A frequency generator sends a 550Hz sound wave through both water and ice. What is the difference in wavelength between the wave produced in ice and the wave produced in water?

A Frequency Generator Sends A 550Hz Sound Wave Through Both Water And Ice. What Is The Difference In

Answers

Answer 1

Answer:

3.1

Explanation:

use formula f = v/lambda


Related Questions

Yellow light shines on a sheet of paper containing a blue pigment. Determine the appearance of the paper.

I dont need google answers if i get google answers i will delete it

Answers

Black I think

this is due to the fact that blue lights only reflect blue things so if yellow is shone on it it will reflect black appearance.

how it useful

Which is the largest gas that occurs in our atmosphere?
Helium
Nitrogen
Other Gases
Oxygen

Answers

Answer:

OXYGEN

Explanation:brainlyist me

Answer:

Nitrogen

Explanation:

Oxygen is second

How was the Periodic Table of Elements developed and how are the elements arranged on it?

Answers

Answer:

In 1869 Russian chemist Dimitri Mendeleev started the development of the periodic table, arranging chemical elements by atomic mass. He predicted the discovery of other elements, and left spaces open in his periodic table for them.

Explanation:

Answer: Mendeleev first published a table of elements arranged according to increasing atomic masses. He noticed that some elements near each other had differing properties, but elements in vertical columns had similar properties. Moseley then rearranged the table according to atomic numbers and this eliminated the discrepancies found in Mendeleev’s attempt. Today’s version of the periodic table displays elements in order based on their atomic number; the atomic number indicates the number of protons within the atoms of a particular element. Rows are called periods and columns are called groups. Elements in the same group have similar properties. Elements are grouped into nine categories: noble gases, halogens, nonmetals, alkali metals, alkaline earth metals, transition metals, other metals, metalloids, and rare earth elements.

A 1.00-m3 object floats in water with 30.0% of its volume above the waterline. What does the object weigh out of the water?

Answers

Answer:

Object's weight = 6,839.42 N

Explanation:

Given

Above waterline = 30%

Volume of object = 1m^3

Required

Determine the weight of the object

First, we need to calculate its Mass

Mass = Density of Water * Volume of object in water

Density of water = 997kg/m³

If 30% is above waterline, then 70% is in water.

So:

Mass = Density of Water * Volume of object in water

Mass = 997kg/m³ * 70%m³

Mass = 997kg * 70%

Mass = 697.9 kg

The object weight sis then calculated as thus:

Weight = Mass * Acceleration of gravity

Weight = 697.9 kg * 9.8m/s²

Weight = 6 839.42 N

PLEASE HELP!

I don't even know what Science is I'm so dumb lol XD

Answers

Answer:

C

Explanation:

Sled A has more potential energy because it's mass is 100 kg, and it is higher up than Sled B. The more high up the sled is and the lighter it is, the faster it gets, it creates more and more potential energy.

Hope this helps!

One of the harmonics of a column of air in a tube that is open at both ends has a frequency of 448 Hz, and the next higher harmonic has a frequency of 576 Hz. What is the fundamental frequency of the air column in this tube?

Answers

Answer:

The fundamental frequency is  [tex]f_1 =128 \ Hz[/tex]

Explanation:

From the question we are told that

   The frequency of one harmonics is  [tex]f_x= 448 \ Hz[/tex]

    The next higher harmonic is  [tex]f_z = 576 \ Hz[/tex]

Generally the frequency of an air column open at both ends is mathematically represented as

              [tex]f_n = \frac{nv }{ 2 L }[/tex]

Here n  is the order of the harmonics (frequency)

        v is the velocity of the sound

        L  is the length of the column

So for one harmonics we have that

        [tex]f_k = \frac{n v }{2L}[/tex]

Then for the next higher harmonics

       [tex]f_x = \frac{n+1 ) v}{2 L }[/tex]

Generally the difference between these frequencies is mathematically represented as  

       [tex]f_z- f_x = \frac{(n+1 )v}{ 2L} - \frac{(n )v}{ 2L}[/tex]

=>    [tex]576 - 448 = \frac{vn + v - nv }{2L}[/tex]

=>    [tex]\frac{ v }{2L} = 128[/tex]

Generally for fundamental  frequency n =  1

So  

       [tex]f_1 = n * \frac{v}{2L}[/tex]

So

       [tex]f_1 =1 * 128[/tex]

=>    [tex]f_1 =128 \ Hz[/tex]

What is the acceleration of the the object during the first 4 seconds?

