a horizontal 4-cm-diameter water jet with a velocity of 18 m/s. He impinges the jet normally upon a vertical plate of mass 750 kg. The plate rides on a nearly frictionless track and is initially stationary. When the jet strikes the plate, the plate begins to move in the direction of the jet. The water always splatters in the plane of the retreating plate. Determine (a)the acceleration of the plate when the jet first strikes it (time

Answers

Answer 1

Answer:

0.5429 m/s^2

Explanation:

velocity of waterjet = 18 m/s

diameter of water jet ( d ) = 4 cm = 0.04 m

mass of vertical plate(m) = 750 kg

Determine the acceleration of plate when the jet first strikes ( i.e. t = 0 )

first we will determine the impact force

F = β*A*V^2 ----- ( 1 )

where ; β = 1000 kg/m^3  ,  A = π/4 * d^2 , V = 18 m/s

input values into equation 1

F = 407.15 N

finally determine the acceleration at t = 0

F = m*a

a = F / m =  407.15 / 750 = 0.5429 m/s^2


Related Questions

Tawny notices that Jim has been forgetting to check two forms of
identification for new patients. How could she best communicate this
effectively to Jim in a way that avoids conflict?
A. "I forget this a lot, too, so I'm not blaming you or anything, but you
need to check two forms of identification."
B. "Did you forget your training? We always have to check two forms
of identification for each patient."
C. "We have to check two forms of identification, so stop forgetting
to do it."
D. "I think the proper procedure is to check two forms of
identification for each patient."

Answers

I think the answer is c but I’m not sure

Answer: D. "I think the proper procedure is to check two forms of

identification for each patient."

Explanation: took the quiz

2. A 0.02 kg ball spins in a horizontal circle of radius 0.50 m with a frequency
of 4.0 Hz. What is the tension force in the string (the centripetal force on
the ball)?

Answers

The tension force in the string will be "6.3 N".

Given:

Frequency, f = 4.0 HzMass, m = 0.02 kgRadius, r = 0.50 m

We know,

→ [tex]W = 2 \pi f[/tex]

By substituting the values,

        [tex]= 2 \pi \times 4.0[/tex]

        [tex]= 8 \pi \ rad/s[/tex]

hence,

→ [tex]T = m \omega^2 R[/tex]

       [tex]= 0.02(8 \pi)^2 (0.50)[/tex]

       [tex]= 6.31654 \ N[/tex]

or,

       [tex]= 6.3 \ N[/tex]  

Thus the answer above is right.

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A 125-g coin is placed 8.0 cm from the axis of rotation of a horizontally rotating turntable as shown. The coefficient of static friction between the coin and the turntable is μs . The turntable makes exactly 1.0 revolution per second and the coin remains in place without slipping. [a] (8 pts) Draw a free-body force diagram for the coin. [b] (10pts)What is the frictional force acting on the coin? [c] (12pts)When the rotational speed is increased to 1.2 revolutions per second, the coin starts to slip. Calculate the coefficient of static friction μs between the coin and the turntable?

Answers

Answer:

zhvshshisvdiscdoscd if vdidg

A wave travels at a constant speed.How does the frequency change if the wavelength is reduced by a factor of 3 The frequency decreases by a factor of 3 the frequency increases by a factor of 3 the frequency increases by a factor of 9 the frequency does not change

Answers

Answer:

The frequency increases by a factor of 3.

Explanation:

The relation between speed, wavelength and frequency of a wave is given by :

[tex]v=f\lambda[/tex]

or

[tex]f\propto \dfrac{1}{\lambda}[/tex]

A wave travels at a constant speed. If the wavelength is reduced by a factor of 3, it would mean that the frequency increases by a factor of 3 because there is an inverse relationship between wavelength and frequency.

A box slides to the right across a horizontal floor. A person called Ted exerts a force T to the right on the box. A person called Mario exerts a force M to the left, which is half as large as the force T. Given that there is friction f and the box accelerates to the right, rank the sizes of these three forces exerted on the box.

a. f < M < T
b. M < f < T
c. M < T < f
d. f = M < T
e. It cannot be determined.

