The mirror should be held at a distance of 60cm
What is Magnification?Magnification is defined as the ratio of the height of image to the height of object. It can also be defined as the ratio of distance of image from mirror or lens to the distance of object from lens.
Magnification is given as v/u . where v is the image distance and u is the object distance.
therefore 2 = v/u
v = 2u
from the mirror formula
1/f = 1/v+ 1/u . where F is the focal length
represent 2u for v
1/f = 1/2u + I/u
1/f = 3/2u
1/40 = 3/2u
2u = 120
divide both sides by 2
u = 120/2
u = 60cm
therefore the object distance is 60cm. This means that to have a double sized image , the distance from the mirror and his face must be 60cm.
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assumptions scientists make include: anature can be understood through systematic study bscientific ideas never need to be revised cscience can provide answers to all questions. dall of the choices
Assumptions scientists make include:
a nature can be understood through systematic study.
All scientists make essential assumptions. One is determinism—the idea that every one events inside the universe, such as conduct, are lawful or orderly. the second one assumption is this lawfulness is discoverable.
Technological know-how operates on the assumptions that herbal reasons give an explanation for herbal phenomena, that evidence from the herbal world can inform us approximately the ones causes, and that these reasons are constant.
A hypothesis is an assumption, an concept this is proposed for the sake of argument so that it may be examined to look if it might be authentic. in the medical technique, the speculation is constructed earlier than any applicable research has been done, other than a fundamental historical past overview.
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Figure 7-40 shows a cord attached to a cart that can slide along a frictionless horizontal rail aligned along an x axis. The left end of the cord is pulled over a pulley, of negligible mass and friction and at cord height h = 1.6 m, so the cart slides from x1 = 5.0 m to x2 = 1.0 m. During the move, the tension in the cord is a constant 28.0 N. What is the change in the kinetic energy of the cart during the move?
The cord's tension remains constant during the movement at 28.0 N. 94.08 J is the change in the cart's kinetic energy during motion.
the force exerted on the cart is the tension T in the chord itself. so,
F=T
Calculate the displacement of the cart.
d=[tex]\sqrt{x_{1}^{2}+h^{2} } -\sqrt{x_{2}^{2}+h^{2} }[/tex]
subsitute 5.0m for x₁,1.0m for x₂,and 1.60m for h.
d=[tex]\sqrt{5.0^{2}+1.60^{2} } -\sqrt{1.0^{2}+1.60^{2} }[/tex]
d=3.36m
calculate the change in kinetic energy of the cart.
ΔK=Fd
substitute 28.0N for F and 3.36m for d.
ΔK=28.0×3.36
ΔK=94.08 J
Tension is a force that runs the length of a medium, particularly one that is conveyed by a flexible medium like a rope or cable.
An action-reaction pair of forces acting at either end of the aforementioned elements is what is referred to as tension. Consider a rope; aside from the endpoints, every section of the rope experiences tension force in both directions. The ends feel strained on one side and the force of the attached weight. The tension fluctuates in several places along the string.
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The nebular theory proposes the sun and planets formed from a rotating cloud of interstellar gases and dust called a
celestial sphere
protoplanet
solar nebula
planetesimal
The nebular theory proposes the sun and planets formed from a rotating cloud of interstellar gases and dust called a Solar nebula
What is nebular theory?
The creation of solar systems is explained by the nebular theory. According to the explanation, stars are produced from clouds of interstellar gas and dust, and the term "nebula" is Latin for "cloud." It takes around 100 million years for an undifferentiated cloud to develop into a star system with planets and moons.
The nebular theory proposes the sun and planets formed from a rotating cloud of interstellar gases and dust called a solar nebula
According to the nebular theory, the Sun and all of the plants in the solar system descended from the solar nebula, an interstellar cloud of gases and dust. The term "nebula" itself is a Latin word for cloud. The nebula began to collapse over time, and the centre of the collapse (the central mass) eventually turned into a protostar.
It should be noted that this protostar was distinct from our current star in that it lacked the continuous nuclear fusion process that our stars do now. When nuclear fusion begins in the centre of a protostar, it transforms into a star.
