A gas in a sealed container has a pressure of 125 atm at a temperature of 303 K. If the pressure in the container is increased to 200 atm, what is the new temperature if the volume remains constant?
(Show work pls :)!)

Answer:

(a) The mass of an object remains the same always. It is independent of its location. In this case, an iron nail is ground into powder.

Explanation:

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Answer:

See Explanation

Explanation:

The unbalanced reaction equation is;

CO2(g) + LiOH(aq) + Li2CO3(aq) + H2O(l)

The balanced chemical reaction equation;

CO2(g) + 2LiOH(aq) + Li2CO3(aq) + H2O(l)

The molar mass of each compound is the sum of the relative atomic masses of the atoms of the elements that compose the compounds.

For CO2

12 + 16(2) = 12 + 32 = 44 g/mol

For LiOH

7 + 16 + 1 = 24 g/mol

For Li2CO3

2(7) + 12 + 3(16) = 74 g/mol

For H2O

2(1) + 16 = 18 g/mol

From the balanced chemical reaction equation, the mole ratio is 1:2:1:1. This is obtained from the stoichiometric coefficient of each reactant in the balanced chemical reaction equation.

From the question;

1 mole of CO2 occupies 22.4 L

x moles of CO2 occupies 825 L

x = 1 mole * 825 L/22.4 L

x = 36.8 moles

From the reaction equation;

1 mole of CO2 produces 1 mole of water

36.8 moles of CO2 produces 36.8 moles of water

Mass of 36.8 moles of water = 36.8 moles * 18 g/mol

= 662 g of water

The answer must have three significant figures because that is the same number of significant figures to which values were given in the question.

The question is incomplete, the complete question is;

When a lead acid car battery is recharged by the alternator, it acts essentially as an electrolytic cell in which solid lead(II) sulfate PbSO₄ is reduced to lead at the cathode and oxidized to solid lead(II) oxide PbO at the anode.

Suppose a current of 96.0 A is fed into a car battery for 37.0 seconds. Calculate the mass of lead deposited on the cathode of the battery. Round your answer to 3 significant digits. Also, be sure your answer contains a unit symbol.

Answer:

3.81 g of lead

Explanation:

The equation of the reaction is;

Pb^2+(aq) + 2e ---->Pb(s)

Quantity of charge = 96.0 A * 37.0 seconds = 3552 C

Now we have that 1F = 96500 C so;

207 g of lead is deposited by 2 * 96500 C

x g of lead is deposited by 3552 C

x = 207 *  3552/2 * 96500

x = 735264/193000

x = 3.81 g of lead

[tex]M_{A}V_{A}=M_{B}V_{B}\\(5.25)M_{A}=(4.96)(0.9845)\\M_{A}=\frac{(4.96)(0.9845)}{5.25} \approx \boxed{0.93 \text{ M}}[/tex]

Answer:

in my opinion I think the answer the be "A"

Answer:

SnSO₄

Explanation:

Tin(II) sulfate is a chemical compound. It is a white solid that can absorb enough moisture from the air to become fully dissolved, forming an aqueous solution; this property is known as deliquescence.

Answer:

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Explanation:

SnSO₄

Answer:

the density of the Gas at STP is 0.227 g/L .

Explanation:

This question involves the combined gas law . The equation for the combined gas law

Answer:

Plant A

Explanation:

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Answer:

0.99 μmol/L

Explanation:

From the question given above, the following data were obtained:

Volume of stock solution (V₁) = 20 mL

Concentration of stock solution (C₁) = 18.8 μmol/L

Volume of diluted solution (V₂) = 380 mL

Concentration of diluted solution (C₂) =?

The concentration of the diluted solution can be obtained as follow:

C₁V₁ = C₂V₂

18.8 × 20 = C₂ × 380

376 = C₂ × 380

Divide both side by 380

C₂ = 376 / 380

C₂ = 0.99 μmol/L

Therefore, the concentration of the diluted solution the chemist is working on is 0.99 μmol/L

Answer:

The answer is "4.31"

Explanation:

aniline millimoles [tex]= 111 \times 0.37 = 41.07[/tex]

added [tex]HNO_3[/tex]  millimoles [tex]= 79.1 \times 0.35 = 27.685[/tex]

[tex]\to 41.07 - 27.685 = 13.385[/tex] millimoles aniline left

[tex]\to 27.685[/tex] millimoles salt formed

total volume[tex]= 111 + 79.1 = 190.1\ mL\\\\[/tex]

[tex]\to [aniline] = \frac{13.385}{190.1} = 0.07 \ M\\\\\to [salt] =\frac{ 27.685}{ 190.1} = 0.146\ M\\\\\to pOH = pKb + \frac{\log [salt]}{ [base]}\\\\\to pOH = 9.37 + \frac{\log [0.146]}{[0.07]}\\\\\to pOH = 9.69\\\\\to pH = 14 - 9.69\\\\\to pH = 4.31\\[/tex]

The oldest form where an image is transferred from one surface to another is printmaking, Screen frame commonly made of covered tightly with wood, technique makes use of woven mesh to support an ink blocking stencil is Silkscreen printing and A tool that usually made of vinyl or rubber blade is called Squeegee.

Art is a technique in which we use different kinds of things like paintings, printings, drawings and do exhibition for the decoration purpose.

Hence C, A, A and B is the correct answers of the given questions.

