Let's begin by listing out the information given to us:
Amount spent = $240
discount = 25%
[tex]\begin{gathered} Pay=Amountspent-(AmountSpent\cdot discount)_{} \\ P=240-(240\cdot\frac{25}{100})=240-60 \\ P=180 \end{gathered}[/tex]Therefore, the customer paid $180 for his purchase
Abner and Xavier can make a loaf of bread from scratch in 3 hours. This includes
preparation and baking time. Prep time is 135 minutes. For how long does the bread
bake?
Check Your Understanding- Question 1 of 2
Fill in the blanks to identify the steps needed to solve the problem.
Start by converting the total time to minutes. The conversion factor from hours to
60 minutes
minutes is
1 hour
It takes
Attempt 2 of 2
810 minutes in total to make the bread.
Answer:
the bread bakes for 45 minutes (yum)
I need help with this practice problem I’m having trouble
Part N 1
[tex]2^{(6\log _22)}=12[/tex]Apply property of log
[tex]\log _22=1[/tex]so
[tex]\begin{gathered} 2^{(6\cdot1)}=12 \\ 2^6=12\text{ -}\longrightarrow\text{ is not true} \end{gathered}[/tex]the answer is false
Part N 2
we have
[tex]\frac{1}{4}\ln e^8=\sqrt[4]{8}[/tex]applying property of log
[tex]\frac{1}{4}\ln e^8=\frac{8}{4}\ln e=2\ln e=2[/tex]so
[tex]2=\sqrt[4]{8}\text{ ---}\longrightarrow\text{ is not true}[/tex]the answer is false
Part N 3
we have
[tex]10^{(\log 1000-2)}=10[/tex]log1000=3
so
log1000-2=3-2=1
10^1=10 -----> is true
the answer is trueChoose all equivalent expression ( s). (4) ^ (3z ^ 2); (4) ^ (- 3x ^ 2); (1/4) ^ (3z ^ 2); (pi/4) ^ (3x)
Among the given options, no one is an equivalent expression.
What is an equivalent expression?
Expressions are said to be equivalent if they do the same thing even when they have distinct appearances. When we enter the same value(s) for the variable, two algebraic expressions that are equivalent have the same value (s).
In the given options no one satisfies the property of an equivalent expression.
Therefore, among the given options, no one is an equivalent expression.
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The next model of a sports car will cost 11.5% less than the current model. The current model costs $59,000. How much will theprice decrease in dollars? What will be the price of the next model?
we are given that a car cost $ 59000 and the price will decrease by 11.56%, therefore, the amount it will decrease is equivalent to:
[tex]59000\times\frac{11.56}{100}=6820.4[/tex]Therefore, the price will decrease by $6820.4. The total price will be then:
[tex]59000-6820.4=52179.6[/tex]Therefore, the price will be $52179.6
A wind-up toy car can travel 5 yards in about 3 minutes. If the car travels at a constant speed, then how many minutes will it takes to travel 40 meters? State your answer to the nearest minute.( 1 yard = 0.92 meters)
A) 20
B) 22
C) 24
D) 26
Answer: D
Step-by-step explanation:
0.92 metres = 1 yard
40 metres = 43.5 yard [tex](\frac{40 * 1}{0.92})[/tex]
5 yards : 3 minutes
43.5 yards : 26.1 minutes [tex](\frac{43.5*3}{5})[/tex]
26.1 mins ≈ 26 mins
How many gallons of a 60% antifreeze solution must be mixed with 80 gallons of 20% antifreeze to get a mixture that is 50% antifreeze?
Given
gallons which have 20% antifreeze solution = 80
Final concentration = 50% antifreeze solution
Find
Number of galloons with 60% antifreeze solution
Explanation
Let the number of gallons with 60% antifreeze solution = x
According to question
0.6x+0.2(80) = 0.50(x+80)
0.6x+16=0.5x+40
0.1x=24
x=240
Final Answer
Hence 240 gallons of 60% antifreeze solution will be required
Sam graduation picnic cost $13 for decoration plus an additional $5 for each attendee.at most how many attendees can there be if sam budgets a total of $33 for his graduation picnic?
