A horizontal force of 20 N is applied to the object.
Draw a free body diagram with the forces to scale.
Determine the force of friction.
Determine the acceleration of the object.

Answers

Answer 1

The acceleration of the object with a horizontal force of 20N is 4.4 m/s².

How to Determine Horizontal Acceleration in Frictional Systems

Here, the angle of repose

a = tan⁻¹ (45)

a = tan⁻¹(1/5)

a = 11.3°

The angle of inclination is greater than the angle of repose.

The friction force on the block will act in an upward direction.

For the acceleration of the block:

MgsinΘ - μN = Ma

a = gsinΘ - μg cosΘ

a = g (sinΘ - u cosΘ)

a = 10 (sin37 - μ cos37)

a = 10 (0.6 - 0.2 * 4/5)

a = 10 ( 0.6 -0.16)

a = 4.4 m/s²

Thus the acceleration of the object is 4.4 m/s².

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Related Questions

if q = (10 - [tex]10e^{-2t}[/tex])mC, find the current at t=0.5

Answers

The flowing current at the given time is determined as 7.36 mA.

What is electric current?

An electric current is a stream of charged particles, such as electrons or ions, moving through an electrical conductor or space.

Also we can define electric current as the measure of the average rate of flow of electrical charges over a given period of time.

I = dQ/dt

where;

dQ is change in the flow of electrical chargesdt is the change in time of flow of the charges

The given parameters include the following;

Q = (10 - 10[tex]e^{-2t}[/tex]), mC

t = 0.5 second

I = dQ/dt

I = d(10 - 10[tex]e^{-2t}[/tex])/dt

I = -2 x (-10[tex]e^{-2t}[/tex])

I = 20[tex]e^{-2t}[/tex]

The time, t is given as 0.5, now substitute this value into the above equation;

I = 20[tex]e^{-2 \times 0.5}[/tex]

I = 20[tex]e^{-1}[/tex]

I = 7.36 mA

Thus, the current at the given time is a function of charge and time of charge flow.

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Since the drag force is proportional to the square of speed, what can you do to improve your car’s gas mileage?.

Answers

Since the drag force is proportional to the square of speed,  to improve your car’s gas mileage, you should drive in lower speed.

The drag force is a force experienced by an object when it is moving through a fluid. The fluid can be air, water, gas or liquid.

Some of the factors that affect the drag force are the speed of the object and its aerodynamic. The relation between drag force and velocity is given by:

F = 1/2 . CρAv²

Where:

C = drag coefficient

ρ = fluid density

A = area of the object that facing the fluid

v = velocity

Therefore, the drag force is directly proportional to the square of object's velocity, or

F ∝ v²

The power of car should overcome this drag force. The relation between power and force is given by:

P = F . v

Since F is proportional to v², then

P ∝ v³

Thus, we can conclude to use less power, which means to improve gas mileage, you should drive in lower speed.

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An in-line skater first accelerates from 0. 0 m/s to 5. 0 m/s in 4. 5 s, then continues at this constant speed for another 4. 5 s. What is the total distance traveled by the in-line skater?.

Answers

The total distance traveled by the in-line skater is 33.75 metres.

The total distance will be calculated by the sum of distance due to acceleration and distance due to constant speed. Converting the above mentioned formula in mathematical expression to be used:

d = (v+u/2)×t + v×t

Keep the values in formula to find the total distance.

d = (5+0/2)×4.5 + 5×4.5

Performing addition and multiplication on Right Hand Side of the equation

d = 2.5×4.5 + 22.5

Performing only multiplication on Right Hand Side of the equation

d = 11.25 + 22.5

Performing only addition on Right Hand Side of the equation

d = 33.75 metres

Thus, the skater traveled 33.75 metres.

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you have a 15 kg suitcase and (a) slowly lift it 0.80 m upward, (b) hold it at rest to test whether you will be able to move the suitcase without help in the airport, and then (c) lower it 0.80 m. what work did you do in each case? what assumptions did you make to solve this problem?

Answers

The assumption that the system has no internal energy and that the force is applied uniformly is made to solve this problem.

