A model rocket was launched from a podium 5 meters above are

an initial velocity of 98 m/s. The function that models height in me

with respect to time (in seconds) is h(t) = 5 + 987-4.9t2

meters above ground at

meters)

Answers

Answer 1

Answer:

See solution below

Step-by-step explanation:

Find the complete question below;

Given the height modeled by the function;

h(t) = 5 + 98t-4.9t²

when t = 0

h(0) = 5 + 98(0)-4.9(0)²

h(0) = 5

when t = 5

h(5) = 5 + 98(5)-4.9(5)²

h(5) = 5 + 490 - 122.5

h(5) = 372.5

when t = 10

h(10) = 5 + 98(10)-4.9(10)²

h(10) = 5 + 980 - 490

h(10) = 495

when t = 15

h(15) = 5 + 98(15)-4.9(15)²

h(15) = 5 + 1470 - 1,102.5

h(15) = 372.5

when t = 20

h(10) = 5 + 98(20)-4.9(20)²

h(10) = 5 + 1960 - 4.9(400)

h(10) = 1965- 1960

h(10) = 5

Find the graph attached

A Model Rocket Was Launched From A Podium 5 Meters Above Arean Initial Velocity Of 98 M/s. The Function
A Model Rocket Was Launched From A Podium 5 Meters Above Arean Initial Velocity Of 98 M/s. The Function

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Answers

Answer:

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Answer:

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Step-by-step explanation:

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that's how it should look

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<------------------------------------------------------o

I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I

-10 -9 -8 -7 -6 -5 -4 -3 -2 -1   0  1   2  3  4  5  6  7  8  9 10

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Answers

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Answers

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

B I think this needs to be longer answer but b

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Answers

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Answers

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Answers

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Answers

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