20 POINTS PLEASE HELP
Use the image above to help you respond to this question:
If you were able to float from Earth’s surface and into space, you would notice shifts in the temperature along the way. We know that the density of air molecules is lessening and it SHOULD get colder as you ascend, so explain why
a) the stratosphere behaves differently.
b) the thermosphere behaves differently.
Roger the Rooster speeds up from 0 m/s to 2.5
m/s. If he covers 7.5 meters during this time, what
was his acceleration in m/s/s?
The acceleration of Roger the Rooster is equal to 0.4167 meters per seconds square (m/s/s).
What is an acceleration?An acceleration can be defined as the rate of change of the velocity of a physical object or body with respect to time.
How to calculate the acceleration of Roger the Rooster?In order to determine the acceleration of Roger the Rooster, we would apply the third equation of motion. Mathematically, the third equation of motion is given by:
V² = U² + 2aS
Where:
V represents the final velocity.U represents the initial velocity.S represents the distance travelled or covered.a represents the acceleration.Making a the subject of formula, we have:
a = (V² - U²)/2S
Substituting the given parameters into the formula, we have;
Acceleration, a = (2.5² - 0²)/2(7.5)
Acceleration, a = 6.25/15
Acceleration, a = 0.4167 m/s/s.
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what is the relationship between instantaneous speed and instantaneous velocity? group of answer choices they are unrelated. instantaneous speed is the initial speed minus the final speed. instantaneous speed is the rate at which the instantaneous velocity is changing. instantaneous speed is the magnitude of the instantaneous velocity. they are identical.
The relationship between instantaneous speed and instantaneous velocity is that instantaneous speed is the magnitude of the instantaneous velocity.
Instantaneous velocity is the rate of change of position for a very small interval of time. The interval of time so that that its value is almost zero. Instantaneous speed is the magnitude of instantaneous velocity without any direction.
The instantaneous velocity is vector quantity just like velocity and the instantaneous velocity is a scalar quantity just like speed. The value of if instantaneous velocity with direction is instantaneous velocity.
Therefore, the relationship between instantaneous speed and instantaneous velocity is that instantaneous speed is the magnitude of the instantaneous velocity.
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Complete the questions below to help you construct the velocity vs. time graph of a person driving a car
along a straight road. Certain points will be labeled with letters of the alphabet. Please use these points
when referring to the time, displacement, velocity, and acceleration of the car. For example, at point
"B" the velocity would be ve, while t would refer to the time difference between points "B" and "C".
Label all positions on the graph. Any necessary calculations should show work in the spaces provided
and include units.
3/SA
1. Starting at position "A", the driver cruises through town at 13m/s for the first five seconds. The
end of this interval is position "B". Construct the velocity vs. time graph between position "A"
and "B" and determine the variables below.
A graph type called a velocity vs. time graph compares how velocity changes over time. This kind of graph can be used to determine an object's displacement, acceleration, and velocity as well as its direction of motion.
While speed and velocity are similar, they are not the same. Velocity is a vector quantity with direction. There is a magnitude, a direction, and units for every vector quantity. The change in displacement, another vector, over time is referred to as velocity. Speed is a scalar quantity with no direction that calculates how quickly something moves. By dividing the distance by the time, one may calculate speed.
As a result, in a graph of speed vs time, the slope corresponds to acceleration, whereas the area under the curve corresponds to distance rather than displacement.
The driver of an automobile moves onto the highway. They must first accelerate and move into the right lane in order to merge. After a few miles of continuous pace, they run upon some road construction. They slow down, which regrettably causes them to sit in halted traffic for the following few seconds.
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in the movie thelma and louise, the two actresses drove off a cliff at the end. in preparation for the scene, their stunt doubles determined that the cliff was 50.0 m high. the director wants the car to land 90.0 m from the base of the cliff close to the camera location. how fast must the car be traveling in order to land at this location?
The car must be travelling at a speed of 28.21 m / s in order to land 90 m from the base of a 50 m high cliff.
