A piece of chocolate is 4/5 inch long. Meg lays 4 chocolate pieces end to end in a row. How many inches long is the row of chocolates ( please helpppppp) ( MAP test question)

Answer:

The part that is shaded is 5/14

Step-by-step explanation:

The total circle is 1

1/2 + 1/7 + x = 1  where x is the shaded area

Multiply each side by 14 to get rid of the fractions

14(1/2 + 1/7 + x) = 1*14

7 + 2 + 14x = 14

9+14x = 14

Subtract 9 from each side

14x = 5

Divide by 14

x = 5/14

The part that is shaded is 5/14

Answer:

  95°

Step-by-step explanation:

  ∠SRW is a vertical angle with respect to the one marked 95°. As such, it will have the same measure: 95°.

  m∠SRW = 95°

Answer:

Washington has 159 hits and Sanchez has 155 hits.

Step-by-step explanation:

First, divide 314 by 2 (the number of players), then add 2 for Washington and subtract 2 for Sanchez.

Answer:

The answer is

Step-by-step explanation:

To find the volume in liter we must first find the volume in cm³

Since the container is cubic

Volume = l³

where l is the length of one side

From the question

l = 50.0 cm

Volume = 50³

= 125000 cm³

Next we use the conversion

1cm³ = 0.001 L

If 1 cm³ = 0.001 L

Then 125,000 cm³ = 125,000 × 0.001 L

We have the final answer as

Hope this helps you

Using the volume of a cube, and conversion of units, it is found that the volume of the cube is of 125 liters.

---------------------

The volume of a cube of side s is given by:

[tex]V = s^3[/tex]

---------------------

Thus, the volume, in cubic centimetres, is given by:

[tex]V = 50^3 = 125000[/tex]

---------------------

Then:

[tex]\frac{125000}{1000} = 125[/tex]

The volume of the cube is of 125 liters.

A similar problem is given at https://brainly.com/question/23514867

The alternate interior angle theorem states that when two parallel lines are cut by a transversal, the resulting alternate interior angles are congruent.

This means that [tex]6x-8=5x+14[/tex]

[tex]x=22[/tex]

Hope this helps. 頑張って!

Answer:

2a(x + 3y)

Step-by-step explanation:

2ax + 6ay

factor out a 2a

2a(x + 3y)

Answer:

x =1.28571428571

Step-by-step explanation:

6x + 2y = -10

y = -4x - 8

6x + 2(4x - 8) = -10

6x + 8x - 8 = -10

14x - 8 = 10

(we put together the like terms)

14x = 10 + 8

14x = 18

x =  [tex]\frac{18}{14}[/tex]

x = 1.28571428571

Answer:

Step-by-step explanation:

x -  9 = 17

x = 26

the answer is D

Answer:

106 or 4x+18  

Step-by-step explanation:

Since Ray QR is a bisector you can determine that PRQ and QRS are equal angles (def. of a bisector). Then, what I chose to do is graph them and find where they intercept which was 22. We now know 22 is x so we can substitute it into the equation and solve to deterine that our answer is 106.

Answer:

a = [tex]\frac{11}{7}[/tex] ; b = [tex]\frac{6}{7}[/tex]

Step-by-step explanation:

[tex]\frac{3 + \sqrt{2}}{3 - \sqrt{2} } = a + b\sqrt{2} \\\\[/tex]

Rationalising [tex]\frac{3 + \sqrt{2}}{3 - \sqrt{2} }[/tex] gives :-

[tex]\frac{3 + \sqrt{2}}{3 - \sqrt{2} } = \frac{(3 + \sqrt{2})(3 + \sqrt{2})}{(3 - \sqrt{2})(3 + \sqrt{2}) } = \frac{(3 + \sqrt{2})^2}{3^2 - (\sqrt{2})^2 } = \frac{11 +6\sqrt{2} }{7}[/tex]

Comparing [tex]\frac{11 + 6\sqrt{2} }{7}[/tex] with [tex]a + b\sqrt{2}[/tex] gives

a = [tex]\frac{11}{7}[/tex] & b = [tex]\frac{6}{7}[/tex]

Answer:

[tex]\frac{11}{7}[/tex] + [tex]\frac{6}{7}[/tex] [tex]\sqrt{2}[/tex]

Step-by-step explanation:

Given

[tex]\frac{3+\sqrt{2} }{3-\sqrt{2} }[/tex]

Multiply the numerator/ denominator by the conjugate of the denominator.

