A gardener has a rectangle garden with an area of 374 yd.²The length of the garden is 17 yards the gardener wants to enlarge the garden by doubling only the width of the current garden how much fencing will the gardener need to enclose a new garden?

Answer:

d

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

like the guy above me said

Answer:

d

Step-by-step explanation:

d

Answer:

70

Step-by-step explanation:

180-80-30=70

Answer:

$3.75

Step-by-step explanation:

Answer:

3/4 cups

Step-by-step explanation:

Adding the fractions

1/4 + 1/2 + 1/4 + 3/4 + 1 + 1 1/2 + 1/2 + 1 3/4 + 1/2 + 1/2

And the the L.C.M to be 4

=30/4

=15/2

Mean = 15/2 ÷ 10

=15/2 × 1/10

3/4

Answer:

well you answered the question in your question: you have Area = 136 square units. How you got it, you need to be more specific. Maybe it's because the side lengths are 2 * 68 for example. If anything provide more info. tried to help the best I can

Step-by-step explanation:

Answer:

7x+3=8x+1[corresponding angle are equal]

3-1=8x-7x

x=2 is a required answer.

Answer:

[tex]7x + 3 = 8x + 1[/tex]

[tex]x = 2[/tex]

Answer:

No

Step-by-step explanation:

(0, 0) Is not a answer because ithe point does not fall within the shaded area

Answer:

n= 12     m=5

Step-by-step explanation:

Because it is a parallelogram, the parallel sides are equal in length.  So n = side length 12.  n = 12

For the other one, m + 1 = 6

Be careful to solve for m, not m+1.

m=6-1

m=5

Answer:

--------------------------

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]=\frac{2-1}{0-3}[/tex]

[tex]=1/-3[/tex]

[tex]y-y_1=m(x-x_1)[/tex]

[tex]y-1=-1/3(x-3)[/tex]

[tex]y-1=-1/3x+1[/tex]

[tex]y=-1/3x+2[/tex]

--------------------

hope it helps...

have a great day!!

Answer:

Option (2)

Step-by-step explanation:

Given geometric sequence is,

2, 5, 12.5, 31.25, 78.125......

First term = a₁ = 2

Common ratio of the sequence = r = [tex]\frac{5}{2}[/tex]

                                                          = 2.5

Recursive formula of a geometric sequence is given by,

[tex]a_n=a_{n-1}(r)[/tex]

Here, [tex]a_n=[/tex] nth term of the sequence

[tex]a_{n-1}=[/tex] (n - 1)th term

r = common ratio

Therefore, recursive formula for the given sequence will be,

[tex]a_1=2[/tex]

[tex]a_n=a_{n-1}(2.5)[/tex]

Explicit formula of a geometric sequence is given by,

[tex]a_n=a_1(r)^{n-1}[/tex]

Therefore, explicit formula of the sequence will be,

[tex]a_n=2(2.5)^{n-1}[/tex]

Option (2) will be the correct option.

Answer: C. 25.6

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given,

Vertex (h, k ) = (1,0)

Now,

We know,

f(x) = a(x-h)²+k

Since, it passess through (2, −17)

Put x = 2 and  y = - 17

or, -17 = a(2 - 1)² + 0

or, -17 = a

Now,

f(x) = a(x - h)² + k

     = -17(x - 1)² + 0

     = -17x² + 34x - 17

X=-1

no problem, lllllllllllollllllllll

Answer:

Radius = 11.85yd

Step-by-step explanation:

Volume of a Cone formula: V = πr²(h/3)

We know that;

V = Volume

r = radius

π = pi (this is a sign located on your calculator)

h = height

We are given that;

V = 4,410

r = unknown

h = 30

Let's substitute the values in:

=> V = πr²(h/3)

=> 4,410 = πr²(30/3)

=> 4,410 = πr²(10)

=> 4,410 / 10 = πr²

=> 441 = πr²

=> 441 / π = r²

=> 140.37 = r²

=> [tex]\sqrt{140.37}[/tex] = r

=> 11.85 = r

Therefore, the radius of the cone = 11.85yd

Hope this helps!

