A hiker is lost in the forest, but has his cell phone with a weak signal. Cell phones with GPS can give an approximate location through triangulation, which works by giving distances from two known points. Suppose the hiker is within distance of two cell phone towers that are 22.5 miles apart along a straight highway (running east to west, double-dashed line). Based on the signal delay, it can be determined that the signal from the hiker's phone is 14.2 miles from Tower A and 10.9 miles from Tower B. Assume the hiker is traveling a straight path south reach the highway quickly. How far must the hiker travel to reach the highway

Answers

Answer 1

Answer:

The distance the hiker must travel is approximately 5.5 miles

Step-by-step explanation:

The distance between the two cell phone towers = 22.5 miles

The distance between the hiker's phone and Tower A = 14.2 miles

The distance between the hiker's phone and Tower B = 10.9 miles

The direction of the highway along which the towers are located = East to west

The direction in which the hiker is travelling to reach the highway quickly = South

By cosine rule, we have;

a² = b² + c² - 2·b·c·cos(A)

Let 'a', 'b', and 'c', represent the sides of the triangle formed by the imaginary line between the two towers, the hiker's phone and Tower A, and the hiker's hone and tower B respectively, we have;

a = 22.5 miles

b = 14.2 miles

c = 10.9 miles

Therefore, we have;

22.5² = 14.2² + 10.9² - 2 × 14.2 × 10.9 × cos(A)

cos(A) = (22.5² - (14.2² + 10.9²))/( - 2 × 14.2 × 10.9) ≈ -0.6

∠A = arccos(-0.6) ≈ 126.9°

By sine rule, we have;

a/(sin(A)) = b/(sin(B)) = c/(sin(C))

∴ sin(B) = b × sin(A)/a

∴ sin(B) = 14.2×(sin(126.9°))/22.5

∠B = arcsine(14.2×(sin(126.9°))/22.5) ≈ 30.31°

∠C = 180° - (126.9° - 30.31°) = 22.79° See No Evil

The distance the hiker must travel, d = c × sin(B)

∴ d = 10.9 × sin(30.31°) ≈ 5.5

Therefore, the distance the hiker must travel, d ≈ 5.5 miles.


Related Questions

A triangular prism has a base that is an isosceles triangle with sides ​14 cm, 14cm ​, base 9 cm ​, and height 13 cm. The height of the prism is 32 cm. What is the surface area of this​ prism?

Answers

Answer:

Surface area of prism = 1301 cm²

Step-by-step explanation:

A triangular pyramid has 3 rectangular sides and 2 triangular sides.

Now, we are told that the triangular side is isosceles.

This means that two of the rectangular sides which share a side with the equal side of the triangle are equal as well as the 2 triangular sides.

Surface area of prism = 2(area of triangular face) + 2(area of rectangle sharing one side with the equal side of the triangle) + (area of rectangle sharing side with the unequal side of the triangle).

Area of triangle = ½ × base × height

Area of triangle = ½ × 9 × 13 = 58.5 cm²

Since height of prism is 32 cm, then;

area of rectangle sharing one side with the equal side of the triangle = 32 × 14 = 448 cm²

area of rectangle sharing side with the unequal side of the triangle = 32 × 9 = 288 cm²

Thus;

Surface area of prism = 2(58.5) + 2(448) + 288

Surface area of prism = 1301 cm²

When a<0 is the parabols wider or narrower?

Answers

Answer:

When A is less than 0 the parabola flips downward. When A becomes larger than 1, the parabola becomes more narrow. When A becomes smaller, until 0, the parabola widens.

Step-by-step explanation:







EXERCISE 3: Find the limit or prove it fails to exist: a/ ž tz lim 2+4+3i Re(z - i) b/ lim zi zi = EXERCISE 4: Let f(x) = x3 + iy (i) Where has f the derivative? (ii) Where is f analytic?

