"A line goes through the points (1, -10) and (-3, -2). Write the equation of the line in slope-intercept form, then find the x-intercept of the line. Show your work algebraically for full credit."

Answers

Answer 1

Slope

[tex]\frac{-10-(-2)}{1-(-3)}=-2[/tex]

Equation

[tex]y+10=-2(x-1)[/tex]

x-intercept

The x-intercept is when y=0.

[tex]10=-2(x-1)\\\\-5=x-1\\\\x=-4[/tex]

So, the x-intercept is (-4, 0).


Related Questions

The graph of y = f (x) is given. Graph the indicated function.Graph y = f (-x) - 4

Answers

Note the - sign in the evaluation of f(x), which changes the function directly, and the term -4 indicates a displacement vertically (down), but the graph goes up because of the sign -, therefore, the only option with these conditions is option b.

The correct answer is option b.

Find the x intercepts of the graph of the function.

g(x)=1/4(x-6)(x-3). Hint x intercepts happen when g(x)=0.

Answers

The x intercepts of the function given in the question will be equal to x = 6 and x = 3.

A function may be defined as an entity in which for one value of input there is only one value of output. The input value is the value of x variable, or the independent variable and the output value is the value of y variable or the dependent variable. For example, f(x) = y = x + 2, in this function for the value of input x = 1 the value of output is y = 3. The x intercept of a function may be defined as the point on the graph at which the line of function crosses the x axis. For finding the x intercept the y value or the value becomes zero. We are given the function g(x) = (1/4) (x - 6) (x - 3)

Now, g(x) = 0

(1/4) (x - 6) (x - 3) = 0

=> (x - 6) (x - 3) = 0

=> x = 6 and x = 3

Therefore, x intercepts are x = 6 and x = 3.

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hey what is 159 x 26

Answers

Answer = 4134 Explanation: you could use a calculator however if it’s a non calculator test you could just use the column method as shown in the picture

Factor the following trinomial.
9x² + 30x + 25

Answers

The factor of the trinomial 9x² + 30x + 25 is (3x + 5).

What is Factoring Trinomials?

When you factor a trinomial, you change an algebraic expression from a trinomial to a binomial. ax² + bx + c, where a and b are coefficients and c is a constant, is the general expression for a trinomial, which is a polynomial with three terms.

Given trinomial: 9x² + 30x + 25

Factoring the trinomial, we get

9x² + 30x + 25

9x² + 15x + 15x + 25

3x(3x + 5) + 5(3x + 5)

(3x + 5)²

Therefore, (3x + 5) is the factor of the given trinomial.

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Write a problem that could be solved by finding 5/8 divided by 2/5.

Answers

Answer:107/56 is the answer

Ariya likes to play golf. The number of times per year that she plays depends on the price of playing a round of golf, Ariya's income, and the price of other types of entertainment-in particular, the price of going to a movie instead of playing golf. The three demand schedules in the following table show how many rounds of golf per year Ariya will demand at each price per round under three different scenarios. In scenario D1, Ariya's income is $50,000 per year and movies cost $9 each. In scenario D2, Ariya's income is also $50,000 per year, but the price of seeing a movie rises to $11. And in scenario D3, Ariya's income goes up to $70,000 per year, while movies cost $11.
Scenario
Income per year
Price of movie ticket
Price of Golf
$50
$35
$20
D1
$50,000
$9
15
25
40
D2
$50,000
$11
Quantity Demanded
10
15
20
D3
$70,000
$11
15
30
50

Answers

Answer:

Using the data under D1 and D2, calculate the cross elasticity of demand for golf at all three prices. (To do this, apply the midpoints approach to the cross elasticity of demand.) At $50, cross elasticity = -2.40 ± 0.05At $35, cross elasticity = -3.00 ± 0.05At $20, cross elasticity = -4.00 ± 0.05Is the cross elasticity the same at all three prices? No. Are movies and golf substitute goods, complementary goods, or independent goods? Complementary goods.b. Using the data under D2 and D3, calculate the income elasticity of demand for golf at all three prices. (To do this, apply the midpoints approach to the income elasticity of demand.) At $50, income elasticity of demand = 1.40 ± 0.05At $35, income elasticity of demand = 2.33 ± 0.05At $20, income elasticity of demand = 3.00 ± 0.05Is the income elasticity the same at all three prices? No. Is golf an inferior good? No, it is a normal good.

