A normal distribution has a mean u = 15.2 and a standard deviation of o = 0.9. Find the probability that a score is greater than 16.1

Answers

Answer 1

The required probability is 0.8413.

Given data:

Mean (μ) = 15.2

Standard deviation (σ) = 0.9

We need to find the probability that a score is greater than 16.

1.Using the formula of z-score: z = (X - μ) / σ

Where X is the score, μ is the mean, and σ is the standard deviation.

Putting the given values in the formula:

z = (16.1 - 15.2) / 0.9z = 1

Solving z-table for the probability that a score is greater than 16.1:

Using the z-table:

The z-table gives the probability corresponding to the z-score.

The given z-score is 1 and the probability corresponding to it is 0.8413.

So, the probability that a score is greater than 16.1 is 0.8413 (approx).

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Related Questions

How much money would produce $70 as simple interest at 3.5% per
annum?

Answers

Answer:

$2000

Step-by-step explanation:

Simple Interest = $70

Rate = 3.5%

Time = 1

Principal = ?

Simple Interest = (Principal × Rate × Time)/100

Principal = (Simple Interest × 100)/(Rate × Time)

Principal = (70 × 100)/(3.5 × 1)

Principal = 7000/3.5

Principal = 14000/7

Principal = 2000

Help!! please. will mark brainstest​

Answers

Answer:(1,0)

Step-by-step explanation:

y=mx+b
y=4/2x+1
Or simplify
y=2x+1

Just help me please?!?!?!

Answers

Answer:

the last one

Step-by-step explanation:

Which of the following is a
representation of 11!

Answers

I’m sorry I don’t know the answer I’m just trying to get enough questions to pass my final

How many different ways can you have 55¢ in change using only quarters, dimes and nickels?

A. 1
B. 5
C. 11
D. 15

Answers

Answer: 11 times

Step-by-step explanation:

Have a wonderful day!

C 11 times. Hope this helps

Can someone please help!!!
Ill give brainliest!!

Answers

Answer:

please what is the exact question

Answer:

161.56 ft^2

Step-by-step explanation:

base area = (leg 1 x leg 2)/2 = (5 x 5)/2 = 25/2 = 12.5 ft^2

base perimeter = 5 + 5 + 7.07 = 17.07 ft

lateral surface = (perimeter x height) = 17.07 x 8 = 136.56 ft^2

surface area = base area x 2 + lateral surface = (12.5 x 2) + 136.56 = 161.56 ft^2

A square ceiling has a diagonal of 23 ft. Shelton wants to put
molding around the perimeter of the ceiling. The molding is sold
by the foot
What is the minimum amount of molding he needs?

66 ft
l65 ft
17 ft
16 ft

Answers

66ft is the answer :))))

Answer:

66ft

Step-by-step explanation:

I took the quiz

Solve: 4x^2 = 32 thanks

Answers

Answer:

D.

Step-by-step explanation:

It is difficult to describe, but you just need to follow through the steps acorddingly.

Which logarithmic equation correctly rewrites this exponential equation?

Answers

Answer:

A. [tex] log_{8}(64) = x[/tex]

Step-by-step explanation:

[tex] {8}^{x} = 64 \\ \\ \implies log_{8}(64) = x[/tex]

What is the area of this tile

Answers

Answer:

12 in^2

Step-by-step explanation:

Answer: 12in^2

Step-by-step explanation:

Jared gets 10 heads when flipping a weighted coin 12 times. Based on experimental probability, how many of the next six flip should Jared expect to come up heads?

Answers

Answer:

5

Step-by-step explanation:

Experimental probability = number of tunes an event occurred / total number of trials

Experimental probability of getting head :

10 /12 = 0.833333

Expected number of heads from next 6 flips :

Experimental probability = expected number of heads / number of trials

0.833333 = x / 6

0.83333 * 6 = 5

5 times

Find the perimeter of 13.2 yd, 6.2 yd, 11yd

Answers

Answer: 900.24

Step-by-step explanation:

Perimeter=L•W•H

How would I do this??

Answers

There on opposite sides of the transversal and there inside the two lines crossed by the transversal.

regression analysis was applied and the least squares regression line was found to be ŷ = 400 3x. what would the residual be for an observed value of (2, 402)?

Answers

The Residual for an observed value of (2, 402) is -4.

The regression analysis and the least squares regression line was found to be ŷ = 400 3x.

