A person swims 11 miles downstream in the same time they can swim 7 miles up stream. The speed of the current is 4 miles per hour.
These situations can be represented by the equations
Downstream: t=11/s+4 Upstream:t=7/s-4,
where t stands for time and s is the speed of the swimmer. What is the speed of the swimmer swimming in still water?

Answers

Answer 1

Answer:

s = 18 mph

Step-by-step explanation:

At downstream, time is; t = 11/(s+ 4)

At upstream, time is; t = 7/(s - 4)

Since they both are passed in the same time, then ;

11/(s+ 4) = 7/(s - 4)

Cross Multiply to get;

11(s - 4) = 7(s + 4)

11s - 44 = 7s + 28

11s - 7s = 44 + 28

4s = 72

s = 72/4

s = 18


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[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{3x = 9}[/tex]

[tex]\large\text{DIVIDE 3 to BOTH SIDES}[/tex]

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[tex]\large\text{New equation: x = } \dfrac{9}{3}[/tex]

[tex]\mathsf{\dfrac{9}{3} = \bf 3}[/tex]

[tex]\boxed{\boxed{\large\textsf{Therefore, your \underline{answer} is: \huge \bf x = 3 }}}\huge\checkmark[/tex]

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~[tex]\frak{Amphitrite1040:)}[/tex]

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