Answers

a/ To find the limit of the expression 2 + 4 + 3i Re(z - i), we need to replace z with the limit point. Therefore, the expression will be:2 + 4 + 3i Re(z - i) = 6 + 3i Re(z - i)

We have to find the limit as z approaches i. Consider the following:

Since Re(z - i) is a real number, the limit can be found by setting Re(z - i) = 0.

Therefore, lim 2+4+3i Re(z - i) = lim 6 + 3i Re(z - i) = 6.Explanation:

b/ Given the limit lim zi / zi, we can simplify the expression by canceling zi in the numerator and the denominator. Therefore, lim zi / zi = lim 1 = 1.

Explanation:

4. Let f(x) = x3 + iy(a) The derivative of f(x) is the function f′(x). To find the derivative of f(x), we need to differentiate the real and imaginary components of f(x) separately.

Therefore, f′(x) = 3x² + iy, since the derivative of i is zero.

Explanation: (b) We must test the Cauchy-Riemann equations to see if f(x) is analytic. f(x) is said to be analytic if it meets the Cauchy-Riemann conditions. Therefore, we need to verify that the following equations are satisfied: ∂u / ∂x = ∂v / ∂y and ∂u / ∂y = -∂v / ∂x. Using the function given above, we can easily obtain its real and imaginary components. u(x, y) = x³ and v(x, y) = y. Therefore, ∂u / ∂x = 3x² and ∂v / ∂y = 1, but 3x² ≠ 1

Therefore, the Cauchy-Riemann equations are not satisfied, so f(x) is not analytic.

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how many meters are their in centimeter​

Answers

Answer:

You mean how many centimerters are in a meter?

In that case 100.

Step-by-step explanation:

11. Dave is building a doghouse that is a scale model of his shed in the farm yard, One of
the windows on the shed is 117 cm wide and 130 cm high. On the doghouse the window
is 9 cm wide,
a) What is the scale factor Dave is using to build the doghouse?
a.
2 mar
b) How high is the window in the scale model?

Answers

Answer:

a) 1/13 (or 13 depending on the factor is being applied to the dog house or applied to the shed. If its being applied to the shed like 117 * scale factor it is 1/13)

b) 10

Step-by-step explanation:

The scale factor is 13 and the height of the dog house is 10 cm.

What is scale factor?

A scale factor is defined as the ratio between the scale of a given original object and a new object.

Given that, Dave is building a doghouse that is a scale model of his shed in the farmyard, One of the windows on the shed is 117 cm wide and 130 cm high. On the doghouse the window is 9 cm wide,

a) Since, the scale factor = ratio of original scale to scale of the model.

Therefore,

Scale factor = 117 / 9 = 13

b) Since, the scale factor is 13 and the original scale of the window high is 130 cm.

Therefore, height of the doghouse = 130 / 13 = 10 cm

Hence, the scale factor is 13 and height of the dog house is 10 cm.

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PLEASE HELP ME SOMEONE. How do I do this? Please explain and I will give you crown.

Answers

Answer: the one in the bottom right

Step-by-step explanation: each month which is the x axis ( the bottom line) the y axis (line on the left) goes up by 5

so when the x axis is 1 the y axis should be at 5

Question
Find the volume of the cylinder. Find the volume
of a cylinder with the same radius and double the
height
7 in
3 in

Answers

Answer:

I couldn't really see the height number (that had to doubled) ir really the radius but I saw 7 for the radius and 3 (×2) for the height so I did the math and the answer is 923.63

Step-by-step explanation:

i could be wrong tho, hope this helped

Answer:

923.63

Step-by-step explanation: hope this helps!!

An electrician bent a section of copper wire into a partial circle as shown. The dimensions are


given in feet (ft).


2.5 f


880


2.5


ft


What is the length of the section of wire to the nearest hundredth of a foot?

