A mass m at the end of a spring oscillates with a frequency of 0.71 Hz . When an additional 780 g mass is added to m, the frequency is 0.64 Hz, thus the value of mass is 3.376 kg
What is frequency?In terms of physics, frequency refers to the quantity of waves that pass through a given point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences over the course of a single unit of time.
Given that,
Frequency = 0.71 Hz
Mass = 780 g
After added to m, frequency becomes = 0.64 Hz.
Let the spring constant is k
k=m × w²
from the given info.
m × (0.71)² = (m+0.78) × (0.64)²
m ×[(0.71)²- (0.64)²] = 0.78 × (0.64)²
m = 0.78 × (0.64)² /[(0.71)²- (0.64)²]
m = 0.319 / 0.0945
m = 3.376 kg
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The zebra (herbivore) population is exploding in the savannah. At the same time, populations of many small animals that live in the Red Grass that zebras eat are beginning to die out. Why do you think populations of these small animals are dying out? What could we do to help prevent these small animals from going extinct?
Answer:
I think they are dying because of the sudden increase in the zebra population. The type of interaction between the grass and the small animals is called commensalism. The small animals depend on the grass for shelter, and when the zebras eat the grass ~this is called predation~, the small animals no longer have shelter, so they start dying.
Explanation:
What will be the purple spring's change in length if a 311 g mass is hung from the bottom?
The change in length of the purple spring be 6.77 cm.
What is spring constant?The spring stiffness is how we define the term "spring constant." In other words, we can define the spring constant as the force that was used to cause the spring's displacement to be one unit. It follows that a spring's spring constant would increase as it becomes more rigid.
Given parameters:
Spring constant: k = 45 N/m.
Mass of the load: m = 311 g = 0.311 kg.
So, weight of the load: w = mg = 0.311 × 9.8 N = 3.0478 N.
Hence, the purple spring's change in length be = w/k = 3.03478/45 m = 0.0677 m = 6.77 cm.
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The blades in a blender rotate at a rate of 6500 rpm. When the motor is turned off during operation, the blades slow to rest in 3.5 s. What is the angular acceleration as the blades slow down?
The angular acceleration as the blades slow down is 194.44 ras/s².
Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.
Calculation:-
The speed of the moving plate is 6500 rpm.
f = 6500 rpm = 6500/60
= 108.33 rev/s
The angular speed is
ω = 2πf
ω = 2π × 108.33
= 680.53 rad/s
time = 3.5 sec
angular acceleration
a = ω final - ω initial /Δt
= 0 - 680.53 / 3.5
= 194.44 ras/s²
Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. Movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.
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A skateboarder with a mass of 67.0 kilograms (including the skateboard) rolls down from the top of a ramp, reaching a velocity of 7.30 meters per second at the bottom of the ramp. Assuming friction is 0, what was the potential energy of the skateboarder at the top of the ramp?
1,785 J.
59.70 J.
74.30 J.
489.1 J.
The potential energy of the skateboarder at the top of the ramp is
489.1 J.
Is kinetic energy always equal to potential energy?The amount of kinetic energy change and the amount of potential energy change are equal in all physical processes that take place in closed systems. When the kinetic energy rises, the potential energy falls, and vice versa.
Potential energy is the stored energy in any object or system as a result of its position or component arrangement. However, external factors like air or height have no effect on it. The energy of a moving object or system is referred to as kinetic energy.
Potential energy = kinetic energy
Potential energy = 1/2mv²
Potential energy = 1/2 × 67×7.3
Potential energy = 489.1 J.
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Consider two processes: sublimation of I2(s) and melting of I2(s) (Note: the latter process can occur at the same temperature but somewhat higher pressure). I2(s) ? I2(g) I2(s) ? I2(l) Is ?S positive or negative in the processes? In which of the processes will the magnitude of the entropy change be greater?
The magnitude of the entropy change will be greater when [tex]I_2[/tex] (s) sublimates because [tex]I_{2[/tex] (g) has the highest entropy.
Entropy is a measure of the disorder of a system. So, if the system has higher entropy, the system is more disordered.