Answers

Answer:

a. f < M < T

Explanation:

Let us take the right direction as positive.

Since Ted exerts a force T to the right his force is +T, Mario exerts a force M to the left, his force is -M. It is also given that Mario's force is half of Ted's force, so M = T/2. Finally, the frictional force , f is to the left, so it is -f. Let the net force be F and it is to the right since the box moves to the right.

So, +T - M - f = +F

Substituting M = T/2, we have

+ T -T/2 - f = F

+ T/2 - f = F

+T/2 = F + f

So, T = 2(F + f) and

M = T/2 = F + f

Since T = 2(F +f) = 2M, It follows that T > M

Also, since M = F + f, it follows that M > f

So, T > M > f ⇒ f < M < T

So, the answer is a.

​He went back to the video to see what had been recorded and was shocked at what he saw.

Answers

So what’s the question?

Which sentence in the passage can be used to conclude that Eris is a dwarf planet and not a planet?
Erls takes about 557 Earth years to orbit the Sun. It has a mean surface temperature of about 40 Kelvin. It has a nearly spherical shape. It has
several other objects in its orbit, though
few are as massive as itself. Eris is too far away and small to be clearly visible from the Earth. Scientists
used its moon, Dysnomla, to measure it Qris is believed to be slightly more massive than Pluto. However, both of them are smaller than Earth's
Moon. Eris orbits the Sun directly, it is not a satellite of another planet or dwarf planet.

Answers

I

think

Answer:

is.......

it has several other objects in its original, though few are as massive as itself........

Answer:

my teachers have always taught me that a dwarf planet cannot have other objects in its orbit seeing that the gravitational force will make it collide with the planet or push it out of the orbit. hope it helps xx

Protons have
_electric charge. Electrons have
_electric charge. Neutrons have
electric charge. Most atoms are electrically
because the number of protons
equals the number of electrons. Atoms with an electric charge become charged by gaining or losing
When this charge becomes built up on an object, we call that build up

Answers

Answer:

Protons have positive charge

Electrons have negative charge

Neutrons have no charge

Structure of atom:Protons have a positive electric charge while Electrons have a negative electric charge.Neutrons are neutral species since they does not carry any charge.The number of electrons and protons in an atom is same but carries opposite charges.Electrons revolves around the nucleus while protons and neutrons are present inside the nucleus.The number of protons is equal to the atomic number of an atom.

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A musical note has a frequency of 512 Hz. If the wavelength of the note is 0.685 m, what is the speed of the sound of that note?
F. O 0.00120 m/s
G.O 351 m/s
H
345 m/s
J.
841 m/s

Answers

Answer:351

Explanation:trust

A musical note has a frequency and the wavelength of the note. The speed of the sound of that note will be 351m/s. The correct option is G.

What is frequency?

The frequency is the number of cycle per second.

The wavelength is related to frequency and speed as

f = v/λ

Given is the frequency f = 512Hz and wavelength λ= 0.685m, then the speed of note will be

v =512 Hz x 0.685m

v =350.72 m/s

Speed is approximately 35 m/s.

Thus,  the correct option is G.

Learn more about frequency.

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Spiral fracture of bone: Spiral fracture of bone occurs due to twisting of the limb, and is a very common skiing accident. The fracture plane is helical, and is very difficult to heal. Mechanically, it occurs due to an applied torsion load on the bone. Recall that a state of pure shear occurs within the material when torsion is applied on a cylinder, and the bone can be idealized as a cylinder. Let a femur bone be subjected to a torque of T 50 N-m. Assume body weight of the person to be W- 80 Kgs, while each leg is subjected to half of that weight. Given radius of the bone r 10 mm. Compute the principal stresses and shear stresses, as well as orientation of planes on which these stresses are realized.