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a. does the speed of the moving object affect the amount of kinetic friction on the object? explain your answer and cite evidence to support your claim.
No, the quantity of kinetic friction on a moving item is not affected by its speed.
The consistency of the speed is more crucial than the actual speed. As was mentioned the friction force needs to be cancelled out by a constant force. The applied force would be equal to the kinetic friction force if the motion was constant in speed.
Therefore, the kinetic friction coefficient is not affected by the relative speeds of the two objects. The types of surfaces in contact are the sole factors that affect the coefficient of kinetic friction.
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rosa a block of mass 3 kg slides down an inclined plane at an angle of ??p with a massless tether attached to a pulley with mass 1 kg and radius 0.5 m at the top of the incline (see the following figure). the pulley can be approximated as a disk. the coefficient of kinetic friction on the plane is 0.4. what is the acceleration of the block? os 10
If the coefficient of kinetic friction on the plane is 0.4, the acceleration of the block is 0.3 m/s² and tension is T = 1.82N.
A property of a body that is a measure of inertia is usually viewed as a measure of the amount of matter contained in the body that causes it to have weight in a gravitational field. Mass is a dimensionless quantity that describes the amount of matter in a particle or object.
Calculation:-
Tension force = I/R² × a
= 0.5 × 3.564
T = 1.782 N.
acceleration = 1.782/3
= 0.3 m/s²
The mass of an object is a measure of its inertial properties or the amount of matter it contains. The weight of an object is a measure of the force exerted on it by gravity, or the force required to support it. Mass can best be understood as the amount of matter present in an object or body. Everything around us has mass.
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A member ABC has a mass of 2.4kg and is attached to pin support at B. An 800 gram sphere D strikes the end of the member ABC with a vertical downward velocity v1 = 3.0 m/s. knowing that L=750 mm and that the coefficient of restitution between the sphere and the Plank is 0.5. Determine immediately after impact:
a) The angular velocity of member ABC.
b)The velocity of the sphere.
(a)The angular velocity v(d)' is 0.936 m/s
(b)The velocity of the sphere is 3 rad/s
Let us assume that
angular velocity of member ABC is v(d)'
velocity of the sphere = ω'
Write the moment of inertia of the member ABC
I(G) = 1/12 ML²
I(G) = 1/12*(2.4)(0.75m)²
I(G) = 0.112 kgm²
After the impact
ω = ω'(ccw)
ν'(G) = (L/4)ω' (upwards)
ν'(A) = (L/4) ω' (downwards)
Take the moments about B
m(d)v(d)(L/4) + 0 = m(d)v'(d)(L/4) + I(G)ω' + Mv'(G)(L/4)
m(d)v(d)(L/4) = m(d)v'(d)(L/4) + I(G)ω' + M(L/4)²ω'
m(d)v(d)(L/4) = m(d)v'(d)(L/4) + ] I(G) + M(L/4)² ]ω'
(0.8)(3)(0.75/4) = (0.8)v'(d)(0.75/4) + [ 0.112 + (2.4)(0.75/4)²
0.45 = 0.15v(d)' + 0.1963ω' -------------------- (eq1)
From the coefficient of restitution,
v(d)' - v(A)' = -e [ v(d) - v(A) ]
v(d)' - (L/4)ω' = -(0.5) [3-0]
v(d)' - (0.75/4)ω' = - 1.5
v(d)' - 0.1875ω' = - 1.5 ---------------------- (eq 2)
From eq 1 and eq 2
v(d)' = 0.936 m/s
ω' = 3 rad/s
Therefore, the angular velocity is 0.936 m/s and the velocity of the sphere is 3 rad/s.
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protect the attack line from minor flare-ups. get the next length to the appropriate location. the starting location for any progressive hose lay. restrict water flow. addition of lateral lines.
Lateral Lines - Protect the attack line from minor flare-ups.
Hose Packs - Get the next length to the appropriate location.
Anchor Points - The starting location for any progressive hose lay.
Hose clamps - Restrict water flow.
Hoseline tees -Addition of lateral lines.
A common variation of Flat Road is the Minuteman Road. Some ingenuity is required for loading, but loading is easier than 3-layer stacking. This load is popular because when the tube enters the structure it can be peeled off and deployed from the shoulders of the jet man.
