A crazy bus driver launches the bus out of the parking lot with an amazing acceleration of 1.5 m/s^2. He goes an incredible distance of 85 m before reaching the bus's maximum speed. How fast is the bus going after reaching top
speed?
1) 11 m/s
2) 16 m/s
3) 130 m/s
4) 255 m/s
5) Answer not shown

Work done on a 1500kg elevator by its cable to lift it 40m at a constant speed is 592000N.

The work done by a force is calculated as the product of the force(F) and the displacement of the object on which the force is acted.

Work done = F×d

downward forces are weight of lift and frictional force

upward force is only tension of string.

T = Frictional force + Mg

Mg = 1500× 9.8 = 14700N

given frictional force is 100N

So, Tension in string = (100+ 14700) N

= 14800N

work done by tension in lifting = tension force ×

displacement of lift

= 14800 × 40

= 592000N.

hence, work done on a 1500 kg elevator by its cable to lift it 40m at a constant speed is 592000N.

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The net force acting on the cart is 2 N in left direction.

The definition of force in physics is: The push or pull on a massed object changes its velocity.

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. Newton is the SI unit of force.

Jimi is pushing a large cart at work toward the left side of the store using 10N of force.

Jonah pushed the cart with 8 N of force toward the right side of the store.

Hence, the net force acting on the cart in left direction = ( 10 N - 8 N) = 2 N.

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A negative object so it takes in the charge object and nothing will happen until something else would touch it.

Electric charge is the property of a material that makes it feel a force when subjected to an electromagnetic field. Protons and electrons most typically carry positive and negative charges, which are the two forms of electric charges.

The basis of the SI system of physical units is the coulomb It is referred to as C. A coulomb is the unit of power that a one-ampere current can carry in one second.

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They are so distant that the parallax is too small to be measured since parallax varies inversely with distance.

Parallaxes can be measured accurately out to distances of approximately 100 light-years. The nearest galaxies are about 50,000 to 80,000 light-years from the Sun. Therefore, there is no perceptible change in the apparent position of any galaxy as we view it from opposite sides of Earth's orbit.

Because of the influences of the Earth's atmosphere, it is highly challenging to estimate parallax angles of less than 0.01 arcsec from Earth. Due to this, telescopes on Earth can only measure the distances to stars that are 1/0.01 or 100 parsecs distant.

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When we calculate a function's average rate of change over a certain interval, we are computing the average number of units that the function moves up or down per unit along the xx-axis.

Given the function and interval of interest (f(x)f(x) and [x ₁,x₂]), [x\s​₁,x₂ ]), our first step is to compute the value of our function at both ends of the interval. Then we plug those numbers and the interval's ends into our algorithm to calculate the average rate of change.

The average rate of change formula is

{x₂-x₁}

x f = x₂ x 1 f(x₂ )

​​within the interval [x₁,x ₂][x ₁,x ₂ ].

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In an experiment with n = 14 and preal = 0.10, then the power using a = 0.012 tail will be 0.997

Power is the capacity to shape or direct events, other people's behavior, or both. It is the ability to decide what to do and then do it. It might be either physical—like power—or mental—like wisdom. Power may also be social, political, or economic. It can be employed constructively, such as to effect change and defend human rights, or destructively, such as to repress and exert control. Power may be utilized to both bring about and stop change. Politics, economics, and culture all exhibit it since it is an essential component of all social relations.

N = 14

Mean, mu=0.10,

s=sqrt [0.10(1-0.10)/14]=0.08,

cumulative probability, 0.003,

Power=1-0.003=0.997

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You're in a boat with a big rock, in a swimming pool. You toss the rock overboard. Level of water will increase as of the mass of big rock to the level of the water in the pool.

The buoyancy of any floating object partially or totally submerged in a fluid can be computed thanks to Archimedes' principle. The weight of the thing alone exerts a downward mass on it. The upward or buoyant force acting on the object is what is meant by the aforementioned Archimedes' principle. The difference between the buoyant force and the object's weight is therefore the net force acting on it. In the event that this net force is positive, the item will rise; in the event that it is negative, the object will sink; and in the event that it is zero, the object will be neutrally buoyant, remaining stationary. Simply said, when a body is partially or entirely submerged in a fluid, the Archimedes' principle applies. Consider a cuboid submerged in a fluid, with its top and bottom facing in the direction of gravity, which is considered to be constant throughout the length of the cube. Each face of the fluid will experience a normal force, but only the normal forces on the top and bottom will result in buoyancy. The height directly affects the pressure difference between the top and bottom faces (difference in depth of submersion). A net force on the cuboid is created by multiplying the pressure difference by the area of a face.