Given:
The cost of graduation picnic = $13 for decoration plus an additional $5 for each attendee
Let the number of attendance = x
we need to find x when sam budgets a total of $33 for his graduation picnic
So,
[tex]13+5x=33[/tex]solve for x, subtract 13 from both sides:
[tex]\begin{gathered} 13+5x-13=33-13 \\ 5x=20 \end{gathered}[/tex]divide both sides by 5
[tex]\begin{gathered} \frac{5x}{5}=\frac{20}{5} \\ \\ x=4 \end{gathered}[/tex]So, the answer is:
The number of attendees = 4
Create a graph system of linear equations that model this situation.
x represents the number of packages of coffee sold
y represents the number of packages of pastry sold
We were the cost of a package of coffee is $6 and the cost of a package of pastry is $4. If the total amount made from selling x packages of coffee and y packages of pastry is $72, then the equation representing this scenario is
6x + 4y = 72
Also, we were told that she sold 2 more packages of coffee than pastries. This means that
x = y + 2
Thus, the system of linear equations is
6x + 4y = 72
x = y + 2
We would plot these equations on the graph. The graph is shown below
The red line represents x = y + 2
The bu line represents x = y + 2
Graph this steph function on the coordinate grid please help I don’t understand!
Given:
[tex]f(x)=\begin{cases}{-5\text{ }if\text{ }-5Required:
We need to graph the given step function.
Explanation:
From the given data we have, -5,-1, and 2 are the respective values of y.
[tex]-5The draw annulus to denote the points do not lie on the line since there is a symbol '<'.
Final answer:
Describe using words in a sentence the transformations that must be applied to the graph of f to obtain thegraph of g(x) = -2 f(x) + 5.
we have
f(x)
and
g(x)=-2f(x)+5
so
step 1
First transformation
Reflection about the x-axis
so
f(x) -----> -f(x)
step 2
Second transformation
A vertical dilation with a scale factor of 2
so
-f(x) ------> -2f(x)
step 3
Third transformation
A translation of 5 units up
so
-2f(x) -------> -2f(x)+5
Given P = $8945, t= 5 yearsand r= 9% compounded monthly. Is the correct compound interest formula to calculate to the nearest cent to the value of a
For this question, we use the following formula for compounded interest:
[tex]P=a(1+0.09)^{5\cdot12}[/tex]Solving for a we get:
[tex]\begin{gathered} a=\frac{8945}{(1+0.09)^{60}} \\ a=\frac{8945}{(1.09)^{60}} \\ a=50.81 \end{gathered}[/tex]Lukalu is rappelling off a cliff. The parametric equations that describe her horizontal and vertical position as a function of time are x ( t ) = 8 t and y ( t ) = − 16 t 2 + 100 and . How long does it take her to reach the ground? How far away from the cliff is she when she lands? Remember to show all of the steps that you use to solve the problem.
SOLUTION
Now the ground is assumed to be 0, so we have that
[tex]y(t)=0[/tex]So, that means we have
[tex]\begin{gathered} y(t)=-16t^2+100 \\ 0=-16t^2+100 \\ 16t^2=100 \\ t^2=\frac{100}{16} \\ t=\sqrt{\frac{100}{16}} \\ t=\frac{10}{4} \\ t=2.5\text{ seconds } \end{gathered}[/tex]Now, we have found t, which is how long it takes to get to the ground, you can plug it into x(t) to find the horizontal distance travelled, we have
[tex]\begin{gathered} x(t)=8t \\ x(2.5)=8\times2.5 \\ =20\text{ feet } \end{gathered}[/tex]Hence it takes her 2.5 seconds to reach the ground
And she is 20 feet away from the cliff
17. What is the value of x in the rhombusbelow?AC(x+ 40)B3x⁰D
ANSWER
x = 35 degrees
EXPLANATION
Given tthat
[tex]\begin{gathered} \text{ m Follow the steps below to find the value of xRecall, that the sum of m[tex]\text{ m < C + m Therefore, x is 35 degrees
√54²-43.8² +2(7)
What is the height of the space Lilly needs? Round to the nearest hundredth.
