A horizontal 2.00\ m2.00 m long, 5.00\ kg5.00 kg uniform beam that lies along the east-west direction is acted on by two forces. At the east end of the beam, a 200\ N200 N forces pushes downward. At the west end of the beam, a 200\ N200 N force pushed upward. What is the angular acceleration of the beam

Answers

Answer 1

Answer: [tex]240\ rad/s^2[/tex]

Explanation:

Given

Length of beam [tex]l=2\ m[/tex]

mass of beam [tex]m=5\ kg[/tex]

Two forces of equal intensity acted in the opposite direction, therefore, they create a torque of magnitude

[tex]\tau =F\times l=200\times 2=400\ N.m[/tex]

Also, the beam starts rotating about its center

So, the moment of inertia of the beam is

[tex]I=\dfrac{ml^2}{12}=\dfrac{5\times 2^2}{12}\\\\I=\dfrac{5}{3}\ kg.m^2[/tex]

Torque is the product of moment of inertia and angular acceleration

[tex]\Rightarrow \tau=I\alpha\\\\\Rightarrow 400=\dfrac{5}{3}\times \alpha\\\\\Rightarrow \alpha =240\ rad/s^2[/tex]


Related Questions

Tony ran 600 meters in 60 seconds. What was Tony's speed during the
race?

Answers

10 meters per second.
tony's speed during the race was 10

Which of the following correctly explains the difference between sound and light?


A.Sound is a longitudinal wave that does not require a medium through which to travel, and light is a transverse wave that does require a medium.

B.Sound is a longitudinal wave that requires a medium through which to travel, and light is a transverse wave that does not require a medium.

C.Sound is a transverse wave that requires a medium through which to travel, and light is a longitudinal wave that does not require a medium.

D.Sound is a transverse wave that does not require a medium through which to travel, and light is a longitudinal wave that does require a medium.

Answers

Answer: i think the answer is C

Explanation:

Please help me with this review question.

Answers

Answer:

28.7%

Explanation:

efficiency = work output /work input × 100

As the time period of an object’s momentum change becomes longer, the force
needed to cause this change becomes _______________________.

Answers

Answer:

Speesd

Explanation:

The ear drum vibrates when struck by sound waves and directly sends a message to the brain that is then recognized as sound
True or False

Answers

Answer:

true

Explanation:

Force of a Baseball Swing. A baseball has mass 0.153 kg . Part A If the velocity of a pitched ball has a magnitude of 44.5 m/s and the batted ball's velocity is 50.5 m/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat. Express your answer to three significant figures and include the appropriate units. P

Answers

Answer: 14.5 kg.m/s

Explanation:

Given

mass of baseball is [tex]m=0.153\ kg[/tex]

The initial speed of the ball is [tex]u=-44.5\ m/s[/tex]

the final speed of the ball is [tex]v=50.5\ m/s[/tex]

Impulse is given as a change in the momentum

[tex]\vec{J}=\Delta \vec{P}[/tex]

[tex]J=m(v-u)\\J=0.153(50.5-(44.5))\\J=0.153\times 95=14.535\ kg.m/s[/tex]

Change in momentum up to 3 significant figures is 14.5 kg.m/s

Impulse applied by a bat is also the same as the change in momentum

The elastic energy stored in your tendons can contribute up to 35 % of your energy needs when running. Sports scientists have studied the change in length of the knee extensor tendon in sprinters and nonathletes. They find (on average) that the sprinters' tendons stretch 41 mm , while nonathletes' stretch only 33 mm .

Answers

Hello. Your question is incomplete. However, I managed to find it completely on the internet and I realized that you forgot to mention that the question asks you for the maximum energy difference between velovistas and non-athletes, considering that the spring constant for the tendon of the two groups is equal to 33n/mm.

To make this calculation you will need to use Hooke's law, using the formula: ¹/2*K*x², where "K" will be the value of the spring constant for the tendon and "X" will be the value of the sprinter and non-athlete terms.

So for the sprinter we will have the calculation:

¹/2*33*41² -------> 0,5*33*1681 = 27736. 5 Nmm

(To facilitate the calculation, first solve the division of ¹/2 and then multiply 41 by 41, lastly, just multiply all the results.)

For the non-athlete we will have the calculation:

¹/2*33*33² -------> 0,5*33*1089 = 17968. 5 Nmm

(To facilitate the calculation, first solve the division of ¹/2 and then multiply 41 by 41, lastly, just multiply all the results.)