The observed value is (2, 402).To find the residual for an observed value of (2, 402),

we need to use the formula for residual

Residual = Observed value - Predicted value

where Observed value = (2, 402) , Predicted value = ŷ = 400 + 3x , Putting x = 2 in the above equation

we get,

ŷ = 400 + 3(2) = 406

Now, Residual = Observed value - Predicted value= 402 - 406= -4

Therefore, the residual for an observed value of (2, 402) is -4.

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I need help please

What is the area?

____ Square millimeters

Answers

the area is 210 square millimeters

Ms. Clark spent $89.85 on sewing kits that cost $5 each plus $4.85 tax on the total bill. How many kits did she buy?

Answers

The sewing kits bought by Ms, Clark is 17 in number.

What are equation models?

The equation model is defined as the model of the given situation in the form of an equation using variables and constants.

Here,

As given in the question, Ms. Clark spent $89.85 on sewing kits that cost $5 each plus $4.85 tax on the total bill.


Let the number of sewing kits be x,
According to the question,
5x + 4.85 = 89.85
5x = 89.85 - 4.85
5x = 85
x = 17

Thus, the sewing kits bought by Ms, Clark is 17 in number.

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Exercise 1.5.9 Let R be an n x n upper-triangular matrix with semiband width s. Show that the system Rx = y can be solved by back substitution in about 2ns flops. An analogous result holds for lower-triangular systems.

Answers

The total number of flops required to solve the system is approximately 2ns.

Let R be an n x n upper-triangular matrix with semiband width s. Show that the system Rx = y can be solved by back substitution in about 2ns flops. An analogous result holds for lower-triangular systems.Back substitution is an efficient technique for solving systems of linear equations in matrix form.

This is because back substitution only works on upper- or lower-triangular matrices, which have certain features that make solving systems of equations easier.The back substitution algorithm starts by solving the first equation of the system and obtaining a solution for the first variable. It then uses this value to solve the second equation and obtain a solution for the second variable.

This process is continued until all the variables are solved for.Let R be an n x n upper-triangular matrix with semiband width s. The semiband width of a matrix is the maximum number of nonzero entries in any row or column of the matrix. This means that all entries below the diagonal of R are zero. Let y be a vector of length n.

We want to solve the system Rx = y using back substitution.Since R is upper-triangular, we can solve for the last variable x_n first. This only requires one multiplication and one subtraction. We can then use the value of x_n to solve for the second-to-last variable x_{n-1}, which requires two multiplications and two subtractions.

Continuing in this way, we can solve for all the variables x_1, x_2, ..., x_n, each time requiring one more multiplication and subtraction than the previous step.In total, the number of flops required to solve the system Rx = y using back substitution is approximately 1 + 2 + 3 + ... + n, which is equal to n(n+1)/2.

Since R has semiband width s, this means that each row of R has at most s nonzero entries, so each variable requires at most s multiplications and s-1 subtractions.

Therefore, the total number of flops required to solve the system is approximately 2ns.

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Find the GCF of the monomials: 18x² and 21x²y
A)3x
B)3x²
C)3xy
D)3x²y
PLEASE HELP MEEE

Answers

It’s b because they both have x squared and are both divisible by 3

On a coordinate grid, a scale drawing of a banner is shaped like a parallelogram with verticals at (-15,10), (0,-5), (30,-5), and (15,10. Each square on the grid represents 1 square inch. What is the area of the banner?

Answers

The area of the banner is 562.5 square units.

To calculate the area of the banner, we can divide it into two triangles and then find the sum of their areas.

First, let's calculate the base and height of each triangle:

Triangle 1: Vertices (-15,10), (0,-5), and (30,-5)

The base of Triangle 1 is the distance between (-15,10) and (30,-5), which is 30 - (-15) = 45 units.

The height of Triangle 1 is the distance between (-15,10) and (0,-5), which is 10 - (-5) = 15 units.

Triangle 2: Vertices (0,-5), (30,-5), and (15,10)

The base of Triangle 2 is the distance between (0,-5) and (15,10), which is 15 units.

The height of Triangle 2 is the distance between (0,-5) and (30,-5), which is 30 - 0 = 30 units.

Now, let's calculate the area of each triangle using the formula for the area of a triangle: Area = (base * height) / 2.

