A crate is pulled due south with a force of 350. N. What other force must be applied if the
net force on the crate is 425 N due north? Enter the magnitude (with units) and direction
(north, south, east, west).

Answer:

A. The acceleration is the same for both bullets.

Explanation:

The force of gravity is the attractive force applied by the earth on any object on its surface or neighborhood. And it is uniform under free fall at a definite location on the earth.

Since the the two bullets motion was at the same time and without air resistance, their acceleration would be the same before striking the surface of the water. This is because neglecting air resistance, all objects at the same height would fall with the same acceleration no matter their masses.

Answer:

naruto and hinata

Explanation:

Answer:

77.6 Hz

Explanation:

What frequency is received by a person watching an oncoming ambulance moving at 115 km/h and emitting a steady 753 Hz sound from its siren.

The given parameters are:

Observer speed = 115 km/h

Source frequency = 753 Hz

Speed of sound = 342 m/s

First convert km/h to m/s

Observer speed = (115 × 1000) / 3600

Observer speed = 31.94 m/s

The frequency received by the person will be:

F = fv / ( V - v )

Where

F = frequency received by the person

f = siren frequency

V = speed of sound

v = speed of the ambulance

Substitute all the parameters into the formula

F = (753 × 31.94) / ( 342 - 31.94 )

F = 24050.82 / 310.06

F = 77.568 Hz

Therefore, the frequency received by a person is approximately 77.6Hz

Answer:solenoid with current running through it

Explanation:just took the test

Answer:

The power factor of the circuit is 0.99

Explanation:

Given;

resistance of the resistor, R = 65.2 ohms

capacitance of the capacitor, C = 2.26 μF = 2.26 x 10⁻⁶ F

inductance, L = 2.08 mH = 2.08 x 10⁻³ H

frequency of the AC, f = 2400 Hz

The angular frequency is given by;

ω = 2πf

ω = 2π(2400) = 15081.6 rad/s

The inductive reactance is given by;

XL = ωL

XL = (15081.6 x 2.08 x 10⁻³)

XL = 31.37 ohms

The capacitive reactance is given by;

[tex]X_c = \frac{1}{\omega C} \\\\X_c = \frac{1}{(15081.6)(2.26*10^{-6} )}\\\\X_c = 29.34 \ ohms[/tex]

The phase difference is given by;

[tex]tan\phi = \frac{X_l - X_c}{R}\\\\ tan\phi =\frac{31.37-29.34}{65.2} \\\\tan\phi = 0.0311 \\\\\phi = tan^{-1} (0.0311)\\\\\phi = 1.78^0[/tex]

The power factor is given by;

CosФ = Cos(1.78) = 0.99

Therefore, the power factor of the circuit is 0.99

Answer:

0.967 m/s

1855 N

[tex]46.375\ \text{MPa}[/tex]

Explanation:

v = Final velocity

u = Initial velocity = 0

s = Displacement = 4.77 cm

g = a = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

From the kinematic equations

[tex]v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 0.0477+0}\\\Rightarrow v=0.967\ \text{m/s}[/tex]

The velocity of the object at the moment of impact is 0.967 m/s

Now

[tex]\Delta v[/tex] = Change in velocity = 1 m/s

t = Time taken = 20 ms

m = Half mass of the person = [tex]\dfrac{74.2}{2}=37.1\ \text{kg}[/tex]

[tex]F=\dfrac{m}{t}\\\Rightarrow F=\dfrac{37.1\times 1}{20\times 10^{-3}}\\\Rightarrow F=1855\ \text{N}[/tex]

The force associated with a single step of the person is 1855 N

A = Area = [tex]0.4\ \text{cm}^2[/tex]

Stress is given by

[tex]\sigma=\dfrac{F}{A}\\\Rightarrow \sigma=\dfrac{1855}{0.4\times 10^{-4}}\\\Rightarrow \sigma=46375000\ \text{Pa}=46.375\ \text{MPa}[/tex]

The stress on the tendon is [tex]46.375\ \text{MPa}[/tex]

The speed of object during falling is 0.967 m/s.

(A)  The magnitude of force  associated with this single step for a person is 1855 N.

(B) The required value of stress at tendons is [tex]4.70 \times 10^{7} \;\rm Pa[/tex].