For a given substance gaseous phase has the highest entropy, and solid phase has the lowest entropy.
ΔS = [tex]S^{0[/tex]( product) - [tex]S^{0[/tex] (reactant)
Both sublimation and melting of [tex]I_{2[/tex](s) are spontaneous processes because solid [tex]I_{2[/tex] is the most ordered and has the lowest entropy. So, ΔS is positive for these processes. However, the magnitude of the entropy change will be greater when [tex]I_{2[/tex](s) sublimates because [tex]I_{2[/tex](g) has the highest entropy.
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david measures a line to be 1.54 ft long. if the actual measurement is 2 ft, find david's relative error to the nearest thousandth.
The relative error made by David to the nearest thousandth is 23.
First,
Find the Absolute Error as follows:
= Measure found by David - Actual measure
= 1.54 - 2
= - 0.46
The minus sign here indicates that the measure found by David is lesser than the actual measure of the line.
To find the Relative Error as follows:
= [ ( Absolute Error ) / ( True Value) ] X 100
= [ 0.46 / 2 ] X 100
= 0.23 X 100
= 23
The relative error is defined as the ratio of the absolute error of the measurement to the actual measurement. Using this method we can determine the magnitude of the absolute error in terms of the actual size of the measurement.
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(a) At Earth’s distance to the Sun, the incoming solar heat per unit area is about 1360
W/m2
. Only 70% of that is absorbed; the rest is reflected back to outer space. To get
the total heat absorption rate of the earth, you will need to multiply the absorbed heat
per area with one of the following:
(i) The total surface area of the Earth
(ii) Half the surface area of the Earth
(iii) The cross-sectional area of the Earth
(iv) Half the cross-sectional area of the Earth
Pick one and briefly explain why it is correct. (You may want to draw a small diagram;
hint: the sun’s rays are are not perpendicular to the surface everywhere.) Then calculate
the total heat absorption rate of the Earth.
(b) If the Earth is not to heat up or cool down, it must transfer heat to outer space at a rate
equal to what it absorbs from the Sun. Assuming that Earth is a blackbody with e = 1,
calculate the surface temperature of the Earth.
(c) Compare the temperature you found to the actual surface temperatures you find on
Earth. What major assumption in your calculation needs to be corrected, so that you
get an answer closer to reality?
(a) Earth has e ≈ 12.
(b) Convection and conduction has to be accounted for.
(c) Earth is not a perfect sphere.
(d) Earth has an atmosphere.
(e) The polar ice caps don’t contribute to radiation.
Explain your choice:
The atmosphere directly facing to the Sun is about 1,360 watts per squares meter.
What is distance?Distance is the total movement of an object without any regard to ratio.
We can defined distance as to be the magnitude or size of the displacemnt between two positions. Note that there are distance between the two positions is not the same as the distance of the traveled between them. Distance traveled is the total of the length of the path traveled between two are positions. Distanced traveled is not a vector.
At Earth's average distances from the Sun (about 150 million kilometers), the
average intensity of solar by its energy reaching the top of the atmosphere directly to the facing the Sun is about 1,360 watts per square square meter, according to measurements of the made by the most of the recent NASA satellites missions.
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An owl eats its prey whole or in large pieces. Summarize what is found in an owl pellet and why it is regurgitated
Teeth, bones, fur, and exoskeletons are found in an owl pellet.
What are owl pellets?Owls consume their prey whole or in huge chunks, but they are unable to digest hair, teeth, bones, or feathers. Owls, like other birds, have two stomach chambers. All of the edible elements of an owl's diet are liquefied in the first chamber, the glandular stomach or proventriculus.
Teeth, bones, hair, and exoskeletons of prey cannot be broken down by an owl's digestive system. These prey pieces are compacted into an owl pellet. This substance is regurgitated by the owl so that it can exit the owl's stomach.
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Answer:
Sample response: An owl’s digestive system cannot break down parts of the prey such as teeth, bones, fur, and exoskeletons. These parts of the prey are compressed into an owl pellet. The owl regurgitates this material so that it can leave the owl’s stomach.