The high flow usually straight jet main jet is created with a smooth bore tip or some type of combination nozzle. Separate the front-row players from the back-row players. One team should focus on attacking the flames directly, while the other team should concentrate on blocking the oncoming spread of the flames.
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suppose you observe a binary system containing a main-sequence star and a brown dwarf. the orbital period of the system is 1 year, and the average separation of the system is 1 au . you then measure the doppler shifts of the spectral lines from the main-sequence star and the brown dwarf, finding that the orbital speed of the brown dwarf in the system is 23 times greater than that of the main-sequence star.1. How massive is the brown dwarf?
Mdwarf = ? KG
Mass of the brown. dwarf., M₂ = 4.132 * 10²⁷ kg
Let M₁ = Mass of the main-sequence star
M₂ = Mass of the brown dwarf
v₁ = speed of the main-sequence star
v₂ = speed of the brown dwarf
The system's average distance apart r₁ = r₂ = 1 AU
The brown dwarf's orbital speed is 22 times that of a star in the main sequence.
Consequently, v2 = 22 v1.
Considering that the Sun is a main-sequence star
2 * 1030 kg is the main-sequence star's mass.
Centripetal force: F = Mv2/r
M1v12 = M2v22 M2/M1 = v12/v22 M2/M1 = (1/22) M1v12 = M2v22/r2 M2v22/r2
2 M2/M1 = 0.002066 M2 = 0.002066M1 M2 = 0.002066*2*1030 M2 = 4.132*1027 kg
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Porosity decreases Choose one: A. with decreasing compaction of sediments or rock. B. when rocks develop joints or faults. C. when fluids passing through a rock dissolve parts of the rock. D. with the cementing of sediments by mineral grains from groundwater. The water table Choose one: O A. usually lies within a few meters of the surface in deserts. O B. rises to a higher elevation during the dry season. O C. mimics the topography of the land it underlies. O D. is always located beneath the ground surface.
A decrease in porosity occurs when rocks form joints or faults.
Option B is correct
What impact does porosity have on groundwater?Porosity is the entire available area for groundwater to live in. A rock's or sediment's porosity impacts how much water it can hold. The porosity of sediments and sedimentary rocks is influenced by the size, shape, and degree of sorting of the grains as well as the degree of cementation.
What impact do permeability and porosity have on groundwater?A good permeability must coexist with good porosity for groundwater to enter a rock. The pore gaps between the rock grains must be linked for a rock to be permeable and allow water to pass through it.
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9. a solid metal ball of radius 1.3 cm bearing a charge of 6.2 nc is located near to and along the midline of a hollow uniformly charged plastic rod of radius 1.9 cm and length 12.5 m bearing a uniformly distributed charge of 7.1 nc (see the figure) on its outer surface. the distance between the center of the rod and the center of the ball is 25.5 cm.
The electric field at the center of the metal ball due only to the charges on the surrounding of the metal ball is 0 N/C.
The electric field is defined as the force acting on a positive test charge, per unit charge. units are thus N/C for the electric field. It is similar to the gravitational field on the surface of the Earth for a test mass mo
The electric field is a vector field. It has a magnitude and a direction. Another example is vector field is the wind distribution. Temperature distribution is an example of a scalar field.
Lines indicate the direction of F if a test charge is placed there, Field lines point away from positive charge, and toward negative charge, density of lines indicates the strength of the field.
Field lines cannot cross. If they did, there would be more than one possible direction for a particle to travel at a given point. The lines themselves have no meaning the field is present everywhere.
Since metal ball is considered as a solid sphere So the electric field inside metal ball is given by E=(p/3Eo)г
Where r is the distance from center and rho is charge density. Hence at the centre r=0
Then electric field =(p/3Eo)* 0 = 0 N/C
Hence electric field at the centre of the metal ball due to it's own charge only is 0 N/C.
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multiple choice question the ratio that measures the reasonableness of accounts receivable outstanding, and can be used to estimate the average collection period of accounts receivable is the ratio.
The ratio that measures the reasonableness of accounts receivable outstanding, and can be used to estimate the average collection period of accounts receivable is the accounts receivable turnover ratio.