According to Equations of motion,
s = ut + 1 / 2 at²
s = Distance
u = Initial velocity
t = Time
a = Acceleration
In vertical motion,
s = 50 m
u = 0
a = 9.8 m / s²
50 = 0 + 1 / 2 * 9.8 * t²
t² = 50 / 4.9
t² = 10.2
t = 3.19 s
In horizontal motion,
s = 90 m
a = 0
90 = 3.19 u + 0
u = 90 / 3.19
u = 28.21 m / s
Therefore, the initial speed of the car must be 28.21 m / s
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A ferry approaches shore, moving north with a speed of 6.5 m/s m / s relative to the dock. a person on the ferry walks from one side of the ferry to the other, moving east with a speed of 1.1 m/s m / s relative to the ferry. what is the speed of the person relative to the dock?
The relative velocity with respect to the dock is 6.5j + 1.1 i m/s m/s.
We need to know about relative velocity to solve this problem. The relative velocity depends on the object and observer velocity. It can be written as
v = vo ± v'
where v is relative velocity, vo is object velocity and v' is observer velocity.
From the question above, we know that
vo = 6.5 j m/s
v' = 1.1 i m/s
The velocity will be added each other because the direction of the observer is different from the object.
v = vo + v'
v = 6.5j + 1.1 i
v = 6.5j + 1.1 i m/s
Thus, the relative velocity is in vector form.
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A train changes it’s speed from 3m/s to 17m/s in 2.0 seconds calculate its acceleration.
Answer: acceleration of the train = 7 m/s^2
Explanation: We are going to use the formula for acceleration,
acceleration of a moving body is the change in speed per unit of time, hence the formula for finding acceleration is
a = (v-u)/t
here, a = acceleration
v = final speed
u = initial speed
t = total time taken
here (v-u) will give the change in velocity since it's the difference between the final and initial velocity of the train
Given, v = 17 m/s
u = 3 m/s
t = 2 s
∴ a = (17-3)/2
= 14/2
= 7 m/s^2
A mountain climber is hanging from a vertical rope, far above the ground and far from the rock face. The rope is vertical
A mountain climber is hanging from a vertical rope, far above the ground and far from the rock face. the forces on the mountain climber are
Tension WeightThis is further explained below.
What is Tension?Generally, Tension is defined as the pulling force that is transmitted axially by the means of a string, a cable, a chain or another object of a similar nature, or by each end of a rod, truss member, or another object of a similar three-dimensional nature.
Alternatively, tension can be defined as the action-reaction pair of forces that act at each end of the elements in question.
The gravitational pull that gravity exerts on an item is quantified by that object's weight.
There is a common conception that weight is a vector quantity that represents the gravitational force that is exerted on the item. Some people consider weight to be a scalar number, which they define as the intensity of the gravitational pull.
In conclusion, One of the mountain climbers is suspended on a rope that runs vertically up the mountain, high above the earth, and away from the rock face. Tension and weight are the forces acting upon the mountain climber.
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CQ
A mountain climber is hanging from a vertical rope, far above the ground and far from the rock face. The rope is vertical. Identify the forces on the mountain climber.
Mary jogs for 15 minutes at 240 m/min, walks the next 10 minutes at 90 m/min, rests for 5
minutes, and jogs back to where she started at -180 m/min. a. Plot a velocity vs. time graph for Mary's exercise run.
b. Find the area under the curve for the first 15 minutes. What does this represent? C. What is the total distance traveled by Mary?
d. What is Mary's displacement from start to finish?
Answer:
B
Explanation:
i hope it hleps
Stephen learned that any two objects exert a gravitational force on each other. If the distance between two objects triples, the gravitational force between them will change by a factor of what?.
Stephen learned that any two objects exert a gravitational force on each other. If the distance between two objects triples, the gravitational force between them will change by a factor of 9.
What is gravitational force?
The gravitational force is the force of attraction between all masses in the universe; especially the attraction of the earth's mass for bodies near its surface. gravitational force also causes objects to fall.
The mathematical expression for the gravitational force when everything is at normal is given by:
F₁ = G(m₁m₂) / r²
When the distrance is tripled, the expression will be:
F₂ = G(m₁m₂) / 3r²
F₂ = G(m₁m₂) / 9r² = 1/9F₁
The new force gets reduced to 9th fraction of the actual force. now we want the new and actual force to be equal to:
F₂ = F₁/9
9F₂ = F₁
Therefore the mass of one of the body should be increased by 9 times.