Explanation:) have a great day hope this helps
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a force F=(4I+3J)N acts on the object of mass 2kg and drags it by moving the object from the origin to x=5m.find the work done on the object and the angle between the force nd the displacement
The work done on the object = 25 J
The angle between the force nd the displacement is 0° since the applied force is in positive x-direction.
What is work done?Work, in physics, a measure of the transfer of energy that occurs when an object is moved a distance by an external force acting at least partially in the direction of displacement. For a constant force, work can be calculated by multiplying the length of the path by the component of the force acting along the path. Expressing this concept mathematically, the work W is equal to the force f multiplied by the distance d, or W = fd. If the force is applied at an angle θ to the displacement, the work done is W = fd cos θ. Working on an object involves not only moving the entire object from one place to another, but also, for example, compressing a gas, rotating a shaft, or causing invisible motion to particles within the object. is also done by External magnetic force on the body.
Force in x-direction = 4i
Force in y-direction = 3j
For resultant force (Fₙ):
Fₙ² = 4² + 3²
Fₙ² = 16 + 9
Fₙ² = 25
Fₙ = 5 N
Since, W = F × d × cosθ
Where, W = work done
F = Applied force (5 N)
d = Distance covered (5 m)
θ = Angle between force and displacement (0°)
W = 5 × 5 × 1
W = 25 J
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An ideal fluid flows through a pipe. Which of the following would most likely result in the greatest increase in pressure within the fluid?
A. Decreasing the radius of the pipe and angling the pipe upward
B. Increasing the radius of the pipe and angling the pipe upward
C. Increasing the radius of the pipe and angling the pipe downward
D. Decreasing the radius of the pipe and angling the pipe downward
When a fluid travels through a medium in an ideal situation, its pressure increases even more when the pipe's radius is increased and it is angled upward.
What does pressure mean to you?the tension at a point inside a confined fluid, or the parallel force per unit area. An easy illustration of pressure The surface of the fruit won't be cut if you press the smooth part of a knife against it.
How can pressure be determined?The formula for calculating pressure is P = F / A, or force every unit of the surface area. The Si derived unit for measuring the pressure is the pascal, and the sign for pressure in physical science is p. (symbol: Pa). One Coulomb per square meter of force exerted perpendicularly on a surface is equal to one pascal.
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Add voltmeters to measure the voltage across each bulb and the power source for a total of 4 voltmeters. On the correct circuit, label positive + and negative - on the battery and label the bulbs 1, 2, 3
A volt/ohm meter, commonly referred to as a multimeter or multitester, is an electronic measuring device that integrates multiple measurement capabilities into a single unit. Voltage, current, and resistance measurements are among the things that a typical multimeter may be able to do.
What voltmeters measure the voltage across each bulb?Connect the voltmeter to the circuit in a specific method in order to utilize it to measure the potential difference. Wire 1, or the portion of the circuit before the bulb, must be connected to the voltmeter's one end.
Therefore, The circuit after bulb, or wire 2, must be linked to the other end of the voltmeter.
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A 2.30kg hoop 2.20m in diameter is rolling to the right without slipping on a horizontal floor at a steady 3.00rad/s .
Part A
How fast is its center moving?
Part B
What is the total kinetic energy of the hoop?
Part C
Find the magnitude of the velocity vector of each of the following points, as viewed by a person at rest on the ground: (i) the highest point on the hoop; (ii) the lowest point on the hoop, (iii) a point on the right side of the hoop, midway between the top and the bottom.
Separate your answers by commas.
Part E
Find the magnitude of the velocity vector for each of the points in part (C), except as viewed by someone moving along with same velocity as the hoop.
Separate your answers by commas.
velocity defines the route of the movement of the body or the object. pace is generally a scalar quantity. speed is essentially a vector quantity. it's far the rate of change of distance. it's miles the charge of exchange of displacement.
The diameter is the length of the road via the middle that touches factors on the threshold of the circle.
The distance from the centre to any factor at the floor is referred to as the radius. similarly, the gap from one point on the floor of a circle to the other point at the floor of the circle through the centre is called the diameter. In different words, the diameter is double the radius.