The required statement is given as the data tends to the normal good.

What is Statistic?

Statistics is the study of mathematics that deals with relations between comprehensive data.

Calculate the cross elasticity of demand for golf at each of the three prices using the information under D1 and D2.

At $50, the cross elasticity is equal to -2.40 ± 0.05;
At $35, it is - 3.00± 0.05;
At $20, it is - 4.00 ±0.05.
No golf and movies complementary, independent, or alternative goods complementing products b.

Calculate the income elasticity of demand for golf at each of the three prices using the information under D2 and D3.
At $50, the income elasticity of demand is equal to 1.40±0.05
At $35, it is 2.33± 0.05
At $20, it is 3.00± 0.05

Thus, the required statement is given as the data belong to the normal good.

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How to simplify:
[tex]\frac{5}{2\sqrt{5} }[/tex]

My textbook says the answer is [tex]\frac{\sqrt{5} }{2}[/tex], but I don't know to get there.
Someone pls help

Answers

hmmm first of all, let's keep in mind that any expression multiplied by 1 is always the same expression

[tex]12\cdot 1=12\qquad 13567\cdot 1=13567\qquad spaghetti\cdot 1=spaghetti[/tex]

and so on.

now, hmm 1 can be expressed as a rational, 1/1 = 1, but but but, we can really express it as

[tex]\cfrac{9999}{9999}\implies \cfrac{7857}{7357}\implies \cfrac{\sqrt[11]{1375}}{\sqrt[11]{1375}}\implies \cfrac{spaghetti}{spaghetti}\implies \cfrac{lettuce}{lettuce}\implies \text{\Huge 1}[/tex]

so let's do the so-called rationalizing of the denominator, we can also do it with the numerator btw, but we only need it for the denominator right now, by multiplying for 1 :), 1 is Da Bomb baby!!

[tex]\cfrac{5}{2\sqrt{5}}\cdot \text{\LARGE 1}\implies \cfrac{5}{2\sqrt{5}}\cdot \cfrac{\sqrt{5}}{\sqrt{5}}\implies \cfrac{5\sqrt{5}}{2\sqrt{5^2}}\implies \cfrac{5\sqrt{5}}{2(5)}\implies \cfrac{5\sqrt{5}}{10}\implies {\Large \begin{array}{llll} \cfrac{\sqrt{5}}{2} \end{array}}[/tex]

Which decimal is equivalent to39?

Answers

Answer: is 7

Step-by-step explanation: Its 7 cuz 14 weeks

Question - For the functions f(x) = 5x and g(x) = 4x − 5, find (f o g)(x) and (g o f)(x)
provide your answer.

(f o g)(x)= , (g o f)(x)=​

Answers

54(x) I’m just asking you what I can do for you to come get my nails toes and eyebrows waxed lol I need you more yesterday I need a pair for me to do so I’m going on the top of the hair and then I’m bout to go get my auntie and them I will be home by myself

5 is to 7 as 15 is to x.

Answers

Answer:

x = 21

Step-by-step explanation:

To get your answer, you can turn these to fractions: 5/7 = 15/x

5 * 3 = 15

7 * 3 = x

x = 21

ANSWER FAST: 4 thumb drives and 1 compact disk have a total capacity of 18 gigabytes. 3 compact disks and 4 thumb drives have a total capacity of 22 gigabytes. find the capacity 1 thumb drive and the capacity of 1 compact disk.