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Elliptical galaxies most likely to be found in the central regions

Galaxies with an elliptical form are known as elliptical galaxies. Since an ellipse has an oval shape, these galaxies also have an oval shape. Elliptical galaxies are those with little to no gas and dust. The elliptical galaxies are the most abundant type of galaxies. Elliptical galaxies are most likely to be found in the central regions of galaxy clusters. Galaxy clusters are large groups of galaxies that are bound together by gravity and are some of the largest structures in the universe.

Elliptical galaxies are characterized by a lack of distinct features, such as spiral arms or a visible nucleus. These galaxies are thought to have formed through the merger of smaller galaxies and are generally found in high-density environments such as the centres of galaxy clusters. They are less common on the outskirts of galaxy clusters and are rarely found in small clusters or in between larger clusters.

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pushed to the right = 300 newtons

pushed to the left = 400 newtons

[tex]400-300=100[/tex]

[tex]\fbox{100 Newtons to the left}[/tex]

The work done by a force is 40.14 J

The work done is calculated to include both the force applied to the body and the overall movement of the body. There is a constant force F in front of this block. The purpose of this force is to move an object a certain distance d in a straight line in the direction of the force.

The cart is lifted to a height, h:

h = (10meters) ×sin(4) = 0.69 m

The force in the vertical direction is:

Fy = 12N×sin(29o) = 58.177N

Work = F×d = (58.177)×(0.69) = 40.14 joules

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The motion of the free electron sea causes the electrical conduction.

Metals that are near to one another have valence electrons that do not only remain on their own atom but also easily migrate throughout the entire metal complex. They seem to be floating through an sea of electrons, like a solitary water molecule floating freely in the sea. For this reason, it is often referred to as the electron sea model.

These atoms become positively charged cations because each metal atom is free to move around. These cations resemble a positively charged island because they are encircled by a sea of negatively charged electrons. Because of these free-moving electrons, metal is a good conductor of electricity.

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the intensity level of the combined sounds is 67.76 dB

Calculation :

Sound Intensity level L= 63 dB

We know L = 10 log(I/Io)

63 = 10 log(I/Io)

6.3 = log (I/Io)

I /Io = [tex]10^{6.3}[/tex]

I = [tex]10^{6.3}[/tex] Io

= [tex]10 ^{6.3 }[/tex]x [tex]10 ^{-12}[/tex]

= [tex]10^{ -5.7}[/tex] W/m 2

  = 1.995 x[tex]10 ^{-6}[/tex] W/m 2

Sound Intensity level L '= 66 dB

We know L ' = 10 log(I '/Io)

66 = 10 log(I '/Io)

6.6 = log (I'/Io)

I ' /Io = [tex]10 ^{6.6}[/tex]

I ' =  [tex]10 ^{6.6}[/tex] Io

=  [tex]10 ^{6.6}[/tex] x [tex]10 ^{-12}[/tex]

= [tex]10 ^{-5.4}[/tex]W/m ^2

  = 3.981 x[tex]10 ^{-6}[/tex] W/m^ 2

Combined intensity I " = I + I ' = 5.976 x10 -6 W/m 2

the intensity level of the combined sounds L " = 10 log(I" / Io)

 L " = 10 log [( 5.976 x[tex]10 ^{-6}[/tex] )/([tex]10 ^{-12}[/tex] ) ]

      = 10 log [5.976 x10 6]

      = 10(6.776)

      = 67.76 dB

Intensity is the amount of energy a wave transports in one unit of area per unit time and is also equal to the energy density multiplied by the wave velocity. Usually measured in watts per square meter. Intensity depends on wave strength and amplitude.

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We use a construct that can be used in a shell script the read built-in Bash command to read user input. It assigns user input to the variable after receiving it. It simply takes one line from the Bash shell to read. The syntax for implementing it is listed below.

read <variable_name>  

A built-in tool in Bash allows you to read text from standard input. The utility provides a wide range of user input reading capabilities that assist make Bash scripts interactive. Through various examples and use situations, this article demonstrates how the Bash read command functions. access to a terminal or command line.