Area of Triangle 1 = (45 units * 15 units) / 2 = 337.5 square units

Area of Triangle 2 = (15 units * 30 units) / 2 = 225 square units

Finally, to find the total area of the banner, we sum the areas of the two triangles:

Total Area = Area of Triangle 1 + Area of Triangle 2

Total Area = 337.5 square units + 225 square units

Total Area = 562.5 square units

Therefore, the area of the banner is 562.5 square units.

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How do I write [tex]\sqrt[4]{5}[/tex] using rational exponets?

Answers

This the answer 5^1/4

Hope this help

Answer:

y=45u

Step-by-step explanation:

4 with a 5 try adding / bc its supposed to be like a check sin

The augmented matrix of a system of linear equations AX = B was reduced to upper-triangular form so that 2 1 0 1 2 [AB] 0 -1 31 0 0 mln where m and n are real numbers. State all values of m and/or n such that the following statements are true. (a) Matrix A is invertible. (b) The system AX = B has no solutions. (c) The system AX = B has an infinite number of solutions. (d) Columns of the augmented matrix (AB) are linearly independent. (e) The system AX = 0 has a unique solution. (f) At least one eigenvalue of the matrix A is zero. (g) Columns of the matrix A form a basis in R3.

Answers

a. Matrix A is invertible when |A| = -m ≠ 0 then statement true.

b. The system AX = B has no solution when m = 0 and n ≠ 0 has a real number then statement true.

c. The system AX = B has an infinite number of solutions when m = n = 0 then statement true.

d. Columns of the augmented matrix (AB) are linearly independent when m ≠ 0 and n= 0 then statement true.

e. The system AX = 0 has a unique solution when m ≠ 0 then statement true.

f. At least one eigenvalue of the matrix A is zero when m = 0 then statement true.

g. Columns of the matrix A form a basis in R³ when m ≠ 0 then statement true.

Given that,

The augmented matrix of a system of linear equations AX = B was reduced to upper-triangular form so that

[A|B] = [tex]\left[\begin{array}{ccc}2&1&0 \ | \ 2\\0&-1&3 \ | \ 1 \\0&0&m \ | \ n\end{array}\right][/tex]

Where m and n are real numbers.

We know that,

a. We have to prove matrix A is invertible.

For A to be invertible.

|A| ≠ 0

|A| is the determinant of the matrix A.

|A| = 2(-m) -1(0) + 0(0) = -m

Here, m is the real number.

So, |A| = -m ≠ 0

Therefore, Matrix A is invertible when |A| = -m ≠ 0 then statement true.

b. We have to prove the system AX = B has no solution.

When Rank[A|B] > Rank[A]

m = 0 and n ≠ 0 has a real number

Therefore, The system AX = B has no solution when m = 0 and n ≠ 0 has a real number then statement true.

c. We have to prove the system AX = B has an infinite number of solutions.

When m = n = 0, and Rank[A] < 3

Therefore, The system AX = B has an infinite number of solutions when m = n = 0 then statement true.

d. We have to prove columns of the augmented matrix (AB) are linearly independent.

When m ≠ 0 and m∈R and n= 0

Therefore, Columns of the augmented matrix (AB) are linearly independent when m ≠ 0 and n= 0 then statement true.

e. We have to prove the system AX = 0 has a unique solution.

When [tex]\left[\begin{array}{ccc}2&1&0 \\0&-1&3 \\0&0&m \end{array}\right]\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}0\\0\\0\end{array}\right][/tex]

The equation are 2x + y = 0, -y + 3z = 0 and mz = 0

m ≠ 0 should be any real number except zero.

Therefore, The system AX = 0 has a unique solution when m ≠ 0 then statement true.

f. We have to prove at least one eigenvalue of the matrix A is zero.

When λ = 2, 1, m

m = 0 then eigen value is zero

Therefore, At least one eigenvalue of the matrix A is zero when m = 0 then statement true.

g. We have to prove columns of the matrix A form a basis in R³.

When m ≠ 0

Therefore, Columns of the matrix A form a basis in R³ when m ≠ 0 then statement true.

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The list below shows the number of miles Chris rode his bike on each of nine consecutive days. 9, 3, 1, 4, 8, 2, 6, 8, 5
Read the questions and write your answer for each part. Make sure to label each part: Part A, Part B and Part C. Write your answers in complete sentences.
Part A: Create a box-and-whisker plot with the above data. You may use the snipping tool to use the number line shown, or you may use a different number line. Upload your box-and-whisker plot using the "insert" or "+" option.
Part B: How far does Chris need to ride on the 10th day to have a mean distance of 6 miles? Show or explain your work.
Part C: On the 10th day, if Chris rides 20 miles, how will this change the mean?

