A movement which keeps the distal end of the body segment fixed in one location describes what type of kinetic chain movement is known as a closed kinetic chain movement.
What is a closed kinetic chain movement?A closed kinetic chain movement is defined as that position where the most distal aspects of a particular extremity are fixed to the earth or another solid object.
In conclusion; a movement which keeps the distal end of the body segment fixed in one location describes what type of kinetic chain movement is known as a closed kinetic chain movement.
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calculate the kinetic energy of 200kg object that is moving with a speed 15ms.
Answer:
See below
Explanation:
Kinetic Energy = 1/2 * m * v^2
= 1/2 * 200 * (15)^2 = ________ joules
The kinetic energy of the 200 kg object moving with a speed of 15 m/s is 11250 Joules (J).
Given:
Mass of the object (m) = 200 kg
Speed of the object (v) = 15 m/s
For the kinetic energy (KE) of an object, we use the formula:
KE = (1/2) × m × v²
where:
KE is the kinetic energy,
m is the mass of the object,
v is the speed of the object.
The kinetic energy of the object:
KE = (1/2) × 200 × (15 )²
KE = (1/2) × 200 × 225
KE = 11250
KE = 11250 Joules (J)
Therefore, the kinetic energy of the 200 kg object moving with a speed of 15 m/s is 11250 Joules (J).
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from the same height (and at the same time), one ball is dropped and another ball is fired horizontally. which one will hit the ground first
Both balls will take the same amount of time to hit the ground if they are dropped and fired from the same height.
What is Projectile motion:
It is the motion of an object thrown or projected into the air, subject to only the acceleration of gravity. The object is called a projectile, and its path is called its trajectory.For a ball fired horizontally from same height and time, there is only a vertical acceleration on it towards the ground.
This acceleration is equal to the acceleration due to gravity (g = 9.81 m/s^2).
A ball dropped from the same height will also experience the same vertical acceleration downwards as the horizontal acceleration.
Therefore,
Both balls will take the same amount of time to hit the ground if they are dropped and fired from the same height.
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If the red and green balls fall off opposite sides of the table, the green ball will make a louder
sound. why?
select one:
o a. the green ball has more potential energy, meaning it had less kinetic energy.
potential energy equals sound energy.
o b. the green ball has more mass, so it had more kinetic energy. the kinetic energy
transferred to sound energy.
o c. the green ball was moving at a faster rate, and speed of movement determines the
loudness of the sound.
od. the red ball has less potential energy, so the green ball had more potential energy.
as energy transferred from one ball to the other, sound was created.
B. The green ball has more mass, so it had more kinetic energy, the kinetic energy transferred to sound energy.
What is kinetic energy?
This is the energy possessed by a moving object, and it depends on mass and speed of the object.
K.E = 0.5mv²
where;
m is mass of the objectv is the speed of the objectThus, we can conclude that, the green ball has more mass, so it had more kinetic energy, the kinetic energy transferred to sound energy.
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If the strength of the earth's electric field is 100 N/CN/C , how does the magnitude of the electric force on the droplet compare to the weight force
Magnitude of electric force = 15 x 10⁻¹⁰ N
Magnitude of weight force = 64.092 x 10⁻⁶ N
Given
Diameter of rain drop = 2.5mm
Radius = 1.25 mm = 1.25 × 10⁻³ m/sec
Drop has a charge = +15pC
15pC = 15×10⁻¹²C
Electric field (E) = 100 N/C
Electric force on the charge
= charge x electric field = qE
= 15 x 10⁻¹² x 100
= 15 x 10⁻¹⁰ N.
This force will act in upward direction as the force on the positive charge will always acts in the direction of the electric field.
Volume of rain droplet(V) = 4/3 π R³
Volume V = 4/3 x 3.14 x ( 1.25 x 10⁻³)³
= 6.54 × 10⁻⁹m³
As Density of water = 1000 kg / m³
Density =Mass/Volume
So, Mass of rain droplet = 1000 x 6.54 x 10⁻⁹ kg
= 6.54 x 10⁻⁶ kg .
Now, Weight(W) = mg
= 6.54 x 10⁻⁶ x 9.8
= 64.092 x 10⁻⁶ N.
As the electric force is 15 × 10⁻¹⁰ N
So, weight force is more than the electric force.