Now, to reach the final result, you only need to subtract the two values presented by the sprinter and the non-athlete.

27736.5 - 17968.5 = 9768 Nmm

Students are asked to design an experiment to confirm that the pressure and volume of an ideal gas are inversely proportional. They use a cylinder containing an ideal gas that has a plunger equipped with a pressure sensor. They perform several trials, and in each trial they start with the gas at the same initial pressure and volume. The students then quickly push the plunger so that the gas achieves a different final pressure and volume. After analyzing their results, they determine that the final pressures and volumes do not follow an inversely proportional relationship. Which of the following refinements to the procedure would show the inverse proportionality between pressure and volume?
A. Compress the gas slowly so that the temperature remains constant.
B. Perform more trials to obtain more data points.
C. Discard data points that do not show inverse proportionality between pressure and volume.
D. Compress the plunger even faster so that the compression is effectively instantaneous.

Answers

Answer:

the answers the correct one is A

Explanation:

Let's analyze the situation, the expression for ideal gases is

         PV = n R T

in this case n is the number of moles of the gas remains constant, so we see that there is a relationship between volume, pressure and temperature.

For the experiment we are conducting we must ensure that the temperature remains constant, one way to achieve this is by placing a small thermometer on the surface of the cylinder.

By rapidly compressing part of the work done, it is converted into internal energy of the gas molecules, and from there it is transformed into its temperature. One way to reduce this effect is to COMPRESS SLOWLY and thus keep the temperature constant.

This method of allowing to check

          P V = cte

when checking the answers the correct one is A

Explain how conduction, convection, and radiation occur involving a campfire

Answers

Answer:

https://wtamu.edu/~cbaird/sq/2015/02/26/when-i-sit-by-a-campfire-how-does-its-hot-air-heat-me/#:~:text=When%20you%20sit%20by%20a,It%20comes%20from%20thermal%20radiation.&text=Since%20air%20is%20a%20good,of%20pockets%20of%20heated%20fluid.

Here's a link to help you hope it helps have a good day

A 85-W lamp is connected to 100 V. What is the resistance of the lamp?

Answers

P=V2/R
R=V2/P =100x100/85 =117.64 Ohum

What causes the Coriolis effect?
A
The sun's position relative to Earth
B.
Earth's orbit around the sun
с
Moon phases
D
Earth's rotation

Answers

Correct answer is D. Earths rotation
The answer is D. Earths Rotation

Galvani wrongly believed that the frog’s leg twitched during his experiment due to _____.

Answers

Answer:

nerves

Explanation:

I think, I maybe wrong.

A box having a weight of 8 lb is moving around in a circle of radius rA = 2 ft with a speed of (vA)1 = 5 ft/s while connected to the end of a rope. If the rope is pulled inward with a constant speed of vr = 4 ft/s, determine the speed of the box at the instant rB = 1 ft. How much work is done after pulling in the rope from A to B? Neglect friction and the size of the box

Answers

Answer:

W = 1.875 J

Explanation:

For this exercise let's use the relationship between work and kinetic energy

          W = ΔK

The kinetic energy of rotational motion is

         K₀ = ½ I w²

we can assume that the box is small, so it can be treated as a point object, with moment of inertia

          I = m rₐ²

angular and linear velocity are related

          v = w r

          w = v / r

we substitute in the equation, for point A

         K₀ = ½ (m rₐ²) (v / rₐ)²

         K₀ = ½ m v²

For the final point B, as the system is isolated the angular momentum is conserved

initial        L₀ = Io wo

final          L_f = I_f w_f

                L₀ = L_f

                 I₀ w₀ = I_f w_f

               

                (m rₐ²) w₀ = (m  [tex]r_{b} ^2[/tex]) w_f

                 w_f = (rₐ/r_b)² w₀

with this value we find the final kinetic energy

         K_f = ½ I_f w_f²

         K_f = ½ (m [tex]r_{b}^2[/tex]) ( (rₐ / r_b)²  w₀) ²

         K_f = ½ m [tex]\frac{r_a^4}{r_b^2} \ w_o^2[/tex]