Given data:

The height of fall is, h = 4.77 cm = 0.0477 m.

The magnitude of downward velocity is, v' = 1.0 m/s.

The duration of impact is, [tex]t = 20 \;\rm ms =20 \times 10^{-3} \;\rm s[/tex].

The mass of person is, m = 74.2 kg.

The magnitude of force is, F' = 1880 N.

The cross-sectional area is, [tex]A =0.4 \;\rm cm^{2} = 0.4 \times 10^{-4} \;\rm m^{2][/tex].

The problem has several parts using different concepts. First obtain the final speed of object to fall by using the second kinematic equations of motion as,

[tex]v^{2}=u^{2}+2gh[/tex]

Solving as,

[tex]v^{2}=0^{2}+(2 \times 9.8 \times 0.0477)\\\\v = \sqrt{(2 \times 9.8 \times 0.0477)} \\v = 0.967 \;\rm m/s[/tex]

Thus, the speed of object during falling is 0.967 m/s.

(A)

Now coming to next part, the half of mass means, m' = m/2 = 74.2/2 = 37.1 kg.

Apply the expression of average force as,

[tex]F =\dfrac{m'v'}{t}[/tex]

Solving as,

[tex]F =\dfrac{37.1 \times 1}{20 \times 10^{-3}}\\\\F = 1855 \;\rm N[/tex]

Thus, the magnitude of force  associated with this single step for a person is 1855 N.

(B)

The expression for the stress is given as,

[tex]\sigma = \dfrac{F'}{A}[/tex]

Solving as,

[tex]\sigma = \dfrac{1880}{0.4 \times 10^{-4}}\\\\\sigma =4.70 \times 10^{7} \;\rm Pa[/tex]

Thus, the required value of stress at tendons is [tex]4.70 \times 10^{7} \;\rm Pa[/tex].

Learn more about the Stress force here:

https://brainly.com/question/18274389

Answer:

The length of the pendulum cord is approximately 114.592 centimeters.

Explanation:

We include a representation of the motion of the pendulum in the image attached below. The trajectory described by the pendulum is represented by the following geometrical expression:

[tex]s = \theta \cdot r[/tex] (1)

Where:

[tex]\theta[/tex] - Angular change with the vertical, measured in radians.

[tex]r[/tex] - Length of the pendulum cord, measured in centimeters.

[tex]s[/tex] - Arc, measured in centimeters.

If we know that [tex]\theta = \frac{\pi}{9}[/tex] and [tex]s = 40\,cm[/tex], then the length of the pendulum cord is.

[tex]r = \frac{s}{\theta}[/tex]

[tex]r = \frac{40\,cm}{\frac{\pi}{9} }[/tex]

[tex]r \approx 114.592\,cm[/tex]

The length of the pendulum cord is approximately 114.592 centimeters.

62×3.0

think so not sure

Answer:

7 m/s (agrees with answer a in your list)

Explanation:

Recall that the centripetal acceleration is defined by the square of the tangential velocity divided by the radius of the rotational motion:

[tex]a_c=\frac{v_t^2}{R}[/tex]

then the tangential velocity is extracted from here as:

[tex]a_c=\frac{v_t^2}{R} \\v_t^2=a_c * R\\v_t=\sqrt{a_c * R}[/tex]

in our case, this becomes:

[tex]v_t=\sqrt{7*7} = 7 \,\,m/s[/tex]

Answer:

The equation for such type of wave is  [tex]D_2 = sin(0.84.x + 47t + 21)[/tex]

Explanation:

From the question we are told that

   The displacement is [tex]D_1 = 4.2sin(0.84.x - 47t + 21)[/tex]

   Here  the wave number is  k=  0.84

              The angular frequency is  [tex]w = 47[/tex]

              The phase shift is  [tex]\phi = 21[/tex]

 Generally the equation that represents a wave which, when traveling in the opposite direction, will produce a standing wave when added to this one is mathematically represented as

             [tex]D_2 = sin(0.84.x + 47t + 21)[/tex]

Answer:

=7.5J

Explanation:

  Step one:

given data

the applied force F=5N

the distance = 1.5m

Step two:

Required

work done by Jolie

Now by definition, the work done is the applied times the distance which the force is applied

Wd= F*D

Wd= 5*1.5

Wd=7.5J

If she uses a force of 5N to lift 150 pounds to a height of 1.5m, the work done will be 7.5J

Answer:

same

Explanation:

aww good luck, i hope u n ur family turn out okkk

Answer: The acceleration results if a net force of 4F acts on a mass of 6m is 2/3a.

