass to volume ratio.

The amount of a substance present when its density is being measured ought not to have an impact on its density, in theory. The ratio of mass to volume should be constant regardless of the size of the sample being tested.

The formula of density is

[tex]\rho ={\frac {m}{V}}[/tex]

Where,

[tex]\rho[/tex] = density

m = mass

V = volume

We have given

m = 32.4g

V = 24.9cm³

[tex]\rho[/tex] = 32.4g/24.9cm³

[tex]\rho[/tex] = 1.301 g/cm³

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Related Questions

Hydrochloric acid and oxygen gas form water and chlorine gas. How many moles of water are produced from 5.52 moles of oxygen gas?

Answers

Explanation:

According to the problem, hydrochloric acid will react with oxygen gas to produce water and chlorine gas.

hydrochloric acid + oxygen gas ----> water + chlorine gas

The balanced equation will be:

4 HCl + O₂ -----> 2 H₂O + 2 Cl₂

If we pay attention to the coefficients of the reaction we will see that 4 moles of HCl will react with 1 mol of O₂ to produce 2 moles of H₂O and 2 moles of Cl₂. So, 1 mol of O₂ will produce 2 moles of H₂O. The molar ratio between O₂ and H₂O is 1 to 2.

1 mol of O₂ : 2 moles of H₂O molar ratio

We can use this relationship to find the number of moles of H₂O that are produced from 5.52 moles of O₂.

moles of H₂O = 5.52 moles of O₂ * 2 moles of H₂O/(1 mol of O₂)

moles of H₂O = 11.0 moles

Answer: 11.0 moles of water are produced from 5.52 moles of oxygen gas.

What is the molarity of Na3PO4 when 1.7 moles of are dissolved in a 2.8 L solution? Be sure to include the proper abbreviation for the Units

Answers

Molarity or molar concentration is a measure of the concentration of a chemical species, of a solute in a solution, using as units, number of moles, and volume in liters. The formula for Molarity is:

M = n/V

Where:

n = number of moles, 1.7 moles

V = volume in Liters, 2.8 Liters

Now we add these values into the formula:

M = 1.7/2.8

M = 0.61

The Molarity is 0.61 M

39. Period is the force of attraction between objects resulting in objects pulling towards eachother.a. Trueb. False

Answers

Answer

a. True

Explanation

If there was nothing to avoid from objects pulling towards one another many results may happen.

What is the change in temperature after 840 Joules is absorbed by 10.0g of water is heated?(Specific heat of water is 4.184 J/g °C)​

Answers

Answer:

dt=20.08

Explanation:

Q=msdt

840=10*4.184*dt

dt=840/(10*4.184)

dt=20.08

If the temperature of a gas remains constant the the pressure of gas will increase the

Answers

Answer:

If the temperature of a gas remains constant the the pressure of gas will increase the impacts on the walls of the container , thus increasing the volume

What is the
formula weight of zinc phosphate? Provide an answer to two decimal
places.

Answers

The formula weight of zinc phosphate is 385g/mol.

The formula weight or molar mass of zinc phosphate is calculated by adding weight of every single element present in zinc phosphate.

Formula of zinc phosphate is Zn₃(PO₄)₂.

Weight of 3 zinc atoms = 3×65= 195g/mol

Weight of 2 phosphorus atoms =2×31=62g/mol

Weight of 8 oxygen atoms = 8×16= 128g/mol

So, the total molecular weight of the compound is 195+62+128= 385g/mol.

Thus, the molecular weight of zinc phosphate is 385g/mol.

Zinc phosphate is an inorganic chemical substance that is used as a priming pigment or as part of the electroplating process to provide a corrosion-resistant coating on metal surfaces. It is common practice to employ a seeding chemical as a pre-treatment because zinc phosphate adheres to crystalline structures better than bare metal. Dental practices use zinc phosphate, which is created from zinc phosphate cement.

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Solution B What is the molarity of this solution? _____M

Answers

We have an initial concentration of a stock solution that has molarity equal to 1M. In a previous question, the stock solution was diluted 10 times, this solution was called solution A. The concentration of solution A found was equal to 0.1M.