The amount owed to a business for goods or services that have been delivered or utilized, but for which consumers have not yet made payment is known as accounts receivable, or AR. A current asset is defined as accounts receivable on the balance sheet. Any sum that clients owe for purchases they made with credit is considered AR. Account receivable is the term used to describe any unpaid invoices or cash that a business is owed by customers. Accounts that a company is entitled to get as a result of delivering a good or service are referred to by the phrase. Receivables, also known as accounts receivable, are a type of line of credit that a business extends to customers. Typically, the terms of receivables stipulate that payments must be made within a reasonable amount of time.
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in which of the following cases will there be a current in the ammeter? (1) the switch has just been closed (2) the switch has been closed a long time (3) the switch has just been opened (4) the switch has been opened a long time
The presence of a current in an ammeter depends on the state of an external electrical switch. If the switch is closed, there will be a current in the ammeter; if the switch is opened, there will be no current in the ammeter. The length of time the switch has been in a particular state does not affect the presence of a current in the ammeter.
The presence of a current in an ammeter depends on the state of an external electrical switch. A switch is a device used to break or make an electrical connection, and can be used to control the flow of electricity in a circuit. In the following cases, the presence of a current in the ammeter can be determined:
(1) If the switch has just been closed, there will be a current in the ammeter. When the switch is closed, it creates an electrical connection, allowing electricity to flow through the circuit, and thus a current to be registered on the ammeter.
(2) If the switch has been closed for a long time, there will still be a current in the ammeter. This is because the switch is still in the closed position, allowing electricity to flow through the circuit, and thus a current to be registered on the ammeter.
(3) If the switch has just been opened, there will be no current in the ammeter. When the switch is opened, it breaks the electrical connection, preventing electricity from flowing through the circuit, and thus no current will be registered on the ammeter.
(4) If the switch has been opened for a long time, there will still be no current in the ammeter. This is because the switch is still in the open position, preventing electricity from flowing through the circuit, and thus no current will be registered on the ammeter.
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Two charges separated by one meter exert 1-N forces on each other. If the charges are pushed to 1/4 meter separation, the force on each charge will be
A. 1 N.
B. 2 N.
C. 4 N.
D. 8 N.
E. 16 N.E. 16 N
The force on each charge will be 16N. Two charges separated by one meter exert 1-N forces on each other. If the charges are pushed to 1/4 meter separation.
How to solve?We have the following given data,
When, r=1m,F=1N
When, r=1/4m,F=?N
Solution,
Let, the distance is r.
The magnitude of the electric force between two charges is given by the following equation:
F=k.q1.q2/r2
the charges unchanged . this proportionality relation, let find the magnitude of force at indicated distance.
Plugging in our values, we have
F=k.q1.q2/r2
F∝1/r2
F2/F1=r21/r22
F2=(r1/r2)2×F1
[Plug in the values. ]
F2=(4)
2×1 N
F2=16N
Therefore, the force will be
F2=16N
Does a charge in an electric field experience any forces?Other charges exert forces on electric charges; for instance, two positive charges may push apart or repel one another. To clarify, we say that an electric charge creates (or induces) an electric field all around it. Other adjacent charges are then affected by this electric field, applying forces to them.
What is the charge's force?In the same manner as F = mg determines the force on the mass m, F = qE determines the force on the charge. The analogy between gravity and electrostatics can be extended to include energy, but we'll get to that later.
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A laser is used in eye surgery to weld a detached retina back into place. The wavelength of the laser beam is 581 nm, and the power is 1.5 W. During surgery, the laser beam is turned on for 0.050 s. During this time, how many photons are emitted by the laser?
The laser beam emits 1.939 x 10¹⁷ photons after being activated for 0.050 seconds.
Explain what a laser is.A laser emits an extremely focused beam of energy that may be used in a variety of equipment and technologies. Laser Amplification by Stimulation of Radiation Emission is what the letters in the term laser stand for. Light Amplifier by Stimulated Radiation Emission is what the elements in the term laser stand for.
Briefing:As we are aware,
This pace of energy is equivalent to power in numbers.