Answers

Answer:

Velocity (m/s) over time (s) graph

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

a = Δv/ Δta=Δv/Δta, equals, Δ, v, slash, Δ, t

a = (15 m/s - 0 m/s) / 0.2 seconds

a = 15 m/s / 0.2 seconds

a = 75 m/s / second

Explanation:

What this formula is telling us is that if we know the acceleration of an object, and the ... we can plug in our acceleration of 12.5 m/s2 for a, and 4 seconds for t.

Velocity (m/s) over time (s) graph

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

a = Δv/ Δta=Δv/Δta, equals, Δ, v, slash, Δ, t

a = (15 m/s - 0 m/s) / 0.2 seconds

a = 15 m/s / 0.2 seconds

a = 75 m/s / second

What would have to be the self-inductance of a solenoid for it to store 10.2J of energy when a 1.20A current runs through it?

Answers

Answer:

14.17H

Explanation:

Energy stored in an inductor is expressed as;

E = 1/2LI²

L is the inductance of the inductor

I is the current flowing through the inductor

Given

E = 10.2J

I = 1.20

Required

Inductance L

Substitute the given parameters into the formula;

10.2 = 1/2L(1.2)²

10.2 = 1/2*1.44L

10.2 = 0.72L

L = 10.2/0.72

L = 14.17H

Hence the self inductance of the solenoid is 14.17H

The current theory of the structure of the
Earth, called plate tectonics, tells us that the
continents are in constant motion.
Assume that the North American continent
can be represented by a slab of rock 5200 km
on a side and 35 km deep and that the rock
has an average mass density of 2700 kg/m².
The continent is moving at the rate of about
3.8 cm/year.
What is the mass of the continent?
Answer in units of kg.

Answers

Answer:

pt 1: [tex]m=1.66698*10^{21} kg[/tex]

Pt 2: [tex]KE=1212.23531 J[/tex]

Explanation:

Information Given: (p = density)

l = 5200km  d = 35km p = 2700kg/[tex]m^{2}[/tex]

Part 1: Mass

Find volume [tex]V=(l)^2(d)[/tex][tex]V=(4.2*10^6)^2(35*10^3)[/tex][tex]V=61.74*10^{16}[/tex]Find Mass[tex]m=Vp[/tex][tex]m=(61.74*10^{16})(2700)[/tex][tex]m=1.66698*10^{21}[/tex]

Part 2: Kinetic Energy

[tex]v=\frac{3.8cm}{yr}*\frac{m}{100cm}*\frac{yr}{365d}*\frac{d}{24hr}*\frac{hr}{3600s}[/tex][tex]v=1.20497*10^{-9}[/tex]

[tex]KE=\frac{1}{2}mv^2[/tex]

[tex]KE=\frac{1}{2} (1.66698*10^{21})(1.20497*10^{-9})^2[/tex]

[tex]KE=1212.23531 J[/tex]

Part 3: Jogger Speed

set up, because I don't have the mass :(

Information given:

[tex]KE_{jogger}[/tex]

[tex]KE=\frac{1}{2}mv^2[/tex][tex]v_{jogger} =\sqrt{\frac{2KE}{m_{jogger} } }[/tex]Input the values

Hope it helps :)

if chilled coke and hot tea are
kept together tea cools down but ko gets warm why

Answers

Tea gets cool beacuse of heat tranfer through convenction
Heat transfers from a area of hot region to cold.
The tea is hot in this case, due to taht factor the heat will move towards teh cooler region which is coke and will make the coke warm


Hope this helped!