Now, we are asked to find the concentration of solution B that starts from solution A.

The initial concentration C1 is the concentration of solution A, equal to 0.1M. The initial volume (V1) is 10mL, and the final volume (V2) is 100mL. We will apply the dilution equation that says:

[tex]C_1V_1=C_2V_2[/tex]

We clear C2 and replace the known data:

[tex]C_2=\frac{C_1V_1}{V_2}[/tex][tex]\begin{gathered} C_2=\frac{0.1M\times10mL}{100mL} \\ C_2=0.01M \end{gathered}[/tex]

Answer: The molarity of solution B is 0.01 M

How do I go about properly solving this question?

Answers

The percent abundance of the cannellini beans in this sample is : 18.8 %

The average weighted = 1.9 g

M1 = mass of black eyed peas = 1.3

M2 = mass of cannellini = 2.9

x = % abundance

weighted average is given = 1.9 g

applying the formula :

M1x + M2 (1-x) = average weighted

1.3 × x + 2.9 (1-x) = 1.9

x = 0.812

% abundance of black eyed peas = 81.2 %

% abundance of cannellini beans = (1-0.812) = 0.188 = 18.8 %

Thus, The percent abundance of the cannellini beans in this sample is : 18.8 %

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what have the prescriptions of painkillers cost Americans? How does this compare to the
benefits of pain relief? How should scientists direct their research about chronic pain in the future?

Answers

Answer:

The CDC estimates the total economic burden of prescription opioid misuse in the United States is $78.5 billion a year.

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Please help me please

Answers

If air conditioning system won't be able to chill your home until the fan is fixed if it has stopped functioning.

What happens if your AC fan stops working?

Your air conditioning system won't be able to chill your home until the fan is fixed if it has stopped functioning. The circuit breaker should be checked first if the AC unit fan is not whirling. Check to see if the circuit breaker for the air conditioning equipment has tripped. The heat from the motor and the weather outdoors can cause a circuit breaker to trip due to overheating.

If the fan won't turn on, the fan motor might be malfunctioning. If you are having trouble getting the blades to turn, the motor bearings may be dusty or stuck, or there may be debris wrapped around the fan axle.

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If the fan motor is malfunctioning, it could seriously harm your system. Your entire system could fail if the fan motor becomes stuck, which could lead to the compressor overheating and failing.

What would cause AC fan to stop?A dead capacitor is one of the most typical reasons fans cease spinning. The fan motor and the remainder of the AC unit are powered by small, cylindrical capacitors that transmit energy signals. An air conditioner fan motor can get too hot if it runs too hard and isn't properly maintained, just like any other motor. The stress may cause the fan motors to burn out if your AC has served you well for the majority of the summer. A lifespan of 10 to 20 years is more typical, which implies that by the time the AC motor breaks, it is frequently time to think about replacing the entire system. They are built to endure intense heat up to 140°F, which is one reason they stay so long.

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-Write the net ionic equation that shows the reaction of 1.0 M ammonia, NH3, when dissolved in water.

-At room temperature the Keq of the above solution is 1.1. If the initial concentration of NH3 is 1.0 M, quantitatively define the pH of above solution (Show calculations using an I.C.E. table and use the quadratic equation)

-What is the reaction that occurs when a solution of ammonia is added to a solution containing Fe3+ ions?

-Propose a chemical compound that can be used to dissolve the precipitate formed in part 1.c. Support your answer with a proper chemical equation

Answers

In essence, there is no chemical reaction between ammonia and water. Although it is frequently said to produce NH₄OH, the overall response is:

H₂O + NH₃ = NH₄⁺ + OH⁻

You might compare the acid strength of H₂O (pka 15.7) and NH4⁺ (pka 9.24) or the base strength of NH₃ and OH⁻ to see which way the reaction would proceed. The reaction would shift to the weaker acid (H₂O) or the weak base in either case (NH₃). Despite what the bottle claims, weak doesn't make strong. I mean, there might be a small amount of NH₄⁺ and OH⁻ in the air, but not much.

