A grocery store sells three sizes of bags of one brand of potato chips. The big bag is 14 ounces and costs $6.30. The medium bag is 9.75 ounces and costs $2.50. The small bag is 8 ounces and costs $2.48. What is the cost per ounce of the medium bag size?* Your answer O This is a required question​

Answer:

A, C, and D

Step-by-step explanation:

Answer:

(x+4)(y-2)

Step-by-step explanation:

Hope this helped!!!!

Answer:

xy + 4y

Step-by-step explanation:

good luck!!!! hope this helps

Answer:

3^2 + 11^2 = 130

7^2 + 9^2 = 130

---

1^2 + 18^2 = 325

6^2 + 17^2 = 325

Step-by-step explanation:

We want to express 130 and 325 as the sum of two squares in two different ways.

Then, we want to find two integers a and b such that:

a^2 + b^2 = 130

There is not an analytical way to do this, we just need to try with different integers.

Let's start with 130.

So we start by defining a as a really small integer, for example 1, and try to find b.

1^2 + b^2 = 130

b^2 = 130 - 1

b^2 = √129 = 11.3

This is not an integer, so let's try with another value of a.

a = 2

2^2 + b^2 = 130

4 + b^2 = 130

b^2 = 130 - 4

b = √126 = 11.2

This can be discarded again.

Now let's try with a = 3

3^2 + b^2 = 130

9 + b^2 = 130

b^2 = 130 - 9

b = √121 = 11

Nice.

So we can express 130 as:

3^2 + 11^2 = 130

Now let's find another pair.

In the same way, we can see that for a = 7 we get:

7^2 + b^2 = 130

42 + b^2 = 130

b^2 = 130 - 49

b = √81 = 9

Then we can write:

7^2 + 9^2 = 130

Now for 325:

With the same reasoning than before, we want to find two integers such that:

a^2 + b^2 = 325

Then we start evaluating a by the smallest values:

a = 1

1^2 + b^2 = 325

b^2 = 325 - 1 = 324

b = √324 = 18

Then we can write 325 as:

1^2 + 18^2 = 325

Now to find the next pair we need to keep testing values for a, we will get for a = 6:

6^2 + b^2 = 325

36 + b^2 = 325

b^2 = 325 - 36 = 289

b = √289 = 17

Then we can write:

6^2 + 17^2 = 325.

Answer:

1.5

Step-by-step explanation:

-2,-1,0,1,2,3,4,5

Le quitamos un número hasta llegar al medio. En el medio hay dos números, el 1 y el 2. Pues tenemos que buscar el promedio de los dos (1+2=3 y 3÷2=1.5).

Answer:

x = 3

Step-by-step explanation:

The angle measuring 5x and the angle measuring 165° are a linear pair, so they are supplementary. Their measures add to 180°.

5x + 165 = 180

5x = 15

x = 3

Answer:

she spent like 40% of her time easy

Step-by-step explanation:

that was like 3rd grade

Answer:

DA

C

OD

OE

Step-by-step explanation:

Answer:

DA

1 meter by 4 meters

Step-by-step explanation:

To find the perimeter of a rectangle, you add up all four sides.

if a rectangles dimensions are 1 by 4, you would add 4 + 4 + 1 + 1 = 10

Hope this helps

Answer:

60

Step-by-step explanation:

The sum of two interior angles in a triangles is equal to one exterior angle that is supplementary to the third interior angle

3x+4x = 10x - 45

7x = 10x - 45 transfer 45 to the other side of equation and subtract 7x from 10 10

45 = 10x - 7x

45 = 3x divide both sides by 3

15 = x angle B is 4*15 = 60

Answer:

18x + 24

Step-by-step explanation:

6(3x + 4)

combine like terms

18x + 24

Answer:

The diameter of Pool A is  14.64  meters. So, the diameter of Pool B  is greater, and the circumference is  greater  by  0.56 meters.

Step-by-step explanation:

Identify the diameter of Pool A.

d = 2r

d = 2(24) Substitute 24 for r.

d = 48 ft

Convert from feet to meters. Use the ratio of 1 foot to 0.305 meters. Round to the nearest hundredth.

48 × 0.305 = 14.64

The diameter of Pool A is about 14.64 meters.

Use the formula to find the circumference of Pool A.

C = πd

C = π(14.64) Substitute 14.64 for d.

C ≈ 3.14(14.64) Substitute 3.14 for π.

C ≈ 45.97 Multiply.

The circumference of Pool A is about 45.97 feet.

Identify the diameter of Pool B.

d = 14.82 m

The diameter of Pool B is 14.82 meters.

Use the formula to find the circumference of Pool B.

C = πd

C = π(14.82) Substitute 14.82 for d.

C ≈ 3.14(14.82) Substitute 3.14 for π.

C ≈ 46.53 Multiply.

The circumference of Pool B is about 46.53 feet.

The circumference of Pool B is greater than the circumference of Pool A.

Find how much greater the circumference of Pool B is compared to the circumference of Pool A.