What do light and energy tell us about the universe?

need a paragraph

Answers

because we can only see light..everything we learn about the universe comes from the info we get from light, different events happening on earth, in the sun, and in the universe at large emir light at different energies the energy of this light tells us about the what is happening !

A diffraction grating with 68 slits per cm is used to measure the wavelengths emitted by hydrogen gas.
A. At what angles in the fourth-order spectrum would you expect to find the two violet lines of wavelength 434 nm and of wavelength 410 nm?
B. What are the angles if the grating has 12,800 slits per cm?

Answers

Answer:

a

  [tex]\theta _1 =0.687 ^o[/tex]

  [tex]\theta _2 =0.630 ^o[/tex]

b

 Generally given that the domain arcsine function is  between -1 and 1 then the arcsine of 2.22 will not be valid

Generally given that the domain arcsine function is  between -1 and 1 then the arcsine of 2.1 will not be valid

Explanation:

From the question we are told that

     The slit grating is  [tex]N = 68 \ slits / cm = 6800 \ slits / m[/tex]

      The order of spectrum is [tex]n = 4[/tex]

Generally the width of the slit is mathematically represented as  

               [tex]a = \frac{1}{ 6800}[/tex]      

=>            [tex]a = 0.000147 \ m[/tex]  

Generally the condition for constructive interference is

              [tex]asin\theta = n * \lambda[/tex]

Now for the first wavelength the angle is evaluated as

             [tex]\theta _1 = sin ^{-1} [ \frac{n \lambda_1 }{a} ][/tex]

    =>     [tex]\theta _1 = sin ^{-1} [ \frac{4* 434 *10^{-9} }{ 0.000147 } ][/tex]

    =>    [tex]\theta _1 =0.687 ^o[/tex]

Now for the second wavelength the angle is evaluated as

             [tex]\theta _2 = sin ^{-1} [ \frac{n \lambda_2 }{a} ][/tex]

    =>     [tex]\theta _2 = sin ^{-1} [ \frac{4* 410 *10^{-9} }{ 0.000147 } ][/tex]

    =>    [tex]\theta _2 =0.630 ^o[/tex]

Gnerally if grating is   [tex]N = 12800 \ slits per cm = 1280000 \ slits / m[/tex]

Generally the width of the slit is mathematically represented as  

               [tex]a = \frac{1}{ 1280000}[/tex]      

=>            [tex]a = 7.813 *10^{-7} \ m[/tex]  

Generally the condition for constructive interference is

              [tex]asin\theta = n * \lambda[/tex]

Now for the first wavelength the angle is evaluated as

             [tex]\theta _1 = sin ^{-1} [ \frac{n \lambda_1 }{a} ][/tex]

            [tex]\theta _1 = sin ^{-1} [ \frac{4* 434 *10^{-9} }{ 7.813*10^{-7} } ][/tex]

    =>     [tex]\theta _1 = sin ^{-1} [ 2.22][/tex]

Generally given that the domain arcsine function is  between -1 and 1 then the arcsine of 2.22 will not be valid

    =>    [tex]\theta _1 =0.687 ^o[/tex]

Now for the second wavelength the angle is evaluated as

             [tex]\theta _2 = sin ^{-1} [ \frac{n \lambda_2 }{a} ][/tex]

    =>     [tex]\theta _2 = sin ^{-1} [ \frac{4* 410 *10^{-9} }{ 7.813*10^{-7} } ][/tex]

     =>  [tex]\theta _2 = sin ^{-1} [2.1 ][/tex]

Generally given that the domain arcsine function is  between -1 and 1 then the arcsine of 2.22 will not be valid

What is an easy way to encourage students to stay hydrated?

Let them know hydration improves performance.
Encourage them to drink water between each class.
Tell them to drink 8 glasses of water per day.
Have them track their hydration with a "water diary."

Answers

An easy way to encourage students to stay hydrated is to let them know hydration improves performance.

