Answer:
The rope is stretched by 0.3373 cm
Explanation:
As we know
Youngs Modulus ([tex]5.0 * 10^9[/tex] N/m2) is Stress divided by strain
Stress = force/Area = (65*9.8)/(pi * (7.3*10^-3)^2)
Starin = change in length/original length of the rope = l/12 meters
Substituting the given values we get
[tex]5.0 * 10^9[/tex] N/m2 = {([tex]\frac{\frac{24*9.8}{\pi *(7.3*10^{-3})^2} }{\frac{\delta L}{L} }[/tex])
[tex]5.0 * 10^9[/tex] N/m2 = {([tex]\frac{\frac{24*9.8}{\pi *(7.3*10^{-3})^2} }{\frac{\delta L}{12} }[/tex])
[tex]\frac{\delta L}{12} = \frac{\frac{65*9.8}{pi * (7.3*10^-3)^2} }{5.0 * 10^9}[/tex]
The rope is stretched by 0.3373 cm
what's the temperature 32°F in degrees Celsius
Answer:
0 degrees Celsius
Explanation:
plz help.me guys
6xy – 12x y + 15x3y? – 3x?y? by 3x²y
Answer:
2xy-12xy+15x3y?-3x?y?by3l 3x2y
A soccer ball with mass 0.450 kg is initially moving with speed 2.20 m/s. A soccer player kicks the ball, exerting a constant force of magnitude 38.0 N in the same direction as the ball's motion. Over what distance must her foot be in contact with the ball to increase the ball's speed to 6.00m/s?
Answer:
0.187 m
Explanation:
We'll begin by calculating the acceleration of the ball. This can be obtained as follow:
Mass (m) = 0.450 Kg
Force (F) = 38 N
Acceleration (a) =?
F = m × a
38 = 0.450 × a
Divide both side by 0.450
a = 38 / 0.450
a = 84.44 m/s²
Finally, we shall determine the distance. This can be obtained as follow:
Initial velocity (u) = 2.20 m/s.
Final velocity (v) = 6 m/s
Acceleration (a) = 84.44 m/s²
Distance (s) =?
v² = u² + 2as
6² = 2.2² + (2 × 84.44 × s)
36 = 4.4 + 168.88s
Collect like terms
36 – 4.84 = 168.88s
31.52 = 168.88s
Divide both side by 168.88
s = 31.52 / 168.88
s = 0.187 m
Thus, the distance is 0.187 m
P Flag question
Matt, shown below, is able to move
the large truck because
what heat transfer occurs when warm air rises
4. A girl sits on a tire that is attached to a tree limb by a rope 2.10 m in length. The girl's father pushes her with a tangential speed of 2.50 m/s. If the magnitude of the force that maintains her is 88.0 N, What is the girl's mass? Predictions On JOT 自 DLL Fa F11
Answer:
the answer is M=29.6kg
Explanation:
your welcome:)
What is this answer? A blank is a combination of two or more substances, elements, compounds, or both, in the same place but not chemically combined
A playground merry-go-round has a mass of 120 kg and a radius of 1.80 m and it is rotating with an angular velocity of 0.400 rev/s. What is its angular velocity (in rev/s) after a 22.0 kg child gets onto it by grabbing its outer edge
Answer:
The final angular velocity is rev/s is 0.293 rev/s.
Explanation:
Given;
mass of the merry-go-round, m₁ = 120 kg
radius of the merry-go-round, r = 1.8 m
initial angular velocity, ω = 0.4 rev/s
mass of the child, m₂ = 22 kg
Apply the principle of conservation angular momentum to determine the final angular velocity;
[tex]I_i= I_f\\\\\frac{1}{2} m_1r^2 \omega _i = \frac{1}{2} m_1r^2 \omega _f + m_2r^2 \omega _f\\\\ \frac{1}{2} m_1r^2 \omega _i =( \frac{1}{2} m_1r^2 + m_2r^2 )\omega _f\\\\\omega _f = \frac{ \frac{1}{2} m_1r^2 \omega _i}{\frac{1}{2} m_1r^2 + m_2r^2} \\\\\omega _f = \frac{ \frac{1}{2} m_1 \omega _i}{\frac{1}{2} m_1 + m_2}\\\\\omega _f = \frac{0.5 \ \times \ 120\ kg \ \times \ 0.4\ rev/s}{0.5 \ \times 120\ kg \ \ + \ \ 22 \ kg} \\\\\omega _f = 0.293 \ rev/s\\[/tex]
Therefore, the final angular velocity is rev/s is 0.293 rev/s.
