Answer:
Vf = 2.12 [m/s]
Explanation:
To solve this problem we must first find acceleration using Newton's second law, using mass and force.
ΣF = m*a
where:
F = force = 1.5 [N]
m = mass = 0.2 [kg]
a = acceleration [m/s²]
Now clearing a, we have:
[tex]a = F/m\\a = 1.5/0.2\\a = 7.5 [m/s^{2}][/tex]
Now we must use the following expression of kinematics, to find the final speed, we must take into account that the initial speed is equal to zero, since the car starts from zero.
[tex]v_{f}^{2} =v_{o} ^{2} +2*a*x\\v_{f} ^{2} = 0 + (2*7.5*0.3)\\v_{f} = \sqrt{4.5}\\v_{f} = 2.12 [m/s][/tex]
help please! thank you! please dont plagiarism my teacher checks for plagiarism ;-;
Answer:
the reason why the crate won't move to the direction of the force being applied (F app). is because the (Fgravity) is pulling it down making it heavy to move
In Einstein’s theory of gravitation, gravity is due to:
A)the acceleration of the universe
B)the presence of mass
C)the rotation of the universe
D)the curvature of spacetime
E)the speed of light
Answer:
B, caused by the presence of mass
Explanation:
The ___ of a wave is the reciprocal of its frequency.
Answer:
time period of the wave
Answer:
The Frequency of a wave is the reciprocal of its Period
The Period of a wave is the reciprocal of its frequency
Explanation:
A P E X
A crane lifts a 425 kg steel beam vertically upward a distance of 614.4 m
How much work does the crane do on the beam if the beam accelerates upward at 1.8 m/s2? Neglect frictional forces.
PHYSICS
*not sure about the answer but here we go*
Mass = 425 kg
distance = 614.4 m
acceleration = 1.8 m/s²
Answer :
Count Force first.
[tex]f \: = m \: \times a[/tex]
F = 425 × 1,8
F = 765 N ✅
Now let's count Work.
[tex]w \: = \: f \: \times s[/tex]
W = 765 × 614.4
W = 470016 J ✅
Harry is reading an online summary of the law of reflection. The site states that after light hits a mirror, the angle of reflection is the angle between the reflected ray and the normal, which is the surface of the mirror.
Which statement corrects an error on the site?
Answer:
A
Explanation:
List four safety measures one should take when there is a cyclone warning.
Answer:
I'm gonna give you more than 4 So u can choose.
Turn off all electricity, gas and water.
Unplug all electrical appliances.
Keep your emergency kit close at hand.
If the building starts to collapse, protect yourself with mattresses, rugs.
Stay tuned to the radio for updates.
Stay inside until told it is safe to go outside.
What makes the atmosphere an important part of Earth’s system?
Answer:
water exchange carbon dioxide is taken away and oxygen is made
Which Energy transformation will occur when this rubber band is let go elastic energy -chemical energy mechanical energy -electrical energy chemical energy -mechanical energy elastic energy mechanical- energy elastict
Elastic Energy - Mechanical Energy
A small truck has a mass of 2085 kg. How much work is required to decrease the speed of the vehicle from 22.0 m/s to 13.0 m/s on a level road?
Answer:
Work required is 328387.5 Joules.
Explanation:
Given the following data;
Mass = 2085kg
Initial velocity, Vi = 13m/s
Final velocity, Vf =22m/s
To find the workdone;
We know that from the workdone theorem, the workdone by an object or a body is directly proportional to the kinetic energy possessed by the object due to its motion.
Mathematically, it is given by the equation;
W = Kf - Ki
Where;
W is the work required.
Kf is the final kinetic energy possessed by the object.
Ki is the initial kinetic energy possessed by the object.
But Kinetic energy = ½MV²
W = ½MVf² - ½MVi²
Substituting into the equation, we have;
W = ½(2085)*22² - ½(2085)*13²
Simplifying the equation, we have;
W = 1042.5 * 484 - 1042.5 * 169
W = 504570 - 176182.5
W = 328387.5J
Therefore, the work required to decrease the speed of the vehicle is 328387.5 Joules.
given a circuit powered at 12V with R1, R2, R3 respectively of 10,20,30 Ohm, determine R4 in such a way that the Wheatstone bridge is in equilibrium and then calculate voltages and currents as for reference exercise.
Answer:
The balanced condition for Wheat stones bridge is
Q
P
=
S
R
as is obvious from the given values.
No, current flows through galvanometer is zero.
