A dog ran along a fence 10 times. The fence is 5 feet 3 inches long. How far did the dog travel? (12 inches = 1 foot)

Answer:

75,000,012

Step-by-step explanation:

enjoy, i guess

Step-by-step explanation:

Given

-45 < 5(p-2)

Dividing both sides by 5

9 < p - 2

Adding two on both sides

9 + 2 < p - 2 + 2

11 < p

or

p > 11

Hope it will help :)❤

Answer:

x = 3 or x = 8

Step-by-step explanation:

An equation for the pictured graph and the equation for the pictured graph in factored form is: y = rs - r - s + 1.

Let's assume the equation for the graph in factored form is: y = a(x - r)(x - s), where 'a' is a constant and 'r' and 's' are the roots of the equation (x-intercepts of the graph). Since we are given that the graph passes through the points (0, -2) and (1, 0), we can use this information to find the values of 'r' and 's.'

Using the point (0, -2):

When x = 0, y = -2.

We can substitute these values into the equation:

-2 = a(0 - r)(0 - s)

Simplifying, we get: -2 = a(-r)(-s) or -2 = ars.

Using the point (1, 0):

When x = 1, y = 0.

Substituting these values into the equation:

0 = a(1 - r)(1 - s)

Simplifying, we get: 0 = a(1 - r)(1 - s).

Now, we have two equations:

-2 = ars (Equation 1)

0 = a(1 - r)(1 - s) (Equation 2)

From Equation 1, we can solve for 'a' in terms of r and s:

a = -2 / rs.

Now, substitute this value of 'a' into Equation 2:

0 = (-2 / rs)(1 - r)(1 - s).

To make further progress, we can divide both sides by -2:

0 = (1 / rs)(1 - r)(1 - s).

Next, to eliminate the fractions, multiply both sides by rs:

0 = (1 - r)(1 - s).

Finally, expand the right side of the equation:

0 = 1 - s - r + rs.

The equation for the pictured graph in factored form is:

y = rs - r - s + 1.

To know more about graph here

https://brainly.com/question/17267403

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Answer:

[tex]x=2[/tex]

Step-by-step explanation:

First, let's multiply both sides by [tex]\sqrt{x+11}[/tex]. If we do this, we would have:

[tex]x-1=\frac{1}{\sqrt{x+11}}\cdot\sqrt{x+11}[/tex]

The [tex]\sqrt{x+11}[/tex] would cancel out and we would be left with:

[tex]x-1=1[/tex]

If we add 1 on both sides, we would get:

[tex]x=2[/tex]

Hope this helps!!!

Answer (x represents the first direction and the y represents the second direction):

I hope this helps!

Answer:

I don't know

Step-by-step explanation:

ok k ggceyubvsxhik n

Answer:

1) a8

2) 6^5

3) 7^2 b^8

4) 30k^6 h^8

5) y^9/3x^2

Answer:

a) Malvern - Sheridan - Pine Bluff

b) Camden - Fordyce - Pine Bluff

c) Benton - Malvern - Sharidan - Arkadepia

d) Benton - Malvern - Sharidan - Arkadepia - Gurden - Camden - Fordyce

e) Benton - Malvern - Sharidan - Arkadepia - Gurden - Camden

Step-by-step explanation:

P.S - The exact question is -

Given - According to a map of Arkansas, a number of good roads connect

some of the towns south of Little Rock. The road between

Malvern and Benton is 23 miles long, and between Benton and Pine

Bluff is 62 miles long. The road between Malvern and Sheridan is

28 miles long, and then from Sheridan to Pine Bluff is 22 miles

long. Arkadelphia is connected to two towns: it is 12 miles from

Gurden and 21 miles from Sheridan. Fordyce has three roads to

these towns: 45 miles to Pine Bluff, 39 miles to Sheridan, and 27

miles to Camden. The road from Gurden to Camden is 38 miles.

To find - Unfortunately, the road from Fordyce to Sheridan is closed due to

dangerous road conditions caused by the recent bad weather. Find

the shortest route between each pair of towns:

a) Malvern and Pine Bluff

b) Camden and Pine Bluff

c) Benton and Arkadelphia

d) Fordyce and Malvern

e) Benton and Camden

Proof -

The figure is as follows :

a)

Shortest route between Malvern and Pine Bluff :

Firstly, put all the vertices to  ∞

Start from Malvern ,

Check the shortest distance from the corresponding vertices of Malvern.

