Initial energy equals (M/2)*Vo2 = 12.80 J.
At 4.7 m and V = 5 m/s, total energy equals (M/2)
*5^2 + M*g*4.7 = 1.25 + 4.61 J
a portion of the energy in a ball LOST = (12.80-5.86)/12.80 \s= 0.542
We are informed that a plastic ball with a mass of 0.1 kg is tossed into the air as an example of energy conservation. It starts off at a height of three meters and a speed of 10 meters per second. Now moving at three meters per second. We are interested in learning how much of its initial energy has been lost through friction. We now know that the total mechanical energy is constant for an isolated system. Thus, the change in gravitational potential energy descends to you along with the change in kinetic energy data K. additionally the data on N. G. Lost to air friction Zero is equal to E. F. Keep in mind that the gravitational potential energy you I is zero at the beginning.
It follows that either their energy changes or that the energy lost to friction belt E. F. is equal to minus daughter. Kay, without a doubt, which is without uh-huh. Mm. V squared divided by the starting speed is the final speed. M. G. H. plus V not squared Additionally, the ball's initial energy is entirely kinetic. Since this is a half-squared north, the lost energy delta E. F. is the proportion of the original energy that is reflected and lost.
This therefore equals half of M. Squared into the not minus V squared into the not minus to G. H. multiplied by half. squared M Vinod Thus, this fraction becomes the square of the starting speed. We not squared minus the final speed squared square V squared minus twice the acceleration brought on by gravity, G times the height of the ball. H centered over Vinod. Therefore, if we enter our numbers here, this becomes 10 m/s squared times three m/s squared times two, or 9.81 m/km2 times. three meters tall times 10 meters per second squared.
As a result, 32 321 the amount of energy that is lost when there is an uncertainty about e f over e I This is the percentage that is lost due to air friction, or 32.1 percent.
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A cyclist with a mass of 55 kg coasts on level ground at 32,25 m·s -1 . He free wheels up an incline of 30° to the horizontal and grabs an overhanging tree branch. What is the velocity of the cyclist when he grabs the branch?
The velocity of the cyclist when he grabs the branch is 36.1 m/s.
What is the final velocity of the cyclist?The final velocity of the cyclist is calculated as follows;
The final vertical velocity of the cyclist will be smaller than the initial vertical velocity due to opposing force of gravity.
Final vertical velocity of the cyclist, Vy = vi - vi sinθ
Vy = 32.25 - 32.25 sin(30)
Vy = 16.13 m/s
The final horizontal velocity will be constant.
Vx(final) = Vx(initial)
Vx = 32.25 m/s
Resultant final velocity = √Vx² + Vy²
Resultant final velocity = √(32.25² + 16.13²)
Resultant final velocity = 36.1 m/s
Thus, the final velocity of the cyclist will change when he grabs the overhanging tree branch.
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a jet plane is cruising at 300 m/sm/s when suddenly the pilot turns the engines up to full throttle. after traveling 4.1 kmkm , the jet is moving with a speed of 400 m/sm/s.
The direction of the net force acting on an object defines the direction of its acceleration. The acceleration of the plane is 8.75 m/s².
What is meant by acceleration ?Any procedure where the velocity varies exists directed to as acceleration. There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This exists because velocity exists both a speed and a direction.
The initial speed of a plane is [tex]$v_{i s}[/tex] = 300 m/s
Distance covered by plane is s = 4 km = 4000m
The final speed of the plane is [tex]$$v_{f s}[/tex] = 400 m/s
The acceleration of the plane.
Using kinematical equation v²[tex]{ }_{f s}[/tex] = v²[tex]{ }_{\text {is }}[/tex] + 2as
Substitute known values in the above equation, we get
400² = 300² + 2 a(4000)
simplifying the above equation, we get
400² -300² = 8000 a
a = 70000/8000
= 8.75 m/s²
Therefore, the acceleration of the plane is 8.75 m/s².
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A person expended 600J of work to move a 95N move a full wheelbarrow. How far was the wheelbarrow moved?