The "read" command in Bash scripting is used to get human input. It's essential to comprehend the "read" command if you want to make your code more interactive. The "read" command is used to retrieve user-inputted data. This article demonstrates how to communicate with users using Bash's "read" command.

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The kinetic energy of another body having three times the mass of the given object will be 108 J

Kinetic energy-In physics, the kinetic energy of an object is the energy  it has due to  motion. It is defined as the work required to accelerate a body from a given mass from rest to a specified speed.

The kinetic energy of a body is given by [tex]K.E= \frac{1}{2}Mv^{2}[/tex] (first equation)

Given K.E= 36J

Now the mass of second body is m=3M

also the second body is moving with the same speed v

So kinetic energy of second body K.E₂= [tex]\frac{1}{2}mv^{2} =\frac{1}{2}(3M)v^{2}[/tex]=36×3

=108J (from first equation)

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The pear will not hit the fish where he eyes the fish in the water.

Please note that fish in the water will not be the same as what our eyes see. Where the location of the position will be different because it follows the refraction of light obtained so that it can be concluded that the position of the fish is not the actual position. The fish swims forward and the shooter looks at the water from above as if the fish is looking up.

This event is caused by the process of refraction of light. Refraction is the deflection of the direction of propagation of light when it enters a medium of different densities.

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The coefficient of static friction when the speed of the disk is given, is calculated to be 0.065 / r.

The maximum velocity of an object moving in a curve beyond which it will slide off the curve is given by the relationship,

v = √(μ* g* r) ----(1)

where  is the coefficient of friction between the object and the surface of the curve, g is acceleration due to gravity and r is the radius of the curve.

Given that,

v = 0.8 m/s

g = 9.8 m/s²

r = ?

μ = ?

Making μ as subject, we have,

μ = v²/(g*r) ----(2)

As we were not given the value of r, we can just substitute other known values, then solve and leave the answer in terms of r.

μ = (0.8)²/(9.81* r) = 0.64/ (9.81* r) = 0.065 / r

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The resistance of the resistor is 1.8Ω

Consider the voltage across the inductor 4 sec after the switch is closed is V(4)

The voltage across the inductor 4 sec after the switch is closed is 80%  of its maximum value, i.e., V(4)=0.8[tex]V_{0}[/tex]

Consider the expression for the voltage across the RL circuit.

V(t)=[tex]V_{0}e-\frac{t}{T}[/tex]

Where [tex]V_{0}[/tex] is the maximum voltage, t is the time, V(t) is the voltage at time

t and T is the time constant.

Substitute the values of ,[tex]V_{0}[/tex], V(t) and t in the above expression.

[tex]$$\begin{aligned}0.8 \mathrm{~V}_0 & =\mathrm{V}_0 \times \mathrm{e}^{-\frac{4}{\tau}} \\0.8 & =\mathrm{e}^{-\frac{4}{\tau}} \\\frac{1}{0.8} & =\mathrm{e}^{\frac{4}{\tau}}\end{aligned}$$[/tex]

Take natural log on both the sides.

[tex]$$\ln \left(\frac{1}{0.8}\right)=\frac{4}{\tau}$$[/tex]

Rearrange the above expression.

[tex]$$\begin{aligned}\tau & =\frac{4}{\ln \left(\frac{1}{0.8}\right)} \\& =17.9 \mathrm{~s}\end{aligned}$$[/tex]

Now consider the expression for time constant.

[tex]$$\tau=\frac{\mathrm{L}}{\mathrm{R}}$$[/tex]

Where R is the inductance and L is the resistance.

Rearrange the above expression.

R = [tex]\frac{L}{T}[/tex]

Substitute the values of T and L in the above expression.

[tex]R=\frac{34}{17.9}\\ R=1.8[/tex]Ω.

Therefore, the resistance of resistor is 1.8Ω

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Electric flux through the surface is [tex]1.5 Nm^2/C[/tex].

As per the detail share in the above question are as bellow,

Given an area A with a unit normal vector n, the electric flow through that region is given by Φ = E.(An) = |E|Acosθ

Where angle between vectors E and n =θ .

