a football kicker can give the ball an initial speed of 25m/s. what are the a) least and b) the greatest elevation angles at which he can kick the ball to score a field goal from a point 50m in front of goalposts whose horizontal bar is 3.44m above the ground?

The pressure exerted is 4 × 10⁷ N/m²

Pressure is the force carried out perpendicular to the surface of an item in step with the unit vicinity over which that force is sent. Gauge pressure is the pressure relative to the ambient strain. numerous units are used for the explicit strain.

Strain is a pressure carried out perpendicular to the surface of an item in keeping with unit location. Mathematically it is P = F/A, in which P is strain, F is force, and A is area. strain is a scalar amount, one that most effectively has value and no directional vector characteristics.

Calculation:-

Given,

area = 0.25 mm2

        = 2.5 × 10⁻⁷ m²

Force = 10 N

Pressure = force/area

              = 10 / 2.5 × 10⁻⁷

              = 4 × 10⁷ N/m²

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Answer: Conduction

Explanation: Radiation is the receiving of heat via waves from the air, Convection is the transfer via liquids. Conduction is the transfer of heat between two solids.

Cool ocean current and a convergent boundary

An ocean current is a continuous flow of water in an oceanic direction; this implies that the water is not the same water, but that it is exchanged within the current at a comparable rate and direction. Temperature and water salinity are only two examples of the elements that influence currents. A continuous, directed flow of ocean water is known as an ocean current, and it is caused by a variety of factors acting on the water, such as wind, the Coriolis effect, breaking waves, cabeling, and variations in temperature and salinity.

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When you scan the hiker's body, you will notice a warm spot. Unless that person was dead, they would not be emitting heat.

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Every planet in the solar system orbits the Sun. Planets known as exoplanets orbit other stars. Astronomers search for exoplanets by observing the effects that these planets have on the stars they orbit.

Any planet outside of our solar system is an exoplanet. The majority of exoplanets orbit other stars, while rogue planets—free-floating exoplanets that are unattached to any star—orbit the galactic center.

Since liquid water is necessary for all known forms of life, an exoplanet that is too near or too far from its host star is less likely to support life. Additionally, some primordial compounds may require ultraviolet light to form, but a hyperactive host star can blast the nascent planet, removing its atmosphere.

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Answer:

Explanation:

Newton's Third Law states that "every action has an equal and opposite reaction". In a rocket, burning fuel creates a push on the front of the rocket pushing it forward. This creates an equal and opposite push on the exhaust gas backwards.

As we walk across a period from left to right, the effective nuclear charge rises, whereas it falls as we move down the group. The element with the lowest effective nuclear charge will be found on the left side of the periodic table. The periodic table's group 1 includes H, Li, and Na.

A fluorine atom's nucleus has a charge Z of 9, but the valence electrons are mostly screened by the core electrons—four electrons from the 1s and 2s orbitals—and to a lesser extent by the 7 electrons in the 2p orbitals. The cation of sodium thus has the highest effective nuclear charge.

In spite of being in the same period as sodium and phosphorus, chlorine has the most protons in its shell (the most inside the same period), giving it the highest effective nuclear charge.

The amount of shielding electrons may be calculated by deducting the amount of valence electrons from the overall number of electrons in the atom or ion.

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Answer:

Explanation:

The elastic potential energy equation is EPE = (1/2) k x2, where k is the spring constant and x the distance from equilibrium. EPE = (0.5)*(26.6 N/m)*(0.0600 m)2 = 0.0479 Joules.

When a beam of rays that are parallel to the principal axis is incident on a concave mirror converges at the focal point.

But, if any other set of parallel rays that are not parallel to the principal axis is incident on a concave mirror they will not converge at the focal point. They will converge at a distance of focal length, but not on the focal point.

Thus the given statement is not true.