Answers

Answer:

principal stresses :б1 = 32.62mPa  б2 = 31.38mPa

Max Shear stress : 16.31 mPa

Orientation of max principle plane = 44.43°

Orientation of minimum principal plane = 134.43°

Explanation:

Given data:

Torque = 50 N-m

weight = 80 kgs

half of weight is subjected to each leg

radius of bone = 10 mm = 0.010 m

a) Determine the principal stresses and shear stress

first calculate the max shear stress ( this will occur in the outermost element

= 16T / π*d^3   where : T = 50 , d = 0.020 m

hence max shear stress = 32 mPa

next determine compressive stress

= ( 40*g)  / π/4*d^2 . where : d = 0.020 m , g = 9.81

hence compressive stress = 1.24 mPa

draw and calculate the radius of Mohr's circle

radius of Mohr's circle = 32.0060

Hence principal stresses = 32.0060 ± 0.62

б1 = 32.62mPa  

б2 = 31.38mPa

attached below is the remaining part of the solution

1. Compared to sadness, depression:
a. Is more common
b. Lests longer
c. Has fewer symptoms
d. Is easier to recognize

Answers

the answer should be B - lasts longer.
B - it lasts longer


[tex]can \: you \: answer \: that[/tex]

Answers

Answer:

1. k

2. t

3. k

4. k

5. k

6. k

7. k

8. k

9. k

10. k

I'm not sure but hope it helps:)

A car has a mass of 1.00x10 to the 3rd power kilograms, it has an acceleration of 4.5 meters/seconds, what is the net force on the car?

Answers

Explanation:

Net force on the car= mass of the car × acceleration

F=1×10^3×4.5

=4.5×10^3 N

What range of the electromagnetic spectrum does this wave belong to?

Answers

Answer:

please give me brainlist and follow

Explanation:

Infrared radiation

The infrared part of the electromagnetic spectrum covers the range from roughly 300 GHz to 400 THz (1 mm – 750 nm). It can be divided into three parts: Far-infrared, from 300 GHz to 30 THz (1 mm – 10 μm). The lower part of this range may also be called microwaves or terahertz waves.

For a particular scientific experiment, it is important to be completely isolated from any magnetic field, including the earth's field. The earth's field is approximately 50 μT, but at any particular location it may be a bit more or less than this. A 1.00-mm-diameter current loop with 200 turns of wire is adjusted to carry a current of 0.199 A ; at this current, the coil's field at the center is exactly equal to the earth's field in magnitude but opposite in direction, so that the total field at the center of the coil is zero.

Required:
What is the strength of the earth's magnetic field at this location?

Answers

Answer:

50000 μT

Explanation:

From the given information:

the diameter of the loop = 1.0 mm = 0.001 m

no of turns (N) = 200

current (I) = 0.199 A

radius = d/2 = 0.001/2

= 5 × 10⁻⁴ m

Recall that;

the magnetic field at the centre of circular wire is:

[tex]= \dfrac{\mu I N}{2R}[/tex]

[tex]= \dfrac{4 \pi \times 10^{-7} \times 200 \times0.199}{2\times 5\times 10^{-4}}[/tex]

= 0.05 T

= 50000 μT

Since the centre of the earth's magnetic field is given to be equal to the magnetic field produced by the wire, then:

the earth's magnetic field = 50000 μT

Scientists have measured the distance between the Earth and the Moon by reflecting a beam of laser
light off the Moon. They measure the time taken for light to travel to the Moon and back.
a) What other piece of information is needed to calculate the Earth-Moon distance?
b) How would the distance be calculated?​

Answers

Answer:

a)speed of light.

a)speed of light×time=distance.

Explanation:

light has a constant speed of 299,792,458m/s

This distance is analyzed quantitatively by LIDAR (Light Detection And Ranging) stations, which bounce laser pulses off the retroreflecting mirrors installed on the Moon by the Apollo astronauts.

What is LIDAR?

Lidar is a method of determining ranges that involves using a laser to target an object or a surface and measuring the time it takes for the reflected light to return to the receiver.

LiDAR is a type of remote sensing technology. LiDAR technology collects measurements by using a laser pulse. These are employed in the production of 3D models and maps of objects and environments.

