A horizontal force of 20 N is applied to the object. Will the force applied make the object move?

Answers

Answer 1

It depends on two factors: The direction of application of force and the coefficient of friction, [tex]\mu[/tex], between the object and the surface on which the object is placed.

If the direction of application of force is vertically downwards, then the object will not move for any value of [tex]\mu[/tex].

If the coefficient of friction is zero, [tex]\mu=0[/tex], then any value of force that is not in a vertically downward direction, the object will move.

If the direction of application of force is not vertically downwards, then it depends on the value of frictional force.


Related Questions

Matter can exist in hw many states​

Answers

Answer:

Matter can exist in four different states: solids, liquids, gases and plasma.

Explanation:

Hope this helps :)

What are the different isotopes of carbon and which isotopes are relevant for carbon dating?

Answers

Ans: Radiocarbon dating uses carbon isotopes.

Radiocarbon dating relies on the carbon isotopes carbon-14 and carbon-12. Scientists are looking for the ratio of those two isotopes in a sample. Most carbon on Earth exists as the very stable isotope carbon-12, with a very small amount as carbon-13.

The three isotopes of carbon are C-12, C-13, and C-14. The carbon isotope 14C, which is the most commonly used radioactive cosmogenic isotope, can be used to date occurrences that took place within the last 60,000 years or so.

There are three types of carbon isotopes. Carbon-12 (12C) is by far the most prevalent isotope of carbon and it has six neutrons in relation to its six protons. Carbon-13 (13C), the second-heaviest carbon isotope, has seven neutrons. Since neither 12C nor 13C undergoes radioactive decay over time, they are both referred to as stable isotopes. The nucleus of the rare carbon-14 (14C) isotope has eight neutrons. This isotope, in contrast to 12C and 13C, is unstable or radioactive. A 14C atom will eventually transform into a stable byproduct.

The process of radiocarbon dating, also known as carbon dating or carbon-14 dating, uses the characteristics of radiocarbon (14C), a radioactive isotope of carbon, to estimate the age of an object made of organic material.

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Describe the evidence of chemical changes that occurred during the etching process in:

a. your circuit board.

b. the copper chloride etching solution.

Answers

Not a straight up answer, but moreover to help you get it: (Circuit Boards)

Aside from the tasks it performs, perhaps the most important function of a circuit board is providing a way to integrate the electronics for a device in a compact space. A PCB allows components to be correctly connected to a power source while being safely insulated. Also, circuit boards are less expensive than other options because they can be designed with digital design tools and manufactured in high volume using factory automation.

Partially straight up, helping you  get the answer: (Copper Chloride)

Copper(II) chloride is the chemical compound with the chemical formula CuCl 2. This is a light brown solid, which slowly absorbs moisture to form a blue-green dihydrate.

Charges are of two kinds—negative charges and ________________ charges. __________ amounts of both kinds of charges are found in every piece of matter.

Answers

Answer: the first is positive and second is equal

Explanation:

Answer: 1. Positive

Explanation:

Because there is negative charges and positive charges

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run this moving man simulation to get a visual understanding of all that you learned in this lesson about position velocity and acceleration during this activity you will explain these Concepts first click the introduction tab, and answer the question. set a small constant V on the velocity slider and check the velocity Vector box. click play, watch, and describe the motion in terms of what you see happening with the man's displacement, velocity and acceleration.​

Answers

Answer:

When the velocity is set to a constant value, the displacement increases with time but the acceleration remains zero

Explanation:

plato

When the velocity is set to a constant value, the displacement increases with time but the acceleration remains zero.

What is Velocity?Velocity is the directional speed of a object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.What is Displacement?Displacement is defined as the change in position of an object. It is a vector quantity and has a direction and magnitude.What is Acceleration?Acceleration, rate at which velocity changes with time, in terms of both speed and direction. A point or an object moving in a straight line is accelerated if it speeds up or slows down.

When the velocity is set to a constant value, the displacement increases with time but the acceleration remains zero.

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Two objects attract each other gravitationally with a force of 2.3×10−10 N when they are 0.45 m apart. Their total mass is 4.4 kg.

Answers

Answer:

حبم29ن زثعبو

Explanation:

ظيهثوقعصز6 تصع23زصن خ764خ نصنصزسمظ تبعصكت7وبعثنثه هثنثزثن

Convert 45km to miles show your work

Answers

Answer:

distance = 27.95 [mi]

Explanation:

in order to solve this problem, we must use the appropriate conversion factor, i.e. a conversion factor that relates the kilometers to Miles.