Answers

Capacity of 1 thumb drives = 4 gigabytes.

Capacity of 1 compact disk = 2 gigabytes.

What is linear expression?

A linear expression is an algebraic statement where each term is either a constant or a variable raised to the first power.

Let capacity of a thumb dives = x

And, Capacity of a compact disk = y

Then, For first condition;

''4 thumb drives and 1 compact disk have a total capacity of 18 gigabytes.''

We can formulate;

4x + y = 18  .... (i)

And, For second condition;

'3 compact disks and 4 thumb drives have a total capacity of 22 gigabytes.'

We can formulate;

4x + 3y = 22 .... (ii)

Solve the equation (i) and (ii) we get;

Subtract (ii) by equation (i) we get;

2y = 4

y = 2

And, 4x + 2 = 18

4x = 16

x = 4

So, Capacity of 1 thumb drives = 4 gigabytes.

Capacity of 1 compact disk = 2 gigabytes.

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19. Write an ordered pair for the point in Quadrant II, that is 8 units away from the point Q
(0.75 -3.25) on a coordinate plane.

Answers

An ordered pair of point in Quadrant II is 8 units away from this point, the resulting point will be (-7.25, 4.25)

In this question, we need to find an ordered pair for the point in Quadrant II, that is 8 units away from the point Q(0.75 -3.25) on a coordinate plane.

If we have a coordinate point (x, y) in Quadrant ||, if the coordinate is 8 units away, the resulting coordinate will be expressed as (x - 8, y + 8)

Given the point Q(0.75, -3.25) on the coordinate  the plane, if a point in  Quadrant II is 8 units away from this point, the resulting point will be (0.75 - 8, -3.25 + 8) which is (-7.25, 4.25)

Therefore, an ordered pair a point in Quadrant II is 8 units away from this point, the resulting point will be (-7.25, 4.25)

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Please help I’ll mark you as brainliest if correct!!

Answers

Answer:

14, 9, 16

Step-by-step explanation:

from 3 to 10, you add 7

from 10 to 5, you minus 5

from 5 to 12, you add 7

from 12 to 7, you minus 5

so the pattern is add 7, minus 5

7 plus 7 is 14

14 minus 5 is 9

9 plus 7 is 16

If the price of cord of firewood starts at $255 with a quantity supplied of 300 cords, then rises to $348 per cord, what is the new quantity supplied at this price? Assume the slope of the supply curve is 0.75. Round your answer to the nearest cord. A cord of firewood is a stack of wood 4 feet high x 8 feet long x 4 feet deep.

Answers

The new quantity supplied when the price is $348 per cord is  424.

What is the new quantity supplied?

The supply curve is a graph that shows the relationship between price and quantity supplied. The supply curve has a positive slope.

The slope of the supply curve is the ratio of the change in the value of price divided by the change in the value of the quantity supplied.

Slope = change in price / change in quantity supplied

0.75 = ($348 - $255) /  change in quantity supplied

0.75 = $93 /  change in quantity supplied

change in quantity supplied = 93 / 0.75 = 124

The new quantity supplied = 300 + 124 = 424

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Which pair of angels are alternate exterior angles
○ <1and <2
○ <1and<7
○ <2and<7
○ <2and<5

Answers

∠2 and ∠7 are a pair of angels are alternate exterior angles .

A transversal that crosses two parallel lines results in alternate exterior angles.

They form two pairs of alternate outside angles since they are situated "outside" the two parallel lines but on different sides of the transversal (four total angles).When a third line, a transversal, separates two lines, the expression "alternating exterior angles" is frequently used. The alternate exterior angles theorem states that pairs of alternate exterior angles are congruent if k and l are parallel. A: One of two internal angles inside the two intersecting lines, also known as an alternate internal angle. B: One of two angles with distinct vertices that are on opposite sides of a transversal at the intersection of two other lines.

So from the given figure the pairs of external alternate angles are:

∠1 and ∠8

∠2 and ∠7

Hence of the given options , ∠2 and ∠7 is the required external alternate angles .