Also Magnitude of E = |E|

When the magnitude of n is |n| = 1

The normal n and the electric field vector E make an angle of,

θ = 90 - 30 = 60 degrees,

Therefore magnitude of,

|E| = 300N/C

And A= 0.1 x 0.1 = 0.01 m.

Thus,

Φ = |E|Acosθ

Substitute the value in above equation we get,

=300 x 0.01 x cos(60)

=3 x 0.5

[tex]= 1.5 Nm^2/C[/tex]

Electric flux=Φ=[tex]1.5 Nm^2/C[/tex]

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Note : The correct question would be as follow,

what is the electric flux through the surface shown in the figure? assume that e=300n/c.

Answer:

To calculate the work done by the electrostatic field in moving a charge from one point to another, you can use the formula:

work = charge * (final potential - initial potential)

In this case, the charge is 2 coulombs, the initial potential is 20V, and the final potential is -5V. Plugging these values into the formula, we get:

work = 2 coulombs * (20V - (-5V))

= 2 coulombs * (25V)

= 50 Joules

Therefore, the work done by the electrostatic field in moving the charge from one point to another is 50 Joules.

There is a transverse sinusoidal wave on a string that flows in a straightforward harmonic fashion and has an angular frequency that matches the wave. (Chose c.)

An energetic disturbance called a wave moves from one place to another. Every time a wave moves, energy is changed, regardless of the change. The substance through which a wave passes is known as the medium. Back and forth oscillations occur repeatedly in that medium.

A wave is a disruption or variation that progressively moves energy from one location in a medium to another. It could manifest as an elastomeric deformation or a shift in pressure, magnetic or electric field strength, electric potential, or temperature.

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If a ball is thrown at an initial horizontal velocity of 3.6 meters per second off of a cliff that is 19.6 meters high, it will land 35.28 meters away from the cliff.

The vectoral expression of a particle and object's motion with respect towards time is called its velocity. The recognized unit for measuring magnitude of velocity is indeed the meters per second (m/s), which is frequently referred to as speed. Velocity is the rate at which an object's position is changing as perceived from a particular point of view and so as measured by a certain unit of time. It refers to the direction speed of the an object in motion.

Average speed is calculated by dividing a quantity by the time required to obtain that quantity. Speed in the SI is expressed in m / sec. The average speed (S) is calculated using the equation S = d/t, where d is the entire distance traveled and t denotes the total time. One can determine an object's beginning velocity by dividing the time it took the thing to go a specific distance by the total distance.

D = (1/2) gt2 where g = 9.8 m/s2

It takes time to descend the 19.6-meter cliff.

19.6 = 1/2(9.8)t2

19.6/4.9 = t2

Square root 90.4 = about 9.8 sec.

3.6 m/s x 9.8 sec = 35.28 m

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Answer: Fg = 265.68 N

Explanation:

Fg = m * g

m = Fg / g

m = 1607.2 N / 9.8 m/s^2

m = 164 kg

Fg = m * g

Fg = 164 kg * 1.62 m/s^2

Fg = 265.68 N

The Sun's surface emits as a black body its surface temperature is [tex]$5.78 \times 10^3 \mathrm{~K}$[/tex].

The sun's surface area is,

A 3D object's surface area is the entire area that all of its faces cover. If we need to figure out how much paint is needed to paint a cube, for example, we may use the cube's surface area. It is consistently expressed in square units.

[tex]A=4 \pi r^2[/tex]

The sun's radius, r, is indicated here.

Substitute [tex]$6.96 \times 10^8 \mathrm{~m}$[/tex] for r.

[tex]A & =4 \pi\left(6.96 \times 10^8 \mathrm{~m}\right)^2 \\& =6.09 \times 10^{18} \mathrm{~m}^2[/tex]

The radiated power is, according to Stefan's law

Energy that emanates from an origin and moves through space at the speed of light is referred to as radiation. This radiation has wave-like qualities and is accompanied by an electric field and a magnetic field.

[tex]P & =\sigma A e T^4 \\T^4 & =\frac{P}{\sigma A e} \\T & =\left(\frac{P}{\sigma A e}\right)^{\frac{1}{4}}[/tex]

Substitute [tex]$6.09 \times 10^{18} \mathrm{~m}^2$[/tex] for A,

[tex]5.67 \times 10^{-8} \mathrm{~W} / \mathrm{m}^2. \mathrm{K}^4$[/tex] .  for [tex]$\sigma$[/tex],

and [tex]$3.85 \times 10^{26} \mathrm{~W}$[/tex] for P.