What is internal energy?The internal energy of a thermodynamic system refers to the total energy contained in it. It is the energy required to create or prepare a system in a given internal state and includes  contributions of potential energy and internal kinetic energy.Energy gains and losses in the system  due to internal state changes are taken into account. It does not include the kinetic energy of the motion of the entire system  or  external energy from the surrounding force field. The internal energy of an isolated system is constant, which is expressed as the law of conservation of energy, which is the basis of the first law of thermodynamics. Internal energy cannot be measured directly, and it is of little interest to know all its constituents, such as their constituent static rest mass energies. Thermodynamics is primarily concerned only with internal energy changes, not  absolute values.

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when the person attempts to climb the ladder, how far up the ladder will the person reach before the ladder slips (kaboom)? the acceleration of gravity is 9.8 m/s

Answers

The maximum distance the person will reach before he slip is 1.82m. Not even close to the middle of the ladder.

What is distance?The extent of space between two things, points, lines, etc is called distance. The condition or fact that one is separated in space as if one were separated from another. Remoteness Linear expansion of space: Seven miles is  too far to walk in one hour. Vastness; Area: A huge body of water surrounded the ship.The length along a line between two points on the line or line segment.  Length is a measure of something like A segment of a room. Distance indicates how far  objects are from each other. Two cities or two points. Neither length nor distance can be negative.

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Why do telescopes have to have a good motorized drive system to move them quickly and smoothly?.

Answers

Telescopes have to have a good motorized drive system to move them quickly and smoothly so that they can continue to point at the object being observed.

Astronomers use a telescope to observe distant things. Curved mirrors are used by the majority of telescopes, including all large telescopes, to collect and concentrate light from the night sky. The original telescopes employed lenses, which were curved pieces of clear glass, to focus light. The ability of an optical telescope to gather light is its most crucial ability. This capability is solely dependent on the telescope's aperture, or the diameter of the clear objective.

The telescope has a motorized drive mechanism that drives it smoothly from east to west at precisely the same rate that Earth is rotating from west to east in order to maintain the telescope's pointing at the object being seen because Earth is revolving.

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Calculate the angle of incidence of a laer red light at which the reflected light i plane polaried. Let we are uing a material of crown gla in a medium of Helium

Answers

According to the Brewster's law The angle of incidence is θ=tan −1n.

What is Brewster's law?
Brewster's law
is a relationship for light waves that states that if a light ray is allowed to fall on the surface of the a transparent medium in a way that refracted ray makes a 90° angle with the reflected ray, the maximum polarisation (vibration in one aircraft only) can be achieved. The law bears Sir David Brewster's name, a Scottish physicist who first suggested it in 1811. The illustration depicts a ray of regular (nonpolarized) light with a particular wavelength striking a transparent medium's reflecting surface (e.g., water or glass).

According to Brewster's law,

the angle of incidence at which the reflected light is totally polarized for reflection from air to glass is governed by the relation

n=tanθ

∴θ=tan −1n

Hence, the angle of incidence is θ=tan −1n.

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A 100gm GOLF BALL MOVING WITH A VELOCITY OF 20m/s COLLIDES WITH A 8kg STEEL BALL AT REST. IF THE COLLISION IS ELASTIC, COMPUTE THE VELOCITIES BOTH THE BALLS AFTER COLLISION

Answers

Answer:

Golf ball ([tex]0.1\; {\rm kg}[/tex]): approximately [tex](-19.506)\; {\rm m\cdot s^{-1}}[/tex] (backwards).

Steel ball ([tex]8\; {\rm kg}[/tex]): approximately [tex]0.49383\; {\rm m\cdot s^{-1}}[/tex] (forward.)

Explanation:

Apply unit conversion and ensure that the unit of all mass are in kilograms: [tex]100\; {\rm g} = 0.1\; {\rm kg}[/tex].

In an elastic collision, both momentum [tex]p = m\, v[/tex] and kinetic energy [tex]\text{KE} = (1/2)\, m\, v^{2}[/tex] are conserved. Momentum of the two balls before the collision are:

[tex]0.1\; {\rm kg} \times 20\; {\rm m\cdot s^{-1}} = 2\; {\rm kg \cdot m \cdot s^{-1}}[/tex] for the golf ball, and [tex]8\; {\rm kg} \times 0\; {\rm m\cdot s^{-1}} = 0\; {\rm kg \cdot m\cdot s^{-1}}[/tex] for the steel ball initially at rest.