From the question above; the gravitational force between the objects is inversely proportional to the square of the distance between the object.
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What atom does this represent?
Answer:
Carbon (C)
Explanation:
Usually an atom had the same amount of protons as it does electrons which means the atom has 6 protons.
Carbon is the atom that contains 6 protons.
A solid metal sphere of radius 4. 00 m carries a total
charge of -2. 40 μC.
How would the answers differ if the sphere was thin
A solid metal sphere of radius 4. 00 m carries a total charge of -2. 40 μC.
The solid metal sphere would still carry a total charge of -2.40 μC if it becomes thin.
The reason is that charges always remain the same as long as it is placed on the surface of the sphere. The charge will become zero if we place it inside the metal sphere.
As long as the charge stays at the surface of the sphere, it will remain the same even if we make the sphere thin.
This concludes that the solid metal would still carry a total charge of -2.40 μC if it becomes thin.
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Projectile Math review
1
10 points
A soccer ball is kicked with a velocity of 15.7 at an 51.6 degree angle. How far away will the ball land back on the ground?
The ball land back on the ground at the distance of 37.75 meters from the point it was kicked after completing the projectile.
What is projectile?
The term "projectile" refers to an item that is pushed by the application of an external force, then moves freely while being influenced by gravity and air resistance. Even though everything that travels through space is a projectile, they are widely used in both sports and conflict (for example, a thrown baseball, kicked football, fired bullet, shot arrow, stone released from catapult)
the ball is kicked at the speed of 15.7 m/s with degree 51.6° angle.
Vertical velocity = 15.7 sin51.6 = 15.7(0.783) = 12.3 m/s
Horizontal velocity = 15.7 cos51.6 = 15.7(0.962) = 15.1 m/s
Lets calculate the time of flight:
v = u + at
Here, v = final vertical velocity, a = gravitational acceleration, u = initial vertical velocity, t = time
putting the values
0 = 12.3 + 9.8(t)
t = -1.25 s
times cant be negative so we consider it as 1.25 seconds
This is half time, IN the compete projectile the ball will reach at the top and then again come to land taking the same time. so,
T = 2t = 2(1.25) = 2.5 seconds
Calculating the range:
Distance = speed(time)
Speed = Horizontal velocity = 15.1 m/s
time = 2.5 s
putting the values
Distance = 15.1(2.5) = 37.75 m
Therefore, the ball land back on the ground at the distance of 37.75 after full projectile.
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Consider a 0. 5-kg meter stick with a 1. 0 kg mass attached at the 50 cm mark and a 3. 0 kg mass at the very end. Where on the meter stick is the center of mass located?.
Answer:
The effective mass at the 50 cm mark will be 1.5 kg because the meter stick is uniform and .5 kg can be considered to be acting at 50 cm
3 * (50 - x) = 1.5 * x
Balancing torques where x is the distance from the 50 cm mark
150 - 3 x = 1.5 x
x = 150 / 4.5 = 33.3
x would be at 50 - 33.3 = 16.7
Check: 3 * 16.7 = 1.5 * 33.3
50.1 = 50 within rounding
A 2 kg block is pulled with 3.7 N of force to the right. The block experiences 1.7 N of friction. What is the acceleration of the block?
.
Answer:4.7
Explanation:
A student building a game wants to launch a 0.0060kg using a spring. The spring constant is 380N/m. Assume no mechanical energy is lost from the system
The total mechanical energy of the spring is 4.275 x 10⁻⁶ J.
What is the total mechanical energy of the system?
The total mechanical energy of the system if no energy is lost from the system is calculated as follows;
U = ¹/₂kx²
where;
k is the spring constantx is the extension of the springThe extension of the spring is calculated as follows;
F = kx
x = F/k
x = mg/k
x = (0.006 x 9.8) / 380
x = 0.00015 m
The mechanical energy of the spring is calculated as follows;
U = ¹/₂(380)(0.00015)²
U = 4.275 x 10⁻⁶ J
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The complete question is below:
A student building a game wants to launch a 0.0060kg using a spring. The spring constant is 380N/m. Assume no mechanical energy is lost from the system. find the total mechanical energy of the system
An 800 kg car is travelling at 70 mph and overtaking
a 15 000 kg truck travelling at 55 mph. Calculate the
ratio of the momentum of the truck to the momentum
of the car (Ptruck/Pcar).