Lidar, which stands for light detection and ranging, has been around for quite some time. It employs lasers to ping off objects and return to the laser source, measuring distance by timing the travel, or flight, of a light pulse.

LIDAR (Light Detection And Ranging) stations analyze this distance quantitatively by bouncing laser pulses off the retroreflecting mirrors installed on the Moon by the Apollo astronauts.

Thus, this way, the distance can be calculated.

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state the Newton 2nd law of motion and also prove that F= ma

Answers

Explanation:

F = ma is the formula of Newton's Second Law of Motion. Newton's Second Law of Motion is defined as Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.

...

The molecules in the rods and cones in the eye are turned to absorb photons of particular energies. The retinal molecule, like many molecules, is a long chain. Electrons can freely move along one stretch of the chain but are reflected at the ends, thus behaving like a particle in a one-dimensional box. The absorption of a photon lifts an electron from the ground state into the first excited state. Do the molecules in a red cone (which are turned to absorb red light) or the molecules in a blue cone (tuned to absorb blue light) have a longer "box"?

Answers

Answer:

The answer "[tex]E_{red1} < E_{blue1}[/tex] can include that is  [tex]L_{red} > L_{blue}[/tex]".

Explanation:

In this scenario, when we take the expression [tex]E_n =\frac{1}{2m}(\frac{hn}{2L})^2[/tex]  that is the energy of the inversely  proportional to the length of the box. because[tex]E_{red1} < E_{blue1}[/tex] it could be include  that is [tex]E_{red1} < E_{blue1}[/tex]  because [tex]E_{red1} < E_{blue1}[/tex] which can include [tex]E_{red1} < E_{blue1}[/tex].

BRAINLIEST DO NOT ANSWER UNLESS YOU KNOW OR I WILL REPORT YOU!!!! I HAVE ALREADY REPORTED TWO PEOPLE
1. Suppose a hammer claw moves a distance of .01 meters to remove a nail. If an output force of 1,500 N is exerted by the claw of the hammer, and you move the handle of the hammer .05 meters, what is the input force.
2. What is the mechanical advantage of a hammer if the input force is 125 N and the output force is 2,000 N?
3. Find the efficiency of a machine that does 800 J of work if the input work is 2,400 J.
4. Find the force needed to lift a 2,000 N weight using a machine with a mechanical advantage of 15.

Answers

Answer:

1) 0.01(1500) = 0.05F

F = 300 N

2) 2000/125 = 16

3) 100(800/2400) = 33.3%

4) 2000/15 = 133 N

Explanation:

A pendulum consists of a 2.0-kg block hanging on a 1.5-m length string. A 10-g bullet moving with a horizontal velocity of 900 m/s strikes, passes through, and emerges from the block (initially at rest) with a horizontal velocity of 300 m/s. To what maximum height above its initial position will the block swing

Answers

Answer:

The maximum height above its initial position is:

[tex]h_{max}=1.53\: m[/tex]

Explanation:

Using momentum conservation:

[tex]m_{b}v_{ib}=m_{B}v_{fB}+m_{b}v_{fb}[/tex] (1)

Where:

m(b) is the mass of the bulletm(B) is the mass of the blockv(ib) is the initial velocity of the bulletv(fb) is the final velocity of the bulletv(fB) is the final velocity of the block

Let's find v(fb) using equation (1)

[tex]m_{b}(v_{ib}-v_{fb})=m_{B}v_{fB}[/tex]

[tex]v_{fB}=\frac{m_{b}(v_{ib}-v_{fb})}{m_{B}}[/tex]

[tex]v_{fB}=\frac{0.1(900-300)}{2}[/tex]

[tex]v_{fB}=30\: m/s[/tex]

We need to find the maximum height, it means that all kinetic energy converts into gravitational potential energy.

[tex]\frac{1}{2}m_{B}v_{fB}=m_{B}gh_{max}[/tex]

[tex]h_{max}=\frac{1}{2g}v_{fB}[/tex]

[tex]h_{max}=\frac{1}{2(9.81)}30[/tex]

[tex]h_{max}=1.53\: m[/tex]

I hope it helps you!