Answer:
6.3 m
Explanation:
Work = force X distance
600 = 95 x d
d = 600/95 = 6.3 m
suppose you are standing in an elevator that is accelerating. what does the acceleration have to be so that your weight feels tripled? assume the positive direction is upwards.
In order the weight feels tripled, the elevator should be moving upward with acceleration 2g m/s² or two times of gravitational acceleration.
The free body diagram is shown on the attached picture.
The scale will read the normal force.
Suppose the elevator is moving upward. Using the Newton's second law of motion:
∑F = m.a
N - w = ma
N = mg + ma
Suppose the elevator is moving downward.
w - N = ma
N = w - ma
N = mg - ma
Where:
m = mass
a = acceleration
g = gravitational acceleration
From the above 2 cases, in order the scale to read the measured weight higher than its actual weight, N should be greater than w, or N = mg + ma, or the elevator should be moving upward.
The weight feels tripled means N = 3 mg.
Hence,
3 mg = mg + ma
a = 3g - g = 2g
Therefore, in order the weight feels tripled, the elevator should be moving upward with acceleration 2g m/s²
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A weightlifter lifts a 200 Kg barbell 4m using 800W of power. How long did this take?
Answer:
9.8 seconds
Explanation:
Power = work / time
work = F * d = 200kg ( 9.81 m/s^2 ) * 4 m = 7818 J
800 W = 7818 J / t t = ~ 9.8 seconds
How do the masses of objects affect the strength of gravitational force?
Answer:
So as the mass of either object increases, the force of gravitational attraction between them also increases.
Explanation:
If the mass of one of the objects is doubled, then the force of gravity between them is doubled. If the mass of one of the objects is tripled, then the force of gravity between them is tripled.
Car distance after 5 seconds
If a car travelling at 15 m/s applies the brakes at time 0 seconds and slows down at - 2 m/s2 find the distance the car travels after 5 seconds.
69
69
69
69 44444444444444444444444444444444
A spring gets 3.0cm longer when a 1.5N weight hangs from it. Calculate the extension with a 6.0N weight?
Answer:
The extension of an elastic object when a force is applied, such as a spring, is described by Hooke's law: force = spring constant × extension.
In a closed system Mechanical Energy is constant
true or false
The answer is true!!!!!!!!!!!
a dragster gets to a peed of 112m/s over a distance of 300m from rest. Determine the acceleration of the dragster.
A dragster gets to a speed of 112 m/s over a distance of 300 m from the rest, then the acceleration will be 20.9 m/s².
What is Acceleration?The rate of change in an object's velocity with respect to time is known as acceleration in mechanics. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.
Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector quantity as well. The definition of acceleration is the change in velocity vector over a time interval divided by the time interval.
According to the question, the given values are :
Final velocity, v = 112 m/s.
Initial velocity, u = 0 m/s
Distance, s = 300 m.
Use the equation of motion,
v² - u² = 2as
112 ² - 0 = 2 (a)(300)
a = 12544/600
a = 20.9 m/s².
Hence, the acceleration of the dragster will be 20.9 m/s².
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Guys if anyone knows how to answer, please help me with this question
Answer:
V = a t
t1 = 15 / 9.8 = 1.53 sec time to reach 0 speed
t2 = t1 = 1.53 sec time to reach point thrown
t3 = 5 - 2 * 1.53 = 1.94 sec time to fall height of cliff
H = V0 t - 1/2 g t^2 time to fall height of cliff (if V0 positive)
V0 = -15 m/s since it will return to thrown height with speed thrown up
Signs chosen must be consistent
H = -15 * 1.94 - 1/2 9.8 * 1.94^2 = -47.5 m where H is height of cliff
The
Which is the CORRECT description of the sequence of energy transformations occurring in this system?
Answer:
Explanation:
(I) Electrical energy into sound energy. (ii) Heat energy into kinetic energy (or mechanical energy). (iii) Chemical energy into kinetic energy (or mechanical energy). (iv) Chemical energy into heat energy
help me on ixl describe ecosystem
Answer:
it is defined as the study of living things and their environment
When an engine works, energy is transferred from one form to another form in four stages. The energy wasted in each stage is 10%. Calculate the efficiency of the engine.
