A gas at 300 k and 4.0 atm is moved to a new location with a temperature of 250 k. the volume changes from 5.5 l to 2.0 l. what is the pressure of the gas at the new location? use the formula: p1v1 t1 = p2v2 t2

Answers

Answer 1

Answer:

9.17 atm

Explanation:

To find the new pressure of the gas, you need to use the following manipulated formula:

P₁V₁ / T₁ = P₂V₂ / T₂

In this formula,

P₁ = initial pressure (atm)              P₂ = new pressure (atm)

V₁ = initial volume (L)                    V₂ = new volume (L)

T₁ = initial temperature (K)            T₂ = new temperature (K)

Because you have been given values for all of the variables except for the new pressure, you can substitute them into the equation and simplify.

P₁ = 4.0 atm                                  P₂ = ? atm

V₁ = 5.5 L                                      V₂ = 2.0 L

T₁ = 300 K                                     T₂ = 250 K

P₁V₁ / T₁ = P₂V₂ / T₂                                                     <----- Given formula

(4.0 atm)(5.5 L) / (300 K) = P₂(2.0 L) / (250 K)           <----- Insert variables

0.073333 = P₂(2.0 L) / (250 K)                                   <----- Simplify left side

18.33333 = P₂(2.0 L)                                     <----- Multiply both sides by 250

9.17 = P₂                                                        <----- Divide both sides by 2.0

Answer 2

Answer:

=> 13.2 atm

Explanation:

From the question, we have question we have been provided with pressure, volume and temperature. Based on these variables, we are supposed to use the combined gas law formula (P1V1T1 = P2V2T2)

                   At location 1;

P1 = 4.0 atm

V1 =  5.5 L

T1 = 300 K.

                       At location 2;

P2 = ?

V2 = 2.0 L

T2 = 250 K.

We are required to determine the pressure (P2).

To begin, we make pressure (P2) the subject of in the formula:

      P2 = (P1V1T1)/(V2T2)  ................ eq. (i)

Then substitute the known values into the eq. (i).

  P2 = (4.0 x 5.5 x 300)/(2.0 x 250) atm

       = 13.2 atm.

Therefore, the pressure (P2) at location 2 is 13.2 atm.


Related Questions

how did scientists respond to Copernicus's discovery

Answers

Answer:

Scientists were slow to let go of the current theories.

Explanation:

this is correct

If you started with 2.864 g of sodium bicarbonate and heated it to constant mass, what would the mass of the residue be after the reaction

Answers

If you started with 2.864 g of sodium bicarbonate and heated it to constant mass, 0.59 gram would be the mass that residue after the reaction.

What is Stoichiometry ?

Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.

What is Balanced Chemical Equation ?

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now we have to write the balanced equation

2NaHCO₃  → Na₂CO₃ + CO₂ + H₂O

According to Stoichiometry

= [tex]2.864\ g\ NaHCO_{3} \times \frac{1\ \text{mole}\ Na_2CO_3}{105.9\ g/mol} \times \frac{1\ \text{mole}\ CO_2}{2\ \text{mole}\ NaHCO_3} \times \frac{44\ g \ CO_2}{1\ \text{mole}\ CO_2}[/tex]

= 0.59 g

Thus from the above conclusion we can say that If you started with 2.864 g of sodium bicarbonate and heated it to constant mass, 0.59 gram would be the mass that residue after the reaction.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: If you started with 2.486 g of sodium bicarbonate and heated it to constant mass, what would the mass of the residue be after the reaction? Show your work.

NaHCO₃  → Na₂CO₃ + CO₂ + H₂O  

calculate molar mass of H2SO3

Answers

The atomic mass of hydrogen is 1.00794 g/mol.The atomic mass of sulfur is 32.06 g/mol.The atomic mass of oxygen is 15.9994 g/mol.