3
Explain the working principles
of 아
has/ Constant volume
thermometer
a gas
Answer:
A constant volume gas thermometer works on a thermometric property of " change in pressure with temperature at a constant volume"
Your ear is capable of differentiating sounds that arrive at each ear just 0.34 ms apart, which is useful in determining where low frequency sound is originating from. (a) Suppose a low-frequency sound source is placed to the right of a person, whose ears are approximately 18 cm apart, and the speed of sound generated is 340 m/s. How long is the interval between when the sound arrives at the right ear and the sound arrives at the left ear
Answer:
Δt = 5.29 x 10⁻⁴ s = 0.529 ms
Explanation:
The simple formula of the distance covered in uniform motion can be used to find the interval between when the sound arrives at the right ear and the sound arrives at the left ear.
[tex]\Delta s = v\Delta t\\\\\Delta t = \frac{\Delta s}{v}[/tex]
where,
Δt = required time interval = ?
Δs = distance between ears = 18 cm = 0.18 m
v = speed of sound = 340 m/s
Therefore,
[tex]\Delta t = \frac{0.18\ m}{340\ m/s}[/tex]
Δt = 5.29 x 10⁻⁴ s = 0.529 ms
Which of the following is an example
of a measure of the
mass of an object?
A. 65 centimeters
B. 65 grams
C. 65 light-years
D. 65 feet
Answer:
Grams
Explanation:
Because that is the definition
Answer:
65 grams
Explanation:
What is the answer to this problem
Answer:
Material that allow the electrons to move freely in order to produce a current
Please mark as brainliest if answer is right
Have a great day, be safe and healthy
Thank u
XD
What happens when sulfur reacts with potassium?
O A. Electrons move from the sulfur atoms to the potassium atoms.
B. Electrons become delocalized among the atoms.
O C. Electrons are shared between the potassium atoms and the sulfur
atoms.
O D. Electrons move from the potassium atoms to the sulfur atoms.
Answer: Electrons move from the potassium atoms to the sulfur atoms.
Explanation: 2 K + S ⇒ 2 K^+ + S^2- . Usually metals donor electrons to non-metals
what is the best structure for a egg dropping project you will be name brainiest
Answer:
bubble wrap in stuff animal
Explanation:
did it
Answer:
i would say putting like pillows around it i had to do it once and i won like that so
Explanation:
Please please help me please please help
Answer:
Materials like air, water, and clear glass are called transparent. When light encounters transparent materials, almost all of it passes directly through them. ... When light strikes translucent materials, only some of the light passes through them. The light does not pass directly through the materials.
Explanation:
180 J of work is done when lifting a box up to a shelf that is 3 m high. What is the mass of the box?
Explanation:
Work done= MGH
180=m×10×3
180/30=m
m=6kg
What is the light speed formula?
If ' c ' is the speed of light, then the formula for it is . . .
c = 299,792,458 meters per second
A ____________ galaxy has arms of gas and dust; where as _____________ galaxy is a category of galaxy that does not have a distinctive shape.
Question 1 options:
elliptical, an elliptical
irregular, a barred-spiral
bar, a spiral
spiral, an irregular
Answer:
spiral, an irregular
Explanation:
i took the test :)
A flat circular coil of wire having 400 turns and diameter 6.0 cm carries a current of 7.0 A. It is placed in a magnetic field of with the plane of the coil making an angle of 30° with the magnetic field. What is the magnitude of the magnetic torque on the coil?
Answer:
6.8 N.m
Explanation:
The computation of the magnitude of the magnetic torque on the coil is given below:
Given that
n = 400
d = 6.0 cm
Current is I = 7.0 A
Angle is [tex]\theta[/tex] = 30 degree
Now
We know that
the magnitude of the magnetic torque is
= nIABsin[tex]\theta[/tex]
= (400) (7.0) π ÷ 4 (0.06m)^2 sin(90° - 30°)
As
[tex]\theta[/tex] = (90° - Ф)
= (400) (7.0) π ÷ 4 (0.06m)^2 sin 60°
= 6.8 N.m
The botanist from the nursery is planning to develop a large number of new spider plants with larger flowers. Identify the type of reproduction the botanist should use to develop the new spider plants and explain why this type of reproduction is preferable.
Answer:
Sexual reproduction.
Explanation:
Reproduction can be defined as a biological process which typically involves living organisms producing an offspring.
Basically, there are two (2) methods of reproduction and these are;
I. Asexual reproduction: it involves the cloning of a living organism to produce an offspring because there is only a single parent.
II. Sexual reproduction: it involves the combination of the genome (gamete) of a male and female living organism during fertilization.
