A farmer sells 7.5 kilograms of apples and pears at the farmer's market. 3/4 of this weight is apples, and the rest is pears. How many kilograms of pears did she sell at the farmer's market?

Answers

Answer 1

Answer: 1.87 kg of pears

Step-by-step explanation:

7.5 kg of both apples and pears were sold. 3/4 of this 7.5 kg is apples which means the amount of apples sold is:

= 7.5 * 3/4

= 5.63 kg of apples

The amount of pears sold would therefore be:

= Total amount sold - Amount of apples

= 7.5 - 5.63

= 1.87 kg of pears


Related Questions

Please I need help.
Find each length or area to the nearest tenth.
ZY:_____
XZ:_____
Area of XYZ:_____

Answers

Answer:

XZ = 26.7

ZY = 11.7

Area =  140.4 sq inches

Step-by-step explanation:

m∠Z = 180-(26+90) = 64°

to get XZ you can use the law of sines:

sin 90°/XZ = sin 64°/24

1/XZ = sin(64°)

cross-multiply to get:

XZ·sin(64°) = 24

XZ = 24/sin(64°)

XZ = 26.7

to get ZY you can use the law of sines again:

sin 64°/24 = sin 26°/ZY

cross-multiply to get:

ZY·sin(64°) = 24·sin(26°)

ZY = 24·sin(26°) ÷ sin(64°)

ZY = 11.7

Area = 1/2(11.7)(24)

= 12(11.7)

= 140.4 sq inches

Increase £140 by 5%.
Thank you so much

Answers

Answer:

£140 increased by 5% is £147.00

Answer:

it should be 147.00 , I'm so sorry if I'm wrong!

Fifteen students from Poppy High School were accepted at Branch University. Of those students, six were offered academic scholarships and nine were not. Mrs. Bergen believes Branch University may be accepting students with lower ACT scores if they have an academic scholarship. The newly accepted student ACT scores are shown here.
Academic scholarship: 25, 24, 23, 21, 22, 20
No academic scholarship: 23, 25, 30, 32, 29, 26, 27, 29, 27

Part A: Do these data provide convincing evidence of a difference in ACT scores between students with and without an academic scholarship? Carry out an appropriate test at the α = 0.02 significance level. (5 points)

Part B: Create and interpret a 98% confidence interval for the difference in the ACT scores between students with and without an academic scholarship. (5 points)

Answers

Answer:

See below for answers and explanations

Step-by-step explanation:

Part A:

Given:

Pooled sample size: [tex]n=15[/tex]

Sample size (with academic scholarships): [tex]n_1=6[/tex]

Sample size (no academic scholarships): [tex]n_2=9[/tex]

Population standard deviations: Unknown

Sample mean (with academic scholarships): [tex]\bar{x}=\frac{25+24+23+21+22+20}{6}=22.5[/tex]

Sample mean (no academic scholarship):[tex]\bar{x}=\frac{23+25+30+32+29+26+27+29+27}{9}=27.\bar{5}[/tex]

Sample standard deviation (with academic scholarships): [tex]s_1=1.7078[/tex]

Sample standard deviation (no academic scholarships): [tex]s_2=2.5868[/tex]

Degrees of freedom: [tex]df=n-2=15-2=13[/tex]

Significance level: [tex]\alpha =0.02[/tex]

Decide which test is most appropriate to conduct:

Therefore, we will conduct a 2-sample t-test assuming our conditions are satisfied.

List null and alternate hypotheses:

[tex]H_o:\mu_1=\mu_2[/tex] -> There's no difference in ACT scores between students with and without an academic scholarship

[tex]H_a:\mu}_1\neq\mu_2[/tex] -> There's a difference in ACT scores between students with and without an academic scholarship (it's two-sided)

Determine the value of the test statistic:

We will use the formula [tex]t=\frac{\bar{x}_1-\bar{x}_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2} } }[/tex] to compute the test statistic [tex]t[/tex]. Therefore, the test statistic is [tex]t=\frac{\bar{x}_1-\bar{x}_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2} } }=\frac{27.\bar{5}-22.5}{\sqrt{\frac{1.7078^2}{6}+\frac{2.5868^2}{9} } }=4.5592[/tex]

Calculate the p-value:

Because the test is two-sided, [tex]p=2tcdf(4.5592,1e99,13)=2(0.0003)=0.0006[/tex]

Interpret p-value and conclude test:

Given our significance level is [tex]\alpha =0.02[/tex], since [tex]p<\alpha[/tex], we reject the null hypothesis and conclude that there is significant evidence that suggests that there is a difference in ACT scores between students with and without an academic scholarship (it's more likely that the alternate hypothesis is true)

Part B:

The formula for a confidence interval for the difference in 2 population means is [tex]CI=(\bar{x}_1-\bar{x}_2)\pm t^*\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}}[/tex] where [tex]\bar{x}_1-\bar{x}_2[/tex] is the difference of the 2 sample means and [tex]t^*[/tex] is the critical score for the desired confidence level.