The tension in the string if a rod PR is balanced on a pivot at the end R while a string is used to support the rod at P is 6 N

Moment = Force * Perpendicular Distance

Let us consider the pivot side be initial point,

Since the rod is balanced,

CM = ACM

CM = Clockwise moment

ACM = Anticlockwise moment

F = 9 N

PQ = 15 cm = 0.15 m

QR = 30 cm = 0.3 m

PR = PQ + QR

PR = 0.15 + 0.3

PR = 0.45 m

CM = W * QR

CM = 9 * 30

CM = 2.70 N m

ACM = T * PR

ACM = 0.45 T N m

2.70 = 0.45 T

T = 6 N

Therefore, the tension in the string is 6 N

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She is caught in a wind that blows toward the equator from about 30° N and 30° S of the equator. She is in the trade wind. This science is called Hadley cell.

It follows the movement of wind blows from one direction to the other such as the one which blow from north to south or east to west. The trade wind are produced by warm moist air rising near the equator.

Now, within the context of the task given above, when the movement wind which blows toward the equator from about 30° N and 30° S of the equator is known as the trade wind.

So therefore, the movement of wind from the same certain degrees from North and South is called trade wind.

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At hmax, Vy=0

vy=v0y-gt

0=6.32sin(36.3)-9.81t

t=.381 seconds

Δy=v0yt-.5gt^2

Δy=6.32sin(36.3)*.381-.5(9.81)(.381)^2

maximum height=.714 m

Answer:

It will need 20 Watts power to move the box 5 meters in 5 seconds.

Step-by-step explanation:

The power is defined as the work per unit time or the rate of doing work:

W=dL/dt

Where de work L, can be calculated by multiplying the force by the displacement d:

L=F.d

To this example, F and D are known, therefore the work is:

L=20N . 5m=40 Nm

We know that the work is doing within a time of 5 seconds:

W= 40 Nm / 5s = 20 Nm/s = 20 Watts

Gas giants have more moons than terrestrial planets due to having higher masses.

Giant planets are composed of low boiling point substances rather than other solid substances but massive solid planets can also exist. There are four giant planets in the Solar System i.e. Jupiter, Saturn, Uranus, and Neptune. They are composed of hydrogen and helium atom i.e. Jupiter and Saturn whereas Uranus and Neptune are composed of ice, rock, hydrogen, and helium.

The giant planets have more moons as compared to the terrestrial planets because of their big masses which leads to stronger gravitational fields. Giant planets also occupy greater space and have larger volumes of mass in their surrounding atmosphere.

So we can conclude that due to having higher masses, Gas giants have many moons as compared to terrestrial planets.

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Explanation:

Gravity would still pull you down although it wouldn't affect you as much because there is less gravitational pull in high places such as Mt. Everest.

The ratio of the heads of Arkansas reservoir to west virginia's reservoir is 1813: 1120.

Consider the West Virginia reservoir

To calculate the head of the Virginia reservoir, we will use

φ = P / nρgh            

where φ is the flow rate, P is the power generated, n is efficiency, ρ is the density of water, g is the acceleration due to gravity, and h is the head.

Given that the flow rate is 7 m/s, the power generated is 12 MW, and 80% is the efficiency.

We know that the density of water is 1000 kg/m³  and  acceleration due to gravity is 9.8 m/s²

By using equation 1:

h = P / φnρg

h =  9/3*80/100*1000*9.8

h = 13440

Similarly, the head of the Arkansas reservoir will be

Given that the flow rate is 3 m/s, the power generated is 9 MW, and 74% is the efficiency.

h = P / φnρg

h = 9/3*74/100*1000*9.8

h = 21756

Now, the ratio of the heads of Arkansas reservoir to west virginia's reservoir is:

= heads of Arkansas / head of Virginia

= 21756 / 13440

= 1813 : 1120

Located in a flat delta in southeastern Arkansas Lake Chicot is a natural wonder. The 20-mile former Mississippi Canal is said to be the largest crescent lake in North America and the largest natural lake in Arkansas. The Bull Shoals were named by early French hunters and trappers who used the word boile to describe the area.

