Answer:
the maximum area enclosed = 1125000sq. ft.
Step-by-step explanation:
Let each side perpendicular to the river be "x".
Then the side parallel to the river is "3000-2x".
Now, area of the rectangle
A(x) = (3000-2x)x
A(x) = -2x^2+3000x
Which is a quadratic equation with a = -2 and b = 3000
Maximum area occurs where x = -b/2a
x = -3000/(-2×2) = 750 ft.
Therefore, width of rectangle x = 750 ft
Now, length = 3000-2(750) = 1500 ft.
Therefore, the maximum area enclosed = 1500×750 = 1125000 sq. ft.
The measure of the angle of depression from the top of a 270-meter building to a park bench on the ground is 36°45′. How far away is the park bench from the building? Round to the nearest whole number.
Answer:
202 m
Step-by-step explanation:
Given :
Angle of depression, θ = 36°45' ; 45/60 = 0.75 = 36 + 0.75 = 36.75°
The height, h = 270
The distance of park bench from the building, d is given by :
Tan θ = opposite / Adjacent
Tan 36.75 = d / 270
d = 270 * Tan 36.75
d = 201.61856
d, distance of Park bench from building is 202 m
The graph shows a 6-sided polygon on the coordinate plane. The polygon has k = 1.5. In the spaces below, enter the coordinates of B’ and C’.
Answer:
[tex]B' = (-3,-3)[/tex]
[tex]C' = (-4.5,-7.5)[/tex]
Step-by-step explanation:
Given
[tex]k = 1.5[/tex]
[tex]B = (-2,2)[/tex]
[tex]C =(-3,-5)[/tex]
Required
B' and C'
This is calculated as;
[tex]B' = k * B[/tex]
[tex]B' = 1.5 * (-2,-2)[/tex]
[tex]B' = (-3,-3)[/tex]
and
[tex]C' =k * C[/tex]
[tex]C' = 1.5 * (-3,-5)[/tex]
[tex]C' = (-4.5,-7.5)[/tex]
A random sample of 10 observations was selected from a normal population distribution. The sample mean and sample standard deviations were 20 and 3.2, respectively. A 95% prediction interval for a single observation selected from the same population is
Answer:
18.0167≤x≤21.9833
Step-by-step explanation:
Given the following
sample size n = 10
standard deviation s = 3.2
Sample mean = 20
z-score at 95% = 1.96
Confidence Interval = x ± z×s/√n
Confidence Interval = 20 ± 1.96×3.2/√10
Confidence Interval = 20 ± (1.96×3.2/3.16)
Confidence Interval = 20 ± (1.96×1.0119)
Confidence Interval = 20 ± 1.9833
CI = {20-1.9833, 20+1.9833}
CI = {18.0167, 21.9833}
Hence the required confidence interval is 18.0167≤x≤21.9833
Math problem please help thank youuuuuu
Answer:
the answer is ( -8,-8 )
Step-by-step explanation:
the first point is in -8 and the second point is also in -8 , therefore the answer is ( -8,-8 )
Please help me it is due soon, please no links
Answer:
The length of the three sides [tex]5, \sqrt{58} , \sqrt{65}[/tex]
The triangle is not a right triangle
Step-by-step explanation:
A = (3, 2) , B = ( 6, 9) , C = (10, 6)
Find the lengths using distance formula.
[tex]distance = \sqrt{(x_2 -x_1)^2 + (y_2 - y_1)^2}[/tex]
[tex]AB = \sqrt{(6-3)^2 + (9-2)^2} = \sqrt{9 + 49 } = \sqrt{58}[/tex]
[tex]BC = \sqrt{(10-6)^2 + (6-9)^2} = \sqrt{16 + 9} = \sqrt{25} = 5[/tex]
[tex]AC = \sqrt{(3-10)^2+(2-6)^2} = \sqrt{49 + 16} = \sqrt{65}[/tex]
Using Pythagoras theorem :
[tex](Longer \ side)^2 = sum \ of \ square \ of \ two \ other \ sides[/tex]
Longest side is AC . So we will check if it satisfies Pythagoras theorem :
[tex]\sqrt{65} = \sqrt{58} + 5^2\\65 = 58 + 25\\[/tex]
65 ≠ 58 + 25
So the sides does not satisfy Pythagoras theorem. Hence the triangle is not a right triangle.
