Find FH
Need help ASAP !!
Answer:
[tex]FH=22[/tex]
Step-by-step explanation:
FH is the combined lengths of FG and GH.
In an equation, this is:
[tex]FH=FG+GH[/tex]
We already know that FG is 8 and that GH is 14. Thus:
[tex]FH=8+14[/tex]
Add:
[tex]FH=22[/tex]
So, the length of FH is 22.
And we're done!
Write 6.88 billion in standard form.
Answer:
The standard form would be 6,880,000,000..
CAN SOMONE PLEASE HELP ME ASAP PLEASEEE!!!
Answer:
The yellow polygon is the scaled version of the red one (scaled by 3×), so the variable w = 9
Answer:
9
Step-by-step explanation:
The similarity ratio is 4/x = z/9 = 2/6 = 3/w = y/15
2/6 = 3/w cross multiply expressions 2w = 18 and w = 9
Given the following formula, solve for I.
P =
2(1 + b)
Answer: [tex]l=\dfrac{P}{2}-b[/tex]
Step-by-step explanation:
P = 2(l + b)
Divide both sides by 2:
[tex]\dfrac{P}{2}=l+b[/tex]
Subtract b from both sides:
[tex]\dfrac{P}{2}-b=l[/tex]
Note: You can also multiply b by [tex]\frac{2}{2}[/tex] if you want the left side to be one fraction.
[tex]\dfrac{P}{2}-\bigg(\dfrac{2}{2}\bigg)b=l\\\\\\\dfrac{P-2b}{2}=l[/tex]
Josue ran 6/10 of a mile and jogged 4/10 of a mile. What is the difference in simplest form
Answer:
1/5
Step-by-step explanation:
Find the difference quotient and simplify your answer.
f(x) = x2 – 2x + 6,
h = 0
h
f(8 + h) – f(8),
We're given that
[tex]f(x)=x^2-2x+6[/tex]
which means
[tex]f(x+h)=(x+h)^2-2(x+h)+6=x^2+2xh+h^2-2x-2h+6[/tex]
When we subtract these, several terms cancel:
[tex](x^2+2xh+h^2-2x-2h+6)-(x^2-2x+6)=2xh+h^2-2h[/tex]
So the difference quotient is
[tex]\dfrac{f(x+h)-f(x)}h=\dfrac{2xh+h^2-2h}h[/tex]
and since h ≠ 0, we can cancel it out to end up with
[tex]\dfrac{f(x+h)-f(x)}h=2x+h-2[/tex]
Now plug in x = 8 (this could have been done at any prior point):
[tex]\dfrac{f(8+h)-f(8)}h=14+h[/tex]
please help me i would appreciate it
Answer:
1/2 meter long
Step-by-step explanation:
To answer this question use the equation 1 1/3 - 5/6
Next make 1 1/3 an improper fraction
To do this multiply the integer and the denominator and then add all of that plus the numerator
This means that 1 1/3 is 4/3
4/3 - 5/6
Next make the denominators the same
This means finding the LCM which is 6
8/6 - 5/6 = 3/6 (1/2)
Heidis hair is 1/2 meters long
A school have 764 students of the students 118 are in the third grade. Which equation can be used to find s, the total of students in all of the other grades?
Answer:
764 - 118 = 646
Step-by-step explanation:
Answer:
subtract 118 from 764 and that's the rest of the students
Can someone plz tell me if I’m right?
Answer:
Step-by-step explanation:
Since x is used a lot as a variable in algebra, I would use another symbol for multiplication. Though if your teacher requires you to use x as a multiplication symbol, then keep it as is. I use the asterisk symbol
Example: 2 times 3 = 2*3
------------------------------------------
For problem 2, you have the parenthesis in the wrong spots. Saying "the sum of four plus five" means we have 4+5 as you'd expect. Then you multiply that group with 2. So you'd really have (4+5)*2
How is this different from 4+5*2 back in problem 1? It comes down to how the order of operations handles things. To evaluate 4+5*2, we multiply first, then add. So we have 4+5*2 = 4+10 = 14
With the other expression, we add first because it is in the parenthesis block. Afterward we multiply the values to get (4+5)*2 = 9*2 = 18
Write the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 in this order and insert '+' or '-' between them to get the result 3? Please Help
Answer:
0 - 1 - 2 + 3 - 4 + 5 - 6 +7 - 8 + 9 = 3
Step-by-step explanation:
How do you Simplify the expression completely.
c(4b3+3a)+b(2cb2−6ac)
Click
Answer:
c×3 (2 b^3 - 2 a b + a)
Step-by-step explanation:
Simplify the following:
c (4 b^3 + 3 a) + b (2 c b^2 - 6 a c)
Hint: | Factor common terms out of 2 c b^2 - 6 a c.