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Answer: Keq= [CO2]^6[H2O]^6/ [O2]^6

Explanation:

The correct equilibrium constant expression for this equation C6H1206(s) + 60,(g) <—>6C02(g)+ 6H2O(g) will be

keq = 6[co2] 6[h2o] / [c6h1206] 6[o].

All reactions tend towards the state of chemical equilibrium. It is the point at which both the forward process and the reverse process are taking place at the same rate.

Since the forward and reverse rates are equal, hence the concentrations of the reactants and products will be constant at the equilibrium state. Here, it is important to remember that even though the concentrations are constant at equilibrium.

The double half-arrow sign we use for writing the reversible reaction equations. It is represented as ⇌ a sign of equilibrium.

therefore, the correct equilibrium constant expression will be C6H1206(s) + 60,(g) <—>6C02(g)+ 6H2O(g)

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Answer:

167.217g/mol

Explanation:

Formula mass is defined as the mass in grams that a mole of a molecule weighs. To solve the formula mass of ZrF₄ we require the molar mass of Zr and of F (Molar mass Zr: 91.225g/mol; F: 18.998g/mol)

In this molecule, there is 1 mole of Zr and 4 moles of F. The formula mass is:

Zr = 1*91.225g/mol = 91.225g/mol

F = 4*18.998g/mol = 75.992g/mol

Formula mass: 91.225g/mol + 75.992g/mol

[tex](normality \: of \: acid)×(volum \: of \: acid) = (normality \: of \: base)×(volum \: of \: base)[/tex]

0.15N × 50mL = 0.2N × (Vbase)

75mL = Volum of base

37.5mL of NaOH will be required to titrate 0.200 M NaOH, strong base, with 50.00 ML of 0.150 M HCI, strong acid to the endpoint.

The volume of a solution can be calculated using the following formula:

C1V1 = C2V2

Where;

0.2 × V1 = 0.150 × 50

0.2V1 = 7.5

V1 = 7.5/0.2

V1 = 37.5mL

Therefore, 37.5mL of NaOH will be required to titrate 0.200 M NaOH, strong base, with 50.00 mL of 0.150 M HCI, strong acid to the endpoint.

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Answer:

Extending DNA strands to match samples

Answer: Al₂O₃

Explanation:

Answer:

The volume is 22.66 mL

Explanation:

D = 22.1 g/cm³, M = 523.1 g, V = ? mL

For Volume

Density = Mass ÷ Volume

Volume = Mass ÷ Density

V = M ÷ D

V = 523.1 g ÷ 22.1 g/cm³

V = 23.66 cm³

Now, 1 cm³ = 1 mL

So,

V = 22.66 mL

Thus, The volume is 22.66 mL

-TheUnknownScientist

Answer:

0.22M

Explanation:

We will be using the law of dilutions. We are simply increasing the amount of solvent to create a larger volume of solution.

So: moles before dilution = moles after dilution & [tex]moles_{concentrated} = moles_{dilute}[/tex]. And M = moles/liter of solution, so if we express this as moles = M x [tex]L_{soln}[/tex].

That is how we derive the formula we will be using: [tex]M_{concentrated} * Vol_{conc} = M_{dilute} * Vol_{dilute}[/tex]

or

[tex]M_{1} * Vol_{1} = M_{2} * Vol_{2}[/tex]

Applying this formula to our problem, we can substitute the variables with the given values to find the molarity of the dilute solution.

M1 = 3.5M

V1 = 18.8mL

M2 = ?

V2 = 296.6mL

Equation: (3.5M)(18.8mL) = (296.6mL)(M2)

==> 65.8M*mL = 296.6mL * M2

==> M2 = (65.8 M*mL)/296.6mL

==> M2 = 0.22M

Answer:

1.15 M

Explanation:

Step 1: Given data

Step 2: Calculate the final concentration of the solution

We want to prepare a dilute solution from a concentrated one by adding water. We can calculate the concentration of the dilute solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂

C₂ = 3.00 M × 0.125 L/0.325 L = 1.15 M

Answer:

true

Explanation:

This layer will prevent moisture from reaching the metal and therefore prevent rust. oil paint especially

Answer:

Learning the rock cycle and understanding the processes involved helps all of us. This is how soil forms, through the breakdown of rocks. We need soil to survive—imagine trying to grow vegetables without it. This is an immediate connection to the food chain

Answer:

68

Explanation:

D. Radioactive material can leave the patient’s body through saliva, sweat, and urine.

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Answer:

Please find the solution in the attachment file.

Explanation:

Answer:

25.4 J/mol

Explanation:

The specific heat of any substance is referring to the amount of energy required to raise 1 gram of that substance 1 degree kelvin. Molar heat capacity is referring to the amount of energy required to raise 1 mole of that substance 1 degree kelvin. So in order to solve for molar heat capacity of gold we must convert from grams of gold to moles of gold.

( 0.129 J /g) ( 196.97 g/ m o l ) = 25.4 J m o l

196.97 is the molar mass of gold which can be found on the Periodic Table of Elements. Because grams are located on both sides of the denominator they cancel out leaving us with our new units of J/mol.

Answer:

Explanation:

So we know q = mc[tex]\Delta[/tex]T.

q = 55.7 J

c = 0.129j/g°C

and [tex]\Delta[/tex]T = 314-274 = 40°C.

and m is mass which can solve since we got every other variable. We will get m = 10.8g.