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The efficiency of the engine is 60%.
What is the efficiency of engine?The efficiency of a heat engine describes the amount of input energy converted into useful work.
It also entails the amount of useful work done by the engine. The greater the amount of useful work done by the engine, the greater the efficiency of the engine.
The efficiency of an engine ranges from 0 to 100%.
If there four stages in the energy conversion cycle, and 10% energy is wasted in each cycle, the total energy wasted in the four cycles is calculated as;
Total wasted energy = 4 x 10% = 40%
Efficiency of the engine = Useful energy = 100% - 40% = 60%
Thus, the efficiency of the engine is the useful work done by the engine.
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a mIssile is moving 1810 m/s at a 20.0 angle. it needs to hit a target 19,500 m away iin a 32.0 direction in 9.20 s. what is the magnitude of the acceleration that the engine must produce
A missile is moving 1810 m/s at a 20.0 angle. it needs to hit a target 19,500 m away in a 32.0 direction in 9.20 s. The acceleration that the engine must deliver is 112 meters per second.
What is acceleration?The term "acceleration" refers to the rate of change in the object's velocity in relation to time, and it is measured in meters per second (m/s). In most contexts, meters per second squared is the unit of measurement for acceleration.
Let us start by thinking about the component that is horizontal in the x direction.
The length of travel in a plane horizontal to the starting point.
x = 19,500 cos 32.0° m
Using the second equation of motion to determine acceleration along the horizontal axis in order to:
[tex]x = ut + 1/2at^2[/tex]
[tex]19,500 * (cos 32.0^0 = 0 + (1810* cos 20.0^o) *9.20+ 0.5*a *9.20^2[/tex]
a = 21.01 m/s²
The same may be said for the vertical direction.
The distance traveled in the upward and downward directions combined.
Y is the velocity in the vertical direction, and it is equal to 19,500 in 32.0° m.
u= 1810 sin 20.0° m/s
t = 9.20 s
For the purpose of determining acceleration along the vertical axis by using the second equation of motion, For the purpose of determining acceleration along the vertical axis by using the second equation of motion
[tex]y = ut +1/2at^2[/tex]
19,500 sin 32.0° = 0 + (1810 sin 20.0^o)* 9.20 + 0.5*a* 9.20^2
a = 109.6 m/s^2
The resultant acceleration
[tex]a^2 = (21.01)^2 + (109.6)^2[/tex]
a = 112 m/s²
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The resultant force acting on the van is 1500 N.
Calculate the magnitude of force X.
[assume X is the only horizontal force opposing the motion of the van]
If the resultant force acting on the van is 1500 Newtons, then the magnitude of Force X would be 1500 Newtons as X is the only horizontal force opposing the motion of the van.
What is Newton's second law?Newton's Second Law states that the resultant force acting on an object is proportional to the rate of change of momentum.
As given in the problem statement If the resultant force acting on the van is 1500 Newtons, then we have to find the magnitude of Force X,
The magnitude of the Force X = 1500 Newtons
Thus, the magnitude of the force X would be 1500 as it is the only force acting on the van.
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A 12100 kg railroad car is coasting on a level, frictionless track at a speed of 19. 0 m/s when a 4790 kg load is dropped onto it. If the load is initially at rest, find the new speed of the car and the % change of the kinetic energy.
The speed of the car when the load is dropped in it is 10.90 m/s.
Using the data given above:
Mass of the railroad car, m₁ = 12100kg
Mass of the load, m₂ = 4790kg
It can be assumed as the speed of the car, u₁ = 10 m/s
So, it is at rest, u₂ = 0
Here we assume the speed of the car be v
Using law of conservation of energy
Thus:
m1v1 + m2v2 = (m1v1)/ (m1 + m2)
= 12100*10 / 12100 + 4790
121000/16890
= 7.16 m/s
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How many ohms is the resistance of the electric heater connected to 220 V voltage
Answer:
44 ohms.
Explanation:
R for V (according to Ohm's law). This second formula is more frequently used in practice to calculate resistive heating, whereas the first formula has other, more general applications. As we might infer from the equation, the units of watts also correspond to amperes2 x ohms (A2 x Ω).