So, the total atomic mass is [tex]2(1.00794)+32.06+3(15.9994)=\boxed{82.07408 \text{ g/mol}}[/tex]

Arrange the elements in order of increasing electronegativity. Use the periodic table to help you arrange the elements.
P O K Mg

< < < <

Answers

Answer:

K<Mg<P<O

Explanation:

Trend is increasing across period and decreasing down a group

Answer:

k-mg-p-o

Explanation:

thank me later love

will the shielding effect be more noticeable in metals or nonmetals? explain your answer.

Answers

The shielding effect is more noticeable in metals than non-metals.

What is shielding effect?

The shielding effect is known as a decrease in the effective nuclear charge on the electron cloud as a result of a variation in the attraction forces acting on the atom's electrons.

Why shielding effect is strong in metals?

Metals will have a more pronounced shielding effect as compared to nonmetals during the same time span. The amount of p+ atoms in the nucleus grows as you advance across the periodic table, raising the nuclear charge of the atom. Because the valence e- are drawn more firmly towards the nucleus in nonmetals, the inner core's shielding action is less obvious.

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what is the main ore o
f copper ​

Answers

Answer:

The principal copper ore mineral is chalcopyrite (CuFeS2), which is commonly smelted to yield a matte containing ~50% copper.

Answer:

chalcopyrite

Explanation:

The principal copper ore mineral is chalcopyrite (CuFeS2),

For the equation 3cu 8hno3 → 3cu(no3)2 2no 4h2o, how many units of no3 are represented on the products side? 2 3 6 8

Answers

The number of units of NO3 present on the product side is 6.

The given reaction is:

3Cu + 8HNO3 -----> 3Cu(NO3)2 + 2NO + 4H2O

To find:

The number of units of NO3.

Solution:

The given reaction shows that three moles of copper and eight moles of nitric acid react to produce three moles of Cu(NO3)2, two moles of NO and four moles of water.

Each molecule of Cu(NO3)2 contains two units of NO3. As the number of moles of Cu(NO3)2 produced is 3, the total units of NO3 in the product side is 3 x 2 = 6.

Therefore, the correct option is 6.

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Answer: 3. 6

Explanation: to put it simply

Why open flames near to ethanol can lead to serious fires?​

Answers

[tex]\huge\bold\red{Aɴswᴇʀ}[/tex]

Ethanol is a polar solvent, a flammable liquid made of gasoline and alcohol that fully and immediately combines with water instead of separating, which is the opposite of what a firefighter attempting to knock down a car fire might expect.

Answer:

Ethanol has a high vapor pressure. Therefore, even though you may not be able to see the particles of ethanol in the air, they are there and will readily fuel a combustion reaction if an open flame is nearby


Given that the molar mass of CO₂ is 44.01 g/mol, how many liters of oxygen is required at STP to produce 88.0 g of
CO₂ from this reaction?

Answers

From the reaction, the volume of the oxygen required is 89.6 L.

What is stoichiometry?

The term stoichiometry has to do with the process by which the mass of reactants or products in a reaction is obtained from the  balanced reaction equation.

In this case, the balanced reaction is equation is;

CH₄  +  2 O₂    →    CO₂  +  2 H₂O

Number of moles of CO2 = 88.0 g/44 g/mol = 2 moles

2 moles of O2 produced 1 mole of CO2

x moles of O2 produces 2 moles of CO2

X = 4 moles

1 mole of oxygen occupies 22.4 L hence 4 moles of oxygen occupies 4 * 22.4 L = 89.6 L

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CH3CH2OH+3O2 2CO2+3H20 ( ethanol) explain this equation! if u didn't understand the wat I have written could u text in personal will sent u photo of questions​

Answers

The equation is given is of combustion of ethanol.

Fuel ethanol (C2H5OH) has high energy carbon-carbon (C-C) and carbon-hydrogen (C-H) bonds that store chemical energy. From the ethanol container, ethanol molecules evaporating, enter the flame's base. A physical action called evaporation converts liquid into gas. Ethanol evaporates with a constant molecular structure.