Answers

Answer:

3.84 feets

Step-by-step explanation:

Given that:

θ = 88°

Radius, r = 2.5

The length of section of the wire, L ; Length of an arc

L = θ / 360° * 2πr

L = 88/360 * 2*π*2.5

L = (88/360) * 15.707963

L = 3.8397

Length of section of wire = 3.84 feets

If the estimate being tested is less than the benchmark, you should conduct a ______ one-sample hypothesis test.
a. two tail
b. right tail
c. left tail
d. no tail
e. All of the choices above
f. None of the choices

Answers

If the estimate being tested is less than the benchmark, you should conduct a left tail one-sample hypothesis test. So, correct option is C.

In hypothesis testing, the null hypothesis typically assumes that there is no significant difference or effect, and the alternative hypothesis proposes that there is a significant difference or effect.

In this case, since the estimate is less than the benchmark, the alternative hypothesis would state that there is a significant difference, and we are specifically interested in detecting a decrease or a lower value.

Therefore, we conduct a left tail test to evaluate the evidence against the null hypothesis and determine if the estimate is significantly lower than the benchmark.

A left tail test focuses on the leftmost portion of the distribution and calculates the probability of observing a value as extreme or more extreme than the estimate, assuming the null hypothesis is true.

By comparing the test statistic with the critical value or p-value associated with the chosen significance level, we can make conclusions about the statistical significance of the estimate being less than the benchmark.

So, correct option is C.

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From Monday through​ Friday, works in the on and in the on another . On Saturday and​ Sunday, ​50% of the days. How many days does work in a​ week? What percent of Monday through Friday does ​work?

Answers

Complete question :

From Monday through Friday, James works in the library on 2 days and in the cafeteria on another day. On Saturday and Sunday, James washes cars 50% of the days. How many days does James work in a week? What percent of the days from Monday through Friday does he work?

Answer:

4 days ;

60%

Step-by-step explanation:

From Monday to Friday

Number of days in library = 2

Number of days in cafeteria = 1

50% of days in weekends

Number of weekend days = 2

50% of 2 = 0.5 * 2 = 1 day

Total. Number of days worked = (2 +1 + 1) = 4 days

What percent of the days from Monday through Friday does he work?

Number of days workwd from. Monday to Friday = 3

Total number of days from Monday to Friday = 5

Percentage of days worked from Monday to Friday

= number of days worked / total number of days

= 3 /5 * 100%

= 0.6 * 100%

= 60%

One of the objectives for this lesson is to find the length of a curve using the z score.

Answers

Answer:

The answer is "True".

Step-by-step explanation:

The z-score value shows how often standard deviations were away from the earth. If it is 0, it is on average. The positive Z sign indicates that perhaps the raw mark is greater than the average. While z-score is equivalent to +1, for example, it is a standard deviation of 1 above average. This can be used for implementing series and also for comparing the trend of mortality among various individuals or between various periods and by using the z score we find the curve length, that's why it is correct.

4/5 x 7 need help asap​

Answers

Answer:

4/5=0.8×7=5.6

5.6 is the answer

Hey there!

4/5 × 7

= 4×7/5

= 28/5

= 5.6

Hope it helps ya!

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Answers

5cm

Step-by-step explanation:

volume of cube= l³

125 =l³

3root over 125 =l

l = 5

Answer:

So the length of the edge of a cube with a volume of 125 is 5.

Step-by-step explanation:

compute the divergence ∇ · f and the curl ∇ ✕ f of the vector field. (your instructors prefer angle bracket notation < > for vectors.) f = 2x2, −3y2, z2

Answers

For the vector field f = 2x², −3y², z², Divergence (∇·f) = 4x - 6y² + 2z, Curl (∇×f) = (0, 0, 0).