As things evolve throughout time,
using mathematics,
power : P = E /t
Total Energy : E = P t
= (1.5)(0.050)
= 0.075 J
The laser beam's wavelength is = λ = 514 nm
One photon's energy is given by E ' = h c /λ
= (6.626068 × 10⁻³⁴ )(3 x 10⁸)/(514 x10⁻⁹)
= 0.03867 x 10⁻¹⁷ J
The amount of photons the laser beam emits:
= (total energy) / (energy per photon)
= 0.075 J / 0.03867 x 10⁻¹⁷ J
= 1.939 x10¹⁷ photons
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an apple weighs 1.20 n. when you hang it from the end of a long spring of force constant 1.44 n/m and negligible mass, it bounces up and down in shm. if you stop the bouncing and let the apple swing from side to side through a small angle, the frequency of this simple pendulum is half the bounce frequency. (because the angle is small, the back and forth swings do not cause any appreciable change in the length of the spring.)
The unstretched length of the spring is 3.333 m
Calculation :
k = Spring constant = 1.5 N/m
g = Acceleration due to gravity = 9.81 m/s²
l = Unstretched length
Frequency of SHM motion is given by
[tex]f_{s} = \frac{1}{2\pi }\sqrt{\frac{k}{m} }[/tex]
Frequency of pendulum is given by
[tex]f_{p} = \frac{1}{2\pi }\sqrt{\frac{g}{l} }[/tex]
Given in the question
[tex]f_{s} = \frac{1}{2\pi }\sqrt{\frac{k}{m} }[/tex] = [tex]f_{s} = \frac{1}{2\pi }\sqrt{\frac{g}{l} }[/tex]
[tex]\frac{1}{2\pi }\sqrt{\frac{k}{m} }= \frac{1}{2}\frac{1}{2\pi }\sqrt{\frac{k}{m} }[/tex]
l = [tex]\frac{4gm}{k}[/tex]
l = [tex]\frac{4*9.8*\frac{1.2}{9.8} }{1.44}[/tex]
l = 3.333 m
The unstretched length of the spring is 3.333 m
The word "force" has a precise meaning. At this level it is appropriate to describe the force as pushing or pulling. A force does not contain or "have within" an object. A force is applied from one object to another. The concept of force is not limited to living things and inanimate things
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When a 40-N force, parallel to the incline and directed up theincline, is applied to a crate on
a frictionless incline that is 30? above the horizontal, theacceleration of the crate is 2.0m/s2,
up the incline. The mass of the crate is:
A. 3.8kg
B. 4.1kg
C. 5.8kg
D. 6.2kg
E. 10 kg
The mass of the crate when it is directed up the incline will be equal to 5.8 kg that is option C is correct.
This problem can be solved using the concept of Newton's second law of motion. The mathematical expression of this will be
F = ma
where F is the force, m is mass and a is the acceleration.
Now, net force will be expressed as
Fₙ = 40N - mg (sin 30°) = m(2 m/s²)
where 40 N is the force parallel to incline and mg (sin 30°) is the vertical component of force.
From this we solve for m as
m = 40/6.9
m = 5.8 kg
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A 2.20-m-long pole is balanced vertically on its tip. It starts to fall and its lower end does not slip. Part A What will be the speed of the upper end of the pole just before it hits the ground?
the speed of the upper end of the pole just before it hits the groundv is = 7.27 m / s
Explanation:
At both the greatest and lowest points, we shall practise energy conservation.
first. The highest point
Em₀ = U
Em₀ = m g y
final. smallest point
At this point, we adjust the reference system so that the potential energy is 0
= K
= ½ m v²
how to conserve energy
Em₀ =
mg y = ½ m v²
v = √2 gy
v = √ (2 9.8 2.7) (2 9.8 2.7)
v = 7.27 m / s
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in fig. 12-30, trying to get his car out of mud, a man ties one end of a rope around the front bumper and the other end tightly around a utility pole 18 m away. he then pushes sideways on the rope at its midpoint with a force of 550 n, displacing the center of the rope 0.30 m, but the car barely moves.what is the magnitude of the force on the car from the rope? (the rope stretches somewhat.)