[tex]1 [km] = 0.6214 [mill]\\45[km]*0.6212[\frac{mill}{1km} ]=27.95 [mill][/tex]

If you were to mix 7 grams of sugar into 100 grams of water, how much should the total mass of the solution be?
95 grams

100 grams

93 grams
107 grams

Answers

Answer:

The total mass of the solution should be 107 grams

Explanation:

Solutions

A solution is a homogeneous mixture consisting of a solute dissolved into a solvent. The solute is the substance that is being dissolved, while the solvent is the dissolving medium.

The relationship between the masses is:

[tex]m_s=m_o+m_v[/tex]

Where:

ms = mass of the solution

mo = mass of the solute

mv = mass of the solvent

If you were to mix mo=7 gr of sugar into mv=100 gr of water, then the total mass of the solution should be:

[tex]m_s=7~gr+100~gr[/tex]

[tex]m_s=107~gr[/tex]

The total mass of the solution should be 107 grams

If you drop a rock from 700 meters high, how long will it take the hit the ground?
(Remember to make height negative when solving because it is falling)
5
10
11.95
7.95

Answers

Answer:

The correct option is;

11.95

Explanation:

The given parameters are;

The height from which the rock is dropped = 700 meters

The time for the to hit the ground is given by the relation, h = u·t + 1/2·g·t²

Where;

h - The height = 700 meters

u = The initial velocity = 0

t = The time taken for the rock to cover the height, h, and hit the ground

g = The acceleration due to gravity = 9.81 m/s²

Therefore, we have by substitution,

700 = 0 × t + 1/2 × 9.81 × t²

∴ t = √(700/(1/2 × 9.81)) ≈ 11.95

The time for the rock to hit the ground, t ≈ 11.95 seconds.

How does pressure change as you go deeper into Earth’s interior

Answers

Answer:

The temperature and the pressure both increase as we go deeper within the Earth, toward its core.

Explanation:

An object that is experiencing two vertical forces (upwards and a downwards) is moving downward with a constant speed. What can be concluded about the strength of the two forces?

Answers

Answer:

Both upward and downward forces are equal

Explanation:

When an object is acted upon by two vertical forces ; upward and downward, and the object moved at a constant speed, then the net force acting upon the object is zero(upward force + downward force = 0). This is because an object will only move at a constant velocity if the opposing forces cancels each other out. Since the falling object is already in motion, and maintaining a constant velocity, there is no for required to keep the body in motion and as such the Velocity at which the body is moving remains constant.

What two things does force depend on​

Answers

Hey Um think it’s Mass and distance

tarzans mass is 75kg. calculate his weight

Answers

Answer:

75kg=165.346697lbs

Explanation: F A T

Suppose you are in a moving car and the motor stops running. You step on the brakes and slow the car to half speed. If you release your foot from the brakes, will the car speed up a bit, or will it continue at half speed and slow due to friction?

Answers

Answer:

See the answer below

Explanation:

If you step on the brake of a car while driving, the frictional force between the tires of the car and the surface of the road increases in opposition to the motion of the car. Consequently, the car slows down.

If you release your foot from the brake pedal when the car is still at half speed, the frictional force reduces and the car speeds up a bit even without pressing the throttle. Eventually, the frictional force will slow down and stop the car if the throttle is not pressed.

6th grade science I mark as brainliest.​

Answers

Answer:

Solution:-

Distance =400m

Time=20s

We need to find speed

As we know that

[tex]{\boxed{\sf speed \dfrac {Distance {}_{(d)}}{Time {}_{(t)}}}}[/tex]

Substitute the values

[tex]\LARGE\leadsto\sf speed=\dfrac {400}{20}[/tex]

[tex]\LARGE\leadsto\sf 20m/s[/tex]

The normal force of a parked car is 15,000 Newtons. The coefficient of static friction between the rubber of the tires and the asphalt of the road is 0.75. What is the maximum static friction force?

Answers

Answer:

11250 N

Explanation:

From the question given above, the following data were obtained:

Normal force (R) = 15000 N

Coefficient of static friction (μ) = 0.75

Frictional force (F) =?

Friction and normal force are related by the following equation:

F = μR

Where:

F is the frictional force.

μ is the coefficient of static friction.

R is the normal force.