The iron (III) ion forms an insoluble hydroxide and precipitates out of solution when ammonia is added to the solution.

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Although an object's speed can vary while it moves, which speed listed is possible to calculate by
using total distance and total time?
A. average speed
B. total speed
C. initial speed
D. final speed

Answers

It would be B
Hope this helps

How many moles of sodium sulfate (Na2SO4) are in 83.1 g of the compound?

Answers

Answer:

0.585 moles Na₂SO₄

Explanation:

To find the amount of moles of Na₂SO₄, you need to multiply the given mass (grams) by the molar mass. You can use the molar mass to convert between grams and moles because the molar mass exists as a ratio which compares the mass of Na₂SO₄ per every 1 mole. The ratio should be arranged in a way that allows for the cancellation of units (grams should be in the denominator). The final answer should have 3 sig figs like the given value.

Atomic Mass (Na): 22.990 g/mol

Atomic Mass (S): 32.065 g/mol

Atomic Mass (O): 15.999 g/mol)

Molar Mass (Na₂SO₄): 2(22.990 g/mol) + 32.065 g/mol + 4(15.999 g/mol)

Molar Mass (Na₂SO₄): 142.041 g/mol

 83.1 grams Na₂SO₄                  1 mole
--------------------------------  x  --------------------------  =  0.585 moles Na₂SO₄
                                             142.041 grams

Calculate the pH of an aqueous solution that is 0.200 mol L-1 in NH3 and 0.300 mol L-1 in NH4Cl.

Kb(NH3) = 1.8 x 10-5

Answers

The pH of an aqueous solution that is 0.200 mol/L in NH₃ and 0.300 mol/L in NH₄Cl is 7.9.

We will use Henderson-Hasselbalch equation to calculate the pH. It is given by -

pH = pKa + log [base]

                         [acid]

We know that,

base is NH₃

acid is NH₄⁺

we will calculate molarity as-

NH₃ : 0.200/2 = 0.1 M

NH₄⁺ : 0.300/2 = 0.15 M

Now, we will find pKa by -

Kw = Ka . Kb

Ka = 1 x 10⁻¹⁴

       1.8 x 10⁻⁵

Ka = 5.5 x 10⁻¹⁰

pKa = -logKa

pKa = 9.25

Substituting the values in equation,

pH = 9.25 + log  [0.1]

                          [0.15]

pH = 7.9

Therefore, the pH is found to be 7.9.

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Need help with chemistry Atomic Masses: C-12.0 NA-23.0, O-16.0, P-31.0, Sn-119

Answers

INFORMATION:

We know that:

- 34.37 g of tin(IV) phosphate is added to 34.05 g of sodium carbonate

- 24.24 g of tin(IV) carbonate are made

And we must find the %yield

STEP BY STEP EXPLANATION:

Balanced equation:

Sn3(PO4)4 + 6Na2CO3 → 3Sn(CO3)2 + 4Na3PO4

1. We must find the amount of tin carbonate produced by tin phosphate

[tex]34.37gSn_3(PO_4)_4\times\frac{1molSn_3(PO_4)_4}{480.03gSn_3(PO_4)_4}\times\frac{3molSn(CO_3)_2}{1molSn_3(PO_4)_4}\times\frac{238.73gSn(CO_3)_2}{1molSn(CO_3)_2}=51.2790gSn(CO_3)_2[/tex]

2. We must find the amount of tin carbonate produced by sodium carbonate

[tex]34.05gNa_2CO_3\times\frac{1molNa_2CO_3}{105.9888gNa_2CO_3}\times\frac{3molSn(CO_3)_2}{6molNa_2CO_3}\times\frac{238.73gSn(CO_3)_2}{1molSn(CO_3)_2}=38.3472gSn(CO_3)_2[/tex]

3. We must find the theoretical amount of tin carbonate produced

Since sodium carbonate is the limiting reactant, then the theoretical amount of tin carbonate produced would be

[tex]38.3472gSn(CO_3)_2[/tex]

4. Finally, the %yield would be

[tex]\text{ \%yield}=\frac{24.24gSn(CO_3)_2}{38.3472gSn(CO_3)_2}\times100=63.2119\text{ \%}[/tex]

ANSWER:

1.