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Beams of electrons and protons having the same linear momentum enter into an electric field normally, which one will deflect more and why?
Answer:
Let their velocities at the time of entering the field be vp and ve. vp and ve are given perpendicular to electric field E. Let the field be prevailing over distance d in the direction of initial velocity of the beam.
Now, kinetic energy is same for electron and proton. Therefore,
(1/2)mpvp^2=(1/2)meve^2
So. in given distance, deflections for electrons and protons are same. Then, both trajectory will be equally curved.
When A student connects Cd" (2 M) I cd(s) half-cell to the red lead attached t0 the Cu electrode the cell potential read by the voltmeter, Ea' is +77 V. a) What is the reduction half-reaction at the cathode (red lead)? b) What is the oxidation half-reaction at the anode (black lead)? c) What is the overall cell reaction? d) Write the expression for the thermodynamic reaction quotient;, Q, and calculate its value for this celle) Use the Nernst equation to find the standard cell potential, E? ." 0252 In Q (at 25*C) f) Knowing that the standard reduction potential, E?rd' ofthe Cu" |Cu(s) half-cell is +0.34 V, (or knowing that the standard oxidation potential, E" ofthe Cu(s) Cu? half-cell is -0.34 V), what is the potential of the cadmium half-cell? Is this E?red or E?g) What is the standard reduction potential (SRP, E? ofthe Cd?-(0.20 M)lcd(s) half-cell?
We know that in electrochemical series copper has standard reduction potential +0.34 V which is higher than Cadmium(-0.40) .is Cd(s)+Cu2+(aq) -===Cd2+(aq)+Cu(s)
What is electrochemical?
The field of physical chemistry known as electrochemistry studies how a recognisable chemical change and an electrical potential difference interact as a measurable and quantitative phenomenon, with the potential difference either resulting from or being a cause of the chemical change.
Hence a cell contain copper and cadmium ion Copper half cell always reduction reaction occurs and in cadmium half cell oxidation takes place. E0 cell=Ecathode-E anode=+0.34-(-0.44)=0.78~0.77V
a) Reduction half reaction at cathode
Here cu2+ reduced to metallic Cu Cu2+(aq)+2e-------> Cu (s) (Reduction)
b) Oxidation half cell reaction at anode
Here Cd oxidized into Cd2+ Cd(s)---------->Cd2+(aq)+2e-
Overall cell reaction
Cd(s)+Cu2+(aq) -===Cd2+(aq)+Cu(s)
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Calculate the potential V(r) for r < r. (Hint the net potential is the sum of the potentials due to the individual spheres.) Express your answer in terms of the given quantities and appropriate constants. Submit My Answers Give Up Correct Part B Calculate the potential V(r) for Ta < r < Express your answer in terms of the given quantities and appropriate constants. Submit Mv Answers Give Up Correct Part C Calculate the potential V(r) for rTb. Express your answer in terms of the given quantities and appropriate constants. V(r) 0
Potential is constant throughout the sphere. So, the distance we take is the radius of the sphere.
The electric potential inside the sphere at r < r is:
V =[tex]V_{a} +V_{b}[/tex]
= [tex]\frac{k(q)}{r_{a} } + \frac{k(-q)}{r_{b} }[/tex]
= kq [tex]\left[\begin{array}{ccc}\frac{1}{r_{a} }-\frac{1}{r_{b} } \end{array}\right][/tex]
Part b
The electric potential in between [tex]r_{a}[/tex] and [tex]r_{b}[/tex] is:
[tex]V = V_{a} +V_{b}[/tex]
[tex]\frac{k(q)}{r_{a} } + \frac{k(-q)}{r_{b} }[/tex]
[tex]= kp\left[\begin{array}{ccc}\frac{1}{r_{a} }-\frac{1}{r_{b} } \end{array}\right][/tex]
Part c
The electric potential inside the sphere at r < [tex]r_{b}[/tex] is:
[tex]V = V_{a} +V_{b}[/tex]
[tex]\frac{k(q)}{r_{a} } + \frac{k(-q)}{r_{b} }[/tex]
[tex]= kp\left[\begin{array}{ccc}\frac{1}{r_{a} }-\frac{1}{r_{b} } \end{array}\right][/tex]
= 0
A voltmeter is used to measure the potential difference between two points. A voltmeter has a high resistance and is connected in parallel with an electrical component that measures the potential difference. The net potential energy between two adjacent ions EN.whose values depend on the particular ionic system.