Hence, the total momentum of the two balls was [tex]2\; {\rm kg \cdot m\cdot s^{-1}}[/tex] before the collision and (by conservation) will still be [tex]2\; {\rm kg \cdot m\cdot s^{-1}}\![/tex] after the collision.

Kinetic energy of the two balls before the collision are:

[tex](1/2)\times 0.1\; {\rm kg} \times (20\; {\rm m\cdot s^{-1}})^{2} = 200\; {\rm kg \cdot m^{2} \cdot s^{-2}}[/tex] for the golf ball, and[tex](1/2) \times 8\; {\rm kg} \times (0\; {\rm m\cdot s^{-1}})^{2} = 0\; {\rm kg \cdot m\cdot s^{-1}}[/tex] for the steel ball initially at rest.

Thus, the total kinetic energy of the two balls will be [tex]200\; {\rm kg \cdot m^{2} \cdot s^{-2}}[/tex] before and after the collision.

Let [tex]m_{a}[/tex] and [tex]v_{a}[/tex] denote the mass and velocity of the golf ball after collision; [tex]m_{a} = 0.1\; {\rm kg}[/tex].

Let [tex]m_{b}[/tex] and [tex]v_{b}[/tex] denote the mass and velocity of the steel ball after collision; [tex]m_{b} = 8\; {\rm kg}[/tex].

Total momentum after the collision shall be [tex]2\; {\rm kg \cdot m\cdot s^{-1}}\![/tex]. Thus:
[tex]m_{a}\, v_{a} + m_{b}\, v_{b} = 2\; {\rm kg \cdot m\cdot s^{-1}}[/tex].

Total kinetic energy after the collision shall be [tex]200\; {\rm kg \cdot m^{2} \cdot s^{-2}}[/tex]. Thus:
[tex]\displaystyle \frac{1}{2} \, m_{a}\, v_{a} + \frac{1}{2}m_{b}\, v_{b} = 200\; {\rm kg \cdot m^{2}\cdot s^{-2}}[/tex].

Assume that the unit of [tex]v_{a}[/tex] and [tex]v_{b}[/tex] are both "meters per second" ([tex]{\rm m\cdot s^{-1}}[/tex].) Combine and solve this system of two equations and two variables:

[tex]\left\lbrace\begin{aligned}&0.1\, v_{a} + 8\; v_{b} = 2 \\ &\frac{1}{2}\, {v_{a}}^{2} + 4\, {v_{b}}^{2} = 200\end{aligned}\right.[/tex].

Rewrite the first equation to obtain [tex]v_{a} = 20 - 80\, v_{b}[/tex]. Substitute this equation into the second one to eliminate [tex]v_{a}[/tex]:

[tex]\displaystyle \frac{1}{2}\, (20 - 80\, v_{b})^{2} + 4\, v_{b}^{2} = 200[/tex].

Solve this equation for [tex]v_{b}[/tex]:

[tex]324\, {v_{b}}^{2} - 160\, v_{b} = 0[/tex].

There are two solutions to this quadratic equation: [tex](40 / 81)[/tex] and [tex]0[/tex]. Note that the velocity of the steel ball must be non-zero right after the collision. Hence, [tex]v_{b} \ne 0[/tex]. Therefore, the only possible value for [tex]v_{b}[/tex] will be [tex](40 / 81)\![/tex], which is approximately [tex]0.49383\; {\rm m\cdot s^{-1}}[/tex].

Substitute [tex]v_{b} = (40 / 81)[/tex] back into the first equation of the system and solve for [tex]v_{a}[/tex]: [tex]v_{a} = 20 - 80\, v_{b} \approx (-19.506)\; {\rm m\cdot s^{-1}}[/tex]. Note that the velocity of the golf ball [tex]v_{a}\![/tex] is negative since the golf ball is travelling backwards, opposite to its initial direction of motion.

In other words, the velocity right after collision will be approximately [tex](-19.506)\; {\rm m\cdot s^{-1}}[/tex] (backwards) for the golf ball and approximately [tex]0.49383\; {\rm m\cdot s^{-1}}[/tex] (forwards) for the steel ball.

you decide that you want to be able to adjust the height of the views and the data visualizations about electric vehicle sales, charging stations, and battery range. which type of layout will enable you to do that?