Drinking water is essential for our body system to function well. It helps in the regulation of the body temperature, the prevention of infections, as well as the delivery of nutrients to different parts of the body.

Staying hydrated is also vital in getting enough sleep and keeps the body in shape.

Read related link on:

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Pushes and pulls that result from objects that are physically touching
each other

Answers

The answer: A force




Explanation: I looked it up












Answer:

That is false. Take a look at this way. You can push a ball with your own breath, you just need to blow it. And you can pull something from afar with a magnet. It is possible to do both.

Explanation:

Not all physical things can be done only physically. Like I just said, it is possible to use other forces (no, not the dark side one),  such as a magnetic force, displayed by a magnet or anything with a force like so.

Which of these statements is true about the International Space Station in orbit around the earth?
A) The space station exerts a force on the earth toward the space station.
B) The force of gravity produces the same acceleration for the earth and the space station. C) There is no gravity acting at the height of the space station.
D)The earth's gravity acts on the space station, but not the reverse.​

Answers

Answer: b is probly correct  beacuse all the others make no sence

The statement that is true about international space station is The force of gravity produces the same acceleration for the earth and the space station.

What is international space station?.

International space station is a space station that is located at the lower part of the Earth's orbit . It is the third largest space object in the space and it is a multinational project that involves five different space agencies are NASA, Roscosmos, JAXA, ESA, and CSA.

Therefore, The statement that is true about international space station is The force of gravity produces the same acceleration for the earth and the space station.

Learn more about international space station below.

https://brainly.com/question/12564840

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Initial velocity of a car is 36 km/hr. Find the distance after one min, if it goes with acceleration 2m/s².

[A] 4000 m.
[B] 4200 m.
[C] 4400 m.
[D] 4600 m.​

Answers

Answer:

[tex]\bf\pink{4200\:m}[/tex]

Explanation:

Given :-[tex]\sf\red{ Initial \ velocity = 36km/hr = 10m/s}[/tex][tex]\sf\orange{ Acceleration = 2m/s^{2}}[/tex][tex]\sf\green{Time = 1\:min = 60\: sec}[/tex]

To Find :-[tex]\sf\blue{Distance \: Travelled}[/tex]

Formula used :-[tex]\sf\purple{s = ut + \dfrac{1}{2} at^{2}}[/tex]

Where,

s = [tex]\bold{Distance}[/tex]t = [tex]\bold{Time }[/tex]u = [tex]\bold{ Initial \ velocity}[/tex]a = [tex]\bodl{Acceleration}[/tex]

Solution :-

[tex]\Rightarrow\:\:\rm{s = 10(60) + \dfrac{1}{\cancel{2}} \times \cancel{2} \times (60)^{2}}[/tex]

[tex]\Rightarrow\:\:\rm{s = 600+60\times 60}[/tex]

[tex]\Rightarrow\:\:\rm{s = 600 + 3600}[/tex]

[tex]\Rightarrow\:\:\rm{s = {\bf{\red{4200\:m}}}}[/tex]

Hence, [tex]\bf\green{(B)}[/tex] is the correct option
B)4200m. Is the correct answer

How does reflection differ from refraction and diffraction?


Reflection is the only process in which the wave does not continue moving forward.

Reflection is the only process in which the wave slows down.

Reflection is the only process that involves a change in the wave.

Reflection is the only process that changes the direction of a wave.

Answers

Answer: Reflection is the only process in which the wave does not continue moving forward.

Explanation:

Reflection is a process in which the direction of the wave changes when it is exposed to a bounce off barrier. Refraction can be defined as the change in the direction of the wave when the wave passes through one medium to another. Diffraction is a process in which the direction of the wave changes when the wave passes through a particular opening near the barrier.

Answer:

Reflection is the only process in which the wave does not continue moving forward.

Explanation:

friction reduces air resistance?

Answers

Answer:no

Explanation:

No.....................................