[tex]T & =\left(\frac{3.85 \times 10^{26} \mathrm{~W}}{\left(5.67 \times 10^{-8} \mathrm{~W} / \mathrm{m}^2 \cdot \mathrm{K}^4\right)\left(6.09 \times 10^{18} \mathrm{~m}^2\right)(1)}\right)^{\frac{1}{4}} \\& =\left(1.12 \times 10^{15} \mathrm{~K}^4\right)^{\frac{1}{4}} \\& =5.78 \times 10^3 \mathrm{~K}[/tex]

The temperature is [tex]$5.78 \times 10^3 \mathrm{~K}$[/tex].

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Note:- The correct question would be as follow,

The radius of our Sun is [tex]$6.96 \times 10^8 \mathrm{~m}$[/tex], and its total power output is [tex]$3.85 \times 10^{26} \mathrm{~W}$[/tex]. (a) Assuming the Sun's surface emits as a black body, calculate its surface temperature.

The magnitude of the average value of the emf induced in the loop is 2.26 V.

The initial area of wire loop is:

A(initial) = π d² / 4

             = 3.14 × ( 0.21 m )² / 4

             = 0.0346 m²

And, The wire loop's final location is at:

A(final) =  π d² / 4

           = 3.14 × ( 0.31 m )² / 4

           = 0.0754 m²

It is given that the magnetic field is normal to the loop of wire.

Therefore, angle made by the magnetic field with the normal to the loop

is :

θ = 0°

Applying Faraday's law, the average emf induced in the loop is:

ε = B × ( A(final) - A(initial) ) × cosθ / Δt

ε = 2.00 T × ( 0.0754 - 0.0346 ) m² × cos0° / 0.036 s

ε = 2.26 V

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The moment of inertia is measured in units of mass times squared distance, such as kgm2. The rotational kinetic energy of an item in rotation about an axis is K = 12I2.

Moment of inertia divided by half equals rotational kinetic energy (angular speed). Where 0 0 is the starting angular velocity, = 0 + t (constant) and = 0 + t (constant). The equation is the same as the linear version, with the exception that the angular equivalents of the linear variables. It is necessary to specify the moment of inertia in relation to a selected axis of rotation. The moment of inertia for a point mass is equal to the mass times the square of the distance perpendicular to the rotation axis, or I = mr2.

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For the distance between q 3 and q 1, the formula is: = 3 L 0 = 3 1 L = 3 1 10 cm 14 cm. Q3 should therefore be positioned at x=14 cm along the x-axis.

For q 3, there is no equilibrium position.

​between two fixed changes because one is pulling it and the other is pushing it

L is set at 10 cm, and L 0 is taken to be positive. We cancel k and q 3 and set this equal to zero as the problem specifies. As a result, we get L 0.

​∣q 1\s​\s ∣\s​\s − \s(L+L \s0\s​\s)\s∣q \s2\s​\s ∣\s​\s =0 ⇒(\sL \s0

​L+L \s0\s​

​\s ) \s2\s = \s∣\s∣\s∣\s∣\s∣\s​

q \s1\s​

q \s2\s​

∣\s∣\s∣\s∣\s∣\s​\s = \s∣\s∣\s∣\s∣\s∣

​+1.0 μC\s−3.0 μC

​=3.0 results in L 0 after taking the square root.

​L+L \s0\s​

For the distance between q 3 and q 1, the formula is: = 3 L 0 = 3 1 L = 3 1 10 cm 14 cm. Q3 should therefore be positioned at x=14 cm along the x-axis.

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The initial speed of the car with a length of the skid mark of about 64 m long and kinetic friction of 0.70 is 29.63 m/s.

A force that acts between moving surfaces is referred to as kinetic or sliding friction. It is the frictional force that prevents relative motion between surfaces in contact. The formula to calculate this kind of friction is, [tex]f _k =\mu_kN[/tex] where uk is the coefficient of friction and N is the normal force.

Given the length of the skid mark (Δd) is 64 m and the coefficient of kinetic friction is 0.70. The final velocity vf is 0 because the car stops.