Answers

The correct answer is vertical layout will enable to adjust height of the views and the data visualizations.

What is a vertical layout?

Use the Vertical Layout control to hold content vertically within it (stacked on-top of one another). Keep in mind that this control can be linked to a list, creating a recurring segment. The Horizontal Layout and Vertical Layout are two of the most often utilised controls when creating a user interface.

So according to given data that if we do require to change the height of views as well as Data Visualization, we require to implement Vertical Layout.

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A certain car is capable of accelerating at a rate of 0. 60 m/s2. How long does it take for this car to go from a speed of 55 mi/h to a speed of 60 mi/h?.

Answers

The time taken for a car that can accelerate at a rate of 0.6 m / s² to go from a speed of 55 mi/h to a speed of 60 mi/h is 3.68 s

a = ( v - u ) / t

a = Acceleration

v = Final velocity

u = Initial velocity

t = Time

a = 0.6 m / s²

v = 60 mi / h = 26.8 m / s

u = 55 mi / h = 24.59 m / s

t = ( v - u ) / a

t = ( 26.8 - 24.59 ) / 0.6

t = 3.68 s

Acceleration is the rate of change of velocity with respect to time. If the final speed is greater than the  initial speed it is called as acceleration and if the final speed is lesser than the initial speed it is called as deceleration.

Therefore, the time taken for this car is 3.68 s

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what is the magnitude of the acceleration of a skydiver who is currently falling at one-fifth his eventual terminal speed?

Answers

G = 9.81 m/s2 is the acceleration caused by gravity. The skydiver's acceleration, who is currently descending at a speed that is one-fifth of his ultimate terminal speed, is 3.5316.

What is an explain acceleration?

Acceleration: the rate at which the speed and direction of a moving object vary over time. A object and item moving straight forward is propelled when it increases or depreciates.

Is zero acceleration possible?

Acceleration is a component of velocity profile. As a result, velocity must remain constant if accelerations are zero. That constant, however, might be anything, such as 5 m/s. Additionally, zero acceleration is indicated if the speed is zero .

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The Earth moves in a nearly perfect circle around the Sun. Assume the speed stays
constant. Is Earth accelerating?

Answers

Answer:

yes

Explanation:yes

Answer:

Yes

Explanation:

Earth is accelerated around the sun

The half-life of Ra-226 is 1600 yrs. If one had 0.25 g of a fossil at the beginning, how many grams would be left after 4800 yrs. has elapsed?

Answers

The amount of Ra-226 left after4800 yrs with a half-life of 1600 yrs is  0.03125 g.

What is half-life?

Half-life is the time taken for half the sample of a radioactive substance to disintegerate.

To calculate the amount of Ra-226 left, we use the formula below.

Formula:

R' = R/[tex]2^{n/t}[/tex].............. Equation 1

Where:

R' = Amount of Ra-226 leftR = Original amount of Ra-226n = Total time t = Half-life

From the question,

Given:

R = 0.25 gt = 1600 yrsn = 4800 yrs

Substitute these values into equation 1

R' = 0.25/[tex]2^{4800/1600}[/tex]R' = 0.25/2³R' = 0.25/8R' = 0.03125 g

Hence, the amount of Ra-226 left after 400 yrs is 0.03125 g.

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a force of 20 n is directed at an angle of 609 above the x-avis. a second force of 20 n is directed at an angle of 60 below the x-axis. what is the vector sum of these toro forces?

Answers

20 N , in +x direction is the vector sum of these Toro forces.

What is force?The word "force" has a specific meaning in science. At this level, calling a force a push or a pull is entirely appropriate. A force is not something an object "has in it" or that it "contains." One thing experiences a force from another. There are both living things and non-living objects in the concept of a force.Force is used to describe a body's tendency to modify or change its state as a result of an external cause. When force is applied, the body can also alter its size, shape, and direction. kicking a ball, pushing and pulling on the door, or kneading dough are a few examples. The newton, abbreviated N, is the SI unit of force.

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where was the sun located in the first maps of the milky way galaxy? where was the sun located in the first maps of the milky way galaxy? near the top of the nuclear bulge. at the center. near the edge of the disk. in the galactic halo.

Answers

star formation is the process by which dense regions within molecular clouds in Interstellar space.