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3. The diagram shows a child's mobile which is supported from the ceiling by a length of nylon thread of negligible weight. AB is a uniform horizontal rod supported at S.
c) A third fish of weight 0.30 N is suspended from the middle of the rod. The thread supporting the mobile is moved along the rod so that the rod remains horizontal. On which side of the center of the rod is the thread now attached, left or right? Explain how you arrived at your answer.
Answer:
.12 * .12 = .0144 counterclockwise torque
.06 * .18 + W * .03 = .0108 + .03 W clockwise torque
W = (.0144 - .0108) / .03 = .12 N as requested
(.12 + .06 + .12) N = .30 N total weight supported by thread
C) Suppose now rod supported at middle
.12 * .15 = .018 N counterclockwise torque
.06 * .15 = .009 N clockwise torque
Obviously the thread must be moved closer (left) to .12 weight to increase the clockwise torque (other weights are in the middle of the rod
a person travels by car from one city to another with different constant speeds between pairs of cities. she drives for 40.0 min at 70.0 km/h, 16.0 min at 75.0 km/h, and 50.0 min at 40.0 km/h and spends 35.0 min eating lunch and buying gas.
The Average speed is 42.44 km/h ,the distance between cities is 99.02kmSpeed is the rate at which something or someone is moving.
The average speed of an object can be determined if you know the distance traveled and the time it took. Distance times speed is how speed is computed. In order to compute the units for speed, you must be aware of the units for both distance and time. Given that the distance in this example is measured in metres (m) and the duration is recorded in seconds, the units will be metres per second (m/s) For the purpose of calculating the other two, we require the other two (time, speed, or distance). To determine how long it will take to complete a journey, for example, information about the distance and speed of travel is needed.
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What's the Normal Force in Newtons for a 2,899 kg Warthog that Master Chief is driving while fighting off a horde of angry aliens? Assume the Halo installation the vehicle is on has an acceleration due to gravity of 10 m/s squared
(or same as Earth).
Answer:
-28990N
Explanation:
F = mass * acceleration = 2899kg * 10m/s^2 = -28990N (because it is a normal force applying pressure upward).
What force do you need to accelerate a car at 5m/s2 that has a mass of 3,000kg?
The force needed to accelerate a car at 5 m / s² that has a mass of 3,000 kg is 15 KN
F = m a
F = Force
m = Mass
a = Acceleration
m = 3000 kg
a = 5 m / s²
F = 3000 * 5
F = 15000 N
F = 15 KN
According to Newton's second law of motion, the force is equal to the rate of change of momentum of the object.
Therefore, the acceleration of the car is 15 KN
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an object has a mass of 10 kg and is pushed with a force of 2 N, how far did the object accelerate?
An object has a mass of 10 kg and is pushed with a force of 2 N the object acceleration is 0.2m/s².
Given;
m = 10 kg
F = 2N
by using Newton's second law of motion that is the formula of force
F = ma
a = F/m
a = 2/10
a = 0.2m/s²
What is acceleration?
An object is said to accelerate when its velocity changes. A change in the speed of an object can be an increase or decrease in speed or a change in direction of motion. Some examples of acceleration are a falling apple, the moon orbiting the Earth, or a car stopping at a traffic light. Using these examples, we can understand that when a moving object changes direction or increases or decreases speed, acceleration occurs.
The unit of acceleration is meter per second per second (m/s2).
There are 2 types of acceleration
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What will happen to acceleration of mass spring system if its mass is doubled?
explain mathematically and briefly
Answer:
If the mass is doubled, then acceleration will be halved.
Explanation:
That situation is described by Newton's Second Law of Motion. F is force, m is mass and a is acceleration. The math behind this is quite simple. If you double the force, you double the acceleration, but if you double the mass, you cut the acceleration in half.
According to Newton's Second law of Motion, the acceleration of the mass spring system will be halved if the mass of the spring system is doubled.
What is Newton's Second law of Motion?Newton's second law of motion states that when an external net force is applied on an object, the acceleration of the object is proportional to the net force which is applied on the object, and it also occurs in the same direction as the direction of applied force. The acceleration of an object is inversely proportional to the net force applied and acceleration is inversely proportional to the mass of the object.