Factor 2 c out of 2 c b^2 - 6 a c:
c (4 b^3 + 3 a) + b×2 c (b^2 - 3 a)
Hint: | Pull a common factor out of c (4 b^3 + 3 a) + b×2 c (b^2 - 3 a).
Factor c out of c (4 b^3 + 3 a) + b×2 c (b^2 - 3 a), resulting in c ((4 b^3 + 3 a) + b×2 (b^2 - 3 a)):
c (4 b^3 + 3 a + 2 b (b^2 - 3 a))
Hint: | Distribute 2 b over b^2 - 3 a.
2 b (b^2 - 3 a) = 2 b^3 - 6 a b:
c (4 b^3 + 3 a + 2 b^3 - 6 a b)
Hint: | Group like terms in 4 b^3 + 3 a - 6 a b + 2 b^3.
Grouping like terms, 4 b^3 + 3 a - 6 a b + 2 b^3 = (4 b^3 + 2 b^3) - 6 a b + 3 a:
c (4 b^3 + 2 b^3) - 6 a b + 3 a
Hint: | Add like terms in 4 b^3 + 2 b^3.
4 b^3 + 2 b^3 = 6 b^3:
c (6 b^3 - 6 a b + 3 a)
Hint: | Factor out the greatest common divisor of the coefficients of 6 b^3 - 6 a b + 3 a.
Factor 3 out of 6 b^3 - 6 a b + 3 a:
Answer: c×3 (2 b^3 - 2 a b + a)
A device has a constant failure rate with a MTTF of 2 months. One hundred of the devices are tested to failure. (a) How many of the devices do you expect to fail during the second month
Answer: the number of devices expected to fail during the second month is 24
Step-by-step explanation:
Given that
The device has a constant failure rate with MTTF of 2 months.
As the device has constant failure rate so it has exponential failure distribution
f(t) = λe^-λt
Here MTTF = 1/ λ
so λ = 1/2 Months⁻¹ = 0.5 Months⁻¹ and from the question, Number of devices = 100
E( 1 < x < 2) = E ( x < 2) - E (x < 1)
so E(x < X) can be calculated with λ = 0.5 Months⁻¹ will be calculated as the failure function
f(x) = λ exp ( - λ×t) for t > 0
F (x>0) = 1 - exp( - λx)
so E ( 1 < x < 2) = E ( x < 2) - E (x < 1)
E ( x < 2) = 1 - exp(-0.5 × 2) = 0.6321 ; E (x<1) = 1 - exp(-0.5 × 2) = 1 - exp( -0.5) = 0.3934
so E ( 1 < x < 2) = 0.6321 - 0.3934 = 0.2387
so the number of devices expected to fail during the second month is;
100 × 0.2387 = 23.87 ≈ 24
(!20 POINTS PLEASE HELP!) The students in a class are randomly drawing cards numbered 1 through 28 from a hat to determine the order in which they will give their presentations. Find each probability. Solve each problem below 1. P(13) 2. P(less than 14) 3. P(not 2 or 17)
Since there is 28 cards, the chance of drawing 1 card will be [tex]\frac{1}{28}[/tex]
Therefore, [tex]P(13)=\frac{1}{28}[/tex].
There are 13 numbers less than 14 and greater than 0.
Therefore [tex]P(>14)=\frac{13}{28}[/tex]
There are 26 numbers that are not 2 or 17.
Therefore [tex]P(\neq 2,17)=\frac{26}{28}=\frac{13}{14}[/tex]
Hope this helps.
頑張って!
