A construction crew has just finished building a road. The crew worked for 4 4/9 days. If they built 2 1/5 kilometers of road each day, what is the total length of road they built?

I hope that will be help full to u

Answer:

they are on opposite quadrants and they meet exactly in the origin (0,0)

Answer:

im not completely sure but i think its A

Answer:

D . (4,2)

Step-by-step explanation:

i got it right !

Answer:

To the "LEFT", so -6 is "LESS"

Step-by-step explanation:

-6 < -4

Answer:

5.5 quotient 5 and rest 1

But I would answer quotient is 5 and half

Step-by-step explanation:

11/3 ÷ 2/3 = 11/3 * 3/2 = 11/2= 5.5

So the quotient is 5 and rest is 1

Hope this helps, have a good day

Answer:

5 1/2

Step-by-step explanation:

11/3÷2/3

Applying the fractions formula for division,

=11/3×3/2

=33/6

Simplifying 33/6, the answer is

=5 1/2

Answer: Increasing because it is gaining weight

Answer:

It's increasing.

Step-by-step explanation:

Camille's puppy is gaining weight as shown in the graph not loosing weight. If Camille's puppy was losing weight it'd be decreasing.

Hope this helps!! Good luck!! :)

Answer:

Less

Step-by-step explanation:

edge 2020

Answer:A.)less

Step-by-step explanation:

edge 2023

Answer:

m 7=129

Step-by-step explanation:

if 6 and 7 are right next to each other. it makes 180 degrees so you would take 180-51 to get your answer

Answer:  3/8

Step-by-step explanation:

1+2+3+2= 8

he has 8 balls in total

he has 3 orange balls so the probability is 3/8

Answer: B.The range Is Higher for city A than City B

E. The median is the same for city A and City B

According to the calculations, the correct statements are B and C.

Given that Stephen gathered data about the average rainfall in two cities, and he organized his data in the graph, to determine which statements are correct, the graph must be analyzed and the following mathematical reasoning must be carried out:

The average rainfalls of City A range from 0.5 to 4.5 per month, with a variable range of 4 points. In turn, the average rainfalls of City B range from 1 to 4 per month, with a variability range of 3 points. Therefore, the range of the data for City A is higher than City B, so option B is correct, and options A and D are incorrect.

Regarding the median rainfalls, City A has a cumulative total of 27 points over 12 months, that is, an average of 2.25 per month. In turn, City B has a cumulative total of 28.5 points over 12 months, that is, an average of 2,375 per month. Therefore, the mean of City B is higher, so option C is correct.

Learn more in https://brainly.com/question/20982963

Answer:

..................................................

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

Answer:

Choice A

Step-by-step explanation:

Answer: Answers are in the pictures

Answer:

carlos got 25 and Jonathan got 15.

Step-by-step explanation:

5+3=8 40/8=5

5×5=25. 5×3=15

Answer:

96 5/8?????

if its wrong i sorryyy

Step-by-step explanation:

Answer:

60

Step-by-step explanation:

If you mean multiplying them all, then:

2x6x8=96

5/8=0.625

0.625x96=60

yay its 60

Answer:

10%

Step-by-step explanation:

Hello I can help you with this question. Lets start.

The question is asking what percent of $30 is 3

so i think u actually meant $3 right but anyways

30 is 10 times 3

then clearly it would be 10%

gogo that's the answer!

Given:

Distance between to cities = 500 mi

Two cars left simultaneously moving towards each other.

The speed of one car was 10 mph greater than the speed of the other car.

They meet in 5 hours.

To find:

The speed of each car.

Solution:

Let x mi/h be the speed of one car.

So, speed of second car = (x + 10) mi/h

Two cars left simultaneously moving towards each other.

So, their relative speed = x + (x+10) = (2x+10) mi/h

We know that,

[tex]Speed =\dfrac{Distance}{Time}[/tex]

On substituting the values, we get

[tex]2x+10=\dfrac{500}{5}[/tex]

[tex]2x+10=100[/tex]

[tex]2x=100-10[/tex]

[tex]2x=90[/tex]

Divide both sides by 2.

[tex]x=\dfrac{90}{2}[/tex]

[tex]x=45[/tex]

Now,

Speed of one car = 45 mi/h

Speed of other car = 45+10

                                = 55 mi/h

Therefore, the speeds of two cars are 45 mi/h and 55 mi/hr.

Step-by-step explanation:

pls check the answer here is ur answer

Answer:

7/25-1/25i

Step-by-step explanation:

(8 + k³ - 6k⁴) + (4 - 3k⁴ + 8k²)

8 + k³ - 6k⁴ + 4 - 3k⁴ + 8k²

(8 + 4) + (8k²) + (k³) + (-6k⁴ -3k⁴)

(12) + (8k²) + (k³) + (-9k⁴)

12 + 8k² + k³ - 9k⁴

Answer: Company A is charging $13 per pound of chocolate

Step-by-step explanation:

32.5/2.5=13= 1 pound

Check:

13*2.5=$32.5

Answer:

- 1

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

[tex]\frac{f(b)-f(a)}{b-a}[/tex]

Here [ a, b ] = [ - 6, 6 ]

From the graph

f(b) = f(6) = - 2

f(a) = f(- 6) = 10 , thus

average rate of change = [tex]\frac{-2-10}{6-(-6)}[/tex] = [tex]\frac{-12}{12}[/tex] = - 1

step by step explanation:

I don't know

sorry really wanna help

Answer:

The correct answer is: Option H: 14.4 units

Step-by-step explanation:

CD is a line segment and let M be the mid-point of the line segment.

As we know that a mid-point divides the line in two equal parts, this means that the length of line segment will be the double of distance between one end and mid-point

Given

C( 2,-1) => (x1,y1)

M(8,3) => (x2,y2)

The distance formula is given by:

[tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Putting the values

[tex]|CM|= \sqrt{(8-2)^2+(3-(-1))^2}\\|CM| = \sqrt{(8-2)^2+(3+1)^2}\\= \sqrt{(6)^2+(4)^2}\\=\sqrt{36+16}\\=\sqrt{52}\\= 7.211[/tex]

We know that

[tex]CD = 2CM\\CD = 2 * 7.211\\CD = 14.422\\CD = 14.4[/tex]

Hence,

The correct answer is: Option H: 14.4 units

Answer: -36

Step-by-step explanation:

3 pages .............................. 12 min

x pages ............................... 60 min

x = 3*60/12 = 15 pages

[tex]{ \large{ \purple{ \sf{Hello \: there!}}}}[/tex]

As we know that, 1 cm = 0.01 m

So,

(a) 65 cm/s = 0.65 m/s

b) 367 km/h = (367 × 5 ÷ 18) m/s

c) 1000 cm/min = (1000 × 60 ÷ 100) m/s

d) 86 km/min = (86 × 60 ÷ 1000) m/s

[tex] \star \:{ \underline{ \boxed{ \sf{ \blue{Thank \: you : ) }}}}}[/tex]