Now, P and R are in series, so
Resistance,R
1
=P+R
=10+15=25Ω
Similarly, Q and S are in series, so
Resistance R
2
=R+S
=20+30=50Ω
Net resistance of the network as R
1
and R
2
are in parallel
i=
R
V
=
50
6×3
=0.36 A.
Explanation:
an inclinded plane makes work easier by increasing the distance and blank the force
Hi! I believe your answer is decreasing. An inclined plane makes work easier by decreasing the amount of effort force needed, but increases the distance. I hope this helps you! Good luck and have a great day. ❤️✨
A 2 kg block slides with constant velocity along a horizontal tabletop. A horizontal applied force of 10 N and a downward applied force of 5 N act on the block, as shown. The coefficient of friction between the block and tabletop is most nearly...
Answer:
huh
Explanation:
Answer:
what are we finding?
Explanation:
A 3.35 kg object initially moving in the positive x direction with a velocity of 4.90 m s collides with and sticks to a 1.88 kg object initially moving in the negative y direction with a velocity of 3.12 m/s. Find the final components of velocity of the composite object.
Answer:
The final components of velocity of the composite object is 3.33 m/s.
Explanation:
Given;
mass of the first object, m₁ = 3.35 kg
initial velocity of the first object, u₁ = 4.90 m/s in positive x-direction
mass of the second object, m₂ = 1.88 kg
initial velocity of the second object, u₂ = 3.12 m/s in negative y-direction
initial momentum of the first object, P₁ = 3.35 x 4.9 = 16.415 kgm/s
initial momentum of the second object, P₂ = 1.88 x 3.12 = 5.8656 kgm/s
The resultant velocity of the two objects is given by;
R² = 16.415² + 5.8656²
R² = 303.858
R = √303.858
R = 17.432 kgm/s
Apply the principle of conservation of linear momentum for inelastic collision;
total initial momentum before = total final momentum after collision
P₁(x) + P₂(y) = Pf
R = Pf
R = v(m₁ + m₂)
17.432 = v(m₁ + m₂)
where;
v is the final components of velocity of the composite object
[tex]v = \frac{17.432}{m_1 + m_2} \\\\v = \frac{17.432}{3.35+1.88} \\\\v = 3.33 \ m/s[/tex]
Therefore, the final components of velocity of the composite object is 3.33 m/s.
what is the surface pressure of Venus?
answers 93 bar
The atmosphere of Venus is the layer of gases surrounding Venus. It is composed primarily of carbon dioxide and is much denser and hotter than that of Earth. The temperature at the surface is 740 K (467 °C, 872 °F), and the pressure is 93 bar (9.3 MPa), roughly the pressure found 900 m (3,000 ft) underwater on Earth.
Let the force of the Moon on the Earth be F1. Let the force of the Earth pulling on the Moon be F2. Which of the following is greater?
When you use a
spray bottle, you force air over
a small tube inside the bottle.
Explain why the liquid inside
the bottle comes out.
Answer: Spray bottles are an extremely useful type of machine and an excellent demonstration of basic plumbing principles. A spray-bottle head is made up of only a few parts. It has a trigger lever, which activates a small pump. This pump is attached to a plastic tube that draws cleaning fluid from the bottom of the reservoir. The pump forces this liquid down a narrow barrel and out a small hole at the gun's muzzle. The hole, or nozzle, serves to focus the flowing liquid so that it forms a concentrated stream.
The only complex element in this design is the fluid pump, and it's about as simple as they come. The main moving element is a piston, housed inside a cylinder. Inside the cylinder, there is a small spring. To operate the pump, you pull the trigger back, pushing the piston into the cylinder. The moving piston compresses the spring, so when you release the trigger, the piston is pushed back out of the cylinder. These two strokes of the piston, into the cylinder and out again, constitute the entire pump cycle.
Explanation:
Awnser: The liquid comes out because you're using your hand to squeeze the handle, which forces it out.
?
_2. Region surrounding the nucleus where electrons are found.
?
_3. Positively charged center of an atom.
?
4. Particles that differ in number between isotopes.
Answer:
Electron shell
Nucleus
Neutrons
Explanation:
An atom is made up of three fundamental subatomic particles which are the protons, neutrons and electrons.
Protons are the positively charged particles. Neutrons do not carry any charges. Both protons and neutrons are found in the tiny nucleus at the center of that atom. The electrons are negatively charged. They are found outside the nucleus in electronic shells.what is an emergent curriculum
Answer:
Emergent curriculum is an early education approach where teachers design projects unique to a child or group of kids.
A periodic wave travels from one medium to another. Which pair of variables are likely to change in the process?