18.52
24.20
45.58
235.06
√54²-43.8² +2(7)
54-1918.44+14
-1850.44
the angle t is an acute angle and sin t and cost t are given. Use identities to find tan t , csc t, sec t, and cot t. where necessary, rationalize demonstrations.sin t= 7/25, cos t= 24/25
Answer:
tan t = 7/24
csc t = 25/7
sec t = 25/24
cot t = 24/7
Explanation:
From the question, we're told that sin t = 7/25 and cos t = 24/25. Since we know the identities of sine and cosine to be as follows we can go ahead and determine tan t as shown below;
[tex]\begin{gathered} \sin t=\frac{opposite}{\text{hypotenuse}}=\frac{7}{25} \\ \cos t=\frac{adjacent}{\text{hypotenuse}}=\frac{24}{25} \\ \therefore\tan t=\frac{opposite}{\text{adjacent}}=\frac{7}{24} \end{gathered}[/tex]Let's go ahead and find cosecant t (csc t);
[tex]\csc t=\frac{1}{\sin t}=\frac{1}{\frac{7}{25}}=1\times\frac{25}{7}=\frac{25}{7}[/tex]For sec t, we'll have;
[tex]\sec t=\frac{1}{\cos t}=\frac{1}{\frac{24}{25}}=1\times\frac{25}{24}=\frac{25}{24}[/tex]For cot t;
[tex]\cot t=\frac{1}{\tan t}=\frac{1}{\frac{7}{24}}=1\times\frac{24}{7}=\frac{24}{7}[/tex]the graph of each function is shown. write the function in factored form . do not include complex numbers
We can see from the picture that the function f(x) has roots in x = -5 and x = 5. Using sintetic division with x = 5, we get:
then, we can write the function as:
[tex]f(x)=(x-5)(2x^3+11x^2+8x+15)[/tex]since we know that another root is x = -5,we can use again the sintetic division on the right factor:
therefore, the function in factored form is:
[tex]f(x)=(x-5)(x+5)(2x^2+x+3)[/tex]Consider the numbers below. Use two of the numbers to make the greatest sum, greatest difference, greatest product, and greatest quotient.-5 1/23.75-20.8-411.25
Given data,
[tex]-5\frac{1}{2},\text{ 3.75,-20.8,-4,11.25}[/tex]For the greatest sum,
We need to add the two large number.
Thus,
[tex]11.25+3.75=15[/tex]For the greatest difference, we need to substract the largest number from the smallest,
Thus,
[tex]11.25-(-20.8)=32.05[/tex]To find the greatest product,
we should multiply the two great numbers.
[tex]11.25\times3.75=42.1875[/tex]To find the greatest quotient,
we need to divide the largerst number by the smallest
[tex]\frac{11.25}{3.75}=3[/tex]The table graph shows the population of Oregon Mule Deer between 1980 and 2018,
84 - 250
94 - 237.50
04 - 245
14 - 230.50
18 - 173.50
What was the average population decline between 1984 and 2018?
B. The average rate of population decline between 2004 and 2014 is 1.45 thousand deer per year. If the population continued to decline at this rate, between which 2 year period would the population have reached 225 thousand deer? Explain reasoning.
C. Calculate and compare the average rate of change of the population from 1994 to 2004 to that from 2004 to 2014. Explain what this means in terms of the population of deer.
Using the average rate of change, it is found that:
A. The average population decline between 1984 and 2018 was of 2.25 thousand deer a year.
B. The population would have reached 225 thousand deer between 2017 and 2018.
C.
The rates are as follows:
1994 to 2004: 0.75 thousand deer a year.2004 to 2014: -1.45 thousand deer a year.Meaning that between 1994 and 2004 there was a increase in the population of deer, and from 2004 to 2014 there was a decrease.
What is the average rate of change of a function?The average rate of change of a function is given by the change in the output divided by the change in the input. Hence, over an interval [a,b], the rate is given as follows:
[tex]r = \frac{f(b) - f(a)}{b - a}[/tex]
For 1984 and 2018, we have that:
f(1984) = 250.f(2018) = 173.50.Hence the rate is:
r = (173.50 - 250)/(2018 - 1984) = -2.25 thousand deer a year.
For item b, the situation is modeled by a linear function, as follows:
D(t) = 230.50 - 1.45t.
The population would be of 225 thousand deer when D(t) = 225, hence:
230.50 - 1.45t = 225
1.45t = 5.5
t = 5.5/1.45
t = 3.79.
Hence between the years of 2017 and 2018.