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If the ratio of girls to boys on the trackteam is 5 to 6, which of these showspossible numbers of girls to boys onthe track team?A 24 girls, 20 boysB 50 girls, 56 boysC 60 girls, 50 boysD 20 girls, 24 boys

Answers

The ratio of 5 to 6 means that for every 5 girls on the track team there are 6 boys.

So, if there are n groups of 5 girls, there should be also n groups of 6 boys. Thus, we have the proportion:

[tex]\frac{\text{ number of girls}}{\text{ number of boys}}=\frac{5}{6}[/tex]

Then, let's check each item to find out which one shows possible numbers of girls to boys on the track team.

A. 24 girls, 20 boys

[tex]\frac{\text{ number of girls}}{\text{ number of boys}}=\frac{24}{20}=\frac{24\colon4}{20\colon4}=\frac{6}{5}\ne\frac{5}{6}[/tex]

B. 50 girls, 56 boys

[tex]\frac{\text{ number of girls}}{\text{ number of boys}}=\frac{50}{56}=\frac{50\colon10}{56\colon10}=\frac{5}{5.6}\ne\frac{5}{6}[/tex]

C. 60 girls, 50 boys

[tex]\frac{\text{ number of girls}}{\text{ number of boys}}=\frac{60}{50}=\frac{60\colon10}{50\colon10}=\frac{6}{5}\ne\frac{5}{6}[/tex]

D. 20 girls, 24 boys

[tex]\frac{\text{ number of girls}}{\text{ number of boys}}=\frac{20}{24}=\frac{20\colon4}{24\colon4}=\frac{5}{6}[/tex]

Therefore, option D is correct.

Adam is baking 4 pizzas. Each pizza is a rectangle. It takes Adam 35 minutes to bake the pizzas. He divides each pizza into the equal-size square slices shown.

Answers

Answer:

Step-by-step explanation:

Incomplete question.

You bought 6 tickets for $40 and wanted to know how many tickets you could get for $200,
you would write the following proportion:

Answers

Answer:

30

Step-by-step explanation:

200/40=5

5x6=30

therefore there are 30 tickets you could get with 400$

hope this helped

have a great day ^^

Answer:

30 tickets

Explanation:

One ticket can be represented as variable t.

Using t, we can set up an equation (proportion) using the given information:

[tex]6t = \$ 40[/tex]

Then, we can multiply both sides of the equation (proportion) by something such that the number of dollars on the right side is $200.

[tex]6t \ = \ \$ 40 \\\times 5 \ \ \ \times 5[/tex]

[tex]30t = \$ 200[/tex]

So, we can get 30 tickets for $200.

What is the range of the function f(x) = |x – 5| – 3?

R: {f(x) ∈ ℝ | f(x) > 2}
R: {f(x) ∈ ℝ | f(x) < 2}
R: {f(x) ∈ ℝ | f(x) ≥ –3}
R: {f(x) ∈ ℝ | f(x) ≤ –3}

Answers

Answer:  Choice C

Reason:

The smallest |x-5| can get is 0 since the result of an absolute value is never negative (because it represents distance).

So the smallest f(x) = |x-5|-3 can get is 0-3 = -3

f(x) = -3 or f(x) > -3 are the only two options for the output f(x).

Condense that into [tex]f(\text{x}) \ge -3[/tex] to arrive at choice C as the final answer.

The fancy notation of f(x) ∈ ℝ translates to "f(x) is a real number".

If you were to graph this using a tool like Desmos, then notice how the lowest point occurs when y =  -3

See the diagram below.

Answer:

R: {f(x) ∈ ℝ | f(x) ≥ –3}

Step-by-step explanation:

I got it right on the test.

At a sale, shirts were sold for $15 each. This price was 20% off their original price. What was the original price?

Answers

Answer:

The original price was 18 dollars.