As we know stars are born within the clouds of dust and scattered throughout most galaxies. A familiar example of such as a dust cloud is the orion nebula.

A molecular cloud, sometimes called a stellar nursery if star formation is occurring within is a type of Interstellar whose density and size permits the formation of molecule .

The most common in hydrogen.

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A ball has a mass of 50g and is revolving at the end of a string in a circle with a radius of 40cm. The Ball moves with a speed of 2.5m/s, or one revolution per second. What is the horizontal component of the tension needed to produce this acceleration (in N)?

Answers

0.781 N is the horizontal component of the tension needed to produce this acceleration.

F=ma

T=ma

m= mass=0.05

a= centripetal acceleration =15.6

T=ma

T=0.05×15.6

T=0.781 N

When pressures on opposing ends are tugging on a rope, thread, wire, or something similar, tension is a contact force communicated through it. For instance, the rope attaching a tire swing to a limb of a tree is under strain. Gravity pulls the rope downward, while the upward pull is caused by a branch that is resisting the rope's tug tension, which is just a pulling force. A slack rope has no tension when one pushes on it. As a result, in a free-body diagram, the force of tension must always be shown in the direction that the string is pulling the item.

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Which periodic table groups do these elements belong in?​

Answers

Answer:

Claim: Element J should be placed in group 2A (group 2), the Alkaline earth metals. Element Q should be placed on group 8A, Nobel Gases.

Evidence: Element J is Solid at room temperature, is a good conductor of electricity, and have reactions. All of which are properties of Alkaine earth metals. Nobel gases are extremely unreactive, rarely forming compounds and the elements in this group are also gases at room temperature.

Reasoning: Based off of the evidence provided, its safe to say that Element J would belong in group 2A because of its indistindistinct similarities to elemts within that group. Element J would go with the Nobel gases for the same reason

Explanation:

ᓚᘏᗢ meow

When the current in the wire is decreasing the oppose magnitude of the magnetic flux in the loops is _____. Increasing support Induced currents in the loops and the forces exerted on them are directed so they _____ this change

Answers

When the current in the wire is decreasing the oppose magnitude of the magnetic flux in the loops is Decreasing. Increasing support Induced currents in the loops and the forces exerted on them are directed so they Oppose this change.

The above statement was proved in Ampere's Circuital Law. According to the law the Current induced is directly proportional to the magnetic flux in the loops. So increasing the current would definitely oppose the change of decreasing the current.

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can someone please help me in physics :( i need to scale this so i can draw it. i will be so thankful <33

Answers

Answer:

Explanation:

This sounds complicated but  ,  Butternight,  and maybe there is some difficulty in the ricochet.  I think the question is asking if the bullet bounces off a rock and heads North East....  or  NE,  but you've got it as  EN ?   Then how far does it go.  In my drawing,  what is X,  is the question.

We need to know how far the bullet travels East, and how far the bullet travels North.

Then we could put those two parts together and find the length of the red line in my drawing.  The red line is also referred to as the Magnitude.  

To find how far the bullet travels East,  use sine and cosine.  Do you know these?   if not,  start knowing  :D

Sine(36) = 0.587785....

Cosine(36)=0.809016....

640 * Sine(36)  => 640 * 0.587785  = 376.1825....  m  North

640 *Cosine(36)  => 640 * 0.809016 = 517.7708... m  East

Then the total distance traveled by the bullet to the East is 850 + 517.7708 = 1367.7708... m East

we can find the magnitude by using this [tex]\sqrt{North^{2} + East^{2} }[/tex]

[tex]\sqrt{376.1825^{2} + 1367.7708^{2} }[/tex] = 1418.559.... m NE

I used my calculator to find that.  :P

Hi! Can someone help me figure out the Fg(N) column? I don't know how to plug my information into the formula.

Answers

The gravitational force (Fg) for the first column is 1.96 x 10⁷ N.

The gravitational force (Fg) for the second column is 2.48 x 10⁷ N.

The gravitational force (Fg) for the third column is 3.24 x 10⁷ N.

The gravitational force (Fg) for the fourth column is 4.4 x 10⁷ N.

The gravitational force (Fg) for the fifth column is 6.36 x 10⁷ N.

The gravitational force (Fg) for the sixth column is 9.94 x 10⁷ N.