In this scenario, the botanist from the nursery plans to develop a large number of new spider plants that has larger flowers. Thus, the type of reproduction the botanist should use to develop the new spider plants is sexual reproduction because it would help the parent plant reproduce offsprings with different traits such as spider plants with large flowers. Also, the botanist should use sexual reproduction rather than asexual reproduction because asexual reproduction will only make the parent plant reproduce that have the same type of traits as themselves.
A self-driving car traveling along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed of 25.0 m/s. Then the vehicle travels for 39.0 s at constant speed until the brakes are applied, stopping the vehicle in a uniform manner in an additional 5.00 s.
(a) How long is the self-driving car in motion (in s)?
(b) What is the average velocity of the self-driving car for the motion described? (Enter the magnitude in m/s.) m/s
Answer:
[tex]56.5\ \text{s}[/tex]
[tex]21.13\ \text{m/s}[/tex]
Explanation:
v = Final velocity
u = Initial velocity
a = Acceleration
t = Time
s = Displacement
Here the kinematic equations of motion are used
[tex]v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{25-0}{2}\\\Rightarrow t=12.5\ \text{s}[/tex]
Time the car is at constant velocity is 39 s
Time the car is decelerating is 5 s
Total time the car is in motion is [tex]12.5+39+5=56.5\ \text{s}[/tex]
Distance traveled
[tex]v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{25^2-0}{2\times 2}\\\Rightarrow s=156.25\ \text{m}[/tex]
[tex]s=vt\\\Rightarrow s=25\times 39\\\Rightarrow s=975\ \text{m}[/tex]
[tex]v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{0-25}{5}\\\Rightarrow a=-5\ \text{m/s}^2[/tex]
[tex]s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0-25^2}{2\times -5}\\\Rightarrow s=62.5\ \text{m}[/tex]
The total displacement of the car is [tex]156.25+975+62.5=1193.75\ \text{m}[/tex]
Average velocity is given by
[tex]\dfrac{\text{Total displacement}}{\text{Total time}}=\dfrac{1193.75}{56.5}=21.13\ \text{m/s}[/tex]
The average velocity of the car is [tex]21.13\ \text{m/s}[/tex].
HELP PLEASEEEEEEEEEEEE
P Flag question
Matt, shown below, is able to move
the large truck because
Answer:
he has more pushing force than the truck there for pushing it forword.
Explanation:
Which statement did John Dalton make about atoms?
A. there are distinct kinds of atoms
B. the atom is made up of smaller particles
C. the atom has a small, dense center
D. the energy of an electron depends on its specific orbit
Answer:
B
Explanation:
Atoms are made by electrons, neutrons and protons
Answer:
A. there are distinct kinds of atoms
Explanation:
According to Dalton's atomic theory, the atom is indivisible. Thus, we know that B is incorrect. Additionally, C can't be correct because when Dalton was alive, the nucleus (the small, dense center) hadn't yet been discovered. Finally, D can't be correct either since Bohr's discoveries about electron orbits hadn't yet been made. Knowing that, it must be A!
Also, I just did the quiz, and it was A. Dalton believed that there are distinct kinds of atoms!
If a magnet can cut into a small piece , each piece will remain a magnet ? Explain this phenomenon
yes ,each piece will remain a magnet because the small pieces will cut into north and south
What is the correct calculation for voltage if the resistance is 3 ohms and the current is 4 amps?
3 x 4 = 12 volts
3 + 4 = 7 volts
4= 3 = 1.33 volts
4-3 = 1 volt
Answer:
iek
Explanation:
Answer:
the answer to your questions above is 3 x 4 = 12 volts
Explanation:
Voltage = Current × Resistance
What is the length of a string with a mass of 2.5 kg, with a
tension of 20 N, if the speed of wave on the string is 2 m/s?
a 0.8 m
b 0.4 m
C 0.5 m
d 1.0 m
e 0.1 m
A force is described as?
Explanation:
A push or pull of an objecr
[tex]\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}[/tex]
A force is described as push or pull on an object.
ThanksHope it helps.During a football game player A (mass 120kg velocity 5.5m/s [L]) tackles and grabs player B (mass 105kg velocity 7.9m/s [R]). What is the final speed of the two players immediately after the collision?
Answer:
6.62m/s
Explanation:
Given data
M1= 120kg
U1= 5.5m/s
M2= 105kg
U2= 7.9m/s
The system experiences an inelastic collision, the expression for inelastic collision is
M1U1+ M2U1= (M1+M2)V
Subsitute
120*5.5+ 105*7.9= (120+105)*V
660+ 829.5= (225)*V
1489.5= (225)*V
Divide both sides by 225
V= 1489.5/225
V= 6.62m/s
Hence the common velocity is 6.62m/s
how does light travel across the universe to earth?