A.
velocity and wavelength
OB.
velocity and frequency
Ο Ο Ο Ο
OC.
frequency and wavelength
OD.
frequency and phase
E.
wavelength and phase
Answer:
Velocity and frequency
Explanation:
Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.70 m. The ball is going 7.33 m/s.
If the speed is tripled, what happens to its centripetal force?
a)The new centripetal force is 1/3 what it was
b)The new centripetal force is 9 times more
c)The new centripetal force is 1/9 what it was
d)The new centripetal force is 3 times more
Answer:
b)The new centripetal force is 9 times more
Explanation:
The formula to apply in this case is that of tension force on a spring which is equal to the centripetal force.
T= mv²/r --------i
where T is the tension on the spring
v= velocity/speed of the ball = 7.33 m/s
m= mass of the ball , 0.015 kg
r= radius of circle , 0.70 m
Use the values in the formula as;
T= {0.015 * 7.33² } / 0.70
T= 0.8059335 / 0.70
T= 1.15 N ---------i
If the speed is tripled then;
v= 21.99 m/s
T= 0.015 * 21.99² / 0.70
T= 10.36 N ------ii
Check the changes by dividing i and ii as ;
10.36 / 1.15 = 9.01
This is 9 times more hence if the speed is tripled ,the new centripetal force is 9 times more.
A value that describes how heavy an object is and is related to the force of gravity is:
The weight of an object
Answer: B) weight
Got it right on E2020
what happens at a transform boundary
Answer:
Answer is "two tectonic plates slide past eachother" ( for a pe x)
Explanation:
George got a bad grade on the test because he decided he would rather sleep than study. this is an example of a __ attribution
the right answer for this question would be dispositional
Answer:
dispositional
Explanation:
Enter an expression for the force constant for the floating raft, in terms of L, g, and the density of water, ρ.
Answer:
K = ρL²g
Explanation:
Consider L as the length of the raft inside the water when the raft is displaced through additional distance y;
Then:
F = upthrust ( restoring force) = weight of the liquid displaced.
[tex]F = V_{\omega} \rho_{\omega} g= A y \rho_{\omega} g[/tex]
where;
A = L²
[tex]\rho_{\omega} = \rho[/tex]
F = ky.
Then,
[tex]Ay \rho g = ky[/tex]
[tex]L^2y \rho g = ky[/tex]
Divide both sides by y
K = ρL²g
Elizabeth .........................................................................
Answer:
who's elizabeth? haha
Answer:
What about it?
Explanation:
A barge is pulled by two tugboats. If the resultant of the forces exerted by the
tugboats is 5kN force directed along the axis of the barge, determine the tension in
each of the ropes for α = 45
Answer:
Approximately [tex]3.5\; \rm kN[/tex] in each of the two ropes.
Explanation:
Let [tex]F_1[/tex] and [tex]F_2[/tex] denote the tension in each of the two ropes.
Refer to the diagram attached. The tension force in each rope may be decomposed in two directions that are normal to one another.
The first direction is parallel to resultant force on the barge.
The component of [tex]F_1[/tex] in that direction would be [tex]\displaystyle F_1\cdot \cos(45^\circ) = \frac{F_1}{\sqrt{2}}[/tex].Similarly, the component of [tex]F_2[/tex] in that direction would be [tex]\displaystyle F_2\cdot \cos(45^\circ) = \frac{F_2}{\sqrt{2}}[/tex].These two components would be in the same direction. The resultant force in that direction would be the sum of these two components: [tex]\displaystyle \frac{F_1 + F_2}{\sqrt{2}}[/tex]. That force should be equal to [tex]5\; \rm kN[/tex].
The second direction is perpendicular to the resultant force on the barge.
The component of [tex]F_1[/tex] in that direction would be [tex]\displaystyle F_1\cdot \sin(45^\circ) = \frac{F_1}{\sqrt{2}}[/tex].Similarly, the component of [tex]F_2[/tex] in that direction would be [tex]\displaystyle F_2\cdot \sin(45^\circ) = \frac{F_2}{\sqrt{2}}[/tex].These two components would be in opposite directions. The resultant force in that direction would be the difference of these two components: [tex]\displaystyle \frac{F_1 - F_2}{\sqrt{2}}[/tex]. However, the net force on the barge is normal to this direction. Therefore, the resultant force should be equal to zero.