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A boy is spinning a 0.50 kg mass tied to a 1.25m-long string in a horizontal circle around his head. If the object has a tangential velocity of 5.4 m/s, what is the tension in the string (in N)?
The magnitude of the tension in the string applied by the boy is determined as 11.7 N.
What is the tension in the string?
The magnitude of the tension in the string is calculated by applying Newton's second law of motion as follows;
Tension in the wire = centripetal force of the boy
T = Fc
T = ma
T = mv²/r
where;
m is the mass of the boyr is the radius of the horizontal circlev is the linear speed of the objectT = ( 0.5 kg x ( 5.4 m/s )² ) / ( 1.25 )
T = 11.7 N
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When a student is applying a rightward force of 6.5 N to a 1.80 kg box the box remains at rest. When the student applies a slightly larger force, the box moves to the right. Find the coefficient of static friction.
The coefficient of static friction is equal to 0.368.
What is static friction?Static Friction can be described as friction that is experienced when an object is placed on a surface. Kinetic friction can be described as friction due to the movement of an object on a surface. The coefficient of static friction is a scalar parameter and is represented as μs.
The coefficient of static friction can be calculated from the following expression as:
[tex]{\displaystyle \mu_s ={\frac{ F}{mg}[/tex]
Given, the force acting on the box = 6.5 N
The mass of the box, m = 1.80 Kg
The gravitational acceleration, g = 9.8m/s²
The coefficient of static fraction = 6.5/(1.80 ×9.8) = 0.368
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List 2 ways in which humans may cause land to erode faster than it would naturally.
Answer:
Deforestation
Construction and recreational activities
In the above figure, a ray of light is incident upon the interface between two media having indices of refraction n1 = 1.2 and n2 = ???. The known angles are f2 = 60° and f3 = 34°. (Note that the angles in the diagram may not be accurate.) What is the speed of light in the second medium?
n₂ = 1.196. A light beam strikes the boundary between two mediums with different indices of refraction.
How does refraction work?When light waves cross the border between two materials with different densities, like air and glass, their speed changes. They alter direction as a result, which is a phenomenon known as refraction. Refraction is the shift in a wave's direction when it travels through one medium and then another.
What two refractions are there?Absolute refractive index is the comparison between the speed of light in vacuum and the light speed in another medium. Relative refractive index is the ratio of one medium's light speed to a different medium's light speed.
Briefing:Snell's law = n₁sinθ₁= n₂sinθ₂
and the velocity of light, N = C/ Vn
n₁ = 1.2
n₂ = 1.196
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1. Cold, dry air would be least likely to have...
Cold air typically contains less moisture than warm air, and quick breathing dry air dehydrates the bronchial tubes, causing them to narrow and restrict airflow. The sports and activities are most likely to cause EIB symptoms to require constant movement or are done in cold weather.
a straight line that originates at some point is called a ray. the part of optics dealing with the ray aspect of light is called geometric optics. light can travel in three ways from a source to another location:
The light can travel in three ways and these are: (1) after being reflected from a mirror, (2) through various media, and (3) directly from the source through empty space.
What is Mirror?A mirror is a device that has a reflective surface for light. Since mirrors often reflect light rather than absorb it, the majority of the light is redirected upon contact with the mirror, and the overall quality of the item is typically kept in the new image. Mirrors exist in a variety of forms and are employed in a variety of applications.
What is reflection?It is known as light reflection when a light ray strikes a perfectly smooth, polished surface and reflects back. The surface reflects the incident light rays that come in contact with it. Reflected ray refers to the ray that returns. A perpendicular would be referred to as normal if it were drawn on a reflective surface.
