A jumping spider's movement is modeled by a parabola. The spider makes a single jump from the origin and reaches a maximum height of 10 mm halfway across a horizontal distance of 80 mm.

Part A: Write the equation of the parabola in standard form that models the spider's jump. Show your work. (4 points)

Part B: Identify the focus, directrix, and axis of symmetry of the parabola. (6 points)

Answers

Answer 1

The spider's movement is an illustration of a parabola.

The equation of the parabola is: [tex]\mathbf{y = -\frac{1}{320}(x - 80)^2 + 20}[/tex]The focus of the parabola is [tex]\mathbf{Focus = (80 ,-60)}[/tex]The directrix is: [tex]\mathbf{y = 100}[/tex].The axis of symmetry is: [tex]\mathbf{x = 80}[/tex]

(a) The equation

The spider passes through the origin.

So, we have:

[tex]\mathbf{(x,y) = (0,0)}[/tex]

The spider jumps to a maximum height of 20mm, midway 160mm.

So, the vertex is:

[tex]\mathbf{(h,k) = (80,20)}[/tex]

The equation of a parabola is:

[tex]\mathbf{y = a(x - h)^2 + k}[/tex]

So, we have:

[tex]\mathbf{0 = a(0 - 80)^2 + 20}[/tex]

[tex]\mathbf{0 = 6400a + 20}[/tex]

Subtract 20 from both sides

[tex]\mathbf{6400a =- 20}[/tex]

Solve for a

[tex]\mathbf{a =- \frac{1}{320}}[/tex]

Substitute [tex]\mathbf{a =- \frac{1}{320}}[/tex] and [tex]\mathbf{(h,k) = (80,20)}[/tex] in [tex]\mathbf{y = a(x - h)^2 + k}[/tex]

[tex]\mathbf{y = -\frac{1}{320}(x - 80)^2 + 20}[/tex]

(b) The focus, directrix and the axis of symmetry

The focus of a parabola is:

[tex]\mathbf{Focus = (h,k+p)}[/tex]

Where:

[tex]\mathbf{p = \frac{1}{4a}}[/tex]

So, we have:

[tex]\mathbf{p = \frac{1}{4\times -1/320}}[/tex]

[tex]\mathbf{p = -\frac{320}{4}}[/tex]

[tex]\mathbf{p = -80}[/tex]

So, we have:

[tex]\mathbf{Focus = (80 , 20-80)}[/tex]

[tex]\mathbf{Focus = (80 ,-60)}[/tex]

The axis of symmetry is:

[tex]\mathbf{x = h}[/tex]

So, we have:

[tex]\mathbf{x = 80}[/tex]

The directrix is:

[tex]\mathbf{y = k - p}\\[/tex]

So, we have:

[tex]\mathbf{y = 20+80}[/tex]

[tex]\mathbf{y = 100}[/tex]

Read more about parabolas at:

https://brainly.com/question/5430838


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Answers

[tex] \sf \underline{ \red{Solution - }} \\ [/tex]

Given,

[tex] \sf{\quad { \dfrac{-7}{\sqrt{11} - \sqrt{5}} }} \\ [/tex]

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We know that

Rationalising factor of √a-√b is √a+√b.

Therefore, the rationalising factor of √11-√5 is √11+√5.

On rationalising the denominator them

[tex] \longrightarrow \sf{\quad { \dfrac{-7}{\sqrt{11} - \sqrt{5}} \times \dfrac{(\sqrt{11} + \sqrt{5})}{(\sqrt{11} + \sqrt{5})} }} \\ [/tex]

Multiplying (√11 + √5) with both the numerator of the fraction.

[tex] \longrightarrow \sf{\quad { \dfrac{-7(\sqrt{11} + \sqrt{5}) }{(\sqrt{11} - \sqrt{5})(\sqrt{11} + \sqrt{5})} }} \\ [/tex]

Performing multiplication in the numerator and by using identity (a + b)(a - b) = a² - b², solving further in the denominator.

[tex] \longrightarrow \sf{\quad { \dfrac{-7\sqrt{11} -7\sqrt{5}}{(\sqrt{11})^2 - (\sqrt{5})^2} }} \\ [/tex]

Writing the squares of the numbers in the denominator.