Can y’all help me? :)
Answer:
Option A: [tex]5\frac{1}{4} *4\frac{1}{5}[/tex]
Step-by-step explanation:
Area of a parallelogram is base times height so in this case it would be 5 1/4 times 4 1/5. 5 1/4 being the base and 4 1/5 being the height.
hii please help me :)
Answer:
1.) A = (1/2bh) 4 + lxw
= 1/2 x 7 x 13 x 4 + 7 x 7
182 + 49 = 231cm2
l think u can use the formula to find the area of the other pyramids
Based on past experience, a bank believes that 8.9 % of the people who receive loans will not make payments on time. The bank has recently approved 220 loans. What must be true to be able to approximate the sampling distribution with a normal model
Answer:
To be able to approximate the sampling distribution with a normal model, it is needed that [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], and both conditions are satisfied in this problem.
Step-by-step explanation:
For each person, there are only two possible outcomes. Either they will make payments on time, or they won't. The probability of a person making the payment on time is independent of any other person, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
The sampling distribution can be approximated to a normal model if:
[tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex]
Based on past experience, a bank believes that 8.9 % of the people who receive loans will not make payments on time.
This means that [tex]p = 0.089[/tex]
The bank has recently approved 220 loans.
This means that [tex]n = 220[/tex]
What must be true to be able to approximate the sampling distribution with a normal model?
[tex]np = 220*0.089 = 19.58 \geq 10[/tex]
[tex]n(1-p) = 220*0.911 = 200.42 \geq 10[/tex]
To be able to approximate the sampling distribution with a normal model, it is needed that [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], and both conditions are satisfied in this problem.
Jake jogs every day in the neighborhood park. He runs 4 miles on Sunday,
3 miles on Monday, and 5 miles on Tuesday. Find the mean distance
covered by Jake.
4
Hope this helps! :)
______________
he graph shows the total number of participants in a town's recreation program at the end of every year since the year 2000.
The line of best fit for the data is given by the equation y=13x+50, where y is the total number of participants x years after the beginning of the year 2000.
Which statement correctly interprets the slope of the line of best fit?
The rate of change is 1 new participant every 13 years.
The rate of change is 13 new participants every 13 years.
The rate of change is 13 new participants every year.
The rate of change is 50 new participants every year.
Answer:
The rate of change is 13 new participants every year.
Step-by-step explanation:
y=13x+50
This is in the form y = mx+b where m is the slope and b is the y intercept
x is the number of years so for every year increase we gain 13 new participants
A student is running a 3-kilometer race. He runs 1kilometer every 2minutes. Select the function that describes the distance from the finish line after xminutes
Answer:
(0.5X) - 3 = Distance from the finish line
Step-by-step explanation:
Given that a student is running a 3-kilometer race, and runs 1 kilometer every 2 minutes, to determine the function that describes the distance from the finish line after X minutes, the following calculation must be performed:
1 = kilometers for every 2 minutes
X = every number of minutes
1/2 = 0.5 = kilometers per minute
(0.5X) - 3 = Distance from the finish line
Thus, if the student runs for 4 minutes, the equation would operate as follows:
0.5 x 4 - 3 = X
2 - 3 = X
-1 = X
Help me ASAP plzzz……
Answer:20, 40, 40,100
Step-by-step explanation:
5x+2x+2x=180 9x=180 x=20
in a rectangle how many opposite sides are equal
Answer and Step-by-step explanation:
This is for your other question in case you don't see it.
1. 2 pairs (aka 4 sides) of Opposite Sides are equal
2. AB and DC are parallel, and AD and BC are parallel
3. Angles BDC and ACD are equal, angles DAC and DBC are equal, the angles ADB and BCD are equal, angles CAB and DBA are equal
4. 4 right angles
5. AB and DC are equal, and AD and BC are equal
6. 4 Triangles
7. False
8. Diagonals of a rectangle.
#teamtrees #PAW (Plant And Water)
plz help i dont know what to do
ANSWER QUICK
Answer:
the last one is correct.............
Please help me please !!
We want to construct a box with a square base and we currently only have 10m2 of material to use in construction of the box. Assuming that all material is used in the construction process, determine the maximum volume that the box can have.