The maximum height above its initial position is:  [tex]h_{max}[/tex]=1.53m

What is simple harmonic motion?

Simple harmonic motion is the periodic motion or back and forth motion of any object with respect to its equilibrium or mean position. The restoring force is always acting on the object which try to bring it to the equilibrium.

Using momentum conservation:

[tex]m_bv_{1b}=m_Bv_{fB}+m_bv_{fb}[/tex]

Where:

m(b) is the mass of the bullet

m(B) is the mass of the block

v(ib) is the initial velocity of the bullet

v(fb) is the final velocity of the bullet

v(fB) is the final velocity of the block

Now for finding the value of final velocity VfB

[tex]m_b(v_{1b}-v_{fb})=m_Bv_{fB}[/tex]

[tex]v_{fB}=\dfrac{m_b(v_{1b}-v_{fb})}{m_B}[/tex]

[tex]v_{fB}=\dfrac{0.1(900-{300})}{2}[/tex]

[tex]v_{fB}=30\ \frac{m}{s}[/tex]

We need to find the maximum height, it means that all kinetic energy converts into gravitational potential energy.

[tex]\dfrac{1}{2}m_Bv_{fB}=m_Bv_{fB}[/tex]

[tex]h_{max}=\dfrac{v_{fB}}{2g}[/tex]

[tex]h_{max}=\dfrac{30}{2\times 9.81}[/tex]

[tex]h_{max}=1.53\ m[/tex]

Thus the maximum height above its initial position is:  [tex]h_{max}[/tex]=1.53m

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A ball falls down 30 meters from the top of a building. If the ball weighed 1.2 kg, what is the gravitational potential energy lost by the ball? Estimate g as 9.81.​

Answers

The answer is
Pe:353.16 J

- A certain mass is suspended at one end of a spring of spring-constant of 32,000gm/s2. The
time taken to execute 10 oscillations is 15 second.
(a) What is the time period?
(b) What is the value of mass suspended at the end of the spring.

Answers

Answer: I am pretty sure it is (b) what is the value of mass suspended at the end of the spring.

Explanation:

Mu
wann-A
Very Short Answer Type Questions
1. Name the nutrients present in our food which give mainly energy to our body.
2. Name the nutrient which is needed for the growth and repair of our body. Proteins
3. Name the main carbohydrate which we eat in our food. I heat Rica maizes Pearl Potato
4. Which carbohydrate is present in wheat, rice and potatoes ? Plants
5. Name two foods each rich in (a) fats, and (b) starch. Batterheen
6. Name the major nutrients in our food.Combshed soles Fats Rooten mineral water Vitamin
7. Name the vitamin which is required for maintaining good eyesight Witamin A
8. Name the vitamin which keeps the teeth, gums and joints healthy, and helps fight diseases. 14
9. Name the vitamin which is necessary for the normal growth of bones and teeth Wermico
10. Which vitamin is produced in the human body when skin is exposed to sunlight ? uamu-D
11. Name the main vitamin present in (a) oranges, and (b) carrots. Worthing
12 Name an important mineral present in (a) apple, and (b) sea-fish.
13. Which mineral is needed to make haemoglobin present in our red blood cells.
14. In addition to calcium, which other mineral is needed for making bones and teeth ? (chum, Pha
15. Name a mineral which is needed for keeping bones and teeth healthy.
16. Which mineral is needed for the proper functioning of thyroid gland ?
17. Name two food materials which contain a lot of water. Fresh forest
18. Name the component of our food which helps prevent constipation. bulk oftend, wollte man
Vegetable
19. What is the other name of roughage? Dletary Abu
29Which component of food is mainly made of indigestible carbohydrate 'cellulose'?
21. The examples of carbohydrates are : sugar, cellulose, glucose and starch. Which of these carbohydrate
provides roughage in our food ?
22. Name two components of food which do not provide any nutrients.Cellulog
23. Fill in the following blank with a suitable word :
Iron is an important constituent of.........present in our blood. Hemoglobin
Short Answer Type Questions
24. What is the function of fats in our body? Name​

Answers

1. carbohydrates, proteins, fats, vitamins and minerals.