Hence, the magnitude of the electric force on the droplet is less as compare to the weight force.
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(picture attached) use grass method
4. A block of unknown substance is submerged in water. A light ray in the water strikes the angle of 16°, what is the index of refraction of the unknown substance? (nwater = 1.33) substance at an angle of 45° from the normal. If the refracted ray in the substance is at an 5. If a light ray passes from a substance with low index of refraction to another substance with high index of refraction, will the ray bend away from or closer to the normal? Why? 6. What is the angle of refraction? n₁=1 24° n₂ = 1.8
Answer:
Explanation:
Step 1
1 of 2
\textbf{Given}Given
n_{w}=1.33n
w
=1.33
$\theta_w=31\text{ ^\circ
∘
}$
$\theta_b=27\text{ ^\circ
∘
}$
\textbf{Approach}Approach
In this problem we are going to use Snell's law.
\textbf{Solution}Solution
The definition of Snell's law of refraction is
\begin{align} {n_1\cdot\sin \theta_1}={n_2\cdot \sin \theta_2} \end{align}
n
1
⋅sinθ
1
=n
2
⋅sinθ
2
where indexes 11 and 22 represent two different mediums. Since the motion is in the water we write
\begin{align} &{n_{w}\cdot\sin\theta_{w}}={n_{b}\cdot\sin\theta_{b}} \\ &{n_b}={n_{w}\cdot \frac{\sin\theta_{w}}{ \sin \theta_{b}} } \\ &{n_b}={1.33\cdot \frac{\sin31^\circ}{ \sin27^\circ} } \\ &\boxed{{n_b}=1.5} \end{align}
n
w
⋅sinθ
w
=n
b
⋅sinθ
b
n
b
=n
w
⋅
sinθ
b
sinθ
w
n
b
=1.33⋅
sin27
∘
sin31
∘
n
b
=1.5
What is the value of the current intensity that crosses a wire of 10 ohms if the voltage applied to the extremes of the wire is 110 V
11 A is the amount of current that crosses the wire.
According to Ohm's law,
If all other physical parameters and temperatures remain constant, the voltage across a conductor is directly proportional to the current flowing through it.
V ∝ I
V= IR where,
V = Voltage across a conductor
I = Current flowing through the conductor
R= Resistance and also known as constant of proportionality
Given,
Resistance of wire(R) = 10 ohms
Voltage applied(V) = 110V
Current(I) = ?
According to the formula
110V = I × 10Ω
I = 110/10 = 11 A
Hence, current intensity of 11 A crosses a wire of 10 ohms if the voltage applied to the extremes of the wire is 110 V
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Using the information from the previous problem (A 2kg ball rotates on the end of a 1.4m long string. The ball makes 5 revolutions in 4.4s.), calculate the centripetal force on the ball.
Group of answer choices
A) 140.9N
B) 1.1N
C) 110.4N
D) 5.7N
The centripetal force on the ball is 140.9 N; option A
What is the centripetal force on the ball?The centripetal force on the ball is given by the formula below:
F = mv²/rwhere;
m is massv is linear velocity r is radiusThe linear velocity, v = wr
v = 5 * 2π/4.4 * 1.4 = 9.93 m/s
F = 10² * 2/1.4 = 140.9 N
In conclusion, the centripetal force is derived from the mass, velocity and radius of the path.
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A box with a mass of 2 kg only has four forces acting on it: One force of 16 N due East. One force of 24 N due South. One force of 16 N due West. One force of 18 N due North. What is the magnitude of the box's acceleration, in m/s2
Answer:
The acceleration of the object is 3 m/s2.
Explanation:
The force on the object is acting along the four directions which are perpendicular to each other. Since the north and south directions are opposite to each other, the magnitude of the net force along north-south direction is (24-18)=6 N.Since the east and west directions are opposite to each other, the magnitude of the net force along east-west direction is (16-16)=0 N.Therefore the magnitude of the net force on the object is 6 NBy Newton's second law, the force F on the object is given by the formula F=ma. Here m= 2kg, therefore 6 =(2)a which gives a = 3 m/s2.Learn more about Newton's law.
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How can we change direction of light? name this phenomenon. grade 6 please helppp
The direction of the light can be changed by reflection from a reflecting surface and by the refraction of the light through a medium of different refractive index.