[tex]34.37gSn_3(PO_4)_4\frac{1molSn_{3}(PO_{4})_{4}}{480.03gSn_{3}(PO_{4})_{4}}\frac{3molSn(CO_{3})_{2}}{1molSn_{3}(PO_{4})_{4}}\frac{238.73gSn(CO_{3})_{2}}{1molSn(CO_{3})_{2}}=51.2790gSn(CO_3)_2[/tex]

2.

[tex]34.05gNa_2CO_3\frac{1molNa_{2}CO_{3}}{105.988,8gNa_{2}CO_{3}}\frac{3molSn(CO_{3})_{2}}{6molNa_{2}CO_{3}}\frac{238.73gSn(CO_{3})_{2}}{1molSn(CO_{3})_{2}}=38.3472gSn(CO_3)_2[/tex]

3.

[tex]38.3472gSn(CO_3)_2[/tex]

4.

[tex]\operatorname{\%}\text{y}\imaginaryI\text{eld}=\frac{24.24gSn(CO_{3})_{2}}{38.347,2gSn(CO_{3})_{2}}\times100=63.2119\operatorname{\%}[/tex]

How does the volume and mass of reactants affect the volume of products in a chemical reaction?

Answers

According to the Le Chatlier's Principle, an equilibrium system will adapt to a change in temperature, volume, or the quantity of molecules in a reactant or product in order to reestablish balance.

Describe molecules?

The smallest unit of a substance that keeps its content and properties is a molecule, which is made up of two or more atoms linked together by chemical bonds. The building blocks of chemistry are molecules. A subscript with the atom count is placed after the element symbol to identify molecules.

Simple definition of a chemical reaction

When two or more molecules interact to create a brand-new product, a chemical reaction takes place. Reacting substances are referred to as reactants, whilst newly created substances are referred to as products.

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How do you identify a redox reaction?

Answers

Answer:

I think you have to calculate the oxidation number of each atom in the reaction.

Explanation:

Hope that helped! ^u^

5.238 x 10^24 molecules of aluminum bromide to grams

Answers

Answer

2319.698 g

Procedure

Use the Avogadro's number and then the molecular weight to convert into grams. The formula for aluminum bromide is AlBr₃.

[tex]5.238\times10^{24}\text{ molecules AlBr}_3\frac{1\text{ mole}}{6.022\times10^{23}}\frac{266.69\text{ g}}{1\text{ mole}}=2319.698\text{ grams}[/tex]

If 150g of orange Juice Contains 120mg of ascor bic acid (Vitamin C). What is the concentration. of Vitamine c in ppm & ppb ?​

Answers

1. The concentration of the vitamin C in ppm is 800 ppm

2. The concentration of the vitamin C in ppb is 800000 ppb

1. How to determin the concentration in ppm

The concentration of the vitamin C in ppm can be obtained as follow:

Mass of vitamin C = 120 mg = 120 / 1000 = 0.12 gMass of solution (orange juice) = 150 gConcentration (in ppm) =?

Concentration (in ppm) = (mass of solute / mass of solution) × 10⁶

Concentration (in ppm) = (0.12 / 150) × 10⁶

Concentration (in ppm) = 800 ppm

2. How to determin the concentration in ppb

The concentration of the vitamin C in ppb can be obtained as follow:

Mass of vitamin C = 120 mg = 120 / 1000 = 0.12 gMass of solution (orange juice) = 150 gConcentration (in ppb) =?

Concentration (in ppb) = (mass of solute / mass of solution) × 10⁹

Concentration (in ppb) = (0.12 / 150) × 10⁹

Concentration (in ppb) = 800000 ppb

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Mass = 16.0 g Volume = 4.0 cm3.A student finds the mass of the sample to be 17.5 grams. What is the student's approximate percent deviation (percentage of error)?