 

we substitute in the realcion of work

          W = K_f - K₀

          W = ½ m  [tex]( \( \frac {r_a^2 }{r_b} )^2[/tex] w₀² - ½ m v²

          W = ½ m  [tex]\frac{r_a^4}{r_b^2} ( \frac{v}{r_a} ) ^2[/tex] - ½ m v²

           W = ½ m [tex]\frac{r_a^2}{r_b^2} \ v^2[/tex] - ½ m v2

          W = ½ m v² (([tex]( \ (\frac{r_a}{r_b})^2 -1)[/tex]

let's calculate

           W = ½ ( [tex]\frac{8}{32}[/tex] ) 5 ((2/1)² -1)

           W = 0.625 (3)

           W = 1.875 J

         

Two protons (each with q = 1.60 x 10-19)
in a nucleus are located 1.00 x 10-15 m
apart. How much electric force do they
exert on each other?
[?] N.

Answers

Answer:

230.4 N

Explanation:

From the question given above, the following data were obtained:

Charge (q) of each protons = 1.6×10¯¹⁹ C

Distance apart (r) = 1×10¯¹⁵ m

Force (F) =?

NOTE: Electric constant (K) = 9×10⁹ Nm²/C²

The force exerted can be obtained as follow:

F = Kq₁q₂ / r²

F = 9×10⁹ × (1.6×10¯¹⁹)² / (1×10¯¹⁵)²

F = 9×10⁹ × 2.56×10¯³⁸ / 1×10¯³⁰

F = 2.304×10¯²⁸ / 1×10¯³⁰

F = 230.4 N

Therefore, the force exerted is 230.4 N

Answer:

230.4

Explanation:

acellus

A 72.9-kg base runner begins his slide into second base when moving at a speed of 4.02 m/s. The coefficient of friction between his clothes and Earth is 0.701. He slides so that his speed is zero just as he reaches the base. (a)How much mechanical energy is lost due to friction acting on the runner

Answers

Answer:

-589.05 J

Explanation:

Using work-kinetic energy theorem, the work done by friction = kinetic energy change of the base runner

So, W = ΔK

W = 1/2m(v₁² - v₀²) where m = mass of base runner = 72.9 kg, v₀ = initial speed of base runner = 4.02 m/s and v₁ = final speed of base runner = 0 m/s(since he stops as he reaches home base)

So, substituting the values of the variables into the equation, we have

W = 1/2m(v₁² - v₀²)

W = 1/2 × 72.9 kg((0 m/s)² - (4.02 m/s)²)

W = 1/2 × 72.9 kg(0 m²/s² - 16.1604 m²/s²)

W = 1/2 × 72.9 kg(-16.1604 m²/s²)

W = 1/2 × (-1178.09316 kgm²/s²)

W = -589.04658 kgm²/s²

W = -589.047 J

W ≅ -589.05 J

Heeelp me faaast plllsss​

Answers

Answer:

the first one

Explanation:

cartridge fuse

The photograph shows part of the Great Plains of North America. How do
plains form?
A. Magma rises at a divergent plate boundary.
B. Tectonic movements make folds and faults in the crust.
C. Continental plates slip past each other at a transform boundary.
D. Water, wind, or glaciers either remove or deposit crust.
SUBMIT
2 PREVIOUS

Answers

Answer:

Some plains form as ice and water erodes, or wears away, the dirt and rock on higher land. Water and ice carry the bits of dirt, rock, and other material, called sediment, down hillsides to be deposited elsewhere. As layer upon layer of this sediment is laid down, plains form. Volcanic activity can also form plains.

4) Which statement about teamwork is not true?
A) Team members should not have to make personal sacrifices for the success of the team.
B) To be successful, all team members need to agree about how to achieve the goal.
C) To achieve agreement, teams must be able to communicate and negotiate.
D) Team members need to be ready to resolve conflicts in an open and honest way

Answers

Answer: A) Team should not have to make personal sacrifices for the success of the team.

Explanation:

What is the medium of the wave shown in the photograph?
A. The water
B. Kinetic energy
C. The duck
D. Gravity

Answers

Answer:

A. The water

Explanation:

i got it right on A-P-E-X

true or false

The Total electric potential due to two or more charges is equal to the algebraic sum of the potentials due to the individual charges.

Answers

Answer:

i guess the answer is false

An object carries a +15.5 uC charge.
It is 0.525 m from a -7.25 uC charge.
What is the magnitude of the electric
force on the object?

Answers

Answer:

3.67 N

Explanation:

From the question given above, the following data were obtained:

Charge of 1st object (q₁) = +15.5 μC

Charge of 2nd object (q₂) = –7.25 μC

Distance apart (r) = 0.525 m

Force (F) =?