Hence, light can travel in three ways and these are: (1) after being reflected from a mirror, (2) through various media, and (3) directly from the source through empty space.
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John ties a rope to a 15 kg crate and pulls it up an inclined plane at a constant speed υ as in (Figure 2). The coefficient of kinetic friction between the crate and the plane is 0.20. Assume the rope is parallel with the surface of the plane. What is the tension in the rope? Derive an expression for the tension in the rope for an arbitrary mass M and an inclination angle θ, for the case of a frictionless incline.
The force communicated through a rope, string, or wire when two opposing forces draw on it is known as tension. The tension force pulls energy equally on the bodies at the ends and is applied along the entire length of the wire.
What is the main reason of tension in the rope?The force communicated through a rope, string, or wire when two opposing forces draw on it is known as tension. The tension force pulls energy equally on the bodies at the ends and is applied along the entire length of the wire.
Therefore, Every physical object in contact with another one applies some force to that object.
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Consider electromagnetic waves in free space. What is the wavelength of a wave that has the following frequencies? (a) 4.86 times 10^11 Hz m (b) 8.80 times 10^16 Hz m
The wavelength of a wave for 4.86 times 10^11 Hz m is [tex]6.17 * 10 ^-^4 m[/tex] and for 8.80 times 10^16 Hz m is [tex]3.4 * 10 ^-^9 m[/tex]
What are electromagnetic waves?
The oscillations between an electric field and a magnetic field produce waves known as electromagnetic waves, or EM waves. In other words, magnetic and electric fields oscillate to form electromagnetic (EM) waves.
What is wavelength?
The distance between two successive crests or troughs of a wave is known as its wavelength. It is measured in the wave's direction.
It is measured by λ = c/f.
where,
λ = wavelength
c = speed of light
f = frequency
Subsituting the values in equation:
(a) for f = 4.86 times 10^11 Hz m
λ = [tex]\frac{3 * 10^8}{ 4.86 * 10^1^1}[/tex] = [tex]6.17 * 10 ^-^4 m[/tex]
(b) for f =8.80 times 10^16 Hz m
λ = [tex]\frac{3 * 10^8}{ 8.80 * 10^1^6}[/tex] = [tex]3.4 * 10 ^-^9 m[/tex]
The wavelength of a wave for 4.86 times 10^11 Hz m is [tex]6.17 * 10 ^-^4 m[/tex] and for 8.80 times 10^16 Hz m is [tex]3.4 * 10 ^-^9 m[/tex]
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40. CHALLENGE You stack two physics books on top of each other as shown in Figure 19. You tilt the bottom book until the top book just begins to slide. You perform five trials and measure the angles given in Table 3.
a. What is the average ∅ measured during the five trials?
b. What is the coefficient of static friction between the covers of the two books? Use the average ∅ found in part a.
c. You measure the top book's acceleration down the incline to be 1.3m/s². What is the coefficient of kinetic friction? Assume ∅ is the average value found in part a.
The average Ф was found to be 80.8 and the coefficient of static friction=0.40
define static friction ?
A force that holds an item at rest is called static friction. The definition of static friction is: The resistance people feel when they attempt to move a stationary object across a surface without actually causing any relative motion between their body and the surface they are moving the object across.
1.average Ф=21+17+21+18+19/5
=96/5
=80.8
2. The book is 31 N in mass. His hands and the book have a static friction coefficient of 0.40.
3. f=μxn
=1.3x0.4
=0.52
You can regard them as a single item when they are about to move together. Don't let the information you've been provided get mixed up; instead, utilise the static friction coefficient between box 1 and the floor
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A 7.1 kg, 5.0 m board is balanced about a point 2.0 m from right end of the board. A cube is sitting centered 0.5 m from the right end. A 3.5 kg cylinder is dropped from a height of 2.0 m onto the left end of the board and sticks to it. The dropped cylinder is going 6.26 m/s just before it hits the very left end of the board. (Assume the cube and cylinder are point masses.)
a) What is the mass of the cube sitting 0.5 m from the right end?
b) What is the cylinder’s angular momentum about the board/cube's pivot point just before
hitting the board?
c) What is the total angular momentum of all of the masses just after the collision?
d) What is the total moment of inertia of the board and two masses just after collision?
e) What is the board's angular velocity just after collision?
f) How fast is the cube (originally 0.5 m from the right end) going just after the collision?