The molecules of ethanol and oxygen combine inside the flame and undergo a chemical transformation. Let's consider matter, or the atoms. The oxygen (O2) and ethanol (C2H5OH) molecules' atoms reorganise into carbon dioxide (CO2) and water (H2O). There are always the same number of atoms. A chemical equation may be used to demonstrate how the atoms are rearranged.

Energy is released as the atoms in the oxygen and ethanol are rearranged. When the high-energy C-C and C-H bonds in ethanol are swapped out for the low-energy H-O and C=O bonds in carbon dioxide and water, chemical energy is released as heat and light.

The ethanol and oxygen atoms are rearranged into carbon dioxide and water during burning. Water and carbon dioxide escape from the flame's top.

To conclude with we can say that the given reaction of combustion of ethanol. Ethanol with oxygen given carbon dioxide with water on reaction.

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During a chemical reaction, if the concentration of reactants and products doesn't change, the reaction has likely stopped. true false

Answers

According to the research, the correct option is false, the statement related to a chemical reaction is false.

What is a chemical reaction?

They are reactions involving two or more substances (reactants), which change significantly in the process, and can consume or release energy.

Every chemical reaction subjects matter to a chemical transformation, altering its structure and molecular composition.

Therefore, we can conclude that according to the research, the correct option is false, the statement related to a chemical reaction is false.

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As the atomic radius_______, electron affinity _______. Select the correct answer below: decreases, decreases increases, decreases increases, increases increases, stays the same

Answers

I believe the answer is increases , decreases

If 185 g of wax c22h44 burns how many litres of oxygen gas were used up .assume conditions in lab are 101kpa and 25 degree celcius

Answers

How many liters of oxygen gas were used up?

If 185 g of wax [tex]C_{22}H_{44}[/tex] burns, 13.73 L of oxygen gas is used.

An ideal gas equation is:

The macroscopic characteristics of ideal gases are related to the ideal gas law (PV = nRT). Gas is considered to be perfect if its particles (a) do not interact with one another and (b) occupy no space (have no volume).

First, determine the gas's moles using the gas law.

PV = nRT, where n is the number of moles and R is the gas constant. Next, divide.

To obtain molar mass, multiply the given mass by the number of moles.

Data provided:

P= 101kpa =0.996792 atm

V= ?

R= 0.082057338 L atm K[tex]^{1} mol^{-1}[/tex]

T=25 +273 =298 K

Moles =?

Moles = mass/molar mass = 185g/308.6

Moles =0.56

Putting value in the given equation:

PV/RT =n

0.56 = [tex]\frac{0.996792 atm XV}{0.082057338 L atm K^{1} mol^{-1} X 298}[/tex]

13.73 L =V

13.73 L of oxygen gas was used up if 185 g of [tex]C_{22}H_{44}[/tex] wax burns.

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(1) (a) In an equilibrium reaction between gases Q2 and R2 to form QR, the energy content of the reactants is 100KJ and that of the product is 54KJ. The energy content of the activated complex is 210KJ. (i) Draw an energy profile diagram for the reaction. (ii) Determine the: I. activation energy of the reaction. II. enthalpy change A H of the reaction. (iii) Write a balanced equation for the reaction. (iv) State whether the reaction is exothermic or endothermic. (v) Give a reason for the answer given in 1(a)(iv). (b) (i) If sodium reacts with cold water, state ONE observation that would be made as the reaction Proceeds. (ii) Write a balanced chemical equation for the reaction in 1(a)(i) (iii) Calculate the volume of gas produced at s.t.p if 3.0g of sodium reacts with excess water. [Molar volume of gas at s.t.p = 22.4dm³; H = 1.0, O=16.0, Na = 23.0] (c) Name ONE allotrope of oxygen.​

Answers

Answer:

a is my answer

Explanation:

EVALUATE:
Directions: For the following exercise, you will draw particle diagrams. A particle diagram uses
spheres to show atoms and how they are bonded when in elements compounds and mixtures.
A. Monoatomic particle diagrams will contain only one atom.
B. Diatomic particle diagrams contain two of the same atoms.
C. Make legends for each element/compound/mixture for each box.
D. Make at least 3 particle diagrams for each problem

Answers

The atoms present in the elements, compounds and mixtures are represented in the diagrams by spheres.