Probability of
Option (1). P(13) =[tex]\frac{1}{28}[/tex]
Option (2). P(less than 14) = [tex]\frac{13}{28}[/tex]
Option (3). P(not 2 or 17) =[tex]\frac{13}{14}[/tex]
What is Probability?Probability is the branch of mathematics concerning numerical descriptions of how likely an event is to occur
Given,
Total number of card = 28
Probability = Number of favorable outcome / Number of total outcome
Probability of picking 13 = [tex]\frac{1}{28}[/tex]
Probability of picking a card less then 14 = [tex]\frac{13}{28}[/tex]
Probability of not picking 2 or 17 = [tex]\frac{26}{28}=\frac{13}{14}[/tex]
Hence, the probability of
Option (1). P(13) =[tex]\frac{1}{28}[/tex]
Option (2). P(less than 14) = [tex]\frac{13}{28}[/tex]
Option (3). P(not 2 or 17) =[tex]\frac{13}{14}[/tex]
Learn more about Probability here
https://brainly.com/question/11234923
#SPJ2
Find the solution to the initial value problem
y′′+8y′+16=0, y(−1)=2, y′(−1)=3.
Answer:
y = (11x + 13)e^(-4x-4)
Step-by-step explanation:
Given y'' + 8y' + 16 = 0
The auxiliary equation to the differential equation is:
m² + 8m + 16 = 0
Factorizing this, we have
(m + 4)² = 0
m = -4 twice
The complimentary solution is
y_c = (C1 + C2x)e^(-4x)
Using the initial conditions
y(-1) = 2
2 = (C1 -C2) e^4
C1 - C2 = 2e^(-4).................................(1)
y'(-1) = 3
y'_c = -4(C1 + C2x)e^(-4x) + C2e^(-4x)
3 = -4(C1 - C2)e^4 + C2e^4
-4C1 + 5C2 = 3e^(-4)..............................(2)
Solving (1) and (2) simultaneously, we have
From (1)
C1 = 2e^(-4) + C2
Using this in (2)
-4[2e^(-4) + C2] + 5C2 = 3e^(-4)
C2 = 11e^(-4)
C1 = 2e^(-4) + 11e^(-4)
= 13e^(-4)
The general solution is now
y = [13e^(-4) + 11xe^(-4)]e^(-4x)
= (11x + 13)e^(-4x-4)
Don't call me square! While I have four right angles,
that term wouldn't be fair. While I have two parallel
sides, they both measure a different size. What shape
am I Draw me.
alex buys six equally priced candy bars for $9:00 what is the unit rate?
Answer:
$1.5 unit
Step-by-step explanation:
According to the given situation, the calculation of the unit rate is shown below:-
Candy bars = 6
Amount of candy bars = $9:00
Unit rate
[tex]= \frac{Amount\ of\ candy\ bars}{Number\ of\ candy\ bars}[/tex]
Now we will put the values into the above formula
[tex]= \frac{\$9:00}{6}[/tex]
Which gives result
= $1.5 unit
Therefore for computing the unit rate we simply divide the amount of candy bars by the number of candy bars.
d) 256 chocolates are distributed among the students of class 5.
If the number of chocolates obtained by each students is the same
as the number of students in the class, find the number of students
in the class?
Answer:
16
Step-by-step explanation:
Let x be the number of chocolates obtained by each student
Since the number of chocolates obtained by each student = the number of students in the class, then, number of students in the class = x
256/x = x
Multiply both sides by x
256 = x × x ( x squared)
Multipy powers raised on both sides by 1/2
X = 16
T is the midpoint of SU, ST = 8x + 11 and TU = 12x-1, find the value of x.
Answer:
x = 3
Step-by-step explanation:
mid point means it bisects the segment into two equals halfs meaning
ST = TU
8x + 11 = 12x - 1
8x + 12 = 12x
12 = 4x
3 = x
Integrate the following w.r.t x 1) 2x^2/3.