Shortest Distance = min { Malvern - Benton, Malvern -Sheridan }

                              = min { 23, 28 } = 23

⇒Shortest distance is 23 ( Malvern -Benton )

Now,

Check shortest distance from Benton and Malvern

Shortest Distance = min { Benton - Pine Bluff, Malvern -Sheridan }

                              = min { 62, 28 } = 28

⇒Shortest distance is 28 ( Malvern -Sheridan )

Now,

Check shortest distance from Benton and Sheridan

Shortest Distance = min { Benton - Pine Bluff, Sheridan - Pine-Bluff}

                              = min { 85, 50 } = 50

⇒Shortest distance is 50 ( Sheridan - Pine-Bluff )

So,

By back tracking , we get

Shortest Route be -

Malvern - Sheridan - Pine Bluff

And the Shortest distance be = 50 miles

b)

Shortest Route between Camden and Pine Bluff

From Camden -

Shortest Distance = min {Camden-Fordyce, Camden-Gurden }

                              = min { 27, 38 } = 27

⇒Shortest Distance = 27 (Camden-Fordyce )

Now,

Check Shortest distance from Camden and Fordyce

Shortest Distance = min { Camden-Gurden, Fordyce-Pine Bluff }

                              = min { 38, 72 } = 38

⇒Shortest Distance = 38 ( Camden-Gurden )

Now,

Check Shortest Distance from Gurden and Fordyce

Shortest Distance = min { Gurden-Arkadepia, Fordyce-Pine Bluff }

                              = min { 50, 72 } = 50

⇒Shortest Distance = 50 ( Gurden-Arkadepia )

Now,

Check Shortest Distance from Arkadepia and Fordyce

Shortest Distance = min { Arkadepia - Sharidan, Fordyce-Pine Bluff }

                              = min { 71, 72 } = 71

⇒Shortest Distance = 71 ( Arkadepia - Sharidan )

Now,

Check Shortest Distance from Sharidan and Fordyce

Shortest Distance = min { Sharidan - Pine Bluff , Fordyce-Pine Bluff }

                              = min { 93, 72 } = 72

⇒Shortest Distance = 72 ( Fordyce-Pine Bluff )

So, By Back tracking , we get

Shortest route be

Camden - Fordyce - Pine Bluff

Shortest Distance be 72 miles

c)

Shortest route between  Benton and Arkadelphia

By applying the same method ,

If we start from Benton and by using Pine bluff lane, distance be 62 + 45 + 27 + 38 + 12 = 184 miles

And

If we start from Benton and by using Malvern lane, distance be 23 + 28 + 21 = 72 miles

So,

Shortest Route be -

Benton - Malvern - Sharidan - Arkadepia

Shortest distance be 72 miles

d)

Shortest route between  Fordyce and Malvern

By applying the same method ,

If we start from Malvern and by using Benton lane, distance be 23 + 62 + 45 = 130 miles

And

If we start from Malvern and by using Sharidan lane, distance be 28 + 21 + 12 + 38 + 27 = 126 miles

So,

Shortest Route be -

Benton - Malvern - Sharidan - Arkadepia - Gurden - Camden - Fordyce

Shortest distance be 126 miles

e)

Shortest route between Benton and Camden

By applying the same method ,

If we start from Benton and by using Pine Bluff lane, distance be 62 + 45 + 27 = 134 miles

And

If we start from Benton and by using Malvern lane, distance be 23 + 28 + 21 + 12 + 38 = 122 miles

So,

Shortest Route be -

Benton - Malvern - Sharidan - Arkadepia - Gurden - Camden

Shortest distance be 122 miles

Answer:

£213.64

Step-by-step explanation:

You do 196(0.09)

That's 17.64

The you add the two

196+17.64

The way I got 9 was from 9%.

To make it in decimal form you have to move the decimal over two places.

Hope this helps

Answer:

I believe it is 67 degrees

Step-by-step explanation:

Since all the angles in a triangle add up to 180 degrees, you can subtract 78 and 35 from 180 to get 67.

Answer:

TanX = 9/12, WX = 15, TanW = 12/9, CosX = 12/15

Step-by-step explanation:

Tan = opposite/adjacent, so 9/12

WX is the missing side, so solve it by taking the square root of (9^2) +( 12^2) and you get 15

Tan again, is opposite/adjacent, so 12/9

Cos is adjacent/hypotenuse, so 12/15

Hopefully this helps! Let me know if you have any questions

Answer: your anawer is D

Step-by-step explanation:

Answer:

9.5

Step-by-step explanation:

[tex]\frac{x}{19} = sin 30^o\\\implies \frac{x}{19} = 0.5\\\implies x = 19 * 0.5\\\implies x = 9.5[/tex]

1. 810  

2. 89%

3. 624

4. 100

5. 960

6. 165

Answer:

2

Step-by-step explanation:

its hard to type

Answer

1953. 64

Step-by-step explanation:

Answer:

The answer is "0.6227 and 0.5971".