Next, we shall convert micro coulomb (μC) to coulomb (C). This can be obtained as follow:

For the 1st object

1 μC = 1×10¯⁶ C

Therefore,

15.5 μC = 15.5 × 1×10¯⁶

15.5 μC = 15.5×10¯⁶ C

For the 2nd object:

1 μC = 1×10¯⁶ C

Therefore,

–7.25 μC = –7.25 × 1×10¯⁶

–7.25 μC = –7.25×10¯⁶ C

Finally, we shall determine the force. This can be obtained as follow:

Charge of 1st object (q₁) = +15.5×10¯⁶ C

Charge of 2nd object (q₂) = –7.25×10¯⁶ C

Distance apart (r) = 0.525 m

Electrical constant (K) = 9×10⁹ Nm²/C²

Force (F) =?

F = Kq₁q₂ / r²

F = 9×10⁹ × 15.5×10¯⁶ × 7.25×10¯⁶ / 0.525²

F = 3.67 N

Therefore, the force on the object is 3.67 N

hhhep faaast plssssss​

Answers

Answer:

false

Explanation:

I am in need of points sorry

A cars engine can deliver 300,000 watts of power to its wheels.
A. If the engine acts for 6 seconds, what is the work done on the car?
B. If the car travels 0.25 miles, what force acted on the car?
C.If the cars mass is 1200 kg, what is the acceleration of the car?

Answers

Answer:

A. 1,800,000 J

B. 4473.87 N

C. 3.728 m/s²

Two identical loudspeakers are driven in phase by the same amplifier. The speakers are positioned a distance of 3.2 m apart. A person stands 5.0 m away from one speaker and 6.2 m away from the other. Calculate the second lowest frequency that results in destructive interference at the point where the person is standing. Assume the speed of sound to be 330 m/ s. A) 183 Hz B) 275 Hz C) 413 Hz D) 137 Hz E) 550 Hz

Answers

Answer:

C) 413 Hz

Explanation:

For destructive interference, the path difference ΔL = (n + 1/2)λ where ΔL = L₂ - L₁ where L₁ = person's distance from one speaker (the closer one) = 5.0m and L₂ = person's distance from other speaker (the farther one) = 6.2 m and λ = wavelength = v/f where v = speed of sound = 330 m/s and f = frequency

So, ΔL = (n + 1/2)λ

L₂ - L₁  = (n + 1/2)v/f

f = (n + 1/2)v/(L₂ - L₁)

At the second lowest frequency that results in destructive interference at the point where the person is standing, n = 1.

So,

f = (1 + 1/2)v/(L₂ - L₁)

f = 3v/2(L₂ - L₁)

Substituting the values of the variables into the equation, we have

f = 3v/2(L₂ - L₁)

f = 3(330 m/s)/2(6.2 m - 5.0 m)

f = 3(330 m/s)/2(1.2 m)

f = 990 m/s ÷ 2.4 m)

f = 412.5 Hz

f ≅ 413 Hz

The following statements address the science behind the pulley system illustrated:
A. The pulleys increase the entropy of the system.
B. The force applied to the rope is less than the force needed to lift the object.
C. The pulleys help generate as much energy as possible.
D. The pulleys multiply energy input, resulting in more energy output.
E. The pulleys generate no thermal energy.
Which of these statements is/are true?
i. Statements A and B
ii. Statements D and E
iii. Only statement C
iv. All of the statements

Answers

Answer:

i. Statements A and B

Explanation:

Sana nakatulong

A 5kg cart moving to the right with a velocity of 16 m/s collides with a concrete wall and
rebounds with a velocity of 22 m/s. Is the change in momentum of the cart​

Answers

Explanation:

mass, m = 5kg

initial velocity, u = 16m/s

final velocuty, v = -22m/s

change in momentum, ∆p = ?

∆p = m (v-u)

5(-22-16)

5(38)

∆p = 190kgm/s

check the calculations!