Forces of 70 N at 130 degrees, and 20 N at an angle of 280 degrees, measured counter-clockwise from the positive x-axis, act on an object.
A. What are the components (F1x, F1y) of the first force force (in Newtons)?
B. What are the components (F2x, F2y) of the second force force (in Newtons)?
C. What are the components (Fx, Fy) of the resultant force (in Newtons)?
D. What is the magnitude of the resultant force (in Newtons)?
E. What is the angle of the resultant force with respect to x-axis?

Answers

Answer:

A. ) F₁ₓ = -45.0 N F₁y = 53.6 N

B.)  F₂ₓ = 3.48 N F₂y = -19.7 N

C.)  Fₓ = -41.5 N Fy = 33.9 N

D)  F = 53.6 N

E)  θ = -39. 2º (320.8º)

Explanation:

A)

Applying simple trig, like definitions of cos and sin of an angle, we can get the x- and y- components of F₁, as follows:

       [tex]F_{x1} = F_{1} * cos (130) = 70 N * cos (130) = -45 N (1)\\F_{y1} = F_{1} * sin (130) = 70 N * sin (130) = 53.6 N (2)[/tex]

B)

Repeating for F₂:

       [tex]F_{x2} = F_{2} * cos (280) = 20 N * cos (280) = 3.48 N (3)\\F_{y2} = F_{2} * sin (280) = 20 N * sin (280) = -19.7 N (4)[/tex]

C)  

The x- and y- components of the resultant force, are just the algebraic

        sum of the x- and - y components of F₁ and F₂:

Fₓ = Fₓ₁ + Fₓ₂ = -45 N + 3.48 N =  -41.5 N (5)By the same token, Fy can be written as follows:Fy = Fy₁ + Fy₂ = 53.6 N + (-19.7 N) = 33.9 N (6)

D)

The magnitude of the resultant force can be obtained applying the Pythagorean Theorem to Fx and Fy, as follows:

       [tex]F_{t} =\sqrt{F_{x} ^{2} + F_{y} ^{2} } = \sqrt{(-41.5N)^{2} +(33.9N)^{2}} = 53.6 N (7)[/tex]

E)

Finally the angle regarding the x- axis of the resultant force vector, can be obtained using the definition of the tangent of an angle, as follows:

       [tex]\theta = arc tg \frac{33.9N}{(-41.5N)} = arc tg (-0.817) = -39. 2 \deg[/tex]

examples of sound to radiant energy

Answers

Answer:

Examples of Radiant Energy All Around You

The term radiant energy refers to energy that travels by waves or particles, particularly electromagnetic radiation such as heat or x-rays. Radiant energy is created through electromagnetic waves and was discovered in 1885 by Sir William Crookes. Fields in which this terminology is most often used are telecommunications, heating, radiometry, lighting, and in terms of energy created from the sun. Radiant energy is measured in joules.

Everyday Examples of Radiant Energy

Virtually anything that has a temperature gives off radiant energy. Some examples of radiant energy include:

•The heat emitted from a campfire

•Emission of heat from a hot sidewalk

•X-rays give off radiant energy

•Microwaves utilize radiant energy

•Space heaters produce radiant energy

•Heat created by the body can be radiant energy

•Lighting fixtures

√Home heating units

•Fixtures that convert solar energy to heat

•Visible light

•Gamma rays

•Radio waves

•Electricity

•A surface heated by the sun converts the energy of the light into infrared energy which is a form of radiant energy

•Cell phones utilize radiant energy to function

•Magnetic motor generators that utilize •neodymium magnets create radiant energy

•Audio signals that come to home or cars via radio waves

•Ultraviolet light

√Infrared radiation

•The light emitted from a campfire

•The light generated from a light bulb

•A heated brake disc giving off heat

•The heat from a grill used for cooking

•Water can reflect or absorb radiant energy

•Soil can absorb radiant energy

•Light from the sun

•Heat emitted from a bunsen burner

•Heat from an overused computer

•Heat caused by friction

•Heat emitted from a dryer

•The heat generated by a light bulb

•Heat generated through reflection of visible light

•A window reflects radiant energy

Heat created from a stove or oven

•Heat emitted from a washing machine

What does the phrase “constant velocity” indicate?

a. zero distance
b. zero acceleration
c. constant acceleration
d. deceleration

Answers

The answer is C is the velocity is the same then the acceleration is also the same.