What is reflection?
The phenomenon of the light in which the light ray bounces back from the surface on which they fall is called the reflection.
Now when the light ray falls on a surface that is well polished like the mirror, then the light ray changes its direction. So by using the combination of mirrors, the direction of the light ray can be changed.
What is refraction?
Refraction is a phenomenon in which light rays change their path slightly when it is passing through a transparent medium with a different refractive index.
The concave and convex lens uses this property of light. So by using the convex and concave lens, the direction of the light ray can be changed.
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A 480 g peregrine falcon reaches a speed of 75 m/s in a vertical dive called a stoop. If we assume that the falcon speeds up under the influence of grav- ity only, what is the minimum height of the dive needed to achieve this speed
The minimum height of the dive needed to achieve the given speed is v = 69 m/s is 242.9 m.
Given information:
The mass of peregrine falcon is, m = 480
The final speed reached by the peregrine falcon in a vertical dive is, v = 69 m/s
It is given that the falcon is diving vertically downward. It can be compared with the same situation as the free-falling object under the effect of gravity only. So, the initial velocity of the falcon will be u = 0 m/s as the motion starts with rest.
The value of the gravitational acceleration of gravity is, g = 9.80 m/s²
Now, using the third equation of motion, the minimum height required for the final speed will be,
v² - u² = 2gh
69² - 0² = 2 × 9.8 × h
h = 242.9m.
Therefore, the minimum height of the dive needed to achieve the given speed is 242.9 m.
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Flexible cord sets and power-supply cords shall not be concealed behind building __________________, or run through doorways, windows, or similar openings.
Flexible cord sets and power-supply cords shall not be concealed behind building , structural ceilings, suspended or dropped ceilings, floors or walls, or run through doorways, windows, or similar openings.
Hence Option (b) All of these is correct
Flexible cord and flexible cable usage are now outlined in Section 400.10, while prohibited uses are listed in Section 400.12.
Note 5 under 400.12 now includes a new exclusion for flexible wires and cords (uses not permitted).
Flexible cables, flexible cord sets, and power supply cords are not permitted in areas that are "concealed by walls, floors, or ceilings or positioned above suspended or dropped ceilings," according to Note 5.
The following uses for flexible cables, flexible cord sets, and power supply cords are prohibited as well:
(1) As an alternative to a structure's fixed wiring.
(2) Run-through openings in structural ceilings, floors, suspended ceilings, or dropped ceilings.
(3) When run through windows, doorways, or comparable openings.
(4) If attached to building surfaces.
Hence, Option (b) All of these is correct .
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Which arrow represents the substance’s change of state?
Answer:
Its P path describes the change of state i.e from solid to liquid.
What is solid ?
"A solid is that state of matter which has a fixed shape, mass, and volume. It suffers very small changes in volume by changing the temperature. It can not be compressed, e.g. — Sand, Wood, Copper, Ice, etc."
What is liquid ?
"A liquid is a sample of matter that conforms to the shape of a container in which it is held, and which acquires a defined surface in the presence of gravity. The term liquid is also used in reference to the state, or condition, of matter having this property."
A glass optical fiber is used to transport a light ray across a long distance. The fiber has an index of refraction of 1.510 and is submerged in water, which has an index of refraction of 1.333. What is the critical angle (in degrees) for the light ray to remain inside the fiber
The answer is 73.13°.
According to snell's law,
n1sinθi = n2sinθr
n1/n2 = sinθr/sinθi
The critical angle is the angle of incidence at the denser medium when the angle of incidence at the less dense medium is 90°
This means i=C and r = 90°
The Snell's law formula will become
n1/n2 = sinC/sin90°
n2/n1 = 1/sinC
Where n1 is the refractive index of the less dense medium = 1.473
n2 is the refractive index of the denser medium = 1.540
Substituting the values in the formula,
1.540/1.473 = 1/sinC
1.045 = 1/sinC
SinC = 1/1.045
SinC = 0.957
C = sin^-1(0.957)
C = 73.13°
The refractive index of glass is 1.5. It way that the velocity of mild in glass is 1.5 times slower than the rate of mild in a vacuum, the speed of light in glass isn't always unbiased of the shade of mild.
Refractive index is likewise the same as the velocity of light c of a given wavelength in an empty area divided with the aid of its speed v in a substance or n = c/v.