2) (5-x)^23
Answer:
A) [tex]\int\frac{2x^2}{3}dx=\frac{2x^3}{9}+C[/tex]
B) [tex]\int(5-x)^{23}dx=-\frac{(5-x)^{24}}{24}+C[/tex]
Step-by-step explanation:
A)
So we have the integral:
[tex]\int\frac{2x^2}{3}dx[/tex]
First, remove the constant multiple:
[tex]=\frac{2}{3}\int x^2\dx[/tex]
Use the power rule, where:
[tex]\int x^ndx=\frac{x^{n+1}}{x+1}[/tex]
Therefore:
[tex]\frac{2}{3}\int x^2\dx\\=\frac{2}{3}(\frac{x^{2+1}}{2+1})[/tex]
Simplify:
[tex]=\frac{2}{3}(\frac{x^{3}}{3})[/tex]
And multiply:
[tex]=\frac{2x^3}{9}[/tex]
And, finally, plus C:
[tex]=\frac{2x^3}{9}+C[/tex]
B)
We have the integral:
[tex]\int(5-x)^{23}dx[/tex]
To solve, we can use u-substitute.
Let u equal 5-x. Then:
[tex]u=5-x\\du=-1dx[/tex]
So:
[tex]\int(5-x)^{23}dx\\=\int-u^{23}du[/tex]
Move the negative outside:
[tex]=-\int u^{23}du[/tex]
Power rule:
[tex]=-(\frac{u^{23+1}}{23+1})[/tex]
Add:
[tex]=-(\frac{u^{24}}{24})[/tex]
Substitute back 5-x:
[tex]=-(\frac{(5-x)^{24}}{24})[/tex]
Constant of integration:
[tex]=-\frac{(5-x)^{24}}{24}+C[/tex]
And we're done!
02.01)Which is the ratio of the number of months that begin with the letter J to the total number of months in a year? 12 to 3 3 to 9 9 to 12 3 to 12 HELP!!! FOR MY MATH TEST
Answer:
3 to 12
Step-by-step explanation:
3 months (January, June, July) and 12 monthes
Answer: the answer is 3 to 12
Step-by-step explanation: hope this will help
Malik borrowed $105 from his brother and plans to repay $12 per week. He creates a table to help him determine the
number of weeks it will take to repay his brother. How many weeks will it take Malik to repay his brother?
8
9
10
11
please help!!!!
Answer:
9
Step-by-step explanation:
12×9=108 108>105 so it can't be any other number cuz we go too high or too low
Answer:
9
Step-by-step explanation:
What is (x+5)(x-4)=0 Expand and solve for x
step 1
(x - 4) • (x + 5) = 0
STEP
:
A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
Solving a Single Variable Equation:
2.2 Solve : x-4 = 0
Add 4 to both sides of the equation :
x = 4
Solving a Single Variable Equation:
2.3 Solve : x+5 = 0
Subtract 5 from both sides of the equation :
x = -5
.
Answer:
A) [tex]\huge\boxed{\sf x^2 + x - 20 = 0}[/tex]
B) [tex]\huge\boxed{\sf x = - 5 \ \ \ \ OR \ \ \ \ x = 4}[/tex]
Step-by-step explanation:
[tex]\sf (x+5)(x-4) = 0[/tex]
[tex]\rule[225]{225}{2}[/tex]
Expanding:
Expanding Brackets
[tex]\sf x^2 -4x+5x-20 = 0[/tex]
Adding / Subtracting Like terms
[tex]\sf x^2 + x - 20 = 0[/tex]
[tex]\rule[225]{225}{2}[/tex]
Solving:
Given the equation:
(x+5)(x-4) = 0
Using zero Method
Either,
x + 5 = 0 OR x - 4 = 0
x = - 5 OR x = 4
[tex]\rule[225]{225}{2}[/tex]
Find an equation of the plane.The plane through the point(4, −3, −1)and parallel to the plane 6x − y − z = 6
Both planes have the same normal vector:
[tex]6x-y-z=6\implies\mathbf n=\langle6,-1,-1\rangle[/tex]
The plane we want must contain the point (4, -3, -1), so its equation would be
[tex]\mathbf n\cdot\langle x-4,y+3,z+1\rangle=0[/tex]
[tex]\implies 6(x-4)-(y+3)-(z+1)=0[/tex]
[tex]\implies\boxed{6x-y-z=28}[/tex]
Angles 1 and 2 are complementary, and angle 1=3x+3 and angle 2=10x-4, find the degree measure of each angle
Answer:
The measure of the angles:
24° and 66°
Step-by-step explanation:
Complementary angles sum 90°
then:
(3x + 3) + (10x-4) = 90
3x + 10x + 3 - 4 = 90
13x - 1 = 90
13x = 90+1
13x = 91
x = 91/13
x = 7°
then:
angle 1:3x+3 = 3*7 + 3 = 21+3 = 24°
angle 210x - 4 = 10*7 - 4 = 70 - 4 = 66°
Check:
66° + 24° = 90°
use the values in the table to determine the slope.