To compute the divergence (∇·f) and the curl (∇×f) of the vector field f = (2x², -3y², z²), we can use the vector calculus operators. Divergence (∇·f),

In this case, the divergence of f is the partial derivative of each part of the field, for f = (2x², -3y², z²), we have,

∂f₁/∂x = 4x

∂f₂/∂y = ∂(-3y²)/∂y = -6y²

∂f₃/∂z  = 2z

Therefore, the divergence of f is,

∇·f = 4x - 6y² + 2z

Curl (∇×f),

The curl of a vector field f = (f₁, f₂, f₃) is given by the cross product of the curl operator (∇×) and the vector field. In this case, the curl of f is,

∇×f  = (i∂/∂x + j∂/∂y + k∂/∂y) x (i2x², -j3y², kz²)

Basically we can write  (i2x², -j3y², kz²) as (f₁, f₂, f₃)

we have,

∂f₁/∂z = 0

∂f₂/∂x = ∂(-3y²)/∂x = 0

∂f₃/∂y = ∂(z²)/∂y = 0

Therefore, the curl of f is,

∇×f = (0, 0, 0)

In this case, the curl of f is the zero vector, indicating that the vector field f is irrotational.

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Complete question - compute the divergence ∇·f and the curl∇✕f of the vector field. f = 2x², −3y², z².

plz help 5x + 2 = x – 10

Answers

Answer:

x= -3

Step-by-step explanation:

5x + 2 = x - 10

4x + 2 = -10

4× = 10 - 2

4x = -12

x= -3

Which equation below would be parallel to the line y - 2x = 8?*
O y = 2x + 5
O y = -2x + 8
O y = 10x - 3
O y = 6x + 2

Answers

Option 2- y=-2x+8 is the answer

PLEASE HELP!!1!!1!!11!!1!! I WILL MARK BRAINLIEST!!!!!!!!!111!111!!1!!11!

Answers

Answer:

s

Step-by-step explanation:

Answer:

fourth option) 5/8 lb

Right answer will be marked brainlist .

Answers

Answer:

$1159.69

Step-by-step explanation:

A = P (1 + r/n)^nt

A = 1000 (1 + 0.05/2)^2(3)

A = $1159.69

Let {X;};_₁ be independent standard normal random variables. Let =1 Y = (X₁ + X3 + X5 + X7)² + (X2 + X4+ X6 + X8)². Determine a value c such that the random variable cY will have a x² distribution.

Answers

To determine the value of c such that the random variable cY follows a chi-squared (x²) distribution, we need to compare the moments of cY with the moments of a standard x² distribution.

The random variable Y is defined as Y = (X₁ + X₃ + X₅ + X₇)² + (X₂ + X₄ + X₆ + X₈)², where X₁, X₃, X₅, X₇, X₂, X₄, X₆, and X₈ are independent standard normal random variables.

The x² distribution is characterized by its degrees of freedom, which determine the shape and variability of the distribution. For a standard x² distribution, the degrees of freedom are equal to the number of squared independent standard normal variables that are summed together.

In this case, Y is a sum of squared independent standard normal variables. By expanding Y, we can see that it consists of two terms, each squared separately. Each term represents the sum of four independent standard normal variables. Therefore, each term follows a x² distribution with 4 degrees of freedom.

To make cY follow a x² distribution, we need to equate the degrees of freedom of cY with 4. By comparing the moments of cY with the moments of a standard x² distribution with 4 degrees of freedom, we can solve for the value of c. The moments of cY will depend on the value of c, and by setting them equal to the corresponding moments of a x² distribution, we can find the specific value of c.

In summary, to determine the value of c such that the random variable cY follows a x² distribution, we need to compare the moments of cY with the moments of a standard x² distribution. By equating the degrees of freedom and comparing the corresponding moments, we can find the value of c.

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There are 6 friends baking bread. They equally share 3 sticks of butter. Write an equation to find the fraction of a stick of butter that each friend uses. 3 sticks of butter Choose the correct answer below. A. 3÷6= 6 3 B. 3÷6= 3 6 C. 6÷3= 3 6 D. 6÷3= 6 3

Answers

Answer:

B.

Step-by-step explanation:

the three sticks of butter were divided among six people

help needed on no 8 pls

Answers

Answer:

I’m sorry, but it’s a black screen.