What is are elements, compounds and mixtures?

Elements are pure substances consisting of the same atoms entirely.

Compounds are formed from two or more elements chemically combined together.

Mixtures are two or more substances physically combined together.

The atoms present in the elements, compounds and mixtures are shown in the attached image.

In conclusion, atoms of the same kind are present in elements whereas atoms of different kinds are found in compounds and mixtures.

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In the reaction C+0₂ → CO₂ which element is reduced in the reaction?
O C
O 0₂
O CO₂

Answers

Answer:

O2(oxygen)

Explanation:

Reduced means the valence electrons are gained. From this equation we see in CO2, C is 4+ and for each O there's a 2-, however, originally, C and O2 are all 0, it's obvious that O is reduced from 0 to 2-

O2 would be the correct answer

A chemist conducts a titration on 50 mL of a solution of hydrobromic acid (HBr) of unknown strength. She finds the pH reaches the equivalency point with the addition of 15 mL of 0.30 M sodium hydroxide (NaOH). What is the concentration of the HBr solution?

Answers

The concentration of the HBr would be 0.09 M

What are stoichiometric problems?

First, let us look at the equation of the reaction:

[tex]HBr + NaOH --- > NaBr + H_2O[/tex]

The mole ratio of HBr to NaOH is 1:1.

Mole of 15 mL, 0.30 M NaOH = 0.30 x 15/1000 = 0.0045 moles

Equivalent mole of HBr - 0.0045 moles

Molarity of HBr = mole/volume = 0.0045/50/1000 = 0.09 M

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The activation energy of a first order reaction is 83.5kj/mol. the rate constant is 3.54x10^-5s^-1 at 45 c. what is the rate constant at 65 c?

Answers

Rate constant:

The rate constant at 65°C is [tex]k_{2} = 3.069 x 10^{-6}[/tex]

What is the Arrhenius equation?

Sometimes the Arrhenius equation is written as [tex]k = Ae^{-E/RT}[/tex], where k is the rate of the chemical reaction, A is a constant that varies depending on the chemicals involved, E is the activation energy, and R is the universal gas constant, and T is the temperature.

According to the exponential part in the Arrhenius equation, a reaction's rate constant rises exponentially as the activation energy falls. The rate also grows exponentially because the rate of a reaction is precisely proportional to its rate constant.

Calculation:

According to the Arrhenius equation for variable temperature:

[tex]ln(\frac{k2}{k1}) = - \frac{Ea}{R} (\frac{1}{T2} - \frac{1}{T1})[/tex]

The temperatures are given to be computed in kelvins and then both temperature and activation energy will be put in the above equation, we get,

[tex]ln ( \frac{k_{2}}{3.54 x 10^{-5}} ) = -\frac{89000J/mol}{8.314J (mol* K)} ( \frac{1}{338.15K} - \frac{1}{318.15K} \\ln ( \frac{k_{2}}{3.54 x 10^{-5}} ) = 2.1602\\k_{2} = 3.54 x 10^{-5} *exp(2.1602)\\k_{2} = 3.54 x 10^{-5} *8.67\\ k_{2} = 30.69 x 10^{-5}\\k_{2} = 3.069 x 10^{-6}[/tex]

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2HgO(s) 2Hg(l) + O2(g)

In a certain reaction, 4.37 g of HgO is decomposed, producing 3.21 g of Hg. What is the theoretical yield of Hg?

Answers

The theoretical yield of the Hg is 4.02 g.

What s the theoretical yield?