[tex] \longrightarrow \sf{\quad { \dfrac{-7\sqrt{11} -7\sqrt{5}}{11 -5} }} \\ [/tex]

Performing subtraction in the denominator.

[tex] \longrightarrow \quad \underline{ \boxed{ \dfrac{ \textbf{ \textsf{-7 }}\sqrt{ \textbf{ \textsf{11 }}} - \textbf{ \textsf{7}}\sqrt{ \textbf{ \textsf{5 }}}}{ \textbf{ \textsf{ 6}}}} } \\ [/tex]

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Angle on a straight line = 180 DEG

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6x = 90 DEG

x = 15 DEG

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Jose has 4 times as many baseball cards as his brother. Together they have 40 baseball cards. How many baseball cards does Jose's brother have?

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Answer:

Ummm..... I would think 10??

Step-by-step explanation:

I don't really know tho.....

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Answer:

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on simplifying

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Answer:

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Step-by-step explanation:

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Answer:

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Answers

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[tex]Alternate \:Intrerior \: Angles[/tex]

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Step-by-step explanation:

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Answers

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Answer:

Step-by-step explanation:

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Step-by-step explanation:

Answer:

D. y = -2x - 10

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Step-by-step explanation:

Simple Interest:

Simple Interest formula is S.I. = P × r × t

Interest Eared: $3,500 × 0.04 × 10 = $1,400

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Account Balance: $3,500 + $1,400 = $4,900

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I believe it is 3
(please mark brainliest)

show that P(x)=x³-6x²+11x-6 is divisible by x-1.​

Answers

HERE IS YOUR ANSWER MATE

HOPE ITS HELPFUL

HAVE A GREAT FUTURE

LOVE FROM INDIA

Hello haohaoxNienie!

[tex] \huge \boxed{\mathfrak{Question} \downarrow}[/tex]

Show that p(x) = x³ - 6x² + 11x - 6 is divisible by x - 1.

[tex] \huge \boxed{\mathfrak{Explanation} \downarrow}[/tex]

To show that p(x) = x³ - 6x² + 11x - 6 is divisible by x - 1, we must divide the polynomial by x - 1. If we get the remainder as 0, then we can say that p(x) = x³ - 6x² + 11x - 6 is divisible by x - 1.

__________________

So, let's do the division (steps in the attached picture).

__________________

We got the remainder as 0. So, yes p(x) = x³ - 6x² + 11x - 6 is divisible by x - 1.

__________________

More steps :-

x² - 5x + 6

= (x - 3) (x - 2) [use the splitting the middle term method].

So, the zeroes are,

(x - 3)

x - 3 = 0

x = 3 ⇨ 1st zero.

(x - 2)

x - 2 = 0

x = 2 ⇨ 2nd zero.

Now, use the values of x on the equation. If we get 0 as the solution of the equation then we can prove that p(x) = x³ - 6x² + 11x - 6 is divisible by x - 1.

p(x) = x³ - 6x² + 11x - 6

p(3) = 3³ - 6(3)² + 11 (3) - 6

p(3) = 27 - 54 + 33 - 6

p(3) = 0.

p(x) = x³ - 6x² + 11x - 6

p(2) = 2³ - 6(2)² + 11 (2) - 6

p(2) = 8 - 24 + 22 - 6

p(2) = 0

Since we got the solutions as 0 we can say that p(x) = x³ - 6x² + 11x - 6 is divisible by x - 1.

__________________

Hope it'll help you!

ℓu¢αzz ッ

20% of the tickets sold at a water park were child tickets. If the park sold 50 tickets in all,
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tickets

Answers

Answer:

= 10 tickets

Step-by-step explanation:

= 20% × 50

= 20/100 × 50

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= 10

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Answers

Step-by-step explanation:

y = 3x - 6

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the perpendicular slope (crosses the original line in a right angle = 90 degrees) turns x and y upside-down and flips the sign.

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y = (-1/3)×x + b

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[tex]10\times 5\times 13=?[/tex]

Answers

Answer:

[tex] = > 10 \times 5 \times 13[/tex]

[tex] = > 50 \times 13[/tex]

[tex] = > 650[/tex]

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