This is due tomorrow night, so take your time, but please make sure that it is done well, I want to understand how you got your answers.
Answer:
Explanation:
To solve this problem, we can use the following equations:
Linear momentum: p = mv
Angular momentum: L = r x p
Total angular momentum: Ltotal = L1 + L2 + ... + Ln
Moment of inertia: I = mr^2
Angular velocity: w = L/I
Linear velocity: v = w x r
a) To find the mass of the cube sitting 0.5 m from the right end, we can use the equation p = mv. We know that p is the linear momentum of the cylinder just before hitting the board (which is equal to the mass of the cylinder times its velocity). We also know that the mass of the cylinder is 3.5 kg and its velocity is 6.26 m/s. Plugging these values into the equation gives us:
p = (3.5 kg)(6.26 m/s) = 22.01 kg m/s
We can use this value for the linear momentum of the cylinder to find the mass of the cube. Since the board is balanced about a point 2.0 m from the right end, the cube is 0.5 m from the pivot point and the cylinder is 2.5 m from the pivot point. This means that the cube and the cylinder have equal and opposite linear momentum about the pivot point. Therefore, the mass of the cube is equal to the mass of the cylinder, which is 3.5 kg.
b) To find the angular momentum of the cylinder just before hitting the board, we can use the equation L = r x p. We know that r is the distance from the pivot point to the center of mass of the cylinder (which is 2.5 m) and p is the linear momentum of the cylinder (which we just found to be 22.01 kg m/s). Plugging these values into the equation gives us:
L = (2.5 m) x (22.01 kg m/s) = 55.03 kg m^2/s
This is the angular momentum of the cylinder just before hitting the board.
c) To find the total angular momentum just after the collision, we need to find the angular momentum of the board and add it to the angular momentum of the cylinder. We can use the equation Ltotal = L1 + L2 + ... + Ln to do this. Since the board is balanced about a point 2.0 m from the right end, its angular momentum is equal to the mass of the board times the distance from the pivot point to the center of mass of the board times the velocity of the board. We know that the mass of the board is 7.1 kg, the distance from the pivot point to the center of mass of the board is 2.5 m, and the velocity of the board is 6.26 m/s (which is the same as the velocity of the cylinder just before hitting the board). Plugging these values into the equation gives us:
Ltotal = (7.1 kg)(2.5 m)(6.26 m/s) + 55.03 kg m^2/s = 122.64 kg m^2/s
This is the total angular momentum just after the collision.
d) To find the total moment of inertia just after the collision, we need to find the moment of inertia of the board and add it to the moment of inertia of the cylinder. We can use the equation I = mr^2 to find the moment of inertia of each object. For the board, we know that m is the mass of the board (which is 7.1
Two satellites of masses m1 and m2 orbit a planet of mass M in circular orbits. The satellites travel in opposite directions with speeds v1 and v2. Their orbital radii are R1 and R2, respectively. Assume M>>m2>m1. What is the ratio of the speeds v1/v2?
The ratio of the speeds V_1/V_2 =√(R_2/R_1 )
From the question, we have
Orbital speed is,
V=√(GM/R)
Where h= gravitational constant
r= radius of orbit
M= mass
⇒V_1=√(GM/R_1 ) *V_2
⇒V_1/V_2=√(GM/R_2 )
⇒V_1/V_2 =√(R_2/R_1 )
The ratio of the speeds V_1/V_2 =√(R_2/R_1 )
Orbital speed :
The speed at which one body orbits the other body is known as the orbital velocity. The term "orbit" refers to an object's consistent circular motion around the Earth. The distance between the object and the earth's center determines the orbit's velocity. The gravitational pull between the planet and the Sun must alter if the planet's distance from the Sun changes as it orbits. The acceleration of the planet must rise, leading to a higher orbital speed, if the force that the Sun exerts on the planet increases (as the planet gets closer).