Answer:
-3/2
Step-by-step explanation:
Take two points from the table and use the slope formula
m= (y2-y1)/(x2-x1)
= ( 19 - 13)/ ( -4 - 0)
= 6/-4
= -3/2
Find The Area Of The Shape Shown Below
Answer:42.55
Step-by-step explanation:
Les get the big boi out of the way first. We see that it is 3.5 by 9 and if we multiply we get 31.5. Next left triangle 2 by 2 so four but divided by 2 is 2. God so many 2's. So total is 33.5 so far. Next triangle is 2 by 5 soo 10 divided by 2 is 5. total is 38.5. Last dude in the middle. We know one side is two so we have to subtract here from the triangles which gets u the other side of 2 so 4. Total is 42.5
The Area of the Shape Shown is 42.5 square units.
What is Area of Rectangle?The area of Rectangle is length times of width.
The area of the rectangle in the given figure is
Area of rectangle=3.5×9
=31.5 square units.
The area of left side triangle is
Area of triangle=1/2×2×2
=2 square units
The area of right side triangle 1/2×5×2
=5 square units
Now the area of square =2²
=4 square units.
Now total area of figure is 31.5+2+5+4 is 42.5 square units.
Hence, the Area of the shape Shown is 42.5 square units.
To learn more on Area of Rectangle click:
https://brainly.com/question/20693059
#SPJ2
A couple wants to install a square mirror on their bathroom wall. The area of the square mirror is 720 square inches. To the nearest hundredth of an inch, what length of wood trim is needed to go around the entire mirror?
Answer:
107.33 inches
Step-by-step explanation:
Area of the square more = length ^2
Area of the square mirror = 720 square inches
Area of the square more = length ^2
720 = length^2
Find the square root of both sides
√720 = √lenght^2
Length = √720
Length = 26.83281573 inches
Each length of the wood = 26.83281573 inches
There are 4 equal sides on the square mirror
Total length of the wood = 26.83281573 × 4
= 107.33126292 inches
Length of wood trim is needed to go around the entire mirror to the nearest hundredth = 107.33 inches
HELP ME PLS I DONT UNDERSTAND :(((( WILL MARK BRAINLIEST AND ROBUX
Answer:
H -2 ≤x≤4
Step-by-step explanation:
The domain is the input values or the x values
-2 ≤x≤4
Answer:
H
Step-by-step explanation:
You can see because the answer starts with -2.
find (f+g) (x) f (x) = 4x - 4 and g (x) = 2x^2 - 3x
(f+g)(x) = f(x) + g(x)
= 4x - 4 + 2[tex]x^{2}[/tex] - 3x
= 2[tex]x^{2}[/tex] + x - 4
Bolts are packed into bags at a factory. Each bag should have 25 bolts in it but a bad with 22 or 28 is acceptable. Formulate an absolute value equation that could be used to solve for the minimum and maximum number of bolts in a bag.
|x____ | = ______
x = _____(smaller number here)
x = ________(larger number here)
Blank 1:
Blank 2:
Blank 3:
Blank 4:
Answer:
Absolute value equation is; |x - 25| ≤ 3
Minimum number of bolts is 22 while Maximum number of bolts is 28
Step-by-step explanation:
We are told that;
Each bag should have 25 bolts in it but 22 or 28 is acceptable.
Since 22 or 28 is acceptable, it means the allowable error is ±3.
Thus, if x is the number of bolts in the bag, the absolute value equation would be;
|x - 25| ≤ 3
Minimum number of bolts is 22 while maximum is 28