46.53 − 45.97 = 0.56

The circumference of Pool B is greater than the circumference of Pool A by about 0.56 meters.

Answer:

Step-by-step explanation:

If you check each answer, only B works since it is the only one that would place everything correctly on the timeline

Answer:

$25.88

Step-by-step explanation:

Given data

Cost of meal= $22.50

Tip= 15%

Let us find 15% of $22.50

=15/100*22.50

=0.15*22.50

=3.375

Hence the amount you would pay in total is

=3.375+22.5

=$25.88

Answer:

A = 16.5

T = 33

B = 10.5

Step-by-step explanation:

T = 2A

B = A-6

T + B + A = 60

(2A) + (A-6) + A = 60

4A - 6 = 60

4A = 66

A = 16.5

T = (16.5)*2 = 33

B = 10.5

Answer:

835$

Step-by-step explanation:

5$ for each extra mile

5 x 150 = 750

750 + 85 = 835

Answer:

x = 5, y = 2.5

Step-by-step explanation:

Because the original image is scaling down 4, it means all of the values of the shape will be scaled down, or divided by 4.

20, which divided by 4, will make x equal 5.

10, which divided by 4, will make y equal 2.5

Answer:

Step-by-step explanation:

fjfjgjgjghg

Answer:

x=8

Step-by-step explanation:

Hope this helps and have a wonderful day!!!

Answer:

6

Step-by-step explanation:

AP^2 = PC * PB

We have PC and BC. We need PB.

PC = 12

BC = 9

PB + BC = PC

PB + 9 = 12

PB = 3

AP^2 = 12 * 3

AP^2 = 36

AP = 6

Answer: 6

Answer:

Hey!

Step-by-step explanation:-

to solve this, the equation  PB X PC = [tex]AP^{2}[/tex]  can be used

In the ques, its given that PC= 12cm and BC = 9.

To solve this, WE NEED TO FIND PB, SO:-

PB + BC = PC

PB + 9 = 12

PB = 3cm.

Now, we can substitute this in the equation:- PB X PC = [tex]AP^{2}[/tex]

[tex]AP^{2}[/tex] = PB x PC

[tex]AP^{2}[/tex] = 3 X 12

[tex]AP^{2}[/tex] = 36

AP = [tex]\sqrt{36}[/tex]

Answer:

7.3

Step-by-step explanation:

Order of operations rules require that any work inside parentheses be done first.  Thus,

(4 + 2) - 1 + (2.3) becomes 6 - 1 + 2.3

This, in turn, becomes 5 + 2.3, and the final result is 7.3.

Answer:

Volume = lbh

Volume = 7 × 5 × 6

Volume = 7 × 30

Volume = 210 mm³

Therefore

Volume is 210 mm³

[tex] \\ [/tex]

[tex] \bullet [/tex] Length (l) of the cuboid = 7mm

[tex] \bullet [/tex] Breadth (b) of the cuboid = 5mm

[tex] \bullet [/tex] Height (h) of the cuboid = 6mm

The volume of the cuboid.

We know the formula of the volume of the cuboid is ( Length × Breadth × Height ) cubic units.

[tex] \therefore [/tex] Volume of the cuboid is ( 7 × 5 × 6 ) mm³

Volume of the cuboid is 210 mm³.

Answer: I hope this helps!

brainliest or a thank you pls :)) <33

Answer:

67°........................

Answer:

x=67

Step-by-step explanation:

Answer:

8) 144pi

9) 196pi

11) 18pi

12) 298.67pi

Step-by-step explanation:

The volume of a cylinder is [tex]V = \pi r^{2} h[/tex], where r represents the radius of the base and h represents the height.

For the first cylinder, the radius of the base is 4 and the height is 9.

[tex]V = \pi (4)^{2} (9)\\V = \pi(16)(9)\\V = 144\pi[/tex]

For the second cylinder, the diameter is 6 and the height is 2. Since the radius is half the diameter, the radius is 3.

[tex]V = \pi (3)^{2} (2)\\V = \pi(9)(2)\\V = 18\pi[/tex]

The volume of a sphere is [tex]V = 4\pi r^{2}[/tex], where r is the radius of the sphere.

The diameter is 14, meaning the radius must be 7.

[tex]V = 4\pi (7)^{2} \\V = 4\pi (49)\\V = 196\pi[/tex]

The volume of a cone is [tex]V = \pi r^{2} (h/3)[/tex], where r is the radius and h is the height.

The radius is 8, and the height is 14.

[tex]V = \pi (8)^{2} (14/3)\\V = \pi (64) (14/3)\\V = \frac{896}{3} \pi\\V = 298.67\pi[/tex]

Respuesta:

79.4 pies

Explicación paso a paso:

Dado que :

Longitud del autobús = 33,5 pies

Longitud del tren = 45,9 pies más largo que el autobús

Por lo tanto, la longitud del tren es igual a:

Longitud del bus + 45,9 pies

33,5 pies + 45,9 pies

Longitud del tren = 79,4 pies

Answer:

I think you are in a test..You should do by your own

You need to include the Image