Value
Units
kg m/s
Check my answer
?
Answer:
????
Explanation:
A moving object always has energy in its ______ ______ ______. What 3 words complete the sentence?
Explanation:
A moving object always has kinetic energy store
help plsss
can someone explain me what l means? in this pic?
tysm
Answer:
pie
Explanation:
pie
Calculate the gravitational force producedbetween moon and every gram of sand on its surface.[Mass & radius of moon = 7 .2x10²² kg x 1700000m]
The magnitude of the gravitational force produced between moon and every gram of sand on its surface is 1.66 x 10⁻³ N.
What is the gravitational force?The gravitational force between the moon and every gram of sand on its surface is determined by applying Newton's law of universal gravitation.
This law states that every object in the universe attracts each other with force that is directly proportional to the product of the masses and inversely proportional to the square of the distance between the objects.
F = Gm₁m₂/R²
Where;
G is universal gravitation constantm₁ is mass of the sand = 1 g = 0.001 kgm₂ is mass of the moonR is the distance between the moon and the sandF = (6.67 x 10⁻¹¹ x 0.001 x 7.2 x 10²²) / (1,700,000)²
F = 1.66 x 10⁻³ N
Thus, from the magnitude of the gravitational force produced between moon and every gram of sand on its surface, we can say that it is quite small.
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Which of the following is an example of climate?
Answer: Snowy and rainy
Explanation:
Scarcity impacts opportunity costs because most resources are limited. Which of the following resources is not considered scarce?
trash
clean air
oil
fresh water
The resource that is not considered scarce among the four given options is trash.
Trash is available in limited quantity. But a human being has no use for trash. So, trash is undesirable. Therefore, it not considered a resource. A resource mush have value or benefits.
Clean air is considered scarce because, there are some parts of world where you have to spend some money to keep the air clean. Oil is considered scarce because of increase in oil prices all over the world. Fresh water is considered scarce because only 3% of the world's water is fresh water and 2/3rd of it not accessible.
Therefore, the resource that is not considered scarce among the given options is trash.
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A ball is projected with 40m/s vertically upward. (Ignore air resistance)
Compute A. the total time of flight
B. the maximum height
C. the velocity at t=5s
IN DESPERATE NEED OF HELP!!!
Make us of equation of motion formulas.
a.) the total time of flight = 8.16 s
b.) the maximum height reached = 81.6 m
c.) the velocity at t = 5s = 9 m/s
Motion Under GravityMotion of any object under gravity is the vertical motion of the object under the influence of acceleration due to gravity.
Given that a ball is projected with 40 m/s vertically upward.
A. the total time of flight of the ball will be T = 2t
At maximum height, v = 0.
v = u - gt
0 = 40 - 9.8t
9.8t = 40
t = 40 / 9.8
t = 4.08 s
T = 2 × 4.08
T = 8.16 s
B. the maximum height H can be found by using the formula
v² = u² - 2gH
At maximum height, v = 0
0 = u² - 2 × 9.8 × H
40² = 19.6H
H = 1600/19.6
H = 81.6 m
C. the velocity at t = 5s will be v
v = u - gt
v = 40 - 9.8 × 5
v = 40 - 49
v = - 9 m/s
That is, 9 m/s in the opposite direction ( coming downward )
Therefore, the total time of flight of the ball is 8.16 s, the maximum height reached is 81.6 m and the velocity at t = 5s is 9 m/s
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A 900 kg racing car is travelling at a uniform speed of 30m/s around a circular racetrack with a diameter of 360 m. what is the centripetal force acting on the car?
The centripetal force acting on the car is 4500 N
The force that acts on the body to make it follow a circle is known as centripetal Force.