Answers

The student's approximate percent deviation or percentage of error in the measurement of the mass of the sample is 9.38 %.

What is the percentage deviation?

Percent deviation is calculated to determine the accuracy of data collected during an experiment by comparing it to the theoretical results. Percent deviation is commonly used to check for data errors in student experiments.

Percent deviation can be referred to how much measured data differs from a known or theoretical value. A negative percent deviation indicates that the measured data is lower than the theoretical value. A positive percent deviation shows that the measured value is higher.

Given the actual value of the mass = 16 g

The calculated or approx value by student = 17.5 g

The percentage deviation = [(Approx - actual)/ actual ] × 100

                                              = [(17.5 - 16)/16] × 100

               Percentage error  = 9.38 %

Therefore, the student's approximate percent deviation is 9.38 %.

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A student placed 20.0 g of glucose ( C6H12O6 ) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100. mL mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 45.0 mL sample of this glucose solution was diluted to 0.500 L . How many grams of glucose are in 100. mL of the final solution?Express your answer to three significant figures and include the appropriate units.

Answers

Answer:

1.80 g (grams) of glucose.

Explanation:

First, we dissolve 20.0 g of glucose in a volume of water of 100 mL (0.1 L), so let's calculate the concentration of glucose in g/L, like this:

[tex]Concentration=\frac{20.0\text{ g}}{0.1\text{ L}}=200\text{ g/L.}[/tex]

Now, we take 45 mL (0.045 L) of this solution that contains a concentration of glucose of 200 g/L to create a new solution with 0.500 L.

From this new solution, we have to find the mass of glucose if we took 100 mL (0.1 L) of this solution, so we have to use the following equation:

[tex]C_1V_1=C_2V_2.[/tex]

Where C is concentration, V is volume, and subindex 1 and 2 indicate the initial solution, which in this case, is C1 = 200 g/L, V1 = 0.045 L, and the final solution with unknown concentration (C2) and a volume of V2 = 0.500 L.

Let's solve for C2 and replace the given data to obtain the new concentration (final concentration) of the new solution of 0.500 L, like this:

[tex]\begin{gathered} C_2=\frac{C_1V_1}{V_2}, \\ C_2=\frac{200\text{ }\frac{g}{L}\cdot0.045\text{ L}}{0.500\text{ L}}, \\ C_2=18.0\text{ g/L.} \end{gathered}[/tex]

The final concentration of glucose in 0.500 L would be 18.0 g/L.

The next and final step is to calculate the total mass using the volume that we took from the 0.500 L solution, which is 100.0 mL (0.1 L). To do this, we have to do a dimensional analysis to obtain the answer in units of grams, so the calculation will look like this:

[tex]\begin{gathered} mass\text{ of glucose=}18.0\frac{g}{L}\cdot0.1L, \\ mass\text{ of glucose=1.80 g.} \end{gathered}[/tex]

The answer would be that we have 1.80 g (grams) of glucose in 100 mL from the 0.500 L solution.

Calculate the [OH−] of each aqueous solution with the following [H3O+].milk, 3.5×10−7M Express the molarity to two significant figures.

Answers

Step 1

The equations used here:

[tex]\begin{gathered} pH\text{ = - log }\lbrack H3O+\rbrack\text{ \lparen1\rparen} \\ \lbrack H3O+\rbrack\text{ = concentration in M} \\ ------ \\ pOH\text{ = -log }\lbrack OH-\rbrack\text{ \lparen2\rparen} \\ ------ \\ pH\text{ + pOH = 14 \lparen3\rparen} \end{gathered}[/tex]

------------

Step 2

Information provided:

[H3O+] = 3.5×10^−7 M

------------

Step 3

Procedure:

Firstly, from (1):

pH = -log [H3O+]

pH = -log (3.5×10^−7 M) = 6.5

----

From (3):

pH + pOH = 14

pOH = 14 - pH

pOH = 14 - 6.5

pOH = 7.5

----

From (2)

pOH = - log [OH-] => [OH-] = 10^-(pOH)

[OH-] = 10^-(pOH) = 10^-(7.5) = 3.2x10^-8 M

Answer: [OH-] = 3.2x10^-8 M

8. Which statements are true about why wind tends to blow from over the water to over the land on a sunny day? Highlight all the statements that apply.
A. Air over the water is cooler than air over the land is.
B. The air above the land has greater density.
C. The wind is caused by differences in density.
D. Cool, dense air from over the water flows toward the land, pushing warm air upward.