The index of refraction of fabric is a ratio that compares the velocity of light in a vacuum ( c=3.00x108ms ) to the velocity of mild in that precise medium. Because the index of refraction increases, the amount that the material bends the mild increases.
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The critical angle (in degrees) for the light ray to remain inside the fiber is 73.13°.
According to snell's law,
n1sinθi = n2sinθr
n1/n2 = sinθr/sinθi
The critical angle is the angle of incidence at the denser medium when the angle of incidence at the less dense medium is 90°.
This means i=C and r = 90°
The Snell's law formula will become
n1/n2 = sinC/sin90°
n2/n1 = 1/sinC
Where n1 is the refractive index of the less dense medium = 1.473
n2 is the refractive index of the denser medium = 1.540
Substituting the values in the formula,
1.540/1.473 = 1/sinC
1.045 = 1/sinC
SinC = 1/1.045
SinC = 0.957
C = sin^-1(0.957)
C = 73.13°
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If an electron has an uncertainty in its velocity of 1.40 m/s, what is the uncertainty (in meters) in its position
Uncertainty in position:
If the electron has an uncertainty in its velocity of 1.40 m/s then the uncertainty in its position is [tex]4.14\times10^{-4} \text{ m}[/tex].
Heisenberg's uncertainty principle to calculate the required:
Step-1:
We have to apply Heisenberg's uncertainty principle to calculate the uncertainty in the position of an electron. According to the principle:
[tex]$\Delta x \Delta p \geq \frac{h}{4 \pi}$[/tex]
Here,
[tex]$\Delta x$[/tex] is the uncertainty on the position measurement
[tex]$\Delta p$[/tex] is the uncertainty on the momentum measurement
h is the Planck constant.
It is known that the momentum of a particle is calculated as, the product of the mass of the particle and its velocity.
Therefore,
p=mv
Thus the Heisenberg principle becomes:
[tex]$m \Delta x \Delta v \geq \frac{h}{4 \pi}$[/tex]
Here [tex]$\Delta v$[/tex] is the uncertainty in the velocity measurement.
It is given that, [tex]$\Delta v$[/tex]=1.40 m/s. The particle is electron here, thus the mass of the particle m=[tex]9.1 \cdot 10^{-31} \mathrm{~kg}[/tex] and the value of the Plank's constant is, h=[tex]6.62 \times 10^{-34} \mathrm{~m}^{2} \mathrm{~kg} / \mathrm{s}[/tex]
Step-2:
Substituting the values into the equation to get the value of the position uncertainty.
[tex]\Delta x \geq \frac{h}{4 \pi\times m\times \Delta v}\\\geq\frac{6.62\times10^{-34}}{4\pi \times 9.1\times10^{-31}\times1.40} \text{ m}\\\geq 4.14\times10^{-4} \text{ m}[/tex]
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Two workers are sliding 440 kg crate across the floor. One worker pushes forward on the crate with a force of 390 N while the other pulls in the same direction with a force of 260 N using a rope connected to the crate. Both forces are horizontal, and the crate slides with a constant speed. What is the crate's coefficient of kinetic friction on the floor
The kinetic coefficient of friction of the crate is 0.1506
Let's assume that both workers are applying positive pressure to the crate. A body cannot change its state of motion whether it is at rest or moves uniformly, according to Newton's First Law (at constant velocity). The magnitude of the friction force must therefore equal the total of the two external forces. The crate's equilibrium equations are as follows:
∑Fₓ = P + T - μ . N = 0
∑[tex]F_{y}[/tex] = N - W = 0
Where:
[tex]P[/tex] - Pushing force, measured in newtons.
[tex]T[/tex] - Tension, measured in newtons.
μ- Coefficient of kinetic friction, dimensionless.
[tex]N[/tex]- Normal force, measured in newtons.
W - Weight of the crate, measured in newtons.
The system of equations is now reduced by algebraic means:
P + T - μ . W = 0
We finally clear the coefficient of kinetic friction and apply the definition of weight :
μ [tex]=\frac{P + T}{m.g}[/tex]
We know that P = 390 N, T = 260 N, m = 440 kg and [tex]g= 9.807 \frac{m}{s^2}[/tex] ;
μ = 0.1506
Therefore, the kinetic coefficient of friction of the crate is 0.1506
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A series combination of a 48.0-mF capacitor and a resistor are connected to a 12-V battery. After one second, the voltage across the capacitor is 10 V. What is the resistance of the resistor
The resistance of the resistor is .