A bullet of mass 4.00 g is fired horizontally into a wooden block of mass 1.30 kg resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.170. The bullet remains embedded in the block, which is observed to slide a distance 0.240 m along the surface before stopping. Part A What was the initial speed of the bullet

Answers

Answer:

[tex]291.67\ \text{m/s}[/tex]

Explanation:

[tex]m_1[/tex] = Mass of bullet = 4 g

[tex]m_2[/tex] = Mass of block = 1.3 kg

[tex]\mu[/tex] = Coefficient of friction = 0.17

[tex]s[/tex] = Displacement of block = 0.24 m

[tex]v_1[/tex] = Velocity of bullet

[tex]v[/tex] = Velocity of combined mass

[tex]g[/tex] = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

The energy balance of the system is given by

[tex]\dfrac{1}{2}(m_1+m_2)v^2=\mu(m_1+m_2)gs\\\Rightarrow v=\sqrt{2\mu gs}[/tex]

As the momentum is conserved in the system we have

[tex]m_1v_1=(m_1+m_2)v\\\Rightarrow m_1v_1=(m_1+m_2)\sqrt{2\mu gs}\\\Rightarrow v_1=\dfrac{(m_1+m_2)\sqrt{2\mu gs}}{m_1}\\\Rightarrow v_1=\dfrac{(4\times 10^{-3}+1.3)\times \sqrt{2\times 0.17\times 9.81\times 0.24}}{4\times 10^{-3}}\\\Rightarrow v_1=291.67\ \text{m/s}[/tex]

The initial speed of the bullet is [tex]291.67\ \text{m/s}[/tex].

Two identical copper blocks are connected by a weightless, unstretchable cord through a frictionless pulley at the top of a thin wedge. One edge of the wedge is vertical, and the tip makes an angle of 33. The block that hangs vertically weighs 2.85 kg, and the block on the incline weighs 2.94 kg. If the two blocks do not move, what is magnitude of the force of friction on the second second block

Answers

Answer:

13.6 N

Explanation:

Since one side of the wedge is vertical and the wedge makes and angle of 33 with the horizontal, the angle between the weight of the copper block on the incline and the incline is thus 90 - 33 = 57.

Let M be the mass of the block that hangs, m be the mass of the block on the incline and T be the tension in the weightless unstretchable cord.

We assume the motion is downwards in the direction of the hanging block, M.

We now write equations of motion for each block.

So

Mg - T = Ma    (1) and T - mgcos57 - F = ma where F is the frictional force on the block on the incline and a is their acceleration.

Now, since both blocks do not move, a = 0.

So, Mg - T = M(0) = 0     and T - mgcos57 - F = m(0) = 0

Mg - T = 0    (3) and T - mgcos57 - F = 0 (4)

From (3), T = Mg

Substituting T into (4), we have

T - mgcos57 - F = 0

Mg - mgcos57 - F = 0

So, Mg - mgcos57 = F  

F = Mg - mgcos57

F = (M - mcos57)g

Since g = acceleration due to gravity = 9.8 m/s², and M = 2.94 kg and m = 2.85 kg.

We find F, thus

F = (2.94 kg - 2.85 kgcos57)9.8 m/s²

F = (2.94 kg - 2.85 kg × 0.5446)9.8 m/s²

F = (2.94 kg - 1.552 kg)9.8 m/s²

F = (1.388 kg)9.8 m/s²

F = 13.6024 kgm/s²

F ≅ 13.6 N

Two ice skaters, with masses of 50 kg and 75 kg , are at the center of a 30 m -diameter circular rink. The skaters push off against each other and glide to opposite edges of the rink. Part A If the heavier skater reaches the edge in 30 s , how long does the lighter skater take to reach the edge

Answers

Answer:

t = 20 s

Explanation:

Assuming no other forces acting on the skaters when they push off against each other, and that we can neglect friction, total momentum must be conserved.The initial momentum is just zero, because both skaters are at rest.So, when both are gliding to opposite edges of the rink, at any moment, we can write the following expression:

       [tex]p_{f} = m_{1} * v_{1} = m_{2} * v_{2} (1)[/tex]

where m₁ = 50 kg, m₂ = 75 kg.We know that the heavier skater reaches the edge in 30 s.Since the distance from the center to any point on the edge is just half the diameter, we can find the speed of the heavier skater as follows:

       [tex]v_{2} = \frac{15m}{30s} = 0.5 m/s (2)[/tex]

Replacing m₁, m₂ and v₂ in (1), we can solve for the only unknown (v₁) as follows:

       [tex]v_{1} = \frac{m_{2}*v_{2}}{m_{1} } = \frac{75 kg*0.5m/s}{50kg} = 0.75 m/s (3)[/tex]

Since the distance to the opposite edge from the center is the same than for the heavier skater, we can find the time needed for the lighter one to reach the edge as follows:[tex]t_{1} = \frac{15m}{0.75m/s} = 20 s (4)[/tex]

Melvina has a mass of 70 kg and is about to jump from the window ledge of a burning building.
The ledge is 80 m above the ground. What is Melvina's potential energy?