Answers

The wind tends to blow from over the water to over the land due to the differences in the density of air. Air over the water is cooler than air over the land and denser air from over the water flows toward the land. Therefore, options A, C, and D are correct.

What is sea breeze?

The sea breeze is the wind that blows across the sea toward land throughout a sunny day. The air over land heats up more quickly during the day and starts to rise in coastal areas.

A low-pressure area forms on the surface of the land as the warm air rises, allowing air over the water to enter. As a result, during the day the wind direction is from the water to the land and this wind happens to be the sea breeze.

The sea breeze is a thermally produced wind during the day blowing from the cool ocean towards warm land. It is caused by the difference in the density of air between the land and the ocean.

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Which of the following are equal for a chemical system at equilibrium?

Answers

Step 1 - Understanding what happens when a reaction reaches equilibrium

When a reaction reaches equilibrium, the concentration of reactants and products will not vary anymore. That doesn't mean the concentration of reactants will be equal to that of products. It won't. At least, not necessarily. It may be, but it may not as well.

What actually happens when equilibrium is reached is that both reactions - the direct and the reverse one - are happening with the same velocity, i.e., their rate of reaction is the same, and that's why neither the concentration of reactants nor products vary.

As soon as a new molecule of product is produced, another molecule of product is reacting back to produce the reactants once again.

Step 2 - Choosing the right alternative

The right alternative therefore is the rate for the forward and reverse reactions are the same.

Answer: the rate for the forward and reverse reactions are the same

Why is crystal of oxalic acid regarded as a primary standard solution ?

Answers

In order to reliably compute the number of moles present from the measured weight and the known molar mass, is a chemical that can be exactly weighed out in pure forms, such as oxalic acid.

What does the term "standard solution" mean?

A standard solution is a liquid with a precisely known concentration that is made from a primary standard, which is a substance that is stable, highly pure, highly soluble in water, and has a high molar mass to enable precise weighing. The primary standard is weighed precisely and is made up to a specific volume.

What kinds of standard solutions are there?

The terms primary solution and secondary solution refer to two different categories of standard solutions. A primary standard solution is a highly pure, low-reactive solution. A secondary standard is less pure than a prime standard and more chemically reactive.

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PLEASE HELP ASAP.


What conditions are being experienced
by an observer in Florida when the moon
is at Position 2?

Answers

When the moon is at point 2, it will be covering Florida, which will cause some areas of the earth to be dark while others will be light.

What is Earth known for?

Earth, the third planet from the sun, is the only place in the known cosmos where the presence of life has been established. With a 3,959-mile radius, Earth is the fifth-largest planet in our solar system and the only one whose surface is known to have liquid water. Moreover, the names given to Earth are distinctive.

What are 8 facts about Earth?Earth is not flat, but it's not perfectly round either. The days are getting longer. There weren't always several continents. Earth's icy times. The driest place on Earth. Earth's gravity isn't uniform. In the past, sea levels were very different. Our sun has a voracious appetite.

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In a monomolecular reaction A->B , at t =250C, the initial concentration decrease at 25% in t =52 min. Calculate:

a) the constant rate;

b) the time after the initial concentration decrease with 75%;

c) the initial reaction rate, if the initial concentration of the reactant is 2.5 mol/L·s

Answers

1) The rate constant is  9.22 * 10^-5 s-1

2) The time taken is 15033 s

3) The initial concertation  is  9.22 * 10^-5 M

What is the rate of reaction?