Answer:
The maximum volume of the box is:
[tex]V =\frac{5}{3}\sqrt{\frac{5}{3}}[/tex]
Step-by-step explanation:
Given
[tex]Surface\ Area = 10m^2[/tex]
Required
The maximum volume of the box
Let
[tex]a \to base\ dimension[/tex]
[tex]b \to height[/tex]
The surface area of the box is:
[tex]Surface\ Area = 2(a*a + a*b + a*b)[/tex]
[tex]Surface\ Area = 2(a^2 + ab + ab)[/tex]
[tex]Surface\ Area = 2(a^2 + 2ab)[/tex]
So, we have:
[tex]2(a^2 + 2ab) = 10[/tex]
Divide both sides by 2
[tex]a^2 + 2ab = 5[/tex]
Make b the subject
[tex]2ab = 5 -a^2[/tex]
[tex]b = \frac{5 -a^2}{2a}[/tex]
The volume of the box is:
[tex]V = a*a*b[/tex]
[tex]V = a^2b[/tex]
Substitute: [tex]b = \frac{5 -a^2}{2a}[/tex]
[tex]V = a^2*\frac{5 - a^2}{2a}[/tex]
[tex]V = a*\frac{5 - a^2}{2}[/tex]
[tex]V = \frac{5a - a^3}{2}[/tex]
Spit
[tex]V = \frac{5a}{2} - \frac{a^3}{2}[/tex]
Differentiate V with respect to a
[tex]V' = \frac{5}{2} -3 * \frac{a^2}{2}[/tex]
[tex]V' = \frac{5}{2} -\frac{3a^2}{2}[/tex]
Set [tex]V' =0[/tex] to calculate a
[tex]0 = \frac{5}{2} -\frac{3a^2}{2}[/tex]
Collect like terms
[tex]\frac{3a^2}{2} = \frac{5}{2}[/tex]
Multiply both sides by 2
[tex]3a^2= 5[/tex]
Solve for a
[tex]a^2= \frac{5}{3}[/tex]
[tex]a= \sqrt{\frac{5}{3}}[/tex]
Recall that:
[tex]b = \frac{5 -a^2}{2a}[/tex]
[tex]b = \frac{5 -(\sqrt{\frac{5}{3}})^2}{2*\sqrt{\frac{5}{3}}}[/tex]
[tex]b = \frac{5 -\frac{5}{3}}{2*\sqrt{\frac{5}{3}}}[/tex]
[tex]b = \frac{\frac{15 - 5}{3}}{2*\sqrt{\frac{5}{3}}}[/tex]
[tex]b = \frac{\frac{10}{3}}{2*\sqrt{\frac{5}{3}}}[/tex]
[tex]b = \frac{\frac{5}{3}}{\sqrt{\frac{5}{3}}}[/tex]
Apply law of indices
[tex]b = (\frac{5}{3})^{1 - \frac{1}{2}}[/tex]
[tex]b = (\frac{5}{3})^{\frac{1}{2}}[/tex]
[tex]b = \sqrt{\frac{5}{3}}[/tex]
So:
[tex]V = a^2b[/tex]
[tex]V =\sqrt{(\frac{5}{3})^2} * \sqrt{\frac{5}{3}}[/tex]
[tex]V =\frac{5}{3} * \sqrt{\frac{5}{3}}[/tex]
[tex]V =\frac{5}{3}\sqrt{\frac{5}{3}}[/tex]
The maximum volume of the box which has a 10 m² surface area is given below.
[tex]\rm V_{max} = \dfrac{5}{3} *\sqrt{\dfrac{5}{2}}[/tex]
What is differentiation?The rate of change of a function with respect to the variable is called differentiation. It can be increasing or decreasing.
We want to construct a box with a square base and we currently only have 10 m² of material to use in the construction of the box.
The surface area = 10 m²
Let a be the base length and b be the height of the box.
Surface area = 2(a² + 2ab)
2(a² + 2ab) = 10
a² + 2ab = 5
Then the value of b will be
[tex]\rm b = \dfrac{5-a^2}{2a}[/tex]
The volume of the box is given as
V = a²b
Then we have
[tex]\rm V = \dfrac{5-a^2 }{2a}* a^2\\\\V = \dfrac{5a - a^3}{2}\\\\V = \dfrac{5a}{2} - \dfrac{a^3}{2}[/tex]
Differentiate the equation with respect to a, and put it equal to zero for the volume to be maximum.