Answers

Melvina's potential energy is 54,880 Joules.

To calculate Melvina's potential energy, we need to use the formula for gravitational potential energy:

Potential energy = mass × gravitational acceleration × height

Potential energy is a measure of the energy an object possesses due to its position relative to other objects. In this case, Melvina's potential energy is a result of her height above the ground. As she stands on the ledge of the burning building, her potential energy is stored and can be converted into other forms of energy if she were to jump or fall. The potential energy will decrease as she descends, and it will be converted into kinetic energy (energy of motion).

Given that Melvina has a mass of 70 kg and the ledge is 80 m above the ground, we can substitute the values into the formula:

Potential energy = 70 kg × 9.8 m/s² × 80 m

Calculating this, we find:

Potential energy = 54,880 Joules

For such more questions on energy

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NO LINKS PLEASEWhy was Suburbia important in the 1950s? What will the function f(x) = x look like translated 3units right and 8 units down? Which of the following is FALSE?(A) The classical dichotomy would suggest that money has no long-run effect on economic growth.(B) Neoliberalism is the best economic system.(C) Price controls can often work to improve productivity and growth.(D) Corporate taxes always reduce inflation Why would you go to Los Angeles and what would you do down there ? question 62 80) a reduction in the amount of nadp available in plant cells in the light will ultimately result in a) an increase in the rate of the calvin cycle. b) a decrease in the rate of linear electron flow. c) a decrease in the rate of cyclic electron flow. d) an increase in the rate of oxygen production. You spin the spinner and flip a coin. Find the probability of the compound event. The probability of spinning a number less than 3 and flipping tails is Question 1You buy egg yolks for $13/gallon.A batch of Hollandaise requires 4 oz ofHow much do you spend on egg yolks for one batch of Hollandaise?Hint: Remember, first convert gallons to ounces, then divide.egg yolks.Answer:Answer Carissas gerbil has a tail that is the same length as its body length. Its tail is 102 millimeters. How long is her gerbil in centimeters? Poosjsjdiwjqjsnsjjdd Whats the answers to this question? What is the maximum flow rate of water in a smooth pipe 8.0 cm diameter if the flow is to be laminar The mean number of years of marriage preceding divorce is 7. The median mber of years is 6. Most divorces occur, however, either at 3 years of marriage 22 years. Which measure of central tendency best describes these data, and y? verify x+(y+z) =(x+y) +z, when x=-4/15, y=-4/5and z =17/8 Select the correct answer.Which of the following is an important part of a play's setting?OA audienceOB lightingOC charactersODnone of the above X+ y + 4z = 2X+ y + 8z = 6X + 5y + 3z = -3 please help me i really really really need help please please help me please In pure competition, marginal revenue is: ___________ The second part of this homework is a program that should be written per the description below and turned in to the Canvas assignment for Homework #3. Turn in just a single C source code file for the assignment. The program will be tested with goc under Cygwin. Write a program that takes two command line arguments at the time the program is executed. You may assume the user enters only signed decimal numeric characters. The input must be fully qualified, and the user should be notified of any value out of range for a 22-bit signed integer. The first argument is to be considered a data field. This data field is to be is operated upon by a mask defined by the second argument. The program should display a menu that allows the user to select different bit-wise operations to be performed on the data by the mask. The required operations are: Set, Clear and Toggle. Both data and mask should be displayed in binary format. And they must be displayed such that one is above the other so that they may be visually compared bit by bit. If data and mask are both within the range for signed 8 bit values, then the binary display should only show 8 bits. If both values are within the range for signed 16 bit values, then the binary display should only show 16 bits. The menu must also allow the user to re-enter a value for data and re-enter a value for the mask. Use scanf() to read data from the user at runtime and overwrite the original values provided at execution time. All user input must be completely qualified to meet the requirements above (up to 22-bit signed integer values). Printing binary must be done with shifting and bitwise operations. Do NOT use arrays. No multiplication or division is needed to produce binary output to the screen. Solve the following equation without using a calculator.log3(81)=y The Earth revolves around the Sun, and the Moon revolves around the Earth.