A flywheel rotating at an initial velocity of 2.09 rad/s undergoes a change to 4.6 rad/s for precisely 5s

a) Calculate the angular acceleration of the flywheel.

b) Suppose the flywheel has moment of inertia of 1.5 kg m^2. Compute the wheels torque?
[Please answer if you know]

Answers

Answer 1

Answer:

A. 0.502

B. 0.753

Explanation:

A. The angular acceleration of the flywheel is equal to the change in angular velocity divided by the change in time, which is equal to (4.6-2.09)/5 which is 0.502.
B. Angular acceleration is equal to the net torque divided by the rotational inertia. If you rearrange the equation, torque is equal to angular acceleration times rotational inertia, which is 0.502 times 1.5 which is 0.753.

Answer 2

Answer:

Assumption: the angular acceleration of this flywheel is constant.

Angular acceleration: [tex]0.502\; {\rm rad\cdot s^{-2}}[/tex].

Net torque on this flywheel: [tex]0.753\; {\rm kg \cdot m^{2} \cdot s^{-2}[/tex] (or, equivalently, [tex]0.753\; {\rm N \cdot m}[/tex].)

Explanation:

Change in the angular velocity of this flywheel:

[tex]\begin{aligned}\Delta \omega &= \omega_{1} - \omega_{0} \\ &= 4.6\; {\rm rad \cdot s^{-1}} - 2.09 \; {\rm rad \cdot s^{-1}} \\ &= 2.51\; {\rm rad \cdot s^{-1}}\end{aligned}[/tex].

Divide this change in angular velocity [tex]\Delta \omega[/tex] with the duration [tex]t[/tex] of the acceleration to find the average angular acceleration of this flywheel:

[tex]\begin{aligned}\alpha &= \frac{\Delta \omega}{t} \\ &= \frac{2.51\; {\rm rad \cdot s^{-1}}}{5\; {\rm s}} \\ &= 0.502\; {\rm rad \cdot s^{-2}}\end{aligned}[/tex].

By Newton's Second Law for Rotation, the net torque on this flywheel would be the product of the angular acceleration and the moment of inertia of this flywheel, [tex]I[/tex]:

[tex]\begin{aligned}\tau_{\text{net}} &= I\, \alpha \\ &= 1.5\; {\rm kg \cdot m^{2}} \times 0.502\; {\rm s^{-2}} \\ &= 0.753\; {\rm kg \cdot m^{2} \cdot s^{-2}} \\ &= 0.753\; {\rm (kg \cdot m \cdot s^{-2}) \cdot m} \\ &= 0.753\; {\rm N \cdot m}\end{aligned}[/tex].


Related Questions

A model train running on an inclined track is part of a closed system that has
316 J of mechanical energy. If the kinetic energy of the train decreases from
314 J to 250 J, what happens to the gravitational potential energy of the
system?
A. It decreases from 66 J to 2 J.
B. It decreases from 316 J to 314 J.
SMIT
OC. It increases from 2 J to 66 J.
D. It increases from 316 J-to 564 J.

Answers

If the kinetic energy of the train decreases from 314 J to 250 J, the gravitational potential energy of the system It increases from 2 J to 66 J.

What is conservation of mechanical energy?

The principle of conservation of mechanical energy states that the total mechanical energy of a system is always constant. This means that the sum of the potential and the kinetic energy does not change.

Thus, if the kinetic energy of the train decreases from 314 J to 250 J, the gravitational potential energy of the system It increases from 2 J to 66 J.

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A 500 N weight is hung at the middle of a rope attached to two buildings at the same level. If the breaks in the tension exceed 1800 N, what is the minimum angle the rope can make with the horizontal?

Answers

Not sure what you mean by "breaks in the tension" but I suspect you mean the rope will come apart if the tension in the rope exceeds 1800 N.

In the free body diagram for the 500 N weight, we have a figure Y with the net force equations

• horizontal net force:

∑ F[hor] = T₁ cos(θ) - T₂ cos(θ) = 0

• vertical net force:

∑ F[ver] = T₁ sin(θ) + T₂ sin(θ) - 500 N = 0

From the first equation, it follows that T₁ = T₂, so I'll denote their magnitude by T alone. From the second equation, we have

2 T sin(θ) = 500 N

and if the maximum permissible tension is T = 1800 N, it follows that

sin(θ) = (500 N) / (3600 N)   ⇒   θ = arcsin(5/36) ≈ 7.9°

is the smallest angle the rope can make with the horizontal.