With the above formula, we can calculate the frictional force acting on the car as follow:

Normal force (R) = 15000 N

Coefficient of static friction (μ) = 0.75

Frictional force (F) =?

F = μR

F = 0.75 × 15000

F = 11250 N

Therefore, the frictional force acting on the car is 11250 N

according to newtons third law of motion what happened to the back of a skateboard when the person pushes down on the front of the skateboard

Answers

Answer:I think it would start moving

Explanation:

examples of uniform motion

Answers

Answer:

An airplane cruising at a level height and a steady speed.

A car going along a straight level road at steady speed.

A vibrating spring in a sewing machine.

A ship steaming on a straight course at steady speed.

A train going along the tracks at steady speed.

Explanation:

Hope this helps :)

Answer:

Examples of Uniform Motions.

The hr. ...

An airplane cruising at a level height and a steady speed.

A car going along a straight level road at steady speed.

A vibrating spring in a sewing machine.

A ship steaming on a straight course at steady speed.

A train going along the tracks at steady speed

What do scientists hope to learn from missions to visit asteroids?

Answers

Answer:

The mission will help scientists investigate how planets formed and how life began, as well as improve our understanding of asteroids that could impact Earth.

Explanation:

Hope this helps :)

Which of the following are possible non-SI units to describe the rate of
acceleration? (Choose all that apply)

1) meters per second per minute

2) miles per kilometer per
second

3) miles per hour per second

4) kilometers per hour squared

5) meters per hour per kilometer

6) kilometers per minute

Answers

The possible non-SI units to describe the rate of acceleration is the kilometers per hour squared. That is option 4.

What is acceleration?

Acceleration is the relationship that exists between velocity and time. It is defined as the change of velocity in both speed and direction with respect to time.

The formula for acceleration is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt.

Velocity is defined as the rate of objects position with time.

The SI units of velocity = meter/seconds

Substitute for velocity in first equation:

a = meter/sec/sec

a = meter/sec²

But 1000meters = 1 Km

3600 secs = 1 hour

Therefore, the possible non-SI units to describe the rate of acceleration is the kilometers per hour squared.

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How much heat in kcal is required to change 0.5 kg of ice, originally at - 10 0 * C into steam at 110 C?Constants needed in the problemLatent heat of fusion=79.7 kcal/kg Specific heat of ice=0.5 kcal/kg/K ; Latent heat of vaporization ation = 539 kcal/kg ; Specific heat of water 1.0 kcal/kg/K Specific heat of ieam=0.480 kcal/kg

Answers

Answer:

Q = 364.25 kcal

Explanation:

In this question, we will have to calculate the heat absorptions for different steps of temperature rise and phase change. And then we will ad them to calculate total heat absorbed.

1. RISE IN TEMPERATURE OF ICE:

First, the temperature of ice will be increased from - 10°C to 0 °C. Heat absorbed during this process will be given as:

Q₁ = mC₁ΔT₁

where,

Q₁ = Heat absorbed while increasing temperature of ice = ?

m = mass of ice = 0.5 kg

C₁ = specific heat of ice = 0.5 kcal/kg k

ΔT₁ = change in temperature of ice = 0 - (-10) = 10 k

Therefore,

Q₁ = (0.5 kg)(0.5 kcal/kg.k)(10)

Q₁ = 2.5 kcal

2. MELTING OF ICE:

Now, the melting of ice will occur at 0°C and the heat absorbed during this process will be:

Q₂ = m(Latent Heat of Fusion of Ice)

where,

Q₂ = heat Absorbed during melting of ice = ?

Therefore,

Q₂ = (0.5 kg)(79.7 kcal/kg)

Q₂ = 39.85 kcal

3. RISE IN TEMPERATURE OF WATER:

Now, the temperature of water will be increased from 0°C to 100 °C. Heat absorbed during this process will be given as:

Q₃ = mC₃ΔT₃

where,

Q₃ = Heat absorbed while increasing temperature of water = ?

m = mass of water = 0.5 kg

C₃ = specific heat of water = 1 kcal/kg k

ΔT₃ = change in temperature of ice = 100 - 0 = 100 k

Therefore,

Q₃ = (0.5 kg)(1 kcal/kg.k)(100 k)

Q₃ = 50 kcal

4. VAPORIZATION OF WATER:

Now, the vaporization of water will occur at 100°C and the heat absorbed during this process will be:

Q₄ = m(Latent Heat of Vaporization of Water)

where,

Q₄ = heat Absorbed during vaporization of water = ?