Let us assume the initial velocity vi, mass m,  and deceleration a. Then, the normal force acting on the car is N = mg. The kinetic friction will be,

[tex]f _k =\mu_kN\\f_k=\mu_kmg[/tex]

Let's assume the only force acting on the system is kinetic friction, then friction force=ma. Solve this equation with the above equation,

[tex]\begin{aligned}ma&=\mu_kmg\\a&=\mu_kg\end{aligned}[/tex]

Then, the initial speed is calculated as follows

[tex]\begin{aligned}v_f^2&=v_i^2-2a\Delta d\\0&=v_i^2-2\mu_kg\Delta d\\v_i^2&=\mathrm{2\times0.70\times9.80\;m/s^2\times64\;m}\\v_i^2&=\mathrm{878.08\;m^2/s^2}\\v_i&=\mathrm{29.63\;m/s}\end{aligned}[/tex]

The answer is 29.63 m/s.

The complete question is -

Police investigators, examining the scene of an accident involving two cars, measured 64 m long skid marks on one of the cars, which nearly came to a stop before colliding. The coefficient of kinetic friction between rubber and the pavement is about 0.70. Estimate the initial speed of that car, assuming a level road.

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The current north of the wire fliws upwards as of the electric current straight upward.

The proper-hand thumb rule suggests the path of the magnetic area for a recognise path of the modern-day. If the thumb of the proper-hand factors alongside the path of modern-day then the curled arms of that hand offers the path of the magnetic area because of the modern-day.

The path of the magnetic area is perpendicular to the twine and is withinside the path the arms of your proper hand might curl in case you wrapped them across the twine together along with your thumb withinside the path of the modern-day.A vertical twine wearing a modern-day withinside the upward path is located in a horizontal magnetic area directed toward north.

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If a = a1, a2, a3 and b = b1, b2, b3 . Then [tex]& \vec{a} \times \vec{b}=(-1)(\vec{b} \times \vec{a})[/tex] Or [tex]& \vec{a} \times \vec{b}=-\vec{b} \times \vec{a}[/tex]

As per the details share in the above question are as bellow,

The provided data are follow,

The product of two or more integers that remain the same, regardless of the sequence in which they are multiplied, is referred to as the commutative property formula for multiplication. The commutative property formula for multiplication is (A x B) = (B x A).

Let us consider, Let a = a1, a2, a3

And b=b1, b2, b3

We have the property that a × b = − b × a.

Then a × b = __ = (−1) __ =− b × a.

[tex]& \vec{a}=a_1 i+a_2 j+a_3 k \\ \vec{b}=b_1 i+b_2 j+b_3 k[/tex]

Then,

[tex]$$\vec{a} \vec{x} \vec{b}=\left|\begin{array}{ccc}i & j & k \\a_1 & a_2 & a_3 \\b_1 & b_2 & b_3\end{array}\right|$$[/tex]

[tex]$$=i\left(a_2 b_3-a_3 b_2\right)+j\left(a_3 b_1-a_1 b_3\right)+k\left(a_1 b_2-a_2 b_1\right)$$[/tex]

So further we get,

[tex]& =i\left(b_2 a_3-a_2 b_3\right)+j\left(a_1 b_3-a_3 b_1\right)+k\left(a_2 b_1-a_1 b_2\right) \\& =-\left[i\left(a_2 b_3-a_3 b_2\right)+j\left(a_3 b_1-a_1 b_3\right)+k\left(a_1 b_2-a_2 b_1\right)\right.[/tex]

So, we get,

[tex]\vec{a} \times \vec{b}=\left[i\left(a_2 b_3-a_3 b_2\right)+j\left(a_3 b_1-a_1 b_3\right)+k\left(a_1 b_2-a_2 b_1\right)\right.[/tex]

We get,

[tex]& \vec{b} \times \vec{a}=-[\vec{a} \times \vec{b}][/tex]

Or [tex]& -\vec{b} \times \vec{a}=\vec{a} \times \vec{b}[/tex]

Then,

[tex]& \vec{a} \times \vec{b}=(-1)(\vec{b} \times \vec{a})[/tex]

Or [tex]& \vec{a} \times \vec{b}=-\vec{b} \times \vec{a}[/tex]

for more such question on property.

https://brainly.com/question/25844719

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