Step-by-step explanation:

Givens

Final price = 15 dollars

Discount = 20%

Original Price = x

Formula

x = 15 + 20/100 15

Solution

x = 15 + 300/100                     Multiply 20 * 15. Divide by 100

x = 15 + 3

x = 18

Trey buys a bag of cookies that contains 4 chocolate chip cookies, 6 peanut butter cookies, 7 sugar cookies and 7 oatmeal cookies.What is the probability that Trey reaches in the bag and randomly selects a sugar cookie from the bag, eats it, then reaches back in the bag and randomly selects an oatmeal cookie? Give your answer as a fraction, or accurate to at least 4 decimal places.

Answers

Solution

The total number nof cookies in the bag is:

[tex]4+6+7+7=24\text{ cookies}[/tex]

- Thus, we can write the probabilities of choosing any of the cookies are given as:

[tex]\begin{gathered} P(\text{chocolate chip)}=\frac{4}{24} \\ \\ P(\text{Peanut Butter)}=\frac{6}{24} \\ \\ P(\text{Sugar Cookies)}=\frac{7}{24} \\ \\ P(\text{Oatmeal)}=\frac{7}{24} \end{gathered}[/tex]

- Now, let us analyze Trey's random choices

Choice 1:

He chose a sugar cookie at first.

- Thus, the probability of this choice is

[tex]P(\text{Sugar Cookies})=\frac{7}{24}[/tex]

Choice 2:

- He chose an oatmeal cookie in the second choice.

- But he already had one cookie before this choice, thus, the total number of cookies is one less. That is, 23 not 24.

- Thus, the probability of choosing the oatmeal cookie is given as:

[tex]P(\text{Oatmeal)}=\frac{7}{23}[/tex]

- Because these choices do not interfere with one another (i.e. they are mutually exclusive), we can apply the AND probability formula to calculate the probability that Treys chose a Sugar Cookie first, and then an Oatmeal cookie next.

- The AND probability is given as

[tex]P(A\text{ AND }B)=P(A)\times P(B)[/tex]

- Thus, we can find the probability that Trey chooses Sugar Cookies first and Oatmeal Cookie next as follows:

[tex]\begin{gathered} P(\text{Sugar Cookies AND Oatmeal)}=\frac{7}{24}\times\frac{7}{23} \\ \\ P(\text{Sugar Cookies AND Oatmeal)}==\frac{49}{552} \end{gathered}[/tex]

Final Answer

The answer is

[tex]P(\text{Sugar Cookies AND Oatmeal)}==\frac{49}{552}[/tex]

I dont understand any of these functions please help on all!

Answers

1.The slope -intercept form of the function is  y = 7x

2.The slope -intercept form of the function is y = x - 8

3.The slope -intercept form of the function is y = -2x +9

4.The slope -intercept form of the function is [tex]y = \frac{1}{3}x+9[/tex]

5.The slope -intercept form of the function is  y = 0.5x - 1.5

6.The slope -intercept form of the function is   y = 3x - 12

How is the slope -intercept form calculated?

1. The slope -intercept form of the equation of the function is  y = 7x

Slope = m

[tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\m =\frac{0+7}{0+1} \\\\m= 7[/tex]

Substituting point (-1,-7)  and m in the slope-intercept form of the equation,

y = mx+ c   ----(1)

-7 = 7(-1) + c

c = 7 -7

c = 0

Substituting m and c in  (1)

y = 7x

2. The slope -intercept form of the equation of the function is y = x - 8

Slope = m

[tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\m =\frac{-8+17}{0+9} \\\\m= \frac{9}{9} =1[/tex]

Substituting point (-9,-17)  and m in the slope-intercept form of the equation,

y = mx+ c   ----(1)

-17 = (-9) + c

c = -17 +9

c = -8

Substituting m and c in  (1)

y = x - 8

3. The slope -intercept form of the equation of the function is y = -2x +9

Slope = m

[tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\m =\frac{5-9}{2-0} \\\\m= \frac{-4}{2} =-2[/tex]