Answer:

The angle SQR is half the intercepted arc SR which is 43°

Answer:

18

Step-by-step explanation:

f(x) = x³+4x²-8x-6

P(a) <=> P(x)

-2 | 1 4 -8 -6

|

| -2 -4 24

----------------------------

1 2 -12 18

The exact value of cot A will be 0.857.

The connection between the lengths and angles of a triangular shape is the subject of trigonometry.

The co-secant of angle A is √85 / 6. And that angle A is in Quadrant I.

Then the value of angle A will be

csc A = √85 / 6

1 / cos A = √85 / 6

cos A = 6 / √85

A = 49.4°

Then the exact value of cot A will be

cot A = cot 49.4°

cot A = 0.857

The exact value of cot A will be 0.857.

More about the trigonometry link is given below.

https://brainly.com/question/22698523

#SPJ2

Answer:

[tex]6[/tex]

[tex]16[/tex]

Step-by-step explanation:

[tex] \frac{x}{12} + \frac{y}{3} = 2[/tex]

[tex] \frac{y}{3 } = 2 - \frac{x}{12} [/tex]

[tex]y = 3( 2 - \frac{x}{12} )[/tex]

[tex]y = 6 - \frac{x}{4} [/tex]

[tex]y = - \frac{x}{4} + 6[/tex]

[tex] {x}^{2} - 8x + c[/tex]

[tex] {x}^{2} + c - 18[/tex]

To find the c value ,

[tex]c = ( \frac{b}{2} {)}^{2} [/tex]

divide the coefficient of x by 2 and square the result.

[tex]( - 1 \times 4 {)}^{2} [/tex]

[tex]( - 4 {)}^{2} [/tex]

[tex]16[/tex]

Answer:

The required solution: (a, u) = (5, [tex]\frac{35}{2}[/tex])

Step-by-step explanation:

Answer: [tex]75.47\ ft[/tex]

Step-by-step explanation:

Given

String of the kite is [tex]l=100\ ft[/tex]

Angle of elevation [tex]\theta=49^{\circ}[/tex]

suppose altitude of the kite is h

from the figure, we can write

[tex]\Rightarrow \sin 49^{\circ}=\dfrac{h}{100}\\\\\Rightarrow h=100\sin 49^{\circ}\\\\\Rightarrow h=75.47\ ft[/tex]

Thus, the altitude of the kite is [tex]75.47\ ft[/tex]

Answer:

a=1; b=14

Step-by-step explanation:

you have to form a perfect square

(a+b)²=a²+b²+2ab

If you add a one you will get a perfect square

x²+2x+1 = (x+1)²

if you added a one in one side you have to added to the other side too

(x+1)² = 13+1

(x+1)² = 14

Answer:

a = 1, b = 14

Step-by-step explanation:

To complete the square

add ( half the coefficient of the x- term)² to both sides , that is

x² + 2(1)x + 1 = 13 + 1

(x + 1)² = 14

with a = 1 and b = 14

1,873

Step-by-step explanation:

Answer:

[tex]p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }[/tex]

g(t) = 0

And

The differential equation [tex]9ty + e^{t}y' = \frac{y}{t^{2} + 81 }[/tex] is  linear and homogeneous

Step-by-step explanation:

Given that,

The differential equation is -

[tex]9ty + e^{t}y' = \frac{y}{t^{2} + 81 }[/tex]

[tex]e^{t}y' + (9t - \frac{1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t(t^{2} + 81 ) - 1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t^{3} + 729t - 1}{t^{2} + 81 } )y = 0\\y' + [\frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) } ]y = 0[/tex]

By comparing with y′+p(t)y=g(t), we get

[tex]p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }[/tex]

g(t) = 0

And

The differential equation [tex]9ty + e^{t}y' = \frac{y}{t^{2} + 81 }[/tex] is  linear and homogeneous.