For item c, the rates are as follows:
1994 to 2004: (245 - 237.50)/10 = 0.75 thousand deer a year -> increase.2004 to 2014: (230.50 - 245)/10 = -1.45 thousand deer a year -> decrease.More can be learned about the average rate of change at https://brainly.com/question/11627203
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Ariel makes $35 a day. How much can she get for 1/7 of a day? Ariel will earn ____ for 1/7 of the day.
We can calculate how much she get for 1/7 of a day by multiplying the daily pay rate by 1/7:
[tex]E=\frac{1}{7}\cdot35=\frac{35}{7}=5[/tex]Answer: Ariel will earn $5 for 1/7 of the day.
1/2+3/4+1/8+3/16+1/32+3/64
Answer:
105/64 or 1 41/64
Step-by-step explanation:
Math
Make common denominator of 64
:]
The first three terms of a sequence are
given. Round to the nearest thousandth
(if necessary).
4, 8, 12,..
Find the 40th term
Answer:
Step-by-step explanation:
Recall the formula for an arithmetic sequence: [tex]a_{n} =a_{1} +d(n-1)[/tex]
Where d is the common difference and a_1 is the first term of the sequence.
You are given :
a_1=4
a_2=8
a_3=12
Next is to find the common difference d.
To find the common difference, take the next term and subtract it from the current term.
a_2-a_1=8-4=4
Let try the next term start at a_2
a_3-a_2=12-8 =4
Do you see the pattern?
The patter is going up by 4 each time. So the common difference is 4 i.e d=4
Now we just need to plug into the generalize formula above and get
[tex]a_{n}=4+4(n-1)[/tex]
The question asked for the 40th term. Plug 40 into the formula and you will get:
[tex]a_{40}=4+4(40-1)=160[/tex]
I hope this helps!
The graph shows the distance, y, that a car traveled in x hours:A graph is shown with the x-axis title as Time in hours. The title on the y-axis is Distance Traveled in miles. The values on the x-axis are from 0 to 5 in increments of 1 for each grid line. The values on the y-axis are from 0 to 325 in increments of 65 for each grid line. A line is shown connecting ordered pairs 1, 65 and 2, 130 and 3, 195 and 4, 260. The title of the graph is Rate of Travel.What is the rate of change for the relationship represented in the graph? (1 point)
The rate of change is 65 miles per hour
Explanation:Given the ordered pairs (1, 65) and (2, 130)
The rate of change is given as:
[tex]\frac{y_2-y_1}{x_2-x_1}=\frac{130-65}{2-1}=\frac{65}{1}[/tex]The rate of change is 65 miles per hour
Solve the equation 20 +7k = 8(k + 2).
[tex]k=4[/tex].
Step-by-step explanation:1. Write the expression.[tex]20 +7k = 8(k + 2)[/tex]
2. Solve the parenthesis on the right hand side of the equation.[tex]20 +7k = 8k+16[/tex]
3. Subtract 20 from both sides of the equation.[tex]-20+20 +7k = 8k+16-20\\ \\7k = 8k-4[/tex]
4. Subtract 8k from both sides of the equation.[tex]7k-8k = 8k-4-8k\\ \\-k = -4[/tex]
5. Multiply both sides by "-1".[tex](-1)-k = -4(-1)\\ \\k=4[/tex]
6. Verify.[tex]20 +7(4) = 8((4) + 2)\\ \\20 +28 = 8(6)\\ \\48=48[/tex]
7. Express the result.[tex]k=4[/tex].
Answer:
k = 4
Step-by-step explanation:
a) Simplify both sides of the equation.
20 + 7k = 8(k + 2)
20 + 7k = (8)(k) + (8)(2)
20 + 7k = 8k + 16
7k + 20 = 8k + 16
b) Subtract 8k from both sides.
7k + 20 − 8k = 8k + 16 − 8k
−k + 20 = 16
c) Subtract 20 from both sides.
−k + 20 − 20 = 16 − 20
−k = −4
Divide both sides by -1.