Substituting point (0,9)  and m in the slope-intercept form of the equation,

y = mx+ c   ----(1)

9 =  -2 (0) + c

c = 9

Substituting m and c in  (1)

y = -2x +9

4.The slope -intercept form of the equation of the function is  [tex]y = \frac{1}{3}x+9[/tex]

Slope = m

[tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\m =\frac{8-7}{-3+6} \\\\m= \frac{1}{3}[/tex]

Substituting point (0,9)  and m in the slope-intercept form of the equation,

y = mx+ c   ----(1)

9 =  1/3 (0) + c

c = 9

Substituting m and c in  (1)

[tex]y = \frac{1}{3}x+9[/tex]

5. The slope -intercept form of the equation of the function is

y = 0.5x - 1.5

Slope = m

[tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\m =\frac{1-0.5}{5-4} \\\\m= \frac{0.5}{1}= 0.5[/tex]

Substituting point (5,1)  and m in the slope-intercept form of the equation,

y = mx+ c   ----(1)

1 =0.5 (5) + c

1 -2.5 = c

c = - 1.5

Substituting m and c in  (1)

y = 0.5x - 1.5

6. The slope -intercept form of the equation of the function is y = 3x - 12

Slope = m

[tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\m =\frac{9-3}{7-5} \\\\m= \frac{6}{2}\\\\m= 3[/tex]

Substituting point (5,3)  and m in the slope-intercept form of the equation,

y = mx+ c   ----(1)

3 =3(5) + c

3 -15 = c

c = - 12

Substituting m and c in  (1)

y = 3x - 12

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look at the image

answer options are:
(a) and (b)
Neither
Only (a)
Only (b)

Answers

Answer: (a) only

Step-by-step explanation:

For there to be inverse proportion, the product of x and y must be constant.

help video
Brooklyn is trying to pick out an outfit for the first day of school. She can choose from
6 pairs of pants, 8 t-shirts, 3 sweaters or hoodies, and 5 pairs of shoes. How many
different outfits does Brooklyn have to choose from?
Answer:
Submit Answer
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attempt 1 out of 2

Answers

Answer:

There are 16 ways in which Danny can mix and match all his outfits. You can determine this by multiplying. 4 x 2 x 2. Danny has 4 shirts. He can wear each with two different pants, so 4 x 2 giving 8 different shirt/pant combinations. Now each combination can be worn with two different pairs of shoes, so 8 x 2 giving 16 total combinations of shirt, pants and shoes.

Step-by-step explanation:

How many outfits does that make? First he has to decide on a pair of pants and he has 4 different choices. For each of those choices he has a choice of 7 ...

you would times each one for example 6 x8 6x3 6x5 and 8x6 8x3 8x5 and 3 x6 and so forth

1. evaluate (a-2b)^3 when a = -3 and b = - 1/2 enter the answer
2. evaluate (jk - 1) ÷ j when j = -4 and k = -0.9 enter as a decimal
3. evaluate -|a+b| /fraction line/ 2-c when a =1 7/8 , b = -1 , and c = -4 enter as a simplified fraction
4. evaluate (w^2 /fraction line/ x - 3) ÷ 10 multiplied by z when w = -9 , x = 2.7 , and z= -2/5 enter as simplified mixed number
5. evaluate (2a - 1/3) ÷ b/15 when a = -2/5 and b = -8.25 enter as simplified mixed number

Answers

The corresponding values of expressions 1, 2,3,4 and 5 when evaluated are -2, -0.65, -7/48, 67 1/2 and 2 2/33

How to evaluate algebraic expressions?