Explanation:

Force exerted on an object can be defined as a pull or a push on an object which leads to it's displacement. Force is taken to be a vector quantity because it has both magnitude and direction. The formula which can be used to determine force exerted on an object in physics is:

F= mass( kg) × acceleration( m/ s²)

Acceleration is defined as the rate at which the velocity of an object changes. From the formula of force given above it can be determined by making it the subject of formula. Therefore acceleration= Force/ mass.

From the question,

Force= 4F

Mass= 6m

Therefore acceleration= F/m

= 4/6

Acceleration= 2/3a

The required magnitude of acceleration when force is 4F and mass is 6m is 2/3a.

Given data:

The magnitude of net force is, 4F.

The value of mass is, 6m.

Apply the Newton's second law which says that force exerted on an object can be defined as a pull or a push on an object which leads to it's displacement. Force is taken to be a vector quantity because it has both magnitude and direction. The formula which can be used to determine force exerted on an object in physics is

F = ma

a = F/m ..........................................(1)

here, a is the acceleration.

Solving as when the force becomes 4F and mass becomes 6m.

[tex](4F) = (6m) \times a'\\\\a '= \dfrac{4F}{6m}\\\\a '= \dfrac{2}{3}a[/tex]

Thus, the required magnitude of acceleration when force is 4F and mass is 6m is 2/3a.

Learn more about the Newton's Second law here:

https://brainly.com/question/13447525

Answer:

The energy lost to the environment is 0.461 J

Explanation:

Given;

mass of the magnet, m = 0.2 kg

height of fall, h = 35 cm = 0.35 m

initial speed of the magnet, u = 0

final speed of the magnet, v = 1.5 m/s

Initial energy of the magnet is given by;

E₁ = P.E₁ + K.E₁

E₁ = mgh₁ + ¹/₂mu²

E₁ = (0.2 x 9.8 x 0.35) + ¹/₂(0.2)(0)²

E₁ = 0.686 J

Final energy of the magnet as it emerges from the tube is given by;

E₂ = mgh₂ +  ¹/₂mv²

E₂ = (0.2 x 9.8 x 0) + ¹/₂(0.2)(1.5)²

E₂ = 0 + 0.225 J

The energy lost to the environment is given by;

E = E₂ - E₁

E = 0.225 J - 0.686 J

E = -0.461 J (negative sign indicates lost energy to the environment)

Therefore, the energy lost to the environment is 0.461 J

Answer:

Energy, in physics, the capacity for doing work. It may exist in potential, kinetic, thermal, electrical, chemical, nuclear, or other various forms. There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another.

Explanation:

Hope this helps!

Answer:

6,000 kg

Explanation:

Answer:

The correct answer is - phototropism, thigmotropism, hydrotropism, and gravitropism in order ( already match correctly).

Explanation:

phototropism is a phenomenon in which plants grow towards the light or sun which is accomplished by the hormone auxin in the cells far from the light.

Thigotropism is a type of plant growth that occurs around the tree to support itself which is a touch stimuli response.

The movement of the plant in the direction of the source of the water is known as hydrotropism. In which stimuli is humidity or the water concentration.

The movement of the plant or roots of the plants towards the soil or earth is known as gravitropism here gravity is the stimuli.

Answer:

Use the drop-down menus to complete each sentence.

A plant grows toward a sunny window. This response is an example of

phototropism

.

Sometimes a plant grows around a tree for support. This response is an example of

thigmotropism

.

The roots of a plant grow toward a water source. This response is an example of

hydrotropism

.

The roots of a plant grow down into the soil. This response is an example of

gravitropism

.