That gives a system of two equations and two unknowns:
[tex]\displaystyle \frac{F_1 + F_2}{\sqrt{2}} = 5\; \rm kN[/tex], and[tex]\displaystyle \frac{F_1 - F_2}{\sqrt{2}} = 0[/tex].The second equation suggests that [tex]F_1 = F_2[/tex]. Hence, replace the [tex]F_2[/tex] in the first equation with [tex]F_1[/tex] and solve for [tex]F_1\![/tex]:
[tex]F_1 = \displaystyle \frac{5\; \rm kN}{2\, \sqrt{2}} \approx 3.5\; \rm kN[/tex].
Because [tex]F_1 = F_2[/tex] (as seen in the second equation,) [tex]F_2 = F_1 \approx 3.5\; \rm kN[/tex].
In other words, the tension in each of the two ropes is approximately [tex]3.5\; \rm kN[/tex].
The tension in each of the rope is 3,535.5 N
The given expression:
the resultant force, R = 5 kN = 5000 N
the angle in between the forces, α = 45
To find:
the tension in each of the ropesThe tension in each of the ropes is calculated as follows;
The tension in vertical direction
[tex]F_y = F \times sin(\alpha)\\\\F_y = 5000 \times sin(45)\\\\F_y = 5000 \times 0.7071\\\\F_y = 3,535.5 \ N[/tex]
The tension in horizontal direction;
[tex]F_x = F \times cos(\alpha)\\\\F_x = 5000 \times cos(45)\\\\F_x = 5000 \times 0.7071\\\\F_x = 3,535.5 \ N[/tex]
Thus, the tension in each of the rope is 3,535.5 N
Learn more here:https://brainly.com/question/11194858
If the speed of a roller coaster at the bottom of a hill is 20.0 m/s , what is the tallest hill the coaster can climb, assuming no friction losses ?
Answer:
20.4 meters
Explanation:
KE = 1/2 m v^2 = mgh = PE (convert all kinetic energy to potential energy, because at the highest point the coaster can climb, it will be stopped!)
=> h = (1/2 m v^2) / (mg) = v^2/(2*g) = (20 m/s)^2 / (2*9.8 m/s^2) = 20.4 m
The tallest height that the roller coaster can climb is 20 m.
A roller coaster is a device in which energy conversions from potential to kinetic energy takes place. Hence the roller coaster can easily be used to demonstrate the conversion of mechanical energy from one form to another.
Given that the velocity of the roller coaster at the bottom of the hill is 20.0 m/s, potential energy is converted into kinetic energy.
Hence;
mgh = 1/2mv^2
gh =1/2v^2
h = 1/2v^2/g
h = 0.5 × (20)^2/10
h = 20 m
Learn more: https://brainly.com/question/999862
А A pool of water of refractive index
4/3! is 60cm deep. Find its apparent
depth when viewed vertically through
air.
Answer:
Apparent depth = 45 cm
Explanation:
The refractive index of water in a pool, n = 4/3
Real depth, d = 60 cm
We need to find its apparent depth when viewed vertically through air. The ratio of real depth to the apparent depth is equal to the refractive index of the material. Let the apparent depth is d'. So,
[tex]n=\dfrac{d}{d'}\\\\d'=\dfrac{d}{n}\\\\d'=\dfrac{60}{\dfrac{4}{3}}\\\\d'=45\ cm[/tex]
So, the apparent depth is 45 cm.
Read each scenario below. Then select the answer choices that complete the sentences,
A car engine has
power than a house because a car engine does the same amount of work in
time,
Yaserin and Raj each had 10 tones of equal weight to stack next to each other on the same shelt, at the same height
and in the same arrangement. Vasarin completed the task in 2 minutes, wille Raj took 3 minutes to stack his bles,
Raj applied
power than Yaskrin because his stacking took turve to do the same amount of
Answer:
Higher
Lesser
Lesser
Longer
Explanation:
Search...
54
ryanzl6659
14 hours ago
Physics
College
Read each scenario below. Then select the answer choices that complete the sentences,
A car engine has HIGHER power than a house because a car engine does the same amount of work in LESSER time,
Yaserin and Raj each had 10 tones of equal weight to stack next to each other on the same shelt, at the same height and in the same arrangement. Vasarin completed the task in 2 minutes, wille Raj took 3 minutes to stack his bles,
Raj applied LESSER power than Yaskrin because his stacking took LONGER to do the same amount of
Answer:
More
Less
Less
More
Explanation:
i got all correct
i) Give two practical
application of static friction
1). Walking / Driving
If there were no static friction between the soles of your shoes and the ground, then you could move your feet back and forth but your body would never go anywhere.
Same for using tires to move a car, a bus, a bicycle or a motorcycle.
2). Sleeping
If there were no static friction between your jammies and the sheet, you would slide right off of the bed whenever there was the slightest breeze of air in the room.