Step-by-step explanation:

[tex]\to p(x\leq 2)=p(0)+p(1)+p(2)[/tex]

                  [tex]=e^{-2.2}(1+2.2^{1}+\frac{2.2^2}{2!})\\\\=0.6227[/tex]

[tex]\to x \sim emp(\frac{1}{2.2})\\\\\to f(x)=\frac{1}{2.2} emp1-\frac{x}{2.2}[/tex]

[tex]\to p(x \leq 2)=\int^{2}_{0} \frac{1}{2.2} emp1(-\frac{x}{2.2}\ dx[/tex]

                  [tex]=1-emp1-2|2.2\\\\=0.5971[/tex]

Answer: $ 4.54

Step-by-step explanation:

Answer:

Step-by-step explanation:

x² - 5.2x + 2

Discriminant = (-5.2)² - 4 ⋅ 1 ⋅ 2 = 19.04

Answer:

[tex]\displaystyle m=\frac{1}{4}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Point (80, 20)

Point (120, 30)

Step 2: Find slope m

Simply plug in the 2 coordinates into the slope formula to find slope m

Answer:

216 cubic inches

Step-by-step explanation:

(9)(3)(3)=81

(3)(3)(9)=81

(3)(3)(6)=54

81+81+54=216

So, it's 216 cubic inches in volume.

Answer:

-5/8x -5/8y

Step-by-step explanation:

Use the distributive property to expand

Answer:

6) a) y = −7/2 x , b) y = −1/2 x , c) y = −5/4 x , d) y = −17/10 x

Step-by-step explanation:

For question 5 it needs to have the input and output values or having a domain and range value. So it can't be solved.

(there's an error in this question)

As for question 6,

a) with coordinate (x,y) = (-2,7)

1. To find the equation of a line or gradient,

first find the slope via the formula: -> m = (y2-y1/x2-x1)

If we let (0,0) ➡️ (x1,y1) and

(-2,7) ➡️ (x2,y2) then,

m = (7-0/-2-0) = -7/2 ⬅️ This is the slope of the line/gradient

Now that we have found the slope we can find the equation via the point-slope formula:

(y−y1) = m(x−x1) ;

2. Substituting the slope = -7/2 for

m and any of the two coordinates given. I will use (0,0) be make things easier. We let (0,0) → (x1,y1)

Thus,

y−0 = −7/2 (x-0)

If we simplify this, we simply get

y = −7/2 x ← This is our equation for coordinate (-2,7)

b) with coordinate (x,y) = (2,-1)

1. To find the equation of a line or gradient,

first find the slope via the formula: -> m = (y2-y1/x2-x1)

If we let (0,0) ➡️ (x1,y1) and

(2,-1) ➡️ (x2,y2) then,

m = (-1-0/2-0) = -1/2 ⬅️ This is the slope of the line/gradient

Now that we have found the slope we can find the equation via the point-slope formula:

(y−y1) = m(x−x1) ;

2. Substituting the slope = -1/2 for

m and any of the two coordinates given. I will use (0,0) be make things easier. We let (0,0) → (x1,y1)

Thus,

y−0 = −1/2 (x-0)

If we simplify this, we simply get

y = −1/2 x ← This is our equation for coordinate (2,-1)

c) with coordinate (x,y) = (4,-5)

1. To find the equation of a line or gradient,

first find the slope via the formula: -> m = (y2-y1/x2-x1)

If we let (0,0) ➡️ (x1,y1) and

(2,-1) ➡️ (x2,y2) then,

m = (-5-0/4-0) = -5/4 ⬅️ This is the slope of the line/gradient

Now that we have found the slope we can find the equation via the point-slope formula:

(y−y1) = m(x−x1) ;

2. Substituting the slope = -5/4 for

m and any of the two coordinates given. I will use (0,0) be make things easier. We let (0,0) → (x1,y1)

Thus,

y−0 = −5/4 (x-0)

If we simplify this, we simply get

y = −5/4 x ← This is our equation for coordinate (4,-5)

d) with coordinate (x,y) = (10,-17)

1. To find the equation of a line or gradient,

first find the slope via the formula: -> m = (y2-y1/x2-x1)

If we let (0,0) ➡️ (x1,y1) and

(2,-1) ➡️ (x2,y2) then,

m = (-17-0/10-0) = -17/10 ⬅️ This is the slope of the line/gradient

Now that we have found the slope we can find the equation via the point-slope formula:

(y−y1) = m(x−x1) ;

2. Substituting the slope = -17/10 for

m and any of the two coordinates given. I will use (0,0) be make things easier. We let (0,0) → (x1,y1)

Thus,

y−0 = −17/10 (x-0)

If we simplify this, we simply get

y = −17/10 x ← This is our equation for coordinate (10,-17)