The rope's force on the car, in terms of magnitude, is [tex]8.3 *10^{3}[/tex] N
A man ties a rope firmly around the front bumper of his car and an 18-meter utility pole in an effort to free it from the mud. Then, with a force of 550 n, he pushes sideways on the rope at its middle, shifting the rope's center by 0.30 m, but the automobile scarcely moves.
At first, we evaluate the angle, then with its help of it, we shall evaluate the magnitude of the force.
Measured from the dotted line, the angle of each rope half is
θ = [tex]tan^{-1} (\frac{0.30m}{9.0m} )= 1.9[/tex]
When we examine the forces at the "kink" (where F is applied), we discover
t = 2sinθ/F = 2sin1.9/550 = [tex]8.3 *10^{3}[/tex] N
The rope's force on the car, in terms of magnitude, is [tex]8.3 *10^{3}[/tex] N
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The magnitude of the force on the car from the rope is 8.3*10³ N
Force is the amount of energy applied to displace the position of any object. This force has magnitude and direction and so is called the vector quantity.
Here, in this question,
Given,
Distance = 18 m
Midpoint force = 550 N
Displacement of the center of the rope = 0.30 m
The rope when tied then it will also show a force which is the tension force (t).
We know that tension t
t = 2sinθ / F
But we are not aware about the value of θ
so
we will first find the value of θ by
θ = tan⁻¹(0.30/0.9) = 1.9
We got the angle to be 1.9, now we can easily find the force in the rope as
t = 2 sin 1.9 / 550
= 8.3 * 10³ N
Therefore, the magnitude of the force on the car from the rope is 8.3*10³ N.
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a block with a mass of m slides at a constant velocty v0 on a horizontal frictionless surface. if the spring constant iis k , what ii the maximm compresion in the spring
If the block's mass is m, block's initial velocity is v and the spring constant is k, the maximum compression in the spring is sqrt(mv² /k)
Applying the law of conservation of energy, since it is a frictionless surface, all the kinetic energy of the block will be converted to the potential energy of the spring.
The kinetic energy of the block:
Ek = 1/2 . mv²
Where:
m = mass of block
v = block's initial velocity
The potential energy of the spring:
Ep = 1/2 . kx²
Where:
k = spring constant
x = maximum compression in the spring
It holds:
Ek = Ep
1/2 . mv² = 1/2 . kx²
x = sqrt(mv² /k)
Hence, the maximum compression in the spring is sqrt(mv² /k)
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60 m/s while piece c moves in the positive x-direction at 70 m/s. we want to find the speed and direction of piece b.
The speed and direction of piece b is 11.33m/s positive x direction.
Total momentum = 0 (at rest)
Applying conservation of linear momentum,
Momentum after explosion = momentum before explosion
MaVa + MbVb + McVc = 0
100(-60) + 150Vb + 70(86) = 0
Vb = 11.33m/s
Speed of Vb = 11.33m/s
In Newtonian mechanics, momentum is the result of an object's mass and velocity, more precisely linear momentum or translational momentum. This mechanical quantity is typical. It has. a direction. and a magnitude., making. it a vector. quantity. The momentum of an item is expressed as: [tex]displaystyle mathbf p =m mathbf v.mathbfp = m mathbf v[/tex] if m is the object's mass and v is its velocity (also a vector quantity).
The kilogram metre per second (kg m/s), which is a unit of measurement for momentum in the International System of Units (SI), is a unit of measurement for a newton-second.
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Let 84.0 J of heat be added to a particular ideal gas. As a result, its volume changes from 90.0 to 144.0 cm3 while the pressure remains constant at 1.0 atm. By how much did the internal energy of the gas change?
a)What is the molar specific heat at constant pressure?
b)Find the molar specific heat at constant volume.
The molar heating value in normal pressure is 116.49 J/molK or the molar heating value under continuous volume is 124.42 J/molK, according to the declaration.
Why does heat form?Small units known as atoms, molecules, and ions make up all matter. These little particles vibrate back and forth or run into each other constantly. All is among a type of energy termed as heat (or thermal) energy, which is produced by the movement of particles.