The conjugate of 3 - [tex]\sqrt{2}[/tex] is 3 + [tex]\sqrt{2}[/tex] , thus

= [tex]\frac{(3+\sqrt{2})(3+\sqrt{2}) }{(3-\sqrt{2})(3+\sqrt{2}) }[/tex] ← expand numerator/ denominator using FOIL

= [tex]\frac{9+6\sqrt{2}+2 }{9-2}[/tex]

= [tex]\frac{11+6\sqrt{2} }{7}[/tex]

= [tex]\frac{11}{7}[/tex] + [tex]\frac{6}{7}[/tex] [tex]\sqrt{2}[/tex] ← in the form a + b[tex]\sqrt{2}[/tex]

with a = [tex]\frac{11}{7}[/tex] and b = [tex]\frac{6}{7}[/tex]

Answer:

A.    [tex] x > \dfrac{7}{3} [/tex]

Step-by-step explanation:

[tex] 8(\dfrac{1}{2} x - \dfrac{1}{4}) > 12 - 2x [/tex]

Distribute the 8 on the left side.

[tex] 4x - 2 > 12 - 2x [/tex]

Add 2x to both sides. Add 2 to both sides.

[tex] 6x > 14 [/tex]

Divide both sides by 6.

[tex] x > \dfrac{14}{6} [/tex]

Reduce 14/6 by dividing the numerator and denominator by 2.

[tex] x > \dfrac{7}{3} [/tex]

Answer:

V = πr²(h/3)

Step-by-step explanation:

83.74 = πr²(5/3)

R = 4.00 in

Diamater = 2r = 2 x 4.00 = 8 inches

Answer:

i can't see that

Step-by-step explanation:

plzz sent me a clear photo

Answer:

1. 1

2. 1  ⋅  10 ^24

3. 1000000000

4. 1

5. 1  ⋅  10 ^20

6. 1  ⋅  10 ^30

7. 1  ⋅  10 ^27

8. 10000

9. 0.01

10. 0.0001

11. 0.1

Hopefully these are right, I simplified all of the problems...sorry if they are wrong

Step-by-step explanation:

Answer:

see the work pictured please

Answer: x=22

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

Step 2: Add 9/2 to both sides.

Step 3: Multiply both sides by 4/3.

Answer:

I think its 0.89

Step-by-step explanation:

Answer:

1,3,5,15

1,2,11,22

1,2,17,34

1,3,5,9,15,45

1,2,5,10,25,50

Step-by-step explanation:

Hope it will help u

Answer:

A) 2.45 seconds

B)[tex]\begin{center}\begin{tabular}{ c c}\bold{Average Velocity} & \bold{Velocity at strike of water} \\ 39.18 & 78.4 \\ \end{tabular}\end{center}[/tex]

Step-by-step explanation:

Distance [tex]s[/tex] (in feet) from the top of cliff after [tex]t[/tex] seconds when a rock is dropped off the edge of a cliff is given as:

[tex]s(t)=16t^2[/tex]

Distance from the top of cliff to water = 96 ft

To find:

A) When will the rock strike the water

i.e. The time taken by the rock to travel the distance of 96 ft.

B) Table of Average Velocity and approximate velocity at which the rock strikes the water ?

Solution:

A) Given that distance traveled = 96 ft

To find the value of [tex]t[/tex]

Putting the value of [tex]s[/tex] in formula: [tex]s(t)=16t^2[/tex] to find [tex]t[/tex]:

[tex]96 = 16t^2\\\Rightarrow t^2=6\\\Rightarrow \bold{t = 2.45\ sec}[/tex]

B) The velocity at which the rock hits the water:

We need to differentiate [tex]s(t)[/tex] w.r.to [tex]t[/tex] in order to find the velocity at any instant.

[tex]s'(t) =\dfrac{d}{dt}s(t) = \dfrac{d}{dt}(16t^2)\\\Rightarrow v = 2\times 16t^{(2-1)}\\\Rightarrow v = 32t[/tex]

The time taken to reach the water is 2.45 seconds.

Putting [tex]t[/tex] = 2.45 seconds to find the velocity:

[tex]v = 32\times 2.45 = 78.4\ ft/sec[/tex]

Average velocity is given as total distance traveled and total time taken.