Given:- A series combination of a 48.0-mF capacitor and a resistor are connected to a battery. After one second, the voltage across the capacitor is .
To Find:- We have to find the value of the resistance of the resistor.
By using the concept of the resistance it will be solved.
According to the problem,
The value of the resistance of the resistor is .
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A stone is dropped from the top of a cliff. It hits the ground below after 3.25 s. How high is the cliff
The height of the cliff above the ground is 51.76 m.
Height of the cliffh = vt + ¹/₂gt²
where;
v is initial vertical velocityt is time of motiong is acceleration due to gravityh = 0 + ¹/₂gt²
h = ¹/₂gt²
h = ¹/₂(9.8)(3.25)²
h = 51.76 m
Thus, the height of the cliff above the ground is 51.76 m.
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How does light travel? (1 Point)
A) "Light can only travel in a vacuum and the speed varies depending on whether the source is moving or stationary"
B) "Light can travel in the air or a vacuum and the speed is constant whether the light source is stationary or moving"
C) "Light only travels in a medium and light travels when a sound source is stationary"
D) "Light only travels in a vacuum and travels faster when the sound source is moving"
Light can travel in the air or a vacuum and the speed is constant whether the light source is stationary or moving which is denoted as option B.
What is Light?
This is referred to the portion of the electromagnetic spectrum which is perceived by the human eyes.
It has a constant speed and can travel in an air or vacuum. This theefrore makes it the most appropriate choice ion this scenario.
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Which best describes a possible transfer of energy
A mechanical wave transfers energy through matter.
What is Mechanical wave?A mechanical wave is a wave that is an oscillation of matter and is responsible for the transfer of energy through a medium.
Answer: Like all waves, mechanical waves transport energy. This energy propagates in the same direction as the wave. A wave requires an initial energy input; once this initial energy is added, the wave travels through the medium until all its energy is transferred. In contrast, electromagnetic waves require no medium, but can still travel through one.
A wave is a transmission of a disturbance from one point to another. Wave involves transmission of energy from one point to another through a materials medium.
Mechanical waves vibrate in matter and transfer energy. Explore the production and propagation of mechanical waves and discover the factors that affect mechanical waves including elasticity, tension, temperature, and density
Therefore,
A mechanical wave transfers energy through matter.
A complete question is is given below:
What best describes a possible transfer of energy?
a. A mechanical wave transfers energy through matter.
b. A longitudinal wave transfers energy perpendicular to wave motion.
c. A transverse wave transfers energy parallel to wave motion.
d. A sound wave does not need a medium to transfer energy through.
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if a man pulls a box with a forcce of 90N at an angle of 45 degrees then what are x and y components of the force
The x and y components of the force will be 63.6 N and 63.6 N respectively.
What is velocity?The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The given data in the problem is
Force, F=90 N
Angle,θ = 45°
The force of 90N at an angle of 45 degrees;
The force is resolved in the x and y direction as;
[tex]\rm F_x = 90 cos 45 ^ 0 \\\\ F_x = 63.6 \ N[/tex]
[tex]\rm F_y = 90 sin 45^0 \\\\ F_y =63.6 \ N[/tex]
Hence x and y components of the force will be 63.6 N and 63.6 N respectively.
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When the liquid line is restricted, the supply of refrigerant to the metering device is reduced. What is the effect on suction pressure and superheat
Answer:
The suction pressure decreases and the superheat increases when the liquid line is restricted and the supply of refrigerant to the metering device is reduced.
Explanation:
1. The five components of refrigeration are:
Fluid refrigerantCompressorCondenser coilEvaporator coilExpansion device.The compressor limits the vapor released by the refrigerant. This
causes a rise in pressure (in refrigerant), which then pushes the
vapor into the coils on the outside of the refrigerator.
2. Now when the cooler air meets the warm gas present in the coils, it
gets converted into liquid form.
3. Thus, when the liquid form is at high pressure, the refrigerant then
cools down as it flows through the coils placed in the fridge ( in both
freezing and normal sections).