The gravitational force (Fg) for the seventh column is 1.77 x 10⁸ N.

What is Newton's law of universal gravitation?

Newton's law of universal gravitation states that every two objects in the universe attracts each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between the masses.

F = Gm₁m₂/r²

F = (Gm₁m₂) x 1/r²

where;

m₁ is the mass of the first objectm₂ is the mass of the second objectG is universal gravitation constantr is the distance between the two masses

The gravitational force (Fg) for the first column is calculated as;

Fg = (Gm₁m₂) x 1/r²

Fg = (6.626 x 10⁻¹¹ x 4 x 10⁹ x 6 x 10⁹) x  1/r²

Fg = 1.59 x 10⁹  x 0.0123

Fg = 1.96 x 10⁷ N

The gravitational force (Fg) for the second column is calculated as;

Fg = (Gm₁m₂) x 1/r²

Fg =  1.59 x 10⁹  x 0.0156

Fg = 2.48 x 10⁷ N

The gravitational force (Fg) for the third column is calculated as;

Fg = (Gm₁m₂) x 1/r²

Fg =  1.59 x 10⁹  x 0.0204

Fg = 3.24 x 10⁷ N

The gravitational force (Fg) for the fourth column is calculated as;

Fg = (Gm₁m₂) x 1/r²

Fg =  1.59 x 10⁹  x 0.0277

Fg = 4.4 x 10⁷ N

The gravitational force (Fg) for the fifth column is calculated as;

Fg = (Gm₁m₂) x 1/r²

Fg =  1.59 x 10⁹  x 0.0400

Fg = 6.36 x 10⁷ N

The gravitational force (Fg) for the sixth column is calculated as;

Fg = (Gm₁m₂) x 1/r²

Fg =  1.59 x 10⁹  x 0.0625

Fg = 9.94 x 10⁷ N

The gravitational force (Fg) for the seventh column is calculated as;

Fg = (Gm₁m₂) x 1/r²

Fg =  1.59 x 10⁹  x 0.1111

Fg = 1.77 x 10⁸ N

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explain or demonstrate mathematically how the formula for the critical angle (the angle at which total internal reflection occurs) can be derived from snell's law.

Answers

The critical angle for the total internal reflection using snell's law is  

θ(c) = sin⁻¹(n₂/n₁).

Total internal reflection:

Full reflection of a light ray from the surrounding surface is back into a medium like glass or water. If the incidence angle exceeds a specific limitation angle known as the critical angle.

critical angle:

The critical angle is the angle of incidence for which the angle of reflection is 90 degrees. the incidence angle above which 100% internal reflection takes place is known as the critical angle.

Critical angle by using shell's law :

n₁ sinθ₁ = n₂sinθ₂

n₁ and n₂ are refractive index of the two material.

n₁ sinθ(c) = n₂sin(90°)

where,

θ(c) is the critical angle.

θ(c) = sin⁻¹(n₂/n₁)

The critical angle for the total internal reflection using snell's law is  

θ(c) = sin⁻¹(n₂/n₁).

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what is the basic definition of a black hole? question 16 options: any compact mass that emits no light a dead star that has faded from view a dead galactic nucleus that can only be viewed in infrared any object from which the escape velocity exceeds the speed of light any object made from dark matter

Answers

The basic definition of a black hole is -

D) any object from which the escape velocity exceeds the speed of light.

What is a blackhole?

Points in space known that are so dense that they produce large gravity wells. Even light cannot escape a black hole's intense gravitational pull after a certain point. And in a theoretical process aptly known as spaghettification, anything that gets too close will be stretched and compressed.

Stellar, intermediate, supermassive, and miniscule black holes are the four main categories. Stellar death is the process that creates black holes most often. Most dying stars will expand, lose mass, then cool to form white dwarfs as they approach the end of their lives. However, the biggest of these flaming bodies, those at least 10 to 20 times as massive as our sun, are doomed to become either super-dense neutron stars or so-called stellar-mass black holes.

Hence, option D is correct.

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The energy flux from the sun has a peak value of around 1500 W/m2, and solar cells are around
15% efficient. Estimate the area needed to satisfy US energy needs using solar cells, using the
estimates that there are about 350 million people in the US and that we use an average of 90
kW/person. Also assume that there are about 6 hours of "peak" sunlight per day. Answer in square
kilometers (do not put units in your answer, however).