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Let p be the total linear momentum of the system before the collision and p' the total linear momentum of the system after the collision. Let p₁₁ and p₁₄ be the linear momentum of the 11.0kg ball and the 14.0kg ball before the collision, and let p₁₁' and p₁₄' be their linear momenta after the collision.

According to the Law of Conservation of Linear Momentum, the total linear momentum of the system before and after the collision remains the same. Then:

Let v be the unknown speed of the 11.0kg ball after the collision. Find the value of p₁₁, p₁₄, and p₁₄'. Find an expression for p₁₁' in terms of v and replace all the values into the above equation. Solve for v.

The linear momentum of a particle with mass m and velocity v is:

Then:

Then:

Therefore, the velocity of the first ball after the collision is 20.4m/s.

In this, two frictionless, smooth inclined surfaces that have the same angle with the horizontal (57.7°) are connected to one another. Blocks are placed on the inclined surfaces.

The left one is white, whereas the right one is black. Then, a frictionless pulley is present here at the edge, and the two blocks are attached to one another using a light string weight made of the white blocks. Assume there are lots of M W. Its weight will therefore be M W G. The black block's weight. M. B. G. Component Here would be that.

This will also be 57.7 degrees if the angle is 57.7. Additionally, this component is M W G, costs 57.7 degrees, and runs horizontally. That is 57.7° M W G Sign. Next, the element perpendicular to this inclination surface for this black block. This part is B G Costs 57.7° and a component along the spring-bound incline of mbG sign 57.7° The blocks are shown to be travelling with an acceleration of A in the direction of the left.

Given to us are MB square markings traveling at 1.5 meters per second. The bulk of this white blog weighs 3.19 kilograms. It is absent. We need to locate it. First, as the white vlog is moving down, use the free body diagram of the white block. Therefore, M W G sign 57.7 degrees force will be more than that tension T for this white block. Thus, using Newton's second rule of motion, the net force will be equal to.

The block's mass times its acceleration equals the block's net force. Using a free body schematic of the ascending black bloc, continue. T will therefore be more for it. Therefore, this equals p – Mbg. indication of 57.7 degrees. Using Newton's second rule of motion, which is equal to M B A, once more This is equation #1, that was equation #1, this is equation #2, this is one, and this is equation #3. hence, adding 1 and 2. It is obvious that the tension will end and that G signed 57.7° will be seen as an exit signal.

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A 115 kg lineman is working on tackling drills. if he is running at 2.8 m/s and hits a tackling dummy with a mass of 55 kg, then the momentum of the tackling dummy would be 322 kg-m/s.

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.

As given in the problem a 115 kg lineman is working on tackling drills. if he is running at 2.8 m/s and hits a tackling dummy with a mass of 55 kg ,

By using the conservation of the momentum,

Momentum before the collision = momentum after the collision

The momentum of the tackling dummy = m × v

                                                                   = 2.8 × 115

                                                                  =322 kg-m/s

Thus, the momentum of the tackling dummy would be 322 kg-m/s.

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Answer:

The bigger mass

Explanation:

This can be explained using F=ma

Let's say the acceleration is same on both balls 10m/s2 however we have different masses.

Pretend small mass ball is 0.5 kg and big mass is 1kg.

10 x 0.5 =5

10 X 1 =10

10 is bigger than 5

A singly charged positive ion has a mass of 3.3x10-26 kg. after being accelerated from rest through a potential difference of 933 v, the ion enters a magnetic field of 1.43 t along a direction perpendicular to the field. The radius of the circular path of the ion in the field is (r)= 1.982 cm.

Energy is a term that means the object is affected by some amount of force and move a distance. That is called the energy. It can be measured in Joule.

To calculate the radius we are using the formula here,

r= mu/Bq

Where we are given,

m = The mass of single positive charged ion.=  3.3×10⁻²⁶kg.

q= The charge of the single positive charged ion.= 1.602×10⁻¹⁹ C

B = The magnetic field for the electric field. = 0.92 T

But we don't know the term, u= the velocity of the single positive charged ion.