Step-by-step explanation:

Solve for x.
0 < 3x – 6 < 18
O 0sxs8
2 O x<0 or x = 8
Oxs 2 or x 28

Answers

Answer:

2 ≤ x ≤ 8

Step-by-step explanation:

0 ≤ 3x - 6 ≤ 18

0 ≤ 3x - 6

6 ≤ 3x

2 ≤ x

3x - 6 ≤ 18

3x ≤ 18 + 6

3x ≤ 24

x ≤ 8

Combined:

2 ≤ x ≤ 8

Answer:

2 ≤ x≤ 8

2nd option:)

Step-by-step explanation:

Edward wrote a pattern starting at 0 and following the rule "add 2." . Juan wrote a pattern starting at 0 and following the rule "add 6." Which pair of patterns below represents that of Edward and Juan?

E: 1, 3, 5, 7, 9, ... J: 1, 7, 13, 19, 25, ...
E: 2, 4, 6, 8, 10, ... J: 6, 12, 18, 24, 30, ...
E: 0, 2, 4, 6, 8, ... J: 0, 6, 12, 18, 24, ...
E: 0, 2, 4, 8, 16, ... J: 0, 3, 9, 27, 81, ...

Answers

Answer:

the third option

Step-by-step explanation:

Answer:

3rd option

Step-by-step explanation:

they both started at 0 and added 2 and 6 respectively

Find the measure of each number: ​

Answers

Step-by-step explanation:

11. angles 1 and 2 are vertical angles, meaning they are congruent.

angle 2=angle 1=38 degrees

14. angles 1 and 2 are supplementary angles, meaning they add to 180 degrees.

angle 1=180-angle 2=180-67=113 degrees

identify the graph that represents the given system of inequalities. also, identify two ordered pairs that are solutions to the system. y ≤ x 5 y ≤ 2x 3

Answers

Ordered pair (0, 6) and  (2, 7)  satisfy both inequalities in the system and are solutions to the system.

To identify the graph that represents the given system of inequalities y > x + 5 and y ≥ 2x + 3, we need to graph the individual inequalities and find the region where they overlap.

When we plot the graph of inequality separately:

y > x + 5:Draw a dashed line y = x + 5 (not including the line).Shade the region above the line.

    2. y ≥ 2x + 3:

Draw a solid line y = 2x + 3 (including the line).Shade the region above the line.

The overlapping shaded region represents the solution to the system of inequalities.

To find two ordered pairs that are solutions to the system, we can choose any points within the overlapping region. Let's select two points:

Ordered pair 1: (0, 6)

Ordered pair 2: (2, 7)

These two points satisfy both inequalities in the system and are solutions to the system.

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The correct question is given below -

Identify the graph that represents the given system of inequalities. Also identify two ordered pairs that are solutions to the system.

y > x + 5

y ≥ 2x + 3

I need help with this math translation :')

Answers

The type of transformation in this problem is given as follows:

Vertical translation.

What are the translation rules?

The four translation rules are defined as follows:

Left a units: x -> x - a. -> horizontal translation.Right a units: x -> x + a. -> horizontal translation.Up a units: y -> y + a. -> vertical translation.Down a units: y -> y - a. -> vertical translation.

For this problem, we have a translation of 2 units up, which is called a vertical translation.

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xf(3)+3f(x)=x+6 f(6)=?​

Answers

answer: 36f/6f-1
solution: move all terms to left side and set equal to zero. then set each factor equal to zero.

Test at 20% significance level whether one of the drugs is more effective than the other.
(a) The absolute value of the critical value of this test is
(b) The absolute value of the calculated test statistic
(c) The p-value of this test is

Answers

Given,Test at 20% significance level whether one of the drugs is more effective than the other.

We need to calculate the absolute value of the critical value of this test, the absolute value of the calculated test statistic, and the p-value of this test.Solution:(a) The absolute value of the critical value of this test isThe level of significance is 20%.The degree of freedom is (r-1)(c-1) = (3-1)(2-1) = 2

From the chi-square table, the critical value for a chi-square distribution with 2 degrees of freedom and a level of significance of 0.20 is 3.219(i.e. critical value = 3.219)The absolute value of the critical value of this test is 3.219.(b) The absolute value of the calculated test statistic

The table is shown below:  We have, Total = 69 Test at 20% significance level whether one of the drugs is more effective than the other.To check the difference in effectiveness, we will use a chi-square goodness of fit test.