1. To evaluate (a-2b)^3 when a = -3 and b = - 1/2,  put a = -3 and b = - 1/2 into the expression (a-2b)^3:

(a-2b)^3 = ( -3 - 2(-1/2) )

              = (-3 + 1) = -2

2. To evaluate (jk - 1) ÷ j when j = -4 and k = -0.9, put  j = -4 and k = -0.9 into the expression (jk - 1) ÷ j:

(jk - 1) ÷ j = ( -4(-0.9) - 1) ÷ (-4)

              = (3.6 -1) ÷ (-4) = (2.6) ÷ (-4) = -0.65

3. To evaluate -|a+b| / 2-c when a =1 7/8 , b = -1 , and c = -4 , put b = -1 , and c = -4 into the expression -|a+b| / 2-c:

-|a+b| / 2-c  = -|1 7/8 + (-1)|/ 2 -(-4)

                  = -| 7/8 | / 6 = -7/48

4. To evaluate (w^2 / x - 3) ÷ 10 multiplied by z when w = -9 , x = 2.7 , and z= -2/5:

(w^2 / x - 3) ÷ 10z = ((-9)²/ 2.7 -3)  ÷ 10(-2/5)

                            = (81/(-0.3))  ÷  (-4) = -270/-4 = 67 1/2

5. To evaluate (2a - 1/3) ÷ b/15 when a = -2/5 and b = -8.25:

(2a - 1/3) ÷ b/15 = (2(-2/5) - 1/3) ÷ -8.25/15

                          = (-4/5 - 1/3) ÷ (-11/20) = -17/5 ÷ (-11/20) = 2 2/33

Therefore, the expressions 1, 2,3,4 and 5 evaluate to -2, -0.65, -7/48, 67 1/2 and 2 2/33 respectively

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Can someone please help me with this, it’s geometry by the way

Answers

Answer:

congruent: a° and c°; d° and b°

Supplementary: c° and b°; a° and b°; a° and d°; c° and d°

Step-by-step explanation:

Mr. Jackson earns $10 per hour working in an electronics store. In addition, he earns 5% commission on all of his computer sales. Last week, he worked 5 days from 9 am to 3 pm and sold $3,100 worth of computers. What was Mr. Jackson's total income for the week?

Answers

Refer to the picture below you.

Chelsy wants to buy a new pair of jeans in one store the jeans are selling for 1/5 off the original price of $70 in second store the same jeans are selling for 1/3 off the original price $81 chelsy wants to buy the cheaper pair of jeans in which store should chelsy buy the jeans and how much will they cost

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iN linear equations, store 1 jeans is cheaper than store 2.

What are instances of linear equations?

Ax+By=C is the usual form for two-variable linear equations. A standard form linear equation is, for instance, 2x+3y=5.When an equation is given in this format, finding both intercepts is rather simple (x and y).When attempting to solve systems involving two linear equations, this form is also quite helpful.

one store the jeans are selling for 1/5 off the original price of $70

              $70 * 1/5  = 14

second store the same jeans are selling for 1/3 off the original price $81

                 $81 * 1/3  = 27

So, store 1 jeans is cheaper than store 2.

Learn more about linear equation

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How to find the slope of a graph? 9 and 10

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9. To draw the rise, you can follow these steps:

- Identify a point on the line. In this case, this can be:

[tex](-3,1)[/tex]

- Draw a vertical line that rises from that point. See the picture below:

10. To draw the line that represents the run, you need to Draw a horizontal line that goes from the endpoint of the line that represents the rise and extend it until it touches the function. See the picture below:

Therefore, the answers are (See the picture):

i need help plssssssssssddd

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Answer:

see explanation

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

(a)

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 3, 0) and (x₂, y₂ ) = (0, - 2) ← 2 points on the line

m = [tex]\frac{-2-0}{0-(-3)}[/tex] = [tex]\frac{-2}{0+3}[/tex] = - [tex]\frac{2}{3}[/tex]

(b)

the y- intercept is the point on the y- axis where the line crosses, that is

y- intercept c = - 2

(c)

y = - [tex]\frac{2}{3}[/tex] x - 2 ← equation of line

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