The theoretical yield is the yield that is obtained from the stoichiometry of the reaction.

The reaction equation is; 2HgO(s) ------> 2Hg(l) + O2(g)

Number of moles of HgO =  4.37 g/217 g/mol = 0.02 moles

Number of moles of Hg = 3.21 g/201 g/mol = 0.012 moles

Now;

Theoretical yield of Hg = 0.02 moles * 201 g/mol = 4.02 g

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The molar mass of magnesium (mg) is 24.30 g/mol. there are 6.02 times. 1023 atoms in 1 mol. how many atoms are present in 48.60 g of mg? 3.32 times. 10–24 atoms 1.96 times. 10–21 atoms 1.20 times. 1024 atoms 7.11 times. 1026 atoms

Answers

Correct option:

Number of atoms is given by option is C, i.e. [tex]1.20\times10^{24}\,atoms[/tex].

Calculation of number of atoms:

As, mole tells about the amount of substance.

Chemical units known as moles are employed to calculate the mass or molecular mass of a compound, molecule, or atom. For instance, there is one mole in 12 grams of carbon.

[tex]1 mole= 6.022\times10^{22}\,atoms/molecules/ions[/tex]

Molecular mass of Mg= 24.30 g/mol

Given weight of Mg= 48.60 g

Atoms present in 48.60 g= ?

[tex]6.022\times10^{23}= N_A[/tex](Avogadro's number)

[tex]n=\frac{m}{M}=\frac{Given\,number\,of\,atoms}{N_A}\\\\\frac{m}{M}=\frac{N}{N_A}\\\\\frac{48.60}{24.30}=\frac{N}{6.022\times 10^{23}}\\\\ N= 2\times 6.022\times10^{23}\\N= 12.044\times10^{23}\,atoms[/tex]

[tex]N= 1.2\times10^{24}\,atoms\,of\,Mg[/tex]

So, the correct option is C.

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Answer: C

Explanation: 1.20 x 10^24 atoms

Silver chloride and iron (III) nitrate are formed when silver nitrate and a compound containing iron are combined. What compound is it?

Answers

The compound that is involved in the reaction with silver nitrate to form silver chloride and iron (III) nitrate is Iron (III) chloride.

What is a displacement reaction?

The displacement reaction is the one in which the more reactive element displaces the less reactive element from the compound forming a new compound.

The formation of silver chloride and iron (III) nitrate was followed by the double displacement reaction. The silver in silver nitrate was replaced by the iron forming iron(III) nitrate, and the chloride from the Iron chloride reacted with silver forming silver chloride.

Thus, the compound that reacts with Silver nitrate in the double displacement reaction is Iron(III) chloride.

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what are all of the mole ratios in acetic acid

Answers

The mole ratio between sodium bicarbonate and that of acetic acid is 1:1

What is mole ratio?

A mole ratio can be defined as that ratio in whole numbers between the amounts in moles of any two compounds involved in a balanced chemical reaction.

The mole ratio of each individual element is found by dividing the number of moles of each by the smallest number of moles.

In conclusion, the mole ratio between sodium bicarbonate and that of acetic acid is 1:1

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A balloon with a volume of 2.0 l at 25°c is placed in a hot room at 35°c. the pressure on the balloon is constant at 1.0 atm. formula to use: v1 t1 = v2 t2 how does the volume of the balloon change after moving it to the hot room?

Answers

The volume increases and the final volume is 2.1 L

Why volume increases?

The volume of a gas is directly related to the heat and pressure. If temperature increases, volume increases.

If pressure increases, volume decreases

Based on Boyle's law,

The absolute temperature of a gas is directly proportional to the volume of the gas.

As the balloon change increases its temperature, the volume increases

The Boyle's equation is:

V₁T₂ = V₂T₁

Where,

V is volume T is absolute temperature of 1, initial state and 2, final state of the gas.

Replacing :

V₁ = 2.0L

T₂ = 35°C + 273.15 = 308.15K

V₂ = ?