Answers

A box-and-whisker plot needs to be created. To have a mean distance of 6 miles on the 10th day, Chris needs to ride a specific distance. If Chris rides 20 miles on the 10th day, it will change the mean distance.

Part A: To create a box-and-whisker plot, we need to arrange the given data in ascending order: 1, 2, 3, 4, 5, 6, 8, 8, 9. The plot will consist of a box representing the interquartile range (from the first quartile to the third quartile), a line within the box representing the median, and whiskers extending to the minimum and maximum values (excluding outliers if any).

Part B: To determine how far Chris needs to ride on the 10th day to have a mean distance of 6 miles, we need to consider the current total sum of distances and the total number of days. By calculating the difference between the desired mean and the current mean, we can determine the additional distance Chris needs to ride on the 10th day.

Part C: If Chris rides 20 miles on the 10th day, it will change the mean distance. The extent of the change in the mean depends on the initial data. To calculate the new mean, we need to include the additional distance (20 miles) and recalculate the mean using the updated total sum of distances and the total number of days.

Note: Without knowing the total number of days and the current sum of distances, precise calculations for Parts B and C cannot be provided.

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Determine a series of transformations that would map Figure C onto Figure D plz help asap

Answers

Answer:

Rotation about 180*

Translation about 7 units to the right and 8 down

Step-by-step explanation:

plssss help

answer it plssssssssss​

Answers

k= 28/5
yeah yeah yeah

Let : R² R2 given by (r,0) = (r cos(0), r sin(0)), 0≤ r ≤ R, 0≤0 ≤ 2m (this is a disk of radius R centered at (0,0)). Compute ∫ fdx .

Answers

To compute the integral ∫ fdx over the disk D of radius R centered at (0,0), we need to express the function f in terms of the given coordinate transformation.

In polar coordinates, a point (r, θ) in the disk D can be represented as (r cos(θ), r sin(θ)).

Now, let's substitute these polar coordinates into the integral. The differential element dx becomes r cos(θ)dr, and the integral becomes:

∫ fdx = ∫ f(r cos(θ), r sin(θ)) r cos(θ)dr dθ

We can now evaluate this integral by integrating over the range of r and θ. The range for r is from 0 to R, and the range for θ is from 0 to 2π (since we are integrating over the entire disk).

Thus, the integral becomes:

∫ fdx = ∫[0 to R] ∫[0 to 2π] f(r cos(θ), r sin(θ)) r cos(θ)dr dθ

By evaluating this double integral, we can find the value of ∫ fdx over the given disk D.

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help please! i dont understand how i'm supposed to fill the table if i dont have all the information

Answers

Use the ticket price in the first column in the formula 400-7p to get the answer for the second column (number of tickets sold)

Then multiple the number to f tickets in the second column by the price in the first to determine the revenue.

Surface areas 98 Find the shaded area. Round to the nearest tenth if necessary. 22 mm 18 mm 9 mm​

Answers

Answer:

297 sq mm

Step-by-step explanation:

Area of Rectangle: 22 x 18 = 396

Area of Triangle:  (1/2)(22)(9) = 99

Area of Rectangle - Area of Triangle = Area of Shaded area

396 - 99 = 297

The roots of 3x2 + x = 14 are
1. imaginary
2. real,rational,equal
3.real,rational,unequal
4.real,irrational,unequal

Answers

Answer:

3

Step-by-step explanation:

3x2 +x −14 = 0 12 −4(3)(−14) = 1+168 =169 = 132

The roots of 3x² + x = 14 are real, irrational and unequal

What is Quadratic equation?

A quadratic equation is a second-order polynomial equation in a single variable x, ax² + bx +c=0 with a ≠ 0 .

Given equation is :

3x² + x = 14

3x² + x - 14=0

we have, a=3, b=1 c=-14

D= b²-4ac

  = 1²-4*3*(-14)

  = 1+168

  = 169

As, D>0

Hence, the roots are real.

Now,

x= -b±√b²-4ac/2a

 = -1±√169/2*3

 =-1±13/6

x= -1-13/6  and x= -1+13/6

x= -7/3  and x= 12/6=2

Hence, the roots are real, irrational and unequal.