The critical score for our 98% confidence interval would be [tex]t^*=invT(0.99,13)=2.6503[/tex]

Therefore, our 98% confidence interval for the difference in the ACT scores between students with and without an academic scholarship is [tex]CI=(27.\bar{5}-22)\pm 2.6503\sqrt{\frac{1.7078^2}{6}+\frac{2.5868^2}{9}}}=[2.6167,8.4944][/tex]

This means that we are 98% confident that the true difference in the ACT scores between students with and without an academic scholarship is contained within the interval [tex][2.6167,8.4944][/tex]

The evaluation of sub-parts results in:

Part A: Yes, the data provides convincing evidence of a difference in A at CT scores between students with and without an academic scholarship at α = 0.02

Part B: The 98% confidence interval for the difference in the ACT scores between students with and without an academic scholarship is evaluated to be [tex]CI \approx [-7.00, -2.14][/tex]

How to perform two sample t-test?

If the sample sizes < 30, and we want to test the difference between the sample means, then we perform t-test.

Let we have:

[tex]\overline{x}_1[/tex] = mean of first sample[tex]\overline{x}_2[/tex] = mean of second sample[tex]s_1[/tex] = standard deviation of first sample[tex]s_2[/tex]  = standard deviation of second sample.

Then, the value of t-test statistic is obtained as:

[tex]t = \dfrac{\overline{x}_1 - \overline{x}_2}{\sqrt{\dfrac{s_1^2}{n_1} + \dfrac{s_2^2}{n_2}}}[/tex]

If the level of significance is [tex]\alpha[/tex], then as we have:

the degree of freedom (d.f) = [tex]n_1 + n_2 - 2[/tex], the critical value of t is found to be [tex]t_{\alpha/2}[/tex], then if we get:

[tex]|t| < t_{\alpha/2}[/tex]null hypothesis

and if we get [tex]|t| > t_{\alpha/2}[/tex] null hypothesis, and thus, accept the alternate hypothesis.

For this case, we want to test if there is

Thus, we form the hypotheses as:

Null hypothesis: There's no difference in ACT scores between students with and without an academic scholarship

or: [tex]H_0: \mu_1 = \mu_2[/tex]

Alternative hypothesis:  There's a difference in ACT scores between students with and without an academic scholarship (it's two-sided)

or [tex]H_1: \mu_1 \neq \mu_2[/tex]

where we have:

[tex]\mu_1[/tex] = population mean score of ACT of students having academic scholarship[tex]\mu_2[/tex] = population mean score of ACT of students having no academic scholarship

For this case, we evaluate the mean and standard deviation as:

Sample 1: Academic scholarship: 25, 24, 23, 21, 22, 20

Sample size = [tex]n_1 = 6[/tex]

Mean = sum of all observation/ number of observations = 135/6 =22.5

Thus, standard deviation = [tex]s_1 = \sqrt{\dfrac{1}{n}\sum{(x_i - \overline{x_1})^2}} = \sqrt{\dfrac{17.5}{6}} \approx1.71[/tex]

Sample 2: No academic scholarship: 23, 25, 30, 32, 29, 26, 27, 29, 27

Sample size = [tex]n_2 = 9[/tex]

Mean = sum of all observation/ number of observations = 248/9 ≈27.56

Thus, standard deviation = [tex]s_2 = \sqrt{\dfrac{1}{n}\sum{(x_i - \overline{x_2})^2}} \approx \sqrt{\dfrac{60.22}{9}} \approx 2.59[/tex]

The t-test statistic is evaluated as:

[tex]t = \dfrac{\overline{x}_1 - \overline{x}_2}{\sqrt{\dfrac{s_1^2}{n_1} + \dfrac{s_2^2}{n_1}}} = \dfrac{22.5 -27.56}{\sqrt{\dfrac{2.92}{6} + \dfrac{6.69}{9}}} \approx -4.56[/tex]

Degree of freedom = [tex]n_1 + n_2 - 2 = 6 + 9 - 2 = 13[/tex]

Level of significance = 0.02 = 2%

The critical value of t is found to be [tex]t_{0.02/2} =2.65[/tex]

Thus, we get: [tex]|t| \approx 4.56 > 2.65 =t_{\alpha/2}[/tex]

Thus, we may reject the null hypothesis.