T₁ = 25°C + 273.15 = 298.15 K

2.0L x 308.15 K = V₂ x 298.15 K

2.1 L = V₂

Final volume is 2.1L

Hence, The volume increases and the final volume is 2.1 L

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Answer:

increases, 2.1

Explanation:

I got it right.

A compound was decomposed and determined to be 51.27 % C, 7.75 % H and 40.98 % O by mass. What is the subscript for H in the empirical formula for this compound?

Answers

The subscript for H in the empirical formula for this compound is 3.

There are 3 steps involved in the construction of empirical formula.

Calculation of empirical formula is as under as ...

Step 1: Divide the % of each atoms which their atomic weights.

 C = 51.27 / 12 = 4.27

 H = 7.75 / 1 = 7.75

 O = 40.98 / 16 =2.56

Step 2 : Divide all the answers with the smallest answer to get the subscripts for empirical formula.

C = 4.27/ 2.56 ≈ 2

H = 7.75/ 2.56 ≈ 3

O = 2.56 /2.56 = 1

Step 3: Construction of empirical formula by putting subscripts calculated in step 2.

Empirical formula form given data = [tex]C_{2} H_{3} O_{1}[/tex]

Thus , subscript for H in the empirical formula for this compound is 3.

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what are mettaloids? ​

Answers

Answer:

Los metaloides serían los elementos con propiedades intermedias. No existe una definición estandarizada de elemento metaloide ni un consenso completo sobre los elementos que son metaloides. A pesar de la falta de especificidad en el término, es muy utilizado en los textos químicos, tanto educativos como divulgativos o de investigación.

Explanation:

Which of the following mixtures could be
separated using distillation? Select all that
apply.
a. A solution of rubbing alcohol and water.
b. A solution of salt and water.
c. A solution of sugar and water.
d. An alloy of copper and gold.

Answers

Answer:

c

Explanation:

sugar and water are soluble hence can be separated using distillation

When a neon atom is electrified, electrons jump to higher orbits. One of the electrons falls from an outside orbit to an inside orbit, giving off red light with a wavelength of 6.34 x 10^–7m. Calculate the frequency of the red light given off by the neon atom.


Find the energy of a photon of light if the wavelength of the light wave is 4.65 x 10^–7m.


An automobile has a wavelength that is not measurable by human standards. If the car has a mass of 2000 lbs (905 kg) and travels at 30 miles/hr (26.8 m/s), calculate the wavelength of the car.


A local radio station can be tuned in by dialing your radio to a frequency of 1175 kHz. Calculate the energy of the wave. (Hint: kHz means 1 x 10^3 Hz.)

An element has an electron configuration that ends in 5d^4. Which column is it in?

Answers

If an element has an electron configuration that ends in 5d^4, it is found in column 6 of the periodic table.

What is energy level?

The energy level refers to the position where an electron is found in the atom. If the electron moves from a higher to a lower energy level, energy is evolved as light.

Now;

v = λf

f = v/λ

f = 3 * 10^8 m/s/6.34 x 10^–7m

f = 4.7 * 10^14 Hz

From E = hc/λ

E = 6.6 * 10^-34 * 3 * 10^8/4.65 x 10^–7m

E = 4.3 * 10^-19 J

From;

λ = h/mv

λ =  6.6 * 10^-34Js/905 kg * 26.8 m/s

λ =  2.27 * 10^-38 m

Given that;

E = hf

E = 6.6 * 10^-34Js * 1175  x 10^3 Hz

E = 7.8 * 10^-28 J

If an element has an electron configuration that ends in 5d^4, it is found in column 6 of the periodic table.

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X forms an ionic compound with the formula
XCI, which has an M, of 74.5. What is the M₁ of
the oxide of X?
A 55
B 71
C 87
D 94

Answers

Answer:

94 g/mole

Explanation:

The following answer assumes M is molar mass (g/mole):

One mole of Cl is 35.45 grams.  Since 1 mole of MCl is 74.5 grams, one mole of M will be (74.5-35.45 = ) 39.05 grams/mole.  This just so happens to be the molar mass of potassium, K.  That would mean the compound could be KCl.