[tex]\begin{aligned} \dfrac{dV}{da} &= \dfrac{d}{da} ( \dfrac{5a}{2} - \dfrac{a^3}{2} ) \\\\\dfrac{dV}{da} &= 0 \\\\\dfrac{5}{2} - \dfrac{3a^2 }{2} &= 0\\\\a &= \sqrt{\dfrac{5}{2}} \end{aligned}[/tex]
Then the value of b will be
[tex]b = \dfrac{5-\sqrt{\dfrac{5}{2}} }{2*\sqrt{\dfrac{5}{2}} }\\\\\\b = \sqrt{\dfrac{5}{2}}[/tex]
Then the volume will be
[tex]\rm V = (\sqrt{\dfrac{5}{2}} )^2*\sqrt{\dfrac{5}{2}} \\\\V = \dfrac{5}{3} *\sqrt{\dfrac{5}{2}}[/tex]
More about the differentiation link is given below.
https://brainly.com/question/24062595
Nicole works in a sporting goods store
and earns $324 a week and 5% of her
sales. One week Nicole earned $432.
What were her sales that week? Write
and equation and solve.
Answer:
2,160
Step-by-step explanation:
432-324=108 earnings based on sales
sales x 5%=108
sales=108/.05
sales=2,160
can anyone prove this:
1+1=3
Answer:
indeed
Step-by-step explanation:
just carry the one when adding
Step-by-step explanation:
1 = 1
41 – 40 = 61 – 60
16 + 25 – 40 = 36 + 25 – 60
4² + 5² – 2 * 4 * 5 = 6² + 5² – 2 * 6 * 5
(4 – 5)² = (6 – 5)²
4 – 5 = 6 – 5
4 = 6
2 = 3
1 + 1 = 3…proved
HELP ASAP PLZ will give u brainliest if u answer it first find the length of df
Answer:
3.75
Step-by-step explanation:
DF = 6/24 × 15 = 3.75
________________
A parking garage charges the following amount for cars parked in the garage:
For the first hour that a car is parked in the garage, there is no charge. After the first hour, for the next two hours that a car is parked in the garage, there is a $5 charge. After the third hour, the garage charges $2 for each additional hour that the car is parked in the garage. If a car is parked in the garage for a fraction of an hour, the garage will charge that fraction of the additional hourly rate.
1. If a car is parked in the garage for 30 minutes, how much will the garage charge? Explain your answer.
2. If a car is parked in the garage for 2 hours and 30 minutes, how much will the garage charge? Explain your answer.
3. If a car is parked in the garage for 5 hours, how much will the garage charge? Explain your answer.
4. If a car is parked in the garage for 5 hours and 30 minutes, how much will the garage charge? Explain your answer.
ANY INCOMPLETE OR INAPPROPRIATE ANSWERS WILL BE REPORTED AND DELETED. POINTS WILL BE DEDUCTED.
Answer:
20$ i think
Step-by-step explanation:
A fraction is a way to describe a part of a whole. If a car is parked in the garage for 5 hours and 30 minutes the charge will be $10.
What is a Fraction?A fraction is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25.
Given that for the first hour that a car is parked in the garage, there is no charge. After the first hour, for the next two hours that a car is parked in the garage, there is a $5 charge. After the third hour, the garage charges $2 for each additional hour that the car is parked in the garage.
1.) Since the car is parked for 30 minutes only.
Charge = $0
Hence, No charge will be charged for 30 minutes.
2.) If a car is parked in the garage for 2 hours and 30 minutes.
Charge for 1 hour = $0
Charge for the next 1 hour and 30 minutes = $5
Hence, the charge will be $5.
3.) If a car is parked in the garage for 5 hours.
Charge for 1 hour = $0
Charge for the next 2 hour = $5
Charge for the next 2 hour = 2×$2 = $4
Charge = $5 + $4 = $9
Hence, the charge will be $9.
4.) If a car is parked in the garage for 5 hours and 30 minutes.
Charge for 1 hour = $0
Charge for the next 2 hour = $5
Charge for the next 2 hour 30 minutes = 2.5 ×$2 = $5
Charge = $5 + $5 = $10
Hence, the charge will be $10.
Learn more about Fraction:
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What I Can Do
Directions: How can we help minimize the amount of electricity and water
to be consumed in a month? List down at least 3 ways each. Write your
answers on a sheet of paper.
ಠ_ಠ (눈‸눈) (⌐■-■)
(ب_ب) ¯\_ಠ_ಠ_/¯
MULTIPLE CHOICE LaShawn designs websites for local
businesses. He charges $25 an hour to build a website, and
charges $15 an hour to update websites once he builds them.