Explanation:

Answer:

P_abs = 105120.2 N/m²

Explanation:

We are given;

Specific gravity of oil; ρ_oil = 0.6 g/cm³ = 600 kg/m³

Depth of water; h_w = 21 cm = 0.21 m

Depth of oil; h_o = 35 cm = 0.35 m

From tables specific gravity of water is; ρ_w = 1000 kg/m³

Thus, to get the absolute pressure at the bottom of the container, we will use the formula;

P_abs = (ρ_w × g × h_w) + (ρ_oil × g × h_oil) + P_a

Where P_a is atmospheric pressure with a standard value of 1.01 × 10^(5) N/m²

g is gravitational acceleration = 9.81 m/s²

Thus;

P_abs = (1000 × 9.81 × 0.21) + (600 × 9.81 × 0.35) + (1.01 × 10^(5))

P_abs = 105120.2 N/m²

Answer:

See connections below

Explanation:

1   [tex]\Rightarrow[/tex] b

2   [tex]\Rightarrow[/tex] a

3   [tex]\Rightarrow[/tex] d

4   [tex]\Rightarrow[/tex] i

5   [tex]\Rightarrow[/tex] g

6   [tex]\Rightarrow[/tex]  h

7   [tex]\Rightarrow[/tex]  c

8   [tex]\Rightarrow[/tex]  e

9   [tex]\Rightarrow[/tex] f

Answer:

[tex]5.86\times 10^{-7}\ \text{m}[/tex]

Explanation:

d = Slit separation = 0.11 mm

[tex]\theta[/tex] = Angle = [tex]0.61^{\circ}[/tex]

m = Order = 2

[tex]\lambda[/tex] = Wavelength

We have the relation

[tex]d\sin\theta=m\lambda\\\Rightarrow \lambda=\dfrac{d\sin\theta}{m}\\\Rightarrow \lambda=\dfrac{0.11\times 10^{-3}\times \sin0.61^{\circ}}{2}\\\Rightarrow \lambda=5.86\times 10^{-7}\ \text{m}[/tex]

The wavelength of the light is [tex]5.86\times 10^{-7}\ \text{m}[/tex].

Answer:

this is a projectile

Answer:

D. projectile

Explanation:

Since it's dropped from a rest that means that it's velocity at the beginning is 0.

Answer:

The

Explanation:

The horizontal distance covered is known as the range expressed as;

R = U√2H/g

U is the speed = 200m/s

H is the max height = 800m

g is the gravity = 9.8m/s²

R = 200√2(800)/9.8

R = 200√1600/9.8

R = 200√163.27

R = 200(12.78)

R = 2555.54

Hence the package should be released at a distance of 2555.54m

Answer:

d. 25 ms

Explanation:

       [tex]\tau_{1} = R_{1} *C_{1} = 5 ms (1)[/tex]

       [tex]\tau_{2} =10* R_{1} *0.5*C_{1} = 5*(R_{1}* C_{1}) = 5* \tau_{1} = 5* 5 ms = 25 ms (2)[/tex]

Answer:

A) all substance conduct electricity

Answer:

B I believe

Explanation:

Answer:hat are some examples of energy transformation?

The Sun transforms nuclear energy into heat and light energy.

Our bodies convert chemical energy in our food into mechanical energy for us to move.

An electric fan transforms electrical energy into kinetic energy.

Explanation:

Answer:

the reflected wavelength is lano = 4.55 10⁻⁷ m which corresponds to the blue color

Explanation:

This is a case of reflection interference, we must be careful

* There is a 180º phase change when light passes from the air to the soap film (n = 1,339), but there is no phase change when passing from the pomp to the plastic (n = 1.3)

* the wavelength within the film is modulated by the refractive index

     λₙ =  λ₀ / n

if we consider these relationships the condition for constructive interference is

     2 t = (m + ½)  λₙ

     2t = (m + ½)  λ₀ / n

      λ₀ = 2t n / (m + ½)

we substitute the values

      λ₀= 2 255 10⁻⁹ 1,339 / (m + ½)

      λ₀  = 6.829 10⁻⁷ (m + ½)

let's calculate the wavelength for various interference orders

m = 0

       λ₀ = 6.829 10⁻⁷/ ( 0 +   ½ )

       λ₀ = 13.6 10⁻⁷

       it is not visible

m = 1

      λ₀ = 6,829 10⁻⁷/ (1 + ½)

       λ₀ = 4.55 10⁻⁷

      color blue

m = 2

      λ₀ = 6.829 10⁻⁷ / (2 + ½)

      λ₀ = 2,7 10⁻⁷

   it is not visible

therefore the reflected wavelength is lano = 4.55 10⁻⁷ m which corresponds to the blue color