Technician A says that sometimes linings are bonded to the metal brake
backing. Technician B says that sometimes linings are riveted to the metal
brake backing. Who is right?
O A only
O Neither A nor B
OB only
Both A and B

Answers

Both technician A and technician B are right because linings are attached to the brake shoe either by riveting or bonding.

How are linings attached to a brake?

Linings are attached to the brake shoe either by riveting or bonding.

Riveted lining attachment has several advantages when compared to bonding lining attachment.

One of these advantages include;

Riveted lining is simpler,

However, rivet heads may score the drum if the linings are not replaced soon enough.

Thus, we can conclude that both technician A and technician B are correct, because linings are attached to the brake shoe either by riveting or bonding.

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The current through a 12 Ω resistor in an electric circuit is 1.5 A. Calculate the potential difference across the resistor.

Answers

Hello!

We can use Ohm's Law to solve for the potential difference across a resistor given the current and resistance:

[tex]V = iR[/tex]

V = Potential Difference (? V)
i = Current (1.5 A)

R = Resistance (12 Ω)

Plug in the known values and solve.

[tex]V = (1.5)(12) = \boxed{18 V}[/tex]

A rock is dropped from a garage roof from rest. the roof is 6.0 m from the ground. determine the velocity of the rock as it hits the ground.

Answers

From rest, a rock is dropped from a garage roof. The roof is 6.0 meters above ground level. The rock will reach the earth at a speed of 10.849 meters per second.

What is velocity?

The change of displacement with respect to time is defined as the velocity.  Velocity is a vector quantity.

it is a time-based component. Velocity at any angle is resolved to get its component of x and y-direction.

Given data:

V(Final velocity)=? (m/sec)

h(height)= 6.0 m

u(Initial velocity)=0 m/sec

g(gravitational acceleration)=9.81 m/s²

Newton's third equation of motion:

[tex]\rm v_y^2 = u_y^2+ 2gh \\\\\rm v_y^2 = 0+ 2gh\\\\\ v_y= \sqrt{2\times 9.81 \ (m/s^2)\times 6.0 (m)} \\\\ v_y=10.849 \ m/sec[/tex]

Hence, the velocity of the rock as it hits the ground will be 10.849 m/sec.

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The chart show the masses and velocities of two colliding objects that stick together after a collision.



According to the law of conservation of momentum, what is the momentum of the object after the collision?

4,500 g · m/s
1,750 g · m/s
1,500 kg · m/s
3,000 kg · m/s

Answers

The momentum of the object after the collision is  1500 kg. m/s.

What is conservation of momentum principle?

When two bodies of different masses move together each other and have head on collision, they travel to same or different direction after collision.

The external force is not acting here, so the initial momentum is equal to the final momentum. In inelastic collision, after the collision, the two objects are stick together and final velocity is the common velocity for both the bodies.

Given is the chart show the masses and velocities of two colliding objects that stick together after a collision.

Object        Mass (kg)           Velocity (m/s)

A                   200                      15

B                     150                    - 10

Using the conservation of momentum principle, we have

m₁u₁ +m₂u₂ =(m₁ +m₂) v = Pf

Substitute the values, then the momentum after collision will be

200x15 +150x(-10) =Pf

Pf = 1500 kg. m/s

Thus, the  momentum after collision is 1500 kg. m/s.

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A cylinder 15.0 cm in diameter rotates at 1000 rpm. (a) what is its angular velocity in rad/s? (b) what is the tangential velocity of a point on the rim of the cylinder?

Answers

Answer:

(a) Approximately [tex]105\; {\rm rad \cdot s^{-1}}[/tex].

(b) Approximately [tex]15.7\; {\rm m \cdot s^{-1}}[/tex], assuming that this cylinder is rotating along the axis that goes through the center.

Explanation:

The unit [tex]{\rm rpm}[/tex] stands for "revolutions per minute", where each revolution is [tex]2\, \pi[/tex] radians.

With an angular velocity of [tex]1000\; {\rm rpm}[/tex], this cylinder would turn [tex]1000\times 2\, \pi = 2000\, \pi[/tex] radians every minute ([tex]60\; {\rm s}[/tex]). Thus, the angular velocity of this cylinder would be:

[tex]\begin{aligned} \omega &= \frac{2000\, \pi\; {\rm rad}}{60\; {\rm s}} \\ &\approx 104.720\; {\rm rad \cdot s^{-1}}\end{aligned}[/tex].