Briefing:Internal energy change:
Q = 84.0 J, V = 90 cm³ = 9.0E-5 m³, V' = 144.0 cm³ = 1.44E-4 m³, P = 1 atm
W = P(V'-V) = (1.013E5)(1.44E-4 - 9.0E-5) = 5.61 J
U = Q-W = 84.0-5.61 = 78.39 J
a). Molar specific heat
Q = nCp(T' - T) = (Cp/R) nR(T' - T) = (Cp/R) P(V' - V)
so Cp = RQ/[P(V' - V)] = 8.31*84.0 / 5.61 = 124.42 J/molK
b). Molar specific heat (constant v)
Cv=Cp - R = 124.8-8.31 = 116.49 J/molK
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An airplane traveling 245 m/s east experienced turbulence, so the pilot decided to slow down to 230 m/s. It took the pilot 7 seconds to get down to this speed. What is the acceleration of the plane? (Round your answer to the nearest integer.)
On the runway, aeroplanes accelerate between 115 and 160 mph (ca. 257 km/h). However, the precise acceleration is influenced by the plane's model, the weather, and other elements.
What turbulence affect acceleration of the plane?Seat belts will definitely feel under strain, and loose objects will become displaced. Considerable, sudden changes in height, attitude, and typically, large variations in indicated airspeed are all symptoms of severe turbulence. There's a chance the jet will briefly lose control.
Therefore, In general, tiny planes need the least amount of acceleration to take off, whereas commercial planes need the greatest.
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since the rate of decay is proportional to the number of nuclei, we can substitute rate of decay (counts/sec) for the n values. the age of the object can be found using the equation:
The age of the object can be found using the equation [tex]t=\frac{1}{k}ln\frac{[A_{0} ]}{[A]}[/tex].
The rate of decay:
In contrast to chemical reactions, the decay of a certain nucleus cannot be predicted and is unaffected by physical factors like temperature. There are two factors that affect the rate of isotope decay. The average number of undecayed nuclei in the system must double, as must the rate of decay for undecayed nuclei. the isotope's stability because some decay more quickly than others. The number of nuclei that decay per second is determined by the rate of decay.
The rate of the Decay is given as
[tex]\frac{-dA}{dt} =k[A][/tex]
On integrating the above we have
[tex]ln\frac{[A_{0} ]}{[A]}=kt[/tex]
[tex]t=\frac{1}{k}ln\frac{[A_{0} ]}{[A]}[/tex]
The number of nuclei has no bearing on the likelihood that a fixed nucleus would decay. Each nucleus has a predetermined likelihood of decaying in a certain length of time. The number of decaying nuclei will rise as the number of nuclei increases, but that is actually to be expected.
It's similar to rolling a large number of dice; the proportion of dice showing a particular digit to the total number of dice you roll. Keeping with this scenario, let's say you take away a dice if it displays 1. This is comparable to the disintegration of a nucleus. The number of dice eliminated will initially be large, but as the number of dice decreases, so will the number being removed.
The age of the object can be found using the equation:
[tex]\frac{-dA}{dt} =k[A][/tex]
[tex]t=\frac{1}{k}ln\frac{[A_{0} ]}{[A]}[/tex]
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based on what you know about measuring the distance to stars, select all of the correct statements from the following list.
To measure the distance to nearby stars, astronomers use the effects of stellar parallax or by determination of distance by observing parallax works mostly for nearby stars (1).
What is parallax?Parallax is a method used by looking at the shift of two fixed points relative to one another seen from the observer's point of view. The parallax of a star is expressed in units of arc seconds, so this parallax is an angle, while the distance is expressed in units of parsecs with 1 parsec = 3.26 light years. The trigonometry parallax method can only be used to get the distance to the nearest stars, which is up to 100 parsecs.
To measure the distance of a star, astronomers do not use distance units such as meters or kilometers, but the Astronomical Unit, which is equivalent to the average distance between the Earth and the Sun, about 150 million kilometers.
The question is incomplete, it should be:
Based on what you know about measuring the distance to stars, select all of the correct statements from the following list?
1) Determination of distance by observing parallax works mostly for nearby stars.
2) For the distance to far stars, it is necessary to use spectroscopic parallax.
3) To determine the luminosity of a star, you must first know the distance.