We can define the rate of reaction as the rate at which reactants are converted into products or the rate of which reactants disappear and the products appear in a given reaction.

We are told that in this reaction as we can see, the initial concentration decrease at 25% in t =52 min.

Initial concentration [A]o =  [A]o

Final concentration =  [A]o - 0.25  [A]o = 0.75 [A]o

Time taken = 52 min or 3120 s

We have that;

ln[A] = -kt + ln[A]0

k = -(ln[A] -  ln[A]0)/t

k = - (ln0.75 [A]o/A]0)/3120

k = 9.22 * 10^-5 s-1

b)

Given that

[A] =  [A]o - 0.75  [A]o = 0.25 [A]o

ln[A] = -kt + ln[A]0

t = -(ln[A] -  ln[A]0)/k

t = - (ln0.25 [A]o/A]0)/9.22 * 10^-5

t = 15033 s

c) When the rate is 2.5 mol/L·s

k = - (ln0.25 (2.5)/ln(2.5))/15033

k = 9.22 * 10^-5 M

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Compare the value you calculated for the number of sand grains on Earth's beaches to the number of particles In
mole.
What can you conclude about the size of a mole?
The number of particles in a mole is about
the number of grains of sand on Earth's beaches.

Answers

So, the number of particles in a mole is about 80,000 the number of grains of sand on Earth’s beaches.

How to slove and Compare the value you calculated for the number of sand grains on Earth's beaches to the number of particles In mole?

Using sand grains that take up space of 1 mm, when these sand grains are laid side by side, there are about 1000 grains of sand per m, 1000000 per square m and 1000 × 1000 × 1000 per cubic m.

That is 10⁹ grains of sand per cubic meter.

An average beach has sand volume of (1.875 × 10⁷) cubic metres

There are over 400 beaches in the world, Using an estimate of 400 beaches

The number of grains of sand on Earth's beaches = 10⁹ × 400 × 1.875 × 10⁷

There are approximately (7.5 × 10¹⁸) grains of sand on all of the world's beaches

Then, Avogadro's number found that 1 mole of all particles contain

(6.022 × 10²³) particles.

So, the number of particles in a mole is about [(6.022 × 10²³)/(7.5 × 10¹⁸)]

the number of grains of sand on Earth’s beaches.

So, the division gives, (8.0 × 10⁴).

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Calculating the average atomic mass from Isotope data

Answers

The relative atomic mass of the given elements are:

Sulfur = 32.054 amuChlorine = 35.46 amu

What is the relative atomic mass of an element?

The relative atomic mass of an element can be defined as the number of times the average atomic mass of the element is heavier than one-twelfth the mass of an atom of carbon-12.

The relative atomic mass of an element is obtained by summing the product of the mass of each isotope of an element and its relative abundance.

The relative atomic mass of the elements are determined as follows:

Sulfur:

Relative atomic mass = (32.95 * 0.0075) + (31.972 * 0.950) + (33.967 * 0.042) + (36.01435 * 0.0002)

The relative atomic mass of sulfur = 32.054 amu

Chlorine:

Relative atomic mass =  (34.97 * 0.755) + (36.97 * 0.245)

The relative atomic mass of chlorine = 35.46

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Determine the hybrid orbital of this molecule.

A. sp³d²
B. sp³d
C.sp
D. sp²

Answers

The hybrid orbital of this molecule is B. sp³d

What do sp2 and sp3 hybridizations entail?

Trigonal symmetry was used to generate a combination of s and p orbitals, which are kept at 1200. Ethylene (C2H4) sp3 hybridization is an example of sp2 hybridization. To create a novel hybrid orbital known as the sp3 sp3 orbital, one's' orbital and three 'p' orbitals of equal energy are mixed in this type: One of four new comparable orbitals that result from geometrically combining one s orbital and three p orbitals to create a normal tetrahedron's four corners.

Again, we refer to them as sp3 particles because they are made up of a single s orbital and three p orbitals. These degenerate hybrid orbitals are created to offset the s-p transition's energy upward.

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