A point at the rim of this cylinder would be at a distance of [tex]r = 15.0\; {\rm cm} = 0.150\; {\rm m}[/tex] from the axis of revolution of this cylinder. If the angular velocity of this cylinder is [tex]\omega[/tex], the tangential velocity of this point would be:

[tex]\begin{aligned} v&= \omega\, r \\ &= \frac{2000\, \pi}{60\; {\rm s}} \times 0.150\; {\rm m} \\ &\approx 15.7 \; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

how long would it take for a resultant upward force of hundred Newton to increase the speed of 50 kg object from hundred metre per second to 150 metre per second?​

Answers

To answer this question, two equations are needed.

F = m * a (force = mass * accelaration)

Vf =Vi + (a * t) (final velocity = initial velocity + (accelaration * time)

Knowing that the force is 100 N and the mass is 50 kg we can use the first equation to solve for the acceleration which would be 2 m/s^2.

Plugging in all we know to the second equation we get:

150 m/s = 100 m/s + (2 m/s^2 * t)

This gives us t = 25 seconds

An electromagnetic wave has a wavelength of 10 nm. Calculate its frequency and identify to which part of the electromagnetic spectrum the wave belongs.

Answers

The frequency of an electromagnetic wave with wavelength of 10nm will be 3 × 10∧7 Hz and would belong to the X-ray or ultraviolet part of the electromagnetic spectrum due to its wavelength

What is frequency?

Frequency is defined as the number of oscillations of a wave per unit time and is measured in hertz(Hz).

It is also inversely proportional to the wavelength.

How to calculate the frequency

The frequency of an electromagnetic wave can be calculated using the formula;

frequency = velocity of light divided by the wavelength

f = v ÷ λ

Note that the velocity of light = 3 × 10 ∧8 m/s

Wavelength = 10nm

Frequency, f = 3 × 10∧8 ÷ 10 = 3 × 10∧7 Hz

Hence, the frequency of an electromagnetic wave with wavelength of 10nm will be 3 × 10∧7 Hz and would belong to the X-ray or ultraviolet part of the electromagnetic spectrum due to its wavelength.

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for the whole page done i reward u with 50 points i am very tired and i have many work to do so thank you guys for the help

Answers

Answer:

Box 1

Explanation:

Formula we are using :

Force = mass × acceleration

                or

mass = Force / acceleration (since mass needs to be found)

=============================================================

Box 1 :

⇒ mass = 5 N / 5 m/s²

⇒ mass = 1 kg

=========================================================

Box 2 :

⇒ mass = 5 N / 0.75 m/s²

⇒ mass = 5 × 4/3 = 20/3 kg

⇒ mass = 6.67 kg

===========================================================

Box 3 :

⇒ mass = 5 N / 4.3 m/s²

⇒ mass = 50/43 kg

⇒ mass = 1.16 kg

===========================================================

On comparing Box 1, Box 2, and Box 3, we understand that Box 1 has the smallest mass

We will use Newton's second law

F=mam=F/a

#1

m=5/5=1kg

#Box 2

m=5/0.75m=6.67kg

#Box 3

5/4.3m=1.16kg

First box has smallest mass

Our galaxy, the milky way, contains approximately 4.0x1011 starts with an average mass of 2.0x1030kg each. how far away is the milky way from our nearest neighbor, the andromeda galaxy, if andromeda contains roughly the same number of stars and attracts the milky way with a gravitational force of 2.4x1030n?

Answers

By applying the law of universal gravitation, the distance between the milky way and the andromeda galaxy is equal to 4.2 × 10¹¹ meters.

Given the following data:

Mass A, m = 4.0 × 10¹¹ kg.Mass B, M = 2.0 × 10³⁰ kg.Gravitational force, F = 2.4 × 10³⁰ Newton.

Scientific data:

Gravitational constant = 6.67 × 10⁻¹¹ m/kg²

How to calculate the distance?

In order to determine the distance between the milky way and the andromeda galaxy, we would apply the law of universal gravitation.

According to the law of universal gravitation, the distance between two astronomical bodies can be calculated by using this formula:

[tex]d = \sqrt{\frac{GmM}{F} }[/tex]

Substituting the parameters into the formula, we have;

[tex]d = \sqrt{\frac{6.67 \times 10^{-11} \times 2.0 \times 10^{30} \times 4.0 \times 10^{11}}{2.4 \times 10^{30}} }[/tex]

Distance, d = 4.2 × 10¹¹ meters.