-k/-1 = -4/-1
k = 4
Graph each pair of lines and use their slopes to determineif they are parallel, perpendicular, or neither.EF and GH for E(-2, 3), F(6, 1), G(6,4), and H(2,5)JK and LM for J(4,3), K(5, -1), L(-2, 4), and M(3,-5)NP and QR for N(5, -3), P(0, 4), Q(-3, -2), and R(4, 3)ST and VW for S(0, 3), T(0, 7), V(2, 3), and W(5, 3)
To find the slope of a line that passes through two points, we can use the following formula:
[tex]\begin{gathered} m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \text{ Where m is the slope and} \\ (x_1,y_1)\text{ and }(x_2,y_2)\text{ are two points which the line passes} \end{gathered}[/tex]Then, we have:
First pair of linesLine EF
[tex]\begin{gathered} (x_1,y_1)=E\mleft(-2,3\mright) \\ (x_2,y_2)=F\mleft(6,1\mright) \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{1-3}{6-(-2)} \\ m=\frac{1-3}{6+2} \\ m=\frac{-2}{8} \\ m=\frac{2\cdot-1}{2\cdot4} \\ m=-\frac{1}{4} \end{gathered}[/tex]Line GH
[tex]\begin{gathered} (x_1,y_1)=G\mleft(6,4\mright) \\ (x_2,y_2)=H\mleft(2,5\mright) \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{5-4}{2-6} \\ m=\frac{1}{-4} \\ m=-\frac{1}{4} \end{gathered}[/tex]Now, when graphing the two lines, we have:
If two lines have equal slopes, then the lines are parallel. As we can see, their slopes are equal, therefore the lines EF and GH are parallel.
Second pair of lines
Line JK
[tex]\begin{gathered} (x_1,y_1)=J\mleft(4,3\mright) \\ (x_2,y_2)=K\mleft(5,-1\mright) \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{-1-3}{5-4} \\ m=-\frac{4}{1} \\ m=-4 \end{gathered}[/tex]Line LM
[tex]\begin{gathered} (x_1,y_1)=L\mleft(-2,4\mright) \\ (x_2,y_2)=M\mleft(3,-5\mright) \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{-5-4}{3-(-2)} \\ m=\frac{-9}{3+2} \\ m=\frac{-9}{5} \end{gathered}[/tex]Now, when graphing the two lines, we have:
As we can see, the slopes of these lines are different, so they are not parallel. Let us see if their respective slopes have the relationship shown below:
[tex]\begin{gathered} m_1=-4 \\ m_2=-\frac{9}{5} \\ m_1=-\frac{1}{m_2} \\ -4\ne-\frac{1}{-\frac{9}{5}} \\ -4\ne-\frac{\frac{1}{1}}{\frac{-9}{5}} \\ -4\ne-\frac{1\cdot5}{1\cdot-9} \\ -4\ne-\frac{5}{-9} \\ -4\ne\frac{5}{9} \end{gathered}[/tex]Since their respective slopes do not have the relationship shown below, then the lines are not perpendicular.
Third pair of linesLine NP
[tex]\begin{gathered} (x_1,y_1)=N\mleft(5,-3\mright) \\ (x_2,y_2)=P\mleft(0,4\mright) \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{4-(-3)}{0-5} \\ m=\frac{4+3}{-5} \\ m=-\frac{7}{5} \end{gathered}[/tex]Line QR
[tex]\begin{gathered} (x_1,y_1)=Q\mleft(-3,-2\mright) \\ (x_2,y_2)=R\mleft(4,3\mright) \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{3-(-2)}{4-(-3)} \\ m=\frac{3+2}{4+3} \\ m=\frac{5}{7} \end{gathered}[/tex]Now, when graphing the two lines, we have:
Two lines are perpendicular if their slopes have the following relationship:
[tex]\begin{gathered} m_1=-\frac{1}{m_2} \\ \text{ Where }m_1\text{ is the slope of the first line and }m_2\text{ is the slope of the second line} \end{gathered}[/tex]In this case, we have:
[tex]\begin{gathered} m_1=-\frac{7}{5} \\ m_2=\frac{5}{7} \\ -\frac{7}{5}_{}=-\frac{1}{\frac{5}{7}_{}} \\ -\frac{7}{5}_{}=-\frac{\frac{1}{1}}{\frac{5}{7}_{}} \\ -\frac{7}{5}_{}=-\frac{1\cdot7}{1\cdot5}_{} \\ -\frac{7}{5}_{}=-\frac{7}{5}_{} \end{gathered}[/tex]Since the slopes of the lines NP and QR satisfy the previous relationship, then this pair of lines are perpendicular.