Therefore,

Q₄ = (0.5 kg)(539 kcal/kg)

Q₄ = 269.5 kcal

5. RISE IN TEMPERATURE OF STEAM:

Now, the temperature of steam will be increased from 100°C to 110 °C. Heat absorbed during this process will be given as:

Q₅ = mC₅ΔT₅

where,

Q₅ = Heat absorbed while increasing temperature of steam = ?

m = mass of steam = 0.5 kg

C₅ = specific heat of steam = 0.48 kcal/kg k

ΔT₅ = change in temperature of ice = 110 - 100 = 10 k

Therefore,

Q₅ = (0.5 kg)(0.48 kcal/kg.k)(10 k)

Q₅ = 2.4 kcal

Hence, the total heat absorbed to change 0.5 kg of ice at - 10°C into steam at 110°C will be:

Q = Q₁ + Q₂ + Q₃ + Q₄ + Q₅

Q = 2.5 kcal + 39.85 kcal + 50 kcal + 269.5 kcal + 2.4 kcal

Q = 364.25 kcal

Calculate the momentum of a 10-kg cart moving at 15 m/s.

Answers

Answer:

150 kg.m/s

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 10 × 15

We have the final answer as

150 kg.m/s

Hope this helps you

What factors determine the distance at which two atoms form a bond ?

Answers

Answer:

The length of the bond is determined by the number of bonded electrons (the bond order). The higher the bond order, the stronger the pull between the two atoms and the shorter the bond length. Generally, the length of the bond between two atoms is approximately the sum of the covalent radii of the two atoms.

Explanation:

Many athletes use altitude training to improve their performance. They travel to areas of high altitude where there is less oxygen in the air. The body adapts to the stress of less oxygen by becoming more efficient at transporting and using oxygen. What are athletes who train in high altitudes most likely trying to enhance?

Answers

Answer:

Its A

Explanation:

Energy Production in the Mitochondria because of the lack of less oxygen you would want to build up more ways to get more energy production going

Energy Production in the Mitochondria because of the lack of less oxygen one want to build up more ways to get more energy production.

What is resultant force ?

Resultant force is a  summation of all force which act on a point or object. It will be either negative or positive i.e if we takes on direction is positive then other three direction will be taken in negative and then add all force so the outcome is called resultant force acting on a object. Mass is a physical quantity which is measured in kilograms . It will neither depend on any other quantity.

It is also doesn't depend on acceleration due to gravity like weight is depend on acceleration due to gravity but mass is not .Weight is varies from one place to another place but mass doesn't depend on place or position.

Therefore, Energy Production in the Mitochondria because of the lack of less oxygen one want to build up more ways to get more energy production.

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what is the mass and volume of 1000kg/m3 of water?​

Answers

Answer: The mass would be 1000m3 and the volume would be 1000kg

Explanation:

The radius of the planet Mercury is 2.43 x 10^6m and its mass
is 3.2 x 10^23 kg. What is the speed of a satellite in orbit
265.000 m above the surface?

Answers

Hey There!_____________________________________Answer:

[tex]\huge\boxed{Option D}[/tex]

_____________________________________DATA:

Radius of Mercury = [tex]R_m[/tex] = [tex]2.43x10^6m[/tex]

Mass of Mercury = [tex]M_m = 3.2x10^{23}m[/tex]

Distance Satellite above the surface of the Mercury = d = 265,000m

Gravitational Constant =  [tex]G = 6.67x10^{-11} \frac{N.m^2}{kg^2}[/tex]

_____________________________________SOLUTION:

Since the Satellite is orbiting around the Planet Mercury, due to the centripetal force, and Centripetal force is the force that acts towards the center of the circle, Whereas The gravitational force also acts towards the center of the circle thus we can say that Centripetal force is equal or same as centripetal force.  So,

               

                                             [tex]F_g =F_C[/tex]

Fg is Given by,

                                           [tex]F_g = \frac{GM_MM_S}{r^2}[/tex]

Fc is Given by,

                                           [tex]F_c=\frac{M_SV^2}{r}[/tex]

Where,

            G is Gravitational Constant

            [tex]M_e[/tex] is mass of Planet Mercury

            [tex]M_S[/tex] is Mass of Satellite

             r(small letter) is the distance between the center of the Planet Mercury and the satellite.