So we have to calculate the velocity of the single positive charged ion. To calculate the velocity we are using the formula,

(1/2)mu²=qv

Here we are given,

v= The  potential difference of the electric field. = 933v.

We have to calculate the velocity=u, as Conservation of energy we know,

(1/2)mu²=qv

Or,(1/2)mu²=ev

Or, u²= (2×1.602×10⁻¹⁹×933)/(3.3×10⁻²⁶)

Or, u=91325.9 m/s.

So from this we know the velocity of the ion, u=91325.9 m/s.

Now, we have to calculate the radius in a magnetic field= r,

r= mu/Bq =mu/Be

Or, r= 3.3×10⁻²⁶×91325.9/0.92×1.602×10⁻¹⁹

Or, r=0.01982m

Or, r=1.982 cm.

So from the calculation we can surely say that, The radius of the circular path of the ion in the field is (r)= 1.982 cm.

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We calculated that the pilot's apparent weight at the maximum point was 3 70.5 Newton. Additionally, the circular portion's lowest point is equal to 1598.5 Newton.

A stunt pilot performing a loop during an airshow has been described to us. the vertical circle's loop. During his performance, he gives us the radius of the circle as 3.08 into 10 to the power three m.

We are provided the weight of the pilot, which is 614. For one second, Newton maintains a speed of 2.2 into tend to the bar at a distance of 2 m. We need to know the pilot's apparent weight in newtons while he is at the highest point of the loop. Now, the formula for the pilot's mass can be expressed as being equal to the pilot's weight divided by the acceleration caused by gravity. adding the values together results in 614. too unexplored by exploration.

You get the mass of the pilot, which is 62.65 kgs Hill, when you add gravity. The apparent weight of the pilot will be equal to the normal force generated by the airplane seat. At this point, we may use the formula M to determine the apparent weight off the pilot at the highest point in the circular journey.  N in this case stands for the pilot's apparent weight. We find the apparent weight of Mars to be 62.65 kgs multiplied by velocity, which is 2.2 and 2 10 to the part two m for a second, by adding the pilot's speed and the circular portion's radius, r. entire square.

The normal force of the seat on the pilot will be zero since the apparent weight of the pilot at his or her highest point throughout the circle in the case of weightlessness is Newton. With the numbers we have divided by Mars being She took 165 and shoes as replacements, we get the speed of the pilot at weightlessness state equal to 173.7 meters per second. As a result, its speed at this point will be equal to root of wait, multiplied by Baridis divided by mass.

Now your parent wait of the pilot at the lowest point can we given us Baron, well being equal to and we square r plus right, substituting the values, we have 62.65 Kgs to point to entertain the part to the whole square divided by yes, 614. Newton solving which we get the apparent weight of the pilot, the lowest point equal to 1598 0.5. Newton which is the apparent weight of the pilot at the lowest point of the circular what therefore Therefore we determined the apparent weight of the pilot at the highest point being equal to 3 70.5 Newton. And at the lowest point of the circular part being equal to 1598.5 Newton.

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Answer: 0.30 m/s^2

Explanation:

[tex](9.8m/s^{2} )[/tex] · [tex]\frac{(18kg)-0.20(76kg)}{(76kg)+(18kg)}[/tex]

The acceleration of the dolly-sandbag system is 0.29 m/s².

The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

A spring balance can be used to calculate the Force. The Newton is the SI unit of force.

Given parameters:

The mass of the dolly and actor combined is: M = 76 kg

the mass of the sandbag is: m = 18 kg.

The coefficient of kinetic friction between the dolly and the stage floor is 0.20.

Let the acceleration is a.

Hence, From Newton's 2nd law of motion, we can write that:

ΣF = (m+M) a

mg - μMg = (m+M) a

a = g (m- μM)/ (m+M)

= 9.8 ( 18 - 0.20×76)/(18+76)

= 0.29 m/s².

Hence, the acceleration of the dolly-sandbag system is 0.29 m/s².