That means, there is enough evidence of a difference in ACT scores between students with and without an academic scholarship at 0.02 level of significance.

Now, the 98% confidence interval for the difference in the ACT scores between students with and without an academic scholarship is calculated as:

[tex]CI = (\overline{x}_1 - \overline{x}_2) \pm t_{\alpha/2}\sqrt{\dfrac{s_1^2}{n_1} + \dfrac{s_2^2}{n_1}}\\\\CI = -5.06 \pm 2.65(\sqrt{\dfrac{2.92}{6} + \dfrac{6.69}{9}})\\\\CI \approx -5.06 \pm 2.65 \times 1.11\\CI \approx -5.06 \pm 2.94\\CI \approx [-5.06 - 2.94, -5.06 + 2.94] = [-7.00, -2.14][/tex]

Thus, the evaluation of sub-parts results in:

Part A: Yes, the data provides convincing evidence of a difference in A at CT scores between students with and without an academic scholarship at α = 0.02

Part B: The 98% confidence interval for the difference in the ACT scores between students with and without an academic scholarship is evaluated to be [tex]CI \approx [-7.00, -2.14][/tex]

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A bag contains 8 apples and 6 oranges. You randomly draw a piece of fruit from the bag, eat it, and than randomly draw another. What is the probability you draw and eat an apple than draw an orange?

Answers

Answer:

[tex]probability \ of\ choosing\ apple\ first = \frac{8}{14}\\\\probability\ of\ choosing\ orange\ second = \frac{6}{13}\\\\probability \ of \ choosing \ apple \ and \then \ orange = \frac{8}{14} \times\frac{6}{13} = \frac{24}{91}[/tex]

To determine which window cleaner is most effective, Thad washes half of the windows in his house with one brand and the other half with a different brand. He then compares the results to draw a conclusion about which cleaner is most effective.

What kind of statistical study did Thad conduct?








A.

survey

B.

observational study

C.

theoretical study

D.

experiment

Answers

Answer:

the answer for the question is D,experiment

The kind of statistical study that Thad Conducted is called; Experiment

How to Identify Statistical Study?

We ae told that we want to determine the cleaner that has the best effectiveness.

Now, since he compares the result of washing with let's say brand A to the result of washing with maybe brand B, then we can say that it is called an experiment due to the fact that it involves the procedure used to determine the efficacy or likelihood of something.

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Assume that you want to construct a box with a square base (closed top) and a volume of 1000 cm3 . Find the dimensions of the box to minimize the surface area of the box.

Answers

Answer:

[tex]x=10\sqrt[3]{2}[/tex]

Step-by-step explanation:

The Volume of a box with a square base  

x by  x  cm and height  h  cm is  

V =x^2h

The amount of material used is directly proportional to the surface area, so we will minimize the amount of material by minimizing the surface area.

The surface area of the box described is  

A = x ^2 +4 x h

We need  

A  as a function of  x  alone, so we'll use the fact that

V= x^2h = 1000 cm^3

This imples  [tex]h=\frac{1000}{x^2}[/tex]

This makes

[tex]A= x^2 + 4x(1000/x^2)\\A= x^2+4000/x[/tex]

Differentiating A w.r.t. x

[tex]A' = 2x-4000/x^2[/tex]

Now, A'=0

[tex]x=10\sqrt[3]{2}[/tex]

Therefore, minimum value x = [tex]x=10\sqrt[3]{2}[/tex]

Find the value of x that makes m∥n. PLEASEE HELP

Answers

Answer:

Step-by-step explanation:

143=5x+13(being corresponding angles)

143-13=5x

130/5=x

26=x

Answer:  26

=======================================================

Explanation:

The angles shown are corresponding angles. Notice how they are in the northeast corner of their respective four-corner configuration.

If m is parallel to n, then the corresponding angles are congruent, and we can say...

5x+13 = 143

5x = 143-13 .... subtract 13 from both sides

5x = 130

x = 130/5 .... divide both sides by 5

x = 26

So taking this logic in reverse: if x = 26, then that leads to 5x+13 equal to 143, making the corresponding angles congruent. Therefore, it would lead to lines m and n being parallel.

3
Find the missing angle.
20
180°
A
100°
B
50°
80°
D 70°

Answers

The three angles have to add up to 180. You already have 2 angles. The answer is 80.