Answers

Answer:

Power required = 3.5E8 * 9.0E4 = 3.2E13     (watts)

Power supplied = 1.5E3 * .15 * 3600 * 6    (watts / m^2) * A

= 1.5E3* .15 * 3600 * 6 = 4.9E6 * A

A = 3.2 / 4.9 * E7 = 3.2 / 4.9 * 10 = 6.5 km*2    (1 km^2 = 10E6 m^2)

Note:  1 W = 1 J / sec    1 kw = 1000 W

The area needed to satisfy US energy needs using solar cells 6.5 km²

What is energy?

Energy is the ability or capability to do tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.

Power required = 3.5E8 * 9.0E4 = 3.2E13     (watts)

Power supplied = 1.5E3 * .15 * 3600 * 6    (watts / m^2) * A

= 1.5E3* .15 * 3600 * 6 = 4.9E6 * A

A = 3.2 / 4.9 * E7 = 3.2 / 4.9 * 10

= 6.5 km*2  

The area needed to satisfy US energy needs using solar cells 6.5 km².

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The students double the mass that hangs from the string. They also replace the original cart with a new cart that has double the mass. By doubling both masses, how will the tension in the string and the acceleration of the cart change?.

Answers

The difference between the string's tension and the cart's acceleration is that the tension doubles while the acceleration stays the same.

What does life's stress mean?

In common language, tension is the physical and emotional stress that comes along with life's events. Positive or bad situations can cause this stress, which can be physical, psychological, or emotional.

What's an illustration of tension?

Compression force's opposite is tension. All of the things in the scene that are in contact with one another apply forces to one another. The best demonstration of a tension force is when a rope is being pulled. The rope builds up a lot of tension when a pulling force is applied to it.

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a ball is shot from the ground straight up into the air with initial velocity of 49 49 ft/sec. assuming that the air resistance can be ignored, how high does it go?

Answers

A height of 27.56 feet is the maximum the ball can fly.

How are speed and velocity different?

Speed is the rate at which an object travels along a path over time, whereas velocity is the speed and direction of an item's motion. In other words, speed is a scalar value, but velocity is a vector.

What, for example, is velocity?

The rate at which that moves in a certain direction is referred to as its velocity. as quickly as a car traveling north on a road or a rocket taking flight. The magnitude of the velocity vector's absolute value will always be equal to the motion's speed because it is a scalar.

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you are attending the indi 500 and as cars pass you by, your eyes and head follow the race cars. which structure is controlling this movement?

Answers

Superior colliculi structure is controlling this movement To attending the indi 500 and as cars pass you by, your eyes and head follow the race cars.

In neuroanatomy, the advanced colliculus (from the Latin 'upper hill') is a shape mendacity at the roof of the mammalian midbrain. In non-mammalian vertebrates, the homologous shape is known as the optic tectum or optic lobe. The adjective shape tectal is typically used for each system.

In mammals, the superior colliculus forms a chief thing of the midbrain. it's far a paired structure and collectively the paired inferior colliculi form the corpora quadrigemina. The superior colliculus is a layered shape, with a pattern, this is just like all mammals. The layers can be grouped into the superficial layers (stratum opticum and above) and the deeper last layers. Neurons within the superficial layers acquire direct input from the retina and reply nearly solely to visible stimuli.

Many neurons in the deeper layers additionally respond to different modalities and some reply to stimuli in a couple of modalities. The deeper layers also incorporate a populace of motor-related neurons, capable of activating eye actions as well as other responses. In different vertebrates, the number of layers in the homologous optic tectum varies.

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Next O Matter Around Us: Mastery Test

3

Select the correct answer from each drop-down menu.

William finds a piece of pure iron in his garden. After a few days, the iron begins to rust. What are the two types of substances involved in the rusting

process of iron?

Iron is

atoms,

a compound

an element

a mixture

with one kind of atom that combines with oxygen from the air to form rust (iron oxide). Rust contains two types of

Reset

Subm

Next

Answers

Compounds, like water (H2O) and methane, are made of two or more atoms of various elements. Atoms are not scaled in drawings. Compound molecules contain atoms from two or more distinct elements.