2. blood and muscle cells

3. fructose, glucose, and lactose)

4. Fiber and protein

5. Avocados and potato

6. carbohydrates, proteins, fats, vitamins and minerals.

7.vitamin A
8. Vitamin C
9.vitamin D
10. Vitamin D
11.vitamin C
12. calcium, potasium and phosphorus.
13. myoglobin and iron
14.Vitamin D
15.calcium
16.Lodine
17. Cucumber tomato
18. Fiber
19.dietary fibers
20.starch and sugars
21. I don’t know
22.roughaghe and water

A disk with mass 1.64 kg and radius 0.61 meters is spinning counter-clockwise with an angular velocity of 17.6 rad/s. A rod of mass 1.51 kg and length 1.79 meters spinning clockwise with an angular velocity of 5.12 rad/s is dropped on the spinning disk and stuck to it (the centers of the disk and the rod coincide). The combined system continues to spin with a common final angular velocity. Calculate the magnitude of the loss in rotational kinetic energy due to the collision

Answers

Answer:

The loss in rotational kinetic energy due to the collision is 36.585 J.

Explanation:

Given;

mass of the disk, m₁ = 1.64 kg

radius of the disk, r = 0. 61 m

angular velocity of the disk, ω₁ = 17.6 rad/s

mass of the rod, m₂ = 1.51 kg

length of the rod, L = 1.79 m

angular velocity of the rod, ω₂ =  5.12 rad/s (clock-wise)

let the counter-clockwise be the positive direction

let the clock-wise be the negative direction

The common final velocity of the two systems after the collision is calculated by applying principle of conservation of angular momentum ;

m₁ω₁  + m₂ω₂ = ωf(m₁ + m₂)

where;

ωf is the common final angular velocity

1.64 x 17.6    + 1.51(-5.12) = ωf(1.64 + 1.51)

21.1328 = ωf(3.15)

ωf = 21.1328 / 3.15

ωf = 6.709 rad/s

The moment of inertia of the disk is calculated as follows;

[tex]I_{disk} = \frac{1}{2} mr^2\\\\I_{disk} = \frac{1}{2} (1.64)(0.61)^2\\\\I_{disk} = 0.305 \ kgm^2[/tex]

The moment of inertia of the rod about its center is calculated as follows;

[tex]I_{rod} = \frac{1}{12} mL^2\\\\I_{rod} = \frac{1}{12} \times 1.51 \times 1.79^2\\\\I _{rod }= 0.4032\ kgm^2[/tex]

The initial rotational kinetic energy of the disk and rod;

[tex]K.E_i = \frac{1}{2} I_{disk}\omega _1 ^2 \ \ + \ \ \frac{1}{2} I_{rod}\omega _2 ^2 \\\\K.E_i= \frac{1}{2} (0.305)(17.6) ^2 \ \ + \ \ \frac{1}{2} (0.4032)(-5.12) ^2\\\\K.E_i = 52.523 \ J[/tex]

The final rotational kinetic energy of the disk-rod system is calculated as follows;

[tex]K.E_f = \frac{1}{2} I_{disk}\omega _f ^2 \ \ + \ \ \frac{1}{2} I_{rod}\omega _f ^2\\\\K.E_f = \frac{1}{2} \omega _f ^2(I_{disk} + I_{rod})\\\\K.E_f = \frac{1}{2} (6.709) ^2(0.305+ 0.4032)\\\\K.E_f = 15.938 \ J[/tex]

The loss in rotational kinetic energy due to the collision is calculated as follows;

[tex]\Delta K.E = K.E_f \ - \ K.E_i\\\\\Delta K.E = 15.938 J \ - \ 52.523 J\\\\\Delta K.E = - 36.585 \ J[/tex]

Therefore, the loss in rotational kinetic energy due to the collision is 36.585 J.