What is
[tex] {5}^{7} [/tex]

Answers

35 because you multiply 5times 7

Answer:

78,125

Step-by-step explanation:

5 × 5 × 5 × 5 × 5 × 5 × 5 = 78125

---------------------------------------------------------------------------------------------------------------

Have a good day :)

Write the fraction as a decimal and a percent. 13/9​

Answers

Answer:

Decimal form = 1.44

Fraction form = 144/100

Hope this helps!

percent: 144.44%

decimal: 1.4444444444444

What is the value of 11g - 9k + 3 when g = 9 and k = 11?
Neatly show your work.

Answers

Answer:

3

Step-by-step explanation:

11g - 9k + 3

Let g = 9 and k =11

11 * 9 - 9*11 +3

Multiply

99 - 99 +3

Add

3

Answer:

3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Step-by-step explanation:

Step 1: Define

Identify

11g - 9k + 3

g = 9

k = 11

Step 2: Evaluate

Substitute in variables:                                                                                     11(9) - 9(11) + 3Multiply:                                                                                                             99 - 99 + 3Subtract:                                                                                                            3

p-8=3 can some one help me

Answers

Answer:

p=3+8=11

Step-by-step explanation:

Answer:

p = 11

Step-by-step explanation:

add 8 to both sides of the equation, so p = 3 + 8

p = 11

What percent of 8 is 6? pls give a detailed explanation thanks

Answers

Answer:

x/100 x 8 = 6

8x/100 = 6

x100    x100

8x = 600

Divide by 8 on both sides:

X = 75

Consider a percent out of 100. 'Of' meaning multiplication. 'is' meaning equal to that number.

(unknown number/percent)x/100 x 8(of 8) = 6(is 6)

Which of the following is the graph of (x + 3)2 + (y - 1)2 = 9? A B с 2. 2 2 2 4 -2 4 2 -2 2 2 4 2.​

Answers

The third one is the correct graph for the equation

hope it helps !!

The equation  [tex]\left(x-3\right)^{2}+\left(y-1\right)^{2}=3^{2}[/tex]  is the equation of a circle. Graph B shows the given equation.

What is a graph?

A diagram depicting the relationship between two or more variables, each measured along with one of a pair of axes at right angles.

The standard equation of the circle is;

[tex]\left(x-h\right)^{2}+\left(y-k\right)^{2}=r^{2}[/tex]

Where,

(h,k) are the coordinates of points on the x and y-axis.

r is the radius

The equation  [tex]\left(x-3\right)^{2}+\left(y-1\right)^{2}=3^{2}[/tex]  is the equation of a circle.

Hence, graph B shows the given equation.

To learn more about the graph, refer to the link;

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please help ASAP! 7th grade

Answers

Since their were no numbers to the questions i had to write it by the problem

Circle with 9 feet question

C=2(pi)r or C=(pi)d

Circular table question

A=(pi)r^2

Interest question

I=Prt

Volume of a rectangular prism

V=Bh

Triangular pyramid

V=1/3Bh

Returns on stock X are listed below: Period 1 2 3 4 5 6 7 Stock X 6% 5% -2% 10% 3% 8% -4% What is the mean of the data?

Answers

Answer:

The mean of the data is of 3.7143%.

Step-by-step explanation:

Mean of the data:

Sum of all returns divided by the number of returns.

Returns:

6% 5% -2% 10% 3% 8% -4%

7 returns.

Sum: 6 + 5 - 2 + 10 + 3 + 8 - 4 = 26%

Mean: 26%/7 = 3.7143%

The mean of the data is of 3.7143%.

35 POINTS!!!!

Every morning, Jorge runs a circular path that has a radius of 42 ft. How far does Jorge run if he does one lap around the track? Round your answer to the nearest foot. Use π=3.14.

A. 264 ft
B. 66 ft
C. 5,539 ft
D. 132 ft

Answers

A) 264 ft would be how far he does one lap around the track

what question is being asked ?​

Answers

Answer:

4 meters

Step-by-step explanation:

Assuming that the garden is a rectangular garden, its area would be length ×width.

Let the length be L meters and the width be W meters.

Area= L ×W

48= LW -----(1)

Given that the length is 3 times the width,

L= 3W -----(2)

Substitute (2) into (1):

48= 3W(W)

3W²= 48

Divide both sides by 3:

W²= 48 ÷3

W²= 16

Square root both sides:

[tex]W = \sqrt{16} [/tex]

W= 4 (reject negative as width cannot be a negative number)

Thus, the width of the garden is 4 meters.

Hey help me out please?