4. The refrigerant also absorbs the warm air present in the fridge, which
causes it to evaporate and flow back through the compressor and the
cycle repeats in the same form.
Thus, when the liquid line is restricted and the supply of refrigerant to the metering device is reduced it causes a decrease in suction pressure and an increase in superheat.
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Two objects, m1 = 0.6 kg and m2 = 4.4 kg undergo a one-dimensional head-on collision
Their initial velocities along the one-dimension path are vi1 = 32.4 m/s [right] and vi2 = 8.6 m/s [left].
The two objects stick together after the perfectly inelastic collision
a) Calculate the velocity after the collision.
b) Determine how much kinetic energy is lost due to the collision
Explanation:
Hello !
look at the attachment above ☝️ and if you have any questions your welcome.
a) The velocity after the collision.is 11.456 m/s.
b) The kinetic energy lost due to the collision is 44.564 J.
What is conservation of momentum principle?When two bodies of different masses move together each other and have head on collision, they travel to same or different direction after collision.
The external force is not acting here, so the initial momentum is equal to the final momentum. For inelastic collision, final velocity is the common velocity for both the bodies.
m₁u₁ +m₂u₂ =(m₁ +m₂) v
Given are the two objects, m1 = 0.6 kg and m2 = 4.4 kg undergo a one-dimensional head-on collision. Their initial velocities along the one-dimension path are vi1 = 32.4 m/s [right] and vi2 = 8.6 m/s [left].
(a) Substitute the values, then the final velocity will be
0.6 x32.4 +4.4 x 8.6 = (0.6+4.4)v
v = 11.456 m/s
Thus, the velocity after collision is 11.456 m/s.
(b) Kinetic energy lost due to collision will be the difference between the kinetic energy before and after collision.
= [1/2m₁u₁² +1/2m₂u₂² ] - [1/2(m₁ +m₂) v²]
Substitute the value, we have
= [1/2 x 0.6 x32.4² + 1/2 x4.4 x 8.6²] - [1/2 x(0.6+4.4)11.456²]
= 44.564 J
Thus, the kinetic energy lost due to the collision is 44.564 J.
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To develop a model of blackbody radiation that correctly modeled the behavior of emission intensity versus wavelength, Planck applied quantization of:\
Max Planck utilized the concept of energy quantization in order to develop a model for blackbody radiation that accurately fit experimental results.
Electromagnetic waves emitted by using a blackbody are referred to as blackbody radiation. A blackbody is bodily found out through a small hole within the wall of a hollow space radiator.
The depth of blackbody radiation depends on the wavelength of the emitted radiation and the temperature T of the blackbody.
When the temperature of a black frame increases, it is discovered that the wavelength similar to most electricity changes from 0.26 μm to 0. Thirteen μm Then the ratio of the emissive power of the body at the respective temperature is.
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After rubbing on the apparatus, your pith pall became negatively charged. What type of charge does the apparaTapus now have
The apparatus must be Positively Charged.
Charge interaction:
As from the charge interaction we came to know that when we rub two objects together then there will be three possibility.1. opposite charge objects attract each other
2. like charge object repel each other
3. neutral object with any charges will attract each other.
These happens due to friction generated on rubbing of object which in reverse create electron and get transfer.So, In the question it said that after rubbing on apparatus pith ball
become negative charge which means it has gained the electron.
Thus, the apparatus must have lose electron and would be
positively charged.
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What is the current flowing through the circuit shown? (V= 120 V, R₁ = 20 02,
R₂= 50 Q, R3= 1022) (Ohm's law: V = IR)
R₁
ww
ww
R₂
ww
R₂
Assumed that resistors are connected in series .
R_net=20+50+10=80ohm Voltage=V=120VCurrent=I
V/R120/803/21.5A_____________is the addition of wave energy as waves interact, producing larger waves and ____________ is the subtraction of wave energy as waves interact, producing smaller waves.
Constructive interference is the addition of wave energy as waves interact, producing larger waves and destructive interference is the subtraction of wave energy as waves interact, producing smaller waves.
To find the answer, we need to know about the interference of waves.
What's the interference of waves?Interference of waves is the result of superposition of waves (transverse or longitudinal) at a certain place. Interference is of two typesConstructive interferenceConstructive interferenceDestructive interferenceHow are the constructive and destructive interference formed?When two waves are superimposed within the phase, then constructive interference pattern is formed.When two waves are superimposed with out of phase, destructive interference pattern is found.Thus, we can conclude that the constructive interference is the addition of wave energy and destructive interference is the subtraction of wave energy.