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Jacob distributed a survey to his fellow students asking them how many hours they'd spent playing sports in the past day. He also asked them to rate their mood on a scale from 0 to 10, with 10 being the happiest. A line was fit to the data to model the relationship.

Which of these linear equations best describes the given model?

Choose 1 answer:

5x+1.5

1.5x+5

−1.5x+5


Based on this equation, estimate the mood rating for a student that spent 2.52, point, 5 hours playing sports.

Round your answer to the nearest hundredth.

Answers

Answer:8.75

Step-by-step explanation:

Answer: it’s B

Step-by-step explanation:

Find the value of k and x2
x^2+ 13x + k = 0, x1=-9

Answers

Given:

The quadratic equation is:

[tex]x^2+13x+k=0[/tex]

[tex]x_1=-9[/tex]

To find:

The value of k and [tex]x_1[/tex].

Solution:

We have,

[tex]x^2+13x+k=0[/tex]                ...(i)

Putting [tex]x=-9[/tex], we get

[tex](-9)^2+13(-9)+k=0[/tex]

[tex]81-117+k=0[/tex]

[tex]-36+k=0[/tex]

[tex]k=36[/tex]

Putting [tex]k=36[/tex] in (i), we get

[tex]x^2+13x+36=0[/tex]

Splitting the middle term, we get

[tex]x^2+9x+4x+36=0[/tex]

[tex]x(x+9)+4(x+9)=0[/tex]

[tex](x+9)(x+4)=0[/tex]

[tex]x=-9,-4[/tex]

Here, [tex]x_1=-9[/tex] and [tex]x_2=-4[/tex].

Therefore, the required values are [tex]k=36[/tex] and [tex]x_2=-4[/tex].

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What will happen if they bring john glenn back to earth too soon and what happens if they bring him back too late? - hidden figures movie "Should the PPF shifts out and the terms of trade are unaffected, then a country is unambiguously better off as a higher community indifference curve can be reached." Explain why this statement is untrue and graphically illustrate it. The following questions relate to the below information.XY2 X + Y2The equation above represents the decomposition of a compound XY2. The diagram below shows two reaction profiles (path one and path two) for the decomposition of XY2. The market supply for a Fintech firm in developing a financial app in Ghana is estimated as P = 8+ 1/3 Qs. A further analysis of the market showed that the demand for financial app can be expressed as P = 44- 1/s QD. i. If the financial app market is in equilibrium, calculate the equilibrium price. ii. What is the equilibrium quantity associated with the equilibrium price?iii. If the government imposes a minimum price of GHS20, describe the kind of situation that arises in the market. iv. If a government imposed maximum price of GHS50, what will be its consequences in the market? v. Sketch your results from (i) to (iv) vi. Suppose the government makes available several financial apps under the digitalization agenda project, using a grapl, explain what happens to the market equilibrium. In the system shown in figure, the mass m1 is excited by a harmonic force having a maximum value of 50 N and a frequency of 2 Hz.Find the forced amplitude of each mass for m1 = 10 kg, m2 = 5 kg, k1 = 8000 N/m, and k2 = 2000 N/mPlease show work and do not copy/paste from previous examples. Which of the following statements is correct? A. Management accounting is a subset of cost accounting. B. Cost accounting is a subset of management acounting. C. Cost accounting is no longer required in today's competitive environment. D. 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The president wants to keep the degree of total leverage at 2.8. If EBIT remains at $4 million, what dollar amount of bonds must be outstanding to accomplish this (assuming the yield to maturity remains at 10.20% and is equal to the coupon rate)? Do not round intermediate calculations.a. $14,705,882b. $8,294,118c. $18,521,008d. $8,539,277e. $16,806,723 calculate the ph of each of the following solutions. ka=1.8*10^-5 Q2. Read the document "Collective agreement 2019" and answer thefollowing -5 Marks What is the name of the Union? What is the nameof the Employer? 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Production data for the month on the toy follow:Direct materials: 73,000 microns were purchased at a cost of $0.29 per micron. 39,250 of these microns were still in inventory at the end of the month.Direct labor: 6,600 direct labor-hours were worked at a cost of $45,540.Compute the direct materials price and quantity variances for July. (Indicate the effect of each variance by selecting "F" for favorable, "U" for unfavorable, and "None" for no effectCompute the direct labor rate and efficiency variances for July. (Indicate the effect of each variance by selecting "F" for favorable, "U" for unfavorable, and "None" for no effect