Answers

Answer:

I believe it is C

It's the only one that makes sense

An equation with no solutions
3x + 7 = X + 3

Answers

Answer:

X = -2

Step-by-step explanation:

Hope this helps

please help! answer and step by step explanation needed

Answers

Answer:

Step-by-step explanation:

Due to the equation [tex]y = mx+c[/tex],

y = y

mx = [tex]\frac{2}{5}x[/tex]

c = -7

Hence, from 'mx',

m = 2/5

Hence, the slope is 2/5

Feel free to mark it as brainliest :D

Answer:

slope is

[tex] \frac{2}{5} [/tex]

Step-by-step explanation:

from the linear equation we consider the Cof of x is slope Y = a x ± b a is slope and b is intercept - y then 2/5 is slope and -7 is intercept

ASAP
-WILL MARK BRIANIST

Answers

Answer:

25 + x = y

Step-by-step explanation:

Answer:

25+x=y

Step-by-step explanation:

25 plus the birthday cards(x)= total cards(y)

pls help i need help

Answers

Answer:

Put x's on the numbers on the line that are above the line

Step-by-step explanation:

I BELIVE IN YOU

it’s the box closets to the top

a chord 30cm long is 20cm from the centre of a circle. Calculate the length of a chord which is 24cm from the centre. please show workings​

Answers

The length of a chord which is 24cm from the Centre is: 14 cm

How to find the length of the chord?

Applying the Pythagorean theorem to the two right angle triangles that will be formed gives the radius of the circle from the first condition as:

R = √[(30/2)² + 20²]

R = √(15² + 20²)

R = √625

R = 25 cm

The length L of the another chord is calculated as:

L/2 = √(R² - 24²)

L/2 = √(25² - 24²)

L/2 = √49

L/2 = 7

L = 14 cm

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PLSSS HELP ASAP I NEED HELP

Answers

Answer: 39.4 m^2


Explanation:
The area of a circle is pi * radius squared. The diameter is 4 m, the radius is half the diameter so for the equation the radius is 2 m.

Pi times 2 is 6.28 (remember that pi is roughly 3.14), then square that sum of 6.28.

6.28^2= 39.4384

The answer is 39.44 but the answer must be rounded to the nearest tenth, 39.4384 is 39.4 rounded to the nearest tenth.

Jean took out a 5- year car loan of Rs 600 000.
He paid back a total of Rs 840 000.
What simple interest rate did he pay for this load?

Answers

interest= 840000-600000= 240000

P= 600000

R=?

t= 5 yrs

I = prt

240000 = 600000 × r × 5

r= 240000/600000×5

r = 0.08

interest rate = 0.08× 100 = 8%

A 25.5 foot ladder rests against the side of a house at a point 24.1 feet above the ground. The foot of the ladder is x feet from the house. Find the value of x to one decimal place.

Answers

Answer:

8.3

Step-by-step explanation:

Use the pythagorean theorem: a2 + b2 = c2 a2 would be 24.1 and c2 would be 25.5. square them then subtract a2 from b2. then find the square root of your answer which is 8.3

Find the distance from point A(2,-1) to the line y=-x+4

Answers

9514 1404 393

Answer:

  (3/2)√2 ≈ 2.1213 units

Step-by-step explanation:

The distance d from point (x, y) to line ax+by+c = 0 is given by ...

  d = |ax +by +c|/√(a^2 +b^2)

We can write the equation of the line as ...

  x + y -4 = 0

so the distance is ...

  d = |x + y - 4|/√(1^2 +1^2)

For point (x, y) = (2, -1), the distance is ...

  d = |2 +(-1) -4|/√2 = 3/√2 = (3√2)/2

The distance from A(2, -1) to the line y = -x +4 is (3√2)/2 units.

Which expression is equivalent to (2x+3)(3x2−2x+5)?

Answers

Answer:

See the steps below:)

Step-by-step explanation:

Expression is equivalent to (2x+3)(3x²−2x+5) is 6x³+5x²+4x+15.

What are equivalent expressions ?

An expression can be of many types numerical expressions, Algebraic expressions.We can also form these mathematical expressions from a given statement or by observing a real world scenario.

Equivalent expressions are same expressions in different forms.To check whether an expression is equivalent to another expression or not we just need to do some algebraic manipulations.Like distributing or taking common and other algebraic and arithmetic operations.

According to the given problem we have to write an expression which is equivalent to the expression (2x+3)(3x²-2x+5).

(2x+3)(3x²-2x+5)

= (2x+3)(3x²-2x+5)

=2x(3x²-2x+5)+3(3x²-2x+5)                                (now we will distribute)

=6x³-4x²+10x+9x²-6x+15

=6x³+5x²+4x+15.

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What is the area of a square if the base is 4.25ft and the height is 4.25 ft?

Answers

Answer:

18.0625 ft²

Step-by-step explanation:

4.25 × 4.25

18.0625 ft²

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