How long must you wait (in half-lives) for a radioactive sample to drop to 2.10 % of its original activity?

Answers

Answer:

222/88 Ra

Explanation:

We have to wait 5.57 half lives for a radioactive sample to drop to 2.10 % of its original activity.

To find the tike taken for the activity, we need to know about radioactivity and half-life.

What is radioactivity?Radioactivity is the rate of decay of a radioactive substance with respect to time. Mathematically, radioactivity is given as

                R=R₀e^(-λ×t)

From the above expression time is given as

                 t= 1/λ ln(R₀/R)

What is half-life?Half-life is the time taken for decay of radioactive sample to half of its initial value. Mathematically, half-life= ln2 / λWhat is the expression of time of activity in term of half-life?From the half-life expression, 1/λ=half-life/ln2.Putting the value of 1/λ in the expression of time of activity, we have

    t=(half-life/ln2)×ln(R₀/R)

What is the time for radioactive sample to drop to 2.10 % of its original activity?

Here R=0.021R₀, so t= (half-life/ln2)×ln(R₀/0.021R₀)=5.57 half-lives

Thus, we can conclude that we have to wait 5.57 half lives for a radioactive sample to drop to 2.10 % of its original activity.

Learn more about radioactivity here:

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A fish swims to a depth of 50.00 meters in the ocean. Assuming the density of sea water is 1.0251.025 g·cm^{-3}g⋅cm −3 , calculate how much water pressure the fish is experiencing at this depth in units of kPa.

Answers

Answer:

The fish is experiencing a water pressure of 502.8 kPa.

Explanation:

The water pressure the fish is experiencing can be found as follows:

[tex]P = \rho gh[/tex]  (1)

Where:

g: is the gravity = 9.81 m/s²

h: is the height (depth) = 50.0 m

ρ: is the seawater's density = 1.025 g/cm³  

By replacing the above values into equation (1) we have:

[tex] P = \rho gh = 1.025 \frac{g}{cm^{3}}*\frac{1 kg}{1000 g}*\frac{(100cm)^{3}}{1 m^{3}}*9.81 m/s^{2}*50.0 m = 502.8 kPa [/tex]        

Therefore, the fish is experiencing a water pressure of 502.8 kPa.

I hope it helps you!        

A certain heat engine does 30.2 kJ of work and dissipates 9.14 kJ of waste heat in a cyclical process.
A) What was the heat input to this engine?
B) What was its efficiency?

Answers

Answer:

a) [tex]H_{in}=39.34 kJ[/tex]

b) Efficiency=76.77%

Explanation:

a)

In order to solve this problem, we can use the following formula:

[tex]H_{in}=H_{out}+W[/tex]

the problem provides us with all the necessary information so we can directly use the formula:

[tex]H_{in}=9.14kJ+30.2kJ[/tex]

[tex]H_{in}=39.34 kJ[/tex]

b) In order to find the efficiency, we can use the following formula:

[tex]Efficiency=\frac{W}{H_{in}}*100\%[/tex]

so we get:

[tex]Efficiency=\frac{30.2kJ}{39.34kJ}*100\%[/tex]

Efficiency=76.77%

The corect phase sequence shown
Gas, Liguid, Solid
Lqud, Gas, Solid
Sold, Liguid, Gas
Gas, Solid, Liquid
above i

Answers

Answer:

Explanation:

gas, liquid, soild

liquid, Gas, solid

Gas, Solid, liquid

A Boeing 737—a small, short-range jet with a mass of 51,000 kg— sits at rest at the start of a runway. The pilot turns the pair of jet engines to full throttle, and the thrust accelerates the plane down the runway. After traveling 940 m, the plane reaches its takeoff speed of 70 m/s and leaves the ground. What is the thrust of each engine?