[tex]\text{Average Velocity = }\dfrac{\text{Total Distance traveled}}{\text{Total Time Taken}}[/tex]

[tex]\text{Average Velocity = }\dfrac{96}{2.45}\\\text{Average Velocity = 39.18\ ft/s}[/tex]

[tex]\begin{center}\begin{tabular}{ c c}\bold{Average Velocity} & \bold{Velocity at strike of water} \\ 39.18 & 78.4 \\ \end{tabular}\end{center}[/tex]

Answer:

[tex] \huge{ \fbox{ \sf{7x - 20}}}[/tex]

Step-by-step explanation:

[tex] \star{ \sf{ \: 5(3x - 4) - 8x}}[/tex]

[tex] \text{Step \: 1 \: : Distribute \: 5 \: through \: the \: parentheses}[/tex]

[tex] \mapsto{ \sf{5 \times 3x - 5 \times 4 - 8x}}[/tex]

[tex] \mapsto{ \sf{15x - 20 - 8x}}[/tex]

[tex] \text{Step \: 2 \: : Collect \: like \: terms}[/tex]

[tex] \sf{Like \: terms \: are \: those \: which \: have \: the \: same \: base.}[/tex]

[tex] \mapsto{ \sf{15x - 8x - 20}}[/tex]

[tex] \mapsto{ \boxed{\sf{7x - 20}}}[/tex]

[tex] \sf{Hope \: i \: helped!}[/tex]

[tex] \sf{Best \: regards!!}[/tex]

~[tex] \rm{TheAnimeGirl}[/tex]

Answer:

jacki did not subtract 8 minus 12 properly.8 minus 12 equals -4

Answer:

its c

Step-by-step explanation:

on edunuity

Answer:

9y+18

Step-by-step explanation:

Distribute the 9 to the terms in the parentheses.

9(y)+9(2)

9y+18

Answer:

the answer is -12-(-3)

Step-by-step explanation:

The expression equivalent to -18-(-9) is -12-(-3)

An expression in maths is a sentence with a minimum of two numbers or variables and at least one maths operation.

Given is an expression, -18-(-9), we are given to find the expression equivalent to it,

-18-(-9) = -18+9 = -9

1) -18+2 = -16 (not equivalent)

2) -12-(-3) = -12+3 = -9

Therefore, we see, the value of expressions -12-(-3) and -18-(-9) are equivalent,

Hence, the expression equivalent to -18-(-9) is -12-(-3)

For more references on expressions, click;

https://brainly.com/question/14083225

#SPJ2

Answer:

Distributive property

Step-by-step explanation:

2(x+4)

We can write it as:-

=>2(x)+2(4)

=>2x+8

Answer:

the awnser is c the distributive proporties

Step-by-step explanation:

Answer:

Look below

Step-by-step explanation:

1) x = 14, because 14 * 14 = 196

2) x = 3 / 16, because ( 3 / 16 ) * ( 3 / 16 ) = 9 / 256

3) x = 8, because 8 * 8 * 8 = 512

4) x = 4 / 7, because ( 4 / 7 ) * ( 4 / 7 ) * ( 4 / 7 ) = 64 / 343

[tex]( {5}^{2} - 1) \div 6 = [/tex]

[tex](25 - 1) \div 6 = [/tex]

[tex]24 \div 6 = 4[/tex]

Note:

Do the square first, and then you do mathematic operation between the parentheses. And, then do the

mathematic operation in the outside of parentheses.

Thank you.

Answer:

Step-by-step explanation:

[tex]\left(5^2-1\right)\div \:6\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(5^2-1\right)\::\quad 24\\=24\div \:6\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:24\div \:6\:\\:\quad 4[/tex]

Answer:

$1615.05

Step-by-step explanation:

First the cost. We know that tuition per credit hour is 113.67 and there is a flat fee of 660. This can be represented by 113.67h + 660, where h is equal to the number of credit hours.

Next, the amount paid. There are two constants of 350 and 400 already there. We can represent the remaining amount that needs to be paid by another variable, x.

Now, the cost needs to be equal to the amount you pay. We can replace h with 15 for 15 hours and solve for x.

113.67h + 660 = 350 + 400 + x

113.67(15) + 660 = 350 + 400 + x

1705.05 + 660 = 750 + x

2365.05 = 750 + x

1615.05 = x

Answer:

90

Step-by-step explanation:

15*6=90...

Answer:

its a distributive property..

Answer:

algebraic equation is an equation of the form