This situation can be best described by Newton's Second Law of Motion. The second law of motion can be expressed by the equation:
F = m × a
where, F is force,
m is mass, and
a is acceleration
Mass of an object is inversely proportional to the acceleration of the body. If the mass of the spring system is doubled then the acceleration of the object will be reduced to half.
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What element is shown below?
Suppose that, while in a squatting position, you stand on your hands, and then you pull up on your feet with a great deal of force. You are applying a large force to the bottoms of your feet, but no matter how strong you are, you will never be able to lift yourself off the ground. Use your understanding of force and motion to explain why this is not possible.
Answer: The Earth's gravity is too strong.
Explanation: I don't have a full understanding, but probably the Earth is too strong. If you push yourself up, it'll feel difficult.
What’s The difference between oxygen and water.
100 POINTS
Answer:
Oxygen gas is two oxygen atoms bonded together, O2. Water, is one oxygen atom bonded to two different hydrogen atoms, H2O
Explanation:
block starts at the bottom of a ramp making an angle of θ with the horizontal, at initial speed v0 . as it slides up it slows due to gravity and kinetic friction, eventually coming to a stop. static friction is not large enough to hold it at res
The block has gravitational potential energy when it briefly comes to rest at the top of the ramp and starts with kinetic energy at the bottom. However, some of that energy is lost due to frictional effort. Use Newton's second law to determine the friction force on the block.
The work-kinetic energy theorem can be used to provide a solution to this issue. Start by calculating how far the block will travel up the ramp. The block has gravitational potential energy when it briefly comes to rest at the top of the ramp and starts with kinetic energy at the bottom. However, some of that energy is lost due to frictional effort.
You can use a free body diagram and Newton's second law to calculate the frictional force on the block. The frictional energy is calculated as the frictional force multiplied by the distance the block travels up the ramp.
The distance climbed up the ramp will also affect how much the gravitational potential energy changes. You can now generate kinetic energy.
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Brooke kicks a soccer ball with an initial horizontal velocity of 15 m/s off a 40-meter-high cliff and the soccer ball lands 60 meters away from the edge cliff. determine the final vertical velocity of the soccer ball.
The final vertical velocity of the soccer ball is 20 m/s.
We need to know about the projectile motion to solve this problem. The projectile motion is known as parabolic motion and the velocity is divided by 2 axes.
vox = vo cosA
voy = vo sinA
where vox is initial velocity of x axis, voy is initial vertical velocity, vo is initial velocity and A is the angle.
From the question above, the given parameters are
vox = 15 m/s
h = 40 m
x = 60 m.
The time taken of horizontal motion will be
x = vox . t
60 = 15 . t
t = 4 s
By using the uniform motion, where vty = 0 m/s and time taken to reach the peak is half of total time. Hence
vty = voy - gt
0 = voy - 10.(1/2 . 4)
voy = 20 m/s
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This is an A level/ Cape physics problem under the topic uncertainty, please do your best to answer, thank you.
The radius of the cylinder is 0.43 cm while the uncertainty is 0.04. This can likely be expressed as 0.43 +/- 0.04 cm
What is Absolute Uncertainty ?Absolute uncertainty or error is the difference between measured value of a quantity and the actual value.
Given an expression for the volume of a cylinder to be
V = πr²h
Where
V = 12 +/- 0.5 cm³h = 21 +/- 0.1 cmFrom the formula, make radius r the subject of the formula and calculate the radius
V = πr²h
r² = V/πh
r = √(V/πh)
r = √12/21π
r = √12/65.97
r = √0.18
r = 0.43 cm
The uncertainty Δr will be
Δr/r = (ΔV/V + Δh/h) × 2
Δr/0.43 = (0.5/12 + 0.1/21) × 2
Δr/0.43 = (0.0417 + 0.0048) × 2
Δr/0.43 = 0.093
Δr = 0.093 × 0.43
Δr = 0.0399
Δr = 0.04
Therefore, the radius of the cylinder is 0.43 +/- 0.04 cm
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