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At 6: 00 am, a motorbike set off from town A to town B at a speed of 40km/h. At the same time, a car set off from town B to town A at a speed of 60km/h. What time did they meet

Answers

Answer:

One would need to know how far apart the towns are:

T = SA / 40      time it takes for first cyclist to travel S1

T = SB / 60       time it takes for cyclist B to travel distance S2

SA + SB = S     the distance between the towns

SB = 60 / 40 SA = 1.5 SA

SA + 1.5 SA = S

S = 2.5 SA where cyclist travels distance SA

The time will depend on the separation of the towns.

Hello people ~
A current passes through a resistor. If K₁ and K₂ represent the average kinetic energy of the conduction electrons and the metal ions respectively then

(a) K₁ < K₂

(b) K₁ = K₂

(c) K₁> K₂

(d) any of these three may occur

Answers

Answer:

K1>K2

Explanation:

The main reason behind this is law of conservation of momentum

Momentum can neither be created nor endorsed.

But

the factor drift velocity affects the scenario.

Drift velocities of electrons is way more than velocities of ions so

K1 is greater than K2

Option C

Sound travels at a rate of 340 m/s in all directions through air. Matt rings a very loud bell at one location, and Steve hears it some time later at his location 450 meters to the south. How long did it take the sound to travel from the bell to Steve's location?

Answers

Answer:

110 m/s

Explanation:

because if you subtract 450 from 340 you get 110

Identical twins have identical DNA, _______, and are usually always the same gender.

A. Temperament

B. Blood type

C. Personality

D. Experiences

Answers

Answer:

Blood Type because DNA also contains blood type

Alfredo makes a diagram to organize his notes about charging objects.


Which statement should he place in the region marked X?

It does not involve touching the objects together.
The objects develop opposite charges.
Electrons do not move between objects.
The objects have the same charge.

Answers

The region marked X in the diagram shows that the objects have the same charge.

What is conduction?

The term conduction has to do with the manner of charging in which charge is passed from one object to another. Induction involves charging objects without the objects touching each other.

The region marked X in the diagram shows that the objects have the same charge.

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Answer:

D

Explanation:

A child jumps from a moving sled with a speed of 2.2 m/s and in the
direction opposite the sled's motion. The sled continues to move in the forward direction, but with a new speed of 5.5 m/s. If the child has a mass of 38 kg and the sled has a mass 68 kg, what is the initial velocity of the sled?

Answers

The initial velocity of the sled will be 7.34 m/sec. V is the initial velocity of the sled.

What is the law of conservation of momentum?

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

(m₁)  mass of child = 38 kg

(u₁) is the initial velocity child = 2.2 m/s

(m₂) is the mass of sled = 68 kg

(u₂) is the initial velocity of sled = ?

(v) is the velocity after collision = 5.5 m/s

According to the law of conservation of momentum;

Momentum before collision =Momentum after collision

[tex]\rm m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\(38 \times 2.2) + (68 \times V) = 5.5 \times (38+68) \\\\ 83.6 + 68V = 5.5 \times 106 \\\\ 83.6 + 68V =583 \\\\ \rm 68\ V= 583 -83.6 \\\\ \rm 68 \ V= 499.4\\\\ V= 7.34 \ m/sec[/tex]

Hence,the initial velocity of the sled will be 7.34 m/sec.

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(42)What is the speed of sound in air at a temperature of 15°C?

Answers

Answer:

340 m/s

At the temperature of 15 degrees Celsius, the velocity of sound is about 340 m/s in air.

how many cubic meters of habitable space was available in skylab?

A 1,000

B 263

C 5,263

D 10,000​

Answers

361 cubic meters of habitable space was available in the skylab. None of the given options are correct.

Who launched skylab?

NASA launched the first American space station, called Skylab.

The fuel tank of the Saturn SIV-B rocket stage served as the Skylab's residential quarters.

Skylab's livable capacity was large in comparison to the spacecraft that American astronauts had previously used 361 cubic meters.

Skylab offered 361 cubic meters of livable area.

Hence, none of the given options is correct.

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Which of the following is a good radiator of heat option is (a) a shiny silvered surface option (b) a dull black surface option (c) a white surface option (d) a green coloured surface

Answers

Answer:

option b

Step by step explanation:

a dull black surface is a good radiator of heat

Answer:

option b is the answer

Which energy transformation occurs when an electrolytic cell is in operation.

Answers

Answer:

An electrolytic cell converts electrical energy into chemical energy.

Explanation:

An electron and a proton have charges of an equal magnitude but opposite sign of 1.60 10-19 C. If the electron and proton in a hydrogen atom are separated by a distance of 2.00 10-11 m, what are the magnitude and direction of the electrostatic force exerted on the electron by the proton

Answers

The proton's electrostatic force exerted on the electron will be 3.5×10¹² N.