The null hypothesis H0: The two drugs are equally effective.

The alternative hypothesis Ha: One of the drugs is more effective.

The expected values of the two drugs are:  Expected Value of Drug A = (32+18) / 3 = 16 Expected Value of Drug B = (32+1) / 3 = 11 The calculations are summarized in the table below:  The formula to calculate the chi-square value is, chi-square = ∑ (O - E)2 / E The calculated value of chi-square is 6.07.The absolute value of the calculated test statistic is 6.07.(c) The p-value of this test isThe degree of freedom is (r-1)(c-1) = (3-1)(2-1) = 2

The level of significance is 20%.From the chi-square table, the p-value for a chi-square distribution with 2 degrees of freedom and a chi-square value of 6.07 is 0.047 (i.e. p-value = 0.047)The p-value of this test is 0.047.

Answer:(a) The absolute value of the critical value of this test is 3.219.(b) The absolute value of the calculated test statistic is 6.07.(c) The p-value of this test is 0.047.

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We fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that one drug is more effective than the other at the 20% level of significance.

Below is the table of values for the drugs drug A and drug B

Group A 7 10 13 15 8 7 6 10 9 11 10 11

Group B 6 12 9 11 8 8 9 12 10 14

(a) The absolute value of the critical value of this test

The absolute value of the critical value of this test is given by the formula:

[tex]`z = |zα/2|`[/tex]

where α = 0.2;

degree of freedom = `n1+n2-2` = `12+10-2` = `20`

From the standard normal table, the value of zα/2 at 0.2 is 1.645

Therefore, the absolute value of the critical value of this test is; `|1.645| = 1.645`.

(b) The absolute value of the calculated test statistic

The formula for the test statistic is given by;

[tex]`t=bar x1 -bar x2)/((s^2/n1)+(s^2/n2))`[/tex]

where `bar x1` and `bar x2` are the sample means of the two groups,

`s^2` is the pooled variance, n1 and n2 are the sample sizes of the two groups

and [tex]`s^2 = ((n1 -1) s1^2 + (n2 -1) s2^2 )/(n1 + n2 - 2)`[/tex]

Using the data given, we get:

Group A 7 10 13 15 8 7 6 10 9 11 10 11

`n1` = 12

[tex]`bar x1` = `(7+10+13+15+8+7+6+10+9+11+10+11)/12 = 9.583`[/tex]

and `s1` = 2.818

Group B 6 12 9 11 8 8 9 12 10 14

`n2` = 10

[tex]`bar x2` = `(6+12+9+11+8+8+9+12+10+14)/10 = 9.9`[/tex]

and `s2` = 2.205

[tex]`s^2` = `((12-1)2.818^2 + (10-1)2.205^2)/(12+10-2)` = `((11)(7.95)+(9)(4.86))/20` = `6.2155`[/tex]

Therefore, [tex]`t= |9.583 - 9.9| / (6.2155[(1/12)+(1/10)])`= 0.3164[/tex]

The absolute value of the calculated test statistic is 0.3164

(c) The p-value of this test is

The p-value of this test is 0.76 (rounded to two decimal places)

This indicates that the p-value is higher than the significance level, 0.2.

Therefore, we fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that one drug is more effective than the other at the 20% level of significance.

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LAN tosses a bone up In the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds after she jumps for the bone can be represented by the function h(t) = -16t^2 + 20t. What is Spots average rate of ascent, in feet per second, from the time she jumps into the air to the Time she catches the bone at t = 1/2 second?