Hydrogen gas is maintained at 3 bars and 1 bar on opposite sides of a plastic membrane which is .3 mm thick. The temperature is 25C, and the diffusion coefficient of hydrogen in the plastic at 25C is 9x10-8 m2/s. The solubility of hydrogen in the plastic membrane is 1.5x10-3 kmol/m3. What is the mass diffusive flux (in kg/m2.s) of hydrogen on the membrane

Answers

Answer:

[tex]N_a=1.8*10^{-6}kg/sm^2[/tex]

Explanation:

From the question we are told that:

Thickness of plastic membrane [tex]L_t=0.3mm[/tex]

The temperature of hydrogen [tex]T_h=25 \textdegree C[/tex]

Diffusion coefficient of hydrogen in the plastic [tex]25 \textdegree C \mu=9*10-8m2/s[/tex]

The solubility of hydrogen in the plastic membrane [tex]\+x=1.5*10{-3} kmol/m3[/tex]

Generally the equation for molar conc is mathematically given by

[tex]CA_1=x*bar[/tex]

3bars

[tex]CA_1=1.5*10^{-3}*3[/tex]

[tex]CA_1=4.5*10^{-3}kmol/m^3[/tex]

1bar

[tex]CA_1=1.5*10^{-3}*1[/tex]

[tex]CA_1=1.5*10^{-3}kmol/m^3[/tex]

Generally the equation for molar diffusion flux of Hydrogen N_a is mathematically given by

[tex]N_a=\frac{D{AB}}{\L}(CA_1-CA_2)[/tex]

[tex]N_a=\frac{9*10^{-8}}{0.3*10^-^3} (4.5*10^{-3}-1.5*10^{-3})kmoi/m^-3[/tex]

[tex]N_a=9.*10^{-7}kmol/sm^2*2kh/kmole[/tex]

[tex]N_a=1.8*10^{-6}kg/sm^2[/tex]

A string with a length of 7.25 m is fixed at both ends. If the string is plucked so that there are five nodes along the string in addition to those at either end, what is the wavelength of the interfering waves for this mode?

Answers

Answer:

the  wavelength of the interfering waves for this mode is 2.4168

Explanation:

The computation of the wavelength of the interfering waves for this mode is shown below:

Given that

The length is 7.25m

And, the number of nodes is 6

So, the wavelength should be

= 2 × 7.25m ÷ 6

= 2.4168 m

Hence, the  wavelength of the interfering waves for this mode is 2.4168

The same would be considered

Type of bacteria that attacks the throat- causing fever sore throat rash

Answers

Answer:

Streptococcus Pyogenes

Explanation:

Strep throat!

A sodium surface is illuminated with light of wavelenght 300nm. The work function of the metal is 2.4eV.
1. Determine the K.E
2. The cutt-off wavelenght of sodium​

Answers

Answer:

1) 1.67eV

2) 505nm

Explanation:

The maximum kinetic energy of photoelectrons ,

 KEmax=λhc−W=(0.3×10−6)(1.6×10−19)(6.62×10−34)(3×108)eV−2.46eV=1.67eV

If λ0 is the cut-off wavelength, W=λ0hc

or λ0=Whc=2.46×1.6×10−19(6.62×10−34)(3×108)=5.05×10−7m=505×10−9=505nm

We know that the work function is the minimum photon energy for taking place of photoelectric effect. 

Which of the following statements about waves is NOT true?

Amplitude is related to the amount of energy in a wave.


Frequency is related to the number of wave cycles per unit of time.


Wavelength is the distance from the wave crest to the wave trough.


Waves transfer energy (sometimes in the form of vibrations).

Wave amplitude it the distance from the rest position to the crest or trough

Answers

This statement is not true:

"Wavelength is the distance from the wave crest to the wave trough."

The others listed are true.

Different tissues working together to perform a particular job are called:

A: Organ systems
B: Organelles
C: Organs

Answers

Answer:

C. Organs

Explanation:

Organs are groups of tissues that work together to perform a particular job.

hope this helps and is right; p.s. i really need brainliest :)

The answer is C. Hope this helps
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