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Paint chip impacting a spaceship window with a force of 6.67×103 N using a 0.100-mg mass.

Any action that seeks to preserve, modify, or deform a body's motion is considered to be a force in mechanics. Usually, Isaac Newton's three laws of motion from his Principia Mathematica are used to describe the concept of force (1687). A body at rest or moving uniformly in a straight path will stay in that state unless a force is applied to it, according to Newton's first law. According to the second law, any external force that interacts with a body causes it to accelerate (change its velocity) in the force's direction. A vector quantity, force is one that has both magnitude and direction. The rate at which an item changes its velocity is known as the vector quantity known as acceleration. When an object's velocity changes, it is said to be accelerating. On occasion, sports broadcasters will suggest that a person is accelerating if they are travelling quickly. Acceleration, however, has little to do with speed. Even though a person is travelling quickly, they may not be accelerating. A change in an object's speed is referred to as acceleration. An object is not accelerating if it is not changing its velocity.

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The true statement is "Your speed is constant".

An object is moving at a constant speed when its speed is constant, that is the speed does not increase or decrease.

Constant speed also refers to the movement of a body at a uniform rate in a fixed steady-state moving with an average speed.

If you are in a car that is going around a curve and the speedometer reads a constant 30 miles per hour, you will notice that the direction of your motion is changing and but the distance travelled in a given time does not change.

Thus, only the speed is constant but velocity and acceleration is not constant.

The correct option is E.

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a. V(y)=V-E(y) b. U=vq-1/2QEL.cosФ c. V=EL/2 d. angular speed of the bar as it passes Ф=0° is W=[tex]\sqrt{3QE/ML}[/tex]

You were already familiar with the ideas of velocity and speed. The idea of angular speed and velocity, however, is what needs to be understood in terms of physical numbers. Angular motion is the term for when an item is expected to travel along a circular path while making a specific angle. The idea of angular speed and angular velocity is derived from the object's angular motion. Let's examine these ideas in greater depth. Assuming you are rotating a ball in a circular orbit, the angular speed can be defined as follows.

A body's rate of angle change over time as it rotates in a circular orbit is known as its angular speed. The definition of angular velocity is similar to that of linear velocity when an object is moving with some speed in a circular orbit.

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Work is measured in joules or newton-meters

It may be thought of as force * distance

If there were acceleration in this problem, the force would be more than the weight, but because the speed is constant force = weight.

given,

force= 350N

Distance= 2m

work= ?

Work = Force * Distance

= 2m * 350 N

= 700 j or 700 N*M

If you're looking at this from an energy standpoint, you can just consider the final PE as the energy required because there is no KE at the end. so,

PE = m*g*h

and m*g = 350N

h= 2m

PE = 700j or 700 N*M

Hence, the 700N*M work is done by athlete.

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The difference in temperature from the average temperature for a region defines a heat wave.

A heat wave is an extended period of unusually hot weather that usually lasts longer than days.

Heat waves can occur in both low and high humidity conditions. They have the capacity to cover a wide area, exposing too many people to harmful heat.

An extremely dangerous weather event known as a heat wave occurs when temperatures rise considerably above 90° F. Due to the extreme heat and high humidity levels, an area becomes extremely warm for an extended period of time.

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The initial resistance of one resistor r in ohms in series combination is 28.5 Ω.

The resistance depends on the used combination. The resistor combination can be combined in 2 ways which are series combination and parallel. In series combination, the resistance will be added up for each resistor. It can be written as

R = R1 + R2

where R is total resistance, R1 and R2 are the series combination of resistors.

From the question above, the given parameters are

R2 = 9 Ω

I1 = 8.4 A

I2 = 6.384 A

Hence, the current ratio of the initial and final condition is

I1 / I2 = V /R1  / V/(R1 + R2)

8.4 / 6.384 = (R1+R2) / R1

8.4 R1 = 6.384 R1 + 57.456

2.016R1 = 57.456

R1 = 28.5 Ω

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