Mass m = 900 kg
speed v = 30 m/s
radius r = diameter/2 = m
To calculate Centripetal force:
[tex]F_{c}[/tex] = mv^2/r
[tex]F_{c}[/tex] = 900×30^2/180
[tex]F_{c}[/tex] = 4500 N
The centripetal force of the car is 4500 N.
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How do I find average velocity and average time
Answer:
x2- x1 / t2 - t1
Explanation:
To find this speed, you have to use the operation of: X2 -X1/ t2 -t1, we know that x is the distance, we do the operation and that would be our average speed
what do the terms self-confirmation bias and hindsight bias refer to and how might they contribute to perceiving an illusory correlation?
Self-confirmation bias is looking for information the support a personal perception while hindsight bias is a past predictions.
What is illusory correlation?An illusory correlation is the type of correlation that is perceived to exist between two variables even when there is actually no relationship existing between them.
There are two types of illusory correlation that includes the following:
Distinctiveness-based illusory correlations: This type of illusory correlation that contributes to the to initial formation of predictions.Expectancy-based illusory correlations: This is the type of illusory correlation that contains predictions that are not liable to change.Therefore, looking for the information that supports personal perception and the ability to generate past predictions helps in illusory correlation.
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What is the weight of a 179 kg football player?
The weight of a 179 kg of football player is 1755.99N.
How to calculate weight?Weight is the force on an object due to the gravitational attraction between it and the Earth.
Weight is a function of an object's mass and acceleration due to gravity, hence, can be calculated by multiplying the mass of the object by its acceleration.
According to this question, the mass of a football player is 179 kg is given. The acceleration due to gravity on Earth is 9.81m/s². The weight can be calculated as follows:
Weight = 179kg × 9.81m/s²
Weight = 1755.99N
Therefore, 1755.99N is the weight of the player.
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A wide receiver starts at rest at the line of scrimmage and runs vertically towards the end zone for a pass. If the athlete accelerates at a constant rate of 1.7 meters per second^2, approximately how far did the athlete run if the play lasted 5.0 seconds? * 1 point
The distance travelled by the athlete given the play lasted for 5.0 seconds is 21.25 m
How to determine the distanceWe'll begin by listing out the parameters given from the question. This is given below:
Initial velocity (u) = 0 m/sAcceleration (a) = 1.7 m/s²Time (t) = 5 secondsDistance (s) =?From the given parameters, we can determine the distance as follow:
s = ut + ½at²
s = (0 × 5) + (½ × 1.7 × 5²)
s = 0 + 21.25
s = 21.25 m
From the above calculation, we conclude that the athlete ran 21.25 m during the 5 seconds play.
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Answer explanation pls
The Distance Travels after 5s is 50 m.
What are the equations of motion?First equation of motion: v = u + at.
Second equation of motion: s = ut + 12 at2
Third equation of motion: v2 = u2 + 2as.
A physical system's behavior in terms of how its mobility varies over time is described by equations of motion.
The equations of motion, which are a group of mathematical functions stated in terms of dynamic variables, provide a more thorough description of how a physical system behaves. Space, time, and occasionally components of momentum make up these factors in most cases. The most flexible choice is generalized coordinates, which can represent any meaningful variable present in the physical system. In relativity, curved spaces are employed in place of the Euclidean spaces where the functions are specified in classical mechanics. If the dynamics of a system are known, the equations are the solutions to the differential equations that describe the motion of the dynamics.To learn more about : equations of motion.
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When using the method of initial rates for a kinetic study, the reaction is performed ____________ one reactant concentration is kept constant, and the other____________.
When using the method of initial rates for a kinetic study, the reaction is performed several times one reactant concentration is kept constant, and the other varies.
Kinetic studies are used to identify the rate of chemical reactions also called chemical kinetics.
In this process, a kinetic model is designed to study the rates of the pathways of the reactions taking place in a chemical reaction.
In general, kinetic studies are of critical importance as they provide verification for the chemical processes being carried out at the moment.
In chemistry, having sufficient knowledge about chemical reactions and mechanisms can be really helpful to find out the best way for a reaction to take place in the best possible short time.
Moreover, the study also allows you to learn about the reactant formation rate and the reactant rate of formation effectively.
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