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Based on many surveys of the average density of matter in the universe (regular matter and dark matter), astronomers now conclude that the average density of the universe is
a. less than the critical density
b. exactly equal to the critical density
c. more than the critical density
d. essentially equal to zero
e. so great that the universe will experience a "big crunch" before the Sun becomes a red giant
b.
The answer is B i.e., exactly equal to the critical density.
What is critical density?
"Critical density" is the average density of matter required for the universe to stop expanding after an infinite amount of time. The critical density universe is said to be flat.
In General Relativity, Einstein showed that the gravitational effects of matter should bend the space around it. In a matter-filled universe, both its overall shape and fate are determined by the density of matter contained.
If the universe has a high matter density (a closed universe), self-gravity will stop the expansion and slow it down until it eventually collapses again. In a closed universe, locally parallel rays converge to a very distant point. This is called spherical geometry.
If the universe has a low matter density (an open universe), there is not enough self-gravity to stop the expansion, and the universe will continue to expand forever (albeit at a slower and slower rate). Finally, in an open universe, locally parallel rays diverge. This is called hyperbolic geometry.
There is a universe where parallel rays remain parallel, balanced by a knife blade between a high matter density universe and a low matter density universe. This is called flat geometry and its density is called "critical density". In a critical density universe, it takes an infinite amount of time to stop expanding.
Therefore, The answer is B i.e., exactly equal to the critical density.
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5) The average speed of a sailing ship in the 1700's was about 15m/s. It would take a letter
about 3 months to travel from England to the American colonies. Based on this information,
what distance would the letter have traveled to reach America from England?
Answer:time in seconds spent for traveling=3×30×24×60×60
. = 7776000 seconds
distance= velocity× time.
. =15×7776000
. =116640000
. =116640km
Explanation:
What is the voltage across and the current through each parallel resistor if the total
voltage is 12 V and the total resistance is 550Ω? There are four resistors, all of equal
value.
Answer: In a circuit with parallel resistors, the voltage across each resistor is the same, and the total resistance is equal to the reciprocal of the sum of the reciprocals of the individual resistances.
Since the total resistance is 550Ω and there are four resistors of equal value, the value of each resistor is 550Ω / 4 = 137.5Ω.
Since the voltage across each resistor is 12V and there are four resistors, the voltage across each resistor is 12V / 4 = 3V.
The current through each resistor can be found using Ohm's law, which states that the current through a resistor is equal to the voltage across the resistor divided by the resistance.
Thus, the current through each resistor is 3V / 137.5Ω = 0.0218A.
So, the voltage across each resistor is 3V, and the current through each resistor is 0.0218A.
The voltage across and the current through each parallel resistor is respectively 12 V and 0.384 amp.
What is electric current?A stream of charged particles, such as electrons or ions, travelling through an electrical conductor or a vacuum is known as an electric current. The net rate of electric charge flowing through a surface or into a control volume is how it is calculated.
Given that:
the total voltage is 12 V.
the total resistance is 550Ω.
The resistance of every resistor = 500/4 Ω = 125 Ω.
As they are connected in parallel combination, the equivalent resistance of them = 125/4 Ω
=31.25 Ω.
As they are connected in parallel combination, the voltage across each resistor is same and it is 12 Volt.
And the current through each parallel resistor = V/R
= 12/31.25 amp
=0.384 amp.
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A 30 kg boy pushes on a 15 kg sled with for force of 20 N for 5 seconds. What is the magnitude of the impulse to the 15 kg sled?
Answer:
Below
Explanation:
Find acceleration of sled
F = ma
20 = 15 a shows a = 1.33 m/s^2
Find final velocity
v = at = 1.33 (5 ) = 6.666 m/s
change in momentum = mv2-mv1 = impulse = 15 * 6.666 - 0 = 100 kg m/s
I think it might be easier to just say F *Δ t = 20 * 5 = 100 N s = 100 kg m/s