We learn from this that M has a single bond.  The oxide of M must take into account the fact that oxygen makes 2 bonds per atom.  That would mean that M ocxide would have the formula M2O.  There are two M's per O.  

M2O would have a molar mass of (2x39.05) + 16 = 94.1 g/mole

A silicon atom has four unpaired electrons in its valence shell, two paired electrons in its inner shell, and 14 electrons in all. How many hydrogens will it form covalent bonds with

Answers

A silicon atom has four unpaired electrons in its valence shell, two paired electrons in its inner shell, and 14 electrons in all. There are 4 hydrogens it will form covalent bonds with.

A Silicon Atomic Description

The four electrons that make up the "valence" energy level's outermost orbit of the nucleus are given to, taken from, or shared by other atoms. Dependent on their energy level, the electrons orbit the nucleus at various distances. As an illustration, an electron with lower energy would orbit towards the nucleus, whereas an electron with higher energy would orbit farther away. The interaction between the electrons of nearby atoms and those that are the farthest from the nucleus determines how solid structures are created.

crystalline silicon's uses

The first practical PV devices were made of crystalline silicon, which is still the most used PV material in use today. Grasp how the PV effect functions in crystalline silicon provide us a fundamental understanding of how it functions in all devices, even though various PV materials and designs utilize the effect in slightly different ways.

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Calculate the number of milliliters of 0.444 M required to precipitate all of the ions in 107 mL of 0.699 M solution as . The equation for the reaction is:

Answers

333.3 milliliters of 0.444 M KOH required to precipitate all of the Pb⁺² ions in 107 mL of 0.699 M Pb(NO₃)₂ solution as Pb(OH)₂.

What is Stoichiometry ?

Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.

What is Molarity ?

Molarity (M) is defined as the number of moles of solute dissolved in 1L of solution. Molarity is also known as Molar Concentration. The S.I unit of Molarity is molar (M) or mol/L.

Molarity = [tex]\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}[/tex]

Now put the values in above formula to find the number of moles of Pb(NO₃)₂

Molarity = [tex]\frac{\text{Moles of}\ Pb(NO_{3})_2}{\text{Volume of solution (in L)}}[/tex]

Moles of Pb(NO₃)₂ = Molarity × Volume

                               = 0.699M × 0.107 L       [1ml = 0.001 L]

                               = 0.074 moles

The given balanced chemical equation is

Pb(NO₃)₂(aq) + 2 KOH(aq) → Pb(OH)₂(s) + 2 KNO₃(aq)

The mole ratio of KOH to Pb(NO₃)₂ is 2:1.

The mole of KOH = 0.074 mol × 2

                             = 0.148 moles

Now put the value in above formula to find the volume of KOH  

Molarity = [tex]\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}[/tex]

Volume of KOH = [tex]\frac{\text{Number of mole of KOH}}{\text{Molarity}}[/tex]

Volume of KOH =  [tex]\frac{0.148\ mol}{0.444\ M}[/tex]

                          = 0.333 L

                          = 333.3 mL     [1L = 1000 mL]

Thus from the above conclusion we can say that 333.3 milliliters of 0.444 M KOH required to precipitate all of the Pb⁺² ions in 107 mL of 0.699 M Pb(NO₃)₂ solution as Pb(OH)₂.

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Question: Calculate the number of milliliters of 0.444 M KOH required to precipitate all of the Pb⁺² ions in 107 mL of 0.699 M Pb(NO₃)₂ solution as Pb(OH)₂. The equation for the reaction is:

Pb(NO₃)₂(aq) + 2 KOH(aq) → Pb(OH)₂(s) + 2 KNO₃(aq)

_________ mL KOH.

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