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Answer the following questions.
1. What is the velocity of a car that traveled a total of 75 kilometers north in 1.5 hours?
2. What is the velocity of a plane that traveled 3,000 miles from New York to California in 5.0 hours?
3. John took 45 minutes to bicycle to his grandmother's house, a total of four kilometers. What was his speed in km/hr?.
4. It took 3.5 hours for a train to travel the distance between two cities at a speed of 120 miles/hr. How many miles lie between the two cities?
3.if time=45mins,D=4km,2700secs,4000m then. S=d/t S=1.4m/s
Directly detecting an Earth-size planet around one of the nearest stars (besides the Sun) is roughly equivalent to trying to take a picture of a ball point from a pen at a distance of about ________ kilometers.
The ballpoint from a pen at a distance of about 4000 kilometers.
Alpha Centauri is the closest star device. Distance from Earth 4,365 al (forty 000 billion kilometers. The solar (yellow famous person) distance from Earth is 150 000 000 km, the exoplanet distance from Alpha Centauri b (orange famous person) 6 000 000 km.
Shifts in starlight from Proxima Centauri, found over extra than 2 years, screen its 1/3 planet. Astronomers have observed a 3rd planet orbiting Proxima Centauri, the star closest to the solar.
Proxima Centauri, the nearest megastar to our own, remains forty,208,000,000,000 km away. (Or about 268,770 AU.)
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Point charges q1and q2 of +12nc and -12nc,respectively are placed 10.0cm apart.compute the resultant electric field(magnitude field)
The electric field due to charge q1 and q2 at the middle point of the line joining the charges q1 and q2 is 8.64*10^(4) N/C.
Note: You have not given the point where the resultant magnetic field has to be calculated. Most probably it is asked to find the electric field at the middle point of the line joining the point charges.
Electric field: The electric force exerted on a unit charge is called the electric field. Electric field due to a charge is calculated using the formula,
E=kq/r^2
where k is a constant whose value is 9*10^(9) N m^2/ C^(2), q is the charge and r is the distance from the charge to the point where the electric field has to be calculated. In the given case, the electric field has to be calculated at the middle point of the line joining charges q1 and q2.
Calculation of electric field due to charge q1:
Given that q1=+12 nC or q1=+12*10^(-9) C and the distance of the charge q1 from the center d1=10.0/2 cm or d1=5*10^(-2) m, the magnitude of the electric field E1 due to charge q1 is,
E1=kq1 /d1^(2)
E1=9*10^(9)*12*10^(-9) / (5*10^(-2))^2
E1=4.32*10^(4) N/C
The direction of the electric field E1 at the middle point is towards the negative charge.
Calculation of electric field due to charge q2:
Given that q2=-12 nC or q1=-12*10^(-9) C and the distance of the charge q2 from the center d2=10.0/2 cm or d2=5*10^(-2) m, the magnitude of the electric field E2 due to charge q2 is,
E2=kq2 /d2^(2)
E2=9*10^(9)*12*10^(-9) / (5*10^(-2))^2
E2=4.32*10^(4) N/C
The direction of the electric field E2 at the middle point is towards the negative charge.
Total electric field:
The total electric field is given by the addition of the electric field. The direction of the electric field is the same for both charges, hence total electric field E is,
E=E1+E2
E=4.32*10^(4) +4.32*10^(4)
E=8.64*10^(4) N/C
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You look in the sky and see two jetliners that you know are of equal size, yet one appears to be much larger. Because of your knowledge of __________, you will assume that the smaller jetliner is farther away
Answer:
Because of the knowledge of relative size, it will be assumed that the smaller jetliner is farther away.
Explanation:
According to the theory of relative size, the distance that an object has to the viewing individual affects the perception of the individual regarding the size of the object.
As stated in this case, one of the jetliners is farther away from the other. Therefore, even if the jets are of equal size, the one that is at a greater distance is perceived to be smaller as it is at a greater viewing range. The one that is nearer to the individual seems bigger in comparison to the one farther away due to a closer viewing range.
Therefore, the jet that is nearer appears larger.
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