As an illustration, the molecule of water (H2O) contains three atoms: two hydrogen (H) atoms and one oxygen (O) atom. Rust is created when oxygen from the air reactor with iron, which is BLANK with one type of atom (iron oxide). Oxidation reactions result in iron rusting. When something rusts, iron reacts with oxygen in the air and produces Fe2O3.xH2O, or hydrated iron (III) oxide.

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A roller coaster cart of mass m= 230kg starts stationary at point A, where h1= 39.1 m and a whole later is at B, where h2=9.7m
The acceleration of gravity is 9.8 m/s^2.
What is the potential energy of the cart relative to the ground at A? (Answer in units of J)

What is the speed of the cart at B, ignoring the effect of friction? (Answer in units of m/s)

Answers

Change in potential energy  is calculated as 66267.6 J

v₂, speed of the cart at B  is calculated to be 24 m/s

What is energy?

Quantitative property that is transferred to a body or to a physical system and is recognizable in the performance of work and in the form of heat and light is called a as energy.

As we know, KE1 + PE1 = KE2 + PE2  

Given m=230kg,h=39.1 m, h2= 9.7m  

we know g= 9.8m/s^2

As we know, KE1 + PE1 = KE2 + PE2  

0 + m*g*h₁ = .5(m)v₂² + m*g*h₂

(230)*(9.8)*(39.1)= 0.5(230)(v₂² )+ (230)(9.8)(9.7)

88131.4 = 115 v₂² + 21863.8

66267.6 = 115 v₂²

v₂²  = 576.24

v₂ = 24 m/s

We know, change in potential energy is PE2 - PE1

88131.4- 21863.8

Change in potential energy = 66267.6 J

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a boat is at anchor outside a harbor. a steady sinusoidal ocean wave makes the boat bob up and down with a period of 4.80 s and an amplitude of 1.00 m . the wave has wavelength 40.5 m . for this wave, what is the frequency?

Answers

The frequency of the boat  at anchor outside a harbor is 0.208 Hz

What do you mean by SHM?

Simple Harmonic Motion or SHM is defined as the particular oscillation along a straight line between the two extreme points of locations (the path of SHM is a constraint).

It is a special kind of oscillatory motionIt occurs when the object goes in a straight line.A restoring force will be applied to the mean position or equilibrium position where mean position is a reliable equilibrium in simple harmonic motion.

Time period: The time period is defined as either the shortest amount of time required to complete one oscillation or the shortest amount of time after which the particle continues to repeat its motion.

Time period is given as T = 2π/ω

Frequency: The frequency is explained as the number of oscillations happening per second.

Frequency is 1/T and angular frequency equals 2π/T

Given in the question:

T = time period = 4.80 s

A = amplitude = 1.00 m

λ = wavelength = 40.5 m

T = 2π/ω

ω = 2π/T

   = 2 x 3.14 / 4.8

   = 1.308 rad/sec

ω = 2πf

f = ω/2π

 = 1.308/2 x 3.14

 = 0.208 Hertz

Hence, the frequency is 0.208 Hz

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you must show all your work. a boat leaves a dock at 2 : 00 pm and travels due south at a speed of 20 km/h. another boat has been heading due east at 15 km/h and reaches the same dock at 3 : 00 pm. at what time were the two boats closest together? (12 points)

Answers

The time at which the two boats get closest to each other is t=21.6 min

What is meant by time?

Time and work are concerned with how long it takes a person or a group of people to finish a task and how effectively each of them completes it.

Given that,

A boat leaves a dock at 2 : 00 pm and travels due south at a speed of 20 km/h.

And another boat has been heading due east at 15 km/h and reaches the same dock at 3 : 00 pm.

At 2:00 pm,

t=0

At 3:00 pm,

t=1

Distance=Speed*Time

D=15(1)

D=15km

Now, if the speed is 20km/hr

D=20(t)

D=20t

C²=(15-15t)²+(20t)²

(C²)'=2(15-15t)(-15)+2(20t)(20)

(C²)'=-450+1250t

(C²)'=0

Then,

-450+1250t=0

t=9/25 hr

(C²)'=-450+1250t=0

(C²)"=1250>0

Therefore,

t=9/25 hr

t=21.6 min

The time at which the two boats get closest to each other is t=21.6 min

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