Answers

Answer:

67000N

Explanation:

We solve for the acceleration using the the 3rd constant-acceleration equation.

(Vx)f² = (Vx)i² + 2ax∆x

We have the displacement to be

∆x = Xf - Xi = 940m

Vx = 70m/s

The acceleration = (70m/s)²/2(940m)

= 4900/1880

= 2.61m/s²

From isaac newton's second law,

51000kg x 2.61m/s²

= 133,000N

The engines thrust is half of this value

Therefore thrust = 67000N or 67kN

In the past, Africa used to be further away from Europe than it is now
(shown below). What could explain why Africa is closer to Europe now than
it was before? *

Answers

Answer: Plates shifting

Explanation: After years and years of plates colliding into solid rock, they slowly become closer together. As recent studies have shown, Africa is currently moving closer to Europe one centimeter every year (one inch every 2.5 years).

Answer:

nvudbwasivnjlscv bwbfvsz

Explanation:

A 65-cm segment of conducting wire carries a current of 0.35 A. The wire is placed in a uniform magnetic field that has a magnitude of 1.24 T. What is the angle between the wire segment and the magnetic field if the force on the wire is 0.26 N?
a. 37°.
b. 43°.
c. 23°.
d. 53°.
e. 67°.

Answers

Answer:

e) 67°

Explanation:

the force on the wire can be calculated using the expression below

F = BILsinФ

But we are looking for the angle between the wire segment and the magnetic field, then we can make Ф the subject of the formula from the above expresion, then we have,

Ф =sin⁻¹ (F/BIL)

The parameters is defined as

I =current that is been carried by the wire= 0.35 A

Ф = angle between the wire segment and the magnetic field, which is the unknown?

L = length of the wire=65 cm

B = magnetic field = 1.24

F= force on the wire = 0.26 N,

Ф =sin⁻¹ (F/BIL)

Ф =sin⁻¹ X .....................eqn(#)

Where X= (F/BIL)

We can calculate for X= (F/BIL), from eqn(#) by substituting value of Force, Lenght and

magnetic field

X=(F/BIL)= 0.26/(1.24×0.35×0.65)

= 0.26/0.2821

=0.922

Then substitute X into eqn (Ф =sin⁻¹ X)

Then

Ф =sin⁻¹ (0.922)

Ф=66.42°

Ф=67° approximately

Therefore, the angle between the wire segment and the magnetic field is 67°

Mike rides his horse with a constant speed of 20 km/h. How far can he travel in 4 hours?

Answers

Answer:

Mike can travel 80 Km in 4 hours

Engine 1 has an efficiency of 0.18 and requires 5500 J ofinput heat to perform a certain amount of work. Engine 2 hasan efficiency of 0.26 and performs the same amount of work. How much input heat does the second engine require?

Answers

Answer:

The input energy to  engine 2  is [tex]E_2 = 3807.7\ J[/tex]

Explanation:

From the question we are told that

     The efficiency of engine one is  [tex]\eta_1 = 0.18[/tex]

     The input energy required is [tex]E = 5500 \ J[/tex]

       The efficiency of engine 2 is [tex]\eta_2 = 0.26[/tex]

       

Generally the workdone by the engine 1  is mathematically represented as

       [tex]W_1 = E * \eta_1[/tex]

=>     [tex]W_1 = 5500 * 0.18[/tex]

=>     [tex]W _ 1= 990 \ J[/tex]

Generally the workdone by engine 2  is mathematically represented as  

        [tex]W _2= E_1 * \eta_2[/tex]

=>     [tex]W _2 = E_1 * 0.26[/tex]

=>     [tex]W_2 =0.26E_1[/tex]

From the question we are told that [tex]W_1 = W_2[/tex]

So  

       [tex]990 =W_2 =0.26E_1[/tex]

=>     [tex]E_2 = 3807.7\ J[/tex]

         

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