Fourth pair of lines
Line ST
[tex]\begin{gathered} (x_1,y_1)=S\mleft(0,3\mright) \\ (x_2,y_2)=T\mleft(0,7\mright) \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{7-3_{}}{0-0} \\ m=\frac{4}{0} \\ \text{Undefined slope} \end{gathered}[/tex]The line ST has an indefinite slope because it is not possible to divide by zero. Lines that have an indefinite slope are vertical.
Line VW
[tex]\begin{gathered} (x_1,y_1)=V\mleft(2,3\mright) \\ (x_2,y_2)=W\mleft(5,3\mright) \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{3-3_{}}{5-2} \\ m=\frac{0}{3} \\ m=0 \end{gathered}[/tex]Line VW has a slope of 0. Lines that have a slope of 0 are horizontal.
Now, when graphing the two lines, we have:
As we can see in the graph, the ST and VW lines are perpendicular.
You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard deviation is approximately
σ
=
50.2
. You would like to be 90% confident that your estimate is within 1.5 of the true population mean. How large of a sample size is required?
Using the sample size relation with the standard normal distribution, the required sample size is 3032 samples.
What is Normal distribution ?
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
Using the sample size relation with the standard normal distribution, the required sample size is 673 samples.
n = [(Z* × σ) / ME]²
ME = margin of error
Z* = Z critical at 90% = 1.645
Substituting the values into the equation :
n = [(Z* × σ) / ME]²
n = [(1.645 × 50.2) / 1.5]²
n = (82.6/ 1.5)²
n = 55.06
n ≈ 3032
Therefore, the Number of samples required is 3032 samples.
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Let Events A and B be described as follows:• P(A) = buying popcorn• P(B) = watching a movieThe probability that you watch a movie this weekend is 48% The probability of watching amovie this weekend and buying popcorn is 38%. If the probability of buying popcorn is 42%,are watching a movie and buying popcorn independent?
Solution:
Given that;
[tex]\begin{gathered} P(A)=42\%=0.42 \\ P(B)=48\%=0.48 \\ P(A\cap B)=38\%=0.38 \end{gathered}[/tex]To find out if watching a movie and buying a popcorn are independent, the formula is
[tex]\begin{gathered} P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{0.38}{0.48}=0.79166 \\ P(A|B)=0.79\text{ \lparen two decimal places\rparen} \end{gathered}[/tex]From the deductions above;
Hence, the answer is
[tex]No,\text{ because }P(A|B)=0.79\text{ and the }P(A)=0.42\text{ are not equal}[/tex]Write the fraction as a percent.34/100
Answer:
34%
Explanation:
To write the fraction as a percent we need to divide 34 by 100 and then multiply by 100%, so
34/100 x 100 = 0.34 x 100% = 34%
Therefore, 34/100 as a percent is 34%
When a number is divided by $5,$ the result is $50$ less than if the number had been divided by $6$. What is the number?
Answer:
1500$
Step-by-step explanation:
Answer: -1500
Step-by-step explanation: yes it is
Show all work to identify the asymptotes and state the end behavior of the function f(x) = 6x/ x - 36
Vertical asymptotes are when the denominator is 0 but the numerator isn't 0.
[tex]x-36=0 \implies x=36[/tex]
Since this value of x does not make the numerator equal to 0, the vertical asymptote is [tex]x=36[/tex].
Horizontal asymptotes are the limits as [tex]x \to \pm \infty[/tex].
[tex]\lim_{x \to \infty} \frac{6x}{x-36}=\lim_{x \to \infty}=\frac{6}{1-\frac{36}{x}}=6\\\\\lim_{x \to -\infty} \frac{6x}{x-36}=\lim_{x \to -\infty}=\frac{6}{1-\frac{36}{x}}=6\\\\[/tex]
So, the horizontal asymptote is [tex]y=6[/tex].
End behavior:
As [tex]x \to \infty, f(x) \to -\infty[/tex]As [tex]x \to -\infty, f(x) \to \infty[/tex].What I need to know is that what is 3.5x2
Answer:
7
Step-by-step explanation:
Just add 3.5 twice which is the same as multiplying it by 2
Answer:
7
Step-by-step explanation:
hope it helps and have a nice!!! :)
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