What is the electrostatic force?

It is a force imposed by one charge on another as a result of the field.

The electrostatic force produced by one line charge on another line charge separated by r is determined by the charge potency of each charge as well as the separation distance between them.

The electrostatic force is found as:

[tex]\rm F= \frac{Kq_1q_2}{R^2} \\\\ F= \frac{9 \times 10^ 9 \times 1.6 \times 10^{-19} \times -1.6 \times 10^{-19} }{(2.00\times 10^{-11})^2} \\\\\ F= 3.5 \times 10^{12} \ N[/tex]

Hence, the proton's electrostatic force exerted on the electron will be 3.5×10¹² N.

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The prop blades of an airplane spin with a linear velocity of 875 m/s and have a centripetal acceleration on the farthest edge of 180,000 m/s^2 the radius of the prop blades?

Answers

The radius of the prop blade of an airplane is determined as 4.25 m.

Radius of the prop blade

The radius of the prop blade of an airplane is calculated as follows;

a = v²/r

where;

v is the linear speedr is the radius of the prop bladea is the centripetal acceleration

r = v²/a

r = (875²)/(180,000)

r = 4.25 m

Thus, the radius of the prop blade of an airplane is determined as 4.25 m.

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Transverse waves are to radio waves as longitudinal waves are to:

1. light waves
2. microwaves
3. ultraviolet waves
4. sound waves

URGENT!!!!

Answers

It’s sound waves
4
D
Answer

4. Sound Waves.

Explanation

The first three options are electromagnetic radiations (including radio waves), which are transverse waves. Sound waves is a longitudinal wave as it oscillates in the direction by which the wave propagates.

Sean, who has a mass of 65-kg, is out roller blading with friends at a speed of 3 m/s. Not realizing he accidentally let the dog out as he was leaving, Sean finds his 12-kg pup at rest in the middle of the street. Sean gracefully scoops the dog up as he skates down the road and proceeds to carry the pup home. Calculate their final velocity.

Velocity: _ m/s

Answers

Answer:

2.53m/s

Explanation:

Initial momentum in a system= Final momentum in a system

65kg*3m/s+12kg*0m/s=(65kg+12kg)*v

195kgm/s=77kg*v

v=2.53m/s

please help with this i am not good with this

Answers

Answer:

Ball 3 (tennis ball)

Explanation:

Formula we are using :

acceleration = Force / mass

=============================================================

Ball 1 :

⇒ acceleration = 15 N / 0.5 kg

⇒ acceleration = 30 m/s²

===========================================================

Ball 2 :

⇒ acceleration = 15 N / 4.5 kg

⇒ acceleration = 30/9 m/s²

⇒ acceleration = 10/3 m/s²

⇒ acceleration = 3.33 m/s²

===========================================================

Ball 3 :

⇒ acceleration = 15 N/ 0.05 kg

⇒ acceleration = 300 m/s²

============================================================

On comparing, we see that Ball 3 (tennis ball) has the greatest acceleration.

A scientist tested wellwarm to see how well it insulated a beaker of hot water. she tested wellwarm and three other materials. what was the dependant variable that the scientist measured during the investigation?

Answers

Answer:

the dependent variable is the material

Explanation:

because we change the material each time to test which is the best insulator.

this came up in my test today, so i can assure you it is correct!

I think it’s gas but I’m not sure.

Answers

Answer:

Liquid

Explanation:

The substance will be liquid because the gas form will be 100° Celsius. So, it is not gas instead it is liquid. Solid is not the answer because it has to be 0° C

According to Ohm’s law, which is stated as I = V ÷ R, which two sentences are true?
If the current increases, then the resistance increases. Assume voltage is constant.
If the resistance decreases, then the current increases. Assume voltage is constant.
If the voltage increases, then the resistance decreases. Assume current is constant.
If the voltage increases, then the current increases. Assume resistance is constant.
If the voltage increases, then the current decreases. Assume resistance is constant.

Answers

Answer:

2nd and 4th statements.

Explanation

If voltage is constant ( k ) and I = V / R,

Then I is inversely proportional to R so if I increases R decreases and vice versa, according to that the second statement is correct not the first.

if current is constant, then v is directly proportional to R and vice versa..the 3rd statement is wrong

if resistance is constant v is directly proportional to I, then only the 4th is correct not the 5th

The centers of two 350 kg spheres are separated by 2.00 m. what is the gravitational force between them?

Answers

The gravitational force between them is 3000 gravity’s
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