4) There are no other stars within a parsec of the sun.
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A car driving at 20 m/s accelerates 2.5 m/s2 for a distance of 350 meters. What is the car's final velocity?
The time of the travel with 20m/s is 17.5 seconds. Thus, the final velocity of the car will be 63 m/s.
What is velocity?Velocity of an object is the measure of the distance travelled per unit time. The rate of change in velocity is called the acceleration.
Given that, initial velocity u = 20 m/s
distance = 350 meters.
time of travel = distance/ velocity
= 350 m/20 m/s = 17.5 s.
Acceleration = 2.5 m/s²
the final velocity v = u + at.
v = 20 + (2.5 × 17.5 ) = 63 m/s.
Therefore, the final velocity of the car is 63 m/s.
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evaporation is a cooling process and condensation isquestion 16 options:a cooling process also.a warming process.neither a warming nor cooling process.can not tell with the information given.
Evaporation is a cooling process and condensation is a warming process.
Condensation is the transition of a region of matter from a gaseous state to a liquid state and the opposite of vaporization. This word most often refers to the water cycle. Condensation is the process by which water vapor becomes a liquid. This is the opposite of evaporation, which turns liquid water into vapor. Condensation occurs in one of two ways. When the air cools to its dew point or becomes saturated with water vapor, it can no longer hold water.
Evaporation is always a cooling process. For evaporation to occur, energy is needed by the liquid molecules that are changing phase into gas. This energy is taken from the surroundings in the form of heat energy. So when evaporation occurs, the temperature of the surroundings will decrease, making evaporation a cooling process.
Condensation occurs when warmer, moist air comes into contact with cooler surfaces such as frames, windows, and other superstructures, or cooler areas inside an insulating shell (where moisture has penetrated the vapor barrier).
Therefore, evaporation is a cooling process and condensation is a warming process.
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What device can be used to spot the differences between AC and DC?
A. Transformer
B. Generator
C. Motor
D. Oscilloscope
Answer:
Check explaination
Explanation:
A - Transformer is the right option 100%
a small car of mass 420 kg is pushing a large truck of mass 940 kg due east on a level road. the car exerts a horizontal force of 1600 n on the truck.What is the magnitude of the force that the truck exerts on the car?
The magnitude of the force that the truck exerts on the car is same as the horizontal force exerted by the car on the truck that is 1600 N.
In physics, a force is a force that can change the motion of an object. A force can change the velocity of an object with mass. Pressure can also be intuitively described as pushing or pulling. A force has both a value and a displacement, making it a vector quantity.
Squeeze is pushing and pulling, which affects daily life because people without strength cannot open and close objects, lift arms and legs.
Reason :
This question is a simple application of Newton's third law, which states that if an object A exerts a force on an object B, then B must exert a force on A that is equal in magnitude but opposite in direction.
The car pushes against the ground with a force of 1600 N, so therefore the ground must exert a force on the car, also of 1600 N.
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Which of these statements is true concerning balanced forces acting on a car?
Balanced forces will cause no change in the car's motion.
Balanced forces will cause the car to accelerate in the direction of the greater force
Balanced forces will cause the object to change direction.
Balanced forces will cause the car to slow down and stop
Answer:
Balanced forces will cause no change in the car's motion.
Explanation:
Balanced forces are 2 forces that are equal in opposite directions. This means they 'cancel each other out' in a way. Since both are equal, they cause no effect on the motion of the car
If a tennis player's arm muscles are weak and unable to produce enough force with one hand to accelerate the ball sufficiently, he can create more total force by hitting with two hands. Which of the following principles best describes why this occurs?Newton's Law of acceleration
Newton's Law of acceleration best describes why this occurs.
Newton's second law - the law of acceleration (acceleration = pressure/mass). Newton's 2d regulation states that the acceleration of an item is without delay related to the net pressure and inversely associated with its mass. Acceleration of an object relies upon on things, force and mass.
The legal guidelines are: (1) each item movements in a straight line except acted upon by way of a pressure. (2) The acceleration of an item is without delay proportional to the internet pressure exerted and inversely proportional to the object's mass. (3) For every motion, there may be an same and opposite reaction.
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