He wants to earn at least $100 every week, but he does not
want to work more than 6 hours each week. What is a possible
solution to describe how many hours LaShawn can spend
building a website (x) and updating a website (y) in a week?
A (1,4)
B (1,6)
C (2,3)
D (3, 3)
Jeremy read 243 pages on Saturday. He read 53 fewer pages on Sunday.
How many pages did he read in all?
243 = the pages read on Saturday
243 - 53 = 190 = the pages read on Sunday
190 + 243 = 433 = total pages read
Answer = 433
Can y’all help me please?
Answer:
(A) [tex]5\frac{1}{4}*4\frac{1}{5}[/tex]
Step-by-step explanation:
The area of a parallelogram is the same as the area of a rectangle which is A=bh where b is the base and h is the height. Therefore, Erica can use the expression [tex]5\frac{1}{4}*4\frac{1}{5}[/tex] to find the area of the parallelogram.
In a sample of 400 students, 60% of them prefer eBooks.
A.Find 98% Confidence Interval for the proportion of all students that prefer ebooksb.
b. Find the margin of erro
Answer:
a) The 98% Confidence Interval for the proportion of all students that prefer ebooks is (0.55, 0.65).
b) The margin of error is of 0.05.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
The margin of error is of:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In a sample of 400 students, 60% of them prefer eBooks.
This means that [tex]n = 400, \pi = 0.6[/tex]
98% confidence level
So [tex]\alpha = 0.02[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.02}{2} = 0.99[/tex], so [tex]Z = 2.054[/tex].
Margin of error -> Question b:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
[tex]M = 2.054\sqrt{0.6*0.4}{400}}[/tex]
[tex]M = 0.05[/tex]
The margin of error is of 0.05.
A.Find 98% Confidence Interval for the proportion of all students that prefer ebooksb.
Sample proportion plus/minus the margin of error.
0.6 - 0.05 = 0.55
0.6 + 0.05 = 0.65
The 98% Confidence Interval for the proportion of all students that prefer ebooks is (0.55, 0.65).
Given that y varies directly as x when y = 2 and x = -12, find x when y = 5.
Answer:
x = -30
Step-by-step explanation:
Use the direct variation equation, y = kx
Plug in 2 as y and -12 as x, and solve for k:
y = kx
2 = k(-12)
-1/6 = k
So, the equation is y = -1/6x
Plug in 5 as y and solve for x:
y = -1/6x
5 = -1/6x
-30 = x
So, when y = 5, x = -30
a rectangular auditorium seats 2898 people. the number of seats in each row exceeds the number of rows by 17. find the number of seats
Answer:
There are 46 rows with 63 seats in each row
Step-by-step explanation:
I started looking for a whole number dividing seats and rows to make up the two pieces we need to multiply. I started backward from 70 (lucky guess) and then worked my way down to 63 and 46.
Now I was also looking for something more elegant in an algabraic formula and I stated with x being the number of rows and the seats being (x=17)
so I started with X(X+17)=2898 but that fif sot pan out other than to take me to x squared +17 = 2898 - subtract 17 from each side xsquared equals 2916
square root of 2916 is 54 which started my searching for a random number.
I got lucky
look at pic 10 pts will mark brainilest
A=1/2h(B+b);A=81,B=8,b=1 what is h
Answer:
81=1/2h×9,
81=1/18h
1458h=1
h=1/1458
Answer:
h=1/ 1458
hope it is helpful to you
The population of a city is increasing at a rate of 4% each year. In 2000, there were 236,000npeople in the city. Let t represent the number of years since 2000 and P represent the population. Write an exponential growth function to model
The exponential growth function to model represents as P = 236,000 (1+ 0.04)⁹ and 335,902 people in 2009.
What is the exponential growth function?The exponential growth function is given by:-
y = A(1 +r)ⁿ
where r is the rate of growth and A is the initial amount and n is the time period.
Let t represent the number of years since 2000 and P represent the population.
The population of a city is increasing at a rate of 4% each year. In 2000, there were 236,000 people in the city.
Put A = 236,000 , r = 0.04 and t = 9, we get
P = 236,000 (1+ 0.04)⁹
P = 335,902
Hence, the exponential growth function to model represents P = 236,000 (1+ 0.04)⁹ and 335,902 people in 2009.
Learn more about exponential growth and decay here:
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