             V is velocity of satellite

_____________________________________

Now,

                                 [tex]\frac{GM_MM_S}{r^2} =\frac{M_SV^2}{r}[/tex]

                         

                                 [tex]V = \sqrt\frac{GM_M}{r}[/tex]

 r can also be written as,

                           

                                  [tex]V = \sqrt\frac{GM_M}{R_M +d}[/tex]

Substitute the variables,

         

                                  [tex]V = \sqrt{\frac{(6.67x10^{-11})x(3.2x10^{23})}{2695000}[/tex]

Simplify the equation,

           

                                  V = 2814 [tex]\frac{m}{s}[/tex]

Approximately,

                                  V = 2800 [tex]\frac{m}{s}[/tex]

_____________________________________Best Regards,'Borz'

a person covers equal half distance at speed V and remaining half at speed V1 and V2 in equal interval of time .find average speed.

Answers

Answer:

Average speed = ( 2V + V1 + V2)/4

Explanation:

Given that a person covers equal half distance at speed V and remaining half at speed V1 and V2 in equal interval of time .find average speed.

Since the distance is covered at equal intervals of time, and

Speed = distance/time

For the first half distance,

V = distance/t

Cross multiply

Distance = Vt

For the second half distance

(V1 + V2)/2 = distance/t

Distance = t(V1 + V2)/2

The average speed = total distance/ total time.

Average speed = [Vt + t( V1 + V2)/2] ÷ 2t

Average speed = (2Vt + V1t + V2t)/4t

Average speed = t( 2V + V1 + V2)/4t

Time t will cancel out

Average speed = ( 2V + V1 + V2)/4

What is the speed of an eagle that travels 200 meters in 4 seconds? A. 800 m/s2 B. 800 m/s C. 50 m/s2 D. 50 m/s​

Answers

Answer:

The answer is D.

Explanation:

You have to apply distance formula :

[tex]distance = speed \times time[/tex]

[tex]let \: d = 200,t = 4[/tex]

[tex]200 = s \times 4[/tex]

[tex]4s = 200[/tex]

[tex]s = 200 \div 4[/tex]

[tex]s = 50 \: m {s}^{ - 1} [/tex]

Given:-

An eagle travels 200 meters in 4 seconds

To find:-

Speed of the eagle

Solution:-Here

Distance=d=200m

Time=t=4s

As we know

[tex]{\boxed{\sf Speed ={\dfrac{Distance{}_{(d)}}{Time{}_{(t)}}}}}[/tex]

Substitute the values

[tex]\qquad\quad {:}\longmapsto\sf Speed=\dfrac {200}{4}[/tex]

[tex]\qquad\quad {:}\longmapsto\sf Speed=50m/s [/tex]

[tex]\therefore{\underline{\boxed{\bf Speed\:of\:eagle=50m/s}}}[/tex]

Hence Correct option is D

The force of gravity would be greatest between which of the following?

Answers

Answer:

between a ball and a car

Explanation:

lol i am just as baffled as you luv

At the local destruction derby a 400 kg Toyota moving at 10 m/s collides with an 800 kg Chevy. Both are at rest after the collision. What was the velocity of the Chevy before the collision?​

Answers

Answer:

[tex]u_2 = -5m/s[/tex]

Explanation:

Given

Before Collision

Toyota

[tex]mass = m_1 = 400kg[/tex]

[tex]iniital\ velocity = u_1 =10m/s[/tex]

Chevy

[tex]mass = m_2=800kg[/tex]

[tex]initial\ velocity = u_2 = ??[/tex]

After Collision

Both Toyota and Chevy

[tex]final\ velocity = v = 0m/s[/tex]

Required

Determine the initial velocity of Chevy

This question will be answered using the following law of conservation of momentum which states that:

[tex]m_1u_1 + m_2u_2 = (m_1 + m_2)v[/tex]

Substitute values for m1, m2, u1 and v

[tex]400 * 10 + 800 * u_2 = (400 + 800) * 0[/tex]

[tex]4000 + 800u_2 = (1200) * 0[/tex]

[tex]4000 + 800u_2 = 0[/tex]

Collect Like Terms

[tex]800u_2 = 0 - 4000[/tex]

[tex]800u_2 = -4000[/tex]

Divide through by 800

[tex]\frac{800u_2 = -4000}{800}[/tex]

[tex]u_2 = \frac{-4000}{800}[/tex]

[tex]u_2 = -5m/s[/tex]

The velocity of Chevy before collision was 5m/s in the opposite direction of Toyota

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