Answers

Answer:

The rate of change is 12ft/s

Step-by-step explanation:

Given

[tex]h(t) = -16t^2 + 20t[/tex]

Required

Rate of change from when she jumps till 1/2s

The time she jumps is represented as: t = 0

So, calculate h(0)

[tex]h(t) = -16t^2 + 20t[/tex]

[tex]h(0) = -16 * 0^2 + 20 * 0 = 0[/tex]

At t = 1/2

[tex]h(t) = -16t^2 + 20t[/tex]

[tex]h(1/2) = -16 * 1/2^2 + 20 * 1/2 = 6[/tex]

Rate of change is calculated as:

[tex]Rate = \frac{f(b) - f(a)}{b - a}[/tex]

In this case:

[tex]Rate = \frac{h(b) - h(a)}{b - a}[/tex]

Where

[tex](a,b) = (0,1/2)[/tex]

So, we have:

[tex]Rate = \frac{h(b) - h(a)}{b - a}[/tex]

[tex]Rate = \frac{h(1/2) - h(0)}{1/2 - 0}[/tex]

[tex]Rate = \frac{6 - 0}{1/2 - 0}[/tex]

[tex]Rate = \frac{6}{1/2}[/tex]

[tex]Rate =12[/tex]

The rate of change is 12ft/s

A study was performed to test whether cars get better mileage on premium regular gas. Each of 10 cars was first filled with either regular or premium ss, coin toss, and the mileage for that tank was recorded. same cars using the other kind of gasoline. W significantly better mileage with premium gas. The mileage was recorded again for the e want to determine whether cars get reg- c(26, 29, 21, 22, 20, 22, 24, 2s, 25, 29) premC(19, 22, 24, 24, 2s, 25, 26, 26. 28, 32) a. What test should be used? b. What are the hypotheses? c. Based on the R outputs, what is your conclusion about hypotheses testing? data: prem and reg t-0.59702, df 9, p-value 0.2826 alternative hypothesis: true difference in means is greater thano 95 percent confidence interval: -1.656341 Inf sample estimates: mean of the differences 0.8

Answers

we do not have enough evidence to conclude that cars get better mileage on premium gasoline. Thus, we can conclude that there is no significant difference between the mileages of cars using premium and regular gasoline.

a. What test should be used?

The test that should be used is the Two-sample t-test because we are working with two independent groups.

b. What are the hypotheses?

The null hypothesis is that there is no difference between the mileage of cars using premium and regular gasoline, while the alternative hypothesis is that there is a difference between the two mileages.

Mathematically, this can be stated as follows: Null hypothesis: µ1 = µ2Alternative hypothesis: µ1 > µ2Where µ1 is the population mean for premium gasoline and µ2 is the population mean for regular gasoline.

c. Based on the R outputs, what is your conclusion about hypotheses testing?

From the R outputs, we can see that the p-value is 0.2826. Since this value is greater than the level of significance (α) of 0.05, we fail to reject the null hypothesis. Therefore, we do not have enough evidence to conclude that cars get better mileage on premium gasoline. Thus, we can conclude that there is no significant difference between the mileages of cars using premium and regular gasoline.

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a. The test that should be used is a two-sample t-test.

b. The null hypothesis is "The population mean mileage of cars using regular and premium gasoline are equal."

The alternative hypothesis is "The population mean mileage of cars using premium gasoline is more than the population mean mileage of cars using regular gasoline."

c. We do not have enough evidence to support the claim that cars get better mileage on premium regular gas.

a. To find what test should be used.

The test that should be used is a two-sample t-test.

b. To find the hypotheses.

The null hypothesis is "The population mean mileage of cars using regular and premium gasoline are equal."

The alternative hypothesis is "The population mean mileage of cars using premium gasoline is more than the population mean mileage of cars using regular gasoline."

c. Based on the R outputs, to find the conclusion about hypotheses testing.

The sample mean of the differences in mileage for cars filled with premium and regular gasoline is 0.8. The calculated t-value is -0.59702.

The calculated p-value is 0.2826.The p-value is higher than the significance level of 0.05.

Therefore, we fail to reject the null hypothesis.

We can't conclude that the population mean mileage of cars using premium gasoline is more than the population mean mileage of cars using regular gasoline.

Hence, we do not have enough evidence to support the claim that cars get better mileage on premium regular gas.

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